solve pls brainliest

Answer:

113 feet

Step-by-step explanation:

I will assume you meant h = -4.9t^2 + 135; "t2" is incorrect.

To answer this question, to find the height of the ball after 2.1 seconds, substitute 2.1 for t in the above equation:

h(2.1) = -4.9(2.1)^2 + 135.  This becomes -21.6 + 135, or 113.4.

The closest result to the height of the ball after 2.1 seconds is 113 feet.

(1,2,4)

Range describes the y-values of a graph.

Range

Range is the y-values that a graph covers. Remember that the y-values are found on the vertical axis. If the graph is not continuous, then the values between the points are not included in the range. Similar to the range, the domain of a graph is the x-values that a graph covers. If there is a coordinate point with a y-value, then that y-value should be included in the range.

Finding Range

In order to find the range, we need to find all the unique y-values of the graph. Additionally, the range is given in numerical order. This means starting from the least value and going up to the greatest. The lowest y-value is 1, then 2, and finally 4. Even though there are two points where y = 2, we are only looking for unique values. This means that the range is (1,2,4).

Answer:

hey, what exactly is your question? i don't really get it.

Step-by-step explanation:

In a case whereby the sum of two consecutive numbers is 25 the largest of the consecutive numbers is 13.

Given that sum of two consecutive numbers is 25 , ans we were required to locatye the  largest of the consecutive numbers. The we can represent the consecutive numbers as x and x+1. According to the problem, the sum of these two consecutive numbers is 25:

x + (x+1) = 25

Simplifying the left side of the equation:

2x + 1 = 25

2x = 24

Dividing both sides by 2:

x = 12

So the first consecutive number is 12. The second consecutive number is 12 + 1 = 13. Therefore, the largest of the consecutive numbers is 13.

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We have to solve:

The value of b is b=4.5.

Answer:

The correct answer is C

Step-by-step explanation:

I took the test and got a 100

Answer:

6(3a+7b+1)

Step-by-step explanation:

36a+42v-18a+6
18a+42b+6
GCF=6
6(3a+7b+1)

The factor of the given expression is 6(3a+7b+1).

A factor is a number that divides another number, leaving no remainder.

Given an expression, 36a + 42b - 18a + 6

On factoring, we get,

36a + 42b - 18a + 6

= 18a+42b+6

= 6(3a+7b+1)

Hence, The factor of the given expression is 6(3a+7b+1).

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The expected value of the continuous random variable V is 5. The expected value of V is 5, indicating that, on average, we expect the value of V to be around 5.

To calculate the expected value of a continuous random variable V with a given probability density function (PDF), we integrate the product of V and the PDF over its entire range.

The PDF of V is defined as:

f(v) = 6/24 = 0.25 for 3 ≤ v ≤ 7, and 0 otherwise.

The expected value of V, denoted as E(V), can be calculated as:

E(V) = ∫v * f(v) dv

To find the expected value, we integrate v * f(v) over the range where the PDF is non-zero, which is 3 to 7.

E(V) = ∫v * (0.25) dv, with the limits of integration from 3 to 7.

E(V) = (0.25) * ∫v dv, with the limits of integration from 3 to 7.

E(V) = (0.25) * [(v^2) / 2] evaluated from 3 to 7.

E(V) = (0.25) * [(7^2 / 2) - (3^2 / 2)].

E(V) = (0.25) * [(49 / 2) - (9 / 2)].

E(V) = (0.25) * (40 / 2).

E(V) = (0.25) * 20.

E(V) = 5.

Therefore, the expected value of the continuous random variable V is 5.

The expected value represents the average value or mean of the random variable V. It is the weighted average of all possible values of V, with each value weighted by its corresponding probability. In this case, the expected value of V is 5, indicating that, on average, we expect the value of V to be around 5.

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The probability of student A is 15/44

Given student A is 70% of time and student B is 60% of time

We need to find the probability of student A

Using formula of conditional probability is P(X/Y) = P(X and Y) / P(Y)

Here X = A and Y = A or B

Therefore,

P(A/A or B) = P(A and (A OR B) / P (A or B)

Now, There is none complement for at least 1

We know that Student A attends 70 % of time

So , his absence is 30% of the time .

Hence the probability of absence is 0.3

Now Considering B in the similar way

We get,

Probability of the absence is 0.4

They are both absent (0.3)(0.4)= 0.12

Here we can say that 12 % of time both are absent

So one or another present on that time is 88%

The probability of present of the time is 0.88

Now calculating the probability,

P(A/A or B) = P(A and (A OR B) / P (A or B)

= 0.3/0.88

= 30/88

= 15/44

Hence the Probability Of A is 15/44

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9514 1404 393

Answer:

  $12.50

Step-by-step explanation:

The cost of 5 bags will be 5/3 times the cost of 3 bags:

  5-bag cost = (5/3)($750) = $12.50

Marco would spend $12.50 on 5 bags of cat food.

