Solve for x. I need help for this.

Answer:

2309

Step-by-step explanation:

V=\(\pi r^{2} h\)

plug in

V=2309.07

Answer:

yes it is correct

Step-by-step explanation:

The relative velocity of one plane with respect to the other plane is given

by the sum of the velocity of the two planes.

Reasons:

The distance between the two airports = 2,400 km

Speed of the plane from NAIA = 800 kilometer per hour

Speed of the plane coming from SIN = 640 kilometers per hour

Let t represent the time after which the two planes meet, we have;

800 × t + 640 × t = 2,400

\(\displaystyle t = \frac{2,400 \ km}{800 \ km/hr + 640 \ km/hr} = \frac{5}{3} \ km/hr = 1.\overline 6 \ km/hr\)

The time after which the two planes meet, t = \(\underline{1. \overline 6 \ km/hr}\)

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To find the equation of the tangent plane to the given equation 2(x-2)^2 (y-1)^2 (z-3)^2=10, we need to find the gradient of the function and use the point-slope form of a plane.

First, we find the gradient of the function by taking the partial derivatives with respect to x, y, and z:

∂f/∂x = 4(x-2)(y-1)^2(z-3)^2

∂f/∂y = 4(x-2)^2(y-1)(z-3)^2

∂f/∂z = 4(x-2)^2(y-1)^2(z-3)

Next, we find the point on the surface where we want to find the tangent plane. For simplicity, let's choose the point (2,1,3), which is on the surface because 2(2-2)^2(1-1)^2(3-3)^2=0=10.

Now we plug in the point into the gradient to find the normal vector to the plane:

∂f/∂x(2,1,3) = 4(2-2)(1-1)^2(3-3)^2 = 0

∂f/∂y(2,1,3) = 4(2-2)^2(1-1)(3-3)^2 = 0

∂f/∂z(2,1,3) = 4(2-2)^2(1-1)^2(3-3) = 0

So the normal vector is <0,0,0>.

Finally, we use the point-slope form of a plane to find the equation of the tangent plane:

0(x-2) + 0(y-1) + 0(z-3) = 0

Simplifying, we get:

0 = 0

This means that the tangent plane is the entire xyz-space, since any point satisfies this equation.

Therefore, the equation of the tangent plane to the given equation at the point (2,1,3) is 0 = 0.

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Answer:

f(x)=2x^2-12x+11

Step-by-step explanation:

f(x)=2(x-3)^2-7

=2(x-3)(x-3)-7

=2(x^2-6x+9)-7

=2x^2-12x+18-7

=2x^2-12x+11

Answer:

5

Step-by-step explanation:

The range is the largest minus the smallest; 6-1= 5

Plss brainliest

First, subtract the minimum from the maximum to find the range

6 - 1 = 5

so your range is 5

Answer:

x=4

Step-by-step explanation:

Because 3x4 = 12, and 12 is the number on the other side of the triangle because the sides are equal.

Hope this helps! :)

Answer:

Your answer is B

Step-by-step explanation:

Answer in image.

Answer:

y = -2x + 7 and y = x - 2

Step-by-step explanation:

2x + y = 7

y = -2x +7

x - y = 2

-y = -x +2

y = x - 2

The convolution integral y(t) = x(t) * h(t) for the given pair of signals x(t) and h(t) can be computed as follows:

y(t) = ∫[x(τ) * h(t - τ)] dτ

1) x(t) = δ(t) and h(t) = δ(t - 2) * (t - 1)

The convolution integral becomes:

y(t) = ∫[δ(τ) * δ(t - τ - 2) * (τ - 1)] dτ

To evaluate this integral, we consider the properties of the Dirac delta function. When the argument of the Dirac delta function is not zero, the integral evaluates to zero. Therefore, the integral simplifies to:

y(t) = δ(t - 2) * (t - 1)

The convolution result y(t) is equal to the shifted impulse response h(t - 2) scaled by the factor of (t - 1). This means that the output y(t) will be a shifted and scaled version of the impulse response h(t) at t = 2, delayed by 1 unit.

In summary, for x(t) = δ(t) and h(t) = δ(t - 2) * (t - 1), the convolution integral y(t) = x(t) * h(t) simplifies to y(t) = δ(t - 2) * (t - 1).

