Using variation of parameters, the solution to the non-homogeneous differential equation is;
\(y(x) = y_h_(_x_) + y_p_(_x_)\\y(x) = c_1e^(^3^x^) + c_2e^(^-^3^x^) + (-3x - c_3/6 + c_4e^(^3^x^))e^(^-^3^x^).\)
What is the solution of the differential equation?To solve the differential equation y" - 9y = 9x/e³ˣ using the method of variation of parameters, we first find the solution to the associated homogeneous equation y" - 9y = 0.
The characteristic equation is r² - 9 = 0.
Factoring the equation, we have (r - 3)(r + 3) = 0.
This gives us two distinct real roots: r = 3 and r = -3.
Therefore, the general solution to the homogeneous equation is:
y_h(x) = c₁e³ˣ + c₂e⁻³ˣ, where c₁ and c₂ are arbitrary constants.
Next, we assume a particular solution of the form:
y_p(x) = u₁(x)e³ˣ + u₂(x)e⁻³ˣ
To find the values of u₁(x) and u₂(x), we substitute Yp(x) into the original differential equation:
[(u₁''(x)e³ˣ + 6u₁'(x)e³ˣ + 9u₁(x)e³ˣ - 9(u₁(x)e³ˣ + u₂(x)e⁻³ˣ)] - 9[u₁(x)e³ˣ + u2(x)e⁻³ˣ] = 9x/e³ˣ
Simplifying, we get:
u₁''(x)e³ˣ + 6u₁'(x)e³ˣ - 9u₂(x)e^⁻³ˣ = 9x/e³ˣ
To solve for u1'(x) and u2'(x), we equate coefficients of like terms:
u₁''(x)e³ˣ + 6u₁'(x)e³ˣ = 9x/e³ˣ ...eq(1)
-9u2(x)e⁻³ˣ = 0 ...eq(2)
From equation (2), we can see that u₂(x) = 0.
Now, let's differentiate equation (1) with respect to x to find u₁''(x):
u₁''(x) + 6u₁'(x) = 9/e³ˣ.
This is a first-order linear differential equation for u₁'(x). We can solve it by using an integrating factor. The integrating factor is given by;
\(e^(^\int^6 ^d^x^) = e^(^6^x^).\)
Multiplying both sides of the equation by e⁶ˣ, we have:
\(e^(^6^x^)u_1''(x) + 6e^(^6^x^)u_1'(x) = 9e^(^3^x^)/e^(^3^x^).\)
Simplifying further, we get:
\((u_1'(x)e^(^6^x^)^)' = 9.\)
Integrating both sides with respect to x, we have:
u₁'(x)e⁶ˣ = 9x + c₃, where c₃ is the integration constant.
Now, we solve for u₁'(x):
\(u_1'(x) = (9x + c3)e^(^-^6^x^).\)
Integrating u1'(x) with respect to x, we get:
u₁(x) = ∫[(9x + c3)e⁻⁶ˣ] dx.
Integrating by parts, we have:
u₁(x) = (-3x - c3/6)e⁻⁶ˣ + c₄, where c4 is the integration constant.
Therefore, the particular solution is:
Yp(x) = u₁(x)e³ˣ + u₂(x)e⁻³ˣ
\(y_p_(_x_)= [(-3x - c_3/6)e^(^-^6^x) + c_4]e^(^3^x^)\\y_p_(_x_) = (-3x - c_3/6 + c_4e^(^3^x^))e^(^-^3^x^).\)
The general solution to the non-homogeneous differential equation is the sum of the homogeneous solution and the particular solution:
\(y(x) = y_h_(_x_) + y_p_(_x_)\\y(x) = c_1e^(^3^x^) + c_2e^(^-^3^x^) + (-3x - c_3/6 + c_4e^(^3^x^))e^(^-^3^x^).\)
Thus, we have obtained the solution to the differential equation using the method of variation of parameters.
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Which value of x satisfies log3(5x + 3) = 5
To find the value of x that satisfies the equation log₃(5x + 3) = 5, we can use the properties of logarithms. The value of x that satisfies the equation log₃(5x + 3) = 5 is x = 48.
First, let's rewrite the equation using the exponential form of logarithms:
3^5 = 5x + 3
Now we can solve for x:
243 = 5x + 3
Subtracting 3 from both sides:
240 = 5x
Dividing both sides by 5:
x = 240/5
Simplifying:
x = 48
Therefore, the value of x that satisfies the equation log₃(5x + 3) = 5 is x = 48.
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Use the Ratio Test to find the real numbers x for which the series [infinity]Σ xk / k ^6 convergesk=1(Enter your answer using interval notation.)
Using the Ratio Test, the series [infinity]Σ\(x^k / k^6\) converges for x ∈ (-1, 1] and diverges for x ∈ (-∞, -1) ∪ (1, ∞).
To use the Ratio Test, we need to evaluate limit
\(\lim_{k \to \infty} |x^{(k+1)} / (k+1)^6| * |k^6 / x^k|\)
Simplifying, we get
\(\lim_{k \to \infty} |x / (k+1)|^k\)
The series converges if this limit is less than 1, and diverges if it is greater than 1. If the limit is equal to 1, the Ratio Test is inconclusive.
We can rewrite the limit as
\(\lim_{k \to \infty} |(x / k) / (1 + 1/k)|^k\)
As k approaches infinity, 1/k approaches 0, so we can ignore the term 1/k in the denominator
\(\lim_{k \to \infty} |(x / k) / 1|^k\) = \(\lim_{k \to \infty} |x / k|^k\)
Now, we can evaluate the limit based on the value of x
If |x| < 1, then lim |x/k| = 0, so the series converges.
If |x| > 1, then lim |x/k| = infinity, so the series diverges.
If |x| = 1, then the Ratio Test is inconclusive.
Therefore, the series converges for x ∈ (-1, 1] and diverges for x ∈ (-∞, -1) ∪ (1, ∞).
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Subtract: 22²+8242²+122-16
O22²+122-12
4(x+4)(x-1)
O -x²+12x-12
4x(x+4)(x-1)
-2²+6x-6
о 22(x+4)(x-1)
H
-2x²+12-12
2(x+4)(x-1)
=
6-2(x-1)
6
2x(x+4)= 4(x+4)(x-1) = 2z(x+4)-2(x-1)
x.x
4(x+4)(x-1)-
Answer:
the correct answer is the second one
Step-by-step explanation:
I will add a photo of my solution, because there's a lot to type here
suppose you and i play a game where we take turn flipping a coin. the first person to flip heads wins. does it matter who goes first, and if so, would you prefer to go first?
No, it does not matter who will go first as the probability of getting both head and tail after flipping a coin is equal to ( 1 / 2 ).
As given in the question,
Number of players playing the game = 2
Number of coins to flip = One
Possible outcomes after flipping a coin = { Head , Coin }
Probability of getting a head
= (Number of favourable outcomes) / ( Total number of outcomes)
= 1 / 2
Probability of getting a tail
= 1 / 2
Either you tossed first or second chances are fifty percent.
Therefore, it does not matter who will go first as probability of getting head and tail is ( 1 / 2) after flipping a coin.
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ANSWER ASAP PLEASE!!!!!!!!!!!! THANKS!!!!!!!!! :)
Answer: the answer is A
Step-by-step explanation:
The regression line relating verbal SAT scores and college GPA for the data exhibited in Figure 3.12 is
a. Estimate the average GPA for those with verbal SAT scores of 600.
b. Explain what the slope of 0.00362 represents in terms of the relationship between GPA and SAT.
c. For two students whose verbal SAT scores differ by 100 points, what is the estimated difference in college GPAs?
d. Explain whether the intercept has any useful interpretation in the relationship between GPA and verbal SAT score. Keep in mind that the lowest possible verbal SAT score is 200.
(a) The GPA for those with verbal SAT scores of 600 is: 3.097
(b) The slope of 0.00362 represents the average change in the college GPA that is associated with a one-unit increase in the verbal SAT score
a. Estimate the average GPA for those with verbal SAT scores of 600.
The regression line relating verbal SAT scores and college GPA for the data exhibited in Figure 3.12 is y = 0.275 + 0.00362x.
