Podłoga w łazience ma kształt kwadratu o boku 3 m. Ile płytek terakoty o wymiarach 10cm x 20cm wypełni podłoge ?

Answer:

1464

Step-by-step explanation:

Answer:

1104 points

Step-by-step explanation:

50 points for 30 correct moves is 1500 points

2 minutes and 12 seconds is equal to 132 seconds

at 132*-3 for each second is -396

1500-396 =1104 points

Answer:

325 x 7.00 = 2275.

2495 - 2275 = 220.

Answer:

75 + 25h

Step-by-step explanation:

Hope this helps

Answer:

2nd one

Step-by-step explanation:

Answer:

the second answer

Step-by-step explanation:

( multiply and divide left to right , add and subtract left to right)

Answer:

(y+4)²

Step-by-step explanation:

\((a+b)^2=a^2 + 2ab+b^2\)

Here, a=y and b=4.

Answer: 4

Step-by-step explanation:

The LLN states that if an experiment with a random outcome is repeated a large number of times, the empirical probability that is observed is likely to be close to the theoretical probability.

The Law of Large Numbers (LLN) is a statistical theorem which states that if an experiment with a random outcome is repeated a large number of times, the empirical probability that is observed is likely to be close to the theoretical probability. This means that the empirical probability will approximate the theoretical probability as the number of trials increases. Therefore, the statement that is true about the LLN is that if an experiment with a random outcome is repeated a large number of times, the empirical probability that is observed is likely to be close to the theoretical probability.

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The equation that can be used to prove 1 + tan2(x) = sec2(x) is StartFraction cosine squared (x) Over tangent squared (x) EndFraction + StartFraction sine squared (x) Over tangent squared (x) EndFraction = StartFraction 1 Over tangent squared (x) EndFraction. the correct option is d.

In order to prove this, we can use the following identities:

tan(x) = sin(x) / cos(x)

sec(x) = 1 / cos(x)

tan2(x) = sin2(x) / cos2(x)

sec2(x) = 1 / cos2(x)

Substituting these identities into the given equation, we get:

StartFraction cosine squared (x) Over tangent squared (x) EndFraction + StartFraction sine squared (x) Over tangent squared (x) EndFraction = StartFraction 1 Over tangent squared (x) EndFraction

Therefore, 1 + tan2(x) = sec2(x).

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Answer:

y = 1/2x + 4

Step-by-step explanation:

y = 1/2x + 4

Answer

The inequality to solve this is

(330/Time) ≤ 55

The solution of this inequality is

Time ≥ 6 hours

Explanation

We are told that the car's maximum speed is 55 miles per hour.

To solve this, we should note that

Speed = (distance/time)

But for this question, we are told that the car has a maximum speed of 55 miles per hour.

So,

(Distance/Time) ≤ 55

If the distance covered is 330 miles

(Distance/Time) ≤ 55

(330/Time) ≤ 55

55 (Time) ≥ 330

Divide both sides by 55

Time ≥ (330/55)

Time ≥ 6 hours

Hope this Helps!!!

Answer:

C.

3 units to the right would mean you are adding the positive value of 3 to the number 5

Answer:

5+3 and 5+(-3)

Step-by-step explanation:

hope this hepla

Answer:

Step-by-step explanation:

(10-6)/(2-0)= 4/2= 2

y - 6 = 2(x - 0)

y - 6 = 2x - 0

y = 2x + 6

answer is D

In order for the exponential function and the tangent line to be equivalent at a certain point, their function values and their first derivatives must be equal at that point.

At a given point, if the function values of an exponential function and its tangent line are equal, it means that they have the same value and slope at that point.

This requires that their first derivatives at that point are equal. The first derivative of an exponential function is also an exponential function, so the derivative of the tangent line must also be an exponential function with the same slope as the original function.

Therefore, the two functions must have the same first derivative at that point. This condition is necessary for the two functions to be equivalent at that point.

