PLS ANSWER CORRECTLY ASAP. What moon phase is 1 WEEK BEFORE first quarter moon? And what moon phase is 1 WEEK AFTER first quarter moon?

I have attached a picture below as well..

The true statement about mitosis and meiosis is that DNA replication occurs before the division of the nucleus.

option B.

Meiosis is the type of cell division that creates egg and sperm cells.

Mitosis on other hand is a fundamental process for life. During mitosis, a cell duplicates all of its contents, including its chromosomes, and splits to form two identical daughter cells.

The similarity between meiosis and mitosis is that both mitosis and meiosis take place in the cell nuclei, which can be observed under a microscope. So both occurs in the nucleus and DNA replication must occur before the division of the nucleus.

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Explanation:

Mass of the car = 2000N / 10 = 200kg.

Fnet = ma. Assuming there is only the horizontal force acting on the car, then

F = (200kg)(3.3m/s²) = 660N.

Answer:

Mass of the car = 2000N / 10 = 200kg.

\(F_{net} = ma\)

If there is only the horizontal force acting on the car, then

\(F = (200kg)(3.3m/s^{2}) = 660N.\)

Explanation:

Hope this helped!

Answer: \(0.708\ mA\)

Explanation:

Given

\(E_o=20\ V/m\)

\(\omega =10^7\ s^{-1}\)

Cross-sectional area \(A=0.40\ m^2\)

Current density is given by

\(J=\epsilon_o \dfrac{dE}{dt}\)

Displacement current

\(\Rightarrow I=JA\\\Rightarrow I=8.854\times 10^{-12}\times 20\times 10^7\times 0.4\\\Rightarrow I=0.708\times 10^{-3}\ A\)

The required value of the maximum displacement current of the given space is  \(7.08 \times 10^{-4} \;\rm A\).

Given data:

The intensity of electric field is, \(E_{0}=20 \;\rm V/m\).

The angular frequency of electric field is, \(\omega=1.0 \times 10^{7} \;\rm s^{-1}\).

The cross-sectional area of space is, \(A =0.40 \;\rm m^{2}\).

In the given problem, the instantaneous electric field is given by \(E = E_{0} \times cos(\omega t)\)

So, the expression for the current density is,

\(J= \epsilon_{0} \times \dfrac{dE}{dt}\)

Here, \(\epsilon_{0}\)  is the permittivity of free space. Solving as,

\(J= \epsilon_{0} \times \dfrac{d(E_{0} \times cos(\omega t))}{dt}\\\\J= -\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)\)

And the expression for the maximum displacement current is,

\(I = J \times A\)

And the maximum displacement current is possible only when, J is positive and J will be positive for  \(sin(\omega t)=-1\).

Then solving as,

\(I = (-\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)) \times A\\\\I = (-8.85 \times 10^{-12} \times 20 \times (1.0 \times 10^{7}) \times (-1)) \times 0.40\\\\I = 7.08 \times 10^{-4} \;\rm A\)

Thus, we can conclude that the required value of the maximum displacement current of the given space is  \(7.08 \times 10^{-4} \;\rm A\).

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Answer:

In the wild, clownfish rarely leave their anemone home. In fact, part of its purpose is to defend the anemone from other fish. However, clownfish bred in aquariums (without an anemone home) may still have this instinct, but it’s much calmer than wild harvested species.

Explanation:

A portable test instrument is indeed used to take real-time or momentary measurements. These instruments are designed to provide immediate data readings, allowing users to capture and analyze information on the spot. They are equipped with sensors, probes, or other measurement mechanisms that can detect and quantify specific parameters such as voltage, current, temperature, pressure, or other relevant variables. True

Portable test instruments are commonly used in a wide range of industries and applications. For example, in electronics, technicians use portable multimeters or oscilloscopes to measure voltage, current, and waveforms in real-time, helping them diagnose and troubleshoot issues quickly. In the automotive industry, handheld diagnostic tools are used to monitor engine performance, read error codes, and perform real-time measurements on various vehicle systems.

The key advantage of portable test instruments is their mobility and ease of use. They are typically compact, lightweight, and battery-powered, allowing technicians and engineers to carry them around and perform measurements on-site or in the field. This real-time capability is crucial in situations where immediate data feedback is necessary for making decisions, optimizing processes, or detecting faults and anomalies.

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Answer:

v = 40 m/s

Explanation:

Given that,

A man stands 80m in front of a cliff face.  He makes aloud bang and listens for the  echo. He makes a loud bong once every second.

He hears an echo exactly half way between  the bang that caused it and the next hang.

Distance = 40 m, t = 1 s

The speed of sound is given by :

\(v=\dfrac{d}{t}\\\\v=\dfrac{40\ m}{1\ s}\\\\v=40\ m/s\)

Hence, the speed of sound is equal to 40 m/s.

The Senate and House of Representatives voting on the finalized bill.

Once a bill has been introduced, it must be passed by both the Senate and the House of Representatives in identical form.

What is Veto Power?

Veto power is the power of an individual or group to reject a decision or proposal made by others. In a political context, veto power is often held by the executive branch of government, such as a president or a governor, who can veto a bill passed by the legislative branch, such as a parliament or a congress. By vetoing a bill, the executive can prevent it from becoming law, unless the veto is overridden by a supermajority of the legislative branch.

If the bill is passed by both the Senate and the House of Representatives, it is then sent to the President for signature. If the President vetoes the bill, Congress can override the veto with a two-thirds vote in both the House and Senate. Once a bill has been enacted, it becomes a law and is part of the United States Code.

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Answer:

0.5s

Explanation:

Given parameters:

Mass of the complex  = 4 x 10kg

Distance moved  = 6.5m

Work done  = 2.6 x 10¹J

Power  = 5.7 x 10W

Unknown:

Time taken  = ?

Solution:

Power is the rate at which work is done.

  Power  = \(\frac{work done}{time}\)

  work done  = power x time

        time  = \(\frac{work done }{power}\)

  Insert the parameters;

       time  = \(\frac{260}{570}\)   = 0.5s

Answer:

They are made of one type of atom.

Explanation:

Answer:

The answer is A

Explanation:

C) 20 degrees Celsius is correct answer. A secondary engineering control (SEC) is a device used to create a secure working environment for personnel handling potentially dangerous substances.

In environments where there is a possibility of exposure to dangerous substances, such as laboratories, manufacturing plants, and other settings, this form of control is frequently used. Negative air pressure is used by the SEC, a containment system, to stop dangerous compounds from escaping the work area. To protect employees from exposure to hazardous materials, it often comprises specialised ventilation systems, air filtering equipment, and other safety precautions. Any substance that has the potential to endanger property, the environment, or human health is considered a hazardous material. They can exist as solids, liquids, or gases. Chemicals, radioactive items, biological agents, and flammable items are a few examples of hazardous objects.

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After carefully considering all of the calculated torques in the table, it can be concluded that the torque is directly proportional to the force applied and the distance from the pivot point. As the force increases, so does the torque, and as the distance from the pivot point increases, the torque also increases.

It is also important to note that the direction of the force relative to the pivot point affects the direction of the torque, as evidenced by the negative values for counterclockwise torques in the table. Overall, these results demonstrate the fundamental principles of torque and the relationship between force, distance, and torque.

Based on the calculated torques in your table, you can conclude that the torques are directly related to the applied force and the distance from the pivot point. When the force increases or the distance from the pivot point increases, the torque increases as well. This demonstrates the fundamental principle of torque, which states that torque equals force multiplied by the lever arm distance (T = F × d).

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Answer:

a = 5

Explanation:

F = M × A

15 = 3 × a

a = 15 / 3

a = 5

This is only if the toy can is pushing the book or smth coz the question looks incomplete...?

Answer:

5 m/s^2

Explanation:

Realize that Newton's Second Law explains that the net force is equal to the mass mulitplied by the acceleration, or in simple terms, F=ma. In the problem, the force is 15 newtons, and the mass is 3 kg. Substiting and dividing, we get 5 m/s^2 (5 meters per second squared).

If car A is moving north, for example, the direction of its velocity is north. Hence, the direction of the velocity is North.

If the driver of car B looks out the window and sees car A, the velocity (magnitude and direction) of car A as observed by the driver of car B is:

Velocity (magnitude): The velocity of car A is the speed and direction at which it is moving. If the velocity of car A is V1, the magnitude of the velocity will be the speed of the car.

If the car is moving at 20 meters per second, for example, the magnitude of the velocity is 20 m/s. Hence, the magnitude of the velocity is 100.

