Pls look at the photo and help me! ASAP! Luv you guys <3

Answer:

8, 10, 15, 16, 17, 17, 22

16 is the median

Step-by-step explanation:

Answer:

median is 16

Step-by-step explanation:

Answer:

-162

Step-by-step explanation:

that the answer

Answer:

-162

Step-by-step explanation:

Multiply: −4 + [12 × (−8)] – 62

Remover parentheses: -4 + (-96) – 62

Calculate sum: -4 – 96 – 62

Answer:what is the question

Step-by-step explanation:

Answer:

ok i dont see a question but if you post another question i will answer it

Step-by-step explanation:

Answer:

7295

Step-by-step explanation:

The first thing we can do is rule out any numbers that cannot be divided by 5. Any number that ends in a 0 or a 5 can, so 627 cannot be. The next thing we do is use the division rule for dividing by 3. The rule states that if you add up the digits of a number, and it is divisible by 3, then so is that number.

2+8+5= 15 (multiple of 3)

5+4+9+0=18 (multiple of 3)

7+2+9+5=23 (not a multiple of 3)

4+3+6+9+5=27 (multiple of 3)

Hope you have a great day!

If one mass increases by a factor of 6 and the other mass increases by a factor of 1.5, the distance between them would need to be adjusted to maintain the same gravitational force as before. To calculate the new distance, we can use the inverse square law of gravitational force.

According to the inverse square law of gravitational force, the force (f) between two masses is given by the equation f = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses, and r is the distance between them.

To maintain the same force, we need to adjust the distance (r) between the masses. Let's assume the original distance is represented by r_0. The masses can be denoted as m1_0 and m2_0 initially, and m1_f and m2_f after the increase.

To find the new distance (r_f), we can set up the equation (G * (m1_0 * m2_0) / r_0^2) = (G * (m1_f * m2_f) / r_f^2). Since the gravitational constant and the masses remain the same, we can simplify the equation to (m1_0 * m2_0) / r_0^2 = (m1_f * m2_f) / r_f^2.

Given that one mass increases by a factor of 6 (m1_f = 6 * m1_0) and the other mass increases by a factor of 1.5 (m2_f = 1.5 * m2_0), we can substitute these values into the equation and solve for the new distance. Rearranging the equation, we have (m1_0 * m2_0) / r_0^2 = (6 * m1_0 * 1.5 * m2_0) / r_f^2.

Simplifying further, we find r_f^2 = (6 * 1.5) * r_0^2, which can be written as r_f = sqrt(9) * r_0. Therefore, the masses need to be placed at a distance that is 3 times the original distance (r_f = 3 * r_0) to experience the same gravitational force as before.

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The rectangular pice has a wide of 24 inches and 40 inches long so we can calculate the area of the rectangle:

Now they say that Lenna folds the piece of fabric along its diagonal so the triangle will have halve of the area of the triangle, so que so we can divide the area of the trangle by 2

So the triangle has an area o

Answer:

24

Step-by-step explanation:

5+5+7+7

Answer:

24 feet

Step-by-step explanation:

7 times 2 is 14

5 times 2 is 12

14 plus 12 is 24

Answer:

118

Step-by-step explanation:

The sequence is adding 6 to each number to get the next

4, 10, 16, 22, 28, 34, 40, 46, 52, 58, 64, 70, 76, 82, 88, 94, 100, 106, 112, 118, 124, 130

Answer:

for A

the law

V=Bh or V=πr2h

I will use this V=Bh

V= 16·21

V= 336cm³

For E

the law

A= 1/2·(A + B)·H

A= 1/2·(14 + 8)·4

A= 44cm²

V= A·H

V= 44·4

V= 176 cm³

make a search for each one :

B. triangular prism volume calculator

C. pyramid prism volume calculator

D. rectangular prism volume calculator

F. cube volume calculator

The 98% confidence interval of 93 course evaluation the estimation of the population standard deviation is (0.454, 0.681). For 93 professor evaluations, it is (0.318, 0.457). The course evaluations have a wider interval, indicating more variability compared to professor evaluations.

The construction of 98% confidence interval from which the 93 course evaluations were obtained, by using the formula

Confidence interval = (√((n-1)*s²)/√(chi-square upper)-√((n-1)*s²)/√(chi-square lower)),

where n is the sample size, s is the sample standard deviation, and chi-square upper and chi-square lower are the values from the chi-square distribution table with degrees of freedom (df) equal to n-1 and a cumulative probability of 0.99/2 = 0.495.

