Select the correct answer. in hooke’s law, what does the x represent? a. the thickness of the spring b. the length of the spring c. the displacement of the spring d. the distance from stretched to compressed e. the equilibrium distance
Answers
The length of extension or compression is represented by the symbol x in Hooke's law.
What is Hooke's Law?While studying springs and elasticity, scientist Robert Hooke found that many materials' stress vs. strain graphs had a linear zone.
The force required to extend a metal spring is, up to a point, perfectly proportional to the spring's extension because metal is an elastic material. This is known as Hooke's law, and it is usually expressed as follows: F= -kx
Where FFF is the force, xxx is the length of extension or compression, and kkk is the spring constant, which is typically expressed in text units of N/m.
The negative sign is typically supplied even though the force's direction hasn't been determined explicitly in this case. This is done to show that the spring's restoring force is directed in the opposite direction from the force that created the displacement.
When you pull down on a spring, it will extend downward, which will produce an upward force because of the spring.
When handling mechanics problems requiring elasticity, it is crucial to make sure that the direction of the restoring force is given consistently.
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Related Questions
The balistic pendulum is an apparatus used to measure the speed of a fast-moving projectile, such as a bullet A bullet of mass my is fired into a large block of wood ot mass m^2 surpended from some light wires. The bullet embeds in the block and the entire system swings through a height, h. How can we determine the speed of the bullet from a measurement of h? Your answer should be an expression confaining just the variables m, m. h and any constants relevant to the situation
Answers
This equation relates the speed of the bullet (v) to the masses of the bullet (m) and the wood block (m₂), as well as the height (h) through which the system swings.
To determine the speed of the bullet (v), we can use the principle of conservation of mechanical energy in the system.
Initially, the system has only gravitational potential energy, which is converted into a combination of gravitational potential energy and kinetic energy after the collision. Assuming no energy is lost to other factors like friction or air resistance, we can equate the initial and final energies.
The initial energy is purely potential energy: m₂gh, where m₂ is the mass of the wood block, g is the acceleration due to gravity, and h is the height the system swings through.
The final energy is a combination of potential and kinetic energy: (m + m₂)gh + (1/2)(m + m₂)v², where m is the mass of the bullet and v is its velocity.
Equating the initial and final energies, we can solve for v:
m₂gh = (m + m₂)gh + (1/2)(m + m₂)v².
Simplifying the equation, we find:
v² = 2gh(m₂ - m) / (m + m₂).
Taking the square root of both sides, we get the expression for the speed of the bullet:
v = √[2gh(m₂ - m) / (m + m₂)].
This equation relates the speed of the bullet (v) to the masses of the bullet (m) and the wood block (m₂), as well as the height (h) through which the system swings.
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Which compound is an acid?
a. hydrogen sulfide.
b. water.
c. sodium hydroxide.
d. cannot be determined
Answers
Answer:
a. hydrogen sulfide.
Answer : A
The standard metric unit of volume is the _____.
cubic centimeter
liter
milliliter
cubic meter
Answers
Answer:
. The SI unit of volume is the cubic meter (m3), which is a derived unit.
Liter (L) is a special name for the cubic decimeter (dm3).
A sportscar has a mass of 1500 kg and accelerates at 5 meters per second squared. What is the magnitude of the force acting on the sportscar?
Answers
Answer:
7500 Newtons
Explanation:
Mass of the sportscar= 1500 kg
Acceleration of the sportscar= 5m/s^2
Hence, let the Force acting on it be F
\(We\ know\ that,\\Force=Mass*Acceleration\\F=ma\\\\Here,\\F=1500*5\\=7500 kg m/s^2\ or\ 7500\ Newtons\)
Amplitude of damped oscillations reduces twice during one second. Find the time of its five-fold decrease.
Answers
Use the exponential decrease formula.
\(A=A_0e^{-kt}\)First, find the constant k. The final amplitude would be half, and t = 1.
\(\begin{gathered} \frac{A}{2}=A\cdot e^{-k\cdot1} \\ \frac{1}{2}=e^{-k} \\ \ln (\frac{1}{2})=-k \\ k=-\ln (\frac{1}{2})\approx0.693 \end{gathered}\)Then, we find the time of its five-fold decrease, which means the final amplitude is a fifth part of the initial amplitude.
