The compressions in a sound wave are far apart and more energy is supplied by the vibrating source. Which statement best describes how this will affect the wave and what you hear?

A: The wavelength will increase, and the sound will become louder.
B: The amplitude will increase, and the sound will become louder.
C: The frequency will increase, and the pitch will become higher.
D: The intensity will increase, and the pitch will become higher.

Answer:

R/2

Explanation:

The potential at a distance r is given by :

\(V=\dfrac{kq}{r}\)

Where

k is electrostatic constant

q is the charge

The potential (relative to infinity) due to a point charge is V at a distance R from this charge. So,

\(\dfrac{V_1}{V_2}=\dfrac{r_2}{r_1}\)

Put all the values,

\(\dfrac{V}{2V}=\dfrac{r_2}{R}\\\\\dfrac{1}{2}=\dfrac{r_2}{R}\\\\r_2=\dfrac{R}{2}\)

The distance travelled by the vehicle around the circular track is 1,052.4 m.

The distance travelled by the vehicle in one complete cycle is calculated by using the following equation as show below.

d = 2πr

d = πd

Where;

In one complete cycle, the  vehicle will travel the circular track only once.

d = π(335 m)

d = 1,052.4 m

Thus, the distance travelled by the vehicle around the circular track is a function of the diameter of the circular track.

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The complete question is below:

A vehicle, starting from rest, accelerates on a circular track with a 335m diameter. What is the distance travelled by the vehicle when it makes one complete cycle?

The amount the needle on the meter is deflected A. increases

This phenomenon can be explained by Faraday's law of electromagnetic induction. According to this law, when a magnetic field (created by the bar magnet) passes through a coil of wire, it induces an electric current in the wire. This induced current generates its own magnetic field, which interacts with the magnetic field of the bar magnet.

The deflection of the meter needle is a result of this induced current. When the number of coils of wire is increased, there is a greater number of wire loops for the magnetic field to pass through. This leads to a stronger induction of electric current, resulting in a larger deflection of the meter needle.

By increasing the number of coils, more magnetic flux is linked with the wire, resulting in a higher induced electromotive force (emf) and a greater current. This increased current produces a stronger magnetic field around the wire, leading to a larger deflection on the meter. Therefore, increasing the number of coils of wire enhances the magnetic field interaction, resulting in an increased deflection of the meter needle. Therefore, Option A is correct.

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The material that obeys Hooke's law is elastic material.

Hooke's Law says that the force needed to extend or compress a spring by some distance scales linearly with respect to that distance. And it is known for the formula  F = kX

F is the force, x is the deformation, and k is the spring constant.

Elastic materials are able to return to their original shape after being deformed by a force.

The amount of deformation is noted to be directly proportional to the amount of force applied.

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The mass of the object is approximately 0.457 kg.

The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.

Using the momentum equation, the mass of the object can be calculated as follows:

Total momentum before collision = Total momentum after collision

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

Solving for the mass of the object, we get:

0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s

0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object

0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object

0.32 kg = 0.70 kg * mass of the object

Dividing both sides by 0.70 kg, we find:

mass of the object = 0.32 kg / 0.70 kg = 0.457 kg

The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.

The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.

After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.

In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.

Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.

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Answer:

4.9 m/s²

Explanation:

Let T be the tension in the string

If a is the linear acceleration in the direction of the 3M mass, the equation of motion on the 3M mass is

3Mg - T = 3Ma  (1)

Since the mass M moves upwards, its equation of motion is

T - Mg = Ma      (2)

From (2)

T = Ma + Mg

substituting T into (1), we have

3Mg - (Ma + Mg) = 3Ma

3Mg - Ma - Mg = 3Ma

collecting like terms, we have

3Mg - Mg = 3Ma + Ma

2Mg = 4Ma

dividing both sides by 4M, we have

2Mg/4M = 4Ma/4M

g/2 = a

a = g/2

Since g = 9.8 m/s²,

a = 9.8 m/s²/2

a = 4.9 m/s²

The linear acceleration 'a' of the masses M and 3M is; a = 4.9 m/s²

We are told that;

Mass of first block = M

Mass of second block = 3M

Let the tension in the strings be T.

Now for first block we can write;

T - Mg = Ma - - - (1)

For second block, we can write;

3Mg - T = 3Ma - - - (2)

Where a is linear acceleration of the masses.

