The best test of whether potential entry is a strong or weak competitive force is whether - the number of entry barriers. - a majority of the existing industry members have earned a profit for 3 consecutive years.- the industry's growth and profit prospects are strongly attractive to potential entry candidates.- buyer loyalty to existing brands is high or low. - capital requirements for new entrants are high or low.

Answer:

Simplified it would be 11x^2y^2 - 4xy^

Answer:

11x²y³ - 4xy²

Step-by-step explanation:

is the answer if simplified.

The length of a rock song, including 3.5 minutes, is better classified as discrete data since it consists of distinct, separate values rather than a continuous range of values.

The length of a rock song, such as 3.5 minutes, is actually considered to be from a discrete data set, not a continuous one.

Discrete data refers to values that can only take on specific, separate values within a given range. In the case of the length of a rock song, it is typically measured in whole numbers or specific increments (e.g., 3 minutes, 4 minutes, etc.). While it is possible to have decimal values for song lengths, like 3.5 minutes, they are not as common and usually represent exceptions rather than the norm.

Therefore, the length of a rock song, including 3.5 minutes, is better classified as discrete data since it consists of distinct, separate values rather than a continuous range of values.

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In AAA (Angle-Angle-Angle), triangles do not have the same size and only have 3 pairs of congruent angles.

In SSS (Side-Side-Side), if the three sides of one triangle are equal to the three sides of another triangle, the triangles are congruent.

Answer:

80 degrees

Step-by-step explanation:

angle 1 is equal to 100 because of the law of exterior angles. And since andgle 1 and 2 make 180 degrees we can subtract 80 from 100 and we get the measure of angle 2. Angle 2 and 4 are the same becasue of the law of adjacent angles.

Answer:

Stefanie bought 10 erasers.

Step-by-step explanation:

Stefanie bought a package of pencils for $1.75 and some erasers that cost $0.25 each. She paid a total of $4.25 for these items.

Beind "x" be the number of erasers bought, you can express Stepanie's purchases by the equation:

1.75 + 0.25*x = 4.25

Solving:

0.25*x = 4.25 - 1.75

0.25*x = 2.5

x= 2.5÷ 0.25

x=10

Stefanie bought 10 erasers.

Answer:

10 erasers

Step-by-step explanation:

Answer:

6

Step-by-step explanation:

The prime factorization of 12x is 3*2*2x. The prime factorization of 18 is 2*3*3. The same thing that appears in both prime factorizations is 3*2, or 6.

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Answer:

should be 6cm

Step-by-step explanation:

if you are looking at a cube

Answer:

6 cm 2

Step-by-step explanation:

Surface area of a cube then 1 x 1 x 1 x 6 (6 faces )

The location of point N is -20.

We  can see a number line with 3 points.

Here we know taht MN is 2/7 of MP, so first let's find the length of MP.

The length is equal to the difference between the two values, we can see that:

P = -5

M = -26

Then the length of MP is:

-5 - (-26) = 21

And MN is 2/7 of that, then:

(2/7)*21 = 2*3 =6

Then we can write:

N - M = 6

N - (-26) = 6

N = 6 - 26 = -20

The location of N is -20.

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Is this the answer you were looking for?

√25=5 and −√25=−5 since 52=25 and (−5)2=25 . The principal square root of 25 is √25=5 .

I hope this helped. Comment if it did.

To find the distance from point P to line AB, we can use the formula for the distance between a point and a line. In this case, line AB can be represented by two points A(-4,0) and B(-1,-3).

The formula for the distance between a point (x1, y1) and a line represented by two points (x2, y2) and (x3, y3) is: Distance = |(x2 - x1)(y3 - y1) - (x3 - x1)(y2 - y1)| / √((x2 - x1)^2 + (y2 - y1)^2). Using the coordinates of point P(2, 2) and line AB points A(-4,0) and B(-1,-3), we can calculate the distance: Distance = |(-4 - 2)(-3 - 2) - (-1 - 2)(0 - 2)| / √((-4 - 2)^2 + (-1 - 2)^2). Simplifying the expression: Distance = |-6 - (-3) - (-3 - 4)| / √((-6)^2 + (-3)^2). Distance = |-6 + 3 + 7| / √(36 + 9). Distance = |4| / √(45). Distance = 4 / √45= 0.6.