Using the given data, we have n = 93 and s = 0.56. From the chi-square distribution table with df = 92 and cumulative probability of 0.495, we obtain chi-square upper and chi-square lower as 67.339 and 49.645, respectively.

putting the values in the formula, we get

Confidence interval = (√((93-1)*0.56²)/√(67.339)-√((93-1)*0.56²)/√(49.645))

Confidence interval = (0.454, 0.681)

Therefore, we are 98% confident that the standard deviation of the population from which the 93 course evaluations were obtained falls within the interval (0.454, 0.681).

To construct a 98% confidence interval estimate of the standard deviation of the population from which the 93 professor evaluations were obtained, we can use the same formula as in above part, but with n = 93 and s = 0.41 (the sample standard deviation for professor evaluations).

From the chi-square distribution table with df = 92 and cumulative probability of 0.495, we obtain chi-square upper and chi-square lower as 67.339 and 49.645, respectively.

putting the values in the formula, we get

Confidence interval = (√((93-1)*0.41²)/√(67.339)-√((93-1)*0.41²)/√(49.645))

Confidence interval = (0.318, 0.457)

Therefore, we are 98% confident that the standard deviation of the population from which the 93 professor evaluations were obtained falls within the interval (0.318, 0.457).

Comparing the results from other parts, we can see that the confidence interval for the standard deviation of the population from which the course evaluations were obtained is wider than that for the population from which the professor evaluations were obtained. This suggests that there is more variability in the course evaluations than in the professor evaluations.

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Answer: C

Step-by-step explanation: The slope of Function A is 6 and the slope of Function B is 5.

Answer:

Cost after markup = $62.05

Cost after discount = $29.18

Step-by-step explanation:

It is given that:

Cost of lizard = $36.50

Mark up = 70% = 70/100 = 0.7

Markup = 0.7 * 36.50

Markup = $25.55

Cost after markup = 36.50 + 25.55 = $62.05

Discount = 53%

Discount = 0.53 * 62.05

Discount = $32.87

Price after discount = 62.05 - 32.87 = $29.18

Therefore,

Cost after markup = $62.05

Cost after discount = $29.18

Answer:     40

Step-by-step explanation:

5/3    24/?

    divided by 8 =24 divided by 8 =3

                     5 x 8   =40  

Hope this helps :)

Answer:

40 girls

Step-by-step explanation:

Can't find vertical asymptotes.

No horizontal asymptotes.

Slant asymptotes:

y = 2x/5 , y = -2x/5 + ∞

What do you mean by asymptote?

Asymptote is a straight line that continuously approaches a given curve but does not meet at infinite distance. In other words, an asymptote is a line that approaches as the curve moves toward infinity. The curve follows these asymptote but never overtakes them. Asymptote or implicit form of the curve y = f(x):

Since f(x,y) = 0 is a straight line, the points on the curve tend to infinity, so the distance between the curve and the straight line tends to zero.

Given equation:

\(\frac{x^2}{25}-\frac{y^2}{4}=1\)

⇒ \(\frac{y^2}{4}=\frac{x^2}{25}-1\)

⇒ \(\frac{y^2}{4}=\frac{x^2-25}{25}\)

⇒ \(y^{2} = \frac{4}{25}(x^{2} -25)\)

⇒ \(y= \frac{2}{5}\sqrt{(x^2-25)}\)

⇒ \(f(x)= \frac{2}{5}\sqrt{(x^2-25)}\)

Vertical asymptotes can't find.

Line y = L is a horizontal asymptote of the function y = f(x), if either \(lim_{x \rightarrow \infty}\)f(x)=L or  \(lim_{x \rightarrow -\infty}\)f(x)=L, and L is finite.

\(lim_{x \rightarrow \infty}\) \(\frac{2}{5}\sqrt{(x^2-25)}\) = ∞

\(lim_{x \rightarrow -\infty}\) \(\frac{2}{5}\sqrt{(x^2-25)}\) = ∞

Thus, there are no horizontal asymptotes.

Line y =mx+b is a slant asymptote of the function y=f(x), if either m=\(lim_{x \rightarrow \infty}(\frac{f(x)}{x})\) = L or m=\(lim_{x \rightarrow -\infty}(\frac{f(x)}{x})\) = L  and L is finite and nonzero.

