Select Statistical or Not statistical to classify each question. Question How much does a movie ticket cost at each theater in New York City? How many movie theaters are in New York City? What movie theater in town has the least expensive popcorn? Statistical Not statistical​

A function that gives the length of the hypotenuse of an isosceles right triangle with side length s is given by h(s)=s√2 and the length of the side of the triangle is approximately 4.24 inches.

The hypotenuse of a right angled triangle is defined as the longest side of the triangle. The hypotenuse is also located opposite the right angle.

From the Pythagorean Theorem we know that for a right angled triangle, the sum of the square of the legs of the triangle is equal to the square of the hypotenuse.

Given legs of the right triangle is s. Let us consider a function h(s) for the hypotenuse.

Therefore we can define the function h(s) as

h(s)=s√2

The inverse of the function can be written as

y=s√2

or, s=y²/2

Hence the inverse function is:

h⁻¹(s)=s²/2

Now for hypotenuse = 6 inches.

Each side can be calculated using the inverse function h⁻¹(s)=s²/2.

s=6÷√2

or, s=4.242...

Hence the length of the side of the triangle is approximately 4.24 inches.

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The disjunction of -p or -q can be written as (-p) v (-q). So, we have to find the truth value of (-p) v (-q). So, the compound statement for the disjunction of -p or -q is (-p) v (-q), and its truth value is true.

using the following statements: p: There are 14 inches in 1 foot.

q: There are 3 feet in 1 yard.

Solution: We know that 1 foot = 12 inches, which means that there are 14 inches in 1 foot can be written as 14 < 12. But this statement is false because 14 is not less than 12. Therefore, the negation of this statement is true, which gives us (-p) as true.

Now, we know that 1 yard = 3 feet, which means that there are 3 feet in 1 yard can be written as 3 > 1. This statement is true because 3 is greater than 1. Therefore, the negation of this statement is false, which gives us (-q) as false.

Now, we can use the values of (-p) and (-q) to find the truth value of (-p) v (-q) using the disjunction rule. The truth value of (-p) v (-q) is true if either (-p) or (-q) is true or both (-p) and (-q) are true. Since (-p) is true and (-q) is false, the disjunction of (-p) v (-q) is true. Hence, the compound statement for the disjunction of -p or -q is (-p) v (-q), and its truth value is true.

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Answer: I’m going to do the first problem with a fully detailed explanation and just answer the other ones! :)

Factoring: v^2-4v-60

The middle number is -4 and the last number is -60.

Factoring means we want something like

(v+_)(v+_)

Which numbers go in the blanks?

We need two numbers that...

Add together to get -4

Multiply together to get -60

Can you think of the two numbers?

Try 6 and -10:

6+-10 = -4

6*-10 = -60

Fill in the blanks in

(v+_)(v+_)

with 6 and -10 to get...

(v+6)(v-10)

Second Problem: (x-4)(x-9)

Third Problem: 6(x+5)(x+8)

Fourth Problem: (k+5)(k+10)

Fifth Problem: (a-4)(a-4)

The z score that separate the middle 56% of the distribution from the area in the tails of the standard normal distribution is ±0.77.

Given that the z score separates the 56% of the distribution from the area in the tails of the standard normal distribution.

In a normal distribution in with mean μ and standard deviation σ, the z score of a measure X is as under:

Z=(X-μ)/σ

It is used to measure how many standard deviations the measure is from the mean.

After finding the z score we have to look at the z score table and find the p value associated with this z score, which is the percentile of X.

The normal distribution is symmetric which means that the middle 56% is between the 11th and 67th percentile. Looking at the z table the z scores are Z=±0.77.

Hence the z score that separate the middle 56% of the distribution from the area in the tails of the standard normal distribution is ±0.77.

