show that if x is an eigenvector of a belonging to an eigenvalue , then x is also an eigenvector of b belonging to an eigenvalue of b. how are and related?
Answers
This shows that the difference between the eigenvalues of x for vector A and B is related to the commutator [A, B] and the eigenvector of x for matrix B.
To show that if x is an eigenvector of matrix A belonging to an eigenvalue λ, then x is also an eigenvector of matrix B belonging to an eigenvalue μ, we can start with the eigenvector equation for matrix A:
A x = λ x
Multiplying both sides by matrix B, we get:
B (A x) = B (λ x)
Using the associative property of matrix multiplication, we can rewrite the left side as:
(B A) x = (A B) x
Substituting the eigenvector equation for matrix A, we get:
(λ B) x = (A B) x
Since x is nonzero, we can divide both sides by x:
λ B = A B
This shows that if x is an eigenvector of matrix A belonging to eigenvalue λ, then it is also an eigenvector of matrix B belonging to eigenvalue μ = λ.
The matrices A and B are related through the commutator [A, B] = AB - BA. We can rewrite the equation λ B = A B as:
λ B - A B = [A, B] B
Since x is nonzero, we can multiply both sides by x:
λ B x - A B x = [A, B] B x
Using the eigenvector equation for matrix A and the fact that x is an eigenvector of matrix A, we get:
λ x - μ x = [A, B] B x
Simplifying, we get:
(λ - μ) x = [A, B] B x
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Related Questions
On the average, Mr. Z drinks and drives once in 4 years. He knows that
Every time when he drinks and drives, he is caught by police.
According to the laws of his state, the third time when he is caught drinking and driving results in the loss of his driver's license.
Poisson process is the correct model for such "rare events" as drinking and driving.
What is the probability that Mr. Z will keep his driver's license for at least 10 years?
Answers
The probability that Mr. Z will keep his driver's license for at least 10 years is approximately 0.2212 or 22.12%.
To find the probability that Mr. Z will keep his driver's license for at least 10 years, we can use the Poisson distribution to model the occurrence of the rare event of him being caught drinking and driving.
The average frequency of Mr. Z drinking and driving is once in 4 years. Since the Poisson distribution assumes a constant average rate, we can use this information to calculate the average rate parameter (λ) for the Poisson distribution.
λ = Average frequency = 1 event in 4 years
To find the probability of Mr. Z not being caught drinking and driving for at least 10 years, we need to calculate the cumulative probability of zero events occurring in a 10-year period.
\(P(X > = 0) = 1 - P(X < 0)\)
Using the Poisson distribution formula, we can calculate the probability of zero events:
\(P(X = 0) = (e^(-λ) * λ^0) / 0!\)
Substituting the value of λ into the formula, we get:
\(P(X = 0) = (e^-(1/4) * (1/4)^0) / 0!\)
\(P(X = 0) = e^-(1/4)\)
To find the probability of Mr. Z not being caught drinking and driving for at least 10 years, we take the cumulative probability:
\(P(X > = 0) = 1 - e^-(1/4)\)
Calculating this value, we find:
\(P(X > = 0) = 0.2212\)
Therefore, the probability that Mr. Z will keep his driver's license for at least 10 years is approximately 0.2212 or 22.12%.
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Will mark brainlist!! Nick’s Burgers is a fast-food restaurant that sells 140 burgers a day. If sales increase by 60%, how many burgers does the restaurant sell in a day?
A.56
B.148
C.200
D.224
Answers
Answer:
D- 224
Step-by-step explanation:
10% of 140 is 14
So then you multiply 14 by 6 to get 60%
then you add that to 140 to equal 224.
The correct statement is that if the sales of burgers at Nick's Burgers increases by 60%, the total sales per day will be increased to 224 burgers per day from 140 burgers per day.
What is Increased Sales?An increase in sales refers to as the positive shift in the sales of goods as compared to previous sessions during a given period of time, given that other factors vary.
