Roberto said, "I'm thinking of a fraction that is equivalent to

3/9. The denominator is 2 more than the numerator." What fraction is Roberto thinking of? Enter the numerator in the top blank space and the denominator in the bottom blank space.
MARKING BRAINLIEST

Answer:

2^(n-1)

Step-by-step explanation:

To find the nth term of the sequence 1, 2, 4, 8, 16, 32, 64,..., we can observe that each term is obtained by multiplying the previous term by 2. Therefore, the pattern can be described by the formula:

nth term = 2^(n-1)

In this formula, n represents the position of the term in the sequence.

For example: I

If we want to find the 5th term, we substitute n = 5 into the formula:

5th term = 2^(5-1) = 2^4 = 16

So, the 5th term of the sequence is 16.

The factored form of the original expression is 4v^4x^3(3v^3x^6 + 5y^8).

To factor the expression 12v^7x^9 + 20v^4x^3y^8, we look for the greatest common factor (GCF) among the terms. The GCF is the largest expression that divides evenly into each term.

In this case, the GCF among the terms is 4v^4x^3. To factor it out, we divide each term by 4v^4x^3 and write it outside parentheses:

12v^7x^9 + 20v^4x^3y^8 = 4v^4x^3(3v^3x^6 + 5y^8)

By factoring out 4v^4x^3, we are left with the remaining expression inside the parentheses: 3v^3x^6 + 5y^8.

The expression 3v^3x^6 + 5y^8 cannot be factored further since there are no common factors among the terms. Therefore, the factored form of the original expression is 4v^4x^3(3v^3x^6 + 5y^8).

Factoring allows us to simplify an expression by breaking it down into its common factors. It can be useful in solving equations, simplifying calculations, or identifying patterns in algebraic expressions.

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Answer:

median = 3.5

Step-by-step explanation:

the median is the middle value of the data sey. If there is no exact middle then it is the average of the values either side of the middle.

listing the values from the data set

1 , 1 , 2, 3 ,  4 , 4 , 4 , 5

               ↑ middle

median = (3 + 4) ÷ 2 = 7 ÷ 2 = 3.5

Answer:

x = 23

Step-by-step explanation:

4x + 8 - 8 = 100 - 8

4x = 92

(4x) / 4 = 92 / 4

x = 23

Answer:

x = 23

Step-by-step explanation:

4x + 8 = 100 ( subtract 8 from both sides )

4x = 92 ( divide both sides by 4 )

x = 23

Answer:

12

Step-by-step explanation:

2i * (-6)i

-12i^2

-12(-1)

12

Answer: d

Step-by-step explanation:

The number with an absolute value (distance away from zero on a number line) that is greater than 5 will be: A. -6.

Absolute value of any number is simply the distance of that number from point zero (0) on a number line.

-6 is 6 units from 0.

6 is also 6 units away from 0.

-5 is 5 units from 0.

5 is also 5 units from 0.

Therefore, the number with an absolute value (distance away from zero on a number line) that is greater than 5 will be: A. -6.

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Answer:

Step-by-step explanation:

gradient = 5 = [k-(-1)]/[6-2]

[k+1]/4 = 5

k+1=20

k=19

The value of k in the line that passes through the points A(2, -1) and (6, k) with a gradient of 5 is found to be 19 by using the formula for gradient and solving the resulting equation for k.

To find the value of k in the line that passes through the points A(2, -1) and (6, k) with a gradient of 5, we'll use the formula for gradient, which is (y2 - y1) / (x2 - x1).

The given points can be substituted into the formula as follows: The gradient (m) is 5. The point A(2, -1) will be x1 and y1, and point B(6, k) will be x2 and y2. Now, we set up the formula as follows: 5 = (k - (-1)) / (6 - 2).

By simplifying, the equation becomes 5 = (k + 1) / 4. To find the value of k, we just need to solve this equation for k, which is done by multiplying both sides of the equation by 4 (to get rid of the denominator on the right side) and then subtracting 1 from both sides to isolate k. So, the equation becomes: k = 5 * 4 - 1. After carrying out the multiplication and subtraction, we find that k = 20 - 1 = 19.

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The possible solution set for the system is (- 1, 4) and (4, - 1).

Given are the equations as -

x + y = 3

x² + y² = 17

Refer to the graph of the function attached. The points of intersection represents the possible solution set.