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Answer:

va cyclist covers a distance of 15km in 2hours calculate his speeda cyclist covers a distance of 15km in 2hours calculate his speeda cyclist covers a distance of 15km in 2hours calculate his speeda cyclist covers a distance of 15km in 2hours calculate his speeda cyclist covers a distance of 15km in 2hours calculate his speed

Answer:

Step-by-step explanation:

Given figure : Trapezoid

Base sides,

a = 11 cm

b = 11 - 3 = 8 cm

height ( h ) = 4 cm

Now, finding the area:

\( \frac{1}{2} (a + b) \: h\)

plug the values

\( \frac{1}{2} \times (11 + 8) \times 4\)

Calculate the sum

\( \frac{1}{2} \times 19 \times 4\)

Reduce the numbers with G.C.F 2

\(19 \times 2\)

Calculate the product

\(38 \: {cm}^{2} \)

Hope this helps...

Best regards!

Answer:

Step-by-step explanation:

so we are told that he deposited 7/9 of  his money.  that mean the remaining is  2/9.   because 9/9 - 7/9 = 2/9   get it?

we are also told that 2.50 = 2/9 of his pay

so use that info to find the total pay

also using my calculator tells me that 2/9 = 0.22222222222222222222

knowing that,  we can divide 2.50 by 0.222222222222

2.50 / 0.2222222222  = 11.25

we now know that  2.50 is 0.222 of  11.25

if you want to check your answer just multiply 11.25 x .222222222  to see if you get 2.50

Do you understand?

Answer:

m∠RST = 20

Step-by-step explanation:

Sine the line SP bisects ∠RST, we know that the two angles that were formed are equal.  Set ∠RSP equal to ∠PST.

∠RSP = ∠PST

3x - 2 = 9x - 26

(3x - 2) + 2 = (9x - 26) + 2

3x = 9x - 24

3x - 9x = (9x - 24) - 9x

-6x = -24

(-6x)/-6 = -24/-6

x = 4

Now that you know the value of x, add ∠RSP and ∠PST.  This will give you m∠RST.

m∠RST = (3x - 2) + (9x - 26)

m∠RST = 3x - 2 + 9x - 26

m∠RST = 12x - 2 - 26

m∠RST = 12x - 28

m∠RST = 12(4) - 28

m∠RST = 48 - 28

m∠RST = 20

The point that divides the line segment between 1 and 9 into a ratio of 3:5 is at x = 4.

To find the point that divides the line segment between 1 and 9 into a ratio of 3:5, we need to use the concept of proportionality.

Let's denote the unknown point as "x".

First, we can find the total distance between 1 and 9, which is 9-1 = 8.

Next, we can set up the proportion:
3/5 = distance from 1 to x / distance from x to 9

We know the total distance is 8, so we can set up an equation:
3/5 = (x-1) / (9-x)

To solve for x, we can cross-multiply:

3(9-x) = 5(x-1)
27 - 3x = 5x - 5
8x = 32
x = 4

Therefore, the point that divides the line segment between 1 and 9 into a ratio of 3:5 is at x = 4.

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The functions that are valid solutions to the 1D wave equation are a) D(x,t) = A ln(x+vt) and c) D(x,t) = A sin(kx-ωt).

To verify if each function is a valid solution to the 1D wave equation, we need to substitute the functions into the wave equation and see if they satisfy the equation.

∂²D/∂t² = v²∂²D/∂x²

a) D(x,t) = A ln(x+vt)

Taking the first and second partial derivatives:

∂D/∂t = Av/(x+vt)

∂²D/∂t² = -A(v/(x+vt))²

∂D/∂x = A/(x+vt)

∂²D/∂x² = -A/(x+vt)²

Substituting these derivatives back into the wave equation:

-A(v/(x+vt))² = v²(-A/(x+vt)²)

The equation holds so D(x,t) = A ln(x+vt) is a valid solution to the 1D wave equation.

b) D(x,t) = A(x-vt)⁴

Taking the first and second partial derivatives:

∂D/∂t = -4Avt³

∂²D/∂t² = -12Avt²

∂D/∂x = A(1-vt)⁴

∂²D/∂x² = 0

Substituting these derivatives back into the wave equation:

-12Avt² = v² * 0

Since the equation does not hold, D(x,t) = A(x-vt)⁴ is not a valid solution to the 1D wave equation.

c) D(x,t) = A sin(kx-ωt)

Taking the first and second partial derivatives:

∂D/∂t = -Aω cos(kx-ωt)

∂²D/∂t² = Aω² sin(kx-ωt)

∂D/∂x = Ak cos(kx-ωt)

∂²D/∂x² = -Ak² sin(kx-ωt)

Substituting these derivatives back into the wave equation:

Aω² sin(kx-ωt) = v²(-Ak² sin(kx-ωt))

The equation holds so D(x,t) = A sin(kx-ωt) is a valid solution to the 1D wave equation.

