Solve the equation
4×=68
A.64
B.72
C.12
D.17

The value of x for this problem is given as follows:

x = 5.

Hence the angle measures are given as follows:

We have that angles A and D are congruent for this problem, meaning that they have the same measure.

Hence the value of x is obtained as follows:

7x - 3 = 5x + 7

2x = 10

x = 5.

Hence the angle measures are given as follows:

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Answer:

45

Step-by-step explanation:

5 * 6 = 30$ (the cost of backpacks)

3 * 5 = 15$ (the cost of pens)

15 + 30 = 45

$45

Answer:

I have done it I hope it's the right answer

Given:

Consider the completer question is "Find the derivative \(\dfrac{dy}{dx}\) for \(y=\dfrac{x^2-4x}{x^3-5}\)."

To find:

The derivative \(\dfrac{dy}{dx}\).

Solution:

Chain rule: \(\dfrac{d}{dx}f(g(x))=f'(g(x))\cdot g'(x)\)

Quotient rule: \(\dfrac{d}{dx}\dfrac{f(x)}{g(x)}=\dfrac{g(x)f'(x)-f(x)g'(x)}{[g(x)]^2}\)

We have,

\(y=\dfrac{x^2-4x}{x^3-5}\)

Differentiate with respect to x.

\(\dfrac{dy}{dx}=\dfrac{d}{dx}\left(\dfrac{x^2-4x}{x^3-5}\right)\)

Using chain rule and quotient rule, we get

\(\dfrac{dy}{dx}=\dfrac{(x^3-5)\dfrac{d}{dx}(x^2-4x)-(x^2-4x)\dfrac{d}{dx}(x^3-5)}{(x^3-5)^2}\)

\(\dfrac{dy}{dx}=\dfrac{(x^3-5)(2x-4)-(x^2-4x)(3x^2)}{(x^3-5)^2}\)

\(\dfrac{dy}{dx}=\dfrac{2x^4-4x^3-10x+20-3x^4+12x^3}{(x^3-5)^2}\)

\(\dfrac{dy}{dx}=\dfrac{-x^4+8x^3-10x+20}{(x^3-5)^2}\)

Therefore, the required answer is \(\dfrac{dy}{dx}=\dfrac{-x^4+8x^3-10x+20}{(x^3-5)^2}\).

Answer:

C

Step-by-step explanation:

The first one (0,7) tells you that when x isn't there, the amount of money is 7.

That means that the y intercept is 7.

When x = 1 the total is 15

Money saved = ax + 7

15 = a*1 + 7                         Subtract 7

15-7 = a + 7-7

a = 8

The equation is f(x)  = 8x + 7

The value of y is given as follows:

y = 23.

Hence the angle measures are given as follows:

69º, 23º and 88º.

The sum of the measures of the internal angles of a triangle is of 180º.

The internal angles for the triangle in this problem have the measures given as follows:

Hence the value of y is obtained as follows:

3y + y + 4y - 4 = 180

8y = 184

y = 184/8

y = 23.

Hence the angle measures are given as follows:

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Answer:

120 magazines

Step-by-step explanation:

to get how many 1/7 is you need to divide 120 by 7

210/7=30

now you need to know what 4 sevenths is

30x4=120

so 4/7 of the magazines is 120

(please make sure to rate and thank)

Step-by-step explanation:

\(90 + 90 + 52 + x = 360 \\ x = 360 - 90 - 90 - 52 \\ x = 128\)

The graph shown is a vertical compression and reflection of the graph of y = sin x with an amplitude of 3, period of 2π, phase shift of π/2 units to the right, and a vertical shift of 0. The equation of the graph shown is y = 3 sin (2x - π).

The graph shown appears to be a vertical compression and reflection of the graph of y = sin x. The point indicated on the graph is (π/2, 0), which is the point of maximum compression and reflection for the graph of y = sin x.

To write the equation of the graph shown, we need to determine the amplitude, period, phase shift, and vertical shift of the function.

Amplitude: The amplitude of the graph shown is 3.

Period: The period of the graph shown appears to be 2π.

Phase shift: The phase shift of the graph shown appears to be π/2 units to the right.

Vertical shift: The vertical shift of the graph shown is 0.

Therefore, the equation of the graph shown is:

y = 3 sin (2x - pi)

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--The given question is incomplete, the complete question is given below " 9. The graph shown is a transformation graph of y=sinx. The pointed indicated has coordinates (π/2,0). The equation of the graph shown is y= "--

Answer:

x = 32

Step-by-step explanation:

\(\frac{x-5}{3} = 9\)

x - 5 = 9 × 3

x - 5 = 27

x = 27 + 5

x = 32

Answer:

alr i tried, i hope i got them right! <3 pls let me know if i got them wrong.

