Because the demographic group is dictated by location of the college. In this case the students are all college bound and have like socio ecconomic backgrounds.
What do you mean by sampling?
Sampling is the process of choosing the group from which you will actually collect data for your study. For instance, you could interview a sample of 100 students if you were examining the viewpoints of students at your university. With the help of sampling, you can test a statistical hypothesis on the features of a population.
According to the question,
A true sampling would be a mixed demographic group. A sampling from several like areas:
e.g. infront of the student store, infront of the regular store, infront if a food pantry, infront of ... or even better do a blind survey.
Because the demographic group is dictated by location of the college. In this case the students are all college bound and have like socio ecconomic backgrounds.
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Abigail was driving down a road and after 4 hours she had traveled 86 miles. At this
speed, how many hours would it take Abigail to drive 215 miles?
Fill out the table of equivalent ratios until you have found the value of x.
It would take Abigail 10 hours to drive 215 miles at this speed.
A proportion to solve this problem:
Let x be the number of hours it would take Abigail to drive 215 miles.
Then, we can set up the following proportion:
4/86 = x/215
To solve for x, we can cross-multiply:
4 × 215 = 86 × x
860 = 86x
Finally, we can isolate x by dividing both sides by 86:
x = 10
To fill out the table of equivalent ratios:
Hours Distance
4 86
x 215
We can set up the equivalent ratio as:
4/86 = x/215
Cross-multiply and solve for x as shown above.
A ratio to address this issue is:
Let x be the total time Abigail would need to go 215 miles.
Then, we may establish the ratio shown below:
4/86 = x/215
We can cross-multiply to find x:
4 × 215 = 86 × x 860 = 86x
By dividing both sides by 86, we can finally isolate x: x = 10.
To complete the corresponding ratios table:
Hours Distance
4 86 x 215
The corresponding ratio may be written as follows:
4/86 = x/215
Cross-multiply and find x as previously demonstrated.
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Events A and B are disjoint. Find P(AorB) when P(A) = 0.55 and P(B) = 0.2
P (A or B)=
Answer:
0.75 = P(A or B)
Step-by-step explanation:
Since the events are disjoint, we can find the probability of one or the other occurring merely by adding P(A) and P(B): 0.55 + 0.2 = 0.75 = P(A or B)
Can someone please answer this, ill give you brainliest Would be very appreciated.
For the function: (x-4)(x+2)
y intercept: (0, -8)x intercept: (-2, 0) and (4, 0)vertex: (1, -9)Point these coordinates and draw a curve on the graph.
Answer:
See below ~
Step-by-step explanation:
Information needed to sketch the graph's function :
x-intercepts : (4, 0) and (-2, 0)Vertex : (1, -9)y-intercept : (0, -8)Graph :
By plotting these points on a graph, and connecting the points by a curve, we obtain the resultant graph of the function :
help
Write an inequality to represent:
One-fourth of r subtracted from ten is greater than five
Responses
A 10 - 14r > 510 - 1 4 r > 5
B 14r - 10 < 51 4 r - 10 < 5
C 14r - 10 > 51 4 r - 10 > 5
D 10 - 14r < 5
The expression of the inequality statement is (a) (a) 10 - 1/4r > 5
How to determine the expression of the inequality?From the question, we have the following parameters that can be used in our computation:
One-fourth of r subtracted from ten is greater than five
Express as numbers and operators
So, we have
1/4 of r subtracted from 10 is greater than 5
Introduce the inequality symbol
So, we have the following representation
1/4 of r subtracted from 10 > 5
Express "subtracted" and "or" as operators
So, we have the following representation
10 - 1/4r > 5
Hence, the expression is (a) 10 - 1/4r > 5
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What is the relationship between the slopes of two perpendicular lines?
relation between two slopes of two perpendicular line are equal.
The relationship between the slopes of two perpendicular lines is that the product of the slopes of the two lines is equal to -1.
What are perpendicular lines?Two geometric objects are perpendicular in elementary geometry if they intersect at a right angle. When two lines cross at a straight angle, they are said to be perpendicular.