Therefore, the possible solution set for the system is (- 1, 4) and (4, - 1).

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Step-by-step explanation:

12 = 2 × 2 × 3

18 = 2 × 3 × 3

56 = 2 ×2 × 2 × 7

Now

Common factor = 2

Remaining factor = 2 × 3 × 2 × 3 × 7

LCM = RF × CF

= 504

hence the lCM of 12 , 18 and 56 is 504...

\(...\)

The following shapes can be a cross section of a cylinder: circle, square, rectangle, and parallelogram.

A cylinder is a three-dimensional shape with a circular base and a lateral surface that is a rectangle. The cross section of a cylinder is the shape that is created when we slice through the cylinder with a plane that is perpendicular to the axis of the cylinder.

The possible cross sections of a cylinder are limited to shapes that are circles, squares, rectangles, and parallelograms. This is because the cross section of a cylinder must have the same dimensions as the base of the cylinder.

The circle is the most common cross section of a cylinder. This is because the base of a cylinder is always a circle. However, it is also possible to have a square, rectangle, or parallelogram as a cross section of a cylinder.

Circle: The circle is the most common cross section of a cylinder. This is because the base of a cylinder is always a circle. The circle is also the only cross section of a cylinder that has no sharp edges.

Square: A square is also a possible cross section of a cylinder. This is because the square is a regular quadrilateral, and the base of a cylinder is always a regular quadrilateral.

Rectangle: A rectangle is also a possible cross section of a cylinder. This is because the rectangle is a regular quadrilateral, and the area of a cylinder is always a regular quadrilateral.

Parallelogram: A parallelogram is also a possible cross section of a cylinder. This is because the parallelogram is a regular quadrilateral, and the base of a cylinder is always a regular quadrilateral.

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Question: Select all the correct answers. Which of the following shapes can be a cross sectlon of a cylinder?

5/1

Step-by-step explanation:

you get the whole number which is 5, turn it into a fraction which is 5/1 and it says 5 students like to sing.

I hope this helped

#5/1 is answer

Answer:

b

Step-by-step explanation:

3(2x+1)-(x-1)

\ / / /

5x+2

Answer:

fgcgfcgchgcchcgccghccghcgcghgghcgchchchgcgcghchgchg

Step-by-step explanation:

Given:

The different functions in the form of set of ordered pairs.

To find:

The function which has an inverse that is also a function.

Solution:

A relation is a function if there exists unique y-value for each x-value.

We know that the inverse transformation is defined as:

\((x,y)\to (y,x)\)

So, the inverse of function is also a function if their exists unique x-value for each y-value in the function.

In option A, all x-values and y-values are unique. It means, inverse of this function is also a function. So, option A is correct.

In option B, \(x=-4\) and \(x=-1\) when \(y=6\). It means, inverse of this function is not a function. So, option B is incorrect.

In option C, \(x=-1\) and \(x=4\) when \(y=8\). It means, inverse of this function is not a function. So, option C is incorrect.

In option D, \(x=4\) and \(x=11\) when \(y=1\). It means, inverse of this function is not a function. So, option D is incorrect.

Therefore, the correct option is A.

The p-value can be calculated to test the null hypothesis that the average running time of HP laptops is 120 minutes against the alternative hypothesis that it is not equal to 120 minutes.

The p-value for testing the hypothesis that the average time for the HP laptops is not equal to 120 minutes can be calculated using a t-test. Given a sample mean of 122 minutes, a sample size of 60, a null hypothesis mean of 120 minutes, and a standard deviation of 25 minutes, we can calculate the t-value and find the corresponding p-value.

To calculate the t-value, we use the formula: t = (sample mean - null hypothesis mean) / (sample standard deviation / sqrt(sample size))

Plugging in the values, we get: t = (122 - 120) / (25 / sqrt(60))

Calculating the t-value, we find t ≈ 0.894

To find the p-value associated with this t-value, we can refer to a t-distribution table or use statistical software. The p-value represents the probability of observing a t-value as extreme as the one obtained, assuming the null hypothesis is true.

Since the p-value (0.757) is greater than the commonly used significance level of 0.05, we fail to reject the null hypothesis. This suggests that there is not enough evidence to conclude that the average running time of HP laptops is significantly different from 120 minutes.

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Answer:

sorry

Step-by-step explanation:

We have a basket and a hat.