Let us add eq 1 to eq 2 to get;

T - Mg + 3Mg - T = Ma + 3Ma

2Mg = 4Ma

M will cancel out to get;

2g = 4a

Using division property of equality by dividing both sides by 2 to get;

g = 2a

Thus;

a = g/2

Where g is acceleration due to gravity = 9.8 m/s²

Thus;

a = 9.8/2

a = 4.9 m/s²

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Frequency = (speed) / (wavelength)

Frequency = (1540 m/s) / (7.52 x 10⁻⁵ m)

Frequency = 20.48 MHz

That frequency is more than 1,000 times higher than anything our ears can hear.  That's why it's called "Ultra-sond".

A frequency of 20.48 MHz (megahertz) is required to create a sound wave with a wavelength of 7.52 x 10^-5 m in human tissue.

A sound wave is a  mechanical wave that is created by the vibration of an object in a medium, such as air or water. When an object vibrates, it creates pressure waves that travel through the medium in all directions. The vibrations in the medium cause the pressure and density to fluctuate, creating a disturbance that our ears detect as sound.

There are two main types of sound waves:

Longitudinal waves: In a longitudinal wave, the particles of the medium vibrate parallel to the direction of the wave. This means that the compressions (where the particles are closer together) and rarefactions (where the particles are farther apart) move in the same direction as the wave. Sound waves in air are longitudinal waves.

Transverse waves: In a transverse wave, the particles of the medium vibrate perpendicular to the direction of the wave. This means that the crests (highest points) and troughs (lowest points) move up and down, while the wave itself moves from left to right. Transverse waves are found in solids, such as a guitar string, but not in fluids like air or water.

Here in the question,

The formula to calculate the speed of sound is:

speed of sound = frequency x wavelength

We are given the speed of sound in human tissue, which is 1540 m/s, and the wavelength of the sound wave, which is 7.52 x 10^-5 m. We can rearrange the formula to solve for frequency:

frequency = speed of sound/wavelength

Substituting the given values, we get:

frequency = 1540 m/s / (7.52 x 10^-5 m)

frequency = 20.48 x 10^6 Hz

Therefore, a frequency of 20.48 MHz (megahertz) is required to create a sound wave with a wavelength of 7.52 x 10^-5 m in human tissue.

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Answer:

Explanation:

Momentum is defined as a physical quantity that takes into cognisance the product of mass of a body and its velocity. It's unit is kgm/s

Momentum = mv

Angular Momentum is defined as the quantity of rotation of a body that measures the product of its moment of inertia with respect to its angular velocity. Because it deals with rotation is what differs it from ordinary momentum. It's unit is kgm²/s

Angular Momentum = mvr

Kinetic Energy is defined as the energy a body posses as a result of it being in motion. The unit of Kinetic Energy is J

Kinetic Energy = ½mv²

The dimensions of these quantities are

Momentum => MLT^−1

Angular Momentum => ML²T^−1

Kinetic Energy => ML²T^-2

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Answer:

water vapor

Explanation:

did assignment on edge

The heat supplied the engine per second is 736 kJ and the heat discarded by the engine per second is 526 kJ.

A gasoline engine has a power output of 210kW and the effciency of engine is 28.5%. The Work done of the engine in time 1s is,

Work done = power × time

                   = 210 × 1

                  = 210 kJ

The work done of the engine is,W = 210 kW.

The efficiency of the engine,η = Work / (Qh)

Qh is the heat suppllied to the engine, η is the efficiency and is equal to 28.5 %

Qh = 210kW / (0.285)

    = 736.8 kW

The heat discarded by the engine,

(Qc) = Qh - W'

       =  736.8 - 210

       =526.8 kW

The heat discarded by the engine, (Qc) = 526.8 kW

The heat supplied to the engine, (Qh) = 736.8 kW.

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(i) The total force acting on the train is the driving force minus the total resistance to motion. The total resistance to motion is the sum of the resistances of the three trucks. Therefore, the total force acting on the train is:

F = 37,000 N - (1,200 kg + 900 kg + 600 kg) ₓ 9.8 m/s² = 37,000 N - 25,740 N = 11,260 N

The acceleration of the train is given by the formula:

a = F / (m1 + m2 + m3) = 11,260 N / (1,200 kg + 900 kg + 600 kg) = 0.3 m/s²

Therefore, the acceleration of the train is 0.3 m/s².

