Question below...........................

Question Below...........................

Answers

Answer 1

\(\boxed{\sf PE=mgh}\)

\(\boxed{\sf KE=\dfrac{1}{2}mv^2}\)

\(\boxed{\sf ME=KE+PE}\)

#1

\(\\ \sf\longmapsto PE=60(0)(10)=0J\)

\(\\ \sf\longmapsto KE=\dfrac{1}{2}(60)(8)^2=30(64)=1920J\)

\(\\ \sf\longmapsto ME=1920+0=1920J\)

#2

\(\\ \sf\longmapsto PE=60(10)(1)=600J\)

\(\\ \sf\longmapsto KE=600J\)

\(\\ \sf\longmapsto ME=1200J\)

Now

\(\\ \sf\longmapsto \dfrac{1}{2}mv^2=600\implies 30v^2=600\implies v^2=20\implies v=4.2m/s\)


Related Questions

what is the area of velocity time graph​

Answers

The area under a speed-time graph represents the distance travelled.

TRUE OR FLASE

12. During sleep the pituitary gland shuts down for the rest of the night.

13. When a person has a nightmare they wake up in a sweat and don't remember
the content of their dream.

Answers

Answer:

true for first and false for second

Explanation:

The angular speed of Earth is 1.99 x 10-7 radians /seconds.

Answers

Yes, that is correct. The angular speed of Earth is 1.99 x 10-7 radians per second. This is equal to 2π radians per year, or 1 revolution per 365.25 days.

The angular speed of the Earth is the rate at which it rotates around its own axis. It is measured in radians per second, and is typically expressed as 2π radians per day, or 7.27 x 10-5 rad/s. The angular speed of the Earth is constant, meaning that it does not change over time. This is important, as it allows us to measure the length of a day and use this to calculate the rate of other processes such as the seasons and the passage of time.

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How long( in hours, will it take for 500 000 C of charge to flow through a diode if it requires
0.05 Amp to operate it.

Answers

Answer:

277.78 hours

Explanation:

The formula for calculating the amount of charge is expressed as;

Q = It

I is the current

t is the time

Given

I =0.05A

Q = 50,000C

Required

Time t

Recall that: Q = It

t = Q/I

t = 50,000/0.05

t = 1,000,000secs

Convert to hours

1,000,000secs  = 1,000,000/3600

1,000,000secs = 277.78 hours

Hence it will take 277.78 hours for the charge to flow through the diode

Need a 5 paragraph essay in the eartsh layers and how they function/ benefit the earth!

Answers

There is more to the Earth than what we can see on the surface. In fact, if you were able to hold the Earth in your hand and slice it in half, you'd see that it has multiple layers. But of course, the interior of our world continues to hold some mysteries for us. Even as we intrepidly explore other worlds and deploy satellites into orbit, the inner recesses of our planet remains off limit from us.

However, advances in seismology have allowed us to learn a great deal about the Earth and the many layers that make it up. Each layer has its own properties, composition, and characteristics that affects many of the key processes of our planet. They are, in order from the exterior to the interior – the crust, the mantle, the outer core, and the inner core. Let's take a look at them and see what they have going on.

Like all terrestrial planets, the Earth's interior is differentiated. This means that its internal structure consists of layers, arranged like the skin of an onion. Peel back one, and you find another, distinguished from the last by its chemical and geological properties, as well as vast differences in temperature and pressure.