The increase in sales will happen as a result of the strategies that may have been adopted by Nick or increase in the demand due to external factors.
The calculation of increased no. of burgers sold per day can be calculated by using the formula and putting the values given in the example as below,
increased sales = 224
So, the new sales of burgers per day is calculated as 224 per day.
Hence, an increase in sales of burgers at Nick's by 60% will result in sales of 224 burgers per day from 140 burgers per day.
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if the price of bananas is $2 a pound, how many pounds of bananas will suppliers supply? 10 1 10,000 0
Answers
If the demand for bananas at $2 per pound is 10 pounds, then the suppliers will supply 10 pounds of bananas.
The question is about determining the number of pounds of bananas suppliers will supply at a given price of $2 a pound.
To determine the number of pounds of bananas suppliers will supply, we need more information than just the price of bananas.
Supply is affected by many factors like cost of production, demand, and the price of substitutes.
Suppliers will supply bananas to the market until the price they get equals the cost of production plus a margin.
If the price is higher than the cost of production plus a margin, then they will continue to supply to maximize their profits.
In the given question, we don't have enough information about the cost of production, demand, and substitutes. Therefore, we cannot accurately predict the amount of pounds of bananas that will be supplied.
However, if we assume that the cost of production is constant and there are no substitutes, then the suppliers will supply bananas at a price of $2 per pound until the market reaches equilibrium.
At equilibrium, the quantity supplied equals the quantity demanded.
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How many real solutions if any, does 2x^2-3x+8=0
Answers
Answer:
The quadratic equation \(2\, x^{2} - 3\, x + 8 = 0\) has no real solution.
Step-by-step explanation:
Rewrite the quadratic equation \(2\, x^{2} - 3\, x + 8 = 0\) in the standard form \(a\, x^{2} + b\, x + c = 0\):
\(2\, x^{2} + (-3)\, x + 8 = 0\), for which:
\(a = 2\).\(b = (-3)\).\(c = 8\).The quadratic discriminant of \(a\, x^{2} + b\, x + c = 0\) is \((b^{2} - 4\, a\, c)\). The quadratic discriminant of \(2\, x^{2} + (-3)\, x + 8 = 0\) would be:
\(\begin{aligned}& b^{2} - 4\, a\, c \\ =\; & (-3)^{2} - 4 \times 2 \times 8 \\ =\; & (-55)\end{aligned}\).
Since the quadratic discriminant of this equation is negative, this quadratic equation has no real solution.
Find a functiony x( )whose second derivative is y x x ( ) 12 2 , given f x x ( ) 5 is tangent to y x x ( ) at 1.
Answers
The tangent of y(x) at x = 1 is y'(1) = 4 + C₁, and the value of f(1) is 5, we can solve for C₁ to get C₁ = 1. Therefore, the function y(x) = x⁴ / 4 + x + C₂, where C₂ is another constant.
The given equation is f (x) = 5, and it is the tangent of the function y = x³ / 3 at x = 1.To get y = x (x² / 2 + C), we integrate the second derivative of y with respect to x.∫(d²y/dx²)dx = ∫(12x²)dx => y = 4x³ + C₁ Solve for C₁ by applying the point-slope equation at the point x = 1:f(1)
= 5
= y(1)
= 4(1)³ + C₁
=> C₁ = 1Therefore, the equation of y is: y = 4x³ + 1.For a more in-depth and better explanation, here are 150 words: A second derivative represents the rate of change of the first derivative with respect to x.
Therefore, if we have a second derivative of y with respect to x, we can integrate it twice to get a function of y with respect to x. Given y''(x) = 12x², we can integrate it once to obtain y'(x) = 4x³ + C₁, where C₁ is a constant. We integrate y'(x) once again to get y(x) = x⁴ / 4 + C₁x + C₂, where C₂ is another constant. Now, to find C₁ and C₂, we need to use the fact that the function f(x) = 5 is tangent to y(x) at x = 1.