The basket has the numbers 1, 2, 3, 4 and 5.

The hat contains the letters A, B, C and D.

We have to calculate the probabiltiy of drawing a number that is greater than 3 from the basket and drawing the letter C from the hat.

We have two events:

- Drawing a number greater than 3 from the basket

- Drawing a C from the hat

They are independent as the probability of each on does not depend on the outcome of the other event.

Then, we can calculate the probability of the two events happening together as the product of its probabilities:

The probability of drawing a number greater than 3 can be described as 2/5, as we have 2 numbers greater than 3 (4 and 5) out of 5 numbers in the basket.

The probability of drawing a letter C can be described as 1/4, as we have one letter C out of 4 letters available.

Then, we can calculate the probability as:

Answer: the probability is 1/10 or 0.1.

Answer:

the daily balance of Elliott's account for the month of June is $1497.37.

Step-by-step explanation:

Day 1: 1223

Day 10: 1838 (1223+615)

Day 15: 1775 (1838 - 63)

Day 22: 1655 (1775 - 120)

To find the average daily balance, we add up the balances for each day and divide by the number of days in June:

The numbers on the mailboxes could be considered either categorical or quantitative data. The correct Option is C: Either categorical or quantitative data.

The numbers on the mailboxes can be considered either categorical or quantitative data, depending on the context in which they are being used.

If the numbers are simply labels for the mailboxes, with no inherent numerical value or order, then they can be considered categorical data. In this case, the numbers would be treated as labels for the different categories or groups, rather than as measurements with numerical significance.

On the other hand, if the numbers are being used to represent a quantity or a position in a sequence, then they can be considered quantitative data. For example, if the numbers represent the physical location of the mailbox within a building, or the order in which mail is sorted and delivered, then they can be treated as numerical measurements.

Therefore, without further context, the numbers on the mailboxes could be considered either categorical or quantitative data.

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Answer: n = 20

Step-by-step explanation:

Given that the problem goes thus:

When a number, n is added to 1/5 n of itself, the outcome obtained is 24.

Mathematically,

n + 1/5 of n = 24

n + (1/5n) = 24

1n + 1/5n = 24

(5n + 1n) / 5 = 24

6n / 5 = 24

6n = 24 × 5

6n = 120

n = 120 / 6

n = 20

Answer:

B on edg, n=20

Step-by-step explanation:

Answer:

17

Step-by-step explanation:

Answer:

2.861

Step-by-step explanation:

What is the value of the t score for a 99% confidence interval if we take a sample of size20? Thus, the t-score for a 99% confidence interval for sample size 20 is 2.861.

1) The amplitude c+ is c+l

2) The expectation value is 0

3) The uncertainty ΔSX is √(3/7) c+.

Now, we know that any wave function can be written as a linear combination of two spin states (up and down), which can be written as:

Ψ = c+ |+> + c- |->

where c+ and c- are complex constants, and |+> and |-> are the two orthogonal spin states such that Sx|+> = +1/2|+> and Sx|-> = -1/2|->.

Hence, we can write the given wave function as:Ψ = c+|+> + i/√7|->

Now, we know that the given wave function has been defined in Sx basis, and not in the basis of |+> and |->.

Therefore, we need to write |+> and |-> in terms of |l> and |r> (where |l> and |r> are two orthogonal spin states such that Sy|l> = i/2|l> and Sy|r> = -i/2|r>).

Now, |+> can be written as:|+> = 1/√2(|l> + |r>)

Similarly, |-> can be written as:|-> = 1/√2(|l> - |r>)

Therefore, the given wave function can be written as:Ψ = (c+/√2)(|l> + |r>) + i/(√7√2)(|l> - |r>)

Therefore, we can write:c+|l> + i/(√7)|r> = (c+/√2)|+> + i/(√7√2)|->

Comparing the coefficients of |+> and |-> on both sides of the above equation, we get:

c+/√2 = c+l/√2 + i/(√7√2)

Therefore, c+ = c+l

The amplitude c+ is a real number and is equal to c+l

The expectation value of the operator Sx is given by: = <Ψ|Sx|Ψ>

Now, Sx|l> = 1/2|r> and Sx|r> = -1/2|l>

Hence, = (c+l*) + (c+l) + (i/√7) - (i/√7)(c+l*)= -i/√7(c+l*) + i/√7(c+l)= 2i/√7 Im(c+)

As c+ is a real number, Im(c+) = 0

Therefore, = 0

The uncertainty ΔSX in the state |Ψ> is given by:

ΔSX = √( - 2)

where = <Ψ|Sx2|Ψ>and2 = (<Ψ|Sx|Ψ>)2

Now, Sx2|l> = 1/4|l> and Sx2|r> = 1/4|r>

Hence, = (c+l*) + (c+l) + (i/√7) - (i/√7)(c+l*)= 1/4(c+l* + c+l) + 1/4(c+l + c+l*) + i/(2√7)(c+l* - c+l) - i/(2√7)(c+l - c+l*)= = 1/4(c+l + c+l*)

Now,2 = (2i/√7)2= 4/7ΔSX = √( - 2)= √(1/4(c+l + c+l*) - 4/7)= √(3/14(c+l + c+l*))= √(3/14 * 2c+)= √(3/7) c+

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The training heart rate function, T(M) for a person with a resting heart rate of 62 beats per minute is 0.6M.

a. The maximum heart rate function, M() for a person a years of age. M(x) is 220 - x.

The formulas provided are:

T(M, R) = R + 0.6(M - R)M(z) = 220 - z

where R is the resting heart rate, M is the maximum heart rate, and z is the age.

Using the formula T(M, R) = R + 0.6(M - R), we can find the training heart rate function, T(M), for a person with a resting heart rate of 62 beats per minute:

T(M, R) = R + 0.6(M - R)T(M, 62) = 62 + 0.6(M - 62)T(M, 62) = 62 + 0.6M - 37.2T(M, 62) = 24.8 + 0.6M

Therefore, the training heart rate function for a person with a resting heart rate of 62 beats per minute is T(M) = 24.8 + 0.6M.

To find the maximum heart rate function, M(x), for a person a years of age, we can use the formula M(z) = 220 - z:

M(z) = 220 - z

M(a) = 220 - a

Therefore, the maximum heart rate function for a person a years of age is M(x) = 220 - x.

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B1. the bottle would contain less than 36 oz approximately 20.33% of the time when the machine is set at 37 oz.

B2. The bottles will overflow approximately 4.75% of the time when the machine is set at 38 oz.

B3. The probability that at least one bottle will overflow out of 10 bottles filled when the machine is set at 38 oz is approximately 99.9%.

B4. The probability that exactly 3 bottles will overflow out of 15 bottles filled when the machine is set at 38 oz is approximately 25.0%.

B5. The bottle would need to be approximately 40.796 oz or larger to avoid overflowing 99.8% of the time when the machine is set at 38 oz.

B1. To find the percentage of time the bottle contains less than 36 oz when the machine is set at 37 oz, we need to calculate the probability that a random bottle will have a volume less than 36 oz.

Using the normal distribution, we can calculate the z-score (standardized score) for 36 oz using the formula:

z = (x - μ) / σ

where x is the desired value (36 oz), μ is the mean of the process (37 oz), and σ is the standard deviation (1.2 oz).

z = (36 - 37) / 1.2

z ≈ -0.833

Using a standard normal distribution table or a statistical calculator, we can find the cumulative probability associated with this z-score.

P(X < 36) = P(Z < -0.833) ≈ 0.2033

Therefore, the bottle would contain less than 36 oz approximately 20.33% of the time when the machine is set at 37 oz.

B2. To find the percentage of time the bottles will overflow when the machine is set at 38 oz, we need to calculate the probability that a random bottle will have a volume greater than 40 oz.

Using the normal distribution, we can calculate the z-score for 40 oz using the formula mentioned earlier:

z = (x - μ) / σ

z = (40 - 38) / 1.2

z ≈ 1.67

Using a standard normal distribution table or a statistical calculator, we can find the cumulative probability associated with this z-score.

P(X > 40) = P(Z > 1.67) ≈ 0.0475

Therefore, the bottles will overflow approximately 4.75% of the time when the machine is set at 38 oz.

B3. To find the probability that at least one bottle will overflow out of 10 bottles filled when the machine is set at 38 oz, we can use the complement rule and subtract the probability that none of the bottles overflow.