Explanation:

question 8 how to do​

question 8 how to do

Answers

Answer:

We know that the resistance of a material is its length divided by its cross-sectional area and all that multiplied by its resistivity

Hence, resistance = ρ * length(in m) / Cross-sectional area  

(ρ = constant of resistivity)

If you do not understand cross-sectional area, comment on this answer

since both the wires are made of the same substance, both their resistivity will be the same

since we are told that both the wires have the same resistance,

(ρ * length 1) / cross-sectional area 1 = (ρ * length 2) / cross-sectional area 2

since they both have the same resistivity, both the ρ will cancel out

length 1 / cross-sectional area 1  = length 2 / cross-sectional area 2------(1)

Calculating the cross-sectional area

To simplify it , the cross-sectional area is the area of the circle you can currently see on either of the wire

let the radius of wire 1 = 2r

then, the radius of wire 2 = r

Cross-sectional area 1 = π (2r)^2 = 4πr^2

Cross-sectional area 2 = π (r)^2

Now, using these values in (1)

l / 4πr^2 = l' / πr^2

l / l' = 4πr^2/πr^2

l / l'  = 4 / 1

the length of rod 'P' is l

from the equation, we can simplify:

l (length of rod 'P') = 4 l'(length of rod 'Q')

Therefore, we can say that the length of rod 'P' is 4 times the length of rod 'Q'

Which are characteristics of a solid? (Select all that apply.)

It maintains its volume.

It can be compressed.

It keeps its shape.

It fills the container it is in.

Answers

A solid maintains its volume and shape.

In Figure below, m₁=2.00kg and m₂-4.00kg. Consider the pulley to be frictionless. (a) If m₂ is released, what will its acceleration be? (b) What is the tension in the string? m₂ 55 m₂​

Answers

(a) When m₂ is released, its acceleration will be approximately -3.27 m/s².

(b) The tension in the string is approximately -13.08 N.

To determine the acceleration of m₂ when it is released and the tension in the string, we need to consider the forces acting on the system.

(a) Acceleration of m₂:

Since the pulley is assumed to be frictionless, the tension in the string is the same on both sides of the pulley. We can consider the system consisting of m₁ and m₂ as one body. The net force acting on this system is the difference between the weight of m₁ and the weight of m₂:

Net force = m₁g - m₂g

Applying Newton's second law, F = ma, where F is the net force and a is the acceleration, we have:

m₁g - m₂g = (m₁ + m₂)a

Rearranging the equation to solve for the acceleration, we get:

a = (m₁g - m₂g) / (m₁ + m₂)

Substituting the given values, m₁ = 2.00 kg and m₂ = 4.00 kg, and the acceleration due to gravity, g = 9.8 m/s², we can calculate the acceleration:

a = ((2.00 kg)(9.8 m/s²) - (4.00 kg)(9.8 m/s²)) / (2.00 kg + 4.00 kg)

a = (19.6 N - 39.2 N) / 6.00 kg

a = -19.6 N / 6.00 kg

a = -3.27 m/s²

Therefore, when m₂ is released, its acceleration will be approximately -3.27 m/s². The negative sign indicates that the acceleration is in the opposite direction of the gravitational force.

(b) Tension in the string:

The tension in the string can be determined by considering the forces acting on m₂. The net force on m₂ is equal to its mass multiplied by its acceleration:

Net force = m₂a

Substituting the given values, m₂ = 4.00 kg and a = -3.27 m/s², we can calculate the tension:

Tension = (4.00 kg)(-3.27 m/s²)

Tension = -13.08 N

Therefore, the tension in the string is approximately -13.08 N. The negative sign indicates that the tension acts in the opposite direction of the weight of m₂.

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upon leaving her club, the golf ball moved upward to a height above the surrounding trees. is the ke and pe increasing, decreasing, or staying the same?

Answers

ANSWER

PE increases and KE decreases

EXPLANATION

As described, the golf ball is moving and changing its height, like in the following diagram,

By the law of conservation of energy, the total energy when the ball starts moving and during the whole motion until it stops, must be the same. This total energy is the sum of the potential energy and the kinetic energy.

When the club hits the ball, it gives it a certain amount of kinetic energy but no potential energy. As the ball starts going uphill, the potential energy starts to increase, since it depends on the height of the object. Therefore, to maintain the total energy constant, the kinetic energy must decrease.

upon leaving her club, the golf ball moved upward to a height above the surrounding trees. is the ke

explain the methods to determine specific charge of an electron ?​

Answers

The methods to determine the specific charge of an electron are The J. J. Thomson Method and The Millikan Oil Drop Method.

