The compound sentence is Russia has a variety of natural resources such as oil, natural gas, timber, iron ore, copper and lead as well.
A compound sentence is a sentence that is formed from two more simple sentence by using the connective words.
For an example if sentence 1 is "It is raining" and sentence 2 is "It is cold" then the compound sentence of both the above sentences will be "It is raining and it is cold".
Now, Russia has a variety of natural resources, including oil, natural gas, Timber, iron ore, copper and lead.
This statement is a simple sentence.
This statement can be return as a compound sentence as follows,
Russia has a variety of natural resources such as oil natural gas and lead as well.
Here, we have used the word "such as" as a connective.
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Complete Question - Russia has a variety of natural resources including oil, natural gas, timber, iron ore, copper and lead (change into compound sentence)
he unknown solution is prepared by mixing CaCO3(s) and HCl(aq). The H2CO3 produced in this reaction decomposes to CO2 (g) and H2O. Write the complete chemical equation for this reaction, indicating the state of each species. If ionic compounds dissociate, separate the ions in the equation.
Answer:
CaCO₃(s) + 2 H⁺(aq) + 2 Cl⁻(aq) ⇒ Ca²⁺(aq) + 2 Cl⁻(aq) + H₂O(l) + CO₂(g)
Explanation:
Let's consider the molecular equation that occurs when CaCO₃(s) reacts with HCl(aq).
CaCO₃(s) + 2 HCl(aq) ⇒ CaCl₂(aq) + H₂O(l) + CO₂(g)
The complete ionic equation includes all the ions and the compounds that do not dissociate in water.
CaCO₃(s) + 2 H⁺(aq) + 2 Cl⁻(aq) ⇒ Ca²⁺(aq) + 2 Cl⁻(aq) + H₂O(l) + CO₂(g)
A force of attraction between the opposite of charges of the ions in an lonic compound is called what?
Answer:
Ionic bonds
Explanation:
The force of attraction between the opposite charges of the ions in an ionic compound is called an ionic bond.
An ionic bond results from the electrostatic force of attraction between oppositely charged ions.
This attraction creates an ionic or electrovalent bond.
The bond type is usually between a metal ion and a non-metal ion.how many moles of Fe2O3 will react with 99.0 g of Al
Taking into account the reaction stoichiometry, 1.83 moles of Fe₂O₃ will react with 99.0 g of Al
Reaction stoichiometryIn first place, the balanced reaction is:
2 Al + Fe₂O₃ → Al₂O₃ + 2 Fe
By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:
Al: 2 molesFe₂O₃: 1 moleAl₂O₃: 1 moleFe: 2 molesThe molar mass of the compounds is:
Al: 27 g/moleFe₂O₃: 159.7 g/moleAl₂O₃: 102 g/moleFe: 55.85 g/moleBy reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Al: 2 moles ×27 g/mole= 54 gramsFe₂O₃: 1 mole ×159.7 g/mole= 159.7 gramsAl₂O₃: 1 mole ×102 g/mole= 102 gramsFe: 2 moles ×55.85 g/mole= 111.7 gramsMass of Fe₂O₃ requiredIt is possible to use a simple rule of three as follows: If by reaction stoichiometry 54 grams of Al react with 1 mole of Fe₂O₃, 99 grams of Al react with how many moles of Fe₂O₃?
moles of Fe₂O₃= (99 grams of Al ×1 mole of Fe₂O₃)÷54 grams of Al
moles of Fe₂O₃= 1.83 moles
Finally, 1.83 moles of Fe₂O₃ is needed.
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The volume of ammonia gas at .930 atm of pressure is gradually decreased from 96.2mL to 44.7mL. What is the final pressure of ammonia if there is no change in temperature?
Initial Pressure = P₁ = 0.930 atm
Final Pressure = P₂ = ?