_____

If you like, you can find the "unit rate" -- the cost of one bag of cat food:

  $7.50 / (3 bags) = $2.50 /bag

Then, multiply that rate by 5 bags:

  (5 bags)($2.50/bag) = $12.50

Note that we have multiplied by 5 and divided by 3, the same as if we had multiplied by 5/3.

Answer:

42.91

Add them together.

Get 42.91

Answer:

See below

Step-by-step explanation:

To convert from Cartesian coordinates \((x,y)\) to polar coordinates \((r,\theta)\), use the following formulas:

\(r=\sqrt{x^2+y^2}\\\theta=tan^{-1}(\frac{y}{x})\)

Reference angles are the acutes angles that the terminal side of \(\theta\) makes with the x-axis.

The covariance of z and w, Cov(z,w), as Cov(z,w) = Cov((y- y)/√S,(y- y)/√S) = Cov(1/√S,1/√S) = 1/S = 0.1135.

(a) Using the data given, we can find the sample mean, variance and correlation coefficient as follows:

The sample mean, y, is given by y = (1/80) * Σyᵢ = 49.45.

The sample variance, S², is given by S² = (1/79) * Σ(yᵢ - y)² = 8.798.

The correlation coefficient, R, is given by R = (1/78) * Σ((yᵢ - y)/S)((yⱼ - y)/S) = 0.987.

(b) We can find the inverse of the sample variance, ISI, as ISI = 1/S = 0.1135. The trace of the sample variance, tr(S), is equal to the sum of the diagonal elements of S, which is tr(S) = S₁₁ + S₂₂ + S₃₃ + S₄₄ = 35.187.

For part 2, (a) we can find the standardized variables z and w as zᵢ = (yᵢ - y)/√S and wᵢ = (yᵢ - y)/√S for i = 1,2,...,80. The variances of z and w are both equal to 1.

(b) We can find the covariance of z and w, Cov(z,w), as Cov(z,w) = Cov((y- y)/√S,(y- y)/√S) = Cov(1/√S,1/√S) = 1/S = 0.1135.

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Complete question:

The data (Elston and Grizzle 1962 in T3_6_BONE on CANVAS) given below consist of measurements yıy2,y3, and y4 of the ramus bone at four different ages on each of 20 boys. (a) Find y, S, and R. (b) Find ISI and tr(S). 02. For the same dataset in question 1, define (a) Find z, w and variances of z and w. (b) Find Cov(z,w).

y1 y2 y3 y4

47.8 48.8 49 49.7

46.4 47.3 47.7 48.4

46.3 46.8 47.8 48.5

45.1 45.3 46.1 47.2

47.6 48.5 48.9 49.3

52.5 53.2 53.3 53.7

51.2 53 54.3 54.4

49.8 50 50.3 52.7

48.1 50.8 52.3 54.4

45 47 47.3 48.3

51.2 51.4 51.6 51.9

48.5 49.2 53 55.5

52.1 52.8 53.7 55

48.2 48.9 49.3 49.8

49.6 50.4 51.2 51.8

50.7 51.7 52.7 53.3

47.2 47.7 48.4 49.5

53.3 54.6 55.1 55.3

46.2 47.5 48.1 48.4

46.3 47.6 51.3 51.8

Answer:

Answer is 116

Step-by-step explanation:

12(10)-4 is 116

Answer:

=116

Step-by-step explanation:

12 x 10 = 120

120 - 4 = 116

Answer:

18

Step-by-step explanation:

remember parenthesis, always first then left to right so 6/2 is 3 +8 is 11 the x 22 is 22 then - 4 is 18 so your answer is 18

Answer:

150

Step-by-step explanation:

mark brainliest plz

A. A sample size of 62 should be taken for a 95% level of confidence.

B. The sample size of 107 should be taken for a 99% level of confidence.

a. To estimate the sample size needed to estimate the mean time a staff member spends with each patient, we can use the formula for sample size calculation:

n = (Z^2 * σ^2) / E^2

Where:

n = required sample size

Z = Z-score corresponding to the desired level of confidence

σ = population standard deviation

E = desired margin of error

For a 95% level of confidence:

Z = 1.96 (corresponding to a 95% confidence level)

E = 2 minutes

σ = 8 minutes (population standard deviation)

Substituting these values into the formula:

n = (1.96^2 * 8^2) / 2^2

n = (3.8416 * 64) / 4

n = 245.9904 / 4

n ≈ 61.4976

Since we can't have a fraction of a sample, we round up the sample size to the nearest whole number. Therefore, a sample size of 62 should be taken for a 95% level of confidence.

b. For a 99% level of confidence:

Z = 2.58 (corresponding to a 99% confidence level)

E = 2 minutes

σ = 8 minutes (population standard deviation)

Substituting these values into the formula:

n = (2.58^2 * 8^2) / 2^2

n = (6.6564 * 64) / 4

n = 426.0096 / 4

n ≈ 106.5024

Rounding up the sample size to the nearest whole number, a sample size of 107 should be taken for a 99% level of confidence.