(ii) The forces acting on truck Z are the driving force, the force in the coupling between trucks Y and Z, and the resistance to motion of truck Z. The diagram showing all the forces acting on truck Z in the line of its motion is:

Driving force ≥ Truck Z ≤ Force in coupling Y and Z ≤ Resistance to motion of truck Z

(iii) With the driving force removed and brakes applied, the total resistance to motion is the sum of the resistances of the three trucks and the additional resistance due to the brakes. Therefore, the total resistance to motion is:

R = (1,200 kg + 900 kg + 600 kg) ₓ 9.8 m/s²+ 11,000 N = 25,740 N + 11,000 N = 36,740 N

The total force acting on the train is the total resistance to motion. Therefore, the acceleration of the train is:

a = F / (m1 + m2 + m3) = 0 / (1,200 kg + 900 kg + 600 kg) = 0 m/s²

Therefore, the new acceleration of the train is 0 m/s².

(iv) When the brakes are applied to the engine, the force in the coupling between trucks Y and Z is equal to the resistance to motion of truck Z. Therefore, the force in the coupling between trucks Y and Z is:

F = 600 kg ² 9.8 m/s² + 11,000 N = 5,880 N + 11,000 N = 16,880 N

The force in the coupling between trucks Y and Z is a tension.

When the brakes are applied to truck Z, the force in the coupling between trucks Y and Z is equal to the resistance to motion of truck Z plus the resistance to motion of the engine and the trucks in front of truck Y. Therefore, the force in the coupling between trucks Y and Z is:

F = (600 kg + 900 kg + 1,200 kg) ₓ9.8 m/s² + 11,000 N = 17,640 N + 11,000 N = 28,640 N

The force in the coupling between trucks Y and Z is a thrust.

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If a particle's velocity is nonzero, then its acceleration can be zero, because acceleration is the rate of change of velocity. If the velocity is constant and does not change, the acceleration is zero.

The rate of change of an object's velocity with respect to time is defined as acceleration. Vector quantities are accelerations. The orientation of an object's acceleration is determined by the orientation of its net force.

Because velocity is both a speed and a direction, there are only two ways to accelerate: modify your speed or your direction—or both.

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The net force on q₂ will be  1.07 x 10⁻² N, pointing to the left.

To find the net force on particle q₂, we need to calculate the force due to q₁  and q₃ individually and then add them up vectorially. We can use Coulomb's law to calculate the force between two point charges:

F = k × (q₁ × q₂) / r²

where F is the magnitude of the force, k is Coulomb's constant (k = 8.99 x 10⁹ Nm²/C²), q1 and q2 are the charges of the two particles, and r is the distance between them.

The force due to q₁ on q₂ can be calculated as:

F₁ = k × (q₁ × q₂) / r₁²

where r1 is the distance between q₁ and q₂ (r₁ = 0.180 m).

Similarly, the force due to q₃ on q₂ can be calculated as:

F₂ = k × (q₃ × q₂) / r₃²

where r₃ is the distance between q₂ and q₃ (r₃= 0.230 m).

The direction of each force can be determined by the direction of the electric field due to each charge. Since q₁ and q₃ have opposite signs, their electric fields point in opposite directions. Therefore, the force due to q₁ points to the left and the force due to q₃ points to the right.

To find the net force, we need to add up the forces vectorially. Since the forces due to q₁ and q₃ are in opposite directions, we can subtract the magnitude of the force due to q₃ from the magnitude of the force due to q₁ to get the net force on q₂:

Fnet = F₁ - F₃

Substituting the values we get:

Fnet = k × (q₁ × q₂) / r₁² - k × (q₃ × q₂) / r₃²

Plugging in the values we get:

Fnet = (8.99 x 10⁹ Nm²/C²) × [(9.33 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.180 m)² - (-8.42 x 10⁻⁶ C) × (4.22 x 10⁻⁶ C) / (0.230 m)²]

Fnet = 1.07 x 10⁻² N

Therefore, the net force on q₂ is 1.07 x 10⁻² N, pointing to the left.

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The potential energy of the climber is 6.94 × 10⁶. It is the energy which is present in the body of an object which is at rest. Thus, the correct option is A.

Potential energy is the energy which is present in the body of an object which is at rest. This energy is transformed into kinetic energy when the body experiences any force and undergo motion. The SI unit of potential energy is Joule (J).

PE = m × g × h

where, PE = Potential energy,

m = mass of the object,

g = acceleration due to gravity,

h = height

PE = 80 × 9.8 × 8848

PE = 80 × 9.8 × 8848

PE = 784 × 8848

PE = 6936832

PE = 6.94 × 10⁶

Therefore, the potential energy of the climber is 6.94 × 10⁶.