\(lim_{x \rightarrow \infty}(\frac{2\sqrt{x^2-25} }{5x}) =\frac{2}{5}\)

Since the value of the limit is finite and nonzero, then there is a slant asymptote with m= 2/5

To calculate b, find b= \(lim_{x \rightarrow \infty}\)(-mx+f(x)) = \(lim_{x \rightarrow \infty}\) (\(\frac{-2x}{5}-\frac{2\sqrt{x^2-25} }{5}\)\()\) = 0

Therefore, the slant asymptote is y = 2x/5

Calculate the second limit:

\(lim_{x \rightarrow -\infty}(\frac{2\sqrt{x^2-25} }{5x}) =\frac{-2}{5}\)

Since the value of the limit is finite and nonzero, then there is a slant asymptote with m= -2/5

To calculate b, find b= \(lim_{x \rightarrow -\infty}\)(-mx+f(x)) = \(lim_{x \rightarrow \infty}\) (\(\frac{2x}{5}-\frac{2\sqrt{x^2-25} }{5}\)\()\) = ∞

Therefore, the slant asymptote is y = -2x/5 + ∞

Therefore, Can't find vertical asymptotes.

No horizontal asymptotes.

Slant asymptotes:

y = 2x/5 , y = -2x/5 + ∞

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Answer:

x=23

Step-by-step explanation:

2x+3=49

2x=49-3

2x=46

x=23

Step-by-step explanation:

Question 9:

Hypotenuse = 7

Leg = Hypotenuse / √2 = 7/√2 = 7√2 / 2.

Therefore x = y = 7√2 / 2.

Question 10:

Leg = 10

Since x is also a Leg, x = 10.

Hypotenuse = Leg * √2 = 10√2. => y = 10√2.

Question 11:

Leg = 7

Since x is also a Leg, x = 7.

Hypotenuse = Leg * √2 = 7√2, => y = 7√2.

The displacement of the compressor is 628 cubic centimeters. Other factors that affect the performance of a compressor include its operating pressure, flow rate, efficiency, and power consumption.

To find the displacement of the compressor, we need to use the formula:
Displacement = (pi/4) x bore^2 x stroke
Here, the bore is 8 centimeters and the stroke is 10 centimeters. So, substituting these values in the formula, we get:
Displacement = (pi/4) x 8^2 x 10
Displacement = (3.14/4) x 64 x 10
Displacement = 628.32 cubic centimeters

A compressor is a mechanical device that is used to increase the pressure of a gas or air by reducing its volume. It works by compressing the gas or air in a cylinder and then transferring it to a storage tank or other equipment. The displacement of a compressor is a measure of the volume of gas or air that is displaced or compressed during one complete cycle of the compressor. Therefore, the displacement of the compressor is 628 cubic centimeters. This means that during one complete cycle of the compressor, it displaces or compresses 628 cubic centimeters of gas or air. The displacement is an important parameter of a compressor, as it determines its capacity or the amount of gas or air that it can compress in a given time.

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The displacement of the compressor is 160π cubic centimeters.

To find the displacement of the compressor, we first need to understand what displacement means. Displacement is the change in position of an object in a specific direction. In this case, the compressor has a bore of 8 centimeters and a stroke of 10 centimeters. The displacement of the compressor can be calculated as the product of the bore area (πr^2) and the stroke length.

Displacement = π(4^2) * 10 = 16π * 10 = 160π cubic centimeters.

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Therefore, the answer is option C: theta = pi/2 and theta = 3pi/2.

To determine when tan(theta) is undefined on the unit circle, we need to remember the definition of the tangent function.
Tangent is defined as the ratio of the sine and cosine of an angle. Specifically, tan(theta) = sin(theta)/cos(theta).

Now, we know that cosine can never be equal to zero on the unit circle, since it represents the x-coordinate of a point on the circle and the circle never crosses the x-axis. Therefore, the only way for tan(theta) to be undefined is if the cosine of theta is equal to zero.
There are two values of theta on the unit circle where cosine is equal to zero: pi/2 and 3pi/2.

At theta = pi/2, we have cos(pi/2) = 0, which means that tan(pi/2) = sin(pi/2)/cos(pi/2) is undefined.
Similarly, at theta = 3pi/2, we have cos(3pi/2) = 0, which means that tan(3pi/2) = sin(3pi/2)/cos(3pi/2) is also undefined.
Therefore, the answer is option C: theta = pi/2 and theta = 3pi/2.

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Unit rate

Answer:

$0.08 per minute

Step-by-step explanation:

Unit rate :

Answer:

p = -10

Step-by-step explanation:

-2(6p+5) = -6(p+5) - 8p

-12p-10 = -6p-30-8p

reduce

-12p-10 = -14p-30

add 10 to each side

-12p = -14p-20

add 14p to each side

2p = -20

p = -10

Answer:

2p+20

Step-by-step explanation:

-12p-10=-6p-30-8p

-12p-10=-14p-30

The statement provided does not hold true as the reasoning and conclusions drawn are incorrect.

The statement is incorrect. Let's break it down and explain why.

Given that gy(y, z) = 0, it implies that the partial derivative of the function g with respect to y is equal to zero. However, this does not necessarily imply that g(y, z) = h(z).