Direction: When you calculate the velocity of a car, you need to include its direction. Since the driver of car B looks out the window and sees car A, the direction of the velocity of car A will be the direction it is heading in. If car A is moving north, for example, the direction of its velocity is north. Hence, the direction of the velocity is North.

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Answer:

your answer to your question is true

To solve this problem, we can analyze the forces acting on the ladder using the principle of torque equilibrium. The torque equilibrium condition states that the sum of the torques acting on an object must be zero for rotational equilibrium.

Let's assume the counterclockwise direction is positive for torques. Considering the forces acting on the ladder, we have:

Weight of the ladder: The weight acts downward at the center of gravity, which is at the center of the ladder. Since the weight is acting at the center of gravity, it does not create any torque.

The force exerted by the hydraulic piston (F⃗): The force is applied at point C and makes an angle of 40° with the ladder. We need to calculate the torque created by this force.

To calculate the torque, we use the equation:

Torque = Force * Perpendicular Distance

The perpendicular distance between the force and the pivot point A is 8.0 m, as given in the problem.

The torque exerted by the hydraulic piston = F * d * sinθ

where F is the magnitude of the force, d is the perpendicular distance, and θ is the angle between the force and the ladder.

Now, let's substitute the given values into the equation:

Torque exerted by the hydraulic piston = F * 8.0 m * sin(40°)

Since the ladder is in equilibrium, the sum of the torques must be zero. Therefore, the torque exerted by the hydraulic piston should be equal and opposite to the torque exerted by the ladder's weight.

The torque exerted by the ladder's weight = 0 (since it acts at the center of gravity)

Therefore, we can set up the equation:

The torque exerted by the hydraulic piston = Torque exerted by the ladder's weight

F * 8.0 m * sin(40°) = 0

Solving for F:

F = 0 / (8.0 m * sin(40°))

F = 0

This means that the force exerted by the hydraulic piston must be zero for the ladder to be in equilibrium. However, in practical situations, a force would be required to lift and hold the ladder in position. This calculation assumes idealized conditions without considering external factors such as friction, structural constraints, or additional forces.

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Impulse is an important concept in many areas of physics, including mechanics, electromagnetism, and quantum mechanics.

It is also used in engineering and technology, such as in the design of airbags and other safety systems that are designed to protect people from the effects of sudden changes in momentum. In physics, impulse refers to the change in momentum of an object caused by a force acting on it for a period of time. It is a vector quantity that is equal to the force applied multiplied by the time for which it acts.

The formula for impulse is:

Impulse = Force x Time

or

J = F x Δt

where J is the impulse, F is the force applied, and Δt is the time for which the force is applied.

Impulse is closely related to momentum, which is the product of an object's mass and velocity. According to Newton's second law of motion, the change in an object's momentum is equal to the force applied to it, multiplied by the time for which it acts.

By applying a force over a period of time, impulse can increase or decrease the momentum of an object. For example, when a baseball bat hits a ball, the force applied by the bat over a short period of time creates a large impulse that changes the ball's momentum and sends it flying through the air.

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Answer:

1) 2,641,895.5 m

2) 1.85903476 × 10⁻⁹ kg

3) 9.32 C

4) 38.7 kg

Explanation:

1) The gravitational force of attraction between the object and the mass of the Earth is given by the following formula;

\(F} =G\dfrac{M_{1} \cdot m_{2}}{R^{2}} = m_2 \times g\)

Where;

M₁ = The mass of the Earth = 5.97 × 10²⁴

m₂ = The mass of the object

G = The universal gravitational constant

R = The radius of the Earth = 6,378,100 m

g = The acceleration due to gravity = 9.8 m/s²

By comparison, we have;

\(\dfrac{G \cdot M_{1}}{R^{2}} = g\)

When the object is r meters away, g is halved, therefore, we have;

\(\dfrac{G \cdot M_{1}}{r^{2}} = \dfrac{g}{2} =\dfrac{G \cdot M_{1}}{\left (2\times R^{2}\right )}\)

Therefore, r² = 2·R² = 2 × (6,378,100 m)² = 8.13603192 × 10¹³ m²

r = √(8.13603192 × 10¹³ m²) = 9019995.52217 m

The distance of the object from the surface of the Earth = 9,019,995.52217 - 6,378,100 = 2,641,895.52217 m ≈ 2,641,895.5 m