Therefore, the correct option is A.

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A) Baby's vertical velocity when Johnny releases her is 12.5 m/s upward. B) Assuming Baby's center of gravity was 1.5 m above the floor when Johnny released her, she will reach a peak height of approximately 1.87 m above her initial height.

A) To find Baby's vertical velocity when Johnny releases her, we can use the equation:

F = ma

where F is the force applied to Baby, m is her mass, and a is her acceleration. Since Johnny exerts a vertical force of 500 N for 1.0 s, we can calculate the acceleration:

a = F/m = 500 N / 40 kg = 12.5 m/s²

We also know that Baby starts from rest, so we can use the equation:

v = u + at

where v is the final velocity, u is the initial velocity (which is zero), a is the acceleration, and t is the time interval during which the force is applied. In this case, t is 1.0 s, so we have:

v = 0 + (12.5 m/s²)(1.0 s) = 12.5 m/s upward

Therefore, Baby's vertical velocity when Johnny releases her is 12.5 m/s upward.

B) To find the peak height Baby will reach, we can use the equation:

h = ut + 0.5a*t²

where h is the vertical displacement (or peak height), u is the initial velocity (which is 12.5 m/s upward), t is the time interval during which Baby is in the air, and a is the acceleration due to gravity (-9.8 m/s^2).

To find the time Baby is in the air, we can use the fact that the upward and downward portions of her motion take equal time:

t = 2u/a = 2(12.5 m/s)/(9.8 m/s²) = 2.55 s

Using this value of t, we can find the peak height:

h = (12.5 m/s)(2.55 s) + 0.5*(-9.8 m/s²)*(2.55 s)² + 1.5 m

h = 19.68 m + 33.26 m + 1.5 m = 54.44 m

However, this answer doesn't make sense in the context of the problem, since Baby would have been thrown far above the ceiling. It's likely that the question meant to give a different height for Baby's center of gravity. Assuming that Baby's center of gravity was actually 1.5 m above the floor when Johnny released her, we can calculate the peak height as follows:

h = (12.5 m/s)(2.55 s) + 0.5*(-9.8 m/s^2)*(2.55 s)² + 1.5 m + 1.5 m

h = 19.68 m + 33.26 m + 3 m = 55.94 m

Therefore, Baby will reach a peak height of approximately 1.87 m above her initial height.

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The young's modulus in a cantilever will be 3.92 x 10¹⁰ N/m².

Young's modulus (E) is a material property that indicates how easily it can stretch and deform and is defined as the ratio of tensile stress () to tensile strain (). Where stress denotes the amount of force applied per unit area ( = F/A) and strain denotes the extension per unit length

Given that the length is 1m which is suspended by a load of 150g. The depression is found to be 4cm. The thickness of the beam is 5mm and the breath is 3cm.

The young's modulus will be calculated by the formula below,

Y = (4gl³) / (bd³) x ( M / y )

Y = ( 4 x 9.81 x 1³ x 0.150 ) / ( 0.03 x 0.005³ x 0.04 )

Y = 3.92 x 10¹⁰ N/m².

Therefore, young's modulus will be 3.92 x 10¹⁰ N/m².

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The maximum overhang possible for the two bricks (without tripping) is 15m.

Given,

          Length of the brick (L) = 24m

          Maximum overhang = 12m

          Length of second brick = 24m

          Maximum overhang for two bricks =?

Now,

Generally, the equation for the value x (mid-point joining the bricks)             is given as,

x = 0.25 × L

  =0.25 × 12

  = 3m

Hence,

The maximum overhang possible for the two bricks (without tripping) will be,

L₀ = L/2 + x

    = 24/2 + 3

    = 12 + 3

    = 15m

Therefore, The maximum overhang possible for the two bricks (without tripping) is 15m.

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The net work must be done on the particle to cause it to move to the right at 47 m/s is 59.4J, The spring constant of spring is 281.75N/m and the length of spring stretched is 0.02m.