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Answer:

\({ \bf{total \: ratio = 4 + 3 = 7}} \\ { \tt{let \: population \: be \: p}} \\ \frac{4}{7} \times p = 24 \\ 4p = 168 \\ p = 42 \\ { \bf{there \: are \: 42 \: people}}\)

Boys to girls- 4:3

Boys and girls- 24 and x (let the girls be x)

4/3=24/x

=4x= 72

= x= 72/4

= x= 18 girls

Ans: There are 42 children (24+18)

Answer:

The area would be 81.

Step-by-step explanation:

To find this answer, I multiplied 9 by 9 cm , which gave me 81, which would represent the correct area of the figure.

Answer:

81

Step-by-step explanation:

In order to find the area, multiply

A = l × w

Answer:

use the formula

Step-by-step explanation:

(y-y1)=M(x-x1) use this formula after finding the slope

you will get the answer

Answer:

C

Step-by-step explanation:

because nobody makes wires out of crayons but crayons r cheap and they would be used as wires but they arent probably cuz they dont conduct electricity

Answer:

If your multiplying and the equation is -6 x 4 then your answers gonna be -24

Step-by-step explanation:

But if its something else, sorry, I can't hep you unless I get a further explanation.

Answer:

-24

Step-by-step explanation:

(-6)×(4)

-24

invisible plus at the front of four

-×+=-

If the measure of arc AB is 48, then the measure of inscribed angle ACB is 48/2 = 24 degrees.

What is the arc?

An arc in mathematics is a segment of a curve or a segment of a circle.  A circle's arc is referred to as a portion or section of its circumference. A semicircular arc is one whose length is exactly half that of a circle.

To find the measure of an inscribed angle given the measure of its corresponding arc.

In a circle, an inscribed angle intercepts an arc that is twice as large as the angle.

That is, if an inscribed angle intercepts an arc with measure x, then the measure of the inscribed angle is x/2.

Therefore, if the measure of arc AB is 48, then the measure of inscribed angle ACB is 48/2 = 24 degrees.

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Answer:

68,443,507,502

Step-by-step explanation:

Answer:

68,443,507,502

Step-by-step explanation:

Hope this helps

Step-by-step explanation:

for the perimeter you have to say two brackets live plus height plus with plastic

The minimum that could be earned is $150. The required inequalities are solved below:

What is an inequality?

An inequality in mathematics is a relationship that makes a non-equal comparison between two integers or other mathematical expressions. It is most commonly used to compare the sizes of two numbers on a number line. There are multiple notations used to denote various types of inequalities: The symbol a b indicates that an is smaller than b. The symbol a > b indicates that an is more than b. In either scenario, a and b are not equal. These are characterized as stringent inequalities because an is either strictly less than or strictly bigger than b. Equivalence is not allowed.

(a) The minimum that could be earned is $150.

(b) The required inequality is given as 150+20x≥630

or, 20x≥630-150

or, x≥480/20

or, x≥24

(c) The required inequality is given as 150+20x≥750

or, 20x≥750-150

or, x≥600/20

or, x≥30

(d) The required inequality is given as 150+20x≤950

or, 20x≤950-150

or, x≤800/20

or, x≤40

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(a) If both types of professors choose the same strategy (e.g., publish the same number of papers), the department would always choose not to grant tenure (N), leading to negative payoffs for both professor types.

(1) Pooling Perfect Bayesian Equilibria (PBEs):

In this scenario, pooling refers to the situation where both high-ability (CH) and low-ability (OL) assistant professors choose the same strategy, making it indistinguishable for the department to determine their ability levels. However, pooling PBEs do not exist in this game.

To see why, let's consider the department's perspective. If the department grants tenure (T) to a professor, their payoff is 1 if the professor is high-ability (CH) and -1 if the professor is low-ability (OL). On the other hand, if the department does not grant tenure (N), their payoff is 0 regardless of the professor's ability.

Since the department wants to maximize its payoff, it would never have an incentive to grant tenure to a low-ability professor. Therefore, if both types of professors choose the same strategy (e.g., publish the same number of papers), the department would always choose not to grant tenure (N), leading to negative payoffs for both professor types. As a result, pooling PBEs are not possible in this scenario.

(2) Incentive Compatibility Constraints:

To determine the incentive compatibility constraints, we need to consider whether the assistant professor has an incentive to truthfully reveal their ability type to maximize their own payoff.

Let's denote the assistant professor's strategy as s = (q, T), where q represents the number of papers published and T represents the decision on whether to tenure or not. The two incentive compatibility constraints can be written as follows:

a) If the assistant professor is high-ability (CH):

If q papers are published and T is chosen, the payoff should be maximized compared to other strategies.

If q' papers are published and T' is chosen (with q' ≠ q or T' ≠ T), the payoff should be lower than the payoff for strategy s = (q, T).

b) If the assistant professor is low-ability (OL):

If q papers are published and T is chosen, the payoff should be maximized compared to other strategies.

If q' papers are published and T' is chosen (with q' ≠ q or T' ≠ T), the payoff should be lower than the payoff for strategy s = (q, T).

These incentive compatibility constraints ensure that the assistant professor has no incentive to misrepresent their ability type, as doing so would result in a lower payoff.

(3) Separating PBE with the Smallest Number of Papers Needed:

A separating PBE involves each type of assistant professor choosing a different strategy that allows the department to infer their ability levels accurately. In this case, we want to find a separating PBE that involves the smallest number of papers needed to get tenure.

To achieve this, we can consider a strategy where the high-ability professor (CH) chooses a higher number of papers to publish compared to the low-ability professor (OL). For instance, if the high-ability professor publishes q papers, the low-ability professor could publish q - 1 papers.

This strategy creates a separation between the two types, as the department can observe the number of papers published and make an educated guess about the professor's ability. The separating PBE with the smallest number of papers needed is when the high-ability professor publishes one more paper than the low-ability professor.

Note: To fully determine the values and specific equilibrium strategies, we would need additional information such as the probability distribution of ability types, the value of tenure (V), and the cost parameter (g). Without these specific values, we can discuss the general framework and concepts of PBEs and incentive compatibility.

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The standard form of the equation of the line

The equation of the line can be expressed in several forms. One of them is the standard form:

Ax + By = C

Where A, B, and C are constants, and x and y are the variables.

We have the equation:

Multiplying by 3:

Subtracting 4x:

Is the required standard form of the line

If a paper company needs to ship paper to a late printing business. 12 small boxes were shipped and 8 large boxes were shipped.

Using a system of equations to represent the problem.

Let x represent the number of small boxes shipped

Let  y represent the number of large boxes shipped.

We know that:

x + y = 20 (the total number of boxes shipped)

8x + 21y = 264 (the combined volume of all boxes )

Solving the first equation for y: y = 20 - x

Substituting this expression for y into the second equation:

8x + 21(20 - x) = 264

8x + 420 - 21x = 264

-13x = -156

x = 12 (small boxes)

So,

y = 20 - x

y = 20 -12

y = 8 (Large boxes)

Therefore 12 small boxes were shipped and 8 large boxes were shipped.

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Answer:

how do i make you brainlist

Step-by-step explanation:

Answer:

yes the person below is right it is 22 you just multply and add

Step-by-step explanation:

Answer:

you will have to pay $70 on 3 shirts and s pairs of jeans

Step-by-step explanation:

Answer:

70

Step-by-step explanation:

10+10+10= 30

20+20+40

30+40= 70

To simulate the given weather forecast, we can use a spinner with four equal sectors, three of them marked with the letter "R" (for rain), and one marked with the letter "S" (for sunshine). The "R" sectors represent the 75% chance of rain, while the "S" sector represents the remaining 25% chance of sunshine. By spinning the spinner, we can simulate the probability of whether it will rain or be sunny later today.

Using a spinner is a common way to simulate probability. It is a circular object divided into equal sections, and each section represents a possible outcome. By spinning the spinner, we can randomly choose one of the outcomes, simulating a probability experiment. In this case, we can use a spinner with four equal sectors, where three of them represent the 75% chance of rain and one represents the 25% chance of sunshine.

Using a spinner is an easy and effective way to simulate probability. To simulate the given weather forecast, we can use a spinner with four equal sectors, where three of them represent the 75% chance of rain and one represents the 25% chance of sunshine. By spinning the spinner, we can randomly choose one of the outcomes, simulating the probability of whether it will rain or be sunny later today.

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Our expression is