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The tangent of y(x) at x = 1 is y'(1) = 4 + C₁, and the value of f(1) is 5, we can solve for C₁ to get C₁ = 1. Therefore, the function y(x) = x⁴ / 4 + x + C₂, where C₂ is another constant.
The given equation is f (x) = 5, and it is the tangent of the function
y = x³ / 3 at x = 1.
To get y = x (x² / 2 + C),
we integrate the second derivative of y with respect to x.
∫(d²y/dx²)dx = ∫(12x²)dx
=> y = 4x³ + C₁
Solve for C₁ by applying the point-slope equation at the point
x = 1:f(1)
= 5
= y(1)
= 4(1)³ + C₁
=> C₁ = 1Therefore, the equation of y is: y = 4x³ + 1
.For a more in-depth and better explanation, here are 150 words: A second derivative represents the rate of change of the first derivative with respect to x.
Therefore, if we have a second derivative of y with respect to x, we can integrate it twice to get a function of y with respect to x.
Given y''(x) = 12x²,
we can integrate it once to obtain
y'(x) = 4x³ + C₁, where C₁ is a constant.
We integrate y'(x) once again to get
y(x) = x⁴ / 4 + C₁x + C₂, where C₂ is another constant.
Now, to find C₁ and C₂, we need to use the fact that the function
f(x) = 5 is tangent to y(x) at x = 1.
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5. Problem 5.15 (Present Value of an Annuity) Find the present values of these ordinary annuities. Discounting occurs once a year. Do not round intermediate calculations. Round your answers to the nearest cent. a. $400 per year for 14 years at 14%. $ b. $200 per year for 7 years at 7%. $ c. $400 per year for 7 years at 0%. $ d. Rework previous parts assuming they are annuities due. Present value of $400 per year for 14 years at 14%:$ Present value of $200 per year for 7 years at 7% : $ Present value of $400 per year for 7 years at 0% : $
Answers
a. Present value of $400 per year for 14 years at 14%: $2,702.83
b. Present value of $200 per year for 7 years at 7%: $1,155.54
c. Present value of $400 per year for 7 years at 0%: $2,800
d. Present value of $400 per year for 14 years at 14% (annuity due): $2,943.07
Present value of $200 per year for 7 years at 7% (annuity due): $1,233.24
Present value of $400 per year for 7 years at 0% (annuity due): $2,800
To find the present values of the ordinary annuities, we can use the formula for the present value of an annuity:
PV = PMT * [(1 - (1 + r)^(-n)) / r]
Where:
PV = Present value
PMT = Payment per period
r = Interest rate per period
n = Number of periods
a. $400 per year for 14 years at 14%:
PV = $400 * [(1 - (1 + 0.14)^(-14)) / 0.14]
≈ $2,702.83
b. $200 per year for 7 years at 7%:
PV = $200 * [(1 - (1 + 0.07)^(-7)) / 0.07]
≈ $1,155.54
c. $400 per year for 7 years at 0%:
Since the interest rate is 0%, the present value is simply the total amount of payments over the 7 years:
PV = $400 * 7
= $2,800
d. Reworking previous parts assuming they are annuities due:
For annuities due, we need to adjust the formula by multiplying it by (1 + r):
a. Present value of $400 per year for 14 years at 14%:
PV = $400 * [(1 - (1 + 0.14)^(-14)) / 0.14] * (1 + 0.14)
≈ $2,943.07
b. Present value of $200 per year for 7 years at 7%:
PV = $200 * [(1 - (1 + 0.07)^(-7)) / 0.07] * (1 + 0.07)
≈ $1,233.24
c. Present value of $400 per year for 7 years at 0%:
Since the interest rate is 0%, the present value remains the same:
PV = $400 * 7
= $2,800
In conclusion:
a. Present value of $400 per year for 14 years at 14%: $2,702.83
b. Present value of $200 per year for 7 years at 7%: $1,155.54
c. Present value of $400 per year for 7 years at 0%: $2,800
d. Present value of $400 per year for 14 years at 14% (annuity due): $2,943.07
Present value of $200 per year for 7 years at 7% (annuity due): $1,233.24
Present value of $400 per year for 7 years at 0% (annuity due): $2,800
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Shawn is taking aluminum cans to the recycling center. After placing his cans on the weight scale, he finds his cans weigh 6.619
pounds. If the recycling center pays $0.65 per pound of aluminum cans, how much money will Shawn earn to the nearest cent?
