PLS HELP! QUESTION (2/2)
Two blocks, one of mass 1.00 kg and 4.00 kg are tied together with a massless rope as in the image. This rope is strung over a massless, resistance-free pulley. The blocks are released from rest. Find the tension in the rope and the acceleration of the blocks.

Answer:

\(\boxed {\boxed {\sf 157.5 \ Joules }}\)

Explanation:

Work is equal to the product of force and distance.

\(W=F*d\)

The box is being pushed with an effort (force) of 45 Newtons and the distance is 3.5 meters.

\(F= 45 \ N \\d= 3.5 \ m\)

Substitute the values into the formula.

\(W= 45 \ N * 3.5 \ m\)

Multiply.

\(W= 157.5 \ N*m\)

\(W= 157.5 \ J\)

157.5 Joules of work are done on the crate.

Answer: Various wavelengths emitted by an excited substance

Explanation:

Answer:

i think its A

Explanation:

Answer:

zero

Explanation:

Answer:

the orbital speed of umbriel is 16,800 km/h

Explanation:

The computation of the orbital speed is shown below

According to the question the Data provided in the question

Uranus mass = 8.68 × 10^25 kg

Distance = 2.66 × 10^8 m

Based on the above information, the orbital speed of Umbriel is

\(V = \sqrt{\frac{GM}{R} } \\\\ = \sqrt{\frac{((6.673e-11)(8.68e25)}{2.66e8} }\)

V = 4666 m/s

= 16,800 km/h

Hence, the orbital speed of umbriel is 16,800 km/h

Therefore it can be calculated by applying the above formula

Answer: 4665

Explanation: I got it right after on acellus

The term you are looking for is "chemical battery". Chemical batteries work by converting chemical energy into electrical energy through a series of chemical reactions. These reactions take place within the battery's cells, which are composed of two electrodes and an electrolyte.

When the battery is connected to a circuit, the chemical reactions produce an electrical current that can be used to power devices. Chemical batteries are widely used in many applications, including consumer electronics, electric vehicles, and renewable energy systems. They are a crucial component of our modern technological society, and ongoing research is focused on developing more efficient and sustainable battery technologies to meet growing energy demands.

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The binary search will perform the maximum number of comparisons by diving it into two halves the elements would be 10000.

A relatively space-efficient data structure that permits adding components and membership verification very quickly is the binary array set. Essentially, it functions as a set of sorted arrays of power-of-2 sizes.

The binary array is performed by dividing the elements into two halves then the binary search will perform the maximum number of comparisons by diving it into two halves the elements would be 10000.

Therefore, the maximum number of comparisons by diving it into two halves of the elements would be 10000.

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Answer:

Velocity

Explanation:

The given rod is AMCD made of aluminum with the modulus of elasticity of E=70 GPa. The deflection of point D is 0.13 mm.

The load applied is such that the deflection of the rod has to be calculated at points A and D respectively.

(a) Deflection at point A:

Let P be the load acting at point A.

Let the deflection at point A be δ.

Then, from the theory of elasticity,δ = PL/2AEQ 2.16

Thus,δ = 20 × 0.75^3/(2 × 70 × 10^3 × (π/4) × 0.75^4)

= 0.195 mm

Therefore, the deflection of point A is 0.195 mm.

(b) Deflection at point D:Let the deflection at point D be δ.Then, from the theory of elasticity,

δ = PL/3AEQ 2.16

Thus,

δ = 20 × 0.75^3/(3 × 70 × 10^3 × (π/4) × 0.75^4)

= 0.13 mm

Therefore, the deflection of point D is 0.13 mm.

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Radio waves travel at the speed of light.

Radio waves move at the speed of light in a vacuum, as do all electromagnetic waves, and at a nearly identical but slightly slower speed in the Earth's atmosphere.

The longest wavelengths in the electromagnetic spectrum are found in radio waves, which typically have frequencies of 300 gigahertz (GHz) and lower.

Similar to light, X-rays, and other forms of radiation, radio waves are an electromagnetic radiation with much longer wavelengths.

As a result, they move much more quickly than sound itself through the air, which moves at a speed of 340 metres (1,125 feet) per second (or the speed of light, or 300,000 kilometers/186,000 miles per second).

It's simple to be deceived because when you hear the word "radio," you typically think of voices or music. 

