Plzzzzz help meeeee plzzzz I really d answa

Answer: 4 and 6

Step-by-step explanation:

Because 14/17 is greater than half, you round up to the 4, same goes for the 11/15, it's greater than 1/2 (0.5) so you would round up to the 6.

Answer:

$26.03

Step-by-step explanation:

$234.27/9=$26.03

Answer:

c=3

Step-by-step explanation:

Answer:

0.5

Step-by-step explanation:

7 1/2 • 2 = 15

7 times 2 is equal to 14

1/2 times 2 is equal to 1

14 plus 1 is equal to 15

θ is in the second quadrant and cos(θ) = -1/3. The reciprocal identities are relationships that involve the reciprocals of the six trigonometric functions. Here are the steps to follow to solve the given problem:1.

Recall the definition of secant. Secant is the reciprocal of cosine, so we have sec(θ) = 1/cos(θ).2. Since sec(θ) = -3, we can substitute -3 for sec(θ) in the previous equation to obtain 1/cos(θ) = -3.3. Cross-multiplying yields cos(θ) = -1/3. Therefore, the answer is cos(θ) = -1/3.Note that cos(θ) is negative, which means that θ is in the second or third quadrant. Since sec(θ) is negative, we know that θ is in the second quadrant. This means that cos(θ) is also negative.

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The gradient of the function \(\(f\)\) at the point \(\((-1, -3)\)\) is:

\(\[\nabla f(-1, -3) = \left(-3e^{-3} \sin(12), 4e^{-3} \cos(12)\right)\]\)

To find the gradient of the function \(\( f(x, y) = e^{3x} \sin(4y) \)\) at the point \(\((-1, -3)\)\), we need to compute the partial derivatives with respect to \(\(x\) and \(y\)\) and evaluate them at that point.

The gradient of a function is given by:

\(\[\nabla f(x, y) = \left(\frac{{\partial f}}{{\partial x}}, \frac{{\partial f}}{{\partial y}}\right)\]\)

Let's calculate the partial derivatives:

\(\[\frac{{\partial f}}{{\partial x}} = \frac{{\partial}}{{\partial x}}\left(e^{3x} \sin(4y)\right) = 3e^{3x} \sin(4y)\]\)

\(\[\frac{{\partial f}}{{\partial y}} = \frac{{\partial}}{{\partial y}}\left(e^{3x} \sin(4y)\right) = 4e^{3x} \cos(4y)\]\)

Now, we can evaluate these derivatives at the point \(\((-1, -3)\):\)

\(\[\frac{{\partial f}}{{\partial x}}\Bigr|_{(-1, -3)} = 3e^{3(-1)} \sin(4(-3)) = 3e^{-3} \sin(-12)\]\)

\(\[\frac{{\partial f}}{{\partial y}}\Bigr|_{(-1, -3)} = 4e^{3(-1)} \cos(4(-3)) = 4e^{-3} \cos(-12)\]\)

Simplifying further:

\(\[\frac{{\partial f}}{{\partial x}}\Bigr|_{(-1, -3)} = 3e^{-3} \sin(-12) = -3e^{-3} \sin(12)\]\)

\(\[\frac{{\partial f}}{{\partial y}}\Bigr|_{(-1, -3)} = 4e^{-3} \cos(-12) = 4e^{-3} \cos(12)\]\)

Therefore, the gradient of the function \(\(f\)\) at the point \(\((-1, -3)\)\) is:

\(\[\nabla f(-1, -3) = \left(-3e^{-3} \sin(12), 4e^{-3} \cos(12)\right)\]\)

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Answer:

\(1\frac{1}{2}\)

Step-by-step explanation:

The first step to solving this problem is to convert these into improper fractions.

\(7\frac{2}{3} =\frac{21+2}{3}=\frac{23}{3}\)

\(5\frac{1}{9} =\frac{45+1}{9}=\frac{46}{9}\)

The second step is to determine the reciprocal of the second term.

Reciprocal of \(\frac{46}{9} =\frac{9}{46}\)

The third step is to multiply the first term by the reciprocal of the second term.

\(\frac{23}{3}*\frac{9}{46}=\frac{207}{138}\)

The fourth step is to reduce this fraction.

\(\frac{207}{138}=\frac{3(69)}{3(46)}=\frac{23(3)}{23(2)}=\frac{3}{2}=1\frac{1}{2}\)

Answer:

1 1/2 or 3/2

Step-by-step explanation:

First you need to make your fractions improper.

7 times 3 + 2 = 23, so the fraction is 23/3

5 times 9 + 1 = 46, so the fraction is 46/9

Since this is division, flip the second fraction.

So instead of 46/9, it's now 9/46

Now you can multiply.

23/3 + 9/46 = 207/138

207/138 simplified is 3/2, or  1  1/2

Hope this helped! Leave a comment if it did. :)

Answer:

The last year value of the house will be $230,000.

Step-by-step explanation:

GIVEN: Decrease in house price = 20%

            Current house price = $184,000

TO FIND: Value of the house last year

SOLUTION:

If the value of the house decreased by 20% during last year, this means the value of the house this year is 80% of last year's value.