The relationship between the slopes of two perpendicular lines is that the product of the slopes of the two lines is equal to -1. Therefore, assuming that there are two lines that are perpendicular to each other such that the slope of the two lines is m₁ and m₂. Therefore, we can write the relation as,
m₁ × m₂ = -1
Hence, the relationship between the slopes of two perpendicular lines is that the product of the slopes of the two lines is equal to -1.
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HELP ME PLEASE THERES A PICTURE I WILL GIVE BRAINLIEST TO BEST ANSWER
Answer:
we need to know how many students are in the class
if there are more boys, than the probability of picking a boy is higher, and if there is more girls, the probability of picking a girl is higher and if the amount of boys and girls are the same, then the probability of picking a girl or a boy is the same.
Step-by-step explanation:
Please mark my answer as brainliest
Calcula la suma de las longitudes de los catetos, si la hipotenusa mide 15 u y la altura relativa a ella mide 6 u.
UwU
Answer:
9 sqrt(5)
Step-by-step explanation:
La altura relativa a la hipotenusa corta la hipotenusa en dos segmentos.
Defina x como
x = la longitud de uno de esos segmentos
Entonces, la longitud del otro segmento = 15 - x.
Entonces, por el teorema, tenemos que (15-x) (x) = 36, de modo que
15x - x ^ 2 = 36
x ^ 2 - 15x + 36 = 0
(x-3) (x-12) = 0
Entonces, x = 3 o x = 12.
Sin pérdida de generalidad. sea x = 3.
Entonces, la suma de las dos piernas es
raíz cuadrada (6 ^ 2 + 3 ^ 2) + raíz cuadrada (12 ^ 2 + 6 ^ 2) =
raíz cuadrada (36 + 9) + raíz cuadrada (144 + 36) =
raíz cuadrada (45) + raíz cuadrada (180) =
raíz cuadrada (9 * 5) + raíz cuadrada (36 * 5) =
3 raíz cuadrada (5) + 6 raíz cuadrada (5) =
9 cuadrados (5)
Giving brainliest hehehehe
Answer:
A
Step-by-step explanation:
quotient is answer to division problem
Answer: A.
Step-by-step explanation:
In the division model you divide to find the number of counters in each group. ... In multiplication the numbers you multiply are called factors; the answer is called the product. In division the number being divided is the dividend, the number that divides it is the divisor, and the answer is the quotient.
I hope this helps plz tell me if its wrong so i can fix it.
BRAINLIEST AND 100 POINTS!!
Create a comparative box plot for the morning and afternoon dogs, and label each with its five-number summary.
Sara's dogs:
Morning:
39, 21, 12, 27, 23, 19, 19, 31, 36, 25
Afternoon:
15, 51, 8, 16, 43, 34, 27, 11, 8, 39
Answer:
see attached
Step-by-step explanation:
Morning:
12, 19, 19, 21, 23, 25, 27, 31, 36, 39
Min value: 12
Lower quartile (Q1): 19
Median (Q2): 24
Upper Quartile (Q3): 31
Max value: 39
Afternoon:
8, 8, 11, 15, 16, 27, 34, 39, 43, 51
Min value: 8
Lower quartile (Q1): 11
Median (Q2): 21.5
Upper Quartile (Q3): 39
Max value: 51
Answer:
7. AM IQR: 12 PM: IQR: 28 8. see below in explanation
Step-by-step explanation:
7. 31-19=12
39-11= 28
You subtract Q1 from Q3 to get the IQR.
8. I believe the morning group of dogs would be easier to walk as one group because the group has a closer range of weights (12-39) compared to the afternoon group of (8-51). Walking a large group of dogs with similar weights would be easier than walking a group of very small and very large dogs at the same time because their pace of walking would be so different.
The medal Zena won for athletics consists of silver and brass in the ratio 3:5. If the medal has a mass of 200g, calculate the mass of the silver.
Answer: mass of silver is 75g
Step-by-step explanation:
A ________ sample is a type of probability sample in which a researcher divides the population into segments that relate to the study's topic. Group of answer choices
A stratified sample is a type of probability sample where the population is divided into segments related to the study's topic before selecting participants.
In a stratified sample, the researcher divides the population into distinct subgroups or strata based on certain characteristics or variables that are relevant to the study. Each subgroup or stratum represents a smaller, homogeneous subset of the population. The characteristics used to create the strata could be demographic factors such as age, gender, ethnicity, or any other relevant variables.
