The Blue Origin rocket ship starts vertically upward from the launch pad a constant
acceleration of 6.3 m/sec2. How high does the rocket ship raise above the launch
pad after 94 seconds of flight?
Assume that the rocket ship moves vertically up all the time. Enter your answer in
meters (m).

Answer:

If he's 500 kg and 1 kg = 10 N then it would be 5,000 N

Explanation:

The surface area is unimportant and they'll use it to trick you.

Given that two large parallel plates are separated by 0.20 m and that the potential difference is 12V.

(a) Describe the motion of an electron released from rest at a distance "d" from the negative plate.

(b) What distance from the positive plate will the electron have a speed of 1 x 10^6 m/s?

For part (a):

The magnitude of an electric field can be given as  \(||\vec E||=\frac{\Delta V}{d}\), where "ΔV" is the potential difference and "d" is the distance between the plates.

So, \(||\vec E||=\frac{12 \ V}{0.20 \ m} \Longrightarrow \boxed{||\vec E||=60 \ \frac{N}{C} }\)

An electric field is created between the plates pointing from positive towards negative. We know that negative charges accelerate opposite the direction of electrical fields. So the electron placed "d" meters away from the negative plate will accelerate towards the positive plate at a constant rate.

For part (b):

We know that...

- the charge of an electron is \(\bold{-1.602 \times10^{-19} \ C}\).

- the mass of an electron is \(\bold{9.11 \times10^{-31} \ kg}\).

- \(\vec F_e=q\vec E\)

- \(\vec F =m\vec a\)

\(\Longrightarrow \vec F_e=(-1.602 \times10^{-19} \ C)(60 \ \frac{N}{C} }) \Longrightarrow \boxed{\vec F_e= -9.612 \times10^{-18} \ N}\)

\(\Longrightarrow \vec F =m\vec a \Longrightarrow \vec a=\frac{\vec F}{m} \Longrightarrow \vec a=\frac{-9.612 \times10^{-18}}{9.11 \times10^{-31} \ kg} \Longrightarrow \boxed{\vec a=-1.06 \times10^{13} \ m/s^2}\)

Kinematic Equation: \(\vec v_f^2=\vec v_0^2+2\vec a \Delta \vec x\)

\(\Longrightarrow 1 \times10^{12} \ m^2/s^2=-2.11 \times10^{13} \ m/s^2 \Delta \vec x \Longrightarrow \Delta \vec x= \frac{1 \times10^{12} \ m^2/s^2}{-2.12 1\times10^{13} \ m/s^2}\)

\(\Longrightarrow \boxed{\Delta \vec x= -0.047 \ m}\)

The distance from the positive plate we'll call, "D."

\(D=0.20+\Delta \vec x\)

\(\Longrightarrow D=0.20+\Delta \vec x \Longrightarrow D=0.20 \ m+(-0.047 \ m) \Longrightarrow \boxed{D=0.153 \ m} \therefore Sol.\)

Answer:

Whenever one body exerts a force on a second body, the first body experiences a force that is equal in magnitude and opposite in direction to the force that it exerts

Explanation:

Answer: According to Khan Academy "Newton's third law: If an object A exerts a force on object B, then object B must exert a force of equal magnitude and opposite direction back on object A.

Explanation: This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force itself. We sometimes refer to this law loosely as action-reaction, where the force exerted is the action and the force experienced as a consequence is the reaction.

We can readily see Newton’s third law at work by taking a look at how people move about. Consider a swimmer pushing off from the side of a pool, as illustrated below.

A swimmer pushes on the wall with her feet, which causes the wall to push back on her feet due to Newton's third law."

Hope this helps ^_^ and have a great day

Answer:

Metal is cold because it is a good conductor. A conductor carries heat away from and object. Heat flows from your hand into the metal and then is conducted rapidly away into the bulk of the metal, leaving the metal surface and your skin surface relatively cool.

Explanation:

You are welcome.

Metal has EXTREME thermal conductors...meaning that the metal can easily change due to weather, even when wind blows on it, usually that is why it is cold

Hope this helps..You're welcome ;)

Answer:The choke coil works because it can act as an inductor. When the current pass through will change as AC currents creates a magnetic field in the coil that works against that current. This is known as inductance and blocks most of the AC current from passing through.