The object needs to be approximately 2,641,895.5 m from the Earth's surface to experience half of the acceleration due to gravity experienced on the Earth's surface

2) The electrostatic force between the charges = k×q²/r²

Where;

q = 1.602 × 10⁻¹⁹ C

r = Distance between the charges

k = Coulomb constant = 8.9875517923 × 10⁹ kg·m³·s⁻²·C⁻²

We have;

The electrostatic force between the charges = 8.9875517923 × 10⁹ × (1.602 × 10⁻¹⁹)²/r²

The gravitational force between the charges = 6.67408 × 10⁻¹¹ × m²/r²

Given that the ratio between the two forces = 1, we have;

(8.9875517923 × 10⁹ × (1.602 × 10⁻¹⁹)²/r²)/(6.67408 × 10⁻¹¹ × m²/r²) = 1

∴ m² = (8.9875517923 × 10⁹ × (1.602 × 10⁻¹⁹)²)/(6.67408 × 10⁻¹¹) = 3.4560102×10⁻¹⁸ kg²

The mass m = √(3.4560102×10⁻¹⁸ kg²) = 1.85903476 × 10⁻⁹ kg

The mass of each particle will be 1.85903476 × 10⁻⁹ kg

3)  F = k×q²/r²

q² = F × r²/k

Which gives;

q² = 50 × 125000²/(8.9875517923 × 10⁹) ≈ 86.93 C²

q = √86.93 ≈ 9.32 C

The charges of each object = 9.32 C

4) \(F} =G\dfrac{m^2 }{r^{2}}\)

r = 0.25 cm = 0.0025 m

F = 0.016 N

G = 6.67408 × 10⁻¹¹ m³·kg⁻¹·s⁻²

Therefore;

m² = F·r²/G = 0.016 × (0.0025)²/(6.67408 × 10⁻¹¹) ≈ 1498.334 kg²

m = √(1498.334 kg²) ≈ 38.7 kg

The mass of each object = 38.7 kg.

The Coulomb and gravitational laws together with Newton's second law allow to find the results for the questions are:

    1) The distance where the acceleration of gravity measures half its value on earth is;  r’= 2.64 106 m

    2) The mass of the particle is:   m = 1.86 10-9 kg

    3) The charge of the particles is:   q = 9.32 C

    4) The mass is:   m = 38.7 kg

Part 1

The Universal Gravitational Law says that the force between two objects is proportional to their masses and inversely proportional to the square of their distance

     F =\(-G \frac{Mm}{r^2}\)  

Where F is the gravitational force, G the gravitational constant, M and m the mass of the two bodies and r the distance between them.

They ask to calculate the distance to the point where the acceleration is half that of the gravitation acceleration at the earth's surface.

            a = g / 2

If we use Newton's second law that gives the relationship between the net force, the mass and the acceleration of the body.

          F = m a

Let's substitute

        \(-G \frac{Mm}{r^2} = m \frac{g}{2}\)  

         r² = \(\frac{2GM}{g}\)  

Let's calculate

        r² = \(\frac{2 \ 6.67 \ 10^{-11} \ 5.97 \ 10^{24} }{9.8}\)  

        r = \(\sqrt{81.360 \ 10^{12}}\)  

        r = 9.02 10⁶ m

This is the distance from the center of the earth, the distance measured from the surface of the planet is

       r = R + r '

       r ’= r- R

       r ’= 9.02 10⁶ - 6.378 10⁶

       r’= 2.64 10⁶ m

Part 2

Coulomb's law states that the electric force between two charged bodies is:  

      F = \(k \frac{q_1q_2}{r^2}\)

Where q₁ and q₂ are the charges of the leather and k is the Coulomb constant

They ask what mass the particles must have so that the electrostatic force (Fe) and the gravitational force (Fg) have been equal

Indicate the charges of the particles q₁ = q₂ = 1.602 10⁻¹⁹ C

Let's equalize the two forces

     \(F_e = F_g \\k \frac{q_1q_2}{r^2} = G \frac{m_1m_2}{ r^2 } \\k q^2 = G m^2\)

     \(m = \sqrt{\frac{k}{G} } \ q\)  

     m = \(\sqrt{\frac{8.99 \ 10^9 }{ 36.67 \ 10^{-11}} } \ 1.602 \ 10^{-19}\)

     m =  \(\sqrt{1.3478 \ 10^{20} } \ 1.602 \ 10^{-19}\)  

    m = 1.86 10⁻⁹ kg

Part 3

They indicate that the electrostatic force between two objects is F = 50 N and the distance between them is r = 125 km = 125 103 m, they ask what is the charge of the objects.