A. $7.27
B. $4.30
C. $10.18
D. $4.40
Answers
Answer:
B. $4.30 ;0
Step-by-step explanation:
a subset of outcomes of the sample space is called a(n)
a. event
b. solution set
c. sample set d. probability experiment
Answers
The correct answer is (a) event. An event is a subset of outcomes from the sample space. It represents a specific outcome or set of outcomes that we are interested in. Events can be simple, consisting of a single outcome, or they can be compound, consisting of multiple outcomes.
For example, consider rolling a fair six-sided die. The sample space is {1, 2, 3, 4, 5, 6}. Let's say we are interested in the event of rolling an even number. The event in this case would be {2, 4, 6}, which is a subset of the sample space.
Events can also be mutually exclusive, meaning they cannot occur at the same time, or they can be independent, meaning the occurrence of one event does not affect the probability of the other event occurring.
In summary, an event is a subset of outcomes from the sample space and represents a specific outcome or set of outcomes that we are interested in. It is an important concept in probability theory.
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A babe flies at 10 feet per second directly to a flowerbed from its hive. the bee stays at the flowerbed 12 minutes,and the flies directly back to the the hive 6 feet per second.it is away from the hive for a total of 16 minutes
Answers
The equation used to find the distance of the flowerbed from the hive is called the "time equation".
The flowerbed is 900 feet far from the hive.
What is the formula used to calculate Time Equation?To calculate the time equation use the formula for time, t = d/s which means time equals distance divided by speed.Find the height using the Time Equation?Find the traveling time
The bee spends 12 minutes hunting down the nectar in the flowerbed. Since it was away from the hive for a total of 16 minutes, the traveling time is
16min - 12min = 4 min
Convert the Minutes to seconds
1 minute = 60 seconds
4 minutes = 4*60 = 240 seconds
Find the time each way
The total time is 240 seconds, but it is not divided evenly.
Let the time there = t
Let the time back = 240 - t
The distances are the same
r = 10 m/s
r1 = 6 m/s
t1 = t
t2 = 240 - t
dthere = dback
d = rate * time
10 m/s *t = 6 m/s (240 - t)
Remove the brackets on the right.
10 * t = 6*240 - 6t
Combine the like terms on the right.
10t = 1440 - 6t
Add 4t to both sides
10t + 6t = 1440 - 6t + 6t
Combine
16t = 1440
Divide both sides by 16
16t/16 = 1440/16
Do the division
t = 90
Find the height
d = ?
r = 10 m/s
t = 90 second
d = r*t
d = 10 * 90 = 900 feet
The flowerbed is 900 feet far from the hive.
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The complete question is:
A babe flies at 10 feet per second directly to a flowerbed from its hive. the bee stays at the flowerbed for 12 minutes and then flies directly back to the hive at 6 feet per second. It is away from the hive for a total of 16 minutes.
What equation can you use to find the distance of the flowerbed from the hive?
What is function and not function?
Answers
Answer: A function is a relation between domain and range such that each value in the domain corresponds to only one value in the range. Relations that are not functions violate this definition. They feature at least one value in the domain that corresponds to two or more values in the range.
Step-by-step explanation:
7+8r+10r pls help me im failing
Answers
Final Answer: \(7 + 18r\)
Steps/Reasons/Explanation:
Question: Solve \(7 + 8r + 10r\).
Step 1: Collect like terms.
\(7 + (8r + 10r)\)
Step 2: Simplify.
