Sketch a graph of a function y = f(x) with ALL of the following properties: lim f(x) = -1 878 lim f(x) x-0 does not exist. f(0) = 15.
Answers
The graph of the function y = f(x) has a horizontal asymptote at y = -1,878 and does not have a limit as x approaches 0. The function has a specific point at (0, 15).
The given properties indicate that the graph of the function y = f(x) approaches a horizontal line at y = -1,878 as x tends to positive or negative infinity. This is represented by a horizontal asymptote. However, the function does not have a limit as x approaches 0, suggesting a discontinuity or a sharp change in behavior around that point.
To satisfy the condition f(0) = 15, we know that the graph must pass through the point (0, 15). The exact shape and behavior of the graph between the points where the asymptote and the point (0, 15) occur can vary, allowing for different possible curves.
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Related Questions
The CEO of the Wild Widget Company has decided to invest $360, 000 in his Michigan facgory. His economic analysts have noted that the output of this factory is modeled by the function Q : (0,[infinity])^2 → R given by Q(KL)-60K^-1/3L^2/3 where K denotes the amount (in thousands of dollars) spent on capital equipment and L represents the amount (also in thousands of dollars) spent on labor. (a) How should the CEO allocate the $360, 000 between labor and equipment? (b) Show that
aQ/aK=aQ/aL
at the point (K, L) found in part (a)
Answers
xplanation:
a b c your way out the picture
The CEO should allocate $144,000 to labor and $216,000 to capital equipment.
How should the CEO allocate the $360, 000 between labor and equipment?Step-by-step explanation given below
The CEO should allocate $144,000 to labor and $216,000 to capital equipment. This allocation maximizes the output of the factory, which can be found by taking the partial derivatives of the function Q with respect to K and L and setting them equal to 0.
Partial derivative of Q with respect to K = -20K^-4/3L^2/3 = 0
20K^-4/3L^2/3 = 0
K^4/3L^2/3 = 20
K = (20L^2/3)^1/4
Partial derivative of Q with respect to L = -40K^-1/3L^-1/3 = 0
40K^-1/3L^-1/3 = 0
K/L = 40
K = 40L
Solving for K and L, we get:
K = (20*L^2/3)^1/4
L = 40K
Substituting K into the equation for L, we get:
L = (40*(20L^2/3)^1/4)
L = 80(20L^2/3)^1/4
L^3/4 = 160L^2/3
L^3 = 1280L^2
L^2 = 1280L
L = 1280
Substituting L into the equation for K, we get:
K = (20*1280^2/3)^1/4
K = (307200/3)^1/4
K = 144
Therefore, the CEO should allocate $144,000 to labor and $216,000 to capital equipment.
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Write the trigonometric expression in terms of sine and cosine, and then simplify. cot()/sin()-csc()
Answers
Answer:
First, we know that:
cot(x) = cos(x)/sin(x)
csc(x) = 1/sin(x)
I can't know for sure what is the exact equation, so I will assume two cases.
The first case is if the equation is:
\(\frac{cot(x)}{sin(x)} - csc(x)\)
if we replace cot(x) and csc(x) we get:
\(\frac{cot(x)}{sin(x)} - csc(x) = \frac{cos(x)}{sin(x)} \frac{1}{sin(x)} - \frac{1}{sin(x)}\)
Now let's we can rewrite this as:
\(\frac{cos(x)}{sin(x)} \frac{1}{sin(x)} - \frac{1}{sin(x)} =\frac{cos(x)}{sin^2(x)} - \frac{1}{sin(x)}\)
\(\frac{cos(x)}{sin^2(x)} - \frac{sin(x)}{sin^2(x)} = \frac{cos(x) - sin(x)}{sin^2(x)}\)
We can't simplify it more.
Second case:
If the initial equation was
\(\frac{cot(x)}{sin(x) - csc(x)}\)
Then if we replace cot(x) and csc(x)
\(\frac{cos(x)}{sin(x)}*\frac{1}{sin(x) - 1/sin(x)} = \frac{cos(x)}{sin(x)}*\frac{1}{sin^2(x)/sin(x) - 1/sin(x)}\)
This is equal to:
\(\frac{cos(x)}{sin(x)}*\frac{sin(x)}{sin^2(x) - 1}\)
And we know that:
sin^2(x) + cos^2(x) = 1
Then:
sin^2(x) - 1 = -cos^2(x)
So we can replace that in our equation:
\(\frac{cos(x)}{sin(x)}*\frac{sin(x)}{sin^2(x) - 1} = \frac{cos(x)}{sin(x)}*\frac{sin(x)}{-cos^2(x)} = -\frac{cos(x)}{cos^2(x)}*\frac{sin(x)}{sin(x)} = - \frac{1}{cos(x)}\)
What is the value of x?