Let the value of the house last year be 'x'.

If the value of the house today is  $184,000, then:

                           \(80/100 * x = 184,000\\\\0.8x = 184,000\\\\x = 184,000/0.8\\\\x = 230,000\)

Therefore, the last year value of the house will be $230,000.

Answer:

yes 1.57 is a rational number you could write it as 1 & 57/100 or 157/1000

Answer:

The area of half of the garden in square meters.

So we have shown that the largest possible area of the triangle is \(a^2,\)which occurs when the third side has length 3a and the height is a.

We can use the formula for the area of a triangle, which is A = (1/2)bh, where b is the length of the base and h is the height. In this case, we know that the base has length 2a, so we need to find the height.

Let's call the third side of the triangle, which is not given, b. We know that the sum of the lengths of any two sides of a triangle must be greater than the length of the third side, so we have:

a + 2a > b

3a > b

We can rearrange this to solve for b:

b < 3a

Now, let's use the formula for the area of a triangle:

A = (1/2)bh

We want to maximize A, so we want to maximize h. We know that h is the height of the triangle, which is perpendicular to the base, so it forms a right angle. We can use the Pythagorean theorem to find h in terms of a and b:

\(h^2 = b^2 - a^2\)

We can substitute our inequality for b:

\(h^2 < (3a)^2 - a^2\)

\(h^2 < 8a^2\)

h < √(8\(a^2\))

h < 2 √(2)a

Now we can use the formula for the area of the triangle again:

A = (1/2)bh

A < (1/2)(2 √(2)a)(a)

A < \(a^2\) √(2)

So we have shown that the largest possible area of the triangle is \(a^2,\)which occurs when the third side has length 3a and the height is a.

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Answer:

Step-by-step explanation:

There are 12 inches in one foot. If you have 12 inches, and want to convert inches to feet, you would make a fraction of how many inches you have (12) compared to the number of inches you need for one foot (12). The fraction 12/12 is equal to 1. 12 inches is equal to 1 foot.

1.  [1  2  3]   [x1]   [2]

 [0  1 -1]   [x2] = [8]

 [1  2  1]   [x3]   [4]

2. x3 equals to -11/3.

To solve for x3 using Cramer's rule, we need to find the determinant of the coefficient matrix and then form three additional matrices by replacing the third column of the coefficient matrix with the constants vector. The determinant of the coefficient matrix is:

| 1  2  3 |

| 0  1 -1 |

| 1  2  1 | = 1(1-4)-2(3-1)+3(2-2) = -3

Next, we form three matrices by replacing the third column of the coefficient matrix with the constants vector:

 [1  2  2]   [2]

 [0  1  8] = [8]

 [1  2  4]   [4]

 [1  2  3]   [2]

 [0  1 -1] = [8]

 [1  2  1]   [4]

 [1  2  3]   [2]

 [0  1 -1]   [8]

 [1  2  4]   [4]

The determinants of these matrices are:

| 1  2  2 |    | 1  2  3 |    | 1  2  3 |

| 0  1  8 | = -4| 0  1 -1 | = -3| 0  1 -1 | = 11

| 1  2  4 |    | 1  2  1 |    | 1  2  4 |

Therefore, x3 can be calculated as:

x3 = Det(B)/Det(A) = 11/-3 = -11/3

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z° = 25°+90°

=115°.............

1 is returned by the peek operation on the following priority queue.

The smallest value in a min-heap is returned by peak operation.

Heap:

By creating a min-heap or max-heap using the elements of the supplied array, the elements of a heap sort are processed. The root component or element of an array's sequence, which reflects the array's minimal or maximal element, can be described using either of the heaps (max or min). We will study more about heap sort algorithms in this article. When it comes to the heap sort, the elements are primarily sorted in the following two steps: To construct a heap, the array's elements must first be changed. Next, move the heap's root component to the end of the array and hold the heap structure with the left components while continually removing it.

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9514 1404 393

Answer:

  q/2, p, q

Step-by-step explanation:

You know the area of a triangle is half the product of base and height. The two triangles of interest here have base length p and height q/2. You're being asked to fill in the missing base or height dimension.

  \(=\dfrac{1}{2}\times p \times\boxed{\dfrac{q}{2}}+\dfrac{1}{2}\times\boxed{p}\times\dfrac{q}{2}\\\\=\dfrac{1}{2}\times p\times\boxed{q}\)

Step-by-step explanation:

Between x = -5 to x = -1 the graph is positive ( > 0)   at -5 and -1 it is EQUAL to zero...so those numbers are not included

(-5,-1)    

The domain on which the graph of a function is positive involves finding the x-values for which the function's output is greater than zero. This can be visualized by identifying where on the graph the curve is situated above the x-axis.

The domain on which the graph of f(x) is positive is the set of x-values for which the y-values (the outputs of the function) are greater than zero.