Explanation:

The motorcycle had covered a distance of 16 meters in half the total time.

a) To calculate the acceleration, we can use the formula:

a = (v - u) / t

where a is the acceleration, v is the final velocity, u is the initial velocity (which is 0 since the motorcycle starts from rest), and t is the time.

Given:

u = 0 m/s (initial velocity)

v = ? (final velocity)

t = 4 s (time)

s = 64 m (distance)

Using the equation of motion:

s = ut + 1/2at^2

We can rearrange the equation to solve for acceleration:

a = 2s / t^2

a = 2(64) / (4)^2

a = 128 / 16

a = 8 m/s^2

Therefore, the acceleration of the motorcycle is 8 m/s^2.

b) To find the final velocity, we can use the formula:

v = u + at

v = 0 + (8)(4)

v = 32 m/s

Therefore, the final velocity of the motorcycle is 32 m/s.

c) To determine the time at which the motorcycle had covered half the total distance, we divide the total distance by 2 and use the formula:

s = ut + 1/2at^2

32 = 0 + 1/2(8)t^2

16 = 4t^2

t^2 = 4

t = 2 s

Therefore, the motorcycle had covered half the total distance at 2 seconds.

d) To calculate the distance covered in half the total time, we use the formula:

s = ut + 1/2at^2

s = 0 + 1/2(8)(2)^2

s = 0 + 1/2(8)(4)

s = 0 + 16

s = 16 m

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Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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The net force on the top block is 33.54 N.

Net force is the sum or resultant of two or more forces acting on a body.

Also, the net force is the force which is the sum of all the forces acting on an object simultaneously.

The sum of the upward forces is calculated as follows;

F(upward) = 50 N - 20 N = 30 N

The sum of the horizontal forces is calculated as follows;

F(horizontal) = 15 N

The net force or resultant force on the top block is calculated as follows;

F(net) = √Fy² + Fx²

where;

F(net) = √Fy² + Fx²

F(net) = √[(30)² + (15)²]

F(net) = 33.54 N

Thus, the net force or resultant force on the top block is determined as 33.54 N.

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Answer:

B.lenses bounce light from their surface, mirrors do not

Plate boundaries represent the parts of the Earth's crust where plates come in contact with one another. There are three types of plate boundaries based on the movement and interaction of the plates involved. These are: Divergent Plate Boundaries, Convergent Plate Boundaries, and Transform Plate Boundaries.

Divergent Plate Boundaries
At divergent plate boundaries, two plates move away from each other as magma rises to the surface and creates new crustal material. Examples of divergent plate boundaries include the Mid-Atlantic Ridge, the East Pacific Rise, and the African Rift Valley.

Convergent Plate Boundaries
At convergent plate boundaries, two plates move toward each other and eventually collide. Depending on the type of plate involved, different types of interactions can occur. The three types of convergent plate boundaries are oceanic-continental, oceanic-oceanic, and continental-continental. An example of oceanic-continental convergence is the Pacific Northwest region of the United States. An example of oceanic-oceanic convergence is the Japanese Islands, and an example of continental-continental convergence is the Himalayas.

Transform Plate Boundaries
At transform plate boundaries, two plates move past each other in a horizontal direction. These boundaries are characterized by faults and earthquakes, such as the San Andreas Fault in California.

To create an illustration that represents each type of plate movement, you can draw a diagram that shows the direction of plate movement, the type of boundary, and any notable geological features associated with that type of boundary.

For example, a divergent plate boundary illustration could include a depiction of magma rising to the surface and creating new crustal material, while a transform plate boundary illustration could include a fault line and a depiction of the earthquakes that occur along that boundary.

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The correct answer is D. An average city

Explanation:

A neutron star differs from others due to its massive density, this means a lot of matter is compressed in a small area. Indeed, neutron stars have a mass of around 1.4 to 2.8 times the mass of the sun. But these are considerably small as they only measure around 20 kilometers, which is the size of an average city. Additionally, neutron stars are this dense because they are the result of a regular star exploding, which leads to a super-dense core, or neutron star. In this context, the mass of a neutron star is compressed to the size of an average city.

Answer:

The magnitude and direction of the rocket acceleration is 68.89 m/s² upward.