1. 108 | 6x12 = 72 9x12 = 108 |

2. 91 | 13x7 = 19

3. 19 | 108/6 90/6 = 19/15 |

4. 50. 400/8 = 50

5. 50. 300/6

hope this helped! <3

Step-by-step explanation:

Answer: 9

Step-by-step explanation:

½bh = 29.25

½ × 6.5 × b = 29.25

B= 29.25/ 3.25

The length of the base of the triangle is 9 centimeters.

The area of a triangle is simply expressed as half base multiplied by height.

Area A = 1/2 × base length × height

Given the dimensions of the triangle:

Area A = 29.25 square centimeters

Height = 6.5 centimeters

Base length =?

To find the height of the triangle, plug the given values into the above formula and solve for h:

Area A = 1/2 × base length × height

29.25  = 1/2 × base length × 6.5

29.25  = base length × 3.25

Base length = 29.25 / 3.25

Base length = 9 cm.

Therefore, the base length measures 9 centimeters.

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For the given circle the circumference is 34.54.

What is circumference?

Circumference is the distance around the edge of a circle or any curved, circular object. It can be thought of as the perimeter of a circle.

The circumference of a circle is given by the formula:

C = πd

where d is the diameter of the circle.

Substituting the given value of the diameter, we get:

C = π(11)

Using π = 3.14, we can evaluate the expression:

C = 3.14(11)

C = 34.54

Therefore, the circumference of the circle is 34.54 (rounded to two decimal places).

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The inequality to determine the number of runs per inning, p Kim's team could have scored is; 4r + 6 > 17

Let r represent the number of runs per inning. Thus for 4 innings, we have 4r.

The team already has 6 runs. Now add the additional runs to this to get;

4r + 6

The team wants to score more than the other team, this means they need more than 17 and so the inequality required is;

4r + 6 > 17

Subtract 6 from each side to get;

4r + 6 - 6 > 17 - 6

4r > 11

Divide both sides by 4 to get:

r > 2.75

Approximating to a whole number gives;

r > 3

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Answer:

6+4p> 17
3

Step-by-step explanation:

a)  If the p-value is less than the chosen significance level, we reject the null hypothesis NH: B5 = 0 and conclude that there is evidence to support the alternative hypothesis AH: ß5 ≠ 0. Otherwise, we fail to reject the null hypothesis.

b)  If the p-value is less than the chosen significance level, we reject the null hypothesis NH: B₂ = 0 and conclude that there is evidence to support the alternative hypothesis AH: B₂ ≠ 0. Otherwise, we fail to reject the null hypothesis.

c) If the p-value is less than the chosen significance level, we reject the null hypothesis NH: B₁ = B₂ = B = 0 and conclude that there is evidence to support the alternative hypothesis AH: Not all 0. Otherwise, we fail to reject the null hypothesis.

We can summarize the three hypothesis tests for the second-order model by following these steps:

1. NH: B5 = 0 vs. AH: ß5 ≠ 0

Perform a t-test to test whether the coefficient B5 is significantly different from zero. The t-test calculates a t-value and p-value associated with the test.

Compute the t-value using the formula: t = (B5 - 0) / SE(B5), where SE(B5) is the standard error of the coefficient B5.

Calculate the p-value associated with the t-value using a t-distribution with appropriate degrees of freedom.

Compare the p-value to the significance level (e.g., α = 0.05) to determine if there is sufficient evidence to reject the null hypothesis.

2. NH: B₂ = 0 vs. AH: B₂ ≠ 0

Perform a t-test to test whether the coefficient B₂ is significantly different from zero.

Compute the t-value using the formula: t = (B₂ - 0) / SE(B₂), where SE(B₂) is the standard error of the coefficient B₂.

Calculate the p-value associated with the t-value using a t-distribution.

Compare the p-value to the significance level to determine the test result.

3. NH: B₁ = B₂ = B = 0 vs. AH: Not all 0

Perform an F-test to test whether all the coefficients B₁, B₂, and B are simultaneously equal to zero.

Compute the F-value using the formula: F = (RSS₀ - RSS) / q / MSE, where RSS₀ is the residual sum of squares under the null hypothesis, RSS is the residual sum of squares from the fitted model, q is the number of coefficients being tested (3 in this case), and MSE is the mean squared error.

Calculate the p-value associated with the F-value using an F-distribution.

Compare the p-value to the significance level to determine the test result.

Performing these hypothesis tests will provide insights into the significance of the respective coefficients in the second-order model.

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Answer:

a = -40

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

Step 2: Subtract 6 from both sides.

Step 3: Multiply both sides by 5.

Therefore, a = -40. I hope this helped you!