Enter your answer in the box.
x = ?
Answers
Answer:
x = 26
Step-by-step explanation:
Answer:
26 degrees
Step-by-step explanation:
The small square symbol on the upper left of the line represents a 90-degree angle.
90 - 64 = 26 degrees
Fill in the blank to make equivalent rational expression
2/u+9 = Blank/(u+7)(u+9)
Answers
The missing term in the numerator is 2(u+7).
The equivalent rational expression is:
2/u+9 = 2(u+7)/(u+7)(u+9)
To make the rational expression equivalent, we need to find the missing term in the numerator.
The denominator of the given expression is (u+7)(u+9). In order for the two expressions to be equivalent, the numerator of the equivalent expression should be 2 multiplied by (u+7).
Therefore, the missing term in the numerator is 2(u+7).
The equivalent rational expression is:
2/u+9 = 2(u+7)/(u+7)(u+9)
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Is direct variation the same as slope?
Answers
Answer:
Step-by-step explanation:
A direct variation is a linear relationship between variables so they have a constant ratio. It is a special case of the slope-intercept form y =mx +b, where b = 0.
Expand LaTeX: (4a - 3b^3)^2.
Answers
(4a-3b^3)^2
(4a-3b^3)(4a-3b^3)
16a-12ab^3-12ab^3+9b^3
16a+9b3
Evaluate The Double Integral2xy DA, D Is The Triangular Region Withvertices (0,0), (1,2), And (0,3)
Answers
The value of given double integral ∬(D) 2xy dA is 7/12.
Given, double integral ∬(D) 2xy dA, where D is the triangular region with vertices (0,0), (1,2), and (0,3).
To evaluate the given integral, we divide the region D into two parts: D1 and D2.
For D1:
The region D1 is a right triangle with vertices (0,0), (1,2), and (0,2). The limits of integration are: 0 ≤ x ≤ 1 and 0 ≤ y ≤ 2x.
Therefore, ∬(D1) 2xy dA can be calculated as:
∫(0)¹ ∫(0)²ˣ 2xy dy dx = ∫(0)¹ x³ dx = 1/4
For D2:
We can transform the region D2 by using the variables u = x and v = y - 2x. The inverse transformation is x = u and y = u + v/2.
The equation of the line passing through the vertices (0,2), (1,2), and (0,3) can be expressed as y = x + 2. Substituting the transformations, we get v = u.
The limits of integration for D2 are: 0 ≤ u ≤ 1 and 0 ≤ v ≤ 3 - 2u.
Therefore, ∬(D2) 2xy dA can be calculated as:
∫(0)¹ ∫(0)\(^3^-^2^u\) 2u\(^(^u^+^v^/^2^)\) dv du = ∫(0)¹ [2u\(^2^v^/^2\) + u\(^2^v^/^2\) + v\(^2^u^/^4\)]_0\(^3^-^2^u\) du = ∫(0)¹ [(3u³)/2 - (5u²)/4 + (3u)/8] du = 19/24
Therefore, ∬(D) 2xy dA = 1/4 + 19/24 = 7/12.
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A company manufactures a 14-ounce box of cereal. Boxes are randomly weighed to ensure the correct amount. If the discrepancy in weight is more than 0.25 ounces, the production is stopped.
Which function could represent this situation? Ede
Answers
Answer:
Answer is B on Edge
F(x)=14-x
Step-by-step explanation:
Answer:
B) f(x) = |14 – x|
Step-by-step explanation:
Edge
Complete the missing information in the puzzle. (1.2)
Answers
The missing information in the puzzle
1) 12
2) 2y
3) 12+ 2y
4) 12+ 2y
What are puzzles ?
puzzle, a problem that may take many forms, including games and toys, and is solved through knowledge, ingenuity, or other skills. The solver of a puzzle must arrive at the correct answer, or answers, by thinking or putting pieces together in a logical way.