The speed of the rocket at the given elevation is 186 m/s.

Explanation:

Given;

time to reach the given height, t = 2.7 s

height reached, h = 93 m

initial velocity of the rocket, u = 0

The magnitude and direction of the rocket acceleration is calculated as;

h = ut + ¹/₂at²

h = 0 + ¹/₂at²

h = ¹/₂at²

a = 2h / t²

a = (2 x 93) / 2.7

a = 68.89 m/s²

the direction of the acceleration is upward.

The speed at this elevation, V = u + at

V = at

V = 68.89 x 2.7

V = 186 m/s

Answer:

0.15 m/s²

Explanation:

Acceleration is rate of change of velocity-time function. We can find acceleration by finding the slope. The slope of graph can be found by:

\( \displaystyle{a = \dfrac{ \Delta v}{ \Delta t} \: \to \: \dfrac{v_f - v_i}{t_f- t_i}}\)

Substitute in:

\( \displaystyle{a = \dfrac{5 - 2}{40 - 20}} \\ \\ \displaystyle{a = \dfrac{3}{20}} \\ \\ \displaystyle{a = 0.15 \: \text{m/s}^{2} }\)

Therefore, the acceleration is 0.15 m/s²

Answer:

The cantaloupe has a speed of 117.6 m/s

Explanation:

Free Fall Motion

It occurs when an object falls under the sole influence of gravity. Any object that is being acted upon solely by the force of gravity is said to be in a state of free fall. Free-falling objects do not face air resistance.

If an object is dropped from rest in a free-falling motion, it falls with a constant acceleration called the acceleration of gravity, which value is \(g = 9.8 m/s^2\).

The final velocity of a free-falling object after a time t is given by:

vf=g.t

The cantaloupe has been dropped from rest. We are required to find the speed after t=12 seconds.

Calculate the final speed:

vf=9.8 * 12 = 117.6 m/s

The cantaloupe has a speed of 117.6 m/s

Answer: Net electrostatic force on C is 24.2×\(10^{-2}\) Newtons.

Explanation: Coulomb's Law is used to determine Electrostatic Force. Its formula is:

F = k.\(\frac{q_{0}.q_{1}}{r^{2}}\)

where:

k is electrostatic constant (k = 8.987×\(10^{9}\) Nm²/C²);

q is the charge of the object in Coulumb;

r is the distance between charges;

The net force is the sum of all the forces acting on C, so:

Force B on C:

They are both positive, so there is a relpusive force acting between them on the y-axis.

\(F_{BC} = 8,987.10^{9}.\frac{4.35.10^{-3}.9.67.10^{-4}}{(6.14.10^{2})^{2}}\)

\(F_{BC} = 10.03.10^{-2}\) N

Force D on C:

There is an atractive force between them on the x-axis.

\(F_{CD} = 8.987.10^{9}.\frac{9.67.10^{-4}.1.92.10^{-3}}{(1.42.10^{3})^{2}}\)

\(F_{CD} = 13.64.10^{-4}\) N

Force A on C:

First, find the distance between objects:

The distance is a diagonal line that divides the rectangle into a right triangle. Distance is square of the hypotenuse .

\(r^{2} = (6.14.10^2)^{2} + (1.42.10^{3})^{2}\)

\(r^{2} = 37.72.10^{4}\)

and hypotenuse: r = \(6.14.10^2\)m

There is an atractive force between charges, but there are components of the force in x- and y-axis. So, because of that, force will be:

\(F_{CA} = F_{CA}\).sinα + \(F_{CA}.\)cosα

\(F_{CA} = 8.987.10^{9}.\frac{3.12.10^{-3}.9.67.10^{-4}}{37.72.10^{4}}\)

\(F_{CA} = 7.2.10^{-2}\)

The trigonometric relations is taken from the rectangle:

sinα = \(\frac{6.14.10^{2}}{6.14.10^{2}}\)

cosα = \(\frac{1.42.10^{3}}{6.14.10^{2}}\)

\(F_{CA}.\)cosα = \(7.2.10^{-2}(\frac{1.42.10^{3}}{6.14.10^{2}})\) = 0.17

\(F_{CA}.\)sinα = \(7.2.10^{-2}.(\frac{6.14.10^{2}}{6.14.10^{2}} )\) = 0.072

\(F_{CA} =\) 0.17î + 0.072^j

Now, sum up all the terms in its respective axis:

X: \(13.64.10^{-4} + 0.17 =\) 0.1714

Y: \(10.03.10^{-2} + 7.2.10^{-2}\) = 0.1723

These forms another right triangle, whose hypotenuse is the net electrostatic force:

\(F_{net} = \sqrt{(0.1714)^{2} + (0.1723)^2}\)

\(F_{net} = 24.3.10^{-2}\) N

The net electrostatic force acting on C has magnitude \(F_{net} = 24.3.10^{-2}\) N.