Approximating the value to the nearest tenth: Distance ≈ 0.6. Therefore, the distance from point P(2, 2) to line AB, rounded to the nearest tenth, is approximately 0.6 units.

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Answer:

14\(y^2+35y^12-6y^11-15y^10\)

Step-by-step explanation:

Simply by distributing 5y^4 to the first two terms and then distribute 2y^5 to the same two terms and then add the like terms.

Answer:

80 divded by 10 is c c=8

True, ANOVA has three different degrees of freedom: DF total (n-1), DF within (n-k), DF between (k-1).

ANOVA (Analysis of Variance) is a statistical method used to compare means between two or more groups. It partitions the total variability in the data into different sources of variation, namely the variability within groups and the variability between groups. In ANOVA, there are three different degrees of freedom associated with these sources of variation: DF total, DF within, and DF between.

DF total represents the total number of observations minus one (n-1). It reflects the total variability in the data set and is used to calculate the overall mean square.

DF within represents the degrees of freedom associated with the variability within each group. It is calculated as the total number of observations minus the total number of groups (n-k), where k is the number of groups. DF within is used to calculate the within-group mean square, which is a measure of the variability within each group.

DF between represents the degrees of freedom associated with the variability between groups. It is calculated as the total number of groups minus one (k-1). DF between is used to calculate the between-group mean square, which is a measure of the variability between the group means.

Therefore, the statement that ANOVA has three different degrees of freedom: DF total (n-1), DF within (n-k), DF between (k-1) is true. These degrees of freedom are crucial in determining the statistical significance of the ANOVA results and conducting hypothesis tests.

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This is the dual problem corresponding to the given primal LP problem.

To find the dual problem of the given linear programming (LP) problem, we need to follow these steps:

Step 1: Convert the LP problem to standard form.

The given LP problem is already in standard form.

Step 2: Identify the decision variables.

The decision variables in the primal problem are y1, y2, and y3.

Step 3: Write the objective function and constraints of the primal problem in matrix form.

The objective function: Minimize 6y1 + 3y3 can be written as:

Minimize c^T*y, where c = [6, 0, 3] and y = [y1, y2, y3]^T.

The constraints:

y1 - 3y3 = 30 can be written as:

Ay = b, where A = [1, 0, -3] and b = [30].

6y1 - 3y2 + y3 ≥ 25 can be written as:

Ay ≥ b, where A = [6, -3, 1] and b = [25].

3y1 + 4y2 + y3 ≤ 55 can be written as:

Ay ≤ b, where A = [3, 4, 1] and b = [55].

Step 4: Transpose the matrices A, c, and b.

Transpose A to obtain A^T, transpose c to obtain c^T, and transpose b to obtain b^T.

A^T = [1, 6, 3; 0, -3, 4; -3, 1, 1]

c^T = [6, 0, 3]

b^T = [30, 25, 55]

Step 5: Write the dual problem using the transposed matrices.

Maximize b^T * u, subject to A^T * u ≤ c^T and u unrestricted in sign.

The dual problem for the given primal problem is:

Maximize 30u1 + 25u2 + 55u3

subject to:

u1 + 6u2 + 3u3 ≤ 6

-3u2 + u3 ≤ 0

u1 + 4u2 + u3 ≥ 3

u1, u2 unrestricted in sign, u3 ≤ 0

This is the dual problem corresponding to the given primal LP problem.

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at (4,0), the multiplicity of zero will be even.

because the graph bounces off the x-axis and doesn't go through it, this means that the multiplicity there is even.

an odd multiplicity would look like the graph going through that x-intercept.

hope this helped! best of luck

The formula for the n-th term is:

aₙ = 3*(1/2)⁽ⁿ⁻¹⁾

For a geometric sequence where the first term is a₁ and the common ratio is r, the formula for the n-th term is:

aₙ = a₁*(r)⁽ⁿ⁻¹⁾

Here we know that the first term is a₁ = 3 and the common ratio is r = 1/2.

Then the formula for the n-th term of the sequence is:

aₙ = 3*(1/2)⁽ⁿ⁻¹⁾

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The domain of a function is the set of numbers that can go into a given function.

