Structure of 4-ethylheptene

Answer:

false

Explanation:

Answer:

false

Explanation:

lava is on the earth

The drink that would typically have the highest concentration of alcohol is hard liquor. Hard liquors are made through the process of distillation, which increases the alcohol content to a higher level.

Hard liquor is defined as liquor with an alcohol content of 30% or more, or 60 proof or higher. This means that they have a higher concentration of alcohol than beer, wine, or other drinks.Liquors are classified into different categories based on their alcohol content, which determines the intensity of their flavors and aromas. Some of the most popular types of hard liquor include whiskey, vodka, rum, gin, tequila, brandy, and cognac.

These liquors are usually consumed in small quantities, and they are often mixed with other ingredients to create cocktails. Their high alcohol content makes them perfect for people who want to drink alcohol without consuming large amounts of liquid.The alcohol content of hard liquor varies depending on the type of liquor and the brand. However, the average alcohol content for most hard liquors is between 35% and 45%. Some of the strongest hard liquors can have an alcohol content of up to 90%. Therefore, it is important to consume hard liquor in moderation to avoid harmful effects on the body.

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The structural formula for ethylene, C₂H₄, and state the type of bonds in an ethylene molecule is 4 single bonds and 1 double bond.

The structural formula for ethylene, C₂H₄, the correct option is 4 single bonds and 1 double bond. The one double bond is present in between the carbon and carbon atom. and the four single bonds are present in between  the carbon atom and the hydrogen atom. the structural formula for ethylene, C₂H₄ :

ethylene, C₂H₄ :  H₂C ≡ CH₂

Thus, The structural formula for ethylene, C₂H₄, and state the type of bonds in an ethylene molecule is 4 single bonds and 1 double bond.

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Answer:

F=Air

Explanation:

Because I took the test hope it helps

Answer: conjugate base of a weak acid

Explanation: If the anion is a conjugate base of a weak acid, the solution would be basic. This is because weak acids do not produce enough hydrogen ions in the solution so does not really affect the acidity, so the conjugate base can react with water in the solution to produce a basic solution.

Answer:

There have been seven horizontal rows of elements are called phases in the periodic table of elements. Groups, or families, are called vertical columns of elements. Metals, – anti, and metals are the most common ways of classifying the periodic table.

Explanation:

Answer:

Shifting their growing range towards the equator

Explanation:

Maybe will be like that

Answer:

Ability to store water in leafy structures to prevent excess evaporation.

Explanation:

The reason why plants die in hot temperature is the excess evaporation of water, so to prevent the excess evaporation of water, the plants get adaptive to store water in their leaves.

Hope it helps.

The number of units of aluminum chloride (AlCl₃) that can be produced from 30 atoms of aluminum (Al) is 30 units

The balanced equation for the reaction is given below:

2Al + 3Cl₂ — > 2AlCl₃

From the balanced equation above,

2 atoms of Al reacted to produce 2 units of AlCl₃.

With the above information, we can determine the number of units of AlCl₃ that can be produced by the reaction of 30 atoms of Al. This can be obtained as follow:

From the balanced equation above,

2 atoms of Al reacted to produce 2 units of AlCl₃.

Therefore,

30 atoms of Al will also react to produce 30 units of AlCl₃.

Thus, 30 units of AlCl₃ were obtained from the reaction.

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If 50 g of potassium nitrate is added to 100 g of water at 30 degrees Celcius, 30 gram of potassium nitrate will not dissolve.

A solubility curve is a curve that is produced when the amount of solute that dissolves in a given volume of solvent is plotted against the temperature of the solution formed.

A solubility curve can be used to predict the amount of a given solute that will dissolve in a given amount of solvent at a particular temperature.

The solubility curve of potassium nitrate is shown in the attachment.

At 30°C, the solubility of potassium nitrate is 20 g/100 g of water.

Hence, the amount of potassium nitrate that will remain undissolved when 50 g of it is added to 100 g of water at 30°C will be:

Amount left undissolved = 50 - 20 g

Amount left undissolved = 30

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The total mass of the products is 853.8 g.

We know that we have to apply the principles of stoichiometry so as to be able to obtain the mass of the mass of the products and then the total mass of the products that is obtained in the reaction.