Answer:

photosynthesis, burning fossil fuels, and simply releasing breath from the lungs. 

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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The speed of the car is 100 meters per second.

Speed is a measure of how quickly an object moves from one place to another. It is calculated by dividing the distance traveled by the time taken to cover that distance.

To find the speed of the car in meters per second, we need to convert the distance traveled from kilometers to meters and the time taken from seconds to hours.

Distance traveled = 4 km = 4,000 meters

Time taken = 40 seconds = 40/3,600 hours = 0.0111 hours

Now, we can use the formula:

Speed = Distance / Time

Speed = 4,000 meters / 0.0111 hours

Speed ≈ 360,360 meters per hour

Finally, to convert the speed to meters per second, we divide by 3,600 (the number of seconds in an hour):

Speed = 360,360 meters per hour / 3,600 seconds per hour

Speed ≈ 100 meters per second

Therefore, the speed of the car is approximately 100 meters per second.

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No, the kinetic energy of the moving molecules in the sea water cannot be extracted for use. Details about kinetic energy can be found below.

Kinetic energy is a form of energy that is produced as a result of motion i.e. it is the energy possessed by a moving body.

This means that the kinetic energy of a moving body is specific to that body and dependent on the movement of that body. The kinetic energy is quickly converted to potential energy once the body stops moving.

Therefore, the kinetic energy of the moving molecules in the sea water cannot be extracted for use.

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Answer:

As traditionally used, impairment refers to a problem with a structure or organ of the body; disability is a functional limitation with regard to a particular activity; and handicap refers to a disadvantage in filling a role in life relative to a peer group.

Explanation:

Hope this helps u

Crown me as brainliest:)

Answer:

a circular path

Explanation:

In a magnetism field if a charged particle having a charge of magnitude '' enters  such that its velocity vector V is 90° to the direction of the magnetic field "B'', then it will experience a force, called Lorentz force F

\(F = V\times B\)

According to the property of cross-product, the Lorentz force (F) acting on the particle will be perpendicular to the instantaneous position of the particle, making the path of the particle to be a circular path.

Since we are using a DIY solar oven, we will have that tge aluminum/tin foil will improve the reflections over the thing we are trying to cook, thus increasing the amount of energy we are inputing into it and cooking it slightly faster.

Answer:

true

Explanation:

Initially it requires more force to break the interlock between the irregularities of two surfaces. But once the block is in motion, it takes time to interlock between the irregularities of two surfaces. Also, the body gains the inertia of motion.

(a) The acceleration of the 1,400-kg boat is 0.30 m/s².

(b) The boat move 60 m in 20.0 s

(c) The velocity at the end of that time will be 6 m /s

It is given that mass of the boat = 1400 kg , forward push on the boat by the propeller = 1,725 N and resistive force of water = 1300 N

(a) Let the acceleration of the boat be "a" .

The net force on the boat will be

F(net) = F(push) - F(R)

         = 1725 - 1300

         = 425 N

Using Newton's second law of motion , we get

F(net) = ma

       a = F(net) / m

          = 425 / 1400

          =  0.30 m/s²

(b) Let the distance moved by the boat be "d" .

It is given that it starts from rest which means that u = 0

Now using the kinematic equation  s = ut + 1/2at² .   ...(1)

Putting a = 0.30  , t = 20 and u = 0  in equation (1) , we get

     s = 0 (20) + 1/2 (0.30)(20)²

        = 0 + 1/2 (0.30 × 400)

        =  120 /2

        = 60 m

(c) Let the final velocity of the boat be "v" .

