the condition in which certain colors are diminished as depth increases is called:
Answers
The condition in which certain colors are diminished as depth increases is called color attenuation. This refers to a phenomenon where colors become less vibrant and fade as the distance between the observer and the object increases.
This happens due to the scattering of light by particles in the atmosphere, which reduces the intensity of the light and alters the color perception of the viewer.
As a result, the colors of objects that are far away appear less vivid and washed out, while those that are closer look brighter and more saturated. This effect is particularly noticeable in outdoor scenes where the distance between objects is significant.
The degree of color attenuation depends on the distance between the viewer and the object, the angle of incidence of the light, the quality of the atmosphere, and the presence of any obstructions that might block or reflect light.
Color attenuation is a common phenomenon in outdoor photography and can be used to create depth and dimension in images. Photographers often use color correction techniques to compensate for the loss of color and contrast that occurs when shooting at a distance.
In conclusion, color attenuation is the condition in which certain colors are diminished as depth increases. It is caused by the scattering of light by particles in the atmosphere, which reduces the intensity of light and alters the color perception of the viewer. This phenomenon is particularly noticeable in outdoor scenes and is commonly observed in photography.
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Related Questions
Which statement accurately describes the use of radioactive decay?
Technetium-99 is used as a radioactive tracer because it remains in the body for a long time.
Some types of cancer cells are killed by directing alpha rays at the tumor from outside the body.
Plants utilize radioisotopes in the same way they use nonradioisotopes because they are chemically identical.
Geologists and archaeologists use different dating processes to determine the age of rocks, fossils, and ancient artifacts.
Answers
Answer:
O. Geologists and archaeologists use different dating processes to determine the age of rocks, fossils, and ancient artifacts.
Explanation:
Redioactive decay is the process whereby the radioactive materials reduces in quantity through the decay of its materials.
For example, if there where 100g of polonium today, and 5 years later, it has reduced to 30g, then, radioactive decay has taken place over the long period of time.
One of its major use is in the determination of the ages of rocks, fossils, and ancient artifiacts through its cabon dating inorder to determining the radioactive decay of those materials over the past few decades.
the density of atoms in the interstellar medium is most similar to
Answers
The density of atoms in the interstellar medium is most similar to the density of atoms in a laboratory vacuum.
Interstellar medium is the stuff that fills the space between the stars in a galaxy. The interstellar medium is comprised of various particles, including gas (mostly hydrogen and helium), cosmic rays, and dust. Interstellar space, also known as space between the stars, is filled with vast distances of emptiness, which makes the idea of any kind of density quite challenging.
However, the density of atoms in the interstellar medium is most similar to the density of atoms in a laboratory vacuum. The majority of interstellar space contains less than one atom per cubic centimeter (one atom/cm³) in volume, which means that it is a better vacuum than any vacuum that can be created in a lab.
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A capacitor is made by taking two sheets of aluminum foil, each 0.022 mm thick and placing between them a sheet of paper which comes from a ream of 500 sheets, the ream being 5.5 cm thick with sheets measuring 216 mm by 279 mm. What is the capacitance of the capacitor made this way if the dielectric constant of the paper is 3.7?
THE ANSWER SHOULD BE (18nF)
Answers
The capacitance of the capacitor if the dielectric constant of the paper is 3.7 : 18 nF
Given data :
Thickness of aluminium capacitor = 0.022 mm
Number of sheets = 500
Thickness of ream = 5.5 cm = 0.055 m
measurement of sheets = 0.216 m by 0.279 m
dielectric constant ( k ) = 3.7
Determine the capacitance of the capacitorwe will apply the capacitance formula below
C = Kε₀A / d
= 3.7 * 8.85*10⁻¹² * 0.216 *0.279 / ( 0.055 / 500 )
= 1.8 * 10⁻⁸F ≈ 18nF
Hence we can conclude that The capacitance of the capacitor if the dielectric constant of the paper is 3.7 : 18 nF
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Solve for x in the following diagram:
Answers
Answer:
x = 5.7876
Explanation:
You can use tan Θ to solve this.
Given that,
Tan Θ = 24°
Opposite = x
Adjacent = 13
Let us solve now.
Tan Θ = Opposite ÷ Adjacent
Tan 24° = x ÷ 13
0.4452 = x ÷ 13
0.4452 × 13 = x
5.7876 = x
Therefore,
x = 5.7876
How is a mixture different from a compound?
