Steve is mowing a rectangular patch of grass. He knows the length is four times the width. If he knows the perimeter of the patch of grass is 1000ft. What is the length and the width

Answer:

Item price now= 3.95

Step-by-step explanation:

To find out the price now, we will subtract 79 (original price) by 95% of 75. That will equal the discounted price. Finding the percentage of anything, we can use the formula, Total amount•percentage/100. The total amount is 79, and the percentage is 95. 79•95=7505, 7505/100=75.05. Now, 95% of 79 is 75.05, 79-75.05=3.95. $3.95 is the price now of the item. Though, I am unsure what a ALEKS calculator is. Have a nuce time, and joyful day

Answer:

3^30

Step-by-step explanation:

With the "law of exponents, the "power rule" tells you that to raise a power to a power, just multiply the exponents.

Example: (x^m )^n=x^mn  or (x^2 )^3= x^(2∙3)=x^6

When you multiply -6 * -5 = +30

so (3^-6)^-5 = 3^-6*-5 = 3^30

At a temperature of 20°C, the mouse would burn approximately 1,567.44 calories each day.

According to the given model C = 0.37219T + 1,560, where C represents the number of calories an idle mouse burns each day and T represents the temperature of its environment in °C.

To find the most comfortable temperature for an idle mouse, we need to determine the temperature at which the mouse burns the least amount of calories per day.

To find this temperature, we can minimize the equation C = 0.37219T + 1,560. To do so, we take the derivative of C with respect to T and set it equal to zero:

dC/dT = 0.37219 = 0

Solving this equation, we find that the derivative is a constant value, indicating that the function C = 0.37219T + 1,560 is a linear equation with a slope of 0.37219. This means that the mouse burns the least calories at any temperature, as the slope is positive.

Therefore, there is no specific "most comfortable" temperature for an idle mouse in terms of minimizing calorie burn. However, if we consider the range of temperatures mice typically encounter, we can find a temperature where the calorie burn is relatively low.

For example, if we take a temperature of 20°C, we can calculate the calorie burn:

C = 0.37219 * 20 + 1,560

C = 7.4438 + 1,560

C ≈ 1,567.4438 calories per day

Therefore, at a temperature of 20°C, the mouse would burn approximately 1,567.44 calories each day.

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Answer: 17 packs

Step-by-step explanation: 16 packs of 10 equals 160 beads, and one pack of 5 will give you 164 beads with 1 left over.

After considering all the given options we conclude that the number is atleast 21 and the less than 25, which is Option C.

It is given to us that two events are independent if they take place then one event does not trigger the probability of the other event.

Now if the taking place of a certain event triggers the other event then it is referred as dependent

For the given case, we have four events A, B, Q and L.

A = the state when the given number is At least 21

B = is the sate when the given number is Between 12 and 25

Q = is the sate when the given number is Odd

L = is the state when the given number is a Less than 25

It is clearly visible that events A and L are independent due to the number being at least 21, it doesn't affect whether it's less than 25 or not. So, events B and Q are independent because if we know that a number is between 12 and 25, it doesn't affect whether it's odd or not.

Hence, option C) A and L is correct.

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The complete question is

S = [10, 11, 13, 19, 21, 23, 29, 30]

A = The number is At least 21

B= the number is Between 12 and 25

Q = number is Odd

L= number is a Less than 25

Which events are independent.

Question options:

A) A and B

B) A and O

C) A and L

D) Band O

E) Land B

F) Land O

G) None of the 2 events are independent

Hello and Good Morning/Afternoon:

The table shows a linear function:

 \(\hookrightarrow \text{This means that the slope is consistent between all the points}\\\)

Thus we can use any point to help us find our slope:

 \(\hookrightarrow \text{let's pick two points}\)

       \(\hookrightarrow \text{Slope} = \dfrac{y_2-y_1}{x_2-x_1} = \dfrac{16-7}{5-2} =\dfrac{9}{3} =3\)

Answer: 3

Hope that helps!

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Answer:

Step-by-step explanation:

     f(x) = x² - 2x + 5

1)   f(2) = (2)² - 2(2) + 5 = 5

2) f(-3) = (-3)² - 2(-3) + 5 = 20

3)  f(0) = (0)² - 2(0) + 5 = 5

4) f(5) - f(-2) = (5)² - 2(5) + 5 - [(-2)² - 2(-2) + 5 = 20 - 13 = 7

5) f(1) + f(6) = (1)² - 2(1) + 5 + [(6)² - 2(6) + 5 = 4 + 29 = 33

Answer:

Therefore, the earliest time to take the next pill is after 10.85 hours and the latest time is before 15.14 hours have passed.