The puzzle one)
1st block: 4a
2nd block: -20
Hence , the missing information in the puzzle
1) 12
2) 2y
3) 12+ 2y
4) 12+ 2y
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The inverse of y = 2x + 2 is
Answers
Answer:
(x - 2) / 2
Step-by-step explanation:
x = 2y + 2
2y = x - 2
y = (x - 2) / 2
Answer: (x-2)/2
Step-by-step explanation:
edg
Mark bought 2 pounds of walnuts for 25.50 Approximately how much will he pay for 7 pounds of walnuts
Answers
Answer:
89.25
Step-by-step explanation:
2pound of walnut= 25.50
1 pound of walnut= 12.75
7punds of walnut= 89.25
7pounds of walnut= 12.75* 7=89.25
Part B.
Describe two different ways you could find measure of CFD. What is the measure of
this angle?
Answers
Answer:
∠CFD = 60°
Step-by-step explanation:
Along line CE:
∠AFE + ∠AFB + ∠BFC = 180° (sum of angles on a straight line)
(7x + 4) + (8x + 6) + (6x + 2) = 180
collecting alike terms:
7x + 8x + 6x + 4 + 6 + 2 = 180
21x + 12 = 180
21x = 168
x = 8°
We could find the measure of CFD using:
a) Along line AD:
∠AFB + ∠BFC + ∠CFD = 180° (sum of angles on a straight line).
(8x + 6) + (6x + 2) + ∠CFD = 180
14x + 8 + ∠CFD = 180
∠CFD = `180 - (14x + 8)
∠CFD = 172 - 14x
b) ∠CFD = ∠AFE (vertical opposite angles are equal)
∠CFD = 7x + 4
To find value of ∠CFD, substitute x = 8
∠CFD = 7(8) + 4
∠CFD = 60°
A study compared three display panels used by air traffic controllers. Each display panel was tested for four different simulated emergency conditions. Twenty-four highly trained air traffic controllers were used in the study. Two controllers were randomly assigned to each display panel—emergency condition combination. The time (in seconds) required to stabilize the emergency condition was recorded. The following table gives the resulting data and the JMP output of a two-way ANOVA of the data. Emergency Condition Display Panel 1 2 3 4 A 17 25 31 14 14 24 35 13 B 15 22 28 9 12 19 31 10 C 21 29 32 15 24 28 37 19 Least Squares Means Estimates Panel Estimate Condition Estimate A 21. 500000 1 17. 166670 B 18. 375000 2 24. 666670 C 25. 625000 3 32. 166670 4 13. 333300 Analysis of Variance Source DF Sum of Squares Mean Square F Ratio Model 11 1,480. 3333 134. 576 30. 4700 Error 12 53. 2000 4. 417 Prob > F C. Total 23 1,533. 3333 <. 0001* Effect Tests Source Nparm DF Sum of Squares F Ratio Prob > F Panel 2 2 211. 5833 23. 9528 <. 0001* Condition 3 3 1,253. 0000 94. 5660 <. 0001* Panel* Condition 6 6 15. 7500 0. 5943 0. 7298 Tukey HSD All Pairwise Comparisons Quantile = 2. 66776, Adjusted DF = 12. 0, Adjustment = Tukey Panel -Panel Difference Std Error t Ratio Prob>|t| Lower 95% Upper 95% A B 3. 12500 1. 050793 2. 97 0. 0290* 0. 3217 5. 92826 A C −4. 12500 1. 050793 −3. 93 0. 0053* −6. 9283 −1. 32174 B C −7. 25000 1. 050793 −6. 90 <. 0001* −10. 0533 −4. 44674 Tukey HSD All Pairwise Comparisons Quantile = 2. 9688, Adjusted DF = 12. 0, Adjustment = Tukey Condition -Condition Difference Std Error t Ratio Prob>|t| Lower 95% Upper 95% 1 2 −7. 5000 1. 213352 −6. 18 0. 0002* −11. 1022 −3. 8978 1 3 −15. 2000 1. 213352 −12. 36 <. 0001* −18. 6022 −11. 3978 1 4 3. 8333 1. 213352 3. 16 0. 0359* 0. 2311 7. 4355 2 3 −7. 5000 1. 213352 −6. 18 0. 0002* −11. 1022 −3. 8978 2 4 11. 3333 1. 213352 9. 34 <. 0001* 7. 7311 14. 9355 3 4 18. 8333 1. 213352 15. 52 <. 0001* 15. 2311 22. 4355 Click here for the Excel Data File.
a. Calculate a 95 percent (individual) confidence interval for the mean time required to stabilize emergency condition 4 using display panel B. (Round your answers to 2 decimal places. )
Answers
Without the standard deviation, we cannot calculate the standard error or the 95 percent confidence interval for the mean time required to stabilize emergency condition 4 using display panel B.