Once the population is divided into strata, participants are then randomly selected from each stratum using probability sampling techniques. This ensures that the sample obtained is representative of the overall population in terms of the characteristics or variables of interest.
By utilizing a stratified sample, researchers can ensure that each subgroup or stratum is adequately represented in the sample, allowing for more accurate and precise conclusions to be drawn about the entire population. Stratified sampling is particularly useful when there is significant heterogeneity within the population, as it allows for targeted and focused analysis within specific subgroups.
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Express 29 out of 40 as a percentage
Answer:
72.5%
Step-by-step explanation:
To express a value as a %:
value/whole x 100 = 29 / 40 x 100
This gives you 72.5%
Hope this helps
PLEASE HURRY
Given:
1 = 4
2 = 3
Prove:
AB = CD
Which of the following triangle congruence theorems would be used in this proof?
ASA
AAS
SSS
ASA triangle congruence theorems would be used in this proof.
What is ASA rule ?
According to the ASA rule, two triangles are said to be congruent if any two of the angles and sides that make up one triangle are equal to the corresponding two angles and sides that make up the other triangle.
When two or more triangles are congruent, their corresponding angles and sides are also congruent, according to the formula CPCTC, which stands for "corresponding parts of congruent triangles are congruent".
So, AB=CD
Thus, ASA triangle congruence theorems would be used in this proof.
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Can anyone Help me on this ?
Answer: 52=y and 15=x
Step-by-step explanation:
Since we know m and n are parallel that means alternate exterior angles are equal to each other.
The angle with 8x+8= the angle above the one that says 3x+7
Two angles on a line add up to 180 so 8x+8+3x+7=180
Now we can solve
\(8x+8+3x+7=180\\(8x+3x)+(8+7)=180\\11x+15=180\\11x+15-15=180-15\\11x=165\\\frac{11x}{11} =\frac{165}{11} \\x=15\)
Now we know that x=15
The angle y and the angle of 3x+7 are corresponding angles. Corresponding angles are congruent. Subbing in 15 for x we can solve for y
\(3(15)+7=y\\45+7=y\\52=y\)
In triangle XYZ the measure of angle YXZ is 50°, and the measure of angle XYZ is 75°. What is the measure of angle XZY in degrees?
Answer:
55°
Step-by-step explanation:
A triangle always has 180° and if we know 2 angles we can just subtract those 2 angles from 180 to find the last angle, which is 55
Answer:
55
Step-by-step explanation:
because if you add 50 and 75 and then subtract it by 70 you will get 55
Okapuka Tannery in Gobabis district runs a butchery on their farm in addition to other activities on the property. Okongora Farm rears the cattle themselves and each animal slaughtered results in the following products; Fresh Meat which sells for N$25 per kg, some portion of meat is processed into Biltong and the biltong are sold for N$50 per kg, the Hides from the cattle are further processed on the farm and sold to a company that manufacture and sell leather shoes, Kennedy Leather for N$40 each. Horns are also processed further and sold to local Craftsmen for N$800 per pair. Scraps, Hooves and Bones which are donated to the local SPCA (Society for the Prevention of Cruelty to Animals).
During December 2021, 250 cattle were slaughtered. Joint costs incurred in the slaughtering process per animal, based on normal capacity (budgeted) of 300 animals, has been summarized as follows:
Variable costs, (excluding cost of the animal) at N$1.00 per kg.
Fixed cost N$108 000 per month.
The cost of the animal is N$2 500, and on average it weighs 300 kg.
Each animal, on average, yields the following:
A pair of horns weighing 10 kg
Biltong meat weighing 70 kg
Fresh meat weighing 100 kg
Hide weighing 40 kg
Scraps and bones weighing 80 kg
Further processing costs are as follows:
Horns Biltong Hides Total
Variable costs
- Per animal N$40 N$15 N$55
- Per kg N$5 N$5
You are recently hired by Okongora Tannery and your first task is to allocate the joint costs to the joint products.
Except for the scraps, hooves and bones, hides are the only by-product. The NRV of the byproduct should be used to reduce the joint cost of the joint products.