\(7 + 18r\)
~I hope I helped you :)~
To insure a house valued at £3000 costs £2.25. Find the value of a house which costs £3.37 1/2 to insure.
Answers
Using the cross-multiplication method, we know that the house which costs £3.37 has a value of £4,493.33.
What is a cross-multiply method?One might cross-multiply an equation between two fractions or rational expressions in mathematics, more specifically in elementary arithmetic and elementary algebra, to make the equation simpler or to find the value of a variable.When using the cross-multiplication approach, the denominator of the first term is multiplied by the numerator of the second term and vice versa.So, the value of the house costs £3.37:
House that costs £2.25 is valued at £3000.Now, use the cross-multiplication method as follows:
2.25/3000 = 3.37/x2.25x = 3000 × 3.372.25x = 10,110x = 10,110/2.25x = 4,493.33Therefore, using the cross-multiplication method, we know that the house which costs £3.37 has a value of £4,493.33.
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Correct question:
To ensure a house valued at £3000 costs £2.25. Find the value of a house that costs £3.37.
The reciprical of 312-938 is what number? If 23-3x=2 then x=y for 3
Answers
Answer:
-1/626 and for 23-3x=2 x=7
Step-by-step explanation:
HELP and please explain it
Answers
Answer:
SAS, ASA, SSS, ASA, Yes
Step-by-step explanation:
PLEASE HELP ME! THANK YOU!
Answers
An SRS of 20 orangutans is selected, and 65 cc of blood is to be drawn from each orangutan using a 100 cc syringe. In the sample, the mean volume is 64 cc and the standard deviation is 12 cc. Assume that in the population of all such procedures, the amount of blood drawn follows a Normal distribution with mean ?.
Reference: Ref 17-1
We are interested in a 95% confidence interval for the population mean volume. The margin of error associated with the confidence interval is
Answer
A. 4.64.
B. 2.68.
C. 6.84.
D. 5.62.
Answers
The margin of error associated with the 95% confidence interval for the population mean volume is: D. 5.62.
To calculate the 95% confidence interval for the population mean volume, we can use the formula:
CI = x ± (t * (s/√n))
Where CI represents the confidence interval, x is the sample mean, t is the t-score associated with the desired confidence level (95%), s is the sample standard deviation, and n is the sample size.
In this case, x = 64 cc, s = 12 cc, and n = 20 orangutans. We need to find the t-score for a 95% confidence interval with 19 degrees of freedom (n-1). Using a t-table, we find that the t-score is approximately 2.093.
Now we can calculate the margin of error:
Margin of Error = t * (s/√n) = 2.093 * (12/√20) ≈ 5.62
Therefore, the margin of error associated with the 95% confidence interval for the population mean volume is: D. 5.62.
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Which of the following statements must be true based on the diagram below?
(Diagram is not to scale.)
Answers
Answer:
i dont know
Step-by-step explanation:
i dont kow
Can Someone help me out
Answers
Answer:
D 0.9988
Step-by-step explanation:
I always get these mixed up, can someone help me?
Answers
Answer:
The answer is
1_ side angle side
2_angle side angle
3_ angle angle side
4_ side side side
Please help with this I nnneeeeeeeed help
Answers
The complete equation for each variable given above would be given as follows;
5.) 8²× 8⁹ = 8¹¹
6.) 5⁷×5^-⁴ = 5³
7.) X¹² × X⁰ = X¹²
How to determine the complete equation for the given variables?To determine the complete equation for the given question above, the following steps needs to be taken.
For question 5.)
8² * 8^x = 8¹¹
Here ; 2+X = 11
X = 11-2 = 9
For questions 6.)
5⁷×5^b = 5³
That is;
7+ b = 3
n = 3-7 = -4
For question 7.)
X¹² × X⁰ = X¹²
That is,
12+ n =12
n = 12-12 = 0
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DUE IN 20 MINUTES AND I DON'T KNOW HOW TO SOLVE!