To calculate a 95 percent confidence interval for the mean time required to stabilize emergency condition 4 using display panel B, we can use the least squares means estimates provided in the JMP output.
According to the JMP output, the estimate for the mean time required to stabilize emergency condition 4 using display panel B is 10.375000.
To calculate the confidence interval, we need to find the margin of error. The margin of error can be calculated using the formula:
Margin of Error = Critical Value * Standard Error
In this case, we need to find the critical value for a 95 percent confidence interval. Since we have a sample size of 24 (as mentioned in the question), we can use the t-distribution with (24-1) degrees of freedom to find the critical value.
Looking up the critical value in the t-distribution table, with (24-1) degrees of freedom and a confidence level of 95 percent, we find that the critical value is approximately 2.064.
The standard error can be calculated using the formula:
Standard Error = Standard Deviation / √(sample size)
The standard deviation is not provided in the given information. Therefore, we cannot calculate the standard error or the confidence interval without this information.
In summary, without the standard deviation, we cannot calculate the standard error or the 95 percent confidence interval for the mean time required to stabilize emergency condition 4 using display panel B.
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All mortgages must be paid monthly.
A. True
B.False
Answers
Answer:
A
Step-by-step explanation:
a jazz concert brought in $157,437 on the sale of 8,856 tickets. if the tickets are sold for $10 and $20 dollars, how many of the $10 dollar ticket were sold?
Answers
1968 of the $10 dollar ticket were sold by jazz & 6873 of the $20 dollar ticket were sold by jazz.
Jazz total amount received = $157,437
Total tickets sold = 8,856
Let the $10 tickets sold = x
The $20 tickets sold = 8,856 - x
Here the solution below :
$10(x) + 8,856 - x($20) = $157,437
$10x + $177120 - $20x = $157,437
-$10x = $157,437 - $177120
-$10x = - $19683
x = 1968.3
1968 of the $10 dollar ticket were sold by jazz & 6873 of the $20 dollar ticket were sold by jazz.
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The structure has a 215-foot-tall central tower over the main shrine, built on a pyramid base whose corners are marked by four stepped towers that collectively are meant to symbolize Mount Meru. This is the temple of:
Answers
The temple is described with a central tower and stepped towers symbolizing Mount Meru is Angkor Wat.
The temple is described with a central tower over the main shrine and four stepped towers symbolizing Mount Meru is Angkor Wat. Angkor Wat is a massive temple complex located in Siem Reap, Cambodia, and is one of the most important and iconic archaeological sites in Southeast Asia.
Built-in the 12th century by the Khmer Empire, Angkor Wat is a UNESCO World Heritage Site and is known for its intricate architectural design and religious significance. The central tower stands at a height of 215 feet and is surrounded by four smaller stepped towers, forming a symbolic representation of Mount Meru, which is considered a sacred mountain in Hindu mythology.
Angkor Wat is not only a significant religious site but also attracts visitors from around the world due to its historical and cultural importance, as well as its impressive architectural beauty.
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How do you subtract polynomials Grade 9?
Answers
We can subtract polynomials using rules as performing a subtraction, always add like terms together then change sign of subtracting polynomial.
What is Polynomial ?A polynomial is an expression constructed using integer constants, variables, and algebraic operations is known as an algebraic expression in mathematics. Algebraic operations are adding, subtracting, multiplying, dividing. Additionally only whole number exponents is permitted in polynomial.
Rules for subtracting :
While performing a subtraction, always add like terms together.The signs of every term in the subtracting polynomial will alter, with + becoming – and – becoming +.Example: (4x – 3) – ( 2x^2 + 4x - 8)
(4x – 3) + (-2x^2 – 4x + 8)
Now using the property of addition and subtraction,
= 4x – 3 – 2x^2 – 4x + 8
= (4x-4x) – 2x^2 + (-3+8)
= 0 - 2x^2 + 5
= -2x^2 + 5
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. a construction zone on a highway has a posted speed limit of 40 miles per hour. the speeds of vehicles passing through this construction zone are normally distributed with a mean of 46 mph and a standard deviation of 4 mph. (around your answer to 2 decimal places) b) if the police wish to ticket only those drivers whose speed falls in the upper 20th percent, what is the minimum speed of a driver that will be ticketed?
Answers
a. A speed of 40 mph is 1.5 standard deviations below the mean.
b. The minimum speed of a driver that will be ticketed is approximately 49.36 mph.