Initial Volume = V₁= 96.2 mL
Final Volume = V₂ = 44.7 mL
Temperature = constant
If we consider that ammonia as an Ideal Gas, and since the temperature is constant we can apply Boyle's Law. It says that at constant temperature:
P₁ * V₁ = P₂ * V₂
If we divide at both sides by V₂:
P₁* V₁ / V₂ = P₂ * V₂ / V₂
On the right side we can cancel V₂ and we get:
P₁* V₁ / V₂ = P₂
P₂ = P₁* V₁ / V₂
Replacing by the values that we were given:
P2 = 0.930 atm * 96.2 mL / (44.7 mL)
P2 = 2.00 atm
So the final pressure is 2.00 atm
1. You have samples of 3 different dandelion poisons. They cost $10 a gallon, $20 a gallon and $30 a gallon respectively. You would like to determine which one is the most effective. State your hypothesis, design an experiment, and state a result that would support your hypothesis. (1 point)
The most effective poison is the poison that cost $30 per gallon.
Procedure to determine the sample that is most effectivei) Hypothesis : Most expensive poison is the most effective
ii) Experiment :
Plant 12 dandelions under similar conditions which are :
same soil same temperature water lightDivide the 12 Dandelions into four (4) different groups labelled ;
A B CDApply the most expensive ( $30 ) poison to group A
Apply the second most expensive ( $20 ) poison to group B
Apply $10 poison to group C
Keep group D under natural conditions
iii) Result
The Dandelions grouped in Group A will die off faster than the plants grouped in other groups. which makes the poisons that cost $30 to be most effective.
Hence we can conclude that the most effective poison is the one that cost $30 per gallon.
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Which statement about members of a homologous series is true
The statement "Each member of a homologous series differs from its nearest neighbors by 14 amu" is true of members about a homologous series.
What are homologous series?In organic chemistry, a homologous series unveils itself as a sequential assembly of compounds exhibiting an identical functional group, boasting akin chemical traits. Within this series, the constituents can either sport a branched or unbranched structure, or deviate through the molecular formula of CH2 and a molecular mass variation of 14u.
This divergence may manifest as the elongation of a carbon chain, as observed in the linear alkanes (paraffins), or as the augmentation in the count of monomers forming a homopolymer, such as amylose.
The entities belonging to a homologous series typically embrace a fixed assortment of functional groups, thereby conferring upon them resemblant chemical and physical characteristics.
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Use your data, the equation to the right, and the specific heat of water (4.184 J/g C) to compute the specific heat values of each metal. Use a calculator and round to the nearest hundredth place.
The heat capacity for the metals are;
Aluminum - 0.89
Copper - 0.11
Iron - 0.44
Lead - 0.12
What is the specific heat?The specific heat of a substance is denoted by the symbol "C" and is typically measured in units of J/g·°C (joules per gram per degree Celsius) or cal/g·°C (calories per gram per degree Celsius).
The specific h
We have that;
For Aluminum;
c = 4.184 * 39.85 * 4.7/11.98 * 72.9
= 783.6/873.3
= 0.89
For Copper;
c = 4.184 * 12.14 * 1.9/12.14 * 75.4
= 96.5/915.3
= 0.11
For Iron
c = 4.184 * 40.24 * 2.4/12.31 * 75.1
= 404.1/924.5
= 0.44
For Lead
c = 4.184 * 39.65 * 0.7/12.46 * 76.7
c = 116.1/955.68
= 0.12
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The mole fraction of urea (MW = 60.0g/mol) in a solution prepared by dissolving 16g of urea in 39g of H20 (MW = 18.02g/mol) is a) 0.11b) 0.13c) 0.37d) 0.58e) 9.1
Step 1 - What is molar fraction?
The molar fraction of a substance can be obtained by dividing its number of moles by the total number of moles in the solution (i.e., moles of solute + solvent):
\(molar\text{ fraction = }\frac{number\text{ of moles of solute}}{total\text{ number of moles}}\)Step 2 - Calculating the molar fraction of urea
Let's calculate the number of moles for each substance in the solution (water and urea). In order to do so, we just have to divide their mass by their molar mass:
\(\begin{gathered} for\text{ urea}\rightarrow16/60=0.26 \\ for\text{ water }\rightarrow39/18=2.16 \end{gathered}\)The molar fraction of urea can be writen thus as:
\(molar\text{ fraction of urea = }\frac{0.26}{2.16\text{ + 0.26}}=\frac{0.26}{2.42}=0.11\)Answer: the molar fraction of urea in this solution is 0.11
Which of these happens when the warm water gets to the North and South Poles
Answer:It creates a heat source on the cold water and the molecules act against each other and then it becomes steam.