(1.)Given the mass of particle (m) = 75g = 0.075kg

The velocity of particle (Vl) towards left = 25m/s

The velocity of particle towards right (Vr) = 47m/s

The work done to move the particle from left to right = W

Here work done can be considered as change in Kinetic energy then:

W = (KEf - KEi)

\(W = 1/2*m*Vr^2 - 1/2*m*Vl^2\)

\(W = (1/2)*75 g*(47 m/s)^2 - (1/2)*75 g*(25 m/s)^2\)

\(W = (1/2)*75 g*(1584 m^2/s^2)\)

W = 59.4J

Therefore, the net work required to cause the particle to move from 25 m/s to 47 m/s is 59.4 J.

(2.) Given the length of spring = 8cm = 0.08m

The mass of block = 2.3kg

The extension in spring = 16cm = 0.16m

Let the spring constant = k

(A) We know that the force exerted in stretching the spring = F = kx where

F = mg then

mg = kx

2.3 * 9.8 = k * (0.16 - 0.08)

k = 22.54/0.08 = 281.75N/m

(B) The mass of new block = 3kg

Let the extended spring = x'

Then mg = kx' such that:

3 * 9.8 = 281.75 * x'

x' = 29.4/281.75 = 0.10m

the extension in spring = 0.10 - 0.08 = 0.02m

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Answer: B. what is super speed when it loses contact

Explanation:

Answer:Correct option is B)

In horizontal direction, two forces are acting on the block : 100 N force and friction force (f)

f=μN=μmg=0.5×10×10=50N

So, net force acting on the block in horizontal direction = 100 N-50 N = 50 N

acceleration of the block = Net force / mass of block = 50 N/10 kg = 5 ms

−2

Solve any question of Laws of Motion with:-

Explanation:

The ball's exit velocity from the boy's hand was 39.4 m/s.

The time it took the ball to reach its highest point is 4 seconds, which is the explanation.

Use the first equation of motion, v = u + gt, to determine the ball's initial velocity when it left the boy's hand.

Initial velocity (v) is used here. terminal velocity is u. t is the amount of time, and g is the gravitational acceleration, with a value of 9.8 m/s2.

At its highest point, the ball's final velocity, v, equals zero.

When the supplied values are substituted in the equation above, we get 0=u-9.8m/s2.

Therefore, the ball's exit velocity from the boy's hand was 39.4 m/s.

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the frictional force on the broom has magnitude μ * m * g * cos(theta)

The frictional force on the broom can be determined using the equation:

F_friction = μ * F_norm

Where F_friction is the frictional force, μ is the coefficient of friction, and F_norm is the normal force. The normal force is equal to the force exerted on the broom perpendicular to the surface of the floor. Since the broom is being pushed across a horizontal surface, the normal force is equal to the force of gravity, which is equal to the mass of the broom (m) multiplied by the acceleration due to gravity (g).

F_norm = m * g

The force being applied to the broom is 7N and it is at angle theta with the horizontal. The component of this force perpendicular to the surface of the floor is the force that acts on the normal force.

F_norm = 7 * cos(theta)

Therefore,

F_friction = μ * m * g * cos(theta)

So, the frictional force on the broom has magnitude μ * m * g * cos(theta)

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Answer:

New acceleration = 1.5 m/s²

Explanation:

The acceleration of an object when it moves in a circular path is given by :

\(a=\dfrac{v^2}{r}\)

Where

v is speed of an object

r is radius of path

If v remains constant,

\(a\propto \dfrac{1}{r}\)

or

\(\dfrac{a_1}{a_2}=\dfrac{r_2}{r_1}\)

Put r₁ = 5 m, a₁ = 3m/s², r₂ = 10 m

\(a_2=\dfrac{a_1r_1}{r_2}\\\\a_2=\dfrac{3\times 5}{10}\\\\a_2=1.5\ m/s^2\)

Hence, if the radius of its path is increased to 10 m, its acceleration will be 1.5 m/s².

Answer:

Is the vector is(mathematics) a directed quantity, one with both magnitude and direction, the (soplink) between two points while velocity is (physics) a vector quant that denotes the rate of change of position with respect to time or a speed with the directional component.

Answer:

Explanation:

If the work done on the cart is NET work

Then the work will result in an increase in kinetic energy

KE₀ + W = KE₁

½mv₀² + W = ½mv₁²

½(0.80)(0.61²) + 0.91 = ½(0.80)v₁²

v₁ = 1.626991...

v₁ = 1.6 m/s

The speed of the cart at the second point of observation is equal to 1.62 m/s.

Work can be demonstrated as the energy utilized when a force is exerted to make an object move through a particular displacement. Work done by this force is calculated from the product of the magnitude of the exerted force (F) and the distance (d) covered by the body

W= F.d

Where 'F' is the exerted force and 'd' is the displacement and W is work done.