What is standard deviation?The standard deviation (SD, also written as the Greek symbol sigma or the Latin letter s) is a statistic that is used to express how much a group of data values vary from one another.
a) We can use the z-score formula to find out how many standard deviations away from the mean a speed of 40 mph is:
z = (40 - 46) / 4 = -1.5
This means that a speed of 40 mph is 1.5 standard deviations below the mean.
b) To find the minimum speed of a driver that will be ticketed, we need to find the z-score that corresponds to the 80th percentile (since we want to find the speed for the upper 20th percentile):
z = invNorm(0.8) ≈ 0.84
Using the z-score formula again, we can solve for the speed:
z = (x - 46) / 4
0.84 = (x - 46) / 4
x - 46 = 3.36
x ≈ 49.36 mph
Therefore, the minimum speed of a driver that will be ticketed is approximately 49.36 mph.
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how many ternary strings (digits 0, 1, or 2) are there with exactly 5 0s, 5 1s and 5 2s?
Answers
A ternary string is a string composed of characters 0, 1, and 2. The number of ternary strings that contain exactly n characters, each of which is one of three types, is 3^n.Exactly 5 0s, 5 1s, and 5 2s are required for the ternary string, which means that the total number of characters is 15.
Each of these characters can be one of three types (0, 1, or 2). As a result, the total number of possible strings is 3^15. This is equivalent to 14,348,907. We arrived at this conclusion by computing 3 to the fifteenth power.Explanation:When constructing a sequence of three symbols, the first symbol has three alternatives, the second symbol has three alternatives, and so on. There are n choices for each of the n characters, resulting in a total of 3^n possible sequences.Example 1:Let's assume we have to create 5-character sequences with three symbols: a, b, and c. There are 3*3*3*3*3 = 243 possible sequences since there are three choices for each symbol.Example 2:Let's assume we have to construct a 10-character sequence using three symbols: 0, 1, and 2. There are 3*3*3*3*3*3*3*3*3*3 = 59,049, a total of 59,049 possible 10-character sequences. We can perform the same calculation for 15-character strings using the same logic.
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help! i'll give out a brainliest! just middle school level. <3!
Answers
Answer:3
Step-by-step explanation:
Answer:
3 hours
Step-by-step explanation:
the weight limit for checked luggage on an airline is 22kg. rohan's suitcase weighs 47 pounds. he knows that 1kg is equal to approximately 2.2 pounds. is his suitcase below the limit? Explain
Answers
Weight of Rohan's luggage < weight limit of airline
The weight of the Rohan's luggage is within the limit of airline.
In the above question, it is given that
The weight limit for checked luggage on an airline is = 22kg
The weight of Rohan's suitcase is = 47 pounds
We need to find, whether or not the weight of the Rohan's luggage is within the limit of airline
It is also given that,
1 kg = ~ 2.2 pounds
Then, weight limit of airline in pounds = 22 x 2.2 = 48.4 pounds
We can observe that, the weight of Rohan's luggage is less than the weight limit of airline
i.e weight of Rohan's luggage < weight limit of airline
Hence, the weight of the Rohan's luggage is within the limit of airline.
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when the diameter of one telescope is two times that of another, how does its collecting area compare?
Answers
The collecting area of a telescope is proportional to the square of its diameter. This means that if the diameter of one telescope is two times that of another, its collecting area will be four times larger.
In mathematical terms, the collecting area of a telescope is given by the formula A = πr^2, where A is the collecting area and r is the radius of the telescope's aperture. Since the diameter of a telescope is twice its radius, we can rewrite this formula as A = π(d/2)^2, where d is the diameter of the telescope.
If the diameter of one telescope is two times that of another, then the collecting area of the larger telescope will be A = π(2d/2)^2 = 4π(d/2)^2 = 4A, where A is the collecting area of the smaller telescope.
Therefore, the collecting area of the larger telescope is four times larger than that of the smaller telescope.
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using a 0.01 level of significance, what is the critical point that one would compare to the f statistic in order to make a conclusion? give your answer to three decimal places.
Answers
4.4306 is the critical point using a 0.01 level of significance, that one would compare to the f statistic in order to make a conclusion.
What is the ANOVA?
This is the term that is used to refer to the short form of the term that says analysis of variance.
The ANOVA is used to show the variation that would be in existence of a group of observations.
The F test is known to be positively skewed at all times. So we would have it that the P value would have to be to the right and not to the left in the ANOVA hypothesis.
Using F Statistics table , we can calculate Critical point using a 0.01 level of significance.
Hence,4.4306 is the critical point using a 0.01 level of significance, that one would compare to the f statistic in order to make a conclusion.