Step-by-step explanation:

The concentration of the drug in your system after ingesting 100.0 mg can be calculated using the formula:

C = D / V

where C is the concentration, D is the dose, and V is the volume of distribution (assumed to be constant).

At the initial time, t = 0, the concentration is:

C(0) = 100.0 mg / V

After one half-life, t = 16 hours, the concentration is:

C(16) = C(0) / 2 = 50.0 mg / V

After two half-lives, t = 32 hours, the concentration is:

C(32) = C(16) / 2 = 25.0 mg / V

After three half-lives, t = 48 hours, the concentration is:

C(48) = C(32) / 2 = 12.5 mg / V

To find the earliest and latest times to take the next 100.0 mg pill, we need to calculate the concentration at those times and make sure it stays between 20.0 mg and 140.0 mg.

Let's first find the earliest time at which the concentration drops below 20.0 mg.

20.0 mg / V = C(16 + x) = 50.0 mg / V / (2^(x/16))

Solving for x:

2^(x/16) = 50.0 / 20.0 = 2.5

x/16 = log2(2.5)

x = 16*log2(2.5) = 16*0.678 = 10.85

So the earliest time to take the next pill is after 10.85 hours.

Now let's find the latest time at which the concentration goes above 140.0 mg.

140.0 mg / V = C(16 + x) = 50.0 mg / V / (2^(x/16))

Solving for x:

2^(x/16) = 50.0 / 140.0 = 0.3571

x/16 = log2(0.3571)

x = 16*log2(0.3571) = -15.14

So the latest time to take the next pill is before 15.14 hours have passed.

Step-by-step explanation:

(x-2)^2 + (y-9)^2   = r^2

this is of the form fora circle with center  h,k and radius r

(x-h)^2 + (y-k)^2 = r^2

for the equation given   center =   2, 9    and radius = r

The probability that the first plant is daffodil and the second plant is hyacinth is 2/21

Let the number of flowers be denoted as ,

     Number of daffodils, D = 12

     Number of hyacinths, H = 10

     Number of tulips,  T = 14

Total number of flowers = 12 + 10 + 14 = 36

The probability is given as = (Number of favorable outcomes)/(Total number of outcomes)

Thus, the probability of planting daffodils, P(D) = 12/36 = 1/3

          The probability of planting hyacinth, P(H) = 10/35 = 2/7

We have to find the probability that the first plant was daffodils and the second was hyacinth, that is,

           Probability = P(D) * P(H)

                               = 1/3 * 2/7

                                = 2/21

Hence the probability that the first plant is daffodil and the second plant is hyacinth is 2/21

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Answer:

11.53 degrees.

Step-by-step explanation:

ok so we know the hyp and opp sides. this means that it is sin. according to SOHCAHTOA we do sin^-1(2/10). you should get 11.53

Answer:

11.5396°

Step-by-step explanation:

Please see the attached image

We can do sin(x)=2/10, which simplifies to sin(x)=1/5

To get x by itself do \(x=sin^{-1}\)(1/5) which ≈11.5396°

Answer-29 bronze, 46 gold,and 29 silver.

The first thing to do is take 104 and subtract the 17 medal difference between them all. This is 87. Next we divided 87 into three, which gives us 29. Now we have 29 medals for silver, bronze, and gold. However we must add 17 to the gold medals that we took away earlier. 29+17 is 46. To make sure this is correct we can add 29+29+46. This equals 104, which our original answer, so this was correct.

In 2012 the United States earned 29 bronze medals, 46 gold medals, and 29 silver medals.

HOPE THIS HELPS!! GOOD LUCK!!! <3

Unit analysis is a tool that we can use to convert units. It involves multiplying the original number by a fraction to cancel out units.

We're given:

\(\dfrac{3240\hspace{4}feet}{hour}\)

We also know that:

\(\dfrac{hour}{60\hspace{4}minutes}\)

Multiply the two to cancel out the hour:

\(\dfrac{3240\hspace{4}feet}{hour}\times\dfrac{hour}{60\hspace{4}minutes}\\\\=\dfrac{3240\hspace{4}feet}{60 minutes}\)

Simplify:

\(=\dfrac{54\hspace{4}feet}{minute}\)

\(\dfrac{54\hspace{4}feet}{minute}\)

The value of the equation 7/8-1/x=3/4 is 8, so x=8 is the answer.

Two or more expressions with an Equal sign is called as Equation.

The given equation is 7/8-1/x=3/4

Seven divided by eight minus one by x equal to three divided by four.