Answers
Answer:
MIXTURE
1 In a mixture two or more substances are mixed together (elements or compounds)
2Therd is no fixed proportion of the constituents
3 The mixture may or may not be homogenous
4 There is no chemical reaction between the constituent substances
5 There cannot be a chemical formula for a mixture
6 Heat or any other type of energy is not required or released during the formation of a mixture
7 The constituents can be separated using simple physical processes
8 The properties of the constituents are retaied
COMPOUND
1 Two or more elements form a compound
2 The constituent elements combine in a definite proportion to form a compound
3 The elements are in a definite proportion in any part or fraction of the compound
4 There is a chemical reaction in the formation of a compound
5 A compound has always a chemical formula for a compound
6 Heat orany other energy is often required for the formation of a compound or released during the formation of a compound
7 The constituent elements can't be separated using simple physical processes in case of a compound
8 The properties of the constituent elements are not retained in the compound
The force causes the car to move at a constant speed of 3 m/s. What will happen if the force is changed to 35 N?
Answers
The question is incomplete, the complete question is;
A car is moving at a constant speed of 3 m/s when a force of 25N is acting on it. What will happen if the force is changed to 35N?
The car will move at a constant speed of 13 m/s
The speed of the car will not change.
The speed of the car will increase.
The speed of the car will decrease to 1 m/s
Answer:
The speed of the car will increase.
Explanation:
When a the force acting on an object moving at constant velocity is changed, its velocity changes accordingly.
The question said that the car was moving at a constant velocity of 3m/s when a 25 N force is applied, then the car must move faster than 3 m/s when a 35 N force is applied since the 35N force is greater than the 25 N force.
Hence the answer above.
Does an object with constant speed also have constant velocity?. Single choice.
Answers
Answer: No, constant speed does not mean constant velocity.
A classic often used example would be to consider a car driving in circles. If the speedometer reads say 20 mph the entire time, then the speed of the car is held constant (ie the same). But the velocity is changing because velocity measures direction along with speed. The car is changing direction as it moves in a circle.
For freely falling objects near earth's surface, _____ is constant.
A
acceleration
B
speed
C
velocity
D
momentum
Answers
The correct option is A. acceleration.
For freely falling objects near Earth's surface, acceleration is constant. An object that is allowed to fall freely under the influence of Earth's gravity is known as a freely falling object. Gravity is an acceleration that acts on any two masses.
For freely falling objects near Earth's surface, the acceleration is indeed constant. This fundamental concept is a result of gravity's influence on objects in free fall. When an object is in free fall, it means that no forces other than gravity are acting upon it. In this scenario, the acceleration experienced by the object remains constant and is equal to the acceleration due to gravity, which is approximately 9.8 meters per second squared (m/s²) near Earth's surface.
The constancy of acceleration in free fall can be attributed to the consistent force of gravity acting on the object. Gravity pulls objects downward towards the center of the Earth, causing them to accelerate uniformly. Regardless of the object's mass, shape, or composition, the acceleration remains constant. This is known as the equivalence principle, which states that all objects experience the same acceleration due to gravity in the absence of other forces.
As an object falls freely, its velocity increases at a steady rate. Each second, the object's velocity increases by approximately 9.8 m/s. This means that in the first second, the velocity increases by 9.8 m/s, in the second second it increases by an additional 9.8 m/s, and so on. The consistent acceleration enables the object to cover greater distances in successive time intervals.
In conclusion, for freely falling objects near Earth's surface, the acceleration remains constant at approximately 9.8 m/s². This constancy arises from the unchanging force of gravity acting on the objects, leading to a uniform increase in velocity over time.
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A tennis ball is thrown straight up into the air with an initial velocity of 12.7 m/s. How high does the tennis ball travel?
Answers
Answer:
8.22m
Explanation:
As interpreted from this problem, the angle of launch is 90 degrees as it is thrown straight up. Given an angle launch of 90°, upward initial velocity of 12.7m/s, and initial height of 0m. A much simpler equation can be used to find the maximum height.
\(h_{max} = h_ {0} + \frac{{v_0}^{2} }{2g}\)
this means that the max height is equal to the initial height plus the initial velocity squared divided by 2 times the acceleration of earth's gravity(≈9.8m/s^2 or 10m/s^2 depending on how you fix it).
when substituted into the equation, you should get.
(9.8m/s^2)
hmax = 0 + ((12.7)^2)/(2*9.8)
hmax = 161.29/19.6 ≈ 8.22
hmax = 8.22m
Which scenario does not describe an example of acceleration?
A car increases its speed while turning to the left.