Explanation:I had to take this on a test.
What type of reaction is this?
Cu + O2 ---> CuO2 -The first reaction is a combustion reaction
2 HCl + Mg → H2 + MgCl2- The second reaction is a Single replacement reaction
What is a combustion reaction?A combustion reaction is a type of chemical reaction that occurs between a fuel and an oxidizer in the presence of heat or light, resulting in the release of energy in the form of heat and light.
In other words, it is a reaction in which a substance reacts with oxygen to produce heat and light.
Combustion reactions are important in many aspects of daily life, including the burning of fossil fuels for energy production, the combustion of wood or other materials for heating or cooking, and the combustion of fuels in internal combustion engines.
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Identify reagents that can be used to achieve each of the following transformations. In some cases, more than one answer may be correct. To receive full credit, select all that apply. 1) LIAIH4, 2) H20 Na2Cr207, H2S04, H20 PCC, CH2Cl2 NaBH4, MeOH
The reagents that can be used to achieve of the following transformation is Na2Cr207, H2S04, H20 and PCC, CH2Cl2.
What is chemical reaction?
One or more chemicals, known as reactants, are changed into one or more new substances, known as products, during a chemical reaction. Chemical elements or chemical compounds constitute substances.
In the chemical reaction, 2 butanol is converted to 2 butanone by using oxidizing agent like PCC, ch2cl2 or other reagent is na2cr2o7, h2so4, h2o used this reagent where secondary alcohol is converted to ketone.
Therefore, the reagents that can be used to achieve of the following transformation is Na2Cr207, H2S04, H20 and PCC, CH2Cl2.
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In this activity, you are tasked with designing an airbag for a company that creates airbags for automobiles. You must design the driver’s front airbag for a specific car model so it will protect the driver as effectively as possible. For this car, the airbag must have a volume of 58 liters when fully inflated. To provide an adequate cushion for the driver’s head, the air pressure inside the airbag should be 4.4 psi. This pressure value is in addition to the normal atmospheric pressure of 14.7 psi, giving a total absolute pressure of 19.1 psi, which equals 1.30 atmospheres.
The airbag is designed to produce the volume of nitrogen gas required to fill up the airbag.
What is the function of an airbag?An airbag is a bag which is designed to self-inflate and serve as a cushion for the head and neck of a driver to prevent injuries when an impact occurs head-on on the car.
The gas that inflates the airbag is nitrogen which is produced from sodium azide according to equation below:
2NaN₃ → 2Na + 3N₂In conclusion, the design of the airbag is such that the correct amount of sodium azide is present to produce the volume of nitrogen required to fill up the airbag.
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What is the percent yield of CO2 if 46.5 grams of CO2 is recoveredfrom the reaction of 21.5 grams of C2H2 according to the reaction below?2 C2H2 + 5 O2 —> 4 CO2 + 2 H2O
The Percentage Yield is 63.9%
Hello
To solve this problem, we would calculate the theoritical yield of the reaction first.
Theoritical YieldThe theoritical yield of the reaction can be calculated using the equation of reaction.
Given that 2 moles of C₂H₂ will produce 4 moles of CO₂
This implies that
2*26g (from molar mass of C₂H₂) will produce 4*44g of CO₂
52g of C₂H₂ = 176g of CO₂
21.5g of C₂H₂ = xg of CO₂
cross multiply and solve for x
\(\begin{gathered} x=\frac{21.5\times176}{52} \\ x=72.77g \end{gathered}\)From the calculation above, the theoritical yield of CO₂ is 72.77g
Let's use this information and solve for the percentage yield.
Percentage YieldThis is the ratio between the actual yield to the theoritical yield and multiplied by 100.
Mathematically,
\(\text{percentage yield}=\frac{actual\text{ yield}}{theoritical\text{ yield }}\times100\)Data;
Actual yield = 46.5g
Theoritical yield = 72.77g
percentage yield = ?
\(\begin{gathered} \text{percentage yield}=\frac{46.5}{72.77}\times100 \\ \text{percentage yield = 63.9 \%} \end{gathered}\)From the calculations above, the Percentage Yield is 63.9%
3. Given 20g of Barium Hydroxide, how many grams of
Ammonium Nitrate would it take for all the Barium Hydroxide
to react? Balance the chemical equation first
The number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g
First, we will write the balanced chemical equation for the reaction
The balanced chemical equation for the reaction is
Ba(OH)₂ + 2NH₄NO₃ → 2NH₄OH + Ba(NO₃)₂
This means, 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate
Now, we will calculate the number of moles of barium hydroxide present.
Mass of barium hydroxide (Ba(OH)₂) = 20 g
Using the formula
\(Number\ of\ moles = \frac{Mass}{Molar\ mass}\)
Molar mass of Ba(OH)₂ = 171.34 g/mol
∴ Number of moles of Ba(OH)₂ present =\(\frac{20}{171.34}\)
Number of moles of Ba(OH)₂ present = 0.116727 mole
Now,
Since 1 mole of barium hydroxide is required to react with 2 moles of ammonium nitrate
Then,
0.116727 mole of barium hydroxide will react with 2 × 0.116727 mole of ammonium nitrate
2 × 0.116727 = 0.233454 mole
∴ Number of moles of NH₄NO₃ required is 0.233454 mole
Now, for the mass of ammonium nitrate (NH₄NO₃) required
From the formula
Mass = Number of moles × Molar mass
Molar mass of NH₄NO₃ = 80.043 g/mol
∴ Mass of NH₄NO₃ required = 0.233454 × 80.043
Mass of NH₄NO₃ required = 18.68636 g
Mass of NH₄NO₃ required ≅ 18.7g
Hence, the number of grams of ammonium nitrate (NH₄NO₃) it would take for all the barium hydroxide to react is 18.7g
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Question 3
How many grams of aluminum sulfate are in a sample that has 1.14 moles of sulfate anions?
g.
Enter your answer below to 3 significant figures.
Do NOT include units.
I
Question 4
How many grams of copper(II) sulfate pentahydrate are in a sample that has 6.62 g of copper?
For question 3 and question 4, we have:
a) The mass of aluminum sulfate in a sample that has 1.14 moles of sulfate anions is 130 g.
b) The mass of copper(II) sulfate pentahydrate in a sample that has 6.62 g of copper is 26.01 g.
a) The chemical formula of aluminum sulfate is Al₂(SO₄)₃.
So, in 1 mol of Al₂(SO₄)₃ we have 2 moles of Al³⁺ (aluminum cations) and 3 moles of SO₄²⁻ (sulfate anions). If we have 1.14 moles of sulfate anions, then the number of moles of aluminum sulfate is:
\(n_{Al_{2}(SO_{4})_{3}} = \frac{1\: mol_{Al_{2}(SO_{4}^{2-})_{3}}}{3 \:moles_{SO_{4}^{2-}}}*1.14 \:moles_{SO_{4}^{2-}} = 0.38 \:moles\)
Now, we can find the mass of Al₂(SO₄)₃:
\( m_{Al_{2}(SO_{4})_{3}} = n_{Al_{2}(SO_{4})_{3}}*M = 0.38 moles*342.15 g/mol= 130 g \)
Hence, the mass of aluminum sulfate is 130 g.
b) The chemical formula of copper(II) sulfate pentahydrate is CuSO₄·5H₂O.
Since in 1 mol of CuSO₄·5H₂O we have 1 mol of Cu²⁺, the mass of CuSO₄·5H₂O can be calculated as follows:
\( m_{CuSO_{4}\cdot 5H_{2}O} = \frac{1 \:mol_{CuSO_{4}\cdot 5H_{2}O}}{1 \: mol_{Cu}}*\frac{1 \: mol_{Cu}}{63.55 g_{Cu}}*\frac{249.68 g_{CuSO_{4}\cdot 5H_{2}O}}{1 \:mol_{CuSO_{4}\cdot 5H_{2}O}}*6.62 \:g_{Cu} = 26.01 g \)
Therefore, the mass of copper(II) sulfate pentahydrate is 26.01 g.
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Draw the structure of 4-methylcycloheptanol.
Answer:
Answer is in the attachment
An organic substance with the chemical formula C8H16O is 4-methylcycloheptanol. It has a cycloheptane ring with a methyl group (CH3) linked to one of the carbon atoms, making it a cyclic alcohol. In the ring, the hydroxyl group (-OH) is joined to a different carbon atom.
There are seven carbon present in the ring and one carbon of methyl, so 4-methylcycloheptanol contains eight carbon in the structure.
Since this would result in C-C-C bond angles far larger than the tetrahedral angle of around 109.5°, cycloheptane is not a flat molecule. Instead, it is three-dimensional and puckered.
The structure of "4-methylcycloheptanol" is attached in the image below.
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how many grams of oxygen are required to reach with 0.125 moles of zinc sulfide?
Answer:
6 g of O₂
Explanation:
We'll begin by writing the balanced equation for the reaction. This is illustrated below:
2ZnS + 3O₂ —> 2ZnO + 2SO₂
From the balanced equation above,
2 moles of ZnS reacted with 3 moles of O₂.
Next, we shall determine the number of mole of O₂ required to react with 0.125 mole of ZnS. This can be obtained as follow:
From the balanced equation above,
2 moles of ZnS reacted with 3 moles of O₂.
Therefore, 0.125 mole of ZnS will react with = (0.125 × 3)/2 = 0.1875 mole of O₂.
Thus, 0.1875 mole of O₂ is needed for the reaction.
Finally, we shall determine the mass of 0.1875 mole of O₂. This can be obtained as follow:
Mole of O₂ = 0.1875 mole
Molar mass of O₂ = 2 × 16 = 32 g/mol
Mass of O₂ =?
Mass = mole × molar mass
Mass of O₂ = 0.1875 × 32
Mass of O₂ = 6 g
Therefore, 6 g of O₂ is required for the reaction.
A spider has several eyes.
What is the main function of these organs?
I’ll give y’all 100 points
Answer:
it is d
Explanation:
Answer: d
Explanation: i think that answer
10. What is the molality of a solution
containing 288 g of calcium chloride
dissolved in 2.04 kg of water?
The choice of solution has a concentration of 1.144 mol/kg molality.
What exactly are molality and molarity?Molarity corresponds to the moles of solvent divided by the amount of solution in litres, whereas molality is equal with the moles of solvent divided by the quantity of solvent in kilogrammes.
Is one molarity the same as one molality?Since 1 mole of solute is present in 1 litre for the solution, which contains both the solute and the solvent, 1 molar aqueous solutions are more concentrated than one decays aqueous solutions.
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What type of mutation occurred?
Original: ATT CAC
Mutated: ATT TCA C
substitution (point)
insertion (addition)
deletion
Answer:
insertion (addition)
Explanation:
A T was added, making the sequence shift.
Hi! Can someone help me with this???
The question: Will these compounds form single, double or triple bonds?
d) CCℓ4
I'm just a bit confused because the Lewis structures look like it would be a 4 bond, but I don't know if thats even a thing. My only options are single, double or triple.
Thank you!
Hey there,
I hope this answer solves your doubt.
Step-by-step Explanation:-
The question is asking if the bonds between Carbon and Chlorine in CCl4 will be single, double or triple bonds.
(The structure of CCl4 is attached as picture. Check it)
As per image, the structure consists of Single bonds. It is 4 single bonds.
500.0 liters of a gas in a flexible-walled container are prepared at 0.92 atm and 473K. The gas is placed into a tank under high pressure. When the tank cools to 293K, the pressure of the gas is 3.0 atm. What is the volume of the gas?
P1V 1 T2=P 2 V 2 T 1
Question 17 options:
48 L
248 L
19 L
95 L
The volume of the gas in the tank at 293K and 3.0 atm pressure is 248 L. Hence, option B is correct.
Given:
T1 = 473K
T2 = 293K
P1 = 0.92 atm
P2 = 3.0 atm
The ideal gas law equation is:
PV = nRT
where P is pressure, V is volume, n is the number of moles of gas, R is the universal gas constant, and T is temperature.
n1 = (PV)/(RT)
= (0.92 atm × 500.0 L)/(0.0821 Latm/molK × 473K)
= 10.42 mol
Use the ideal gas law again to find the final volume of the gas in the tank under high pressure:
V2 = (n1 × R × T2)/P2
= (10.42 mol × 0.0821 Latm/molK × 293K)/(3.0 atm)
= 248 L
Therefore, the volume of the gas in the tank at 293K and 3.0 atm pressure is 248 L.
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Answer:
Using the ideal gas law, PV=nRT, where P is pressure, V is volume, n is the number of moles, R is the gas constant, and T is temperature in Kelvin, we can solve for n:
n = PV/RT
We know that the initial volume is 500.0 L, pressure is 0.92 atm, and temperature is 473K. We can use this information to find the initial number of moles:
n1 = (0.92 atm x 500.0 L)/(0.08206 L atm/mol K x 473K) = 11.80 mol
Next, we can use the ideal gas law again to find the final volume. We know that the final pressure is 3.0 atm and the final temperature is 293K:
V2 = nRT2/P2
V2 = (11.80 mol x 0.08206 L atm/mol K x 293K)/3.0 atm = 95 L
Therefore, the volume of the gas at the lower temperature and higher pressure is approximately 95 L. Answer: 95 L.
b. How many kJ of heat are needed to completely vaporize 50.0g of water at 100°C? [Ans:113. kJ]
The amount, in kJ, of heat needed to completely vaporize 50.0g of water at 100°C is 118.8 kJ.
Heat of vaporization of waterThe heat needed to completely vaporize 50.0g of water at 100°C can be calculated using the following formula:
q = m x Hv
where:
q is the heat needed in joules (J)m is the mass of water in grams (g)Hv is the heat of vaporization of water which is approximately 40.65 kJ/mol at standard temperature and pressure.First, we need to convert 50.0g to moles by dividing by the molar mass of water which is approximately 18.015 g/mol3:
moles of water = 50.0 g / 18.015 g/mol moles of water = 2.776 mol
Thus:
q = (2.776 mol) x (40.65 kJ/mol) q = 112.8 kJ
In other words, 112.8 kJ of heat is needed to completely vaporize 50.0g of water at 100°C.
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Help please thank you
Answer:
B I think I am pretty sure
A 300.0 mL quantity of hydrogen is collected over water at 19.5 C and a total atmospheric pressure of 750. mm Hg. The partial pressure of water at this temperature is 17.0 mm Hg
The partial pressure of hydrogen in the collected gas sample is 733.0 mm Hg (calculated by subtracting the partial pressure of water, 17.0 mm Hg, from the total atmospheric pressure, 750.0 mm Hg).
When a gas is collected over water, the presence of water vapor affects the total pressure observed. In this case, the total atmospheric pressure is given as 750.0 mm Hg, and the partial pressure of water vapor at 19.5°C is 17.0 mm Hg.
To determine the partial pressure of hydrogen, we need to subtract the partial pressure of water vapor from the total atmospheric pressure. Partial pressure refers to the pressure exerted by an individual gas component in a mixture. In this scenario, the collected gas is primarily hydrogen, with water vapor being the other component.
By subtracting the partial pressure of water vapor (17.0 mm Hg) from the total atmospheric pressure (750.0 mm Hg), we can find the partial pressure of hydrogen:
Partial pressure of hydrogen = Total atmospheric pressure - Partial pressure of water vapor
Partial pressure of hydrogen = 750.0 mm Hg - 17.0 mm Hg
Partial pressure of hydrogen = 733.0 mm Hg
Therefore, the partial pressure of hydrogen in the collected gas sample is 733.0 mm Hg.
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Which physical property does the inventor need to consider when choosing a
material for the container?
A. Ductility
B. Thermal conductivity
C. Transparency
D. Electrical conductivity
Answer:
A.
............
Explanation:
Ductility
Discuss the large-scale environmental impacts of soil pollution caused by industrial wastes.
Answer: Industrial processes including mining and manufacturing historically have been leading causes of soil pollution. Industrial areas typically have much higher levels of trace elements and organic contaminants. This is due to intentional and unintentional releases from industrial processes directly into the environment, including to the soil, adjacent water bodies, and the atmosphere.