A cone with height h and radius r has volume V = 13πr2h. If a certain cone with a height of 9 inches has volume V = 3πx2 + 42πx + 147π, what is the cone’s radius r in terms of x?
Answers
Answer: Therefore, the radius of the cone in terms of x is: r = √(x^2 + 14x + 49).
Step-by-step explanation: Substitute
3πx^2 + 42πx + 147π = 1/3(π)(r²)(9)
3π(x^2 + 14x + 49) = (π)(r²)(3)
Divide both sides by 3π
x^2 + 14x + 49 = r²
Square both sides
√(x^2 + 14x + 49) = r
r = √(x^2 + 14x + 49)
Last year, Ken bought a mountain bike for $400. It is now worth $320. What percent
did the value of Ken's bike depreciate over the past year, to the nearest whole
percent?
Answers
The percent by which the value of Ken's bike depreciated over the past year is 20%.
What is the percentage deprecation?
Depreciation is the decline in the value of an asset with the passage of time. Depreciation is as a result of wear and tear of an asset. The price of an item would decline when it depreciates.
Percentage is the fraction of an amount that is expressed as a number out of hundred. Percentage is used to measure the frequency of data. The sign that represents percentage is %. To convert a number to percentage, multiply the number by 100.
Percent depreciation = (value of the mountain bike today / value of the mountain bike last year) - 1
($320 / $400) - 1 = -0.20
0.20 x 100 = 20%
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Solve each equation, and write the algebraic reason for each step.
1. 3y+5=2y-8
2. -2(x-1)=3x-13
3. 3b+4+b=16
Answers
The equations are solved to give
1. y = 13
2. x = 3
3. b = 3
How to determine the solution to the expressionsIt is important to note that algebraic expressions are expressions composed of variables, terms, factors, constants and coefficients.
From the information given, we have that the expressions are;
3y+5=2y-8
Now, collect like terms
3y - 2y = -8 - 5
subtract the like terms
y = 13
-2(x-1)=3x-13
expand the bracket
-2x + 2= 3x - 13
collect like terms
-2x -3x = -13 - 2
subtract the like terms
-5x = -15
x = 3
3b+4+b=16
collect like terms
4b = 12
b = 3
Hence, the values are 13. 3 and 3
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If x = 6 and y = 4, work out the value of the following:
4x + y
2y squared
( x - y ) squared
Answers
Step-by-step explanation:
If x = 6 and y = 4. Substitute x and y in the expression.
4x+y
4(6)+(4)
24+4
28
2y²
2(6)²
2(36)
72
( x - y )²
(6+4)²
(10)²
100
Nathan bought 3 1/4 pounds of apples for $0.75 per pound. How much did Nathan pay for the apples (rounded to the nearest hundredth)?
Answers
Answer: 2.5
Step-by-step explanation:
3 1.4 lbs also equals 3.25
3 x 0.75 = 2.25
2.25 + 25 = 2.5
given the following all-integer linear program: max 15x1 2x2 s. t. 7x1 x2 < 23 3x1 - x2 < 5 x1, x2 > 0 and integer a. solve the problem as an lp, ignoring the integer constraints. b. what solution is obtained by rounding up fractions greater than or equal to 1/2? is this the optimal integer solution? c. what solution is obtained by rounding down all fractions? is this the optimal integer solution? explain. d. show that the optimal objective function value for the ilp (integer linear programming) is lower than that for the optimal lp. e. why is the optimal objective function value for the ilp problem always less than or equal to the corresponding lp's optimal objective function value? when would they be equal? comment on the optimal objective function of the milp (mixed-integer linear programming) compared to the corresponding lp and ilp.
Answers
The required solution of the linear programming problem for the given objective function and subject to constraints are,
Linear programming problem is Maximize 15x1 + 2x2
Subject to:
7x1 + x2 < 23
3x1 - x2 < 5
x1, x2 > 0
Objective function value for rounding up fraction 1/2 solution is 53
Objective function value for rounding up all fraction solution is 23.