The set of input values (x) for which a function generates an output value is known as the domain of the function (y).

we can write \(y = f(x).\)

domain is the full set of x-values that can be plugged into a function to produce a y-value.

The most effective approach to finding a domain will depend on the type of function.

The domain is expressed using an open bracket or parenthesis, the domain's two endpoints separated by a comma, and then a closed bracket or parenthesis.

To find domain of function we should know the property of that function like what the function can take inside it.

Like if we consider square root function \(\sqrt{x}\) so inside root negative numbers are not allowed so value of x should be positive means x>=0

So domain of square root function [0, ∞).

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Answer:

a. True

b. True

c. True

d. False

e. False

I hope this helped! Thank You!

Answer:

a. False

b. True

c. True

d. False

e. False

The number of people are 72.

Highest Common Factor is the full name for HCF in mathematics.

According to the laws of mathematics, the highest positive integer that divides two or more positive integers without leaving a residual is known as the greatest common divisor, or gcd.

Least Common Multiple is the full name for LCM in mathematics.

LCM (a,b) in mathematics stands for the least common multiple, or LCM, of two numbers, such as a and b. The smallest or least positive integer that is divisible by both a and b is known as the LCM.

We need to know the size of the pieces in order to calculate how many people can be fed equal-sized pieces of cake from a 16 by 18-inch cake.

Assume that each piece is a square with sides measuring "x" in length. Each piece's area would be x², and the cake's overall area would be 16 x 18 inches, or 288 square inches.

We must divide the entire area of the cake by the area of each piece to determine the maximum number of pieces that can be cut from the cake:

288 / x² = (16*18) / x² = 288 / x²

Choosing a "x" value that evenly splits into 16 and 18 is necessary if we want every piece to be the exact same size. Since 2 is the greatest possible value, we can divide the cake into 8 rows of 9 squares, yielding a total of 72 pieces.

As a result, a cake measuring 16 inches by 18 inches can be divided into 72 equal-sized pieces, each measuring 2 inches by 2 inches.

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We can serve 18 people equal-sized pieces of cake from a cake that is 16 inches by 18 inches, assuming each piece is a square and we want the pieces to be exactly the same size.

A two-dimensional figure, form, or planar lamina's area is a measurement of how much space it takes up in the plane.

To find out how many people can be served equal-sized pieces of cake from a cake that is 16 inches by 18 inches, we need to first determine the size of each piece of cake.

The total area of the cake is:

16 inches x 18 inches = 288 square inches

To divide the cake into equal-sized pieces, we need to determine the size of each piece. Let's assume we want each piece to be a square. To find the size of each square, we need to find the square root of the total area of the cake:

√(288 square inches) ≈ 16.97 inches

Since we want the pieces to be exactly the same size, we'll round down to the nearest inch, which gives us:

Each piece of cake will be approximately 16 inches by 16 inches.

To find out how many people can be served equal-sized pieces of cake, we need to divide the total area of the cake by the area of each piece:

288 square inches ÷ (16 inches x 16 inches) = 18

Therefore, we can serve 18 people equal-sized pieces of cake from a cake that is 16 inches by 18 inches, assuming each piece is a square and we want the pieces to be exactly the same size.

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Answer:

3x+y=-1

6x+2y=-2

Step-by-step explanation:

x=(-1-y)/3

In order to calculate the final price after a 33% discount, we can just multiply the initial value by 100% - 33% = 67%, that is, 0.67.

So we have:

So the value after the discount is $219.09.

The value of the discount is:

Answer:

\(73\)

Step-by-step explanation:

\(73=\sqrt{55^{2} +48^{2} }\)

Answer:

\(\displaystyle x_1=2,\,x_2=-\frac{1}{2}\)

\(\displaystyle y_1=1,\,y_2=-\frac{3}{2}\)

Step-by-step explanation:

\(\displaystyle x+2y^2=4\\x+2(x-1)^2=4\\x+2(x^2-2x+1)=4\\x+2x^2-4x+2=4\\2x^2-3x-2=0\\\\x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\frac{-(-3)\pm\sqrt{(-3)^2-4(2)(-2)}}{2(2)}\\ \\x=\frac{3\pm\sqrt{9+16}}{4}\\ \\x=\frac{3\pm\sqrt{25}}{4}\\ \\x=\frac{3\pm5}{4}\\\\x_1=\frac{3+5}{4}=\frac{8}{4}=2,\,x_2=\frac{3-5}{4}=\frac{-2}{4}=-\frac{1}{2}\)