\(\begin{gathered} \frac{A}{5}=A\cdot e^{-0.693\cdot t} \\ \frac{1}{5}=e^{-0.693\cdot t} \\ \ln (\frac{1}{5})=-0.693t \\ t=\frac{\ln (\frac{1}{5})}{-0.693} \\ t\approx2.32\sec \end{gathered}\)Therefore, the time of its five-fold decrease is 2.32 seconds.
An ice cube can slide around the inside of a vertical circular hoop of radius R. It undergoes small-amplitude oscillations if displaced slightly from the equilibrium position at the lowest point. Find an expression for the period of these small-amplitude oscillations.
Answers
The period of small-amplitude oscillations for an ice cube sliding inside a vertical circular hoop of radius R is given by the expression T = 2π * sqrt(R/g).
To find the period of small-amplitude oscillations of an ice cube sliding inside a vertical circular hoop of radius R, we can use the concept of simple harmonic motion (SHM).
First, let's consider the forces acting on the ice cube. The only force acting on it is the weight mg, directed downwards. At the equilibrium position (lowest point), the weight force is balanced by the normal force N from the hoop.
Next, let's analyze the motion of the ice cube when it is displaced slightly from the equilibrium position. Due to this displacement, a net force arises and acts as a restoring force that tries to bring the cube back to its equilibrium position.
We can consider the restoring force as the component of weight force along the radial direction. This force can be calculated as F = mg * sinθ, where θ is the angle of displacement from the equilibrium position.
Now, we can apply Newton's second law of motion to find the angular acceleration α of the ice cube. The net force acting on the cube is given by F = m * R * α. Equating the restoring force and the net force, we have:
mg * sinθ = m * R * α
Simplifying the equation, we get:
α = (g/R) * sinθ
We know that for SHM, the angular acceleration α is proportional to the angular displacement θ. Therefore, we can write:
α = -ω^2 * θ
where ω is the angular frequency.
Equating the two expressions for α, we get:
ω^2 * θ = (g/R) * sinθ
Simplifying, we have:
ω^2 = g/R
Taking the square root of both sides, we get:
ω = sqrt(g/R)
Finally, we can find the period T of the small-amplitude oscillations using the relation T = 2π/ω.
Therefore, the expression for the period of small-amplitude oscillations is:
T = 2π * sqrt(R/g)
In conclusion, the period of small-amplitude oscillations for an ice cube sliding inside a vertical circular hoop of radius R is given by the expression T = 2π * sqrt(R/g).
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if you are on top of mount Everest and do a small hop without moving forward, would you still be pulled down by gravity? explain it and also answer my other newest question.
Answers
Explanation:
Gravity would still pull you down although it wouldn't affect you as much because there is less gravitational pull in high places such as Mt. Everest.
A 3.91 kg cart is moving at 5.7 m/s when it collides with a 4 kg cart which was at rest. They collide and stick together.
What is the velocity after the collision?
m/s
Answers
Answer:
The velocity after the collision is 2.82 m/s
Explanation:
Law Of Conservation Of Linear Momentum
It states the total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and speed v is
P=mv.
If we have a system of two bodies, then the total momentum is the sum of the individual momentums:
\(P=m_1v_1+m_2v_2\)
If a collision occurs and the velocities change to v', the final momentum is:
\(P'=m_1v'_1+m_2v'_2\)
Since the total momentum is conserved, then:
P = P'
Or, equivalently:
\(m_1v_1+m_2v_2=m_1v'_1+m_2v'_2\)
If both masses stick together after the collision at a common speed v', then:
\(m_1v_1+m_2v_2=(m_1+m_2)v'\)
The common velocity after this situation is:
\(\displaystyle v'=\frac{m_1v_1+m_2v_2}{m_1+m_2}\)
There is an m1=3.91 kg car moving at v1=5.7 m/s that collides with an m2=4 kg cart that was at rest v2=0.
After the collision, both cars stick together. Let's compute the common speed after that:
\(\displaystyle v'=\frac{3.91*5.7+4*0}{3.91+4}\)
\(\displaystyle v'=\frac{22.287}{7.91}\)
\(\boxed{v' = 2.82\ m/s}\)
The velocity after the collision is 2.82 m/s
Different Betweens in Self Induced emf and Mutual Induced emf ~
Thank uh☃️
Answers
Answer:
brain cells that are in your brain
Explanation:
it has something to do with brain cells
A high-performance sports car can go from 0 to 100 mph (44.7 m/s) in 7.2 s.a. What is the car's average acceleration?b. The same car can come to a complete stop from 34 m/s in about 3.7 s. What is its average acceleration?