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Answer:

subtract 5 , m=(-15)

Step-by-step explanation:

15-5

=10

n:

5-10

=(-5)

m:

(-5)-10

=(-15)

hope it help

Main Answer:The recurrence relation for the power series solution of the given differential equation is:   a_(n+2) = a_n / (n+2)

Supporting Question and Answer:

How can we find the recurrence relation for the power series solution of a differential equation?

To find the recurrence relation for the power series solution of a differential equation, we can assume the solution can be expressed as a power series and substitute it into the differential equation. By equating the coefficients of like powers of x to zero, we can derive the recurrence relation for the coefficients of the power series. This recurrence relation allows us to express the coefficients in terms of previous coefficients, providing a systematic way to compute the coefficients of the power series solution.

Body of the Solution: To find the recurrence relation for the power series solution of the differential equation y′′(1 - x)y = 0, we can assume that the solution can be expressed as a power series:

y(x) = ∑(n=0)^(∞) a_n x^n

First, to find the first and second derivatives of y(x):

y'(x) = ∑(n=1)^(∞) na_nx^(n-1)

=∑(n=0)^(∞) (n+1)×a_(n+1)×(x)^n

y''(x) =∑(n=2)^(∞) n(n-1)a_nx^(n-2)

= ∑(n=0)^(∞) (n+2)(n+1)×a_(n+2)×(x)^n

Now, substitute these expressions into the differential equation:

∑(n=0)^(∞) (n+2)(n+1)×a_(n+2)×(x)^n× (1 - x) × ∑(n=0)^(∞) a_n x^n = 0

Expand and collect terms:

∑(n=0)^(∞) [(n+2)(n+1)×a_(n+2) - (n+1)×a_n] ×( x)^n - ∑(n=0)^(∞) (n+2)(n+1)×a_(n+2)×(x)^(n+1) = 0

Now, equating the coefficients of like powers of x to zero:

For n = 0:

[(2)(1)×a_2 - (1)×a_0] = 0

a_2 = a_0

For n ≥ 1:

[(n+2)(n+1)×a_(n+2) - (n+1)×a_n] - (n+2)(n+1)×a_(n+2) = 0

a_(n+2) = (n+1)×a_n / ((n+2)(n+1)) = a_n / (n+2)

Final Answer: Hence, the recurrence relation for the power series solution of the given differential equation is:

a_(n+2) = a_n / (n+2);where a_0 is a constant representing the coefficient of x^0 in the power series solution.

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If a dataset is generated with the model of polynomial regression of degree 3 then a polynomial regression model of degree 3 will have low bias and low variance.

The correct statement is d. A polynomial regression model of degree 3 will have low bias and low variance.

The given dataset is generated using a polynomial regression model of degree 3. Hence, a polynomial regression model of degree 3 will perfectly fit the data, leading to low bias and low variance. The degree 3 polynomial will have enough flexibility to capture the underlying non-linear relationships in the data. On the other hand, simple linear regression will not be able to capture the non-linear relationship between the predictor and response variables, resulting in high bias and low variance.

In summary, a polynomial regression model of degree 3 will have the best fit for this dataset, with low bias and low variance, whereas simple linear regression will have high bias and low variance.

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Answer:

c

Step-by-step explanation:

Answer:

yes because the slopes are the negative reciprocal of eachother

Step-by-step explanation:

Answer:

Only one solution (x = 0)

Step-by-step explanation:

From the graph attached,

Parabola in the graph touches the origin.

It doesn't intersect the x-axis.

Therefore, There will be only one root or solution of the given function,

x = 0

The value of "a" is approximately 1.83 given that the absolute value of the difference of the two roots of the quadratic equation "ax squared plus 5x minus 3 equals 0" is the square root of 61 divided by 3, and "a" is positive.

We are given that the absolute value of the difference between the two roots of the quadratic equation "ax squared plus 5x minus 3 equals 0" is the square root of 61 divided by 3, and "a" is positive. We need to find the value of "a".

Let the two roots of the equation be r1 and r2, where r1 is not equal to r2. Then, we have:

|r1 - r2| = √(61) / 3

The sum of the roots of the quadratic equation is given by r1 + r2 = -5 / a, and the product of the roots is given by r1 × r2 = -3 / a.