Using the kinematic equation v = u + at     ..(2)

Putting a = 0.30  , t = 20 and u = 0  in equation (2) , we get

   v = 0 + (0.30)(20)

      = 6 m /s

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As the fish tank is 20 inches by 12 inches by 12 inches, its volume is 47194744.32 mm³.

The space that any three-dimensional solid occupies is known as its volume. These solids can take the form of a cube, cuboid, cone, cylinder, or sphere.

1 inch = 0.0254 meters.

20 inches = 20 × 0.0254 meters = 0.508 meters = 508 mm.

12 inches = 12 × 0.0254 meters = 0.3048 meters = 304.8 mm.

Hence, The volume of the fish tank  = length × width × height

=  508 mm ×  304.8 mm ×  304.8 mm.

= 47194744.32 mm³

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Answer: \(0.0353\ s^{-1}\)

Explanation:

Given

Radioactive material is found to decrease 40% of its original value in \(2.59\times 10\ s\)

Sample at any time is given by

\(N=N_oe^{-\lambda t}\)

where, \(\lambda=\text{decay constant}\)

Put values

\(\Rightarrow 0.4N_o=N_oe^{-\lambda\cdot 2.59\times 10}\\\Rightarrow 0.4=e^{-\lambda\cdot 2.59\times 10\)

Taking natural logarithm both side

\(\Rightarrow \lambda=\dfrac{\ln 2.5}{25.9}\\\\\Rightarrow \lambda =0.0353\ s^{-1}\)

The neighbour weighs Iron. As he is a blacksmith, iron is the only thing he weighs the whole day.

A riddle is a statement, question or phrase having a double or veiled meaning, put forth as a puzzle to be solved.

If Robert, your neighbor, a forty-five-year-old blacksmith is seven feet tall, and eats all day long, based on these statements, we can explain the riddle as Robert weighs iron for the fact that he  is a blacksmith, iron is the only thing he weighs the whole day.

Thus, the correct explanation for the riddle is " The neighbour weighs Iron. As he is a blacksmith, iron is the only thing he weighs the whole day.

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Answer:

it will burn up in the Earth's atmosphere.

Explanation:

The structure of the Earth's atmosphere protects the surface from frequent meteoroid strikes. As a meteoroid enters the atmosphere from outer space, it moves at very high speeds. At such speeds, intense amounts of friction and heat result. This process usually causes small meteoroids to burn up in the Earth's atmosphere before ever reaching the surface.

(a) To find the horizontal distance d that the ball travels before landing, we can use the equation d = (Vx)t, where Vx is the horizontal velocity of the ball and t is the time it takes for the ball to fall from the ramp to the floor.

First, we need to find the horizontal velocity of the ball when it leaves the ramp. Since the ball is rolling without slipping, we can use the equation V = ωR, where V is the linear velocity, ω is the angular velocity, and R is the radius of the ball. The radius of the ball is 0.20 m / 2 = 0.10 m.

Next, we need to find the angular velocity of the ball. We can use the equation ω = √(2gh/R), where g is the acceleration due to gravity (9.8 m/s^2), h is the vertical height that the ball drops (0.49 m), and R is the radius of the ball (0.10 m). Plugging in the values gives us:

ω = √(2(9.8)(0.49)/0.10) = 31.3 rad/s

Now we can find the horizontal velocity of the ball:

V = ωR = (31.3)(0.10) = 3.13 m/s

Finally, we can find the time it takes for the ball to fall from the ramp to the floor using the equation h = 0.5gt^2, where h is the vertical height (1.31 m) and g is the acceleration due to gravity (9.8 m/s^2). Rearranging the equation and plugging in the values gives us:

t = √(2h/g) = √(2(1.31)/9.8) = 0.52 s

Now we can find the horizontal distance d that the ball travels before landing:

d = (Vx)t = (3.13)(0.52) = 1.63 m

Answer: The ball travels 1.63 m before landing.

(b) To find the number of revolutions that the ball makes during its fall, we can use the equation θ = ωt, where θ is the angular displacement, ω is the angular velocity, and t is the time. The angular displacement is equal to the number of revolutions times 2π, so we can rearrange the equation to solve for the number of revolutions:

θ / 2π = ωt / 2π = (31.3)(0.52) / 2π = 2.59 rev

Answer: The ball makes 2.59 revolutions during its fall.

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