_______ prohibits and punishes certain conduct for the benefit of society.

Answers

Answer 1

Answer:

animal

Explanation:

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Related Questions

Is a neutral particle a nucleus or electron cloud

Answers

A neutral particle of an atom is located at the nucleus.

What are electron cloud?

Electrons are those negatively charged particles that are found revolving round an atom.

Electron cloud is defined as the model of an atom in which the atom consists of a small but massive nucleus surrounded by a cloud of rapidly moving electrons.

A neutral particle is a nucleus because the nucleus of an atom is made up of neutral particles found within the nucleus of an atom which doesn't contain any charges.

An atom is defined as the smallest and indivisible part of an element which can take part in a chemical reaction.

An atom is made up of nucleus which consists of the proton (which is positively charged) and the neutron (which bears no charges at all).

Therefore, a neutral particle can be said to be an electron cloud.

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__Hgo > __Hg + __O2?​

Answers

How to Balance:

Hg + O2 → HgO

✅Word equation: Mercury + Oxygen gas → Mercury (II) oxide

✅ Type of Chemical Reaction: For this reaction we have a combination reaction.

✅ Balancing Strategies: To balance this equation it's probably easiest to begin by changing the coefficient in front of the HgO.

This is a combination reactions because the mercury (Hg) plus the oxygen gas (O2) come together to form the Mercury (II) oxide (MgO).

Hint-1

Hint-2

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1)Grignard reagent when reacted with methanol will yield A) ethanol (B) secondary alcohols (C) tertiary alcohols (D ropanol (E) primary alcohol

Answers

When the reaction of  Grignard reagent reacted with methanol will yield a tertiary alcohol. Therefore, Option C tertiary alcohol is correct.

Contains a carbon-metal link, Grignard reagents are chemicals used in catalysis. They generally result from the anhydrous reaction of magnesium metal with an alkyl or aryl halide. Because of their high reactivity, Grignard reagents frequently act as nucleophiles in organic reactions.

An alkyl group from a Grignard reagent binds to the oxygen atom of methanol (CH3OH) when it interacts with the methanol, breaking the carbon-metal connection. A precursor alkoxide is created as a result. The equivalent alcohol is then produced by protonating the intermediate alkoxide.

The reaction of a Grignard reagent with methanol leads to the formation of a tertiary alcohol.

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Platinum can be found in which of the following formations

A.Sedimentary Bands
B. Aggregates
C. Chromite Bands
D. Hydrothermal Veins

Answers

Answer:

Explanation:

D

The correct answer is c .Chromite Bands

HELP ASAP PLZ!!!! Balance the following equation using whole numbers. What is the coefficient for SiO2? Si12H26+O2⟶SiO2+H2O

Answers

Answer:

I believe Si12H26+02 is the coefficient I might be wrong, Sorry if I am.

The coefficient would be 4:
2Si2H2 + 5O2 → 4SiO2 + 2H2O (balanced reaction)

What is the molarity of a 750.0 milliliter solution containing 2.5 moles of solute?
ОА.
1.9 M
OB
0.0033 M
O c.
1,875 M
OD.
0.30 M
OE.
3.3 M

Answers

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Therefore, the molarity of solution is 3.33

Answer:

A.  1.9 M

B.  0.0033 M

C.  1,875 M

D.  0.30 M

E. 3.3 M

A filtration system continuously removes water from a swimming pool, passes the water through filters, and then returns it to the pool. Both pipes are located near the surface of the water. The flow rate is 15 gallons per minute. The water entering the pump is at 0 psig, and the water leaving the pump is at 10 psig.

A. The diameter of the pipe that leaves the pump is 1 inch. How much flow work is done by the water as it leaves the pump and enters the pipe?

B. The water returns to the pool through an opening that is 1.5 inches in diameter, located at the surface of the water, where the pressure is 1 atm. How much work is done by the water as it leaves the pipe and enters the pool?

C. "The system" consists of the water in the pump and in the pipes that transport water between the pump and the pool. Is the system at steady state, equilibrium, both, or neither?

Answers

Answer:

A .    \(\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }\)

B.   \(\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }\)

C.  The system is at steady state but not at equilibrium

Explanation:

Given that:

The volumetric flow rate of the water = 15 gallons per minute

The diameter of the pipe that leaves the pump is 1 inch.

A. The objective here is  to determine how much work flow is done by the water as it leaves the pump and enters the pipe

The work flow that is said to be done can  be expressed by the relation :

W = P × V

where;

P = pressure

V = volume

Also the given outlet pressure is the gauge pressure

The pressure in the pump P  is can now be expressed by the relation:

\(P_{absolute} = P_{guage} + P_{atmospheric}\)

\(P_{absolute}\) =  10 psig + 14.7 psig

\(P_{absolute}\) =  24.7 psig

W =  P × V

W =  24.7 psig  ×  15 gal/min

\(W = (24.7 \ psig * \dfrac{\frac{lb_f}{in^2}}{psig}) * ( 15 \frac{gal}{min}* \dfrac{0.1337 \ ft^3}{1 \ gal }* \dfrac{144 \ in^2}{1 \ ft^2})\)

\(\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }\)

Thus ; the rate of flow of work is said to be done by the water at \(\mathbf{W = 7133.2 \dfrac{ft. lb_f}{min} }\)

B.

Given that :

The water returns to the pool through an opening that is 1.5 inches in diameter.

where the pressure is 1 atm.

Then ; the rate of work done  by the water as it leaves the pipe and enter the pool is as follows:

W =  P × V

W = 1 atm  ×  15 gal/min

\(W = 1 \ atm * ( 15 \frac{gal}{min}* \dfrac{0.1337 \ ft^3}{1 \ gal }* \dfrac{144 \ in^2}{1 \ ft^2})\)

\(\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }\)

Thus ; the rate of flow of work done by the water leaving the pipe and enters into the pool is  at \(\mathbf{W = 4245.24 \dfrac{ft. lb_f}{min} }\)

C.

We can consider the system to be at steady state due to the fact that; the data given for the flow rate and pressure doesn't reflect upon the change in time in the space between the pump and the pool.

On the other-hand the integral factor why the system is not at equilibrium is that :

the pressure leaving the pipe is different from that of the water at the surface of the pool as stated in the question.

If d represents the density of a gas and k is a constant. The relationship between the rate of diffusion r, and d is ____?

Answers

The relationship between the rate of diffusion r, and d is r ∝ 1/√d.

The relationship between the rate of diffusion (r) and the density of a gas (d) can be explained using Graham's law of diffusion. According to this law, the rate of diffusion of a gas is inversely proportional to the square root of its density. Mathematically, it can be expressed as:

r ∝ 1/√d

where the symbol '∝' represents 'proportional to'. The constant of proportionality (k) can be introduced to this equation as:

r = k/√d

This equation shows that as the density of a gas increases, its rate of diffusion decreases. This is because denser gases have more molecules per unit volume and thus, they experience greater intermolecular collisions that hinder their movement. Therefore, it requires more energy for them to diffuse through a medium compared to less dense gases.

The relationship between the rate of diffusion and density is particularly important in understanding the behavior of gases in different environments. For instance, in a gas chromatography column, the rate of diffusion of a gas determines how quickly it moves through the column and separates from other components. Similarly, in the Earth's atmosphere, the rate of diffusion of greenhouse gases such as carbon dioxide affects their concentration and hence, their impact on climate change.

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What method is being used to separate beans is it physical or chemical?

Answers

Answer:

the method used is physical

What mass of N atoms is present in 1.37 x 10^17 molecules of N2O

Answers

2.05 x 1022 N2O molecules are included in 1.50 g, according to knowledge. The number of N2O in 1 g may be calculated by multiplying this number by 1.5, and the number in 44 g can be calculated using that result.

The nitrogen content of N2O is how many grams?

The required amount of N2 is 0.010 mol due to N2O's two times greater nitrogen to oxygen atom ratio. The required amount of nitrogen is therefore 0.14 g of nitrogen or 0.010 mol x 14 g.

How do you calculate how many atoms there are in N?

Any amount (in moles) of atoms, ions, or molecules can be determined by using the mathematical equation N = n NA:

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the valency of magnesium is 2 why

Answers

The valency of magnesium is 2 because it has two valence electrons in its outermost shell. Magnesium belongs to the second group of the periodic table, which means it has two electrons in its outermost shell or valence shell. In order to achieve a stable configuration, magnesium tends to lose these two valence electrons to form a positively charged ion with a charge of 2+. This makes magnesium a bivalent or divalent element with a valency of 2.

Answer:

Because the outer shell of magnesium contains 2 atoms

Write the symbol for each isotope in the form Ax.
(a) cobalt-60
(b) neon-22
(c) iodine-131
(d) plutonium-244

Answers

The symbol for each isotope in the form Ax (a)⁶⁰₂₇Co and  (b)²²₁₀  Ne and (c)¹³¹₅₃I and (d)²⁴⁴₉₄ Pu

What is an isotope in chemistry easy definition?

They are atoms that have different numbers of neutrons but the same amount of protons. Despite having nearly equal chemical properties, they have different masses, which impacts their physical qualities.

What substances have isotopes?

Every element has an isotope. The number of protons in each atom of a particular element is the same, but the total amount of neutrons and protons in each atom varies. They are virtually equal or identical when that comes to an element's isotopes' chemical characteristics. Different isotopes have almost comparable chemical characteristics.

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An electromagnetic wave having a frequency of 1.33x1017 Hz, what is its wavelength?

Answers

Its wavelength : 2.31 x 10⁻⁹ m

Further explanation

Radiation energy is absorbed by photons

The energy in one photon can be formulated as

\(\large{\boxed{\bold{E\:=\:h\:.\:f}}}\)

Where

h = Planck's constant (6,626.10⁻³⁴ Js)

f = Frequency of electromagnetic waves

f = c / λ

c = speed of light

= 3.10⁸

λ = wavelength

Frequency of electromagnetic waves  : 1.33 x 10¹⁷ Hz

the wavelength :

\(\tt \lambda=\dfrac{c}{f}\\\\\lambda=\dfrac{3.10^8}{1.3\times 10^{17}}=2.31\times 10^{-9}\)

At equilibrium,
a. the forward reaction rate is equal to the reverse reaction rate.
b. the forward reaction rate is higher than the reverse reaction rate.
c. no reactions take place.
d. the forward reaction rate is lower than the reverse reaction rate.

Answers

Hi just wanted to say thank you for answering my question and I wanted to help so I believe the answer is A.

what is another name for horse

Answers

Answer:

Mount, Charger, Colt, Pony, and Folt

Explanation:

what is another name for horse

Answer:

A stallion or a mare

Explanation:

Starting with 0.3500 mol CO(g) and 0.05500 mol COCl2(g) in a 3.050 L flask at 668 K, how many moles of CI2(g) will be present at equilibrium?
CO(g) + Cl2(g)》COCl2(g)
Kc= 1.2 x 10^3 at 668 K

Answers

At equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

1: Write the balanced chemical equation:

\(C_O\)(g) + \(Cl_2\)(g) ⟶ \(C_OCl_2\)(g)

2: Set up an ICE table to track the changes in moles of the substances involved in the reaction.

Initial:

\(C_O\)(g) = 0.3500 mol

\(Cl_2\)(g) = 0.05500 mol

\(C_OCl_2\)(g) = 0 mol

Change:

\(C_O\)(g) = -x

\(Cl_2\)(g) = -x

\(C_OCl_2\)(g) = +x

Equilibrium:

\(C_O\)(g) = 0.3500 - x mol

\(Cl_2\)(g) = 0.05500 - x mol

\(C_OCl_2\)(g) = x mol

3: Write the expression for the equilibrium constant (Kc) using the concentrations of the species involved:

Kc = [\(C_OCl_2\)(g)] / [\(C_O\)(g)] * [\(Cl_2\)(g)]

4: Substitute the given equilibrium constant (Kc) value into the expression:

1.2 x \(10^3\) = x / (0.3500 - x) * (0.05500 - x)

5: Solve the equation for x. Rearrange the equation to obtain a quadratic equation:

1.2 x \(10^3\) * (0.3500 - x) * (0.05500 - x) = x

6: Simplify and solve the quadratic equation. This can be done by multiplying out the terms, rearranging the equation to standard quadratic form, and then using the quadratic formula.

7: After solving the quadratic equation, you will find two possible values for x. However, since the number of moles cannot be negative, we discard the negative solution.

8: The positive value of x represents the number of moles of \(Cl_2\)(g) at equilibrium. Substitute the value of x into the expression for \(Cl_2\)(g):

\(Cl_2\)(g) = 0.05500 - x

9: Calculate the value of \(Cl_2\)(g) at equilibrium:

\(Cl_2\)(g) = 0.05500 - x

\(Cl_2\)(g) = 0.05500 - (positive value of x)

10: Calculate the final value of \(Cl_2\) (g) at equilibrium to get the answer.

Therefore, at equilibrium, the number of moles of \(Cl_2\) (g) will be 0.2025 mol.

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If i can get an answer to these two question ill mark you brainliest with 100 points

Can water stay liquid below zero degrees Celsius?

Can you light diamond on fire?

Answers

Answer:

1. Yes, water can remain liquid at temperatures below 0 degrees Celsius. This can happen in a few different ways.

2. Considering diamond is comprised of carbon, it may be set on fire. Because diamond has strong atomic connections, it takes a lot of energy to separate the carbon atoms and allow them to burn with oxygen.

Hope this helps!!!

The blank
and
blank
of atoms are the same on both sides of
a chemical equation.

Please just answer the question directly instead of giving me some weird cryptic answer that I can’t use. I’ve seen this exact question answered before and nobody would give a straight answer.

The blank andblankof atoms are the same on both sides ofa chemical equation.Please just answer the question

Answers

I think it’s “number” and “type”

Calculate the concentration of buffer components present in 210.00 mL of a buffer solution that contains 0.300 M NH4Cl and 0.300 M NH3 immediately after the addition of 1.00 mL of 6.00 M HNO3.

Answers

Answer:

[NH3] = 0.270M

[NH4Cl] = 0.327M

Explanation:

The HNO3 will react with the weak base, NH3, as follows:

HNO₃ + NH₃ → NH₄⁺ + NO₃⁻

Initial moles of each specie of the buffer:

NH3 = NH4⁺ 0.210L * (0.300mol/L) = 0.063moles

The moles added of HNO3 = Additional moles of NH4Cl and the moles substracted of NH3:

0.001L * (6mol / L) = 0.006 moles.

After the addition:

Moles NH3 = 0.063mol - 0.006mol = 0.057moles

Moles NH4Cl = 0.063mol + 0.006mol = 0.0069moles

And their concentrations are:

[NH3] = 0.057moles / 0.211L = 0.270M

[NH4Cl] = 0.069moles / 0.211L = 0.327M

Which of the following is an example of something that is made of cells?


A flower

A ball

A sock

A television

Answers

The answer is flower lol

It is possible to convert moles to particles by doing what

Answers

Avogadro's number is a very important relationship to remember: 1 mole = 6.022×1023 6.022 × 10 23 atoms, molecules, protons, etc. To convert from moles to atoms, multiply the molar amount by Avogadro's number. Hope this helps! Mark brainly please!

What mass of NaCl is needed to produce a 26.4 mol/L with a 1.7 L volume?

Answers

we would need 2625.13 grams (or 2.62513 kilograms) of NaCl.

To calculate the mass of NaCl required to produce a 26.4 mol/L solution with a 1.7 L volume, we need to use the formula that relates the mass of solute, moles of solute, and molarity:Molarity (M) = moles of solute / liters of solution Rearranging this formula, we get:moles of solute = Molarity (M) x liters of solutionWe can use this formula to find the moles of NaCl needed:moles of NaCl = 26.4 mol/L x 1.7 L = 44.88 molNow, we can use the molar mass of NaCl to convert from moles to grams. The molar mass of NaCl is 58.44 g/mol:mass of NaCl = moles of NaCl x molar mass of NaClmass of NaCl = 44.88 mol x 58.44 g/mol = 2625.13 gTo produce a 26.4 mol/L solution with a 1.7 L volume.

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which picture shows the particles in a compound?



picture I and II

picture I

picture III and IV

picture II

which picture shows the particles in a compound?picture I and IIpicture Ipicture III and IVpicture II

Answers

hi <3

compound are 2(or more) elements combined together

thus your answer will be picture I

hope this helps <3

A scientist did a test to compare two substances: substance Q and substance R. At room temperature, both substances are liquid. When the scientist transferred the same amount of energy out of both substances, only one substance changed phase while the other did not. Which substance changed phase, and how did it change?

Answers

The substance that changed phase would have less heat capacity than the other thus the bonds in it were broken more easily.

What is a phase change?

We have to note that the phase change has to do with the conversion of a liquid to a solid or the conversion of a liquid to a gas. A phase is essentially a  given state of matter.

In the case of the question that we have here, we are told that the two substances that are tested are liquids. It is now clear that the substance that changed phase would have a lower heat capacity.

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Need help with chemistry #4The specific heat of metal is 0.222 cal/g°C. If 587.0 calories of heat energy are added to a chunk of gold and the temperature rises from 18.9°C to 38.8°C, find the mass (in grams) of the piece of gold.

Need help with chemistry #4The specific heat of metal is 0.222 cal/gC. If 587.0 calories of heat energy

Answers

Answer

132.9 grams

Explanation

Given:

Specific heat of the gold metal, c = 0.222 cal/g°C

Quantity of heat energy, Q = 587.0 cal

Initial temperature, T₁ = 18.9 °C

Final temperature, T₂ = 38.8 °C

Temperature change, ΔT = T₂ - T₁ = 38.8 °C - 18.9 °C = 19.9 °C

What to find:

The mass (in grams) of the piece of gold.

Step-by-step solution:

The mass (in grams) of the piece of gold can be calculated using the formula below;

\(\begin{gathered} Q=mc\Delta T \\ \\ \Rightarrow m=\frac{Q}{c\Delta T} \end{gathered}\)

Putting the values of the parameters into the formula, we have

\(m=\frac{587.0\text{ }cal}{0.222\text{ }cal\text{/}g°C\times19.9\text{ }°C}=\frac{587.0\text{ }g}{4.4178}=132.9\text{ }grams\)

The mass (in grams) of the piece of gold is 132.9 grams.

Based on a Kc value of 0.250 and the given data table, what are the equilibrium concentrations of XY, X, and Y , respectively?

Answers

From the solution that we have in the question;

The concentration of X and Y is 0.28 MThe concentration of XY is  0.32 MWhat is the equilibrium constant?

The equilibrium constant, denoted as K, is a value that quantitatively represents the ratio of the concentrations of products to reactants at equilibrium in a chemical reaction.

It is a fundamental concept in chemical equilibrium.

The value of the equilibrium constant provides valuable information about the position of equilibrium and the relative concentrations of species involved in a chemical reaction.

Kc = [X] [Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\)

\(0.25(0.5 - x) = (0.1 + x)^2\)

\(0.125 - 0.25x =0.01 + 0.2x + x^2\\ x^2 + 0.45x - 0.115 = 0\)

x = 0.18 M

The equilibrium amount of X and Y=  0.28 M and the equilibrium concentration of XY = 0.32 M

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Based on the answer to the question that we have;

A 0.28 M concentration of X and Y exists at equilibriumXY's concentration at equilibrium is 0.32 M.

The equilibrium constant

The ratio of the product to reactant concentrations in a chemical reaction at equilibrium is represented quantitatively by the equilibrium constant, abbreviated as K.

It is a cornerstone of the theory of chemical equilibrium.

A chemical reaction's equilibrium position and the relative concentrations of the species involved can both be learned from the equilibrium constant's value.

Kc = [X][Y]/[XY]

\(0.25 = (0.1 + x)^2/(0.5 - x)\\0.25(0.5 - x) = (0.1 +x)^2\\0.125 - 0.25x = 0.01 +0.2x +x^2\\= 0.18 M\)

The equilibrium concentration of;

XY =0.5 - 0.18

=0.32 M

Then the equilibrium amount of

X and Y is

0.1 + 0.18= 0.28 M.

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Based on a Kc value of 0.250 and the given data table, what are the equilibrium concentrations of XY,

You combine carbon monoxide with nitrogen dioxide to form carbon dioxide and nitrogen monoxide as depicted in the below equation . CO(g) + NO2(g) -> CO2(g) + NO(g) If you started with zero carbon dioxide, and over 62.3 seconds, 0.123 M of carbon dioxide was produced, what is the rate of this reaction?

Answers

The rate of the given reaction is 0.00197 M/s.

What is the rate of the reaction?

The balanced chemical equation of the reaction is:

CO (g) + NO₂ (g) → CO₂ (g) + NO (g)

From the equation, 1 mole of CO produces 1 mole of CO₂, and hence the number of moles of CO2 produced is equal to the number of moles of CO consumed.

The concentration of CO₂ produced = 0.123 M.

Therefore, the concentration of CO consumed is also 0.123 M.

The rate of reaction is given by the formula:

rate = Δ[C]/Δt

where Δ[C] is the change in concentration and Δt is the change in time.

Over 62.3 seconds, the concentration of CO decreases from 0 M to 0.123 M.

Δ[C] = 0.123 M - 0 M

Δ[C]  = 0.123 M

Δt = 62.3 s

Substituting the values in the formula, we get:

rate of the reaction = Δ[C]/Δt

rate of the reaction = 0.123 M/62.3 s

rate of the reaction = 0.00197 M/s

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An infant acetaminophen suspension contains 80.0mg/0.80 mL suspension. The recommended dose is 15 mg/kg body weight. (1.000 lb. is equivalent to 453.59 g; this is a measured equality.)

How many mL of this suspension should be given to an infant weighing 17 lb ? (Assume two significant figures.)
Express your answer using two significant figures.

Answers

The amount, in mL, of the suspension that should be given to an infant weighing 17 lb will be 1.16 mL

Dimensional analysis

0.8 mL of the liquid contains 80.0 mg of the drug.

The recommended dose is 15 mg per kg of body weight

The infant to be given the drug weighs 17 lb.

First, let's convert the weight of the infant to kg.

1 lb = 453.59 g

17 lb =       453.59 x 17/1

                   = 7711.03 g

1000 g = 1 kg

7711.03 g = 7711.03 x 1/1000

               = 7.711 kg

So, the baby's weight is 7.711 kg.

The drug dose for the baby can thus be calculated as:

15 mg x 7.711 = 115.67 mg

But 0.8 mL of the drug contains only 80.0 mg. How many mL will contain 115.67 mg?

                   0.8 x 115.67/ 80.0 = 1.16 mL

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Polyethylene is 86.0% C and 14.0%
H. Determine the empirical formula of the compound.
Percent to Mass: How many grams of C/and Hare present in 100.0 g?

Answers

The empirical formula of polyethylene can be determined by converting the given percentages of carbon (C) and hydrogen (H) into grams. To find the grams of each element, we assume a 100.0 g sample of polyethylene.

For carbon:

Mass of carbon = 86.0% × 100.0 g = 86.0 g

For hydrogen:

Mass of hydrogen = 14.0% × 100.0 g = 14.0 g

Therefore, in a 100.0 g sample of polyethylene, there are 86.0 grams of carbon and 14.0 grams of hydrogen.

The empirical formula of a compound represents the simplest whole-number ratio of atoms present in the compound. To determine the empirical formula, we need to find the ratio of carbon to hydrogen in terms of moles.

First, we convert the masses of carbon and hydrogen into moles using their respective molar masses. The molar mass of carbon is approximately 12.01 g/mol, and the molar mass of hydrogen is approximately 1.008 g/mol.

Number of moles of carbon = 86.0 g / 12.01 g/mol ≈ 7.162 mol

Number of moles of hydrogen = 14.0 g / 1.008 g/mol ≈ 13.89 mol

Next, we divide the number of moles of each element by the smallest number of moles to get a simplified ratio.

Carbon: Hydrogen ≈ 7.162 mol : 13.89 mol ≈ 1 : 1.939

Since we want to express the ratio in whole numbers, we multiply both sides by 2 to get a whole number ratio.

Carbon: Hydrogen ≈ 2 : 3.878

Rounding to the nearest whole number, we find that the empirical formula of polyethylene is CH₂.

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what structure in the cheek cell was stained the darkest?​

Answers

Answer:

The nucleus ............

Other Questions
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