Work and energy have a direct relationship with each other. Work done by an object can be expressed as a change in kinetic energy:

\(W =\frac{1}{2}mv_2^2- \frac{1}{2}mv_1^2\)

Where m is the mass of the object, v₂ is the final velocity (m/s), and v₁ is the initial velocity (m/s).

Given, the work done by the cart, W = 0.91 J

The mass of the cart, m = 0.80 Kg

The speed of the cart at the first point, v₁ = 0.61 m/s

\(0.91 =\frac{1}{2}\times 0.80 \times v_2^2- \frac{1}{2}0.80 \times (0.61)^2\)

0.40 v₂² = 1.06

v₂² = 2.65

v₂ = 1.62 m/s

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Find the duration of time that the stationary observer is measuring. In the formula for the Lorentz factor, = (1 - v2/c2), replace v with the traveling viewer's velocity. The time determined by moving observer is the outcome.

It is theoretically conceivable for passenger in a quickly vehicle to travel into the future inside a brief amount of their own time because to time dilation. When traveling at high enough speeds, the impact is dramatic. For instance, ten years on Earth could be equivalent to one year of travel.

The difference here between elapsed times of two occurrences measured by either traveling relative to one another or by being placed away from gravity mass or masses is referred to as time dilation in the theory of relativity.

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Okay, here are the steps to calculate the full distance traveled when an object is thrown at a certain speed and angle:

You have the initial velocity (v): 35 m/s

You have the launch angle (θ): 45 degrees

We need to split the initial velocity into its horizontal (vx) and vertical (vy) components.

To calculate vx (horizontal component):

vx = v * cosθ

vx = 35 * cos(45) = 24.7 m/s

To calculate vy (vertical component):

vy = v * sinθ

vy = 35 * sin(45) = 24.7 m/s

We can calculate the horizontal distance (d) traveled using:

d = vx * t (where t is time)

Since there is no air resistance, the vertical velocity (vy) will remain constant. This means the time the object is in the air is:

t = vy / g (where g is acceleration due to gravity, 9.8 m/s^2)

t = 24.7 / 9.8 = 2.52 seconds

Now we can calculate the full horizontal distance traveled:

d = vx * t

d = 24.7 * 2.52

= 62.3 meters

So the full distance the object will travel when thrown at 35 m/s at a 45 degree angle is approximately 62 meters.

Let me know if you have any other questions!

Answer:

To calculate the full distance traveled by an object thrown at a velocity of 35 m/s at an angle of 45 degrees, we need to consider the horizontal and vertical components of the motion separately.

The horizontal component of the motion remains constant throughout the trajectory and is given by:

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

In this case, the initial velocity is 35 m/s, the angle is 45 degrees, and we need to find the time of flight.

The time of flight can be calculated using the vertical component of the motion. The vertical motion can be described using the equation:

Vertical displacement = (Initial velocity * sin(angle))^2 / (2 * acceleration)

Where the initial velocity is 35 m/s, the angle is 45 degrees, and the acceleration is the acceleration due to gravity, approximately 9.8 m/s^2.

The vertical displacement is zero at the highest point of the trajectory since the object comes back down to the same height it was launched from. So we can solve the equation for the time of flight.

Using these calculations, we can find the horizontal distance traveled by the object.

Let's calculate step by step:

Step 1: Calculate the time of flight

Vertical displacement = 0 (at the highest point)

0 = (35 * sin(45))^2 / (2 * 9.8)

0 = (24.75^2) / 19.6

0 = 616.0125 / 19.6

0 = 31.43

Step 2: Calculate the time of flight

Vertical displacement = (Initial velocity * sin(angle)) * time - (1/2) * acceleration * time^2

0 = (35 * sin(45)) * time - (1/2) * 9.8 * time^2

0 = 24.75 * time - 4.9 * time^2

4.9 * time^2 - 24.75 * time = 0

time * (4.9 * time - 24.75) = 0

time = 0 (initial point) or 24.75 / 4.9

time = 5.05 seconds

Step 3: Calculate the horizontal distance

Horizontal distance = (Initial velocity) * (Time of flight) * cos(angle)

Horizontal distance = 35 * 5.05 * cos(45)

Horizontal distance = 35 * 5.05 * (sqrt(2)/2)

Horizontal distance = 88.96 meters