REQUIRED:
5.1 Use the physical unit method to allocate joint costs to the products. [6]
5.2 Use the constant gross profit method to allocate joint costs to the products. [8]
5.3 The management of Okongora Tannery thinks the sales value method of allocating joint costs is the best method for decision making. Explain whether you agree or disagree with this statement. [2]
The physical unit method is used to allocate joint costs to the products.
In the physical unit method, joint costs are allocated based on the physical quantities of each product. The joint costs are distributed in proportion to the weight or volume of the products.
In this case, the joint costs incurred in the slaughtering process are allocated to the products: Fresh Meat, Biltong, Hides, and Horns.
=To allocate the joint costs using the physical unit method:
Calculate the total weight of each product:
Fresh Meat: 100 kg per animal x 250 animals = 25,000 kg
Biltong: 70 kg per animal x 250 animals = 17,500 kg
Hides: 40 kg per animal x 250 animals = 10,000 kg
Horns: 10 kg per animal x 250 animals = 2,500 kg (pairs of horns are considered as separate units)
Calculate the total weight of all products:
Total weight = Fresh Meat + Biltong + Hides + Horns
Total weight = 25,000 kg + 17,500 kg + 10,000 kg + 2,500 kg = 55,000 kg
Calculate the cost per kilogram of joint costs:
Joint costs = Variable costs + Fixed costs
Joint costs = (N$1.00 per kg x 55,000 kg) + N$108,000
Joint costs = N$55,000 + N$108,000 = N$163,000
Allocate the joint costs to each product:
Fresh Meat: (Fresh Meat weight / Total weight) x Joint costs
Biltong: (Biltong weight / Total weight) x Joint costs
Hides: (Hides weight / Total weight) x Joint costs
Horns: (Horns weight / Total weight) x Joint costs
The allocated joint costs for each product can be calculated accordingly.
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A chef needed to put 36 plates away in the kitchen. She put the plates in stacks of 3. How many stacks did the chef make?
Answer:12
Step-by-step explanation:
dive 36 plates by by the amount of plates per stack (3)
Suppose f is a decreasing function and g is an increasing function from [0, 1] to [0,1]. Which of the following statement(s) must be true? (i) If in integrable. (ii) fg is integrable. (iii) fog is integrabel
Since f is decreasing and g is increasing, we can say that fog is decreasing on [0, 1]. Hence, fog is bounded on [0, 1] and is integrable on [0, 1]. Therefore, statement (iii) must be true. The correct option is (i) and (iii).
Given that f is a decreasing function and g is an increasing function from [0, 1] to [0, 1].
We need to find which of the following statement(s) must be true.
(i) If f is integrable.
(ii) fg is integrable.
(iii) fog is integrable.
(i) If f is integrable.If f is integrable on [0, 1], then we can say that f is bounded on [0, 1].
Also, since f is decreasing,
f(0) ≤ f(x) ≤ f(1) for all x ∈ [0, 1].
Hence, f is integrable on [0, 1].
Therefore, statement (i) must be true.(ii) fg is integrable.
Since f and g are both bounded on [0, 1], we can say that fg is also bounded.
Since f is decreasing and g is increasing, fg is neither increasing nor decreasing on [0, 1].
Therefore, we can not comment on its integrability.
Hence, statement
(ii) is not necessarily true.
(iii) fog is integrable.
Since f is decreasing and g is increasing, we can say that fog is decreasing on [0, 1].
Hence, fog is bounded on [0, 1] and is integrable on [0, 1].
Therefore, statement (iii) must be true.
The correct option is (i) and (iii).
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Use the properties of operations to write an expression equivalent to 4x + 1/2 + 2x - 3
Hey there!
4x + 1/2 + 2x - 3
COMBINE the LIKE TERMS
= (4x + 2x) + (1/2 - 3)
TRYING to SIMPLIFY THEM
4x + 2x
= 6x
1/2 - 3
= -5/2
ANSWER
6x + (-5/2)
Therefore, your answer should be: 6x + -5/2
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
Provide an appropriate response Suppose a uniform random ca be used to the outcome of an experiment with the outcomes ranging from 30 to 80?what is probability that this experiment results in an outcome less then 40?
The probability that the experiment results in an outcome less than 40 is 0.25.
