The boiling point of calcium is 2,703 °F. What is the boiling point of calcium in °C?

Answer:

Explanation:

1,2,4,

The equations that show combustion are equations A, B and D.

When we talk about combustion, the idea is that the substance would be burnt in oxygen. In other words, the combustion can be taken to be an oxidation reaction. It is an oxidation reaction in the sense that the oxidation number of the substance that is reacting with the oxygen would become increased.

When we look at the equations that we have, it is quite easy to pick out among the balanced reaction equations that are shown here the ones that has to do with the burning of the substance in oxygen and a consequent rise in the oxidation number.

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Answer:

» It contains two atoms of sodium sulphate

» It contains 10 molecules of water.

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Answer:

It is combustion because C2H4 is reacting with O2, and creates CO2 and H2O

The type of chemical reaction which is given in the question is combustion reaction.

Combustion reactions are those reactions in which hydrocarbon will burn in the presence of oxygen and will form water molecules and carbon dioxide gas.

In the given chemical reaction ethene (C₂H₄) is a hydrocarbon which reacts with oxygen gas to produce water (H₂O) and carbon dioxide (CO₂), so the given reaction is combustion reaction.

Hence the given reaction is a combustion reaction.

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Chlorofluorocarbons (CFCs) are man-made chemicals containing chlorine and fluorine that cause ozone molecules to break down. Thus, option B is the answer.

Chlorofluorocarbons are non-toxic, synthetic compounds that contain atoms of Chlorine, Fluorine and Carbon. They are commonly used in the manufacture of aerosol sprays and are also used as solvents and refrigerants. CFCs were first introduced in 1928 by General Motors Company for its refrigerators.

While CFCs are very safe to use in most applications and are stable in the lower atmosphere, these chemicals when released to the upper atmosphere can cause significant reactions. CFCs when released into the upper atmosphere can lead to the destruction of the ozone molecules followed by the release of the UV radiation into the atmosphere.

Thus, CFCs are man-made chemicals which cause ozone molecules to break down.

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Answer:

Explanation:

Safety: The rate of energy release determines how quickly and explosively the energy is released. In the case of the stick of dynamite, the rapid and instantaneous release of energy can cause a violent explosion. On the other hand, the controlled release of energy from gasoline allows for safer and more manageable energy output, reducing the risk of accidents and minimizing potential harm.

Efficiency: The rate at which energy is output affects the efficiency of a system. In many practical applications, such as engines or power generation, it is desirable to convert energy into useful work as efficiently as possible. Controlling the rate of energy release allows for a more efficient conversion of energy, minimizing waste and maximizing the desired output.

Control and Functionality: Different systems require energy to be released at specific rates to perform their intended functions. For example, in an internal combustion engine, the controlled and timed release of energy from fuel allows for the synchronized movement of engine components, resulting in the desired mechanical work. Controlling the rate of energy output ensures that a system operates effectively and performs its intended function.

Environmental Impact: The rate at which energy is output can also impact the environment. In processes that release energy too rapidly or uncontrollably, such as certain combustion reactions or explosions, there can be significant environmental consequences, including air pollution, damage to ecosystems, and the release of harmful byproducts. Controlling the rate of energy release allows for better management and mitigation of these environmental impacts.

Overall, the rate at which energy is output from a system is crucial for safety, efficiency, control, functionality, and environmental considerations. By regulating and optimizing the rate of energy release, we can ensure that energy is utilized effectively and responsibly in various applications.

Answer:

The products have more potential energy than the reactants in an endothermic reaction.

Explanation:

In an endothermic reaction, energy is absorbed, so the products have more potential energy that the reactants, like we can see in this drawing:

Answer:

1 volt

Explanation:

Use Ohm's Law:

V = IR

V = (0.05A)(20 ohms) = 1 volt

An electrical circuit has a resistance of 20 ohms and a current of 0.05A. The voltage is applied in this circuit is 1 volt.

Ohm's Law states that the current in a circuit is equal to the potential difference divided by the resistance of the circuit. It is represented by  V = IR, where V is the voltage difference, I is the current in amperes, and R is the resistance in ohms.

The law can be used to perform calculations such as determining the value of resistors or current in a circuit, or measuring voltage. Furthermore, Ohm's law assists us in describing how current flows through materials such as electrical wires, etc.

By using  Ohm's Law we get,

V = IR

V = (0.05A)(20 ohms)

= 1 volt

Thus, The voltage is applied in this circuit is 1 volt.

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To rank these least polar=1 to most polar=11, we need to understand what polarity is. The term "polarity" refers to the distribution of electrical charge in a molecule.

A molecule is polar if its electron cloud is distributed unevenly and has poles, resulting in the molecule having a positive and a negative end. A molecule is nonpolar if its electron cloud is distributed uniformly, resulting in the molecule having no charge poles.

The ranking of the given compounds from least polar to most polar is as follows:

Least polar: 7 (nonpolar)

4 (nonpolar)

9 (nonpolar)

1 (nonpolar)

8 (polar)

2 (polar)

6 (polar)

5 (polar)

10 (polar)

3 (most polar)

Most polar: 3 (most polar)

The reasoning behind this ranking is that the difference in electronegativity between the two atoms that make up the molecule determines polarity.