A car decreases its speed while driving straight ahead.
A car maintains a constant speed while turning to the right.
A car maintains a constant speed while driving straight ahead.
Answers
Answer:
B is the right answer
Explanation:
It is decreasing.
A car maintains a constant speed while driving straight ahead.
What is acceleration?The acceleration of an object is the rate of change of velocity with time. It is measured in meter per second square.
Velocity of the carThe car undergoes velocity when there is change in direction of the speed.
Thus, the only option that does not describe acceleration is a car maintains a constant speed while driving straight ahead.
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The forces exerted by Earth and a skier become an action-reaction force pair when the skier pushes the ski poles against Earth. Explain why the skier accelerates while Earth does not seem to move at all.
Answers
Because of the earth's large mass and solid structure, the skier moves but the earth does not.
Why can't the earth be moved?Because the Earth is such a massive body, it cannot be moved by applying force to it. Because it cannot be moved with a small amount of forceThe amount of matter contained in an object is what gives it inertia, or the tendency of matter to remain at rest if at rest, or to continue moving in the same direction at the same speed if moving. The greater an object's mass, the greater its gravitational force.Mass is the quantity that is solely determined by an object's inertia. The greater an object's inertia, the greater its mass. A heavier object is more likely to resist changes in its state of motion. we can conclude that the skier moves but the earth does not due to the large mass of the earth and its solid structure.To learn more about earth refer to :
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Vul de ontbrekende gegevens in. afstand tijd gemiddelde snelheid 45 km 45 minuten km/h 4,5 km 80 minuten m/s 200 m s 9,0 m/s km 2 uur 85 km/h 20 km minuten 90 km/h
Answers
Antwoord:
60 km / uur; 0,9375 m / s; 22.222; 170 km; 13.333 minuten
Uitleg:
Gegeven:
Afstand ___ tijd ___ gemiddelde snelheid
45 km __45 minuten ___ km / u
4,5 km __80 minuten __m / s
200 m ___s ________ 9,0 m / s
km ____2 uur ______85 km / u
20 km_ minuten ___90 km / u
De relatie gebruiken:
Gemiddelde snelheid (s) = afstand (d) / tijd (t)
A.)
d = 45 km; t = 45 minuten = 45/60 = 0,75 uur
s = 45 / 0,75
s = 60 km / uur
B.)
d = 4,5 km = (4,5 * 1000) = 4500 m
t = 80 * 60 = 4800 s
s = 4500/4800 = 0,9375 m / s
C.)
d = 200 m; s = 9 m / s
t = 200/9 = 22,222 s
D.)
d = s * t
d = 85 * 2 = 170 km
E.)
t = d / s
t = 20/90
t = 0,22222 uur = 13,333 minuten
a
student is pushing a 55 kg box of textbooks with a horizontal force
of 320 N into their turn room across a rich sidewalk.
a. calculate the weight of the box of books.
b. calculate the coefficient of
than, answer. 6. A student is pushing a 55 kg box of textbooks with a horizontal force of 320 N into their dorm room across a rough sidewalk a Calculate the weight of the box of books? b. Calculate th
Answers
a) The weight of the box of textbooks can be calculated as follows;
Weight of
box= mass × acceleration due to gravity
Where mass= 55 kg
Acceleration due to
gravity= 9.8 m/s²Thus, the weight of the box of textbooks is given by;
Weight of
box= 55 kg× 9.8 m/s²= 539 N
the weight of the box of textbooks is 539 N.
b) The coefficient of friction can be calculated using the formula;Coefficient of friction= frictional force/ Normal forceWhere, frictional force is the force required to keep the box moving at constant velocity and normal force is the force acting on the box perpendicular to the surface on which the box is resting.
The force F of the student pushing the box can be resolved into its horizontal and vertical components as follows;
F_x= 320 N (this is the horizontal component of the force)F_y=
(This is the vertical component of the force)Thus, the normal force on the box is given by;
F_y= Normal forceNormal force= weight of box= 539 NThe frictional force is given by.
F_f= F_x= 320 NThe coefficient of friction is given by;Coefficient of friction= frictional force/ Normal forceCoefficient of friction= F_f/ F_yCoefficient of friction= 320 N/ 539 NCoefficient of friction= 0.593Therefore, the coefficient of friction is 0.593.
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Gerald went wingsuit gliding, and jumped off a cliff at 275 m. He never studied, so his equipment didn’t work, and he plummeted to his death. Calculate the final velocity, just before colliding with the ground.