The J. J. Thomson Method

In this method, an electric field is created between two parallel metal plates. Electrons are accelerated by this field from the negative plate to the positive plate. After that, they strike a fluorescent screen. When the electrons are shot through the electric field perpendicular to the magnetic field, they experience the Lorentz force, which is given by the formula: $F= evB$ $F= evB$

When a magnetic field is applied at right angles to an electron beam, it bends the path of the beam into a circular path. The radius of the path of an electron beam in a magnetic field is determined by the relationship:r = mv/eB. As a result, the specific charge of an electron may be calculated from the expression: $e/m = 2V / B^2r^2$

The Millikan Oil Drop Method

This is another technique for determining the specific charge of an electron. The oil drop experiment was first done by Robert A. Millikan in 1909. He did this experiment by suspending charged droplets of oil in a uniform electric field between two parallel plates.

The fall of the oil droplets in the absence of an electric field was also noted. The fall velocity of the oil droplet was determined by measuring the time taken by the oil droplet to pass through a fixed distance between the plates in the absence of an electric field. By measuring the electric field strength, the voltage applied to the plates, and the fall velocity of the oil droplet, the specific charge of the electron was determined.

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The methods to determine the specific charge of an electron are :

The J. J. Thomson Method The Millikan Oil Drop Method.

How do we describe?

In the J. J. Thomson Method, an  electric field is created between two parallel metal plates. Electrons are accelerated by this field from the negative plate to the positive plate. After that, they strike a fluorescent screen.

When the electrons are shot through the electric field perpendicular to the magnetic field, they experience the Lorentz force.

The Millikan Oil Drop Method is an experiment by which is created by suspending charged droplets of oil in a uniform electric field between two parallel plates.

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A negative test charge experiences a force to the right as a result of an electric field. Which is the best conclusion to draw based on this description?

Answers

The most logical conclusion to make in light of the facts available is that the electric field is directed to the left. This conclusion may be drawn from the fact that a negative test charge, which is attracted to positive charges and repels other negative test charges, feels a force to the right.

The force applied to the negative test charge suggests the presence of positive charges in the electric field, indicating that the field lines begin with positive charges and end on negative charges since opposing charges attract.

The assumption that electric field lines originate from positive charges and end on negative charges is supported by this deduction. As a result, in this situation, the electric field is directed leftward.

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Type your response in the box.
Different kinds of substances have different properties. Compare and contrast the electrical properties of salts, acid , metals

Answers

Answer:

salts do not conduct electricity. unless u try to dissociate its ions,it cannot.

metals are good conductors of electricity.

acids also conduct electricity if you dissociate them into ions.

Which of the following is NOT a way that machines provide a mechanical advantage? a. change direction c. change power b. change distance d. change force Please select the best answer from the choices provided A B C D

Answers

The following which is not a way that machines provide a mechanical advantage is that it changes power and is denoted as option C.

What is Mechanical advantage?

This is referred to the measure of how much a force is increased by using a tool or machine and is calculated by finding the ratio of the output force to input force.

Changing the power is not a way in which machines provide a mechanical advantage as a result of the parameter not directly involved in how it functions which is therefore the reason why it was chosen as the correct choice.

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vector A has a magnitude of 8unit Victor has a magnitude of 80 units and makes angle of 45° with the Positive x-axis Vector B has the same magnitude of 8 unit anddirected a long the negative x-axis alon find the magnitude and direction of A+B. ​

Answers

Part: a

First let's represent each vector on a grid.

When we combine vectors visually, we connect the tip (arrow side) of one vector to the tail (non-arrow side) of the other. The vector is then drawn from the beginning point to the final position.The graphical representation of the sum of vectors \($\vec{A}$\)and \($\vec{B}$\) is:[See attachment]

Part: b

The graphical representation \($\vec{A}-\vec{B}$\) is:  [See attachment]

What is Vectors?