We have that in the question; 496. 5 grams of lead II nitrate reacts with potassium bromide is such a way that the lead II nitrate would be completely consumed in the reaction. This means that the lead II nitrate is the limiting reactant in the reaction.

Number of moles of the lead II nitrate = 496. 5 grams /331 g/mol

= 1.5 moles

If 1 mole of  lead II nitrate produces 1 mole of lead II bromide

Mass of lead II bromide produced = 1.5 moles * 367 g/mol

= 550.5 g

If 1 mole of lead II nitrate produces 2 moles of potassium nitrate

1.5 moles of lead II nitrate produces  1.5 * 2 /1

= 3 moles of  potassium nitrate

Mass of  potassium nitrate = 3  moles * 101.1

= 303.3 g

Total mass produced = 550.5 g + 303.3 g

= 853.8 g

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The heat required to raise the temperature of 8.75 g of water from its melting point to its boiling points is 3.662 kJ.

The amount of heat required to increase the temperature of one gram of a material by one degree Celsius (°C) is defined as specific heat.

The equation q = mcΔt can be used to compute the amount of heat acquired or lost by a specific heat (q), where m is the mass of the sample, c is the specific heat, and Δt is the temperature change.

Given:

m = 8.75

c = 4.186 J/g°C

The melting point and boiling point of water is 0° and 100° respectively.

Δt = 100° - 0° = 100°

We know that,

q = mcΔt

  = 8.75(4.186)100

  = 3.662 kJ

Thus, the heat required to raise the temperature of 8.75 g of water from its melting point to its boiling points is 3.662 kJ.

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Explanation:

(a):their malleability:

>iron making. iron worker heat the meat and hammer it to give them the desired shape.

> in the jewelry making process, like the gold or silver you wear are results due to the malleability of metal

(b):their ductility:

>for the making of high tension cable that connects different cities for transferring of electricity.

>for making wire gauze

(c):their ability to conduct electricity:

>for lighting up your house with light bulbs

>for using cooking stoves

>to make refrigerator work.

Answer:

a)gold and silver-used to make jewellery

b)gold and copper(we draw them in wires easily because they are not brittle)

c)copper and iron(this is because both of them are metal and metaps are best conductors of electricity)

Explanation:

uses of copper- to make utensils

to make wires for circuits

uses of silver-to make jewellery

to make mirrors

malleability is the property of a meta in which the metal can be changed into different shapes.

Ductility-can be drawn into thin wires.

Answer:

\(NaSO_{4}\)

Explanation:

Asúmase que existen 100 gramos de compuesto, las cantidades molares de cada componente son, respectivamente: (Let assume that exist 100 grams of the composite, the molar quantities of each component are, respectively:)

Na

\(n = \frac{19.3\,g}{22.99\,\frac{g}{mole} }\)

\(n = 0.839\,moles\)

S

\(n = \frac{26.9\,g}{32.065\,\frac{g}{mole} }\)

\(n = 0.839\,moles\)

O

\(n = \frac{53.8\,g}{15.999\,\frac{g}{mole} }\)

\(n = 3.363\,moles\)

La fórmula molecular empírica es (The empirical molecular formula is):

\((Na_{0.839}S_{0.839}O_{3.363})_{1.192}\)

\(NaSO_{4}\)

Answer:

Food in the stomach that is high in protein will dilute absorption of alcohol in your stomach :) therefore always drink with food in your stomach, just drinking alchol without food will have serious consequences on helath.

Explanation:

The solubility constant is\($6.4 \times 10^{-9}$\).

The equilibrium for the solubility of the salt, \($\mathrm{MgF}_2$\) is,

\($$\mathrm{MgF}_2(s) \stackrel{\mathrm{H} \cdot \mathrm{O}}{\rightleftharpoons} \mathrm{Mg}^{2+}(a q)+2 \mathrm{~F}^{-}(a q)$$\)

The solubility product constant for \($\mathrm{MgF}_2$\) is,

\($$K_{\text {吶 }}=\left[\mathrm{Mg}^{2+}\right]\left[\mathrm{F}^{-}\right]^2$$\)

The molar solubility of \($\mathrm{MgF}_2$\) is taken as x, the x moles of \($\mathrm{MgF}_2$\)is dissolved in one litre water to produce x moles of \($\mathrm{Mg}^{2+}$\)and 2x moles of \($\mathrm{F}^{-}$\).