Answers
ANSWER
\(\begin{gathered} (a)\text{ }6.21m\/s^2 \\ (b)\text{ -}9.19m\/s^2 \end{gathered}\)EXPLANATION
(a) To find the car's average acceleration, we have to apply the formula for average acceleration:
\(a_{avg}=\frac{\Delta v}{t}\)where Δv = change in velocity
t = time
Therefore, the car's average acceleration is:
\(\begin{gathered} a_{avg}=\frac{44.7-0}{7.2} \\ a_{avg}=\frac{44.7}{7.2} \\ a_{avg}=6.21m\/s^2 \end{gathered}\)(b) The car can go from 34 m/s to 0 m/s in 3.7s.
Therefore, applying the formula for average acceleration, the average acceleration of the car is:
\(\begin{gathered} a_{avg}=\frac{0-34}{3.7} \\ a_{avg}=\frac{-34}{3.7} \\ a_{avg}=-9.19m\/s^2 \end{gathered}\)That is the answer.
What evidence can you see of women and men's changing roles over the past few
generations in the US?|
Answers
a rock attached to a string swings back and forth every 7.7 s. how long is the string? m
Answers
To determine the length of the string, we can use the equation for the period of a pendulum. In this case, the rock attached to the string swings back and forth every 7.7 seconds. the length of the string is approximately 14.69 meters.
The period (T) of a pendulum is the time it takes for one complete oscillation. It is given by the formula:
T = 2π√(L/g)
Where L is the length of the string and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Given,
Period (T) = 7.7 s
Rearranging the formula, we can solve for the length of the string:
L = (T^2 * g) / (4π^2)
Substituting the given values:
L = (7.7 s)^2 * 9.8 m/s² / (4π^2)
Calculating the length of the string:
L ≈ (59.29 s^2 * 9.8 m/s²) / (39.48)
L ≈ (581.142 m²/s²) / (39.48)
L ≈ 14.69 m
Therefore, the length of the string is approximately 14.69 meters.
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100 points at-least 3 sentences pls!
Think about routine tasks that astronauts might need to do inside and outside a spaceship.
Choose several tasks, and describe the features of ship and space suits should have to account for zero gravity as the astronaut completes the task. Use newtons law of motion in your analysis.
Answers
Answer:
BOOM
Explanation:
Astronauts perform many tasks as they orbit Earth. The space station is designed to be a permanent orbiting research facility. Its major purpose is to perform world-class science and research that only a microgravity environment can provide. The station crew spends their day working on science experiments that require their input, as well as monitoring those that are controlled from the ground. They also take part in medical experiments to determine how well their bodies are adjusting to living in microgravity for long periods of time.
Working on the space station also means ensuring the maintenance and health of the orbiting platform. Crew members are constantly checking support systems and cleaning filters, updating computer equipment: doing many of the things homeowners must do to ensure their largest investment stays in good shape. Similarly, the Mission Control Center constantly monitors the space station and sends messages each day through voice or email with new instructions or plans to assist the crew members in their daily routines.
Answer:
I'll be utilizing this section from the end to help me with Newton's law: "The acceleration of an item depends on the mass of the object and the amount of force applied." I believe that duties like as resting, fixing objects outside and within the ship, and just enabling them to stay grounded would benefit greatly from modifications. I believe that extremely powerful suction would be required to keep the astronauts grounded. For ease of access, the portions would be placed on both the feet and the hand.
Explanation:
Consider the following list of properties. Which applies to light?
A: Mechanical wave
B: Electromagnetic wave
C: Travels in circular paths
D: Travels in a straight line (1 point)
OA and C
O A, B, and D
O A, B, and C
O B and D
Answers
The property that applies to light is **B: Electromagnetic wave**. Light is an electromagnetic wave.
**Electromagnetic wave** is a term used to describe the propagation of light energy, which consists of oscillating electric and magnetic fields. This wave does not require a medium to travel through and can travel in a straight line, which addresses option D.
While option C mentions traveling in circular paths, it is not a property of light. Light generally travels in straight lines unless it interacts with certain materials or phenomena that cause it to bend or scatter. Therefore, options OA and C and O A, B, and C are incorrect. Additionally, option A, **Mechanical wave**, does not apply to light as it is not a mechanical disturbance that requires a medium for propagation.
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Ayla hangs a 7.5 kg bowling ball from the ceiling by a rope of negligible mass. The rope will break if the tension in the rope exceeds 115 N. What minimum force must Ayla's dog Rufus exert on the bowling ball to break the rope.