Vectors are things that have a magnitude as well as a direction. They may be represented numerically by a number expressing the magnitude and an angle representing the magnitude. They can also be represented visually, with addition and subtraction.A vector is a number that defines not only the size of an object but also its movement or location with respect to another point or object. It is sometimes referred to as a Euclidean vector, a geometric vector, or a spatial vector.The length of the segment of the directed line is known as the magnitude of a vector in mathematics, and the angle at which the vector is slanted displays the vector's direction.

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vector A has a magnitude of 8unit Victor has a magnitude of 80 units and makes angle of 45 with the Positive
vector A has a magnitude of 8unit Victor has a magnitude of 80 units and makes angle of 45 with the Positive
vector A has a magnitude of 8unit Victor has a magnitude of 80 units and makes angle of 45 with the Positive

Calculate the net force exerted on a box.

Calculate the net force exerted on a box.

Answers

Answer:

35 N to the left

Explanation:

Do 65 minus 30, and you get 35 N to the left

Because force is a vector quantity, you have to mention both magnitude and direction in your answer.

What is the independent variable if a scientist is turning bulb on and off to check behaviour of the earthworm?





Answers

The independent variable in this experiment is the act of turning the bulb on and off, while the dependent variable is the behavior of the earthworm in response to changes in light. The scientist can analyze the data collected to determine the impact of light on the earthworm's behavior.

In the experiment where a scientist is turning a bulb on and off to check the behavior of an earthworm, the independent variable is the manipulation performed by the scientist, which is the act of turning the bulb on and off.

The independent variable is the variable that the scientist deliberately changes or controls in order to observe its effect on the dependent variable. In this case, the scientist is interested in investigating how the earthworm responds to changes in light. By turning the bulb on and off, the scientist is manipulating the presence or absence of light in the environment of the earthworm.

The behavior of the earthworm, which is the dependent variable, will be observed and measured in response to the changes in light. The scientist may record various behaviors such as movement, burrowing, or changes in activity level exhibited by the earthworm when the light is turned on and off.

By systematically controlling the independent variable (turning the bulb on and off) and observing the dependent variable (behavior of the earthworm), the scientist can analyze the relationship between light exposure and the earthworm's behavior. This allows for drawing conclusions about how the earthworm responds to light stimuli.

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True or False. A projectile is an object that once set in motion, continues in motion by its own inertia.

Answers

The answer is true.
It’s true hope this helps!!

The motor of an electric drill has a power input of 1200 W. How much work 3 points
is done by the drill in a time of 2 minutes? *
Your answer
This is a required question

Answers

Answer:

Explanation:

1 Watt = 1 J/s

1200 J/s(2 min)(60 s/min) = 144 KJ

The same collision as in Question 5 takes place, only this time the car and the truck bounce off each other completely elastically What are the final velocities of the car and truck just after the collision?

Answers

The final velocities of the car and truck just after the collision will be as per the conservation of momentum.

Momentum is defined as product of mass and velocity of the body. It is denoted by letter p and it is expressed in kg.m/s. Mathematically p = mv. it discuss the moment of the body. body having zero mass or velocity has zero momentum. The dimensions of the momentum is [M¹ L¹ T⁻¹].

According to conservation of momentum, Initial momentum will be equal to the final momentum. In the elastic collision there is no loss of energy, both energy and momentum is conserved.

if the the car is coming with velocity equal to the mass of the truck and truck is coming with mass of the car, then they have same momentum in opposite direction when they collide each other the final velocity of both car and truck becomes zero.

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A ball is throw at an angle of 30 degrees off the horizontal, with an initial velocity of 28 m/s. what is the maximum height the ball will reach?​

Answers

\({\mathfrak{\underline{\purple{\:\:\: Given:-\:\:\:}}}} \\ \\\)

\(\:\:\:\:\bullet\:\:\:\sf{Angle \ of \ projection = 30^{\circ} }\)

\(\:\:\:\:\bullet\:\:\:\sf{Initial \ velocity \ of \ projectile = 28 \: m/s^{-1} }\)

\(\\\)

\({\mathfrak{\underline{\purple{\:\:\:To \:Find:-\:\:\:}}}} \\ \\\)

\(\:\:\:\:\bullet\:\:\:\sf{Height_{\:(max)}\: reached\: by \:the \:projectile }\)

\(\\\)

\({\mathfrak{\underline{\purple{\:\:\: Calculation:-\:\:\:}}}} \\ \\\)

As we know that,

\(\\\)

\(\dashrightarrow\:\: \sf{ H = \dfrac{u^2\;sin^2\theta}{2\;g} }\)

\(\\\)

\(\dashrightarrow\:\: \sf{H = \dfrac{(28)^2\;sin^2 30^{\circ}}{2\;(9.8)} }\)

\(\\\)

\(\dashrightarrow\:\: \sf{H = \dfrac{784 \times \;sin^230^{\circ}}{19.6} }\)

\(\\\)

\(\dashrightarrow\:\: \sf{ H = \dfrac{784}{19.6}\times sin^2 30^{\circ}}\)

\(\\\)

\(\dashrightarrow\:\: \sf{ H = \dfrac{784}{19.6}\times \bigg(\dfrac{1}{2}\bigg)^2 }\)

\(\\\)

\(\dashrightarrow\:\: \sf{ H = \dfrac{784}{19.6}\times \dfrac{1}{4} }\)

\(\\\)

\(\dashrightarrow\:\: {\boxed{\sf{H=10\:m }}}\)

1) Roland has built a circuit, and is using a device called an ammeter to measure how quickly electrical current is flowing through the circuit. He calculates that the current should be 0.1800.180 amps, but he measures the current as 0.1730.173 amps. What is Roland's percent error? 2) Two objects have masses of 1.1551.155 kg and 0.220.22 kg, respectively. Using the correct number of significant figures, what is the sum of these masses? 3) Kwame is measuring the dimensions of a box he will be using in a coming experiment. He measures the dimensions of the box as 0.8850.885 meters wide 0.200.20 meters deep, and 0.750.75 meters tall. Using the correct number of significant figures, what is the volume of this box? please try to answer as many questions as you can, thank you.

Answers

Answer:

1)  3.9 %

2) 1,38 kg

3) 0.13 cubic meters

Explanation:

Part 1)

Calculated current = 0.180 amps

Measured current: 0.173 amps

percent error :   \(\frac{0.180 - 0.173}{0.180} \,100=3.9\) %

Part 2)

mass1 = 1,155 kg

mass2 = 0.22  kg

Addition; 1.155 + 0.22 = 1 375 kg  which should be rounded to just two decimals according to the addition rules for uncertainties:

Answer : 1,38 kg

Part 3)

Volume = 0.885 x 0.20 x 0.75 cubic meters = 0.13275 cubic meters

Notice that the smallest number of significant figures among the set of dimension given is two. Therefore, our answer should be rounded to two significant figures. That is:

Volume = 0.13 cubic meters

what is diffraction grating​

Answers

Answer:

Diffraction Grating: Definition and Applications

A diffraction grating is a device that is used to separate light into its component wavelengths. It consists of a flat surface that has a large number of parallel grooves or lines etched into it. When light is shone onto the grating, it is diffracted into its individual wavelengths, producing a spectrum of colors. Diffraction gratings are commonly used in various applications, such as spectroscopy, astronomy, and telecommunications.

The science behind diffraction gratings is based on the principles of wave interference and diffraction. When light passes through a narrow slit or a small opening, it diffracts, or spreads out, into a series of bright and dark fringes. When a beam of light passes through a grating, the light is diffracted by each of the parallel lines on the surface of the grating, resulting in a series of bright and dark fringes that are spaced apart at regular intervals. The spacing between the lines on the grating determines the amount of diffraction, and therefore the angle at which the diffracted light is scattered.

Diffraction gratings are commonly used in spectroscopy, which is the study of the interaction between light and matter. Spectroscopy is used in various applications, such as identifying the chemical composition of materials, analyzing the spectra of stars and galaxies, and studying the properties of molecules and atoms.

In astronomy, diffraction gratings are used in telescopes and spectrometers to study the spectra of stars and galaxies. By analyzing the spectra, astronomers can determine the chemical composition, temperature, and other properties of celestial objects.

In telecommunications, diffraction gratings are used in fiber-optic communication systems to separate different wavelengths of light. This allows for the transmission of multiple signals over a single optical fiber, increasing the capacity and speed of the communication system.

In conclusion, a diffraction grating is a device that is used to separate light into its component wavelengths. It consists of a flat surface with parallel lines etched into it, which diffract the light and produce a spectrum of colors. Diffraction gratings are commonly used in spectroscopy, astronomy, and telecommunications, and they play an important role in our understanding of the interaction between light and matter.

Explanation:

Answer:

diffraction grating is an optical component with a periodic structure that diffracts light into several beams travelling in different directions.

Explanation:

Hendry throws an object vertically upwards at a velocity of 26,5 m⋅s-1 from the
edge of a cliff of height 120m. After some time, the projectile lands on the
ground below the cliff After 1 second, Cathy fires a second object upwards FROM THE
GROUND BELOW with a velocity of 45 m⋅s-1. Calculate the time and
distance will the two objects meet.

Answers

Hendry and Cathy will each throw an object, and the time and location at which they will collide can be determined using the laws of motion. Hendry's item had an initial velocity of 26.5 m/s, whereas Cathy's object had an initial velocity of 45 m/s. Hendry's object's equation of motion is given by: s = u*t + 0.5*a*t*2, where s is the displacement, u*t* is the starting velocity, t* is the time, and a*t* is the acceleration brought on by gravity.

The acceleration caused by gravity is negative since the item is being flung upward. The item that Cathy threw has the following equation of motion: s = u * t - 0.5 * a * t2.where s is the distance travelled, u is the starting speed, t is the passage of time, and an is the acceleration brought on by gravity. The acceleration caused by gravity is negative since the item is being flung upward.

These equations allow us to determine the location and timing of the two items' collision. By figuring out the two equations for t, one may determine the moment when the objects will collide. By changing the value of t in either equation, one may determine the distance at which the objects will collide. Therefore, using the equations of motion, it is possible to determine the moment and distance at which the two objects will collide.

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5. Use the algebraic technique for adding vectors to find the total displacement of a person who walks the following three paths (displacements-on a flat field. First, she walks 25.0 m in a direction 49.00 north of east. Then she walks 23.0 m heading 15.00 north of east. Finally, she turns and walks 32.0 m in a direction 68.0° south of east. ​

Answers

Answer:

jjjjjjjjjjjjjjjj

Explanation:

A football player with a mass of 100kg runs at a rate of 10m/s. What is the momentum?

Answers

Answer:

1,000KG*M/S

Explanation:

P=M*V

100KG*10M/S=1,000KG*M/S

A 1,100 kg car is traveling at 20 m/s as it begins going down a 40 m hill. What is its total mechanical energy?(1 point)
A 651,200 J
B 211,200 J
C 431,200 J
D 220,000 J

Answers

Answer: 651,200 J

Explanation:

The total mechanical energy of the car is determined as 651,200 J.

Option A is the correct answer.

What is the total mechanical energy of the car?

The total mechanical energy of the car is the sum of the kinetic energy and potential energy of the car.

Mathematically, the total mechanical energy of the car is given as;

M = K.E + P.E

where;

K.E is the kinetic energy of the carP.E is the potential energy of the car

M = ¹/₂mv² + mgh

where;

m is the mass of the carv is the velocity of the carh is the height of the hillg is acceleration due to gravity

The given parameters include;

m is the mass of the car = 1,100 kgv is the velocity of the car = 20 m/sh is the height of the hill = 40 mg is acceleration due to gravity = 9.8 m/s²

M = ¹/₂(1100)(20²) + (1100)(9.8)40)

M = 651,200 J

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eporting results (1) Fifteen measurements of a resistance are quoted here based on approximately 10 repeat measurements. Only three of them obey the five golden rules. Identify the mistakes in the other results. (i) (99.8 ± 0.270) × 103 Ω, (ii) (100±0.3)× 103 Ω, (iii) (100.0±0.3)× 1039, (iv) (100.1 ±0.3) × 103, (v) 97.1 x 103-276Q, (vi) (99.8645 ± 0.2701) × 102 Ω, (vii) 98.6 x 103 ±3 × 10-Q,

Answers

The mistakes in the results include options (v) and (vii) which do not follow the five golden rules for reporting results.

What are the golden rules for reporting results?

The five golden rules for reporting results are:

Always report the uncertainty in the measurement.Report the uncertainty to the same number of decimal places as the measured value.Use the correct units and prefixes.Avoid rounding until the final calculation.Report only the significant figures.

Using these rules, identify the mistakes in the given results as:

(v) 97.1 × 10³ ± 276Ω - The uncertainty is reported to an inappropriate number of significant figures and the units are not consistent.

(vii) 98.6 × 10³ ± 3 × 10^(-Q) - The uncertainty is not reported to the same number of decimal places as the measured value, and the units are not consistent.

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A physics student rolls a ball down a hill with an initial velocity of 2.5m/s. If it accelerates down the hill at a rate of 6.3m/s^2, How long will it take to reach the bottom of the hill, 150 meters away?

Please help!!!

Answers

I'll assume you mean the hill is 150 m along its slope, since that's the direction the ball rolls.

The distance x it rolls after time t is

x = (2.5 m/s) t + 1/2 (6.3 m/s²) t²

Set x = 150 m and solve for t :

150 m = (2.5 m/s) t + 1/2 (6.3 m/s²) t²

(3.15 m/s²) t² + (2.5 m/s) t - 150 m = 0

t = 1/2 [(-2.5 m/s) + √((2.5 m/s)² - 4 * (3.15 m/s²) * (-150 m))]

(Use the quadratic formula, and take the positive root)

t ≈ 6.52 s

A possible means for making an airplane invisible to radar is to coat the plane with an antireflective polymer. If radar waves have a wavelength of 2.92 cm and the index of refraction of the polymer is n = 1.30, how thick (in cm) would you make the coating? (Assume that the index of refraction of the plane is higher than that of the coating. Also assume that the radar waves are normal to the surface of the coating. Give the minimum thickness that would make the airplane invisible to radar.)

Answers

Answer:

The thickness is  \(t = 0.5615 \ cm\)    

Explanation:

From the question we are told that

    The wavelength of the of the rader waves is  \(\lambda = 2.92 \ cm\)

     The index of refraction of the polymer is  \(n = 1.30\)

The thickness is mathematically represented as

             \(t = \frac{\lambda }{4 n }\)

Substituting values

            \(t = \frac{2.92}{4 * 1.30 }\)

          \(t = 0.5615 \ cm\)

Which statement is a scientifically accurate description of velocity?

A, Walking south along the two-mile canyon trail generally takes less time than traveling the same trail north because walking south is all downhill.

B, The hiker began hiking the park's five-mile north hiking trail at 8:00 a.m. with plenty of daylight left to complete the hike before dark.

C, The motorcyclist traveled along a highway at 55 mph and reached the campsite in less than the two-hour estimated time.

D, The boat traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

Answers

Answer: D

Explanation:

north=direction

200-meter= distance

less than 5 minutes= time

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