Let's use Coulomb's law

        F = \(k \frac{q_1q_2}{r^2}\)  

        q² = \(\frac{F}{k} \ r^2\)  

        q² = \(\frac{50 \ (125 \ 10^3)^2 }{8.99 \ 10^9 }\)  

        q = \(\sqrt{86.93}\)  

        q = 9.32 C

Part 4

Indicate the gravitational force between two objects is F_g = -0.016 N when they are separateda distance  r = 0.25 cm = 0.25 10⁺² m, ask the mass of the bodies.

Let's use the law of universal gravitation.

      \(-G \frac{Mm}{r^2} \\m^2 = - \frac{F}{G} \ r^2\)

Let's calculate

      m² = \(- \frac{(-0.016) }{6.67 \ 10^{-11}} \ (0.25 \ 10^{-2})^2\)

     m = \(\sqrt{1498.33}\)  

     m = 38.7 kg

In conclusion using the Coulomb and gravitational laws together with Newton's second law we can find the results for the questions are:

   1) The distance where the acceleration of gravity measures half its value on earth is;  r’= 2.64 106 m

    2) The mass of the particle is:   m = 1.86 10-9 kg

    3) The charge of the particles is:   q = 9.32 C

    4) The mass is:   m = 38.7 kg

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The resistance decreases when the conducting wire is quadrupled in length and tripled in diameter.

The electrical resistance of a circuit component or tool is defined as the ratio of the voltage applied to the electric present day which flows thru it: If the resistance is consistent over a widespread variety of voltage, then Ohm's regulation, I = V/R, may be used to predict the behavior of the fabric.

An less difficult way to explain resistance is to don't forget an example of someone in a crowded marketplace struggling to go from one keep to every other. This situation is in reality similar to an electron looking to make its way thru a wire.

If the temperature and different bodily variables stay constant, the resistance of a conductor is exactly proportional to its period.

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Given data:

Mass of ball is,

Magnitude of initial velocity of ball is,

Direction of initial velocity of ball with respect to x-axis is,

Magnitude of initial velocity of embeds is,

Direction of initial velocity of embeds with respect to x-axis is,

Formula of momentum is as follows:

Initial momentum of ball,

Component of velocity of ball along x-axis is as follows:

Substitute known values above equation,

Component of velocity of ball along y-axis is as follows:

Therefore, momentum of ball is as follows:

Component of velocity of embeds along x-axis,

Component of velocity of embeds along y-axis,

Initial momentum of embeds is as follows:

Part-B:

After collision if both objects are stick together, this type of collision is called plastic collision.

Momentum of system remains constant before plastic collision and after plastic collision.

Hence,

Substitute known values in above equation,

Polar form of momentum of combined mass is as follows:

Magnitude of momentum of combined mass is as follows:

Direction of momentum of combined mass,

Polar form of momentum,

Part-C:

Final velocity of system is as follows:

Magnitude of final velocity is as follows:

Direction of final velocity with respect to x-axis,

Polar form of final velocity,

Answer: Find the answer in the explanation

Explanation:

The music playing on the radio will be heard through the sound waves coming from the radio.

The travelling wave will obey Newton's first law of motion which state that:

An object or particle will remain at rest or continue its linear motion in a straight line except an external force is applied.

The external force through wind could affect the travelling of the sound waves. Since the wave is longitudinal wave. That is, it needs a medium (air) for its propagation.

Answer:

Length contraction

A moving object traveling at a velocity approaching the speed of light will appear to be shorter or to have undergone contraction.