A. 28.0 m/s
B. 14.0 m/s
C. 73.4 m/a
D. 5390 m/s
Answers
The final velocity, just before colliding with the ground is 73.4 m/s
As per the statement, we are given
since Gerald jumped off a cliff means initial velocity is zero
so u=0
height of a cliff is 275 m h=275
and he falling with g acceleration
so a=g
now we use kinematics equation to find final velocity
v=?
v^2-u^2=2gh
v^2=2gh
v^2=2×9.8×275
v^2=5390
v=73.4m/s
Kinematics examines the mechanisms through which a body's position changes over time. It describes how an object's location is determined by its overall velocity and acceleration. An object's motion is described in this area of mechanics. The frame of reference affects how an object's motion is studied.The earth revolves around the sun, whereas the moon revolves around the moon. The moon will therefore have two speeds, one relative to the earth and the other relative to the sun. The frame of reference is fixed with the earth in the former and fixed with the sun in the latter.To know more about Kinematics visit : https://brainly.com/question/7590442
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The gravitational force between a satellite and Earth’s moon is 324 N. The mass of the moon is 7.3 × 1022 kg.
If the distance from the moon to the satellite is 2.6 × 106 m, what is the mass of the satellite?
1.7 × 10–4 kg
2.2 × 10–3 kg
230 kg
450 kg
Answers
Answer:
450 kg
Explanation:
In the picture above. Goodluck
Answer:
The correct answer is D :)
Explanation:
Got it right edge 2021
:3333333333333333333333
Answers
Answer:
Cannot see all the answer choices but, when pressure goes up, volume goes down. So your best bet is to choose the graph that has a downward slant.
Explanation:
A particle with a charge of −6.6μC is moving in a uniform magnetic field of B
=− (1.65×10 2
T) k
^
with a velocity: v
=(3.62 ×10 4
m/s) i
^
+(8.6×10 4
m/s) j
^
. (a) Calculate the x component of the magnetic force (in N) on the particle? (b) Calculate the y component of the magnetic force (in N) on the particle?
Answers
The x-component of the magnetic force on the particle is -4.47 N, and the y-component of the magnetic force on the particle is 1.43 N.
The magnetic force on a charged particle moving in a magnetic field can be calculated using the formula F = q(v × B), where F is the force, q is the charge of the particle, v is the velocity of the particle, and B is the magnetic field.
(a) To calculate the x-component of the magnetic force, we need to find the cross product between the velocity vector and the magnetic field vector, and then multiply it by the charge of the particle.
The cross product of the velocity and magnetic field vectors is given by \(v * B = (v_y * B_z - v_z * B_y) i + (v_z * B_x - v_x * B_z) j + (v_x * B_y - v_y * B_x) k.\) Substituting the given values, we have\(v * B = (-8.6 * 10^4 m/s * (-1.65 * 10^2 T)) i + (3.62 * 10^4 m/s * (-1.65 * 10^2 T)) j\). Multiplying this by the charge of the particle, we get \(F_x = -6.6 * 10^-6 C * (-8.6 * 10^4 m/s * (-1.65 * 10^2 T)) = -4.47 N.\)
(b) Similarly, to calculate the y-component of the magnetic force, we use the formula \(F_y = q(v_z * B_x - v_x * B_z)\). Substituting the given values, we have \(F_y = -6.6 * 10^-6 C * (3.62 * 10^4 m/s * (-1.65 * 10^2 T)) = 1.43 N.\) Therefore, the x-component of the magnetic force is -4.47 N and the y-component of the magnetic force is 1.43 N.
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A higher frequency is often perceived as having lower pitch.
true
false
Answers
The given statement " A higher frequency is often perceived as having lower pitch" is false. Because pitch is closely related to the frequency of a sound wave - the higher the frequency, the higher the pitch.
Pitch is a perceptual characteristic of sound that relates to the frequency of a sound wave. Frequency is the number of cycles of a sound wave that occur in one second, measured in Hertz (Hz).
Higher frequencies have more cycles per second than lower frequencies. Therefore, when we hear a sound with a higher frequency, our brain interprets it as having a higher pitch.
It is possible that the question may have been asking about the perception of the amplitude (volume) of a sound wave. In this case, it could be true that a higher frequency sound is perceived as having a lower volume, as some frequencies may be less audible to the human ear. However, it is important to note that the original question was about pitch, not volume.