So, the functions that are valid solutions to the 1D wave equation are:

a) D(x,t) = A ln(x+vt)

c) D(x,t) = A sin(kx-ωt)

Function b) D(x,t) = A(x-vt)⁴ is not a valid solution to the 1D wave equation.

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Answer:

$19.25

Step-by-step explanation:

12 bracelets at $1.25 each + $4.25 shipping.

Total = 12 * $1.25 + $4.25 = $15.00 + $4.25 = $19.25

Answer: $19.25

Answer:

19.25

Step-by-step explanation:

First you want to multiply $1.25 times 12

$15

Next add $4.25 to $15

$19.25 is your answer

The value of F'(0) = 42

Consider:

y = f(g(x))

Then by the chain rule the derivative is:

f'(g(x)) . g'(x) .Thus the derivative of y = f(g(h(x)))  will be derived as being:

f'(g(h(x))) is derivative of g(h(x))

f'(g(h(x))) . g'(h(x)). h'(x)

If we return our attention to the problem at hand, we get:

F'(x) =  f'(7f(6f(x))) .7f'(6f(x)). 6f'(x)

F'(0) =   f'(7f(6f(0))) .7f'(6f(0)). 6f'(0)

Substituting our knowns:

F'(0) = f' (7f(0)). 7f'(0) . 6(1)

F'(0) = f'(0). 7(1) .6

F'(0) = 1 . 7 . 6

F'(0) = 42.

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Answer:

<4

Step-by-step explanation:

The velocity of the object 2 seconds later is 40/9 m/s.

The acceleration of an object moving along a coordinate line is given by

a(t)=(3t+3) −2 in meters per second per second.

If the velocity at t=0 is 4 meters per second, find the velocity 2 seconds later.

v= meters per second.

To find the velocity of an object 2 seconds later, we need to integrate the acceleration with respect to time.

The integration of the acceleration of the object with respect to time will give us the velocity of the object over time.

First, we will integrate the acceleration and then solve for the constant using the initial velocity.

The formula to find velocity of an object is:

v(t) = -∫a(t) dt + c

Where c is a constant of integration that we need to solve by applying the initial condition.

Here, the initial condition is given as the velocity at t=0 is 4 m/s.

We know that the integral of a(t) will be:

v(t) = -∫a(t) dt + c = -∫[(3t + 3)^(-2)] dt + c

To find v(t), we need to integrate a(t) with respect to t.

v(t) = -∫a(t) dt + c= -∫[(3t + 3)^(-2)] dt + c

Let's apply integration by substitution;

u = 3t + 3 → du = 3dt

Then, the integral will be:

v(t) = -∫[(3t + 3)^(-2)] dt + c= -∫u^(-2) * (du/3) + c= (u^(-1))/(-1) + c= -1/(3t + 3) + c

To find c, we will apply the initial condition, which is the velocity at t = 0 is 4 m/s;

v(0) = -1/(3(0) + 3) + c = 4;

Therefore, c = 4 + 1/3 = 13/3

Thus, the velocity of the object 2 seconds later will be: v(2) = -1/(3(2) + 3) + 13/3= -1/9 + 13/3= 40/9 m/s

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Answer:

22

Step-by-step explanation:

If x = 5, then plug 5 in for x .