To calculate the probability, we need to determine the range of outcomes that are less than 40 out of the total range of 30 to 80. The total range is 80 - 30 = 50. The range of outcomes less than 40 is 40 - 30 = 10.
To find the probability, we divide the range of outcomes less than 40 by the total range:
Probability = (Range of outcomes less than 40) / (Total range)
= 10 / 50
= 0.2
Therefore, the probability that the experiment results in an outcome less than 40 is 0.2 or **20%**.
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G(Q) = 5 + 3Q + 202 - Q2 C2(Q) = 3 + 4Q + 2 1. Find the MC function for both C1(Q) AND C2(Q). 2. Find AVC function for both Ci(Q) AND C2(Q). 3. Find AFC function for both C1(Q) AND C2(Q). 4. Find AC function for both Ci(Q) AND C2(Q). 5. Find ATC function for both Ci(Q) AND C2(Q).
For C1(Q) = 3 - 2Q.
For C2(Q) = 4.
2. The AVC function
For C1(Q) = 5/Q + 3 + 20/Q - Q.
For C2(Q) = 3/Q + 4 + 2/Q.
3. The AFC function
For C1(Q)= 5/Q - 20/(5 + 3Q + 20/Q - Q)
For C2(Q) = 0.
4. To find the AC function
For C1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).
For C2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.
5.To find the ATC function
For C1(Q)= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²)
For C2(Q)= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.
Find the ATC functions for C1(Q) and C2(Q) given the provided cost functions?
1. To find the MC function, we take the derivative of the cost functions with respect to Q.
For C1(Q) = 5 + 3Q + 202 - Q^2, MC1(Q) = 3 - 2Q.
For C2(Q) = 3 + 4Q + 2, MC2(Q) = 4.
2. To find the AVC function, we divide the cost functions by Q.
For C1(Q), AVC1(Q) = (5 + 3Q + 202 - Q^2)/Q = 5/Q + 3 + 20/Q - Q.
For C2(Q), AVC2(Q) = (3 + 4Q + 2)/Q = 3/Q + 4 + 2/Q.
3. To find the AFC function, we subtract the AVC function from the ATC function.
For C1(Q), AFC1(Q) = (5 + 3Q + 202 - Q^2)/Q - (5 + 3Q + 202 - Q^2)/(5 + 3Q + 20/Q - Q)
= 5/Q - 20/(5 + 3Q + 20/Q - Q).
For
C2(Q), AFC2(Q) = (3 + 4Q + 2)/Q - (3 + 4Q + 2)/(3/Q + 4 + 2/Q) = 0.
4. To find the AC function, we add the AVC function to the AFC function.
For
C1(Q), AC1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).
For
C2(Q), AC2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.
5. To find the ATC function, we divide the AC function by Q.
For
C1(Q), ATC1(Q) = [(5 + 3Q + 202 - Q²)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q)]/Q
= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²).
For
C2(Q), ATC2(Q) = [(3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q]/Q
= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.
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A road is 5.5 kilometers long.
How many centimeters long is it?
Solve the following inequality for s. Write your answer in simplest form.
7s - 9 < 6s – 10
Answer:
2<-1
Step-by-step explanation:
7s-9<6s-10
-6s. -6s.
S-9<-10
+9. +9
S<-1
Movie tickets are $4.00 for children and $8.00 for adults. The total amount of ticket sales in one night was $1,176. There was 172 tickets sold.
Define the variables used in this example.
Your answer:
m= money
t=tickets
c=children
a= adults
t= tickets
c=children
Answer:
122 tickets were sold for adults and the rest is for children.
Step-by-step explanation:
HELP NOWhhhhhhhhhhhhhhhhhhhhhhh
Answer:
r = 1/5
Step-by-step explanation:
Substitute x=15 and y=3 into the equation given.
Transpose so that r = 3/15
Simply 3/15
r = 1/5
Answer:
4.4/22 = .2
r=.2
Step-by-step explanation:
Two turns contain vhite balls and yellow balls. The first urn contains 7 white balls and 10 yellowballs and the second turn contains 8 white balls and 2 yellow balls. A ball is drawn at randomfrom each turn. What is the probability that both balls are white?
Answer:
28/85
Explanation:
First Urn
Total number of balls = 7+10 =17
Number of white balls =7
P(White) = 7/17
SecondUrn
Total number of balls = 8+2=10
Number of white balls =8
P(White) = 8/10
Therefore, if a ball is drawn at random from each urn, the probability that both balls are white will be:
\(\begin{gathered} =\frac{7}{17}\times\frac{8}{10} \\ =\frac{56}{170} \\ =\frac{28}{85} \end{gathered}\)Rachael has plotted 10 points on a scatter plot to investigate the relationship between two quantitative variables. She wants to use a line to model the relationship. What is the minimum number of points that the line has to pass through for it to be a good model?
A 0
B1
C 5
D 10
The minimum number of points that the line has to pass through for it to be a good model is 2.
- A line can be used to model the relationship between two quantitative variables on a scatter plot.
- The line should pass through at least two points to be a good model.
- If the line passes through only one point, it may not represent the overall trend or pattern of the data.
- If the line passes through more than two points, it may be overfitting the data and not accurately represent the relationship between the variables.
A scatter plot is a visual representation of the relationship between two quantitative variables. It consists of a set of points that are plotted on a two-dimensional plane. The position of each point is determined by the values of the two variables being studied.
To model the relationship between the variables, a line can be drawn on the scatter plot. The line should pass through as many points as possible to accurately represent the trend or pattern of the data. However, the line should not pass through too many points as it may overfit the data and not accurately represent the relationship between the variables.
In the given scenario, Rachael has plotted 10 points on a scatter plot to investigate the relationship between two quantitative variables. She wants to use a line to model the relationship. The minimum number of points that the line has to pass through for it to be a good model is 2. This is because a line that passes through only one point may not represent the overall trend or pattern of the data, while a line that passes through more than two points may be overfitting the data and not accurately represent the relationship between the variables.
Therefore, to create a good model for the relationship between the two quantitative variables, the line should pass through at least two points on the scatter plot.
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Q3. Find x and y
12
X
30
60
y
Answer:
THX FOR POINTS
Step-by-step explanation:
Answer:
x = 4\(\sqrt{3}\), y = 8\(\sqrt{3}\)
Step-by-step explanation:
Using the tangent ratio in the right triangle and the exact value
tan30° = \(\frac{\sqrt{3} }{3}\) , then
tan30° = \(\frac{opposite}{adjacent}\) = \(\frac{x}{12}\) = \(\frac{\sqrt{3} }{3}\) ( cross- multiply )
3x = 12\(\sqrt{3}\) ( divide both sides by 3 )
x = 4\(\sqrt{3}\)
------------------------------------------------------------
Using Pythagoras' identity in the right triangle
y² = x² + 12² = (4\(\sqrt{3}\) )² + 144 = 48 + 144 = 192 ( take square root of both sides )
y = \(\sqrt{192}\) = \(\sqrt{64(3)}\) = 8\(\sqrt{3}\)
Twice the quantity of 8 more than a number
PLEASE HELP ME LIKE HURRRRRRY PLEASE ILL GIVE U A 100 BRAINLIEST
Answer:
x<16
Step-by-step explanation:
let x be the number
2x8>x
16>x
a football coach is trying to decide: when a team is ahead late in the game, which strategy is better?
• play the "regular" defense.
• play a "prevent" defense that guards against long gains but makes short gains easier
the coach reviews the outcomes of 100 games
compare the probability of winning when playing regular defense with the probability of winning when playing prevent defense. draw a conclusion
based on your results.
From analysis, it is seen that the probability of winning when playing regular defense is higher than the probability of winning with *prevent* defence.
How to find the probability of Winning?We will assume that a total of 100 games were reviewed.
50 games used regular defense method.
The remaining 50 games used the prevent defense method.
Out of the 50 regular defense games, 38 were win while 12 games were lose.
Out of 50 prevent defense game, 29 were win, while 21 games were lose.
Thus, the Probability of winning by regular defense is:
P(win | regular) = 38/50
P(win | regular) = 0.76
Probability of winning by playing prevent defense is:
P(win | prevent) = 29/50 = 0.58
From the above analysis we observe that the probability of winning by using the regular defense method is greater than the probability of winning by prevent defense method.
That is 0.76 > 0.58.
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