Therefore, the given statement is false
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When the bug that is creating waves swims in the direction of the waves, how does the speed of the wave some distance away in front of the bug compare with the speed of the wave created by a stationary bug
Answers
When a bug creates waves while swimming, the speed of the wave some distance away in front of the bug is slower compared to the speed of the wave created by a stationary bug. This is because the bug is swimming in the direction of the waves, adding its own speed to the speed of the waves, making them appear to be slower.
The bug is essentially catching up to its own waves, causing them to bunch up in front of it, resulting in a shorter wavelength and slower speed. This phenomenon is known as Doppler effect, where the apparent frequency and wavelength of waves change due to the motion of the source. Therefore, the speed of waves in front of the bug is slower, but the frequency remains the same, causing a change in wavelength.
Hi! When a bug that creates waves swims in the direction of the waves, the speed of the wave in front of the bug will be greater than the speed of the wave created by a stationary bug. This is because the moving bug adds its own speed to the waves it generates, causing them to travel faster in the direction the bug is moving. In contrast, waves created by a stationary bug only have the speed generated by the bug's movement in the water. To summarize, a swimming bug generates faster waves in front of it compared to a stationary bug.
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Please select the word from the list that best fits the definition
state of most nonmetals at room temperature
options: left, gas, semiconductor, halogen, right, solid, carbon nitrogen
Answers
Answer:
the answer is gas if I'm not mistaken.
Explanation:
Don't come at me if I'm wrong please :')
Please help me, I am following along diligently. V(t) = t^2 -9t+18, with distance, s measured in meters, left or right of 0, and t measured in seconds, with t between 0 and 8 seconds inclusive. The position at time t=0 sec is 1 meter right of 0, that is s(0)= 1Part I: Average velocity over the interval 0 to 8 secondsPart II: The instantaneous velocity and speed at time 5 secsPart III: The time intervals when the particle is moving rightPart IV: The time intervals when the particle is going faster, and slowing downPart V: Total distance the particle has traveled between 0 and 8 seconds
Answers
Given that the velocity at any time t is
\(v(t)=t^2-9t+18\)Also, the time interval is from t = 0 to t = 8 seconds
The position at time t = 0 s is s(0) = 1 m towards right of zero.
The initial time is t = 0 s, so the initial velocity will be
\(\begin{gathered} v_i(t=0)=0^2-9\times0+18\text{ } \\ v_i(0)\text{ = 18 m/s} \end{gathered}\)The final time is t = 8 s, so the final velocity will be
\(\begin{gathered} v_f(t=8)=8^2-9\times8+18 \\ v_f(8)\text{ = 64-72+18} \\ =\text{ 10 m/s} \end{gathered}\)The average velocity will be
\(\begin{gathered} v_{av}=\frac{v_i+v_f}{2} \\ =\frac{18+10}{2} \\ =14\text{ m/s} \end{gathered}\)Thus, the average velocity is 14 m/s.
Part II:
The instantaneous velocity at time t =5 s will be
\(\begin{gathered} v(t=5)=5^2-9\times5+18 \\ =25-45+18 \\ =-2\text{ m/s} \end{gathered}\)The instantaneous speed is the magnitude of instantaneous velocity.
Thus, the instantaneous speed will be 2 m/s.
Part III:
The particle will move towards the right when v(t) > 0
The time intervals will be
\(\begin{gathered} t^2-9t+18>0 \\ t^2-6t-3t+18>0 \\ t(t-6)-3(t-6)>0 \\ (t-6)(t-3)>0 \\ t-6>0\text{ or t>6} \\ t-3>0\text{ ot t>3} \end{gathered}\)Thus, time intervals are t > 3 and t > 6 when the particle is moving towards the right.
Part IV :
The particle will move faster if the acceleration, a(t) > 0
The particle will slow down if the acceleration, a(t) < 0
So, first, we need to find the acceleration, it can be calculated as
\(\begin{gathered} a(t)=\text{ }\frac{d(v(t))}{dt} \\ =\frac{d(t^2-9t+18)}{dt} \\ =2t-9 \end{gathered}\)For the particle moving faster,
\(\begin{gathered} a(t)>0 \\ 2t-9>0 \\ 2t-9+9>9+0 \\ 2t>9 \\ \frac{2t}{2}>\frac{9}{2} \\ t>\frac{9}{2} \\ t>4.5\text{ s} \end{gathered}\)For particle slowing down,
\(\begin{gathered} a(t)<0 \\ 2t-9<0 \\ 2t-9+9<9+0_{} \\ 2t<9 \\ \frac{2t}{2}<\frac{9}{2} \\ t<4.5\text{ s} \end{gathered}\)The total distance can be calculated as
\(\begin{gathered} s(t)=\int ^8_0v(t)dt \\ =\text{ }\int ^8_0(t^2-9t+18)\mathrm{d}t \\ =\lbrack\frac{t^3}{3}\rbrack^8_0-9\lbrack\frac{t^2}{2}\rbrack^8_0+18\lbrack t^{}\rbrack^8_0 \\ =\frac{1}{3}\lbrack512-0\rbrack-9\lbrack64-0\rbrack+18\lbrack8-0\rbrack \\ =\text{ 170.67-576+144} \\ =-261.33\text{ m} \end{gathered}\)Here, the negative symbol indicates it is towards the left from zero.
an air parcel rises over a mountain and cools adiabatically. which lifting mechanism has acted on this parcel?
Answers
The mountain or orographic lifting mechanism has acted on the air parcel, causing it to rise and cool adiabatically as it moves up and over the mountain.
A mountain presents a physical barrier that pushes an air parcel to ascend when it rises over it. Orographic lifting is the term for this procedure. The parcel undergoes a drop in pressure as it rises, which causes adiabatic cooling. The air parcel cools due to adiabatic expansion as it climbs, which causes a decrease in temperature.
The dry adiabatic lapse rate, which measures the temperature drop as 10°C per 1000 metres of climb, is used to describe this phenomenon. The air's ability to condense and form clouds in response to cold may also result in precipitation.
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Orographic lifting mechanism has been used.
Orographic lift of moist air coming off the ocean produces clouds along the Santa Lucia Mountains south of Monterey, California, USA (Credit: NOAA). As an example, the North Shore mountains immediately north of Vancouver often experience heavy rain and snowfall due to orographic uplift.
Detailed Answer - Hi! The lifting mechanism that has acted on the air parcel as it rises over a mountain and cools adiabatically is called Orographic Lifting. This occurs when an air mass is forced to rise over elevated terrain, such as a mountain, causing it to cool and potentially form clouds or precipitation.
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what is escape velocity
Answers
Answer:
Escape velocity is defined as the velocity which will take a body to go the infinite distance away above the surface of the earth when projected upwards.
Hope this helps...
Good luck on your assignment....
Which type of polarity is it if the magnetite is aligned with the south pole?
Answers
If the magnetite is aligned with the south pole, it indicates that the magnetite possesses a north pole. Magnetite is a naturally occurring mineral that exhibits strong magnetic properties. Like any magnet, it has two magnetic poles, the north pole and the south pole.
In a magnet, opposite poles attract each other, while like poles repel each other. The north pole of a magnet is attracted to the south pole of another magnet, while the north poles repel each other, as do the south poles.
Therefore, if the magnetite is aligned with the south pole, it means that the opposite, or north pole, is pointing in the opposite direction. The alignment of the magnetite with the south pole suggests that the north pole of a magnet would be attracted to it. This corresponds to the concept of magnetic polarity, where the north and south poles of magnets exhibit opposite polarities and attract each other.
Understanding the polarity of magnets is essential in various applications, such as magnetic compasses, electric motors, and magnetic storage devices. The proper alignment and recognition of the north and south poles are crucial for utilizing the attractive and repulsive properties of magnets in different technological and scientific contexts.
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The maximum wavelength For photoelectric emissions in tungsten is 230 nm. What wavelength of light must be use in order for electron with maximum energy of 1.5ev to be ejection
Answers
Answer:
λ = 1.8 x 10⁻⁷ m = 180 nm
Explanation:
First we find the work function of tungsten by using the following formula:
∅ = hc/λmax
where,
∅ = work function = ?
h = Plank's Constant = 6.626 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λmax = maximum wavelength for photoelectric emission = 230 nm
λmax = 2.3 x 10⁻⁷ m
Therefore,
∅ = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(2.3 x 10⁻⁷ m)
∅ = 8.64 x 10⁻¹⁹ J
Now we convert Kinetic Energy of electron into Joules:
K.E = (1.5 eV)(1.6 x 10⁻¹⁹ J/1 eV)
K.E = 2.4 x 10⁻¹⁹ J
Now, we use Einstein's Photoelectric Equation:
Energy of Photon = ∅ + K.E
Therefore,
Energy of Photon = 8.64 x 10⁻¹⁹ J + 2.4 x 10⁻¹⁹ J
Energy of Photon = 11.04 x 10⁻¹⁹ J
but,
Energy of Photon = hc/λ
where,
λ = wavelength of light = ?
Therefore,
11.04 x 10⁻¹⁹ J = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/λ
λ = (6.626 x 10⁻³⁴ J.s)(3 x 10⁸ m/s)/(11.04 x 10⁻¹⁹ J)
λ = 1.8 x 10⁻⁷ m = 180 nm
Ana exerts a force of 20 N on a volleyball that has a mass of 0.15 kg. What is the force that the volleyball exerts on Ana?
0.15 N
20 N
19.85 N
20.15 N
Answers
Answer:
20 N
Explanation:
The question above is related to "Newton's Third Law of Motion." It states that every action is being opposed by a reaction of equal size but different direction.
The action force in the situation above is 20 N while the reaction force here is the one coming from the volleyball. So if the action force is 20 N then it's a common sense that the reaction force is also 20 N.
Thus, 20 N is the amount of force that the volleyball is exerting on Ana.
Answer:
the answer is 20 N
Explanation:
yw!!
A few years ago I supervised a third year student who designed a water rocket. The first principle for the design was that it would be made out of recycled or readily available material. Consequently, the first choice was that the body of the rocket was to be a two litre plastic bottle. In the rest of this question you are free to make your own choices on the design but they must fit with the components being readily available or easily created within the engineering department. Note that this is a topic that is frequently discussed on the internet. You are free to use any resources you can find but you must acknowledge the use of pages through referencing. There is a link at the top of page 2 of this document that explains referencing, which you should already be aware of having written the paper for EG-194. a. The first stage of a design process is to develop a conceptual design. In this exercise a conceptual design is where you decide the main components of your design and what they look like. At this stage you should discuss the possibilities for the design of the water rocket. What are the options? What are the advantages and disadvantages of the options? Why did you choose the route you have chosen? In addition to answering the previous questions you should include an annotated diagram of your design. This is normally a sketch rather than a CAD drawing b. Complete a failure mode and effects analysis (FMEA) of the chosen design. Note the team exercise at the start of the module went through a form of FMEA that is suitable for this question. I expect you to cover five aspects of the design. You should focus on items that can be influenced by the design stage of the exercise, in this exercise we will not do the build and test phases. c. In order to optimise the height the rocket can attain it is necessary to develop a computational model. Using the knowledge that you have gained from year 1 of your degree and elsewhere to identify what will affect the height the rocket can reach. What physics will affect the flight of the rocket? What data will the physics require? How would you suggest the data is obtained?
Answers
When designing a water rocket made from recycled or readily available materials, the main component is typically a two-liter plastic bottle. The conceptual design options for the water rocket include variations in fins, nose cones, and deployment mechanisms.
The options for the design of a water rocket include variations in fins, nose cones, and deployment mechanisms. Fins are essential for providing stability during flight. Different fin shapes and sizes can affect the rocket's stability and control.
Larger fins generally provide better stability but may increase drag, while smaller fins can reduce stability but improve aerodynamic performance. The choice of fin design depends on the desired trade-off between stability and aerodynamics.
The nose cone design is another important consideration. A pointed nose cone reduces drag and improves aerodynamics, allowing the rocket to reach higher altitudes.
However, a pointed nose cone can be challenging to construct using readily available materials. An alternative option is a rounded nose cone, which is easier to construct but may result in slightly higher drag.
The deployment mechanism refers to the method of releasing a parachute or recovery system to slow down the rocket's descent and ensure a safe landing. The options include a simple nose cone ejection system or a more complex deployment mechanism triggered by pressure, altitude, or time. The choice of deployment mechanism depends on factors such as reliability, simplicity, and the availability of materials for construction.
In the chosen design route, the emphasis is on simplicity, stability, and ease of construction. The rocket design incorporates moderately sized fins for stability and control, a rounded nose cone for ease of construction, and a simple nose cone ejection system for parachute deployment.
This design strikes a balance between stability and aerodynamic performance while utilizing readily available or recycled materials.
To complete a failure mode and effects analysis (FMEA), five aspects of the design should be considered. These aspects can include potential failure points such as fin detachment, parachute failure to deploy, structural integrity of the bottle, leakage of water, and ejection mechanism malfunction.
By identifying these potential failure modes, appropriate design improvements and safety measures can be implemented to mitigate risks.
The height a water rocket can reach is influenced by various physics principles. Factors that affect the flight of the rocket include thrust generated by water expulsion, drag caused by air resistance, weight of the rocket, and the angle of launch.
To optimize the height, the physics data required would include the mass of the rocket, the volume and pressure of the water, the drag coefficient, and the launch angle.
Experimental data can be obtained through launch tests where the rocket's flight parameters are measured using appropriate instruments such as altimeters, accelerometers, and cameras.
By analyzing and correlating the data, the computational model can be refined to predict and optimize the rocket's maximum height.
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Transfer Functions of Electrical Systems (Special assignmen 3) There are 4 possible types of transfer functions for electrical systems. 1) Voltage Gain H_V(s) Vi(s) Electrical System V.(s) 2) Transfer Admittance H_Y(s) Vi(s) + +1 Electrical System I.(s) 3) Current Gain H_I(s) L(S) (1) 4) Transfer Impedance H_Z(s) L(S) (1) Electrical System Electrical System V.(s) I.(s) R = 12.50, L= 4H, C = 0.01F R + Vi(t) L CT Vo(t) 1) Find Vc(s)/Vs(s). 2) Show the pole-zero map. 3) Find the response to Vs(t) = u(t)V. 4) Find the response to Vs(t) = o(t)V.
Answers
The transfer function is Vc(s)/Vs(s) = (R + 1/(sC)) / (sL + R + 1/(sC)), the pole-zero map includes poles at -R/L and zeros at -1/(sC), the response to Vs(t) = u(t)V can be calculated using inverse Laplace transform techniques and the response to Vs(t) = o(t)V can also be determined using inverse Laplace transform techniques.
To find Vc(s)/Vs(s), we need to consider the given electrical system with components R, L, and C. By applying Kirchhoff's laws and solving for the output voltage Vc(s) and input voltage Vs(s) in the Laplace domain, we can derive the transfer function as (R + 1/(sC)) / (sL + R + 1/(sC)).
The pole-zero map provides insights into the stability and behavior of the system. In this case, the transfer function has poles at -R/L, indicating a time constant associated with the system's dynamics. The transfer function also has zeros at -1/(sC), which affect the frequency response characteristics.
To find the response to Vs(t) = u(t)V, where u(t) represents the unit step function, we can apply inverse Laplace transform techniques to the transfer function Vc(s)/Vs(s). This will yield the time-domain response of the system to a step input.
Similarly, to find the response to Vs(t) = o(t)V, where o(t) represents the unit impulse function, we can use inverse Laplace transform techniques on the transfer function Vc(s)/Vs(s). This will give us the time-domain response of the system to an impulse input.
By calculating the inverse Laplace transforms of the transfer functions in cases 3) and 4), we can obtain the time-domain responses of the electrical system to the respective inputs.
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HELP PLZ!!!!!
Why do things get classified as"hot" or "cold"?
Answers
Answer:
Heat flows from higher to lower temperature. So when you keep hot things in normal temperature, the heat from hot object transfers to the environment until they are both on the same level. Same happens when a cold object is kept in normal room temperature, the heat from the environment transfers to the cold object until they are both equal. its all about achieving the equilibrium in a system
(1 point) find the total mass of the triangular region shown below. all lengths are in centimeters, and the density of the region is δ(x)=4 x grams/cm2.
Answers
The total mass of a triangular region with density δ(x) = 4x is found by integrating the density function over the region and multiplying by the area. For a triangular region defined by (0,0), (8,0), and (0,16), the total mass is approximately 170.67 grams.
To find the total mass of the triangular region, we need to integrate the density function over the region and then multiply by the area. The density function is given as δ(x) = 4x grams/cm², and the triangular region is defined by the vertices (0,0), (8,0), and (0,16) in the xy-plane.
To set up the integral, we need to express the density function as a function of x and y. The density varies only with x, so we can write δ(x, y) = δ(x) = 4x grams/cm².
The integral for the total mass M is given by:
M = ∬R δ(x, y) dA
where R is the triangular region, dA is the differential area element, and the integral is taken over the region R.
We can express the differential area element dA as dA = dx dy, since the region is defined in terms of x and y.
The limits of integration for x are from 0 to 8, and for y they are from 0 to (4/8)x, since the upper boundary is defined by the line y = (1/2)x.
Therefore, we have:
M = ∫₀^₈ ∫₀^(4/8 x) δ(x) dy dx
M = ∫₀^₈ ∫₀^(4/8 x) 4x dy dx
M = ∫₀^₈ 2x² dx
M = [2/3 x³] from 0 to 8
M = (2/3)(8³) - (2/3)(0³)
M = 170.67 grams (rounded to two decimal places)
Therefore, the total mass of the triangular region is approximately 170.67 grams.
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