We have to find the value of x.

Minus is the operator of the equation.

7/8-1/x=3/4

7/8 -3/4 =1/x

LCM of 8 and 4 is 8

7-6 /8 = 1/x

1/8 = 1/x

So value of x is 8

Hence, the value of the equation 7/8-1/x=3/4 is 8, so x=8 is the answer.

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a) P(psychology student)  = 1/3. b) P(psychology or anthropology student)  = 5/6. c) P(not sociology student)= 5/6

(a) The probability of choosing a psychology student is the number of psychology students divided by the total number of students:

P(psychology student) = 4/(6+2+4) = 4/12 = 1/3

(b) The probability of choosing a psychology student or an anthropology student is the sum of the number of psychology and anthropology students divided by the total number of students:

P(psychology or anthropology student) = (4+6)/(6+2+4) = 10/12 = 5/6

(c) The probability of not choosing a sociology student is the number of non-sociology students divided by the total number of students:

P(not sociology student) = (6+4)/(6+2+4) = 10/12 = 5/6

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Answer:

A = 16000(1+0.14)^12 = 77086.4777

Answer:

12 22 23 24 25 26 2u 28 ug6fyd

Note that the probabilities that the engineer will win:

Let's denote the even of winning a contract as W and the event of not winning a contract as NW.

Thus, where we have:

P(W1) =1/2

P (NW1) = 1 - P(W1) = 1-1/2  1/2

P(W2) = 1/3

P(NW2) = 1-P(W2) = 1-1/3 = 2/3

1) To win both contracts, engineer need to have won contracts 1 and 2. Thus,

P(W1 and W2) = P(W1) *P(W2) = (1/2) * (1/3) = 1/6

2) To win only one contract, the engineer can either win contract 1 or contract 2 or vice versa.

Because they are independence,

P((W1 AND NW2) or (NW1 and  W2)) = P(W1 AND NW2) + P(NW1 and W2)

= P(W1) * P(NW2) + P(NW1 * P(W2)
= (1/2) * (2/3) + (1/2) * (1/3)

= 1/2

3) With regard to the contractor winning neighter 1 or 2:

P(NW1 and NW2) = P(NW1) * P(NW2) = (1/2) * (2/3) = 1/3

Hence, it is correct to state that:

that the probabilities that the engineer will win:

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Answer:

  2.908 s

Step-by-step explanation:

The "work" is most easily done by a graphing calculator. We only need to tell it the equation of motion.

For speeds in feet per second, the appropriate equation for vertical ballistic motion is ...

  h(t) = -16t² +v₀t +s₀

where v₀ is the initial vertical velocity in ft/s and s₀ is the initial height in feet. The vertical velocity is the vertical component of the initial velocity vector, so is (65 ft/s)(sin(44°)). We want to find t for h=0.

  0 = -16t² +65sin(44°) +4

Dividing by -16 gives ...

  0 = t^2 -2.82205t -0.2500

Using the quadratic formula, we find ...

  t ≈ (2.82205 ±√(2.82205² -4(1)(-0.25))/2 ≈ 1.41103 +√2.24099

  t ≈ 2.90802

It will take about 2.908 seconds for the discus to reach the ground.

_____

Comment on the question

You're apparently supposed to use the equation for ballistic motion even though we know a discus has a shape that allows it to "fly". It doesn't drop like a rock would.

Answer:

Parallel lines are lines in a plane that are always the same distance apart. Parallel lines never intersect. Perpendicular lines are lines that intersect at a right (90 degrees) angle.

Step-by-step explanation:

hope this helps

Answer:

Parallel lines will continue beside one another forever without ever touching. Perpendicular lines meet at a 90 degree angle forming a T

Step-by-step explanation:

The value x in the secant line using the Intersecting theorem is 4.

Intersecting secants theorem states that " If two secant line segments are drawn to a circle from an exterior point, then the product of the measures of one of secant line segment and its external secant line segment is the same or equal to the product of the measures of the other secant line segment and its external line secant segment.

From the figure:

First sectant line segment = ( x - 1 ) + 5

External line segment of the first secant line = 5

Second sectant line segment = ( x + 2 ) + 4

External line segment of the second secant line = 4

Using the Intersecting secants theorem:

5( ( x - 1 ) + 5 ) = 4( ( x + 2 ) + 4 )

Solve for x:

5( x - 1 + 5 ) = 4( x + 2 + 4 )

5( x + 4 ) = 4( x + 6 )

5x + 20 = 4x + 24

5x - 4x = 24 - 20

x = 4

Therefore, the value of x is 4.