\($\begin{array}{lccc} & \mathrm{MgF}_2(s) & \stackrel{\mathrm{H}_2 \mathrm{O}}{\rightleftharpoons} \mathrm{Mg}^{2+}(a q)+2 \mathrm{~F}^{-}(a q) \\ \text { Initial } & x & 0 & 0 \\ \text { Change } & & +x & +2 x \\ \text { Equilibrium } & x & 2 x\end{array}$\)

The solubility product constant for\($\mathrm{MgF}_2$\) is,

\($$\begin{aligned}K_{u p} &=\left[\mathrm{Mg}^{2+}\right]\left[\mathrm{F}^{-}\right]^2 \\&=(x)(2 x)^2 \\&=4 x^3\end{aligned}$$\)

Substitute the solubility of \($\mathrm{MgF}_2$\) as \($1.17 \times 10^{-3} \mathrm{~mol} / \mathrm{L}$\)in the above equation as shown below:

\($$\begin{aligned}K_{i p} &=4 x^3 \\&=4\left(1.17 \times 10^{-3}\right)^3 \\&=6.41 \times 10^{-9}\end{aligned}$$\)

The solubility constant is \($6.4 \times 10^{-9}$\).(using 2 significant figures).

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Answer:

A volumetric pipette is used to measure 25.0cm3 of 2.0mol/dm3 aqueous sodium hydroxide into aconical flask.

A burette is filled with dilute sulfuric acid.

Write a balanced symbol equation for the reaction between these chemicals when we neutralise.

Explanation:

The reactants of the given reaction are:

sodium hydroxide and dilute sulfuric acid.

The balanced chemical equation of the reaction is:

\(H_{2}SO_{4} (aq) + 2NaOH(aq) -> Na_{2} SO_{4} (aq)+ 2H_{2} O(l)\)

Acid and base raect with each other and form salt and water.

This reaction is called a neutralization reaction.

Answer:

1-T

2-F

3-T

4-T

Explanation:

big brain

Hydrogen breaks down relatively fast in the atmosphere. In the presence of sunlight, hydrogen breaks down within a few years. However, in the absence of sunlight, it can take up to a decade (10 years) for hydrogen to break down in the atmosphere.

Hydrogen is the first element in the periodic table with the symbol H. It is the most abundant element in the universe, but it is rarely found in its elemental form on Earth. It is often found combined with other elements such as oxygen and carbon. Hydrogen is a colorless, odorless, and highly flammable gas. It is used in a variety of applications, such as fuel for vehicles, electricity production, and chemical manufacturing.

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The pressure of the gas when the temperature decreased to 159c is calculated as 1.069 atm.

Sum of the forces of all the molecules striking the wall is divided by area of the wall to give pressure. Pressure of a gas is a measure of the average linear momentum of the moving molecules of gas.

Given, V= 1250 L, T1 = 683 °C= 683 + 273= 956 K

P1= 241 kPa= 2.37atm

P₁ V = n R T₁

n= P₁ V/R T₁

= (2.37 * 1250)/( 0.0821 * 956)

n= 37.7

P₂V = n RT₂

Given T₂= 159 °C = 159 +273 = 432 K

P₂ = n RT₂/V

P₂= 37.7 * 0.0821 * 432/1250

Pressure, P₂= 1.069 atm

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Answer: 2/3

Explanation:

Answer:

This is probably too late but the answer is 351

Explanation:

0.73x751=548.23

After getting both new pressure and new volume and having only one original pressure which is 1.56 you´ll have to divide 548.23 by 1.56 and you´ll end up with 351 which should be the original volume.

An unknown salt, M2Z, has a Ksp of 3.3 x 10⁻⁹, the solubility in mol/L of M2Z is option d. 3.7 x 10⁻⁵ M

The solubility product constant, Ksp, is a measure of the solubility of a sparingly soluble salt in water. When the Ksp value of a salt is known, we can use it to calculate the solubility of the salt in water. In this case, we are given the Ksp of an unknown salt, M2Z, and we are asked to calculate its solubility in mol/L.

The general equation for the dissolution of a sparingly soluble salt, M2Z, in water is:

M2Z(s) ⇌ 2M+(aq) + Z2-(aq)

The Ksp expression for this reaction is:

Ksp = [M+ ]2 [Z2- ]

where [M+ ] is the molar concentration of the cation and [Z2- ] is the molar concentration of the anion.