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The variance of the number of heads that come up when a fair coin is flipped 13 times is 3.25

Mathematical representations of the likelihood of an event occurring or of a statement being true are dealt with in the area of probability. An outcome's probability is a number between 0 and 1, where 1 denotes certainty and 0 denotes the event's impossibility.

Here, flipping a coin is a Bernoulli trial, with n =13, with success as getting a head with probability p = 1/2.

We have to find the variance of the number of success in n Bernoulli trials. The variance of the number of successes in n Bernoulli trials is np(1-p).

the variance np  \((1-p)=13\cdot (1/2)\cdot (1-1/2)=13\cdot (1/2)\cdot (1/2)= 3.25\)

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A new dog park is enclosed by a fence and shaped like a parallelogram. So, the area and perimeter of the dog park is 2125 m² and 202.5 m.

Pictures can be seen in the attachment.

These are the specified parameters:

Coordinate points in the image = (-8, 0), (5, 5), (9, 0), and (-4, -5).

1 unit = 5 m

The area of the parallelogram of the dog park

Triangular base (b) = (9 - (-8)) × 5 m = 85 m

Triangle height (h) = (0 + 5) × 5 = 25 m

A = 2 × 1/2 × b × h

  = 2 × 1/2 × 85 m × 25 m

  = 2125 m²

Perimeter of the dog park

The line a goes through the point (-8, 0) and (5, 5)

a² = (5 - (-8))² + (5 - 0)²

   = 13² + 5²

   = 169 + 25

   = 194

a = √192

a = 13.85

Length a = 13.85 × 5 m = 69.25 m

The line b goes through the point (5, 5) and (9, 0).

b² = (9 - 5)² + (0 - 5²

   = 4² + (-5)²

   = 16 + 25

   = 41

b = √41

b = 6.4

Length b = 6.4 × 5 m = 32 m

Perimeter = 2 × (a + b)

                = 2 × (69.25 m + 32 m)

                = 2 × 101.25 m

                = 202.5 m

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Step-by-step explanation:

Given:

\(\pounds1=1.55 CHF\)

Multiply \(\pounds 145\) by 1.55 to represent 145 pounds in Swiss Frances currency.

\(145 \times 1.55 = 224.75\)

Compare:

\(193.75 < 224.75\)

The watch in Geneva is cheaper.

How Much?

Divide 193.75 CHF by 1.55

\(193.75 \div 1.55 = 125\)

Subtract:

145 - 125 = 20.

The watch is 20 Pounds cheaper.

a. the sampling distribution is  \(\sqrt{[(0.17 \times (1-0.17)) / n]}\)

b. The probability that the sample proportion is within 0.03 of the population proportion is 0.4101.

c. The probability that the sample proportion is within 0.03 of the population proportion for a sample of 200 households is 0.7738.

a. The sampling distribution of the sample proportion, \(\bar p\), can be approximated by a normal distribution with mean equal to the population proportion, p, and standard deviation equal to the square root of \([(p \times (1-p)) / n]\),

where n is the sample size.

Given that p = 0.17 and assuming a large enough sample size, we can use the formula to calculate the standard deviation of the sampling distribution:

Standard deviation = \(\sqrt{[(0.17 \times (1-0.17)) / n]}\)

b. To find the probability that the sample proportion will be within a certain range of the population proportion, we need to calculate the z-score for the lower and upper bounds of that range and then find the area under the normal curve between those z-scores.

Let's say we want to find the probability that the sample proportion is within 0.03 of the population proportion. This means we want to find

P(\(\bar p\)- p ≤ 0.03) = P((\(\bar p\)-- p) / \(\sqrt{[(p \times (1-p)) / n]}\) ≤ 0.03 / \(\sqrt{[(p \times (1-p)) / n]\)

We can use the standard normal distribution and z-scores to find this probability:

\(z_1\) = (0.03 / \(\sqrt{(0.17 \times (1-0.17)/n}\))

\(z_2\) = (-0.03 / \(\sqrt{(0.17 \times (1-0.17))/n}\))

We can find the probability that the z-score is between \(z_1\) and \(z_2\):

P(\(z_1\)≤ Z ≤ \(z_2\)) = P(-0.541 ≤ Z ≤ 0.541) = 0.4101

c. To answer part (c), we need to specify the sample size. Let's say we are taking a sample of 200 households.