3(5) + 7

15 + 7 = 22

Answer:

22

Step-by-step explanation: 3x + 7

3*5 = 15

15+7=22

Answer:

Do it

Step-by-step explanation:

Answer:

um srry i dont know hope you have a good day get a good grade and stay safe

Step-by-step explanation:

Answer:

-2

Step-by-step explanation:

\(\frac{-7-5}{3-(-3)}= \frac{-7+-5}{3+3} =\frac{-12}{6} =-2\)

Answer:

12/-6 or -2

Step-by-step explanation:

-3-3= -6 (run)

5-(-7)= 12(rise)          

        12/-6 rise over run

Therefore, the angle between the biker's line of sight and the trail is changing at a rate of approximately 0.039 radians per second when she is 25 feet away from the tree.

To solve this problem, we need to use trigonometry and calculus. Let's call the angle between the biker's line of sight and the trail θ, and let's call the distance from the traffic cone to the aspen tree x. Then we can use the tangent function to relate θ and x:

tan(θ) = x/15

We can also use the Pythagorean theorem to relate x and the distance d between the biker and the tree:

d^2 = x^2 + 25^2

Taking the derivative of both sides with respect to time t, we get:

2d (dd/dt) = 2x (dx/dt)

Now we can substitute the equation for x in terms of θ and solve for (dθ/dt):

tan(θ) = x/15

sec^2(θ) (dθ/dt) = (1/15) (dx/dt)

(dθ/dt) = (1/15) (dx/dt) sec^2(θ)

We can use the equation for d to solve for x:

x^2 = d^2 - 25^2

2x (dx/dt) = 2d (dd/dt)

(dx/dt) = (d/dd) (sqrt(d^2 - 25^2)) (dd/dt)

(dx/dt) = (d/ sqrt(d^2 - 25^2)) (dd/dt)

Now we can substitute this expression for (dx/dt) into the previous equation and evaluate it when d = 25 and θ = arctan(15/25):

(dθ/dt) = (1/15) [(d/ sqrt(d^2 - 25^2)) (dd/dt)] sec^2(arctan(15/25))

(dθ/dt) = (1/15) [(25/ sqrt(25^2 - 25^2)) (13)] sec^2(arctan(15/25))

(dθ/dt) = (13/375) sec^2(arctan(15/25))

(dθ/dt) ≈ 0.039 radians per second

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2 hours will pass before they meet.

"Information available from the question"

In the question:

Aaron starts riding a bike at a rate of 3 mi/h on a road toward a store 20 mi away.

Zhang leaves the store when Aaron starts riding his bike, and he rides his bike toward Aaron along the same road at 2 mi/h.

Now, According to the question:

Total distance = 20mi

Aaron starts riding a bike at a rate of  = 3mi/h

Zhang rides his bike toward Aaron along the same road at  = 2mi/h

Let y be the number of hours for them to meet.

The expression is given as

3y + 2y = 20

solving for y, we have

5y = 20

y = 20/5

y = 4hrs

Therefore, 2 hours will pass before they meet.

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Answer:

d

Step-by-step explanation:

because think about it for a little bite when it says four times the difference that means it 4(n-16).

The value of the expression z + 3x4 using arithmetic operation where z = 15, is 27. The answer is A) 27.

The given expression is z + 3x4, where z = 15. To evaluate this expression, we substitute 15 for z and perform the multiplication. First, we multiply 3 and 4, which gives us 12. Then, we add 15 and 12 to get the final result of 27.

z + 3x4 = 15 + 3x4

= 15 + 12

= 27

Therefore, the value of the expression when z = 15, is 27. In other words, using arithmetic operation of multiplication and addition, which gives us the final answer of 27. So, the correct answer is option A).

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____The given question is incomplete , the complete question is given below:

Evaluate the expression, where z = 15

z + 3x4

A. 27

B. 32

C. 56

D. 1,304

i. weekly receipts at a clothing boutique

ii. monthly demand for an automotive part

Time series data refers to information collected and recorded at regular intervals over a specific period. In the case of i. weekly receipts at a clothing boutique and ii. monthly demand for an automotive part, both data sets are examples of time series data.

Time series data consists of observations recorded over regular intervals, allowing for the analysis of patterns and trends over time. In i. weekly receipts at a clothing boutique, the data is collected on a weekly basis, providing insights into the boutique's revenue fluctuations over different weeks. Similarly, ii. monthly demand for an automotive part captures the demand for the part on a monthly basis, enabling analysis of monthly variations and seasonal patterns.