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In a certain city the temperature. (in °F)t hours after 9AM was mod- by the function.
T(+) = 48 + 11 sin (πt/12)
Find the average temperature from 9AM to 9 PM.
Answers
The average temperature from 9 AM to 9 PM is approximately 49.83 degrees Fahrenheit.
To find the average temperature from 9 AM to 9 PM, we need to calculate the average value of the temperature function T(t) over that time interval.
The given temperature function is:
T(t) = 48 + 11 sin(πt/12)
We want to find the average value of T(t) from 9 AM to 9 PM, which corresponds to t values from 0 to 12.
The average value of a function over an interval [a, b] is given by the formula:
Average value = (1 / (b - a)) * ∫[a, b] f(t) dt
In this case, the average value of T(t) from 9 AM to 9 PM is:
Average temperature = (1 / (12 - 0)) * ∫[0, 12] (48 + 11 sin(πt/12)) dt
Average temperature = (1 / 12) * ∫[0, 12] (48 + 11 sin(πt/12)) dt
To calculate this integral, we can split it into two parts:
Average temperature = (1 / 12) * (∫[0, 12] 48 dt + ∫[0, 12] 11 sin(πt/12) dt)
The first integral evaluates to:
∫[0, 12] 48 dt = 48t | [0, 12] = 48 * (12 - 0) = 48 * 12 = 576
For the second integral, we use the identity: ∫ sin(u) du = -cos(u)
∫[0, 12] 11 sin(πt/12) dt = -11 * (cos(πt/12)) | [0, 12]
= -11 * (cos(π * 12/12) - cos(π * 0/12))
= -11 * (cos(π) - cos(0))
= -11 * (-1 - 1)
= -11 * (-2)
= 22
Substituting these values back into the equation for the average temperature:
Average temperature = (1 / 12) * (576 + 22)
Average temperature = (1 / 12) * 598
Average temperature = 49.8333...
Therefore, the average temperature from 9 AM to 9 PM is approximately 49.83 degrees Fahrenheit.
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Use a calculator to find each sum or difference. Round your answer to the nearest hundredth.
a. 422 3/7 - 367 5/9
b. 23 1/5 + 45 7/8
Answers
Answer:
54.87
69.08
Step-by-step explanation:
The two lines graphed below are not parallel. How many solutions are there to
the system of equations?
A. Zero
B. Infinitely many
C. Two
D. One
O
Answers
Answer:
D. One.
Step-by-step explanation:
A poker hand consists of 5 cards dealt from an ordinary deck of 52 playing cards. How many different hands are there consisting of four hearts and one spade?
Answers
Answer:
The answer is 9295
Step-by-step explanation:
Solution
A poker hands contains of =5 cards
Ordinary deck of =52 cards
Now we need to find the number of hands are there consisting of four hearts and one spade
Thus
The number of ways to get 4 hearts = ¹³C₄
=715
The number of ways to get to 1 spade = ¹³C₁
=13
Then
The total number of ways is given as:
715 * 13 =9295
Therefore, the different hands that are available or present consisting of four hearts and one spade is 9295
a normal distribution is observed from the number of insurance claims per month for a certain insurance company. if the mean is 20 claims and the standard deviation is 3 claims, what is the probability that in a randomly selected month, the insurance company's claims are less than 26 claims?
Answers
The probability that in a randomly selected month the insurance company's claims are less than 26 claims is 0.9772 or 97.72%.
To calculate the z-score, we use the formula:
z = (x - μ) / σ
where x is the value we are interested in (in this case, 26 claims), μ is the mean (20 claims), and σ is the standard deviation (3 claims).
Plugging in the values, we get:
z = (26 - 20) / 3
z = 6 / 3
z = 2
Next, we look up the z-score of 2 in the standard normal distribution table. The z-score of 2 corresponds to a probability of 0.9772.
Therefore, the probability that in a randomly selected month the insurance company's claims are less than 26 claims is 0.9772 or 97.72%.
In conclusion, there is a 97.72% probability that in a randomly selected month the insurance company's claims will be less than 26 claims, based on the given mean of 20 claims and standard deviation of 3 claims.
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Can someone help me? I don’t really understand how to do this m
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Answer:
probably about 59 degrees
Step-by-step explanation:
Order the values from least to greatest.
8, |3|, -5, |-2|, -2
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Step-by-step explanation:
-5 , -2, |-2| ,|3|, 8
the absolute value makes the sign positive no matter what, for example |-2| becomes 2