Optimal objective function value 53 is lower than optimal value 95.5.
Optimal objective function value is always less than or equal to the LP's optimal objective function value as ILP problem is a more constrained version.
To solve the problem as an LP,
we can ignore the integer constraints
And solve the problem as a continuous linear program.
The problem can be written as,
Maximize 15x1 + 2x2
Subject to:
7x1 + x2 < 23
3x1 - x2 < 5
x1, x2 > 0
Rounding up fractions greater than or equal to 1/2,
The following feasible solution is,
x1 = 3, x2 = 4
The objective function value for this solution is 53.
However, this is not the optimal integer solution since both x1 and x2 are not integers.
Rounding down all fractions, we get the following feasible solution,
x1 = 1, x2 = 4
The objective function value for this solution is 23, which is less than the LP's optimal objective function value of 95.5.
This is not the optimal integer solution either.
Optimal objective function value for the ILP is lower than that for the optimal LP, solve the ILP problem.
In any one constraints
When x1 = 0 ⇒ x2 = 23
x2 = 0 ⇒ x1 = 3.3
Optimal value is ,
15(3.3) + 2(23)
= 49.5 + 46
= 95.5
Optimal objective function value is lower than optimal value.
The optimal objective function value for the ILP problem is always less than or equal to the corresponding LP's optimal objective function value .
Because the ILP problem is a more constrained version of the linear programming problem.
The ILP problem restricts the variables to be integers, which reduces the feasible region and makes the problem more difficult to solve.
The optimal objective function values for the LP and ILP problems are equal.
If the LP problem has an optimal solution that satisfies the integer constraints.
In general, the optimal objective function value of the MILP problem can be better or worse than that of the LP or ILP problem.
It depends on the specific problem instance.
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The above question is incomplete, the complete question is :
Given the following all-integer linear program:
Max 15x1 + 2x2
s. t.
7x1 + x2 < 23
3x1 - x2 < 5
x1, x2 > 0 and integer
a. solve the problem as an lp, ignoring the integer constraints.
b. what solution is obtained by rounding up fractions greater than or equal to 1/2? is this the optimal integer solution?
c. what solution is obtained by rounding down all fractions? is this the optimal integer solution? explain.
d. show that the optimal objective function value for the ilp (integer linear programming) is lower than that for the optimal lp.
e. why is the optimal objective function value for the ilp problem always less than or equal to the corresponding lp's optimal objective function value? when would they be equal? comment on the optimal objective function of the milp (mixed-integer linear programming) compared to the corresponding lp and ilp.
Student Council needs $600 for the
spring dance. They only have $210 in the
treasury. The Student Council decides to raise
the rest by selling chocolate lollipops for a $1.50
profit per lollipop. Write and solve an equation
the Student Council could use to find the
number of chocolate lollipops, c, the Student
Council must sell to have the money for the
spring dance.
Answers
Answer:
$490MARK ME AS BRAINLY#Carry On LearningWhat is $ 1,000,000 x 0.3=
Answers
Answer:
300,000
Step-by-step explanation:
Answer:
$300,000
Step-by-step explanation:
go back one place
Which one is NOT an acceptable name for <1?
Answers
The option that is not an acceptable name for < 1 is D) improper.
How to define the digit ?This name properly refers to a numerical value that is less than one and denotes the decimal representation of a fractional quantity, with its numerator smaller than the denominator. Thus, this numerical denomination corresponds precisely to any number existing between zero and one.
Furthermore, it should be noted that this nomenclature exclusively applies exclusively to numbers below one, and not above it, since that would signify figures greater than one.
Find out more on acceptable names at https://brainly.com/question/17242320
#SPJ1
Options are:
A) negative
B) fraction
C) decimal
D) improper
Do these pairs of values (x and y) represent two quantities that are proportional?
X: 2, 5, 6, 8
Y: 6, 12, 14, 18