Answers
Answer: >41.5N
Explanation:
Mass of bowling ball = 7.5kg
Breaking point of rope = T > 115N
Where T = Tension on the rope
Since the bowling ball is hung by a rope :
Tension (T) = mg = 7.5 kg × 9.8m/s^2 = 73.5kgm/s^2
T = mg + ma
F = ma
T = mg + F
>115 = 73.5 + F
F = 115 - 73.5
F = 41.5N
Force >41.5N
An equipotential surface that surrounds a point charge, q, has a potential of 490V and an area of 1.1m^2. Determine q
I tried to solve for r using 1.1 = (pi) r^2....but I see that the cramster solution uses A= 4(pi)r^2. Where does 4(pi) come from?
Answers
The value of charge q on an equipotential surface that surrounds a point charge is calculated to be 12.52× 10⁻⁹ C.
The expression to find out electric potential at a distance r is given by,
v = k q /r
where,
v is electric potential
q is charge
r is distance
k is coulomb's constant (9 × 10⁹ Nm²/C²)
Electric potential is given as 490 V.
Area is given as 1.1 m². The expression for area is A = 4 π r².
Making r as subject, we have,
Radius r = √(A/4π) = √(1.1/4π) = √0.087 = 0.23 m
To find out charge, let us make q as subject,
q = v r / k = (490 × 0.23)/(9 × 10⁹) = 12.52× 10⁻⁹ C
Thus, the charge on an equipotential surface that surrounds a point charge is calculated to be 12.52× 10⁻⁹ C.
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$1,000 par value zero-coupon bonds (ignore liquidity premiums) Bond Years to Maturity Yield to Maturity A 1 6.00% B 2 7.50% C 3 7.99% D 4 8.49% E 5 10.70% The expected 1-year interest rate 1 year from now should be about __________.
Answers
The expected 1-year interest rate 1 year from now should be about 9.03%.
To calculate the expected 1-year interest rate 1 year from now, we can use the yield to maturity (YTM) of two bonds with different maturities. In this case, we'll use Bond A (1-year maturity) and Bond B (2-year maturity).
YTM of Bond A = 6.00% or 0.06
YTM of Bond B = 7.50% or 0.075
The formula for the expected 1-year interest rate (r) 1 year from now can be derived from the 2-year bond's YTM:
(1 + YTM of Bond B)^2 = (1 + YTM of Bond A) * (1 + r)
Let's plug in the values and solve for r:
(1 + 0.075)^2 = (1 + 0.06) * (1 + r)
1.155625 = 1.06 * (1 + r)
Now, we can solve for r:
(1 + r) = 1.155625 / 1.06
(1 + r) = 1.090311
r = 0.090311 or 9.03%
The expected 1-year interest rate is 9.03%.
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Convert 1215 m to km.
Answer:
Answers
Answer:
it is 12.15 km
Explanation:
1215 km ÷1000
=12.15
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A race car accelerates uniformly from 7.5 m/s to 45 m/s over a distance of 90m. Determine the
acceleration of the car.
Answers
The acceleration of the car is 10.94 m/s².
Acceleration:
This is the rate of change of velocity. The S.I unit of acceleration is m/s²
Below is the formula for acceleration.
Formula:v² = u²+2as..................... Equation 1Where:v = final velocityu = initial velocitya = accelerations = distance.Make a the subject of the equation
a = (v²-u²)/2s................... Equation 2From the question,
Given:v = 45 m/su = 7.5 m/ss = 90 mSubstitute these values into equation 2
a = (45²-7.5²)/(2×90)a = (2025-56.25)/180a = 10.94 m/s²Hence, The acceleration of the car is 10.94 m/s²
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I NEED HELP PLEASE, THANKS! :)
Holiday lights are often connected in series and use special lamps that short out when the potential difference across a lamp increases to the line voltage. Generate an explanation why and explain why these light sets might blow their fuses after many bulbs have failed.
Answers
Answer:
if there isn't a shorting mechanism, the whole sets will be blown out several lamps and then shortened, the overall resistance of the remaining operating lamps will be decreased resulting in an increased working current that is adequate to blast the fuse
Question 2
You can make the puck travel in complex ways by placing a set of charges around on the field. So, here’s your game challenge:
Arrange sources charge around to propel the puck from its starting position into the goal. That’s pretty easy for a straight shot; you just put a negative charge behind the goal. But what if there are barriers along the way? This is a real test of your physical understanding, including Newton’s laws of motion and electrostatic forces. Game’s on!
Part A
On the control bar, check the Trace and Field boxes. The game has three Difficulty levels. Start with Difficulty level one and arrange source charges to get the puck into the goal. Once you’ve made a score at any level, increase the Difficulty level. Take a screen capture of two of your most difficult goals and paste them here. At least one of these should be at Difficulty level 2 or 3.
Answers
Answer:
A. The electric field lines point outward and the black puck moves backwards. From this I can see that I can't put the red charge in front of the black puck because it will go away from the goal.
B. The electric field lines point inward and the black puck moves forwards and backwards. The conclusion I made from this was the blue charge by itself will not be able to get into the goal.
C.The puck moves faster when the mass increases and moves slower when the mass decreases. The more mass, the more force that is applied to the puck.
D. The relationship between the speed of the black puck and its distance from the blue charge is when the puck is further away from the blue charge, the slower the puck moves away from it.
Explanation:
Brainlest if this helped!
The intensity of an ultrasound beam is defined as the _______________ in a beam ____________ by the ______________ of the beam.
Answers
The intensity of an ultrasound beam is defined as the power in a beam divided by the area of the beam.
Intensity of the ultrasound beam is defined as the concentration of energy in the beam i.e. Intensity is the rate at which energy passes through the unit area and is an important quantity when discussing bioeffects and safety.
Intensity = power/beam area
Thus it is measured in Watts per cm^2.
The mechanical bioeffect of ultrasound refers to damage caused by the actual oscillation of the sound wave on tissue. The most common is referred to as cavitation and is caused by the oscillation of small gas bubbles within the ultrasound field.
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PLEASE HELP MEEE!!!
In a science experiment showing the splitting of water into Oxygen and hydrogen, two inverted test tubes of water were placed over the site of the reaction. (see the pic) How can you tell which one was catching the oxygen and which one was catching the hydrogen?
A. The hydrogen is a positive ion and will be located close to the negative terminal of the battery.
B. The oxygen is a negative ion which will be located next to the negative terminal of the battery.
C. There are 2 hydrogen atoms for every oxygen atom. The hydrogen will take up more space and is pushing the water lower in the test tube.
D. The hydrogen, being a smaller atom, will take up less space than the oxygen. It will push the water down less.
Answers
Answer:
Option C
Explanation:
Answer C is the correct option. water can be written as H₂O, which means that there are 2 Hydrogen atoms for every oxygen atom, therefore it will occupy more space than oxygen and push more. there is also one more possibility, if the splitting takes place in Hoffman's Voltameter then the Hydrogen will be close to the cathode as hydrogen is positive. Otherwise, option C is correct answer. Hope this Helps you!
A monochromatic light of wavelength 6000×10 −8
cm is diffracted by a single slit kept at a distance of 100 cm from the screen. The first diffracted minimum appears at a distance of 1 mm from the central maximum. Find the width of the slit.
Answers
The width of the slit is approximately 6000 × \(10^{(-8)\) meters, calculated using the formula for the position of the first diffracted minimum in a single-slit diffraction experiment.
To find the width of the slit, we can use the formula for the position of the first diffracted minimum in a single-slit diffraction experiment:
d sin(θ) = mλ
where:
d is the width of the slit,
θ is the angle of diffraction,
m is the order of the minimum,
λ is the wavelength of light.
Given:
λ = 6000 × \(10^{(-8)\) cm,
The first diffracted minimum appears at a distance of 1 mm (√(1 mm)) from the central maximum, which corresponds to an angle of diffraction of θ.
To convert the distance to an angle, we can use the small-angle approximation:
θ ≈ tan(θ) = (√(1 mm)) / 100 cm
Substituting the values into the formula, we have:
d sin(θ) = mλ
d sin(√(1 mm) / 100 cm) = λ
Since we are dealing with the first minimum (m = 1), we can simplify the equation to:
d sin(√(1 mm) / 100 cm) = λ
Solving for d, we get:
d = λ / sin(√(1 mm) / 100 cm)
Substituting the given values, we have:
d = (6000 × \(10^{(-8)\) cm) / sin(√(1 mm) / 100 cm)
Calculating sin(√(1 mm) / 100 cm):
sin(√(1 mm) / 100 cm) ≈ 0.0100
Substituting this value into the equation:
d ≈ (6000 × \(10^{(-8)\) cm) / 0.0100
Calculating the expression:
d ≈ 6000 × \(10^{(-6)\) cm
Converting to meters:
d ≈ 6000 × \(10^{(-8)\) m
Therefore, the width of the slit is approximately 6000 × \(10^{(-8)\) meters.
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You are pushing a box North in the hallway, at 20n, and a friend gets in front of the box and goes in the opposite direction, at 30n. What direction is the box going at? How much force does the box have going in that direction? (PLEASE HELP)
Answers
Answer:
The box is going south (opposite of north) at 10 N.
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Latrice is helping build birdhouses in an effort to attract more purple martins to her area. Building purple martin birdhouses has been shown to increase the size of populations of this bird, which have declined in recent years. What limiting factor must her area have that decreases purple martin populations?
Answers
The availability of suitable nesting sites is one of the most important limiting factors for the purple martin bird population. Building more birdhouses can help address this limiting factor and increase the size of the purple martin population in the area.
There are several limiting factors that can decrease purple martin populations, but one of the most important is the availability of suitable nesting sites. Purple martins are cavity-nesting birds, which means they require hollow spaces, such as tree cavities or specially designed birdhouses, to build their nests and raise their young. In areas where suitable nesting sites are scarce, the population of purple martins may be limited by the number of available nesting sites.
Therefore, by building more birdhouses, Latrice is addressing this limiting factor and helping to increase the size of the purple martin population in her area. Other limiting factors for purple martins may include the availability of food, the quality of habitat, and the presence of predators.
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Define 1 unit of electricity?
Answers
Answer:
1 Unit Electricity is the amount of electrical energy consumed by a load of 1 kW power rating in 1 hour..
Explanation:
A proton is released from rest in a uniform electric field of magnitude 2.18×105 N/C. Find the speed of the proton after it has traveled (a) 1.00 cm and (b) 13.0 cm.
Answers
The speed of the proton after it has traveled 1 cm is ≈ 6.04 × 10^5 m/s. The speed of the proton after it has traveled 13.0 cm is ≈ 2.74 × 10^6 m/s.
(a) When the proton has traveled 1 cm: Work done by electric field = W = qEd Where: q = charge on proton = 1.6 × 10^-19 Cd = 1.00 cm = 1.00 × 10^-2 mE = 2.18×105 N/C
The work done by electric field (W) is converted into kinetic energy (K). Therefore, W = KqEd = K × 1.6 × 10^-19 CEd = 2.18×105 N/C×1.00 × 10^-2 m
∴ K = W/qE= (1.6 × 10^-19 C) × (2.18×105 N/C) × (1.00 × 10^-2 m) / (1.6 × 10^-19 C)= (2.218 × 10^-12 J) / (1.6 × 10^-19 C)≈ 13.8625 JK = (1/2) mv²v = √(2K/m)
Substituting the values in the above formula,v = √(2×13.8625J / 1.67 × 10^-27 kg)≈ 6.04 × 10^5 m/s
Therefore, the speed of the proton after it has traveled 1 cm is ≈ 6.04 × 10^5 m/s.
(b) When the proton has traveled 13.0 cm:
Work done by electric field = W = qEd
Where: q = charge on proton = 1.6 × 10^-19 Cd = 13.0 cm = 13.0 × 10^-2 mE = 2.18×105 N/C
Similarly, W = K = 1.6 × 10^-19 C × 2.18 × 105 N/C × 13.0 × 10^-2 m/1.6 × 10^-19 C≈ 5.654 J
Kinetic energy, K = 5.654 Jv = √(2K/m)
Substituting the values in the above formula,v = √(2×5.654J / 1.67 × 10^-27 kg)≈ 2.74 × 10^6 m/s
Therefore, the speed of the proton after it has traveled 13.0 cm is ≈ 2.74 × 10^6 m/s.
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(THIS IS ASTRONOMY)
A group of older stars that cluster together in a spherical shape and can contain up to one million stars per cluster is called:
A globular cluster
Open clusters
Spherical clusters
Accretion
Answers
Answer:
the answer to this question is A globular cluster
Henry is trying to move his 232 kg refrigerator. He is pushing, but the refrigerator is not moving. If the maximum coefficient of friction between the refrigerator and the floor is 0.87, how hard does Henry have to push in order to get the refrigerator to move?
Answers
Answer:
Once the fridge is moving you are still applying the same push force but now the opposing friction (now kinetic) force is less.