\(\displaystyle y_1=2-1=1, y_2=-\frac{1}{2}-1=-\frac{3}{2}\)

Answer:

(2, 1) (-0.5, -1.5)

Step-by-step explanation:

\(\begin{cases}x + 2y^2 = 4\\y = x - 1\end{cases}\)

From here, we can substitute \(y = 2x - 1\) into the first equation.

\(x + 2(x - 1)^2 = 4\\x + 2(x^2 - 2x + 1) = 4\\x + 2x^2 - 4x + 2 = 4\\2x^2 - 3x + 2 = 4\\2x^2 - 3x - 2 = 0\\x = 2, -\frac12\)

Substituting back into the second equation to find the corresponding y values:

\(y(x = 2) = 2 - 1 = 1\\y(x = -\frac12) = -\frac12 - 1 = -1.5\)

The correct formula for the expression is,

⇒ f (x)  = - 6 cos (π/4.5x - 2π) + 2

Since, Trigonometry is a branch of mathematics that deals with the relationship between sides and angles of a right-angle triangle.

We have a function:

f(x) = a cos(bx + c) + d

Here a is the amplitude:

Since, The value of d is the average of maximum and minimum.

Hence,  d = (9 - 5)/2 = 4/2 = 2

And, The value of 'a' is the difference between the maximum value and d.

Hence,  a = -4 -(2) = - 6

Here, the half-period is,

= π - 3π/4) = π/4

=  b = 2π/9 = π/4.5

The value of c is the value makes the cosine zero at x= 9

⇒  (π/4.5)(9) +c = 0

⇒  c = -2π

Hence, Function is,

f (x) = - 6 cos (π/4.5x - 2π) + 2

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Answer:

The correct answer would be:

f (x) = - 6 cos (π/4.5x - 2π) + 2

Answer:

88

Step-by-step explanation:

multiply 13 by 2 = 26

then add by 1 52 and 15

= 94

then subtract 94-6

88

Remember use Dmas while solving

The probability of landing in either the triangle or the circle is approximately 29.4%.

To calculate the probability of landing in either the triangle or the circle, we first need to find the total area of all shapes. Given the area of the triangle is 10, the area of the circle is 15, and the area of the rectangle is 60.

Total area = Area of triangle + Area of circle + Area of rectangle
Total area = 10 + 15 + 60
Total area = 85

Now, we calculate the combined area of the triangle and the circle:
Combined area = Area of triangle + Area of circle
Combined area = 10 + 15
Combined area = 25

To find the probability, we will divide the combined area by the total area:
Probability = Combined area / Total area
Probability = 25 / 85
Probability ≈ 0.294

To express the probability as a percentage, multiply by 100:
Probability ≈ 0.294 × 100
Probability ≈ 29.4%
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The combination formula helps to determine the number of non-negative solutions of equation

x₁ + x₂ + x₃ + x₄ + x₅ = 21 in different cases.

a) Total number of solutions for equation in case of x₁ ≥ 1, is equals to the 10626.

b) Total number of solutions for equation in case of xᵢ ≥ 2 for i = 1, 2, 3, 4, 5, is equals to the 1365.

c) Total number of solutions for equation in case of 0 ≤ x₁ ≤ 10 is equals to the 11649.

d) Total number of solutions for equation in case of 0 ≤ x₁ ≤ 3, 1 ≤ x₂ < 4, and x₃ ≥ 15, is equals to the 76.

We have an equation x₁ + x₂ + x₃ + x₄ + x₅ = 21, where xᵢ , i = 1, 2, 3, 4, 5 and we have to determine the number of solution of equation.

a) Solution of equation when x₁ ≥ 1

Let there are 5 boxes namely, x₁,x₂,x₃,x₄,x₅ in which 21 balls are placed distinguished. First ball is placed in box x₁. So, remained 20 balls are placed into 5 boxes with repititions. So, number of ways are C(n+r−1, r-1) = (n + r − 1)!/(r-1)!n! , where n = 20 , r = 5

C(n + r −1, r- 1) = C(20 + 5− 1 ,4)

= C(24,4) = 10626

b) Solution of equation for xᵢ ≥ 2 for i = 1,2,3,4,5.