Answer:

-40 = a

Step-by-step explanation:

-2=6+a/5

-8 = a/5

(5)-8 = a/5(5)

-40 = a

Answer:

88.7364

Step-by-step explanation:

3.14 TIMES 28.26

Answer:

1 is. $3.84

2 is. $20

3 is. $270

I hope this helps

Answer:

Multiply the angle measure by two.

Step-by-step explanation:

Answer:

you would multiple the angle and measure by two

Answer:

one solution y=1 . x=-3

Step-by-step explanation:

Answer:

b 4 red ribbons/7 blue ribbons

The required ratio of red ribbons to blue ribbons is 4/7 which is the correct answer would be an option (A).

The ratio is defined as a relationship between two quantities, it is expressed as one divided by the other.

We have been given that Morgan won 7 blue ribbons and 4 red ribbons at her horse shows.

We have to determine the ratio of red ribbons to blue ribbons she won

The ratio of red ribbons to blue ribbons is equal to the number of blue ribbons divided by the number of red ribbons.

The ratio of red ribbons to blue ribbons = the number of red ribbons /the number of blue ribbons.

The ratio of red ribbons to blue ribbons = 4 / 7

Thus, the required ratio of red ribbons to blue ribbons is 4/7.

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John Barker's repair shop in Ontario is required to calculate the HST payable or refund for the first reporting period. The HST rate is 13% and the amount before HST sales is $150,000. The total HST collected from sales is $19,500 and the total ITCs are $19,790. The net HST payable/refund is $19,500 - $19,790 and the correct option is d) A refund of $5,980.

Given the following information for John Barker's repair shop in Ontario, we are required to calculate the HST payable or refund for the first reporting period. The HST rate for Ontario is 13%.Amount Before HST Sales $150,000 Equipment purchased $96,000 Supplies purchased $83,000 Wages paid $19,000 Rent paid $17,000Let's calculate the total HST collected from sales:

Total HST collected from Sales= HST Rate x Amount before HST Sales

Total HST collected from Sales= 13% x $150,000

Total HST collected from Sales= $19,500

Let's calculate the total ITCs for John Barker's repair shop:Input tax credits (ITCs) are the HST that a business pays on purchases made for the business. ITCs reduce the amount of HST payable. ITCs = (HST paid on eligible business purchases) - (HST paid on non-eligible business purchases)For John Barker's repair shop, all purchases are for business purposes. Hence, the ITCs are the total HST paid on purchases.

Total HST paid on purchases= HST rate x (equipment purchased + supplies purchased)

Total HST paid on purchases= 13% x ($96,000 + $83,000)

Total HST paid on purchases= $19,790

Let's calculate the net HST payable or refund:

Net HST payable/refund = Total HST collected from sales - Total ITCs

Net HST payable/refund = $19,500 - $19,790Net HST payable/refund

= -$290 Since the Net HST payable/refund is negative,

it implies that John Barker's repair shop is eligible for an HST refund. Hence, the correct option is d) A refund of $5,980.

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Answer:5

Step-by-step explanation:

Answer:

\( \huge\blue{ \mid{ \underline{ \overline{ \tt ♡ ANSWER ♡ }} \mid}}\)

➳ 0.

➳ 18 over 23.

Answer:

0 is the correct answer if you won't understand than contact me

Answer: D

Step-by-step explanation:

The resulting matrix is:

[1 0 2 | -6]

[0 1 1 | 0]

[0 0 0 | 0]

(a) To determine the augmented coefficient matrix for this system, we need to combine the coefficients of the variables with the constants on the right-hand side. The augmented coefficient matrix is formed by arranging these coefficients in a matrix format.

The given linear system is:

x - y + 3z = -2

x + y + 5z = -6

-2x + 3y - 5z = 2

The augmented coefficient matrix can be written as:

[1 -1 3 | -2]

[1 1 5 | -6]

[-2 3 -5 | 2]

(b) To determine the reduced row echelon form of the augmented coefficient matrix, we can use row operations to transform the matrix into a triangular form and then apply back substitution.

Using Gaussian elimination, we can perform row operations to reduce the matrix:

R2 = R2 - R1

R3 = R3 + 2R1

The resulting matrix is:

[1 -1 3 | -2]

[0 2 2 | -4]

[0 1 1 | 0]

Next, we can perform additional row operations to further reduce the matrix:

R2 = R2/2

R1 = R1 + R2

The reduced row echelon form of the augmented coefficient matrix is obtained. From this form, we can deduce the solution to the linear system. The variables x and y have pivot positions, while z is a free variable. Thus, the solution can be expressed as:

x = -6 - 2z

y = -z

This represents the general solution to the given linear system.

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