Option C) 4 is the correct answer.

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Using T- ratios, We concluded that the height of the building is 82m.

According to the given question,

the distance between stick and building is 200m,

height of the stick is 2m,

Ami is standing at 5m from the stick,

Let the height of the building = x

So, By observing the pictorial representation of the question through image attached,

And using T - ratios along with

we can conclude that

Tan A = Height of the building / distance between Ami and building

⇒ Tan A = x / 5 + 200                              ......... (1)

Tan A = Height of the stick / Distance between Ami and stick

⇒ Tan A = 2 / 5                                         ............(2)

On equating (1) and (2)

x / 5 + 200  = 2 / 5        

x / 205 = 2/5

x = 2/5 × 205

x = 82

∴ Height of the building is 82m

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Answer:

x = [12]

Step-by-step explanation:

=> \( \frac{x}{6} = \frac{6}{3} \)

=> x = 2 × 6

=> x = 12

Given:

Required: Parametric equation of y.

Explanation:

Substitute 4+t for y into the equation of x.

So, the parametric equation for x is x = 4t+19.

Final Answer: The parametric equation of x is x = 4t + 19.

Answer: e

Step-by-step explanation:

because something scarce means theirs not enough of it for poeple to be pleased with even though it can still be giving by the government. I

Sum

Mean = (4.1 + 3.2 + 2.8 + 2.6 + 3.7 + 3.1 + 9.4 + 2.5 + 3.5 + 3.8) / 10

Mean = 36.7 / 10

Mean = 3.67

To find the median, we need to put the values in order:

2.5, 2.6, 2.8, 3.1, 3.2, 3.5, 3.7, 3.8, 4.1, 9.4

The middle number is the median, which is 3.35 in this case (3.2+3.5)/2.

To find the mode, we look for the value that appears most often. In this case, there is no mode as no value appears more than once.

To find the first quartile (Q1), we need to find the value that separates the bottom 25% of the data from the top 75%. We can do this by finding the median of the lower half of the data:

2.5, 2.6, 2.8, 3.1, 3.2

The median of this lower half is 2.8, so Q1 = 2.8.

To find the third quartile (Q3), we need to find the value that separates the bottom 75% of the data from the top 25%. We can do this by finding the median of the upper half of the data:

3.7, 3.8, 4.1, 9.4

The median of this upper half is 3.95, so Q3 = 3.95.

To find the outlier, we can use the rule that any value more than 1.5 times the interquartile range (IQR) away from the nearest quartile is considered an outlier. The IQR is the difference between Q3 and Q1:

IQR = Q3 - Q1

IQR = 3.95 - 2.8

IQR = 1.15

1.5 times the IQR is 1.5 * 1.15 = 1.725.

The only value that is more than 1.725 away from either Q1 or Q3 is 9.4. Therefore, 9.4 is the outlier in this data set.

Answer:

Step-by-step explanation:

Mean is the average of the data vales : 38.7 (sum of all values) divided by 10 (the number of values).  Mean = 38.7/10 = 3.87

Median is the "middle" number" = put the date in order and find the middle value:

2.5, 2.6, 2.8, 3.1, 3.2, 3.5, 3.7, 3.8, 4.1, 9.4, since there is no middle data value, find the average of the 2 in the middle.

3.2 + 3.5/2 = 6.7 ÷ 2 = 3.35 - median

All values appear once so there is no mode.

First quartile is the middle of the lower set of data = 2.8

Third quartile is the middle of the upper set = 3.8

The outlier is 9.4.

How to calculate the outlier:

First you need the IQR which is the diffence of Q3 - Q1,

so the IQR is 3.8- 2.8 = 1

Outliers are the quartile + or - (1.5)(IQR)

Q1 -(1.5)(1) = 2.8 - 1.5 = 1.3

Q3 - (1.5)(1)= 3.8 + 1.5 =4.5

So anything below 1.3 or above 4.5 is an outlier.

There is one 9.4

f(x)= 2x-1

g(x) = x+4

for (f o g) x on f(x) is replaced by g(x):

(f o g) = 2(x+4)-1

Apply the dsitributive property:

(fo g ) = 2(x)+2(4) -1 = 2x+8 -1 = 2x+7

(f og ) = 2x+7

Using Maxwell's equations, we can determine the magnetic flux density. One of the Maxwell's equations is:

\(\displaystyle \nabla \times \mathbf{H} = \mathbf{J} + \frac{\partial \mathbf{D}}{\partial t}\),

where \(\displaystyle \nabla \times \mathbf{H}\) is the curl of the magnetic field intensity \(\displaystyle \mathbf{H}\), \(\displaystyle \mathbf{J}\) is the current density, and \(\displaystyle \frac{\partial \mathbf{D}}{\partial t}\) is the time derivative of the electric displacement \(\displaystyle \mathbf{D}\).