On the other hand, iii. quarterly sales of automobiles do not fall under time series data. While it represents sales data, the intervals between measurements are not consistent enough to qualify as time series. Quarterly intervals are less frequent and may not capture shorter-term trends or variations as effectively as weekly or monthly intervals.

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Answer:

See below

Step-by-step explanation:

\(1\cdot24=2\cdot12=3\cdot8=4\cdot6=24\)

Answer:

1. 24

2. 12

3. 8

4. 6

Step-by-step explanation:

2 x 12 = 24, 3 x 8 = 24, 4 x 6 = 24

Based on the information, we can infer that if Tamara does the survey in a group of 10 people, 2 people would prefer McDonalds over Taco Bell.

To calculate the number of people who would choose McDonalds over Taco Bell if applied to the survey of 10 people, we must carry out the following mathematical procedure:

1. We must add the total number of people surveyed and make a rule of 3 to find the percentage equivalent to the people who chose Taco Bell and Mc Donalds.

Now we must perform another rule of three to find the equivalent in a group of ten people.

So it would be 2 more people who prefer Mc Donalds over Taco Bell.

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Answer:

the second

Step-by-step explanation:

refers to well-founded standards of right and wrong that prescribe what humans should do, usually in terms of rights, obligations, benefits to society, justice

Answer:

6q

Step-by-step explanation:

Answer:

i think it is 6q

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

When give two points, we can use the slope formula

m = ( y2-y1)/(x2-x1)

    = ( 4- -2)/(4-1)

    = ( 4+2)/(4-1)

    = 6/3

     = 2

Answer:

2

Step-by-step explanation:

When give two points, we can use the slope formula

m = ( y2-y1)/(x2-x1)

    = ( 4- -2)/(4-1)

    = ( 4+2)/(4-1)

    = 6/3

     = 2

Answer:

2

Step-by-step explanation:

f(-6) = -2(-6) - 10

f(-6) = 12 - 10

f(-6) = 2

Explanation: The process used to solve this problem is the Euclidean algorithm, which involves finding the greatest common divisor (gcd) of two numbers by performing a sequence of division and remainder operations. In this case, gcd(82, 26) is found by dividing 82 by 26 to get a quotient of 3 and a remainder of 4, then dividing 26 by 4 to get a quotient of 6 and a remainder of 2, and finally dividing 4 by 2 to get a quotient of 2 and a remainder of 0.

Once the gcd is found, the algorithm is reversed to express it as a linear combination of the two original numbers. This is done by substituting each remainder in the sequence back into the preceding division equation and solving for it in terms of the other numbers. For example, 4 = 82 - 3 . 26 means that 4 can be expressed as a combination of 82 and 26 with coefficients of -3 and 1, respectively. Similarly, 2 = 26 - 6 . 4 means that 2 can be expressed as a combination of 82 and 26 with coefficients of 6 and -19, respectively.

To complete the linear combination, we substitute the expression for 4 into the expression for 2 and simplify:

2 = 26 - 6 . (82 - 3 . 26) = 26 - 6 . 82 + 18 . 26
2 = -474 . 82 + 194 . 26

Therefore, the missing coefficients in the linear combination are -474 for 82 and 194 for 26.

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The teacher sets up 7 workstations in each classroom

Let x represent the number of workstations in each classroom.

Since an art teacher has a total of 7/8 pound of clay. The teacher puts 1/16 pound of clay at each work station . The teacher sets up an equal number of work stations in each of 2 classrooms.

Since the teacher puts 1/16 pound of clay at each work station, there are x × 1/16 pounds in each class.

So, the number of pounds ineach class is x/16.

Since there are 2 classrooms, the number of pounds of clay in both classrooms is 2x/16.

Since the total pounds of clay is 7/8, we have that

2x/16 = 7/8

So, solving for x, we have that

x = 7/8 × 16/2

x = 7/8 × 8

x = 7

So, the teacher sets up 7 workstations in each classroom

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