The greater the difference in electronegativity between two atoms, the more polar the bond between them is. As a result, we can classify the compounds as nonpolar and polar. We rank these compounds based on their polarity, with the least polar being nonpolar and the most polar being polar.

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The molecular formula for sodium nitrate is NaNO₃, and the molecular formula for potassium acetate is KCH₃COO.

Complete ionic equation:

Na⁺(aq) + NO₃⁻(aq) + K⁺(aq) + CH₃COO⁻(aq) → Na⁺(aq) + CH₃COO⁻(aq) + K⁺(aq) + NO₃⁻(aq)

Net ionic equation:

NO₃⁻(aq) + CH₃COO⁻(aq) → no reaction

The net ionic equation shows that there is no reaction between sodium nitrate and potassium acetate. When these compounds are mixed, they will dissociate into their respective ions in solution, but these ions do not react with each other to form any new compounds or products. Therefore, the net ionic equation is simply the two ions that remain in solution after dissociation.

When sodium nitrate (NaNO₃) and potassium acetate (KCH₃COO) are mixed in water, they dissociate into their respective ions due to the polar nature of water molecules.

The net ionic equation shows only the species that are involved in the actual reaction, which in this case is no reaction. We can see that the NO₃⁻ and CH₃COO⁻ ions are both present on both sides of the equation, meaning that they do not react with each other. Therefore, there is no change in the identity of the species present in solution, and no new compounds are formed.

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Explanation:

3+3+6=12 is the three numbers adding up to 12

If an equation includes 7(CrO₄)₂, the numbers of Cr's and O's atoms that are there are 14 and 56 respectively.

The number of atoms present in a chemical compound can be calculated by multiplying the subscript of the particular element by any coefficient.

According to this question, 7 moles of chromate with the chemical formula; (CrO₄)₂ is given. The number of oxygen and chromium atoms in this compound can be calculated as follows:

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250 L of 5.0% w/v glucose solution can be prepared using 125 g of glucose.

w/v = [ mass of solute (g) / volume of solution (mL) ] × 100

5.0 % w/v = [ 125 g / volume of solution (mL) ] × 100

volume of solution (mL) = [ 125 g / 5.0 % w/v ] x 100

volume of solution (mL) = [ 125 g / (5.0 / 100) ] x 100

volume of solution (mL) = [ 125 g / 0.05 ] x 100

Explanation:

Charles's law states that the volume of a gas is directly related to the temperature of the gas when the pressure is constant. Similarly when a gas is heated, like a burner in a hot air balloon, the gas expands. Therefore, when the air inside the balloon expands, it becomes less dense and provides the lift for the air balloon.

Answer:

PbS shows a very low solubility in water, and it is insoluble in organic solvents. Any "dissolution" process in acids (hydrochloric acid, nitric acid, aqua regia) is accompanied with a chemical reaction whereby H2S is liberated and the corresponding soluble Pb2+ salts are formed. hope that helps

The rate of the forward reaction equals the rate of the reverse reaction.

When it comes to chemical reactions, a dynamic equilibrium is a condition in which a reversible reaction produces products and reactants at an equal rate.

Dynamic equilibrium can only be achieved in a closed system. That is, a system in which there are no external influences in form of energy, material, or pressure.

For example, consider the following reversible reaction:

\(A + B < --- > C + D\)

If the reaction is in dynamic equilibrium, there will not be a net production of reactants and products. In other words, the rate of production of A and B will be the same as the rate of production of C and D.

This is as opposed to static equilibrium in which the production of both reactants and products stops completely after reaching equilibrium.

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Answer:

(1760 ÷ 64) x 24.4 =671dm^3

The boiling point of hydrogen at atmospheric pressure is -252. 8°C.

Atmospheric pressure is defined as the pressure which is exerted by the atmosphere to us.

Temperature is term which is defined as the measure of degree of coldness or hotness which is expressed in terms of different type of scales, including Celsius and Fahrenheit.

Boiling point is defined as the bulk phenomenon.

It is the temperature where the pressure of liquid is equal to the pressure of our surrounding or atmospheric pressure.

Or simply it is defined as the temperature at which liquid start boiling.

As we know that,

The atmospheric pressure is 1.0 x 10^5 Pa.

Then the temperature at which hydrogen liquid start boiling is -252. 8°C. Therefore it need to store in the cold or low temperature.

Thus, we concluded that the boiling point of hydrogen at atmospheric pressure is -252. 8°C.

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Answer:

\(\boxed {\boxed {\sf 0.3 \ mol \ NH_3}}\)

Explanation:

We need to use stiochiometry and a mole to mole conversion to solve this problem.

First, examine the chemical equation. Make sure it is balanced before doing any calculations.

\(N_2+3H_2 \rightarrow 2NH_3\)

It is balanced, so we can also use the coefficients to refer to molar amounts.

So, the equation is also saying that 1 mole of N₂ (no coefficient implies 1) and 3 moles of H₂ react to form 2 moles of NH₃.

\(1 \ mol \ N_2 + 3 \ mol \ H_2 \rightarrow 2 \ mol \ NH_3\)

Now we can use this information to make a ratio. We know that we have 0.45 moles of hydrogen, and we are trying to find the moles of ammonia.

According to the original equation, 3 moles of hydrogen produce 2 moles of ammonia. Let's make a ratio.

\(\frac {3 \ mol \ H_2}{2 \ mol \ NH_3}\)

We have 0.45 moles of hydrogen, so multiply by that number.

\(0.45 \ mol \ H_2 *\frac {3 \ mol \ H_2}{2 \ mol \ NH_3}\)

Flip the ratio so the units of moles of hydrogen cancel.

\(0.45 \ mol \ H_2 *\frac{2 \ mol \ NH_3 }{3 \ mol \ H_2}\)

\(0.45 *\frac{2 \ mol \ NH_3 }{3}\)

\(\frac {0.45 *2 \ }{3} mol \ NH_3\)

\(\frac {0.9 \ }{3} mol \ NH_3\)

\(0.3 \ mol \ NH_3\)

0.3 moles of ammonia are produced when 0.45 moles of hydrogen gas react with nitrogen gas.

Answer:

Zero

Explanation:

The number of atoms present in 0.58 mole of magnesium, Mg is 3.49×10²³ atoms.

An atom is the basic building block of chemistry. It is the smallest unit into which matter can be divided without the release of electrically charged particles.

Avogadro's hypothesis

1 mole of Mg = 6.02×10²³ atoms

Therefore,

0.58 mole of Mg = 0.58 × 6.02×10²³

0.58 mole of Mg = 3.49×10²³ atoms

Thus, 3.49×10²³ atoms are present in 0.58 mole of Mg

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Answer:

840960 minutes in 1.6 years ...

Answer: 2.3% :)

............................

Answer: 34%

Explanation:

Answer:

12

Explanation:

There are 4 sulfur atoms in SO4

4×3=12

This means that it turns into 3×(SO4)

=3SO4

Answer:

C the temperature will increase.

Answer:

CH₂

Explanation:

Given parameters:

Percentage composition:

          Carbon  = 40.1%

          Hydrogen  = 6.6%

Unknown:

Empirical formula of the compound  = ?

Solution:

The empirical formula of a substance is its simplest formula.

 Elements                             Carbon                             Hydrogen

Percentage

Composition                           40.1                                     6.6

Molecular mass                        12                                         1

Number of moles                  40.1/12                                  6.6/1

                                                3.342                                    6.6

Divide through by

the smallest                         3.342/3.342                           6.6/3.342

                                                      1                                        2

So the empirical formula of the compound is CH₂

Answer:

When conducting a chemistry lab experiment using chalk (calcium carbonate) in vinegar (acetic acid), there are several limitations and precautions to be aware of:

Limitations of chalk in vinegar chemistry experiment:

Reaction rate: The reaction between chalk and vinegar is relatively slow, which may require a longer observation period or higher concentration of vinegar to observe significant changes within a reasonable time frame.

Solubility: Chalk may not dissolve completely in vinegar, resulting in incomplete reaction or difficulty in obtaining accurate results.

Product formation: The reaction between chalk and vinegar produces carbon dioxide gas, water, and calcium acetate. The carbon dioxide gas may escape into the atmosphere, leading to loss of product and inaccurate measurements.

pH: Chalk is a basic substance, and the reaction with vinegar, which is acidic, may result in neutralization, leading to a decrease in the overall acidity of the reaction mixture.

Precautions to take in chalk in vinegar chemistry experiment:

Ventilation: The reaction between chalk and vinegar produces carbon dioxide gas, which can displace air and potentially cause asphyxiation in a closed or poorly ventilated area. Conduct the experiment in a well-ventilated area or under a fume hood to ensure adequate air circulation.

Eye and skin protection: Vinegar is an acid and can cause skin and eye irritation. Wear appropriate personal protective equipment (PPE), such as gloves and goggles, to protect yourself from contact with vinegar or any other chemicals used in the experiment.

Chemical handling: Handle the chemicals, including chalk and vinegar, with care, following proper lab safety protocols. Avoid ingestion, inhalation, or direct contact with the chemicals, and dispose of them properly according to local regulations.

Accuracy in measurements: Use calibrated and accurate measuring tools, such as graduated cylinders or burettes, to measure the amount of chalk, vinegar, and other reagents accurately. This will ensure the reliability and accuracy of the experimental results.

Observations: Make careful and detailed observations during the experiment, noting any changes in appearance, gas evolution, or other relevant observations. Take measurements at appropriate intervals and record the data accurately for analysis and interpretation.

It is important to follow good laboratory practices, including proper chemical handling, accurate measurements, and cautious observations, to ensure safe and reliable results in a chalk in vinegar chemistry lab experiment. Consult with a qualified instructor or supervisor for specific guidelines and precautions related to your experiment.