We can express the difference between the roots in terms of the sum and product of the roots as follows:

r1 - r2 = √((r1 + r2)² - 4r1r2)

Substituting the expressions we obtained earlier, we have:

r1 - r2 = √(((-5 / a)²) + (4 × (3 / a)))

Simplifying, we get:

r1 - r2 = √((25 / a²) + (12 / a))

Taking the absolute value of both sides, we get:

|r1 - r2| = √((25 / a²) + (12 / a))

Comparing this with the given expression |r1 - r2| = √(61) / 3, we get:

√((25 / a²) + (12 / a)) = √(61) / 3

Squaring both sides and simplifying, we get:

25 / a² + 12 / a - 61 / 9 = 0

Multiplying both sides by 9a², we get:

225 + 108a - 61a² = 0

Solving this quadratic equation for "a", we get:

a = (108 + √(108² + 4 × 61 × 225)) / (2 × 61)

Since "a" must be positive, we take the positive root:

a = (108 + √(108² + 4 × 61 × 225)) / (2 × 61) ≈ 1.83

Therefore, the value of "a" is approximately 1.83.

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The question is -

Given that the absolute value of the difference of the two roots of the quadratic equation "ax squared plus 5x minus 3 equals 0" is the square root of 61 divided by 3, and "a" is positive, what is the value of "a"?

Answer:

The answer you've chosen is correct: 14.91cm

Step-by-step explanation:

Answer: 2.25

Step-by-step explanation:

The no-arbitrage price today of a 5-year $1,000 US Treasury note with a 2% coupon rate and a 4.25% yield to maturity is approximately $908.44, closest to option B: $900.53.

To determine the no-arbitrage price of a 5-year $1,000 US Treasury note with a coupon rate of 2% and a yield to maturity (YTM) of 4.25%, we can use the present value of the future cash flows.First, let's calculate the annual coupon payment. The coupon rate is 2% of the face value, so the coupon payment is ($1,000 * 2%) = $20 per year.The yield to maturity of 4.25% is the discount rate we'll use to calculate the present value of the cash flows. Since the coupon payments occur annually, we need to discount them at this rate for five years.

Using the present value formula for an annuity, we can calculate the present value of the coupon payments:PV = C * (1 - (1 + r)^-n) / r,

where PV is the present value, C is the coupon payment, r is the discount rate, and n is the number of periods.

Plugging in the values:PV = $20 * (1 - (1 + 0.0425)^-5) / 0.0425 = $85.6427.

Next, we need to calculate the present value of the face value ($1,000) at the end of 5 years:PV = $1,000 / (1 + 0.0425)^5 = $822.7967.

Finally, we sum up the present values of the coupon payments and the face value:No-arbitrage price = $85.6427 + $822.7967 = $908.4394.

Rounding to the penny, the no-arbitrage price is $908.44, which is closest to option B: $900.53.

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The cost of the utility pole is approximately $593.96.

Volume is a measure of the amount of space occupied by a three-dimensional object. It is usually measured in cubic units such as cubic meters (m³), cubic centimeters (cm³), or cubic feet (ft³). The volume of an object can be found by measuring its length, width, and height and using a formula that relates these dimensions to the amount of space the object occupies. In geometry, the most common shapes for which volume is calculated include cubes, spheres, cylinders, pyramids, and cones.

The volume of a right cylinder is given by the formula V = πr²h, where r is the radius of the base and h is the height.

In this case, the diameter of the utility pole is 1.5 ft, so the radius is 0.75 ft. The height is 45 ft. Therefore, the volume of the utility pole is:

V = π(0.75 ft)²(45 ft) = 23.3826... cubic feet

Rounding to the nearest hundredth, we get:

V ≈ 23.38 cubic feet

The cost of wood per cubic foot is $25.37. Therefore, the cost of the utility pole is:

$25.37/cubic foot × 23.38 cubic feet ≈ $593.96

So the cost of the utility pole is approximately $593.96.

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To calculate the company's annual holding cost, we need to multiply the annual average inventory by the holding cost per unit.

First, we need to calculate the annual average inventory. The formula for the average inventory is (Q/2), where Q represents the order quantity.