The probability of no overflow in a single bottle is given by:

P(X ≤ 38) = P(Z ≤ (38 - 38) / 1.2) = P(Z ≤ 0) ≈ 0.5

Therefore, the probability of no overflow in 10 bottles is:

P(no overflow in 10 bottles) = (0.5)¹⁰ ≈ 0.00098

The probability that at least one bottle will overflow is the complement of no overflow:

P(at least one overflow in 10 bottles) = 1 - P(no overflow in 10 bottles) ≈ 1 - 0.00098 ≈ 0.999

Therefore, the probability that at least one bottle will overflow out of 10 bottles filled when the machine is set at 38 oz is approximately 99.9%.

B4. To find the probability that exactly 3 bottles will overflow out of 15 bottles filled when the machine is set at 38 oz, we can use the binomial distribution formula:

P(X = k) = (nCk) * \(p^k * (1 - p)^{(n - k)\)

where n is the number of trials (15), k is the desired number of successes (3), p is the probability of success (probability of overflow), and (nCk) is the number of combinations.

Using the probability of overflow calculated in B2:

p = 0.0475

The number of combinations for selecting 3 out of 15 bottles is given by:

15C3 = 15! / (3! * (15 - 3)!) = 455

Plugging the values into the binomial distribution formula:

P(X = 3) = 455 * (0.0475)³ * (1 - 0.0475)¹² ≈ 0.250

Therefore, the probability that exactly 3 bottles will overflow out of 15 bottles filled when the machine is set at 38 oz is approximately 25.0%.

B5. To determine the required size of the bottle to avoid overflowing 99.8% of the time when the machine is set at 38 oz, we need to find the z-score corresponding to a cumulative probability of 0.998.

Using a standard normal distribution table or a statistical calculator, we find the z-score for a cumulative probability of 0.998 to be approximately 2.33.

Using the formula mentioned earlier:

z = (x - μ) / σ

Substituting the known values:

2.33 = (x - 38) / 1.2

Solving for x:

x - 38 = 2.33 * 1.2

x - 38 ≈ 2.796

x ≈ 40.796

Therefore, the bottle would need to be approximately 40.796 oz or larger to avoid overflowing 99.8% of the time when the machine is set at 38 oz.

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Answer:

A is 2,8 and b is 2,3

asked my teacher

Step-by-step explanation:

Answer:

A

Step-by-step explanation

B. is slope intercept formula

Answer:

Option 2

Step-by-step explanation:

10:28 plus 47 is 11:15

a. The distance a baseball travels in the air after being hit is a continuous random variable. b. The number of free-throw attempts before the first shot is made is a discrete random variable.

a. The distance a baseball travels in the air after being hit is a continuous random variable. A continuous random variable can take on any value within a certain range, and in this case, the distance can theoretically take on any non-negative real value. The distance can vary continuously, such as 100.5 feet, 100.51 feet, or even 100.5123456 feet. Therefore, it is considered a continuous random variable.

b. The number of free-throw attempts before the first shot is made is a discrete random variable. A discrete random variable can only take on specific, separate values, usually whole numbers or a countable set of values. In this case, the number of attempts can only be an integer value, such as 0, 1, 2, and so on. You cannot have a fractional or non-integer number of attempts. Hence, the number of free-throw attempts before the first shot is made is a discrete random variable.

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Answer:

32.5

Step-by-step explanation:

We can set this problem up as a proportion:

\(\frac{10}{25} = \frac{13}{x}\) In doing this, we find the exact distance from Boomtown to Dayville. Another way to do it is by dividing 25 by 10, to get 2.5, then multiplying 2.5 by 13 to get 32.5

In the special case of two degrees of freedom, the chi-squared distribution does not coincide with the exponential distribution. The chi-squared distribution is a continuous probability distribution that arises in statistics and is used in hypothesis testing and confidence interval construction. It is defined by its degrees of freedom parameter, which determines its shape.

On the other hand, the exponential distribution is also a continuous probability distribution commonly used to model the time between events in a Poisson process. It is characterized by a single parameter, the rate parameter, which determines the distribution's shape.

While both distributions are continuous and frequently used in statistical analysis, they have distinct properties and do not coincide, even in the case of two degrees of freedom. The chi-squared distribution is skewed to the right and can take on non-negative values, while the exponential distribution is skewed to the right and only takes on positive values.

The chi-squared distribution is typically used in contexts such as goodness-of-fit tests, while the exponential distribution is used to model waiting times or durations until an event occurs. It is important to understand the specific characteristics and applications of each distribution to appropriately utilize them in statistical analyses.

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