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Answer:

artist

Explanation:

Answer:

don t know

Explanation:

The kinetic energy lost as a result of collision is approximately 0.066 J.

The problem involves two carts on an air track. The first cart, with a mass of 0.34 kg and an initial speed of 0.80 m/s, collides with and sticks to the second cart, which is initially at rest and has a mass of 0.45 kg. We need to determine how much kinetic energy is lost as a result of the collision.

To solve this, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

The momentum of an object is given by the product of its mass and velocity. So, before the collision, the momentum of the first cart is (0.34 kg) * (0.80 m/s) = 0.272 kg·m/s. Since the second cart is at rest, its momentum before the collision is zero.

After the collision, the two carts stick together and move as a single object. Let's call their final velocity \(v_f\).

Using the conservation of momentum, we have:

\((0.34 kg + 0.45 kg) * v_f = 0.272 kg.m/s\)

Simplifying, we get:

\(v_f = 0.272 kg.m/s / (0.34 kg + 0.45 kg)\)

\(v_f = 0.272 kg.m/s / 0.79 kg\)

\(v_f = 0.344 m/s\)

The kinetic energy before the collision is given by \((1/2) * (0.34 kg) * (0.80 m/s)^2 = 0.1088 J.\)

The kinetic energy after the collision is given by \((1/2) * (0.34 kg + 0.45 kg) * (0.344 m/s)^2 = 0.0424 J.\)

The kinetic energy lost as a result of the collision is the difference between the initial and final kinetic energies:

\(0.1088 J - 0.0424 J = 0.0664 J\)

Rounded to two significant figures, the energy lost is 0.066 J

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Projectile motion is a combination of horizontal and vertical types of motion.

Projectile motion is a form of motion experienced by an object or particle that is projected near Earth's surface and moves along a curved path under the action of gravity only. Objects experiencing this motion have a constant velocity in the horizontal direction, and a constantly changing velocity in the vertical direction. Types of Projectile Motion are Oblique projectile motion, Horizontal projectile motion and Projectile motion on an inclined plane.

Therefore, third option is the correct answer.

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Answer: The magnitude of B+Q is √69 and the magnitude of B-Q is √41.

Explanation:

Let's calculate the magnitude of B+Q and B-Q.

First, we'll start with B+Q. We know that B is equal to 3i + 4j and Q is equal to 5i - 2j + 1k. So, to find B+Q, we simply add the corresponding components of B and Q:

(3i + 4j) + (5i - 2j + 1k) = 8i + 2j + 1k

To find the magnitude of B+Q, we use the Pythagorean theorem, just like we would in finding the distance between two points in a plane. But since we have three dimensions (i, j, and k), we have to square the values of 8i, 2j, and 1k and add them up, and then take the square root of the result.

The magnitude of B+Q is √(8^2+2^2+1^2) = √(64+4+1) = √69

Now, let's move on to B-Q. We know that B is equal to 3i + 4j and Q is equal to 5i - 2j + 1k. So, to find B-Q, we subtract the corresponding components of Q from B:

(3i + 4j) - (5i - 2j + 1k) = -2i + 6j - 1k

To find the magnitude of B-Q, we again use the Pythagorean theorem, just like we would in finding the distance between two points in a plane. But since we have three dimensions (i, j, and k), we have to square the values of -2i, 6j, and -1k and add them up, and then take the square root of the result.

The magnitude of B-Q is √((-2)^2+6^2+(-1)^2) = √(4+36+1) = √41

And there you have it! The magnitude of B+Q is √69 and the magnitude of B-Q is √41.

It takes the ball 3.06 seconds to reach its highest point

The time it takes for a ball to reach its highest point is given by the equation:

t = v / g

where

In this case, the initial velocity is 30.0 m/s and the acceleration due to gravity is \(9.8 m/s^2\). Therefore, the time it takes for the ball to reach its highest point is:

\(t = 30.0 m/s / 9.8 m/s^2 = 3.06 s\)

Therefore, it takes the ball 3.06 seconds to reach its highest point.

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Answer:

The magnitude of the net electric field is:

\(E_{net}=90.37\: N/c\)

Explanation:

The electric field due to q1 is a vertical positive vector toward q1 (we will call it E1).

On the other hand, the electric field due to q2 is a horizontal positive vector toward q2(We will call it E2).

Knowing this, the magnitude of the net electric field will be the E1 + E2.

Let's find first E1 and E2.