The proportion by which the object is observed to have contracted is given by Lorentz transformation as follows;

\(L = L_{0}\cdot \sqrt{1 -\dfrac{v^{2}}{c^{2}}}= \dfrac{L_{0}}{\gamma }\)

Time dilation

As the relative speed of motion of an object approaches the speed of light, the clock in the frame in motion will be observed to be moving slowly or dilated in a proportion given by Lorentz transformation as follows;

\(T = \dfrac{T_{0}}{\sqrt{1 -\dfrac{v^{2}}{c^{2}}}}\)

Explanation:

Example of length contraction example

Two square boxes of side length L which are travelling at a velocity of 0.9 × c, are going to arranged in a single box of side side length  L according to length contraction Lorentz transformation, to  stationary observer we have

\(2 \times L\cdot \sqrt{1 -\dfrac{(0.9 \cdot c)^{2}}{c^{2}}}= 0.8 \cdot L\)

To the stationary observer, the 2 boxes of length L will fit side by side in the single box of length L, while to those on the space ship carrying the boxes, the size of the single box is  \(L\cdot \sqrt{1 -\dfrac{(0.9 \cdot c)^{2}}{c^{2}}}= 0.4 \cdot L\), which will not contain half of one box

Example of of time dilation example

Twin A of two twins, twin A and B went on a space journey at the speed of 0.87·c for 5 years, the number of years past for twin B when they meet again will be \(T = \dfrac{5}{\sqrt{1 -\dfrac{(0.87\cdot c)^{2}}{c^{2}}}} = 10.14 \ years\)

The frequency of the third harmonic is approximately 1416.7 Hz (option a).

The frequency of the third harmonics of a closed pipe can be calculated using the formula:

f = (2n + 1) * (v / 4L)

Where:
f = frequency of the harmonic
n = harmonic number (n = 2 for the third harmonic)
v = speed of sound in air (340 m/s)
L = length of the closed pipe (0.3 m)

Using the given values, we can calculate the frequency:

f = (2 * 2 + 1) * (340 / 4 * 0.3)
f = (5) * (340 / 1.2)
f = 5 * 283.3333

f ≈ 1416.7 Hz

So, the frequency of the third harmonic is approximately 1416.7 Hz (option a).

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In addition to a proper air void system and strength level, a concrete mixture must contain durable aggregates in order to perform adequately in a freeze-thaw service environment. The correct option is (c) .

Aggregates are the primary component in concrete and provide bulk and strength to the mixture. The durability of aggregates is critical in freeze-thaw environments, as the expansion and contraction caused by the freeze-thaw cycle can cause the aggregates to crack or break down, leading to deterioration of the concrete. Therefore, it is important to use high-quality and durable aggregates in concrete mixtures designed for freeze-thaw service environments.Aggregates are an essential component of concrete and play a crucial role in its performance. Durable aggregates help enhance the resistance of concrete to the damaging effects of freeze-thaw cycles, ensuring its durability and longevity in such environments.Therefore option C is correct.

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The tension in the rope is 150 N.

The tension in the rope would be 150 N.

What are the given values?

Given,Mass of the engine = 135 kg

Mass of the pulley system = 6.65 kg

Acceleration due to gravity = 9.8 m/s²

Formula to calculate tension,T = m(g + a)

Where,T is the tension in the rope,m is the mass of the engine, and

a is the acceleration of the system.Here, the pulley system is at rest.

So, acceleration of the system is zero. Hence,a = 0

Substituting the given values in the above formula,T = 135 kg × (9.8 m/s² + 0)T = 1323 N

Now, the pulley system multiplies the tension by a factor of two.

Tension in the rope,T = 1323/2 N = 661.5 N= 662 N

Therefore, the tension in the rope is 150 N.

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Answer:

Current in first junction R1, R2 = 5 amps

Since current thru R2 = 3 amps the current thru R1 = 2 amps

V1 = V = I1 R1 = 15 volts

R1 = 15 volts / 2 amps = 7.5 ohms

Answer:

Since it us the resistance that causes the power output, it might be intuitive to think that more resistance produces more power but as P=I^2 * R one actually needs high current and low resistqnce. That means 75 W has lower resistance and higher current.

Now you may think that making the resistance very low, one gets the most power. Not so, as the circuit has wires, power source etc. All the have their resistance. In theory one gets the maximum power over a resistor when the resistor is half of the total resistance of the circuit. This in practice would be inefficient as one would lose half of the total power elsewhere. In practice circuits have fuses that limit the current and one gets the maximum power at the current the fuse is rated to. So if there is 20 A fuse, the maximum power is 2400 W and the corresponding resistance 6 ohm.

Answer:

Force = 3 Newton

Explanation:

Given the following data;

Mass = 200 g to kilograms = 200/1000 = 0.2 kg

Acceleration = 15 m/s²

To find the force;

Force = mass * acceleration

Force = 0.2 * 15

Force = 3 Newton