Given:

Annual requirements (Demand) = 7500 units

Ordering cost = BD 12

Order quantity (Q) = 150, 300, 45000 (Assuming these are different order quantities)

Holding cost per unit = BD 0.5

For each order quantity, we can calculate the annual average inventory using the formula (Q/2). Then, we multiply the average inventory by the holding cost per unit.

For order quantity Q = 150:

Average Inventory = Q/2 = 150/2 = 75 units

Holding Cost = Average Inventory * Holding cost per unit = 75 * 0.5 = BD 37.5

For order quantity Q = 300:

Average Inventory = Q/2 = 300/2 = 150 units

Holding Cost = Average Inventory * Holding cost per unit = 150 * 0.5 = BD 75

For order quantity Q = 45000:

Average Inventory = Q/2 = 45000/2 = 22500 units

Holding Cost = Average Inventory * Holding cost per unit = 22500 * 0.5 = BD 11250. Now, we sum up the holding costs for each order quantity:

Annual Holding Cost = BD 37.5 + BD 75 + BD 11250 = BD 11362.5 Therefore, the company's annual holding cost is BD 11362.5.

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Answer:

y = x + 5.25

Step-by-step explanation:

y - 8.25 = (x - 3)

y - 8.25 = x - 3

y = x + 5.25

Could you please give me brainliest for this? Thank you!

Answer:

y = x + 5.25

Step-by-step explanation:

y - 8.25 = x - 3    Add 8.25 to both sides of the equation

y = x + 5.25

Answer:

D

Step-by-step explanation:

Hope this helps. Pls give brainliest.

Answer:

3rd one.

Step-by-step explanation:

y intercept is 8.19 That is very close. Also, the slope is positive AND is low incline, which will make it best fit for many points.

The present value of an amount of $3,000 due to be paid in 3 years is equal to an amount, that with accumulated desired interest would grow to be $3,000 three years from now. This is because the present value is the value of the future payment today, after taking into account the time value of money and the interest rate. The answer to this question is C.

To calculate the present value of $3,000 due in 3 years, we need to discount the future payment back to its present value using the interest rate. This means that we need to find an amount that, when invested today at the given interest rate, will grow to be $3,000 in 3 years.

For example, if the interest rate is 5%, the present value of $3,000 due in 3 years would be approximately $2,530. This means that if you invest $2,530 today at 5% interest, it will grow to be $3,000 in 3 years.

Therefore, the correct answer is C, and we need to know the interest rate to calculate the present value accurately. Answer A is incorrect because the expected value of $3,000 does not take into account the time value of money and the interest rate. Answer B is incorrect because the present value should always be less than the future value if the interest rate is greater than zero. Answer D is incorrect because the expected value and the present value are not the same.

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The annual rate of interest is approximately 6.5%.

To find the annual rate of interest, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A is the final amount

P is the principal (initial investment)

r is the annual interest rate (in decimal form)

n is the number of times interest is compounded per year

t is the time in years

In this case, the initial investment (P) is $3200, the final amount (A) is $3343.34, the time (t) is 5 months (which is 5/12 years since we need the time in years), and we need to find the annual interest rate (r).

We can rearrange the formula and solve for r:

r = ( (A/P)^(1/(nt)) ) - 1

Substituting the given values:

r = ( (3343.34/3200)^(1/(1*(5/12))) ) - 1

r ≈ 0.065 or 6.5%

Therefore, the annual rate of interest is approximately 6.5%.

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The solution of the inequality is x<-5/3 or x>2 .

Inequality, a statement expressing the relationship in terms of greater than, greater than or equal to, less than, or less than or equal to.

A relation known as an inequality compares two numbers or other mathematical expressions in an unfair manner. Most frequently, size comparisons are done between two numbers on the number line.

Given inequality is (3x+5)(4x-8)>0

Now for product of two terms to be greater than 0 either both are positive or both are negative.

Therefore using the above property:

(3x+5) > 0 and (4x-8)>0

or, x > -5/3  and x>2

From the above two inequality we can say that x >2

Now for the second condition:

(3x+5) < 0 and (4x-8)<0

or, x <-5/3  and x<2

From the above two inequality we can say that x <-5/3 .

Now we can say that the the required solution of the inequality is

x<-5/3 or x>2

The solution of the second inequality (5-x)(2x+7)(x-3)≤0 is

-7/2 ≤ x ≤ 3 or x ≥ 5 .

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