The electric field equation is given by:

\(|E_{1}|=k\frac{|q_{1}|}{d_{1}^{2}}\)

Where:

\(|E_{1}|=(9*10^{9})\frac{|-2.60*10^{-9}|}{0.538^{2}}\)

\(|E_{1}|=80.84\: N/C\)

And E2 will be:

\(|E_{2}|=k\frac{|q_{2}|}{d_{2}{2}}\)

\(|E_{2}|=(9*10^{9})\frac{|-8.30*10^{-9}|}{1.36^{2}}\)

\(|E_{2}|=40.39\: N/C\)

Finally, we need to use the  Pythagoras theorem to find the magnitude of the net electric field.

\(E_{net}=\sqrt{E_{1}^{2}+E_{2}^{2}}\)

\(E_{net}=\sqrt{80.84^{2}+40.39^{2}}\)

\(E_{net}=90.37\: N/c\)

I hope it helps you!

Answer:

+90.3 N/C

Explanation:

acellus

The number of joules per coulomb for 120-volt circuit is 120 joules/C.

The amount of energy transferred to each unit of charge is given by the voltage or potential difference between two points.

The unit of potential difference is the volt, which is equivalent to one joule per coulomb.

So if we have a 120-volt circuit, each coulomb of charge that flows between two points receives 120 joules of energy.

Energy per unit charge = Potential difference

= 120 volts

= 120 joules/coulomb

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Answer:

He used the probability assumption

The impact speed will be

v^2 = 2*9.8*1.3

v^2 = 25.48

v= 5.04 m/s or O C. 5.0 m/s

A) The wavelength of the sound wave corresponding to the note G5 on a piano is approximately 0.439 meters.

B) Each vibration of the sound wave takes approximately 1.28 milliseconds.

C) The wavelength of the sound wave one octave higher than the note in part A is approximately 0.219 meters.

(A) The formula to calculate the wavelength (λ) of a sound wave is:

λ = v/f

where v is the speed of sound and f is the frequency of the sound wave.

Substituting v = 344 m/s and f = 784 Hz, we get:

λ = 344 m/s / 784 Hz ≈ 0.439 m

(B) The time period (T) of a sound wave is the time taken for one complete vibration or cycle. It is related to the frequency (f) by the formula:

T = 1/f

Substituting f = 784 Hz, we get:

T = 1 / 784 Hz ≈ 0.00128 seconds

To convert seconds to milliseconds, we multiply by 1000:

T ≈ 1.28 milliseconds

(C) One octave higher than the note G5 on a piano would have a frequency of 1568 Hz (i.e., double the frequency of G5). Using the same formula as in part A, we can calculate the wavelength of the corresponding sound wave:

λ = 344 m/s / 1568 Hz ≈ 0.219 m

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The obvious differences between the beam observations and cylinder observations are that the maximum value of the cylinder observations is higher and the observations for cylinders are more variable or spread out.

In the above case, the material strength observations in Mega Pascals for cylinder and beams are given.

The values for cylinders are as follows

6.1, 5.8, 7.8, 7.1, 7.2, 9.2, 6.6, 8.3, 7.0, 8.3, 7.8, 8.1, 7.4, 8.5, 8.9, 9.8, 9.7 14.1, 12.6 11.2, 8.1, 7.4, 8.5, 8.9, 9.8, 9.7, 14.1, 12.6, 11.2

And the values for beams are

5.9, 7.2, 7.3, 6.3, 8.1, 6.8, 7.0, 7.6, 6.8, 6.5, 7.0, 6.3, 7.9, 9.0, 8.2 , 8.7, 7.8, 9.7, 7.4, 7.7, 9.7,7.8, 7.7, 11.6 11.3 11.8 10.7,8.2, 8.7, 7.8, 9.7, 7.4, 7.7, 9.7, 7.8, 7.7, 11.6, 11.3, 11.8, 10.7

From the above-given values, we can calculate the mean/average value of the observations.

The average value for cylinders comes out to be 8.57.

The average value for beams comes out to be 8.14.

Among the given values, the maximum value is 14.1 for cylinder observations.

The values of beam observations range from 5.9 to 11.8 while the values for cylinder observations range from 5.8 to 14.1. Therefore, the observations for the cylinder are more variable or spread out.

Thus, the maximum value of the cylinder observations is higher and the observations for cylinders are more variable or spread out.