So, for each point (x, y) on the graph, if y is larger than zero that means f(x) is positive. To find out where this is the case, simply look at the graph and identify where the curve lies above the x-axis. These will be the x-values that make f(x) positive.

For example, if the plot of the function is above the X-axis between interval a and b, then the domain on which f(x) is positive is the interval (a, b).

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Answer:

300 new employees

Step-by-step explanation:

1:3

x + 3x = 1,200

4x = 1200

x = 300

Answer:

B

Step-by-step explanation:

You cannot have two or more domains.

'

3 appears twice and is located in the x axis, which is basically the domain.

Hope this helps

Answer: B

a and c are both functions and b is not.

Answer:

Below in bold.

Step-by-step explanation:

4y + 2 > 2.8

4y > 2.8 - 2

4y > 0.8

y > 0.8/4

y > 0.2.

Answer:

0

Step-by-step explanation:

5(x+3) replace x with -3

5(-3+3)

5(0)

0

After six​ months, the​ subjects' symptoms are studied and compared. Answer parts​ are given below.

An assumption or concept is given as a hypothesis for the purpose of debating it and testing if it might be true.

Given:

A pharmaceutical company wants to test the effectiveness of a new allergy drug.

The company identifies 250 females​ 30–35 years old who suffer from severe allergies.

The subjects are randomly assigned into two groups.

One group is given the new allergy drug and the other is given a placebo that looks exactly like the new allergy drug.

After six​ months, the​ subjects' symptoms are studied and compared.

Here, 30-35 year-old girls are used to test the new allergy medication's effects.

(a)

Females between the ages of 30 and 35 who are the test subjects are the experimental units.

The new allergy medication, whose results are being studied, is the remedy.

It's best to choose C.

(b)

A bias may develop if a researcher or patient knows whether subjects received a medication or a placebo.

In this case, choice B is preferable.

(c)

If neither the researcher nor the subject knew whether they were receiving a medicine or a placebo, the study would be considered double-blind.

In this case, choice A is preferable.

Therefore, all the correct choices are given above.

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The complete question is given in the image.

Answer:

7/8 inch

Step-by-step explanation: Good luck!

The subtraction of 11/30 from 3/30 can be simplified by finding a common denominator and then subtracting the numerators. The simplified form of the expression will be given as the answer.

To subtract fractions, we need to have a common denominator. In this case, the denominators are already the same, which is 30. Therefore, we can directly subtract the numerators: (3 - 11)/30 = -8/30. The numerator -8 cannot be further simplified, but we can simplify the fraction by dividing both the numerator and denominator by their greatest common divisor, which is 2: (-8/2) / (30/2) = -4/15. So, the simplified form of 11/30 - 3/30 is -4/15.

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Answer: 211200

Step-by-step explanation: Ok so assuming you are asking how many feet you travel per hour going 40 mph. You would travel 211200. There are 5280 ft in a mile. If you multiply that by 40 you get 211200. So you travel 211200ft per hour

Answer:

C

Step-by-step explanation:

when u take the 2 shortest sides and add them up, they must be greater than the longest length.

Answer: -276.2 ft.

Step-by-step explanation: He descended 91 x 4.5 which is -409.5 ft. But since she goes up 43 x 3.1 which is 133.3 ft, -409.5 + 133.3 = -276.2 ft.

Hope this helps! :)

Option D. The median cost of course materials for nursing majors is over $300 more than the median cost of course materials for non-nursing majors.

The given boxplots show the circulation of the expense obviously materials for nursing majors and non-nursing majors. From the plots, we can reason that the scope of the circulation of the expense obviously materials for nursing majors is like that of non-nursing majors, as the most extreme and least qualities are around at a similar level. We can likewise infer that the most extreme expense for non-nursing majors is more prominent than the middle expense for nursing majors.

Also, the inconstancy of the expense obviously materials for the center half of nursing majors is more noteworthy than the fluctuation of the center half for non-nursing majors, as the cases for nursing majors are more extensive. In any case, we can't reason that the middle expense obviously materials for nursing majors is more than $300 more than the middle expense obviously materials for non-nursing majors, as the medians are not straightforwardly named and their division isn't plainly shown. At last, we can see that the study included 17 nursing majors and 17 non-nursing majors.

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The complete question is:

A college professor conducted a survey in order to assess how much money nursing majors spend on course material compared to all other majors. To do so, she selected a random sample of 34 students. Each student was classified as a nursing major or as a non-nursing major. They were then asked how much they spent on books and other materials required for their courses this semester. Shown above are parallel boxplots summarizing the responses. Based upon the boxplots, which of the following statements cannot be concluded?

A. The range of the distribution of the cost of course materials for nursing majors is about the same as that of non-nursing majors.

B. The maximum cost for non-nursing majors is greater than the median cost for nursing majors.

C. The variability of the cost of course materials for the middle 50% of nursing majors is greater than the variability of the middle 50% for non-nursing majors.

D. The median cost of course materials for nursing majors is over $300 more than the median cost of course materials for non-nursing majors.

E. The boxplots reveal that 17 students are nursing majors and 17 students are non-nursing majors