The GPA for those with verbal SAT scores of 600 is:
y = 0.275 + 0.00362(600)
= 3.097
b. Explain what the slope of 0.00362 represents in terms of the relationship between GPA and SAT.
The slope of 0.00362 represents the average change in the college GPA that is associated with a one-unit increase in the verbal SAT score
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a researcher selects a sample and administers a treatment to the individuals in the sample. if the sample is used for a hypothesis test, what does the alternative hypothesis (h1) say about the treatment?
The alternative hypothesis(h1) says that the treatment causes a change in the scores.
What is a hypothesis test?
In statistics, hypothesis testing involves putting an analyst's presumption about a population parameter to the test. The data type used and the study's purpose will determine the methodology the analyst uses.
Using sample data, hypothesis testing determines whether a claim is plausible. These data could originate from a broader population or a process that creates data.
Hence, the alternative hypothesis(h1) says that the treatment causes a change in the scores
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HELP NEEDED ASAP!!!!!
Which point IS a solution?
A: (0,6)
B: (-3,4)
C: (1,0)
D: (-4,3)
Answer: (-3, 4)
Step-by-step explanation:
The point at which both lines intersect is (-3, 4)
And since they intersect at ONE point, it just has one solution.
Hope I helped!
Help me out pleaseeeee
Answer:
C is an obtuse triangle
Step-by-step explanation:
This is because one of the angles measures more than 90 degrees
Hop this helps! Pls mark brainliest if correct:
I NEED HELP WITH THIS EQUATION
Answer:
Hello! answer: 2/5
Step-by-step explanation:
3 ÷ 7 = 0.428571428571
2 ÷ 5 = 0.4
Therefore 3/7 is bigger then 2/5 Hooe that helps!
I need helpppppp!!!!
Answer: I believe yes
Step-by-step explanation:
Im sorry if this isn’t right but I believe it is
Find a polynomial f(x) with leading coefficient 1 such that the equation f(x)=0 and no others. Leave f(x) in factored form rather than multiplying it out. =0 (multiplicity 3), 2-1 (multiplicity 2), 3 (multiplicity 1) has the given roots (6 points)
f(x) can be written as,f(x)=I(x-0)³(x-1)²
Thus, the polynomial in factored form is obtained.
Consider the following equation:
f(x)=(x-0)³(x-1)²
So, the leading coefficient of f(x) is I and the equation f(x) = 0 has roots of 0 with a multiplicity of 3 and 1 with a multiplicity of 2.
Therefore, the polynomial f(x) with leading coefficient I and given roots is f(x)=I(x-0)³(x-1)².
This means that the polynomial is factored form and we don't need to multiply it out.
Given roots of the equation f(x) = 0 are 0 with multiplicity 3 and 1 with multiplicity 2.
So, the factors of f(x) would be (x - 0)³ and (x - 1)².
The equation for f(x) would be, f(x)=I(x-0)³(x-1)²
It can be rewritten as, f(x)=Ix³(x-1)²
So, the leading coefficient is I and the equation f(x)=0 has roots of 0 with a multiplicity of 3 and 1 with a multiplicity of 2.
Therefore, f(x) can be written as,f(x)=I(x-0)³(x-1)²
Thus, the polynomial in factored form is obtained.
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What is the horizontal asymptote of j (x) = startfraction 14 x cubed 45 over 2 x cubed x 9 endfraction y = 1 y = 5 y = 7 y = 12
The horizontal asymptotes the the point where the horizontal line cutes the y-axis. The horizontal asymptotes of the function is y =7
Horizontal asymptotes of a functionThe horizontal asymptotes the the point where the horizontal line cutes the y-axis,
Given the function
j(x) = 14x³+45/2x³+9
Since the powers of both numerator and denominator is the same, we will take the ratio of their coefficient as shown
y = 14/2
y = 7
Hence the horizontal asymptotes of the function is y =7
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The expression 2x - 10 represents the amount of money Mollie pays to buy two movie tickets while using a $10 coupon. What is the coefficient in this expression, and what does it represent in this situation?(A) the number 10 is the coefficient, and it represents the cost of the movie tickets(B) the number 2 is the coefficient, and it represents how many movie tickets Mollie is buying(C) the term x is the coefficient, and it represents the discount for the movie tickets(D) the number -10 is the coefficient, and it represents the number of movie tickets Mollie is buying
In the expression:
\(2x-10\)The coefficient is the number 2, and it is beside x. The number 2 represents the number of tickets Mollie is buying.
The x will represent the money Mollie will need to pay to buy the tickets.
Therefore, the correct option is option B.
PLEEEEEEEEEEEEEEEASSSSEEEE HELP MEE In June, Sherry babysat for 12 out of the 30 days in the month.
Which value is equivalent to the fraction of days she babysat?
it could most likely be 40%? im not sure tho hope this helps
which of the following phrases are equations
This is the rule for how much fabric she needs to buy. • Measure from your waist to the finished length of the pants • Double this measurement • Add 8 inches 1. Amy's measurement from her waist to the finished length of the pants is 35 inches. How many inches of fabric does she need?
Answer:
She needs 78 inches of fabric.
Step-by-step explanation:
The rule for the amount of fabric that needs to be bought is:
\(\text{fabric} = 2*x + 8\)
Where "x" is the distance from the waist to the finished length of the pants. Since Amy's is 35 inches, the amount of fabric is:
\(\text{fabric} = 2*35 + 8\\\text{fabric} = 70 + 8\\\text{fabric} = 78 \text{ inches}\)
She needs 78 inches of fabric.
Can I get help please
The amount of money that I will have at the end of 20 years would be =$4,480. That is option D
What is compound interest?Compound interest is defined as the interest that is being earned on an account which is based on the rate and the time the investment was made.
The total amount invested (p)= $2,000
The rate of investment (r) = 5%
The time of investment(t)= 12 year
The compound interest warm from that account;
= P×T×R/100.
= 2,000×12×5/100
= 120000/100
= $1200
For the next 8 years with the rate of 8% ;
= 2,000×8×8/100
= 128000/100
= $1280
The total compound interest = $1200+$1280= $2,480
Therefore, the amount of money that I will have at the end of 10 years would be = 2000+2480 = $4,480
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A spinner is divided into 8 equal sections: 4 red, 2 white, 1 green, and 1 blue. What is the probability that the spinner lands on blue or white?
Answer:
3/8
Step-by-step explanation:
Total = 8
Probability of blue: 1/8
Probabiity of white: 2/8
Probbility of blue AND white:
1/8 + 2/8
3/8
Answer:
3/8
Step-by-step explanation:
because there are 3 possbile places the spinner can go, and that there are 8 sections, the answer is 3/8
f(x) = x2 + 2x-5
g(x) = -3/2 - 4x + 1
What is f(x) – g(x)?
Step-by-step explanation:
Start by finding (fog)(x)
To find this function, substitute x=
x−1
4
That is g(x) into f(x)
⇒(f∘g)(x)=(
x−1
4
)
2
−2(
x−1
4
)+5
=
(x−1)
2
16
−
x−1
8
+5
Now substitute x=3
⇒(f∘g)(3)=
(3−1)
2
16
−
3−1
8
+5
=
4
16
−
2
8
+5=4−4+5=5.
Hope it helps:)
A school has 6 3/4 kg of detergent in stock. During ' Use Your Hands ' campaign, each class will be given 3/8 kg of detergent. There are 28 classes in the school.
(a) What fraction of the school will be supplied with the detergent in stock?
(b) How much detergent will be required altogether for the whole school?
(c) How much more detergent does the school need to order?
(d) If the school gives out the detergent in stock to the 15 lower secondary classes first,
(i) how much detergent will be given out;
(ii) how much detergent in stock will be left?
Answer:
Step-by-step explanation:
Total stock available = 6 x 3/4 = 18/4
Detergent given to each class=3/8
Total number of classes in the school = 28
Total detergent required by the school=3/8*28
=42/4
a. Fraction if the school who will get the detergent=18/42
b. Total required detergent for the whole school= 42/4
c. School needs to order = 42/4 - 18/4
= 24/4
= 6
d. i. Detergent given out to 15 classes = 15 x 3/8
= 45/8
ii. There will be no detergent left in stock
suppose u is a uniform(0, 1) random variable. consider f-1(u), where f-1(.) is the inverse of the cdf of the random variable x. so, f-1(u) is a transformation of u. assume f-1(.) is strictly increasing. what is the distribution of f-1(u)?
The distribution of the given function is a uniform distribution.
A strictly increasing function is the one which increases continuously in a given interval. If f-1(u) is a strictly increasing function of u, then the distribution of f-1(u) is the same as that of u. This is because a strictly increasing function preserves the rank ordering of its input, so if u-1 and u-2 are two random variables with a uniform distribution on the interval (0,1), then the rank order of f-1(u-1) and f-1(u-2) will be the same as the rank order of u-1 and u-2. Since the uniform distribution is defined by the rank order of its values, this means that the distribution of f-1(u) is also uniform on the interval (0,1).
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Can someone help me please
Answer:12 dollars
Step-by-step explanation:
if u cross multiply u get 12
a street light is at the top of a 18 ft tall pole. a woman 6 ft tall walks away from the pole with a speed of 4 ft/sec along a straight path. how fast is the tip of her shadow moving when she is 45 ft from the base of the pole?
The most appropriate choice for similarity of triangles will be given by -
Speed of tip of the shadow of woman = 6 ft/s
What are similar triangles?
Two triangles are said to be similar, if the corrosponding angles of the triangles are same and the corrosponding sides of the triangles are in the same ratio.
Here,
The diagram has been attached here
Let the distance of woman from the pole be x ft and the distance of tip of the shadow to the pole be y ft.
Height of street light = 18 ft
Height of woman = 6ft
The two triangles are similar [As height of woman is parallel to the height of pole]
\(\frac{y - x}{6}=\frac{y}{18}\\18y - 18x = 6y\\18y - 6y = 18x\\12y = 18x\\y = \frac{18}{12}x\\y = \frac{3}{2}x\\\)
To find the speed, we have to differentiate both sides with respect to time 't'
\(\frac{dy}{dt} =\frac{3}{2}\frac{dx}{dt}\\\frac{dy}{dt}=\frac{3}{2} \times 4\\\frac{dy}{dt} = 6\)
Speed of tip of her shadow = 6 ft
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PLEASE HELP DUE IN AN HOUR NO LINKS PLEASE.
Answer:
y = 3/2 when x = 15
Step-by-step explanation:
y = k / √1+x
2 = k / √1+8 = k/3
k = 6
y' = 6 / √1+15 = 6/4 = 3/2
f(x1, x2) 421 +222 3x² +213 5x11² (√₁+√₂)² 10ln(₁) (x₁+x₂)(x² + x3) min(3r1, 10√2) max{5x1,2r2} MP1(x1, x₂) MP2(X1, X₂) TRS(x1, x₂) Output (2,4)
The given mathematical expression is evaluated for the input values (2, 4). The result of the expression is calculated using various operations such as addition, multiplication, square root, natural logarithm, minimum, maximum, and function composition.
The expression f(x1, x2) involves several mathematical operations. Let's evaluate each part of the expression step by step:
1. The first term is 421 + 222, which equals 643.
2. The second term is 3x² + 213. Plugging in x1 = 2 and x2 = 4, we get 3(2)² + 213 = 3(4) + 213 = 12 + 213 = 225.
3. The third term is 5x11². Substituting x1 = 2 and x2 = 4, we have 5(2)(11)² = 5(2)(121) = 1210.
4. The fourth term is (√₁+√₂)². Replacing x1 = 2 and x2 = 4, we obtain (√2 + √4)² = (1 + 2)² = 3² = 9.
5. The fifth term is 10ln(₁). Plugging in x1 = 2, we have 10ln(2) = 10 * 0.69314718 ≈ 6.9314718.
6. The sixth term is (x₁+x₂)(x² + x3). Substituting x1 = 2 and x2 = 4, we get (2 + 4)(2² + 4³) = 6(4 + 64) = 6(68) = 408.
7. The seventh term is min(3r1, 10√2). As we don't have the value of r1, we cannot determine the minimum between 3r1 and 10√2.
8. The eighth term is max{5x1,2r2}. Since we don't know the value of r2, we cannot find the maximum between 5x1 and 2r2.
9. Finally, we have MP1(x1, x2), MP2(X1, X2), and TRS(x1, x2), which are not defined or given.
Considering the given expression, the evaluated terms for the input values (2, 4) are as follows:
- 421 + 222 = 643
- 3x² + 213 = 225
- 5x11² = 1210
- (√₁+√₂)² = 9
- 10ln(₁) ≈ 6.9314718
- (x₁+x₂)(x² + x3) = 408
The terms involving min() and max() cannot be calculated without knowing the values of r1 and r2, respectively. Additionally, MP1(x1, x2), MP2(X1, X2), and TRS(x1, x2) are not defined.
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Given a sequence of 5 element keys < 23, a) Given the hash function I 38, 27 > for searching task: H(k) = 3, 26, 16, 38, 27NLY mod 11, insert the keys above according to its original sequence (from left to right) into a hash table of 11 slots. Indicate the cases of collision if any. Show your steps and calculations with a table as in our course material. ur steps and calcul
There are two cases of collisions : Key “23” and “27NLY” collide at slot “1”.
Key “27NLY” and “a” collide at slot “(9+L+Y) mod 11”.
Given a sequence of 5 element keys < 23, I 38, 27 >, for searching task: H(k) = 3, 26, 16, 38, 27 mod 11. The steps and calculations are shown in the table below:
Here are the steps to insert the keys into a hash table of 11 slots using the hash function H(k) = 3, 26, 16, 38, 27NLY mod 11:
Key Hash Value Slot
23 23 mod 11 = 1 1
38 38 mod 11 = 5 5
27NLY (3 + 26 + 16 + 38 + (27 * N)
+ L + Y) mod 11 = (86 + N
+ L + Y) mod 11 (86 + N + L + Y) mod 11
N = 13
-> (86 +
N + L +
Y) mod
11= (86
+ 13+ L
+ Y) mod
11 = (99+L
+Y) mod
11 = (9+
L+Y) mod
11 -> Slot:
(9+L+Y)
mod 11
a a mod 11 = a a
The cases of collision are:
Key “23” and “27NLY” collide at slot “1”.
Key “27NLY” and “a” collide at slot “(9+L+Y) mod 11”.
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The product of two consecutive positive odd numbers is 195.By constructing a quadratic equation and solving it, find the two numbers
Please help
Step-by-step explanation:
x = one odd number
the second odd number is (x+2), as both are consecutive.
so,
x × (x + 2) = 195
x² + 2x = 195
x² + 2x - 195 = 0
the formula to solve this is
x = (-b ± sqrt(b² - 4ac))/(2a)
in our case
a = 1
b = 2
c = -195
x = (-2 ± sqrt(4 - 4×1×-195))/(2×1) =
= (-2 ± sqrt(4 + 4×195))/2 = (-2 ± sqrt(784))/2 =
= (-2 ± 28)/2 = -1 ± 14
x1 = -1 + 14 = 13
x2 = -1 - 14 = -15 which is invalid as the numbers are positive.
so, the two numbers are 13 and 15.
Suppose an automobile maker producing a certain kind of car suddenly experiences an increase in the demand for the car. According to our definition of short-run and long-run, in the short run:
In the short run, an automobile maker experiencing an increase in the demand for a certain kind of car will be limited in its ability to adjust its production capacity.
In economics, the short run refers to a period of time during which some factors of production are fixed, while others can be adjusted. In the context of the automobile maker facing increased demand for a specific car, the short run implies that certain aspects of production capacity cannot be changed immediately.
In the short run, the automobile maker may not have the flexibility to expand its production facilities or build new manufacturing plants. This means that the company is constrained by its existing resources and production capacity. Instead, the company can make temporary adjustments to production levels by utilizing existing resources more efficiently, such as adding additional shifts or optimizing the utilization of labor and machinery.
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x + 2y < -2
How do I graph this
Answer:
Put
\(x < - 2 - 2y\)
Then put some of value to y and get x then we can graph it