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This question is incomplete. The data used for solving the question is given in the adjoining image.

Answer: Oceanic crust, the outermost layer of Earth's lithosphere that is found under ... Sort out the facts and see how deep your knowledge goes in this quiz of the world's oceans. ... They commonly are thin (only about 10 cm [4 inches] thick) and cover a ... km (85 square miles) of seafloor to an average depth of 70 metres (230 feet).

Explanation:

The gravitational force of Earth on the satellite, given that the satellite is launched into orbit 30000 km above sea level is 1.63×10³ N

The gravitaional force between two objects can be obtained by using the following formula:

F = GM₁M₂ / r²

Where

The following data were obtained from he question:

The gravitaional force can be obtained as shown below:

F = GM₁M₂ / r²

F = (6.673×10¯¹¹ × 5.4×10³ × 6.0×10²⁴) / (36400000)²

F = 1.63×10³ N

Thus, the gravitational force is 1.63×10³ N

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Answer:

X is ammeter and Y is voltmeter

Explanation:

The resistance of a wire is directly proportional to the length of the wire. That is the longer the length of the wire, the higher the resistance and the shorter the length of the wire, the smaller the resistance.

Ammeter is a measuring instrument used to measure the current in a circuit by connecting the meter in series with the circuit.

Ammeter is a measuring instrument used to measure the potential difference between two points by connecting the meter in parallel to the points.

Meter X is an ammeter since it is connected in series and meter Y is a voltmeter because it is connected in parallel.

The electric field does a work of 1.98 × 10^-17 J (joules) in moving a proton from a point having a potential of 120 V to a point where it is -75 V.

A proton is an electrically charged particle that has a positive charge. It is assumed to have a charge of +1.602 × 10^-19 coulombs. Electric potential, also known as voltage, is the quantity that measures the electric potential energy per unit charge that a test particle would have if located at a specific point in an electric field. It is expressed in volts. The formula for electric potential difference or voltage is given by V = W/Q, where V is voltage, W is work, and Q is charge.In this case, we have to determine how much work the electric field does in moving a proton from a point having a potential of 120 V to a point where it is -75 V.

Since we have a charged particle, we can use the formula W = Q × V to calculate work.

Therefore, the work done by the electric field is given by:W = Q × ΔV where Q = 1.602 × 10^-19 C

∆∆V = -75 V – 120 V = -195 V

Thus,W = 1.602 × 10^-19 C × (-195 V)

W = -3.12 × 10^-17 J

Therefore, the electric field does a work of 1.98 × 10^-17 J (joules) in moving a proton from a point having a potential of 120 V to a point where it is -75 V. The elec

ric field does a work of 1.98 × 10^-17 J in moving a proton from a point having a potential of 120 V to a point where it is -75 V.

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Answer:

A

Explanation:

The Total time taken for the signal to be transmitted and received after reflecting is 0.261 seconds.

Speed of sound in seawater = 1530m/s.

Total distance travelled by the sound = 200m [ toward fish ] + 200m [ away                                                                                                            from fish ]

Total distance = 400m

As, Speed = \(\frac{ Total Distance}{Total Time}\)

     Total Time = \(\frac{Total Distance}{Speed}\)

     Total Time = \(\frac{400}{1530}\)

  ∴ Total time = 0.261 second

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Gauge pressure required in city water mains for a stream is 147,150 Pa

In fluid mechanics, Bernoulli's principle states that an increase in fluid velocity occurs simultaneously with a decrease in pressure or a decrease in the fluid's potential energy. This principle is named after the Swiss mathematician Daniel his Bernoulli published it in his 1738 book Fluid Mechanics.

According to the Bernoulli's Equation:

P₁ + ρgy₁ + (\(\frac{1}{2}\))ρv₁² = P₂ + ρgy₂ + (\(\frac{1}{2}\))ρv₂²

where, y₁ =  initial height

y₂ = final height

Initial height is 0 meters and final height is 15 meters.

The problem states that the mains have a much larger diameter than the hose, so v₁ = 0

Once our water reaches a 15 m. altitude, it stops going anymore higher. Therefore, v₂ also be 0.

P₁  = P₂ + ρgy₂

Since, we are solving for gauge pressure, we can assume that the pressure at the top of our column of water is zero.

P₁  = ρgy₂

P₁  = 1000 × 9.8 × 15

P₁  = 147,150 Pa

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