Similarly, the statement f(x, y, z) = 2xy²z³ + h(z) is not valid. It assumes that the function f can be expressed as the sum of the given term 2xy²z³ and another function h(z), which is not necessarily the case.

Lastly, f₂(x, y, z) = 0 + h'(z) does not follow logically. The notation f₂(x, y, z) is not well-defined or commonly used. Additionally, adding zero to the derivative of h(z) does not lead to a meaningful conclusion.

In conclusion, the statement provided does not hold true as the reasoning and conclusions drawn are incorrect.

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Answer:

A) 0.81; D. 0.79 ; E) 0.88

Step-by-step explanation:

This question is asking whether an event in more likely to occur than a different event. So we are looking for every event that is more likely occur, or in other words, greater than 0.78. The only 3 events that are greater than 0.78 are 0.81, 0.79, and 0.88.

The probability of winning $1000 a day for life is approximately 5.245 x 10^-11 and the probability of winning $1000 a week for life is approximately 1.07 x 10^-8. The probability of winning the jackpot ($1000 a day for life) is 1/(60^5 * 4), while the probability of winning $1000 a week for life is 1/(60^5).

In the Florida Lottery Cash4Life game, a player must select five numbers from 1 to 60 and then one Cash Ball number from 1 to 4. The jackpot prize is $1000 a day for life if all five numbers and the Cash Ball match the winning numbers drawn on Monday nights. If just all five numbers match the winning numbers, the player will win $1000 a week for life.
To determine the probability of winning $1000 a day for life, we can use the formula for the probability of independent events: P(A and B) = P(A) x P(B)

(a) To win the jackpot of $1000 a day for life, the player needs to match all five numbers and the Cash Ball. There are 60 options for each of the five numbers and 4 options for the Cash Ball. The total number of possible outcomes is 60^5 (60 choices for each of the five numbers) times 4 (for the Cash Ball). So the probability of winning the jackpot is 1/(60^5 * 4). (b) To win $1000 a week for life, the player needs to match only the five numbers, without considering the Cash Ball. The total number of possible outcomes for this scenario is 60^5. Therefore, the probability of winning $1000 a week for life is 1/(60^5).

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Answer:

4 seconds

===========================

Given is the

quadratic function

, which has a graph of parabola.

It has two

x-intercepts

, with the greater one representing the

projectile on the ground, at h(t) = 0

.

Let's

solve

the equation:

- 16t² + 32t + 128 = 0

t² - 2t - 8 = 0

t² - 2t + 1 - 9 = 0

(t - 1)² = 9

t - 1 = 3 and t - 1 = - 3

t = 4

and t = - 2

The root with the greater value is

t = 4

, which represents the time we need.

\(\quad \huge \quad \quad \boxed{ \tt \:Answer }\)

\(\qquad \tt \rightarrow \:4 \:\: sec \)

____________________________________

\( \large \tt Solution \: : \)

height of an object projected in air with time is represented by the given equation :

\(\qquad\displaystyle \tt \rightarrow \: h(t) = - 16 {t}^{2} + 32t + 128\)

The height when the object hits the ground will be 0

so, just equate the equation with 0, and we will get the value of t (time) when the projectile will be back to ground.

\(\qquad\displaystyle \tt \rightarrow \: - 16 {t}^{2} + 32t + 128 = 0\)

\(\qquad\displaystyle \tt \rightarrow \: - 16( {t {}^{2} - 2t}^{} - 8) = 0\)

\(\qquad\displaystyle \tt \rightarrow \: t {}^{2} - 2t - 8 = 0\)

\(\qquad\displaystyle \tt \rightarrow \: t {}^{2} - 4t +2 t - 8 = 0\)

\(\qquad\displaystyle \tt \rightarrow \: t(t - 4) + 2(t - 4) = 0\)

\(\qquad\displaystyle \tt \rightarrow \: (t - 4)(t + 2) = 0\)

So,

\(\qquad\displaystyle \tt \rightarrow \: t = 4 \: \: \: \: or \: \: \: \: t = - 2\)

but since time can't be negative, t = 4 seconds

The object will be back on ground after 4 seconds.

Answer: The perimeter of a parallelogram is the sum of all its sides.

In this case, since all sides of the parallelogram WXYZ are given as 34 units, the perimeter of parallelogram WXYZ is the sum of all its four sides.

So the perimeter of parallelogram WXYZ = 34 + 34 + 34 + 34 = 136 units

It's important to notice that the given value of perimeter = 60 is not correct.

The perimeter of parallelogram WXYZ is 136 units, not 60 units.

Step-by-step explanation: