According to given data, the average speed of train is 25 km/h.
Equation :Given data,
distance = 5 km
time = 12 minutes
average speed = ?
changing time from minute to hour
So,
hour = 12 / 60
hour = 0.2
Then to calculate speed use the formula,
s = d / t
s = 5km / 0.2hr
s = 25 km/h
What is speed?Velocity is the rate and direction of an object's movement, whereas speed is the time rate at which an object is moving along a path. In other words, velocity is a vector value, whereas speed is a scalar value. It has a dimension of time-distance. As a result, the basic unit of time and the basic unit of distance are combined to form the SI unit of speed. Thus, the metre per second (m/s) is the SI unit of speed.
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How does a concentration gradient work? How do solutes and other substances move across the cell membrane? Explain.
A concentration gradient is created when the concentration of a molecule or solute differs on either side of a cell membrane, and this difference drives the movement of molecules and solutes across the membrane. How do solutes and other substances move across the cell membrane? Molecules and ions can diffuse or move across a cell membrane from areas of high concentration to areas of low concentration, which is known as simple diffusion.
They can also be transported by transporters, which are membrane proteins, and the transporters can be passive or active carriers, depending on the energy requirements of the transporter. Active transport, which involves the expenditure of metabolic energy to drive solute transport across a membrane against the concentration gradient, is a type of active carrier. Facilitated diffusion occurs when a protein facilitates the movement of a solute down a concentration gradient; this process is similar to active transport but does not require metabolic energy.
Explanation of the movement of solutes across the cell membrane: During simple diffusion, the movement of solutes occurs across a membrane that has a concentration gradient. Because the membrane is selectively permeable, only certain molecules can move across it. Molecules that are small and uncharged can easily pass through the membrane, while larger or charged molecules are often blocked. Because the solute moves down a concentration gradient, it does not require energy, and it can continue to move across the membrane until the concentrations on both sides of the membrane are equal.
The movement of solutes in facilitated diffusion, which involves the movement of molecules through membrane channels or carrier proteins, is somewhat similar to simple diffusion. Carrier proteins, in particular, help to move molecules through the membrane by undergoing a change in shape as the molecules move across it.
Active transport, which involves the movement of molecules against a concentration gradient, is a process that requires energy. Energy is required for the solute to move across the membrane, and the energy can come from either ATP hydrolysis or the electrochemical gradient of the molecule. The process of active transport is essential for maintaining the balance of ions and molecules within a cell.
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Concentration gradient refers to the gradual variation in concentration of solutes or other substances in a solution that occurs in regions that are separated by a membrane or a barrier. Substances tend to move from an area of higher concentration to an area of lower concentration, down the gradient. This process is called diffusion.
Here's how it works:Substances in a high concentration move toward regions of lower concentration by crossing the membrane or barrier. This happens until the concentration of the substance is uniform throughout the solution.The rate of diffusion across the membrane is influenced by the concentration gradient. A steep gradient results in a faster rate of diffusion, while a shallow gradient results in a slower rate of diffusion.Substances can move across the cell membrane through different mechanisms, depending on their chemical and physical properties. Lipid-soluble substances can diffuse across the lipid bilayer of the membrane, while large and hydrophilic substances require specialized transport proteins to cross the membrane. For example, ions such as sodium, potassium, and calcium move across the membrane through ion channels, while glucose and amino acids move across through transporters. Overall, the movement of solutes and other substances across the cell membrane is an important process that allows cells to maintain a balance of nutrients and other vital components within the cell.
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a) A cell of dry air is moved vertically from its original position under adiabatic conditions. Depending on the temperature profile of the surrounding atmosphere, this gas cell can keep on moving in the same direction, or it may come back to its original position. Considering the temperature profile of the atmosphere, change of the air cell temperature as it moves up and down in the surrounding atmosphere, as well as relative densities of the air cell and atmosphere, explain why and when the atmosphere is considered to be convectively stable and convectively unstable. In answering this question, use diagrams of temperature change with altitude. (13 marks) b) Explain why the adiabatic lapse rate of dry air is different from the adiabatic lapse rate of wet saturated air. Show them both in a diagram. (5 marks) c) Wet unsaturated air rises from the ocean surface. The ambient lapse rate is higher than the adiabatic lapse rate for dry air. There is a temperature inversion layer at higher altitudes. Show in a schematic diagram how the temperature of the wet air changes with altitude, in comparison with the ambient temperature. Explain at what altitudes the cumulus clouds are formed and why. (7 marks)
The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.
a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.
In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.
b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).
This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.
c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.
In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.
Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.
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please help me! Fill in all the blanks using the highlighted words. All 23 please. Thank you!!
Blood travels throughout the body as follows:
oxygen inhale red blood cellsblood vena cavaright atriumright ventriclelungs pulmonary deoxygenated lungs Gas exchangecapillaries oxygenated pulmonaryleft oxygenated heart left atrium ventricle aortaupper lowerHow does circulation work?Circulation is the continuous movement of blood throughout the body by the circulatory system. It consists of the heart, blood vessels (arteries, veins, and capillaries), and blood. The heart acts as a pump, sending oxygen-rich blood through the arteries to the body's cells, and then returning oxygen-depleted blood through the veins back to the heart.
The exchange of oxygen, nutrients, and waste products between the blood and cells occurs through the capillaries. This continuous flow of blood helps to maintain the body's functions and overall health.
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PLEASE HELP!!!! An 85 kg snowboarder accidentally goes off trail and ends up in the middle of a frozen lake and comes to a stop. He remembers taking physics and learning about conservation of momentum in high school and decides to take off his 10 kg backpack
and throw it as hard as he can since he won't need it from being so smart for passing physics) at a speed of 6 m/s East. At what speed and direction will the snowboarder move after throwing the bag?
Okay, so the snowboarder weighs 85 kg and his backpack weighs 10 kg. He throws the backpack with a speed of 6 m/s to the East.According to the law of conservation of momentum, the total momentum before he throws the backpack is 85 kg * 0 m/s (since he's at rest) and the total momentum after he throws the backpack is 85 kg * x m/s + 10 kg * 6 m/s (since the backpack is moving East with a speed of 6 m/s).To find the snowboarder's new speed and direction, we have to set the total momentum before and after equal to each other and solve for x. So,85 kg * 0 m/s = 85 kg * x m/s + 10 kg * 6 m/sWe can solve for x by subtracting 10 kg * 6 m/s from both sides and dividing by 85 kg.x = -0.7143 m/sSo the snowboarder will move with a speed of -0.7143 m/s (which means he will move in the opposite direction of the backpack) and he will move west.
if we know the semimajor axis and ________ of an object’s orbit, then we can determine the object’s closest and farthest points from the mass it is orbiting.
If we know the semimajor axis and eccentricity of an object's orbit, then we can determine the object's closest and farthest points from the mass it is orbiting. The semimajor axis is the distance from the center of mass of the object and the mass it is orbiting, and the eccentricity describes the shape of the orbit. If the eccentricity is zero, the orbit is a perfect circle, and the closest and farthest points are the same distance from the mass.
If the eccentricity is greater than zero, the orbit is elliptical, and the closest point is called the perihelion (or periapsis), while the farthest point is called the aphelion (or apoapsis). Knowing these points can help us understand the behavior of objects in orbit and make predictions about their movements.
If we know the semimajor axis and eccentricity of an object's orbit, then we can determine the object's closest and farthest points from the mass it is orbiting.
Step 1: Identify the semimajor axis (a) and eccentricity (e) values.
Step 2: Calculate the closest point (perihelion) using the formula: Perihelion = a * (1 - e)
Step 3: Calculate the farthest point (aphelion) using the formula: Aphelion = a * (1 + e)
By following these steps, you can find the perihelion and aphelion distances of an object in its orbit around the mass it is orbiting, using the semimajor axis and eccentricity.
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A 3 x 10^-6 C charge is 5m away from a -2x 10^-6 C charge A. Attractive because one is positive the other one is negative B. Determine the magnitude of the electrostatic force acting between them.
Answer:
0.0021576N
Explanation:
F=(k)(q1q2/r^2)
F=(8.99×10^9)(3×10^-6)(2×10^-6)/(5^2)
F=0.0021576N
Physics at UNF: 16-25* You are swinging on one of UNF's swings out by the Student Union. Assume your motion can be represented as a simple harmonic oscillator, where your center of gravity is 2.00 m below the pivot. What is the period of this simple harmonic oscillator? 2.00 s What is the frequency? 1.89 1/5 What is the corresponding angular velocity? 2.21 rad/s
The period of the simple harmonic oscillator is 2.00 s, the frequency is 0.500 Hz, and the corresponding angular velocity is 3.14 rad/s. The motion of a person swinging on a swing can be modelled as a simple harmonic oscillator.
The period, frequency, and angular velocity of the simple harmonic oscillator can be determined from the length of the swing and the acceleration due to gravity.
Let's calculate the period, frequency, and angular velocity of the simple harmonic oscillator in this problem. The period of a simple harmonic oscillator can be calculated using the following formula:
\(T = 2π√(l/g)\), where l is the length of the pendulum and g is the acceleration due to gravity.
The length of the pendulum can be determined as follows: Length of pendulum = Distance from pivot point to center of gravity of the person= 2.00 m. The acceleration due to gravity is approximately 9.81 m/s^2, so the period of the simple harmonic oscillator is
:\(T = 2π√(l/g)\)
= 2π√(2.00/9.81) = 2.00 s
The frequency of the simple harmonic oscillator is given by:
f = 1/T
= 1/2.00
= 0.500 Hz (correct to 3 significant figures)
The corresponding angular velocity is given by:
ω = 2πf
= 2π(0.500)
= 2π(0.500)
= 3.14 rad/s (correct to 3 significant figures)
Therefore, the period of the simple harmonic oscillator is 2.00 s, the frequency is 0.500 Hz, and the corresponding angular velocity is 3.14 rad/s.
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How could you increase the precision and accuracy of your wavelength measurement?
To increase the precision and accuracy of a wavelength measurement, you can take the following steps:
Use a higher-quality measuring instrumentIncrease the number of measurementsHow to increase the precision and accuracy of a wavelength measurementUse a higher-quality measuring instrument: Using a higher-quality instrument that is designed to measure wavelength with high accuracy and precision can improve the results. For example, a high-quality spectrometer can be used to measure the wavelength of light.
Increase the number of measurements: Taking multiple measurements and averaging the results can reduce the effect of random errors and improve precision.
Minimize sources of error: Minimizing sources of error, such as fluctuations in temperature and pressure, can also improve the precision and accuracy of measurements.
Calibrate the instrument: Calibration of the instrument against a known reference can improve the accuracy of measurements.
Use appropriate units: Using appropriate units that are compatible with the instrument being used can prevent errors caused by unit conversions.
Overall, increasing precision and accuracy requires careful attention to the details of the measurement process, from the choice of instrument to the environmental conditions in which the measurement is made.
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a system of two objects has δktot = 6 j and δuint = -5 j. how much work is done by interaction forces
The net work, or the sum of all the work performed by all the forces acting on an item, is equal to the change in the object's kinetic energy as explained by the work-energy theorem. The total energy of the item is changed as a result of the work done after the net force is withdrawn (no further work is being done).
To calculate work done by interaction forces in a system of two objects with δktot = 6 J and δuint = -5 J, we can use the Work-Energy Theorem.
This theorem states that the work done on a system is equal to the change in its kinetic energy. In mathematical terms: Work done = δktot - δuint
Now, we can put in the given values:
Work done = 6 J - (-5 J)
Work done = 6 J + 5 J
Work done = 11 J
So, the work done by interaction forces in the system is 11 J.
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if at a particular instant and at a certain point in space the electric field is in the x-direction and has a magnitude of 3.20 v/m, what is the magnitude of the magnetic field of the wave at this same point in space and instant in time?
The magnitude of the magnetic field at the same point and instant is approximately 1.067 x 10^-8 T. To determine the magnitude of the magnetic field at this point in space and time, we need to know the frequency of the wave.
This is because the electric and magnetic fields of an electromagnetic wave are interrelated through the speed of light and the frequency of the wave. Specifically, the magnitude of the magnetic field is equal to the magnitude of the electric field divided by the speed of light multiplied by the frequency of the wave.
To find the magnitude of the magnetic field (B) at the same point in space and instant in time, we can use the relationship between the electric field (E) and magnetic field in an electromagnetic wave. The relationship is given by the equation: B = E/c, where c is the speed of light (approximately 3.00 x 10^8 m/s). Given the electric field E = 3.20 V/m, the magnetic field magnitude can be calculated as:
B = (3.20 V/m) / (3.00 x 10^8 m/s) ≈ 1.067 x 10^-8 T (tesla).
So, the magnitude of the magnetic field at the same point and instant is approximately 1.067 x 10^-8 T.
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Which career may be a good fit for you if you enjoy planning meals and learning about proper nutrition?
A.
fitness instructor
B.
physical therapist
C.
medical researcher
D.
registered dietician
Answer:
D. Registered dietitian
Answer:
D
Explanation:
Please help
I can’t get this right
Answer:
6,76 x 10^-7 T.
Explanation:
The Magnetic field formula for a wire is B=(μ x I)/2πd , where μ (=4π x 10^-7 Tm/A) is the permeability, I is the current and d is the distance.
Not having to worry about your health, job, or being attacked are related to this level
of needs.
Answer:
This level of needs is known as safety needs. Safety needs are the need for security, stability, and protection from physical and emotional harm. These needs include physical safety, financial security, health and well-being, and protection from discrimination and harassment.
Explanation:
With an increase in strain rate, ductility ______ and tensile strength _____. a) decreases, decreases b) decreases, increases c) increases, increases d) increases, decreases
With an increase in strain rate, ductility decreases and tensile strength increases. Option b. decreases, increases is the correct answer
The ductility of materials decreases as the strain rate rises. The reason is that the material exhibits brittle behaviour. Material increases in tensile strength.
Ductility: A material's ductility refers to its capacity to withstand plastic deformation or drawing without breaking. As a result, it provides information on how "soft" or pliable the material is.
Tensile strength: Maximum load a material can bear without breaking when it is stretched, divided by the material's initial cross-sectional area.
Therefore, option b. is the correct answer for the given question
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Consider a rectangular block of mass 300g has a lergth of 6cm , a wigth of 3cm and a bridth of 1cm. Compute the pressure acting on each face
The pressure acting on the top and bottom faces is\(0.1635 N/cm^2\), the pressure acting on the side faces is\(0.4905 N/cm^2,\) and the pressure acting on the front and back faces is \(0.981 N/cm^2.\)
To compute the pressure acting on each face of the rectangular block, we need to know the weight of the block and the area of each face.
The weight of the block can be calculated as follows:
Weight = Mass x Gravity
Weight = 0.3 kg x 9.81 \(m/s^2\)
Weight = 2.943 N
The area of each face can be calculated as follows:
Top and bottom face: length x width = 6 cm x 3 cm = 18 \(cm^2\)
Side faces: length x height = 6 cm x 1 cm = 6 \(cm^2\)
Front and back faces: width x height = 3 cm x 1 cm = 3\(cm^2\)
Now we can calculate the pressure acting on each face:
Top and bottom face: Pressure = Weight / Area = 2.943 N / \(18 cm^2\) = \(0.1635 N/cm^2\)
Side faces: Pressure = Weight / Area = 2.943 N / \(6 cm^2\) = 0.4905 \(N/cm^2\)
Front and back faces: Pressure = Weight / Area = 2.943 N / 3 cm^2 = 0.981 N/cm^2
Therefore, the pressure acting on the top and bottom faces is\(0.1635 N/cm^2\), the pressure acting on the side faces is\(0.4905 N/cm^2,\) and the pressure acting on the front and back faces is \(0.981 N/cm^2.\)
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What controversial psychological study of prison life took place in 1971?
The controversial psychological study of prison life that took place in 1971 is known as the Stanford Prison Experiment. It was conducted by psychologist Philip Zimbardo and his team at Stanford University to examine how individuals adapt to the roles of prisoners and prison guards in a simulated prison environment.
The study involved 24 male college students who were randomly assigned to either the role of prisoner or guard. The experiment quickly spiraled out of control as the guards began to abuse their power, and the prisoners became increasingly submissive and depressed. The guards used psychological tactics such as humiliation, sleep deprivation, and even physical punishment to maintain their authority over the prisoners.
The study was meant to last for two weeks, but it was terminated after just six days due to the extreme and abusive behavior of the guards. The Stanford Prison Experiment remains controversial due to ethical concerns about the mistreatment of the participants and the potential long-term psychological effects on those who took part.
The study has had a significant impact on the field of psychology and has raised important questions about the ethics of conducting psychological research. It has also shed light on the dangers of group dynamics and how individuals can be easily influenced by social roles and situations.
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a 44 kg , 5.2-m -long beam is supported, but not attached to, the two posts in (figure 1). a 24 kg boy starts walking along the beam. how close can he get to the right end of the beam without it falling over?
The boy can get as close as 1.25 meters from the right end of the beam without it falling over.
What is Torque?
Torque is a measure of the twisting force that causes rotation or angular acceleration of an object. It is often referred to as the moment of force or the turning effect of force. Mathematically, torque is defined as the cross product of the force vector and the lever arm vector, where the lever arm is the perpendicular distance from the point .
To solve this problem, we need to find the point at which the torque due to the boy's weight is equal and opposite to the torque due to the weight of the beam. This will be the point at which the beam is in equilibrium and will not fall over.
First, we can calculate the weight of the beam using the formula:
weight = mass x gravity
where the mass is 44 kg and gravity is 9.8 m/s^2 (acceleration due to gravity)
weight of beam = 44 kg x 9.8 m/s^2 = 431.2 N
Next, we can calculate the torque due to the weight of the beam about the left post. Since the beam is symmetric, this torque will be halfway between the two posts, or 2.6 m from the left post. The torque is given by:
torque = force x distance
torque due to beam = 431.2 N x 2.6 m = 1121.1 Nm
Now, we can consider the torque due to the boy's weight. Let's assume that the boy's weight can be considered as acting at the midpoint of his position on the beam. If he is x meters from the right end of the beam, then his position on the beam is 2.6 + x meters from the left post. The torque due to his weight is then:
torque due to boy = force x distance
torque due to boy = 24 kg x 9.8 m/s^2 x (2.6 + x) m = 235.2 (2.6 + x) Nm
For the beam to be in equilibrium, the torque due to the boy's weight must be equal and opposite to the torque due to the weight of the beam:
235.2 (2.6 + x) = 1121.1
Solving for x, we get:
x = (1121.1 - 235.2 x 2.6) / 235.2 = 1.25 m
Therefore, the boy can get as close as 1.25 meters from the right end of the beam without it falling over.
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What is
meant by (a) Material Properties ( b) Mass Fabric and (c) Mass
Properties in Price's verbal Equation?
In Price's verbal equation, material properties refer to the characteristics and behaviors of a material, mass fabric relates to the distribution and arrangement of mass within a structure, and mass properties involve the quantitative measures of mass distribution and its effects on the structural performance.
(a) Material properties in Price's verbal equation pertain to the specific attributes and qualities of a material that influence its mechanical behavior, such as strength, stiffness, density, thermal conductivity, and elasticity. These properties determine how a material will respond to external forces and environmental conditions, and they play a crucial role in the design and analysis of structures.
(b) Mass fabric refers to the spatial arrangement and distribution of mass within a structure. It considers the organization, orientation, and connectivity of the structural elements that contribute to the overall mass distribution. Mass fabric affects the structural behavior, load transfer paths, and structural efficiency of a system. By understanding the mass fabric, engineers can optimize the arrangement of components to achieve desired structural performance.
(c) Mass properties involve the quantitative measures of mass distribution within a structure and its impact on its mechanical behavior. Mass properties include parameters such as mass, center of mass, moments of inertia, and radii of gyration. These properties provide important information for analyzing the dynamic response, stability, and vibrational characteristics of structures. They also influence the structural design, material selection, and optimization processes.
In Price's verbal equation, these concepts collectively contribute to understanding the behavior and performance of structures, enabling engineers to make informed decisions in design, analysis, and optimization. By considering material properties, mass fabric, and mass properties, a comprehensive understanding of the structural system can be achieved.
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You are in a car traveling at 20 m/s. An ambulance is behind you traveling 35 m/s in the same direction. What frequency do you hear if the siren has a frequency of 550 Hz?
Answer:
The frequency heard is 576.78 Hz
Explanation:
The Doppler effect is defined as the apparent frequency change of a wave produced by the relative movement of the source with respect to its observer. In other words, this effect is the change in the perceived frequency of any wave motion when the sender and receiver, or observer, move relative to each other.
This is what happens in the first part of this problem, where the sender is train A and the receiver is train B. They are both moving in opposite directions. In this case, where both are in motion, the frequency perceived by the receiver will increase when receiver and transmitter increase their separation distance and will decrease whenever the separation distance between them is reduced. The following expression is considered the general case of the Doppler effect:
\(f'=f*\frac{v+-vR}{v+-vE}\)
Where:
f ', f: Frequency perceived by the receiver and frequency emitted by the issuer respectively. Its unit of measurement in the International System (S.I.) is the hertz (Hz), which is the inverse unit of the second (1 Hz = 1 s-1)
v: Velocity of propagation of the wave in the medium. It is constant and depends on the characteristics of the medium. In this case, the speed of sound in air is considered to be 343 m / s
vR, vE: Speed of the receiver and the emitter respectively. Its unit of measure in the S.I. is the m / s
±, ∓:
We will use the + sign:
In the numerator if the receiver approaches the emitter In the denominator if the emitter moves away from the receiverWe will use the sign -:
In the numerator if the receiver moves away from the emitter In the denominator if the emitter approaches the receiverIn this case you are in a car traveling at 20 m/s and an ambulance is behind you traveling 35 m/s in the same direction.
In this case the receiver, you in the car, moves away from the emitter, while the emitter, the ambulance, approaches the receiver behind you in the same direction. So the frequency is calculated by the expression:
\(f'=f*\frac{v-vR}{v-vE}\)
Being:
f= 550 Hzv=343 m/svR= 20 m/svE= 35 m/sand replacing:
\(f'=550 Hz*\frac{343 m/s-20 m/s}{343 m/s-35 m/s}\)
you get:
f'= 576.78 Hz
The frequency heard is 576.78 Hz
3. What type of scientific investigation would you use to view photosynthesis in a
classroom setting? Why?*
Answer: f u
Explanation:
if mdldkdkdmdkdkekek
what do the astrometric, doppler, and transit methods share in common?
They all search for planets by measuring properties of a star rather than of the planets themselves. ... The size of the Doppler shift that we detect depends on the tilt of a planet's orbit.
are eggs a element, a compound, or a mixture
Answer:
I'm gonna go with compund
Answer: a mixture because it is made out of some other substances.
Explanation:
How much work must be done on a spring with a spring constant of 80 N/m to stretch the spring 20 cm?
The amount of work that must be done on the spring to stretch it to 20 cm is 1.6 J.
What is the amount of work done on the spring?The amount of work done on the spring is calculated by applying the following formula as shown below.
W = ¹/₂kx²
where;
k is the spring constantx is the extension of the springThe amount of work that must be done on the spring to stretch it to 20 cm is calculated as follows;
W = ¹/₂ x ( 80 N/m ) x ( 0.2 m ) ²
W = 1.6 J
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8. Calculate the impulse of a 14kg rock that starts at rest and falls to a speed of 6m/s?
Answer:
84 kgm/s
Explanation:
mvf - mvi = impulse
(14kg)(6m/s) - (14kg)(0m/s) = 84 kgm/s
What is a group on the periodic table?
Answer:
A group is a column (vertical, up and down)
Explanation:
A group is vertical and a period is horizontal!
Hope i helped you
Have a great day!
Answer:
A group is a row that goes up and down. (Its vertical)
Explanation:
I do A P E X.
What is the mass of an object if a force of 30 N causes it to accelerate at 1. 5 m/s/s?
The mass of an object if a force of 30 N causes it to accelerate at 1. 5 m/s^2 is 11.33
Newton's second law results in force = mass times acceleration
17 = mass x 1.5
mass = 17/1.5
mass = 11.33
Force is a physical amount that describes the interplay between items. it's far a vector quantity, which means it has both magnitude and course. Force can cause an object to accelerate or change its shape. According to Newton's first law of motion, an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force.
Newton's second law of motion relates force to acceleration, stating that the acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass. Newton's third law of motion states that every action has an equal and opposite reaction, meaning that when two objects interact, they exert equal and opposite forces on each other. There are many types of forces, including gravitational, electromagnetic, frictional, and normal.
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when a rubber cylinder is rubbed with a piece of wool, the cylinder accumulates a negative charge. what can be said about the charge on the wool? why?
Wool acquires a positive charge and equal in magnitude with negative charge on cylinder
When a rubber cylinder is rubbed with a piece of wool, the cylinder accumulates a negative charge. This means that the wool acquires a positive charge. This occurs because electrons are transferred from the wool to the rubber cylinder during the rubbing process, resulting in the rubber having an excess of electrons (negative charge) and the wool having a deficit of electrons (positive charge). This transfer of charges is due to the difference in electronegativity between the materials.
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How does Kirchhoff's Junction Rule apply to series circuits?(1 point) Responses It states that the current can be calculated at any part of the circuit by using V = IR. It states that the current can be calculated at any part of the circuit by using , V, = , IR, . It states that the voltage is the same at all points in the circuit. It states that the voltage is the same at all points in the circuit. It states that the current is the same throughout the entire circuit. It states that the current is the same throughout the entire circuit. It states that the voltage drop across any component of the circuit is equal to V = IR.
11.12 The transfer function of an FIR filter is H(z) = z2(0.5z + 1.2 +0.5z-¹). (a) Find the frequency response H(e) of this filter. Is the phase response of this filter linear? (b) Find the impulse response h[n] of this filter. Is h[n] symmetric with respect to some n? How does this relate to the phase?
For n = -1, h[-n] = 0.5 which is not equal to h[n]. This causes the filter's phase response to be nonlinear.
a) Frequency response, H(e)The frequency response of an FIR filter is evaluated by replacing z with e^jw.
H(e^jw) is then derived as follows:
\(H(e^jw) = e^(jw)(0.5e^(jw) + 1.2 +0.5e^(-jw))H(e^jw)\)
= (1.2 + j0.5 sinw) + j0.5 cosw
This may be written as: H(ejw) = 1.2 + 0.5(2j sinw)e^jw + 0.5e^2jw
The magnitude of H(ejw) is obtained as:
|H(ejw)| = √(1.2^2 + 0.5^2 + 2.4 cos
w)Thus, the frequency response of the FIR filter is |H(ejw)| = √(1.2^2 + 0.5^2 + 2.4 cosw).
The phase response is calculated as: θ(w) = tan^(-1)(0.5 sinw/(1.2 + 0.5 cosw)).
Phase response of the filter is linear. It is because the phase response is a linear function of w.
b) Impulse response, h[n] The impulse response of an FIR filter is obtained by taking an inverse Z-transform of its transfer function. This is done as follows:
H(z) = z²(0.5z + 1.2 +0.5z^(-1))H(z)
= 0.5(z^3 + z²z^(-1) + z^2 + 1.2z^2 + z + 0.5z²z^(-1))
Inverse Z-transforming the equation above gives us: \(h[n] = 0.5(δ[n-3] + δ[n-2] + 1.2δ[n-1] + δ[n] + 0.5δ[n+1])\)
The filter's impulse response is not symmetric with respect to any n. It is because, for n = 0, h[n] = 1.25.
However, h[-n] = 0.5δ[1-n].
Thus, for n = -1, h[-n] = 0.5 which is not equal to h[n]. This causes the filter's phase response to be nonlinear.
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i need help with this question on circuits!!
Answer:
B
A
A
B
Explanation:
In the wiring of houses, a parallel circuit is used, otherwise, if the circuit of one of the parts is interrupted, the current will not enter the other circuits.