Using the formula for standard deviation of the sampling distribution from part (a), we get:

Standard deviation = \(\sqrt{(0.17 \times(1-0.17)) / 200}\) = 0.034

Now we can repeat the same steps as in part (b) with this standard deviation:

\(z_1\) = (0.03 / 0.034)

\(z_2\) = (-0.03 / 0.034)

P(\(z_1\)≤ Z ≤ \(z_2\)) = P(-0.882 ≤ Z ≤ 0.882) = 0.7738

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\(\qquad\qquad\huge\underline{{\sf Answer}}\)

Let's evaluate ~

\(\qquad \tt \dashrightarrow \:(6 \times 1000) + (1 \times 10) + (8 \times \frac{1}{1} ) + (9 \times \frac{1}{10} ) + \frac{4}{100} \)

\(\qquad \tt \dashrightarrow \:6000 + 10 + 8 + \frac{9}{10} + \frac{4}{100} \)

\(\qquad \tt \dashrightarrow \: \dfrac{600000 + 1000 + 800 + 90 + 4}{100} \)

\(\qquad \tt \dashrightarrow \: \dfrac{601894}{100} \)

or

\(\qquad \tt \dashrightarrow \:{6018.94}{} \)

Answer:

12

Step-by-step explanation:

1/5 mint = 6

30 - 6 = 24

Half of 24 is 12

12 is chocolate

so 12 must be vanilla

Answer:

\( Slope (m) = -\frac{3}{4} \)

Step-by-step explanation:

Using any two pairs from the table of values given, (-2, 5) and (2, 2):

\( Slope (m) = \frac{y_2 - y_1}{x_2 - x_1} \)

Where,

\( (-2, 5) = (x_1, y_1) \)

\( (2, 2) = (x_2, y_2) \)

Plug in the value into the slope formula:

\( Slope (m) = \frac{2 - 5}{2 -(-2)} \)

\( Slope (m) = -\frac{3}{4} \)

Answer:

\(y = \frac{3}{2}x - 5\)

Step-by-step explanation:

General format for the slope-intercept form of an equation:

\(y = mx + c\)

where:

m = slope

c = y-intercept

\((x_{1} , y_{1})\) = \((2, -2)\)

\((x_{2} ,y_{2})\) = \((4, 1)\)

m = \(\frac{y_{2} -y_{1}}{x_{2} - x_{1}}\)

   = \(\frac{1- (-2)}{4-2}\)

   =\(\frac{1+2}{2}\)

m = \(\frac{3}{2}\)

Substituting this value of m into our equation:

\(y = \frac{3}{2}x + c\)

Substituting the coordinates of any of the two points into the above equation to solve for c:

1 = \(\frac{3}{2}\)(4) + c

1 = \(\frac{12}{2}\) + c

1 = 6 + c

Isolate c and make it the subject of the equation:

c = \(1 -6\)

c  = \(-5\)

∴The slope-intercept form of the equation after substituting the calculated values of m and c:

\(y = \frac{3}{2}x + (-5)\)

\(y = \frac{3}{2}x - 5\)

Answer:

1/3 * 14/21

=> 14/63

If my answer helped, please mark me as the brainliest!!!

Thank You!!

Answer:

Surveying a group of people standing in line for tickets

Step-by-step explanation:

here the link https://quizizz.com/admin/quiz/5b151fbf90f668001b44cedb/random-sampling

use Quizizz for answers bro

The confidence interval is 0.122<p<0.196

Confidence interval :

A confidence interval (CI) is a range of estimates for an unknown parameter in frequents statistics. The 95% confidence level is the most popular, however other levels, such 90% or 99%, are occasionally used when computing confidence intervals. The percentage of related CIs over the long run that include the parameter's actual value is represented by the confidence level. For instance, 95% of all intervals calculated at the 95% confidence level should include the parameter's actual value. The sample size, sample variability, and confidence level are all variables that have an impact on the CI's width.

Complete question:

Suppose a sample of 208 tankers is drawn. Of these ships, 175 did not have spills. Using the data, construct the 85 % confidence interval for the population proportion of oil tankers that have spills each month. Round your answers to three decimal places.

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if value1 = 2.0 and value2 = 12, then the output of a following command = 24.0

The correct option is A.

The output of the given document is issued is 24.0 (2.0 * 12=24, i.e., it is simply the multiplication operation) if both values, i.e., value 1 and value 2, are taken into consideration as decimal data type values.

There is only one value represented by simple data types. Integer: a basic data type used in the creation of policies. A positive or negative whole number is represented by the integer data type. 0, 1, 2, 3, and 4 are examples of integers.

An attribute of data that instructs a computer system how to interpret its value is called the data type. Knowing the different types of data makes it possible to collect information in the desired format and ensure that the values of each property are as expected.

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I understand that the question you are looking for is:

What is the output of the following command, given that value1 = 2.0 and value2 = 12? print (value+ value2)

A) 24.0

B) value + value2

C) 24

D) 2.0 + 12