Now, xᵢ ≥ 2 for i = 1,2,3,4,5, means first drop two balls into every box. Then, only 11 balls, remaining

n =11, r = 5

C(n+r−1, r-1) = (n+r−1)!/(r-1)!n!

= C(11 + 5−1, 4) = C(15, 4)

= 1365

c) Solution of equation for 0 ≤ x1 ≤ 10

when 21 balls dropped into five boxes x₁, x₂, x₃, x₄,x₅ then C(n+r−1, r-1) = (n+r−1)!/(r-1)!n! ; n= 21, r = 5

C(n + r −1, r - 1) = C(21+ 5− 1 ,4)

C(25, 4) = 12650

xi ≥ 11 , n=11, r = 5 then

C(n + r−1, r- 1 ) = C(11+4−1,4)

C(14,4) = 1001

C(25,4) − C(14,4) = 12650 − 1001 = 11649

d) Solution of equation for 0 ≤ x₁≤ 3, 1 ≤ x₂ < 4, and x₃≥ 15. For this condition solution is = { x1≥ 0, x2≥ 0, x3 ≥ 15} - { x₁≥3, x₃≥ 15} - { x₂≥4, x₃≥ 15} - { x₁=0, x₃ ≥ 15}

Now, first 15 balls are dropped into x3 and remaining 6 are droped into remaining boxes, { x₁ ≥ 0, x₂≥ 0, x₃≥ 15}, Then, n = 6, r = 5

C(n + r −1, r - 1) = C(6+ 5− 1 ,4)

C(10, 4) = 210

Also, { x₁ ≥3, x₃ ≥ 15}, represents 3 and 15 balls are dropped into x₁ and x₃ respectively. and remaining 3 balls will dropped into 5 boxes with repititions, n = 3, r = 5

C(n + r −1, r - 1) = C(3+ 5− 1 ,4)

C(7, 4) = 35 ways

{ x₂≥4, x₃≥ 15} , represents 4 and 15 balls are dropped into x₂ and x₃ respectively. and remaining 2 balls will dropped into 5 boxes with repititions, n= 2, r = 5

C(n + r −1, r - 1) = C(5+ 4− 1 ,4)

C(7, 3) = 15 ways

{ x₂ = 0, x₃ ≥ 15}, represents 0 and 15 balls are dropped into x₂ and x₃ respectively. and remaining 6 balls will dropped into 4 boxes with repititions, n= 6, r= 4

C(n + r −1, r - 1) = C(6+ 4− 1 ,3)

C(9, 3) = 84 ways

So, the number of solutions for this case = 210 - 35 - 15 - 84 = 76.

Hence there are 76 non-negative integer solutions.

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The best method for Carlos to find his five most popular cooking demonstrations from his database would be to sort the demonstrations based on the number of times each demonstration has been viewed or purchased.

Carlos can use the data from his database to determine which cooking demonstrations are the most popular by looking at the number of times each demonstration has been viewed or purchased. By sorting the demonstrations in descending order based on this metric, Carlos can easily identify his top five most popular demonstrations.

Carlos can use various methods to find his five most popular cooking demonstrations from his database. One way is to analyze customer feedback and reviews for each demonstration to determine which ones are the most well-received. However, this method may not be the most accurate as not all customers leave feedback or reviews. Another way is to use data analytics tools to track the number of times each demonstration has been viewed or purchased. This data can be easily obtained from Carlos's database, and he can sort the demonstrations in descending order based on this metric. By doing this, he can easily identify his top five most popular demonstrations and offer them for the next month's cooking demonstrations. In conclusion, Carlos can use data analytics to find his five most popular cooking demonstrations from his database. Sorting the demonstrations based on the number of times each demonstration has been viewed or purchased is the best method for him to use as it is easy to obtain and provides accurate results.

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Answer:

-2c-16

Step-by-step explanation:

do 7-9 because it's the only thing you can solve.
--> -2c-16