In this problem, there is no current density (\(\displaystyle \mathbf{J} =0\)) and no time-varying electric displacement (\(\displaystyle \frac{\partial \mathbf{D}}{\partial t} =0\)). Therefore, the equation simplifies to:

\(\displaystyle \nabla \times \mathbf{H} =0\).

Taking the curl of the given magnetic field intensity \(\displaystyle \mathbf{R} =2\cos( 10^{10} t-600x)\hat{a}_{z}\, \text{Am}\):

\(\displaystyle \nabla \times \mathbf{R} =\nabla \times ( 2\cos( 10^{10} t-600x)\hat{a}_{z}) \, \text{Am}\).

Using the curl identity and applying the chain rule, we can expand the expression:

\(\displaystyle \nabla \times \mathbf{R} =\left( \frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial y} -\frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial z}\right) \mathrm{d} x\mathrm{d} y\mathrm{d} z\).

Since the magnetic field intensity \(\displaystyle \mathbf{R}\) is not dependent on \(\displaystyle y\) or \(\displaystyle z\), the partial derivatives with respect to \(\displaystyle y\) and \(\displaystyle z\) are zero. Therefore, the expression further simplifies to:

\(\displaystyle \nabla \times \mathbf{R} =-\frac{\partial ( 2\cos( 10^{10} t-600x)) \hat{a}_{z}}{\partial x} \mathrm{d} x\mathrm{d} y\mathrm{d} z\).

Differentiating the cosine function with respect to \(\displaystyle x\):

\(\displaystyle \nabla \times \mathbf{R} =-2( 10^{10}) \sin( 10^{10} t-600x)\hat{a}_{z} \mathrm{d} x\mathrm{d} y\mathrm{d} z\).

Setting this expression equal to zero according to \(\displaystyle \nabla \times \mathbf{H} =0\):

\(\displaystyle -2( 10^{10}) \sin( 10^{10} t-600x)\hat{a}_{z} \mathrm{d} x\mathrm{d} y\mathrm{d} z =0\).

Since the equation should hold for any arbitrary values of \(\displaystyle \mathrm{d} x\), \(\displaystyle \mathrm{d} y\), and \(\displaystyle \mathrm{d} z\), we can equate the coefficient of each term to zero:

\(\displaystyle -2( 10^{10}) \sin( 10^{10} t-600x) =0\).

Simplifying the equation:

\(\displaystyle \sin( 10^{10} t-600x) =0\).

The sine function is equal to zero at certain values of \(\displaystyle ( 10^{10} t-600x) \):

\(\displaystyle 10^{10} t-600x =n\pi\),

where \(\displaystyle n\) is an integer. Rearranging the equation:

\(\displaystyle x =\frac{ 10^{10} t-n\pi }{600}\).

The equation provides a relationship between \(\displaystyle x\) and \(\displaystyle t\), indicating that the magnetic field intensity is constant along lines of constant \(\displaystyle x\) and \(\displaystyle t\). Therefore, the magnetic field intensity is uniform in the given medium.

Since the magnetic flux density \(\displaystyle B\) is related to the magnetic field intensity \(\displaystyle H\) through the equation \(\displaystyle B =\mu H\), where \(\displaystyle \mu\) is the permeability of the medium, we can conclude that the magnetic flux density is also uniform in the medium.

Thus, the correct expression for the magnetic flux density in the given medium is:

\(\displaystyle B =6\cos( 10^{10} t-600x)\hat{a}_{z}\).

Answer: dale

Step-by-step explanation:

2÷5=0.4(Cups/minute).........dixie

10÷12=0.833∞(Cups/minute)..........dale

0.8333>0.4

Answer:

C and D

Step-by-step explanation:

\(\cos(2x)\\=\cos(x+x)\\=\cos(x)\cos(x)-\sin(x)\sin(x)\\=\cos^2(x)-\sin^2(x)\\=\cos^2(x)-(1-\cos^2(x))\\=2\cos^2(x)-1 \,\,\,\,\,\,\,\,\,\,\leftarrow \text{Option D}\\=2(1-\sin^2(x))-1\\=2-2\sin^2(x)-1\\=1-2\sin^2(x)\,\,\,\,\,\,\,\,\,\,\,\leftarrow \text{Option C}\)