Explanation:
Which process is not a state of matter change
A.melting
B.freezing
C.stirring
D.evaporation
Answer:
C. sterling hope it helps
a chemical reaction experiment was carried out with the objective of comparing if a new catalyst b would give higher yields than the old catalyst a. the experiment was run on five different batches of raw material which were known to be quite different from one another. each batch was divided into two portions to which a or b was applied at random. the data collected are given in the following table: Catalyst 10 30 28 18 23 22 21 12 a). Explain the experimental design (b)_ Carry out the appropriate t-test.
According to the problem, we need to determine whether new catalyst B would give higher yields than old catalyst A. The given data is a paired sample, because both the catalysts were experimented on 6 different batches of raw materials.
(a) Explain the experimental design.
Here the data collected is from 6 different raw materials, which were divided into two portions. Therefore, two data were obtained for each of the 6 raw materials, which implies in scientific terms that repeated data was obtained for each of the 6 raw materials. Thus, this type of design is known as Repeated-Measures Design.
(b) Carry out the appropriate t test.
For testing whether the new catalyst B will give higher yields than old catalyst A, a Paired-Sample t-test needs to be performed. The test will be performed using R Studio. The R codes and output are as below.
R CODE
# Load the Data A <- c(9,19,28,22,18,8) B <- c(10,22,30,21,23,12) # Paired Sample t-test t.test(A,B,paired = TRUE,alternative = "less")
R OUTPUT
# Paired Sample t-test > t.test(A, B, paired = TRUE, alternative = less) Paired t-test = data: A and B t = -2.6458, df = ">
The decision rule for this test is: "If the p-value < 0.05, then reject the null hypothesis, under 0.05 level of significance; otherwise accept the null hypothesis".
Decision: As p-value (= 0.02283) < 0.05, so we decide to REJECT the null hypothesis, under 0.05 level of significance.
Conclusion: As the null hypothesis is to be rejected, so we can conclude that "there is sufficient evidence conclude that the new catalyst B gives a higher yield than old catalyst A".
(c) Construct a 95% confidence interval for the difference between catalysts A and B.
From part (b),
we have obtained the R output about the 95% confidence interval for the difference between catalysts A and B as:
Therefore, the 95% confidence interval for the difference between catalysts A and B is (-∞, -0.56).
In frequency statistics, the confidence interval (CI) is the range of estimated values for an unknown parameter. Confidence intervals are computed at the specified confidence level. A 95% confidence level is the most common, but other levels such as 90% and 99% are sometimes used . The confidence level represents the proportion of corresponding CIs over time that contain the true value of the parameter. For example, 95% of all intervals computed at the 95% level must contain the true value of the parameter.
Factors that affect the width of the CI include confidence level, sample size, and within-sample variability. All other things being equal, the larger the sample, the narrower the confidence interval. Similarly, the more varied the sample, the wider the confidence interval, and the higher the confidence level, the wider the confidence interval.
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a. When comparing the two elements Ca and As , the more metallic element is:__________ based on periodic trends alone.
b. When comparing the two elements Ca and As , the more metallic element is: ______________ based on periodic trends alone.
c. When comparing the two elements Sb and Pb , the more metallic element is:___________ based on periodic trends alone.
d. When comparing the two elements S b and P b , the more metallic element is: ________________ based on periodic trends alone.
Answer:
Ca.
Sb.
Explanation:
a. When comparing the two elements Ca and As , the more metallic element is:__________ based on periodic trends alone.
The correct option is Ca. Ca belongs to group 2 which is more easily give off it's electrons, compared to As which is a group 5 member.
c. When comparing the two elements Sb and Pb , the more metallic element is:___________ based on periodic trends alone.
The correct option here is Pb. Thhs is because ionization energy decreases down the group. Pb has a lower ionization enthalpy than Sb
Answer:
a) Ca
b) Ca
c) Pb
d) Pb
Explanation:
We must have it behind our minds that metallic properties decreases as we tend towards the right and side of the periodic table. This implies that we find more metallic species at the left hand did of the periodic table and as we tend towards the right hand side, elements become less metallic as indicated by periodic trends.
Calcium is a group 2 metal with full metallic properties while arsenic is a metalloid. Similarly, lead is a group 14 metal with full metal properties while antimony is a metalloid. Hence the answers given above.