Since the salt is sparingly soluble, we can assume that its solubility is x mol/L. At equilibrium, the concentrations of the cation and the anion in the solution are also equal to x mol/L. Substituting these concentrations into the Ksp expression, we get:

Ksp = (2x)2 (x) = 4x3

Solving for x, we get:

x = (Ksp/4)1/3

Substituting the given Ksp value into the equation, we get:

x = (3.3 x 10⁻⁹ / 4)1/3

x ≈ 3.7 x 10⁻⁵ M

Therefore, the correct answer is option d. 3.7 x 10⁻⁵ M.

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Answer

moles = 5.81 mol

Explanation

Given:

Volume = 144 L

AT SATP

1 mole = 24.4651 L

Solution:

1 mole = 24.4651 L

x mole = 144 L

x = 144/24.4651

x = 5.8 mol

Answer:

first identify the cation and write down its symbol and charge. Then, identify the anion and write down its symbol and charge.

Explanation:

The enthalpy change (ΔHrxn) for the given reaction, 2CdS(s) + 3O2(g) → 2CdO(s) + 2SO2(g), can be calculated by utilizing the known enthalpy changes of the provided reactions and applying Hess's Law. The final result is ΔHrxn = -1255.4 kJ.

To calculate the enthalpy change for the given reaction, we can break it down into a series of steps using the given reactions and their respective enthalpy changes:

1. Reverse the first reaction (2H2S(g) + 3O2(g) → 2S(s,rhombic) + 2H2O(g)) and multiply it by 2 to obtain 4H2O(g) and 4S(s,rhombic). This requires reversing the sign of the enthalpy change, resulting in ΔH1 = -2(-442.4 kJ) = 884.8 kJ.

2. Multiply the second reaction (2S(s,rhombic) + 2O2(g) → 2SO2(g)) by 2 to obtain 4SO2(g). This gives ΔH2 = 2(-296.8 kJ) = -593.6 kJ.

3. Multiply the third reaction (CdS(s) + O2(g) → CdO(s) + SO2(g)) by 2 to obtain 2CdO(s) and 2SO2(g). This gives ΔH3 = 2(-124.7 kJ) = -249.4 kJ.

Now, sum up the enthalpy changes of these individual steps to obtain the overall enthalpy change for the given reaction:

ΔHrxn = ΔH1 + ΔH2 + ΔH3 = 884.8 kJ + (-593.6 kJ) + (-249.4 kJ) = -1255.4 kJ.

Therefore, the enthalpy change (ΔHrxn) for the given reaction is -1255.4 kJ.

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The classification of the given compounds is as follows:

(a) lactose (C₁₂​H₂₂​O₁₁​) - non-electrolytes

(b) lactic acid (HC₃​H₅​O₃​) - weak electrolytes

(c) dimethylamine [(CH₃​)₂​NH] - weak electrolyte

(d) barium hydroxide Ba(OH)₂ - strong electrolytes

Electrolytes are substances that when in the molten or solution state conduct electricity and are decomposed by the direct current passing through them.

Electrolytes dissociate into the component ions when they are dissolved in water or in molten form. Some examples of electrolytes are acids and bases.

Strong electrolytes dissociate completely into one while weak electrolytes dissociate partially.

Non-electrolytes do not dissociate into ions in solution but remain as molecules. Some example of non-electrolytes is organic solvents.

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The gas exerts a pressure of 133.33 kPa on the walls of the 3 liter which is calculated by using the expression of Boyle’s law.

A fixed amount of a gas occupies a volume of 1l and exerts a pressure of 400 kPa on the walls of its container.

Initial volume (V1) is 1L

Initial pressure (P1) is 400 kPa

Final volume (V2) is 3L

Boyle's law explains the absolute pressure and volume of a given mass of confined gas are inversely proportional while the temperature remains unchanged within a closed system.

According to the Boyle’s law,

        P1V1 = P2V2

        ⇒ P2 = (P1V1)/V2

Putting all tte values we get,

            P2 = (1L * 400 kPa / 3L )

                 = 133.33 kPa

So we get the gas exerts a pressure of 133.33 kPa on the walls of the 3 liter.

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Gravity, as a fundamental force of nature, is influenced by several factors. The following are some of the key factors affecting gravity: