The continuous circular motion of the wind (air mass) between the equatorial low pressure belt and the subtropical high pressure belts is known as __________

Answers

Answer 1

The continuous circular motion of the wind (air mass) between the equatorial low pressure belt and the subtropical high pressure belts is known as Trade winds

These winds helps ships to travel west. It also steers hurricanes. These winds are air currents that are closer to the Earth's surface. These winds start as warm air from equator and as it travels to polar regions it gets cooler. Trade winds can be found 30 degrees North and South of the equator.

The subtropical high pressure belts extends from 35 degrees North and South of the equator. It is also called as Horse latitude. The equatorial low pressure belt is the area where the trade winds from Horse latitudes of both hemispheres converges.

Therefore, the continuous circular motion of the wind (air mass) between the equatorial low pressure belt and the subtropical high pressure belts is known as Trade winds

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Related Questions

In what way are networks different from other types of electrical wiring?

Answers

Answer:

Networking cables are networking hardware used to connect one network device to other network devices or to connect two or more computers to share printers, scanners etc. Different types of network cables, such as coaxial cable, optical fiber cable, and twisted pair cables, are used depending on the network's physical layer, topology, and size. The devices can be separated by a few meters (e.g. via Ethernet) or nearly unlimited distances (e.g. via the interconnections of the Internet).

There are several technologies used for network connections. Patch cables are used for short distances in offices and wiring closets. Electrical connections using twisted pair or coaxial cable are used within a building. Optical fiber cable is used for long distances or for applications requiring high bandwidth or electrical isolation. Many installations use structured cabling practices to improve reliability and maintainability. In some home and industrial applications power lines are used as network cabling.

Explanation:

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A 2011 Porsche 911 Turbo S goes from 0-27 m/s in 2.5 seconds. What is the car's acceleration?

Answers

Answer:

-10.8m/s^2

Explanation:

a=change in velocity/change in time

-27 m/s/2.5=10.8m/s^2

or if its not negative

27m/s/2.5=10.8m/s^2



A ball of mass 3.0 kg, moving at 2.0 m/s eastward, strikes head-on a ball of mass 1.0 kg that is moving at 2.0 m/s westward. The balls bounce off each other in a perfectly elastic collision. The 3.0 kg ball bounces off with a velocity = 0.66 m/s westward. What is the

velocity(speed and direction) of the 1.0 kg ball after the collision?

Answers

The velocity of the 1.0 kg ball after the collision is 4.34 m/s westward.

In an elastic collision, both momentum and kinetic energy are conserved. We can start by writing the equations for conservation of momentum and kinetic energy:

Conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

where m1 and m2 are the masses of the two balls, v1i and v2i are their initial velocities, and v1f and v2f are their final velocities.

Conservation of kinetic energy:

(1/2)m1v1i^2 + (1/2)m2v2i^2 = (1/2)m1v1f^2 + (1/2)m2v2f^2

where the terms on the left represent the initial kinetic energies of the two balls, and the terms on the right represent their final kinetic energies.

We are given the masses and initial velocities of both balls, as well as the final velocity of the 3.0 kg ball. Using these values, we can solve for the final velocity of the 1.0 kg ball:

Conservation of momentum:

m1v1i + m2v2i = m1v1f + m2v2f

(3.0 kg)(2.0 m/s) + (1.0 kg)(-2.0 m/s) = (3.0 kg)(-0.66 m/s) + (1.0 kg)(v2f)

Solving for v2f, we get:

v2f = [3.0 kg(2.0 m/s) + 1.0 kg(-2.0 m/s) - 3.0 kg(-0.66 m/s)] / 1.0 kg

v2f = 4.34 m/s westward

Therefore, the velocity of the 1.0 kg ball after the collision is 4.34 m/s westward.

The 1.0 kg ball bounces off with a velocity of 4.34 m/s westward after colliding head-on with the 3.0 kg ball, which bounces off with a velocity of 0.66 m/s westward. The collision is perfectly elastic, so both momentum and kinetic energy are conserved.

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What is the mass of a gold bar that has a density of 19.3 g/mL3 and a volume of 100 cm3?

Answers

Answer:

density=mass/volume

density=19.3

mass=x

volume=100

we are looking for mass so we have to change the subject formula to m=dv

which means mass is equals to density multiplied by volume

m= 19.3 x 100

which is 1930.

13. In Section 2.2, three ways to use physical properties are
discussed. Find one example in Section 5.3 that illustrates
each use. If necessary, reread pages 48 and 50.

Answers

Physical properties are used to identify and describe matter. They include

appearance (shape, size, color, texture)boiling/melting pointdensitysolubility viscositymalleability odor

you weigh 500n,what stops you from falling to the center of the earth

Answers

Answer:

bedrock?

Explanation:

The ground is in the way.

What is the acceleration of the object?

What is the acceleration of the object?

Answers

That is b: 0, because the velocity does not change and the acceleration is the change of velocity over a specific time.

how much time will pass when it goes from one-half initial voltage to one-fourth its initial voltage

Answers

The time taken is twice the time taken to decrease from the initial voltage to one-half initial voltage.

How much time will pass when it goes from one-half initial voltage to one-fourth its initial voltage?

The amount of time it takes for a voltage to decrease from one level to another depends on the characteristics of the system generating the voltage.

Assuming that the voltage is decreasing exponentially over time, the time it takes for a voltage to decrease from one level to another can be calculated using the formula:

\(t = -(ln(Vf/Vi))/λ\)

where t is the time taken, Vi is the initial voltage, Vf is the final voltage, and λ is the decay constant of the system generating the voltage.

If the voltage decreases from one-half its initial voltage to one-fourth its initial voltage, then \(Vi = 1, Vf = 1/4\), and the voltage has decreased by a factor of 2.

Assuming that the decay is exponential, the time it takes to decrease by a factor of 2 is:

\(t = -(ln(1/2))/λ\)

We can simplify this expression using the fact that \(ln(1/2) = -ln(2)\), which gives:

\(t = ln(2)/λ\)

Similarly, the time it takes to decrease by a factor of 4 is:

\(t = -(ln(1/4))/λ = ln(4)/λ = 2ln(2)/λ\)

So, the ratio of the time taken to decrease from one-half initial voltage to one-fourth initial voltage is:

\(t(1/4) / t(1/2) = (2ln(2)/λ) / (ln(2)/λ) = 2\)

Therefore, the time taken to decrease from one-half initial voltage to one-fourth initial voltage is twice the time taken to decrease from the initial voltage to one-half initial voltage.

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(20%) (a) (4%) Explain the coherence of wave and state its importance for interference. (b) (4 %) How to improve the interference result if you use a white-light bulb as the light source in Young's double slit experiment? (c) (4%) Explain why the degree of coherence of a laser is better than a light bulb. (d) (4%) A thin film of ZnS (n=2.37) is used to coat a camera lens (ng-1.53) so that it is antireflecting at a wavelength of 550 nm under normal incidence. Find the minimum thickness of the thin film. (e) (4%) A thin film of MgF2 (n= 1.38) is used to coat a camera lens (ng-1.53) so that it is antireflecting at a wavelength of 580 nm under normal incidence. What wavelength is minimally reflected when the light is incident instead at 45⁰?

Answers

A wave's ability to produce stationary interference is known as coherence.

Thus, Coherence is explained through several different ideas. Although these phenomena are uncommon in reality, they provide a basic grasp of waves. It has developed into a crucial idea in quantum physics and wave.

Thus, The term "coherence" refers to the characteristics of the correlation between the physical parameters of a single wave, a group of waves, or a wave packet.

For example, two parallel slits that are illuminated by a single laser beam can be categorized as two coherent sources. The photons of coherent light are in perfect time with one another. The phase shift for the light beam happens simultaneously.

Thus, A wave's ability to produce stationary interference is known as coherence.

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A tennis ball is thrown vertically upward. It reaches the maximum height in 1.25 sec. What is the initial speed of the ball as it leaves the person's hand (m/s)? (neglect air resistance)

Answers

h= max

v= 0

t= 1.25

Vf= 0 at max height

vf = vi + at

0 = vi - 9.8 * 1.25

vi = 12.25 m/s

El cuerpo de 2kg se suelta de A recorriendo el plano inclinado 60° con la horizontal y de superficie lisa hasta el punto B. Luego recorre el tramo rugoso BC deteniéndose en C. Hallar “L” si se sabe que μ= 0,6.

El cuerpo de 2kg se suelta de A recorriendo el plano inclinado 60 con la horizontal y de superficie lisa

Answers

El valor de L del tramo rugoso B a C con coeficiente de fricción igual a 0,6, recorrido por el cuerpo de 2 kg cuando se suelta del punto A es 5.00 m.  

El valor de L se puede calcular a partir de la definición de trabajo:

\(W = F_{\mu}*d\)  (1)

En donde:

\(F_{\mu}\): es la fuerza aplicada sobre el cuerpo en el tramo de B a C = fuerza de roce = -μN (el signo menos se debe a que está en dirección opuesta a la del movimiento)

μ: es el coeficiente de roce = 0,6

N: es la normal = mg

m: es la masa del cuerpo = 2 kg

g: es la aceleración debida a la gravedad = 9,81 m/s²

d: es la distancia = L =?

Por otra parte, el trabajo también se define como la diferencia de energía mecánica entre los puntos B y C.

\( W = E_{C} - E_{B} \)   (2)

Al igualar la ecuación (1) con la (2) tenemos:

\(E_{C} - E_{B} = F_{\mu}*d\)   (3)

En el punto C, la energía es cero (0) dado que el cuerpo se detiene y en el punto B la energía que tiene el objeto es la cinética:  

\( E_{B} = \frac{1}{2}mv_{B}^{2} \)      

En donde:  

\(v_{B}\): es la velocidad del cuerpo en el punto B

La velocidad del cuerpo en el punto B se puede calcular mediante conservación de energía entre los puntos A y B:

\( E_{A} = E_{B} \)          

En el punto A, el cuerpo tiene energía potencial gravitacional, por lo tanto:

\( mgh = \frac{1}{2}mv_{B}^{2} \)    (4)

En donde:

h: es la altura = 3 m

Entonces, la velocidad en el punto B es (eq 4):

\( v_{B} = \sqrt{\frac{2mgh}{m}} = \sqrt{2*9,81 m/s^{2}*3 m} = 7,67 m/s \)

Ahora, la ecuación (3) queda como sigue:  

\( 0 - \frac{1}{2}mv_{B}^{2} = -\mu N*L \)  

\( \frac{1}{2}2 kg*(7.67 m/s)^{2} = 0,6*2 kg*9,81 m/s^{2}*L \)  

Resolviendo para L, tenemos:

\( L = \frac{\frac{1}{2}2 kg*(7.67 m/s)^{2}}{0,6*2 kg*9,81 m/s^{2}} = 5.00 m \)

Por lo tanto, el valor de L es 5.00 m.

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: Prove that the following paraboloid coordinate system (u, v, ϕ):
x = u.v cosϕ
y = u.v sinϕ
z = 1/2 (u2 - v2)
is orthogonal, and then find the following:
1. The scale factors
2. Gradient
3. Divergent
4. Curl
5. Laplacian

Answers

The given paraboloid coordinate system (u, v, ϕ) with x = u.v cosϕ,

y = u.v sinϕ , z = 1/2 (u2 - v2) is orthogonal. The gradient is ∇f = (∂f/∂u) e_u + (∂f/∂v) e_v + (∂f/∂ϕ) e_ϕ ; divergent is ∇²f = ∇ · (∇f) ; curl is (∇ x) and laplacian is  (∇²).

We can prove that the paraboloid coordinate system (u, v, ϕ) is orthogonal, by computing the dot products of the basis vectors. The basis vectors in this coordinate system are given by:

e_u = (∂x/∂u, ∂y/∂u, ∂z/∂u) = (v cosϕ, v sinϕ, u)

e_v = (∂x/∂v, ∂y/∂v, ∂z/∂v) = (u cosϕ, u sinϕ, -v)

e_ϕ = (∂x/∂ϕ, ∂y/∂ϕ, ∂z/∂ϕ) = (-u.v sinϕ, u.v cosϕ, 0)

By Taking the dot products, we find that e_u · e_v = 0, e_v · e_ϕ = 0, and e_ϕ · e_u = 0. This proves that the basis vectors are mutually perpendicular, and therefore, the coordinate system is orthogonal.

Next, we can calculate the gradient (∇) in this coordinate system. The gradient of a scalar function f(u, v, ϕ) is given by:

∇f = (∂f/∂u) e_u + (∂f/∂v) e_v + (∂f/∂ϕ) e_ϕ

The divergence (∇ ·) and curl (∇ x) can be computed using the standard formulas in terms of the basis vectors. Finally, the Laplacian (∇²) can be obtained by taking the divergence of the gradient:

∇²f = ∇ · (∇f)

Thus, By evaluating these operations in the given coordinate system using the appropriate partial derivatives, we can determine the gradient, divergent, curl, and Laplacian for any scalar function in the (u, v, ϕ) coordinates.

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The north pole of one bar magnet is near the south pole of another bar
magnet. What happens to the magnets?
O A. They repel each other.
B. They attract each other.
C. They twist away from each other.
O D. They neither attract nor repel each other.

Answers

B
Opposites attract
Like poles repel

Answer: they attract each other .

Explanation: jus took it.

From which evidence can a forensic expert extract DNA?

Answers

Answer:

The biological material used to determine a DNA profile include blood, semen, saliva, urine, feces, hair, teeth, bone, tissue and cells.

Explanation:

Answer:

bone

Explanation:

If an object weighs 20 N and is sitting on the floor without moving, what must be the normal force of the floor acting on the box?
20 N up
20 N down
10 N up
10 N down

Answers

Answer:

20 N up

Explanation:

Since the object on the floor is sitting still. Based on Newton's law of force. Objects must have equal reaction and force against each other for still objects. So the answer is 20 N up. Since the force are equal on both sides making the object not moving.

Our most detailed knowledge of Uranus and Neptune comes from:
A) spacecraft exploration.
B) the Hubble Space telescope.
C) ground based visual telescopes.
D) ground based radio telescopes.
E) manned missions.

Answers

A) spacecraft exploration.

Our most detailed knowledge of Uranus and Neptune comes from spacecraft exploration. The Voyager 2 spacecraft provided the most extensive and up-close observations of both Uranus and Neptune during its flybys in 1986 and 1989, respectively. These missions provided valuable data on the atmospheres, compositions, magnetic fields, and moons of both planets. Prior to these missions, our knowledge of Uranus and Neptune was limited to ground-based observations, but the spacecraft exploration significantly enhanced our understanding of these outer planets. The Hubble Space Telescope has also contributed to our knowledge of Uranus and Neptune, but it is primarily the spacecraft missions that have provided the most detailed information.

Our most detailed knowledge of Uranus and Neptune comes from spacecraft exploration. NASA's Voyager 2 spacecraft was the first and only spacecraft to fly by both Uranus and Neptune, providing us with a wealth of data and images of these distant gas giants.

The spacecraft conducted numerous flybys, capturing detailed images and measurements of their atmospheres, magnetic fields, and moons. The Hubble Space Telescope has also contributed to our understanding of Uranus and Neptune, but its observations have been more limited compared to the data obtained from spacecraft. Ground-based visual and radio telescopes have also been used to study these planets, but their observations are limited by the Earth's atmosphere. Manned missions have not yet been sent to explore Uranus or Neptune.

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Practice Problem • In 2.5 s a car increases its speed from 60 km/h to 65 km/h while a bicycle goes from rest to 5 km/h.
•Which undergoes the greater acceleration?
• What is the acceleration of each vehicle?

Answers

Answer:

they have same acceleration 2m/s^2

Explanation:

a =v-u/t

65-60/2.5

2m/s^2

a) The acceleration of the car and the bicycle are equal since \(\delta V\) for both vehicle is 5km/h and the time taken for both vehicle is also the same 2.5s.

b) The acceleration of the bicycle is 0.556m/s²

Given the data in the question;

Time taken for both car and bicycle; \(t = 2.5s\)Initial velocity of car; \(u_c = 60km/h = 16.667m/s\)Final velocity of car; \(v_c = 65km/h = 18.0556m/s\)

Since the bicycle starts from rest

Initial velocity of the bicycle; \(u_b = 0\)Final velocity of the bicycle; \(v_b = 5km/h = 1.38889m/s\)

a)

The acceleration of the car and the bicycle are equal since \(\delta V\) for both vehicle is 5km/h time taken for both vehicle is also the same 2.5s.

b)

The acceleration of each vehicle

To determine the acceleration for car and the bicycle, we use the first equation of motion:

\(v = u + at\)

Where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time.

Now, For the car;

\(18.0556m/s = 16.667m/s + ( a + 2.5s )\\\\a = \frac{18.0556m/s - 16.667m/s }{2.5} \\\\a = \frac{1.3886m/s}{2.5s} \\\\a = 0.556 m/s^2\)

Hence, the acceleration of the car is 0.556m/s²

For the bicycle;

\(1.38889m/s = 0 + ( a * 2.5s )\\\\a = \frac{1.38889m/s}{2.5s}\\\\a = 0.556m/s\)

Hence, the acceleration of the bicycle is 0.556m/s²

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You are playing tennis and return a volley. Identify a force pair.

Answers

During a tennis volley, the force pair involved is the action-reaction forces.

When playing tennis and returning a volley, the force pair involved is the action and reaction forces. In the process of hitting the ball, the tennis racket exerts a force on the ball, which is the action force.

The ball, in turn, exerts an equal and opposite force on the racket, which is the reaction force.Both the racket and the ball experience the force of impact during the volley.

The force applied by the racket causes the ball to move forward, while the equal and opposite force applied by the ball pushes the racket back.

These two forces are referred to as action-reaction forces or force pairs. A force pair refers to a pair of forces that are equal in magnitude but opposite in direction.

These forces always act on different objects and occur simultaneously. In this scenario, the action force was exerted by the tennis racket while the reaction force was exerted by the ball.

Therefore, during a tennis volley, the force pair involved is the action-reaction forces.

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A. It Implies That M Is Finitely Generated. B. It Implies That M Has Nonzero Elements Of Nonzero Order. C. When Every Non-Null Element Has Null . D. In The Case That The Ring R Is A Body. E. None Of The Above Alternatives Gives A
Which of the following alternatives give a true statement. Justify your answer.
A modulus M over a ring R has a finite basis:
a. It implies that M is finitely generated.
b. It implies that M has nonzero elements of nonzero order.
C. When every non-null element has null .
d. in the case that the ring R is a body.
e. None of the above alternatives gives a true statement.
Which of the following statements are true?
a. If a subset of a module generates that whole module, then the subset cannot be
empty.
b. Every submodule S of a module M verifies the inequality C. Two different subsets of M have to generate two different submodules of M.
d. If S generates a submodule N of the module M, then contains S.
e. Neither statement is true.

Answers

The correct answer is e. None of the above alternatives gives a true statement. None of the statements in options a, b, c, and d are true when it comes to a modulus M over a ring R having a finite basis.

When a modulus M can be formed entirely from a finite set of elements, the modulus M is said to be finitely generated. M's finite basis does not, however, automatically imply that M is finitely generated. A basis is a set of linearly independent elements, and it might not be enough to produce all of the components of the modulus.

According to the assertion in option b, M must include nonzero items of nonzero order if it has a finite basis. This is untrue, though. The smallest positive number k, such that the element raised to the power of k equals the identity element, is referred to as the order of an element.

According to option c, every non-null element in a modulus with a finite basis has a null. Nevertheless, this claim is likewise untrue. It is possible for a modulus with a finite basis to have non-null elements without a null element.

According to option d, a ring R is a body, or a field, and only then can a modulus have a finite basis. However, this assertion is also untrue. Even though the ring R is not a field, a modulus can nonetheless have a finite basis. None of the given alternatives provides a true statement about a modulus M over a ring R having a finite basis.

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Question 23 of 25 Which statement describes a question that can guide the design of a scientific investigation? A. It asks about a cause-and-effect relationship between two variables. B. It asks about how the observations will be organized. C. It asks about whether a controlled variable is necessary. OD. It asks about the preferred outcome of the investigation. ​

Answers

Scientific investigation asks about a cause-and-effect relationship between two variables. Thus, the correct answer is (a).

Scientific investigation is intended to create a hypothesis and demonstrate its validity or lack thereof. Experiments must be conducted in order to test these hypotheses, and these experiments are planned in accordance with the discovery of a cause-and-effect relationship between the two variables under scientific investigation. In these experiments, the "cause" is variable upto various degrees, and the "effect" of the variance is noted. The experimental design, which will try to manipulate the causes to see how these manipulations impact the second variable, will thus be guided by knowledge of the cause-and-effect connection.

Observations are frequently the first step in a scientific investigation.

An observation is something that is discovered using the senses of humans or tools and measurement technologies that support the senses of humans. Important scientific discoveries may result from unintentional observations.

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how fast is the cheetah running in m/s

how fast is the cheetah running in m/s

Answers

With 4.3 m/s velocity, is the cheetah running.

velocity= distance/time

distance=27.6 m

time=6.3 s

velocity=27.6 m/6.3 s

velocity=4.3 m/s

A vector number known as velocity describes "the pace at which an item changes its location." Imagine a person moving quickly, taking one stride ahead, one step back, and then beginning from the same place each time. A vector quantity is velocity. As a result, velocity is aware of direction. One must consider direction while calculating an object's velocity. Saying that an item has a velocity of 55 miles per hour is insufficient. The direction must be included in order to adequately characterize the object's velocity. Simply said, the velocity vector's direction corresponds to the motion of an item.

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7) Find F1 and F2
HELP PLEASEEE

7) Find F1 and F2HELP PLEASEEE

Answers

The force F1 is equal and opposite to the downward force thus, F1 is equal to 60 N. The force F2 is inclined to 30 ° from leftward force and it is equal to 38.97 N in magnitude.

What is force?

Force is an external agent acting on a body to deform it or to change its state of motion or rest. Force is a vector quantity and it is characterised by its magnitude and direction.

If two forces acting on a body from the same directions, then the net force will be the sum of these two forces. If they are acting from opposite directions, they will cancel each other in magnitude.

The force F1 is equal and opposite to the force acting downward. Thus its magnitude is 60 N. The force F2 is inclined to 30 ° from horizontal direction.

F2 = 45 cos 30 = 38.9 N.

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George wants his airplane to travel along a path that is [60°] with a groundspeed of 280 km/h. If the wind is blowing from the direction [10°] at 65 km/h, then in what direction should the pilot steer towards and what would be his airspeed? use the component method please

Answers

We know that the groundspeed we want is of 280 km/h with a direction of 60° and that the wind is blowing with a speed of 65 km/h with a direction of 10°; this vectors are shown in the diagram below:

Let v be the vector of the speed of the plane. We know that the 280 km/h vector will be the sum of the aispeed vector and the wind vector, that is:

\(\begin{gathered} \vec{r}=\vec{v}+\vec{w} \\ \text{ where} \\ \vec{r}\text{ is the 280 km/h vector } \\ \vec{w}\text{ is the wind vector} \end{gathered}\)

We know that the any given vector can be decomposed as:

\(\vec{v}=\langle v\cos\theta,v\sin\theta\rangle\)

For the resultant vector we have a magnitude of 280 km/s and a direction of 150° (with respect to the x-axis) and for the wind vector the magnitude is 65 km/h and the direction is 10°, then we have:

\(\begin{gathered} \langle280\cos150,280\sin150\rangle=\vec{v}+\langle65\cos10,65\sin10\rangle \\ \vec{v}=\langle280\cos150,280\sin150\rangle-\langle65\cos10,65\sin10\rangle \\ \vec{v}=\langle-306.5,128.7\rangle \end{gathered}\)

Now that we have vector v is component form we can calculate its magnitude and direction; remember that they are given by:

\(\begin{gathered} v=\sqrt{v_x^2+v_y^2} \\ \theta=\tan^{-1}\lvert{\frac{v_y}{v_x}}\rvert \end{gathered}\)

Then we have:

\(\begin{gathered} v=\sqrt{(-306.5)^2+(128.7)^2}=332.4 \\ \theta=\tan^{-1}\lvert{\frac{-306.5}{128.7}}\rvert=67.2 \end{gathered}\)

Now, we need to be careful with the angle, in this case vector v will lie in the second quadrant; which means that the angle is measure from west to north.

Therefore, the airspeed is 332.4 km/h and the direction will be W67.2°N

George wants his airplane to travel along a path that is [60] with a groundspeed of 280 km/h. If the

electromagnetic waves are ........... by shiny surfaces.

1. reflected
2. refracted
3. absorbed

Answers

Answer:

Electromagnetic waves are reflected

Explanation:

Reflection of light (and other forms of electromagnetic radiation) occurs when the waves encounter a surface or other boundary that does not absorb the energy of the radiation and bounces the waves away from the surface. ... This concept is often termed the Law of Reflection.

Electromagnetic waves are reflected by the shiny surfaces. The correct option is 1.

What are electromagnetic waves?

These are the rays which mostly come from the Sunlight. It possess energy or defined by energy of photon.

Reflection of light occurs when the waves strike a surface or boundary that does not absorb the energy of the radiation but bounces the waves away from the surface. This is often called the Law of Reflection.

Thus, the Electromagnetic waves are reflected by the shiny surfaces. The correct option is 1.

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What is the density of a box measuring 100 grams and 10 ml?

Answers

Answer:

In order to convert density to grams, you have to put the mass on one side of the equation, and the density and the volume on the other. Therefore, d * v = m. Multiply the density by the volume. Using the example in step 1, you would multiply 2 g/mL by 4mL.

Explanation:

ok

The plasma membrane of a neuron has voltage-gated sodium and potassium channels. What is the effect of membrane depolarization on these channels?.

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Answer:

Depolarization causes the Voltage-gated channels to open in order for ions to flow or rush in

does the medium in which a wave travels move with the wave? sometimes no always yes

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Sometimes no. such as in other types of waves like electromagnetic waves, the medium does not physically move with the wave.

The medium in which a wave travels can move with the wave under certain circumstances, but it is not always the case. The movement of the medium depends on the type of wave and the nature of the medium itself. In mechanical waves, such as sound waves or water waves, the medium particles do indeed move as the wave propagates through them. For example, in a water wave, the water molecules move in a circular or elliptical motion as the wave passes through the water. Electromagnetic waves, including light waves, can travel through vacuum, which has no physical medium. In this case, the wave consists of oscillating electric and magnetic fields that propagate through space without the need for a medium to physically move. Therefore, whether the medium moves with the wave or not depends on the specific characteristics of the wave and the medium it is traveling through.

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A ball is shot at an angle of 45 degrees into the air with initial velocity of 41 ft/sec. Assuming no air resistance, how high doss it go? How far away does it land? Hint: The acceleration due to gravity is 32ft per second squared. A particle is moving with acceleration a(t)=24t+16. its position at time t=0 is s(0)=12 and its velocity at time t=0 is v(0)=15. What is its position at time t=14 ? Find the average value of f(x)= x³8 +9x on the interval [1,2].

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The ball reaches a maximum height of approximately 42.83 ft.  the ball lands at a horizontal distance of approximately 81.36 ft. he average value of f(x)= x³8 +9x on the interval is 10.5.

To determine the maximum height and horizontal distance traveled by the ball shot at an angle of 45 degrees with an initial velocity of 41 ft/sec and neglecting air resistance, we can use basic kinematic equations.

Maximum Height:

The maximum height reached by the ball can be calculated using the equation for vertical displacement:

y_max = (v₀² * sin²θ) / (2g),

where v₀ is the initial velocity, θ is the launch angle (45 degrees), and g is the acceleration due to gravity (32 ft/s²).

Plugging in the values, we get:

y_max = (41² * sin²45°) / (2 * 32) = 42.83 ft.

Therefore, the ball reaches a maximum height of approximately 42.83 ft.

Horizontal Distance:

The horizontal distance traveled by the ball can be calculated using the equation for horizontal displacement:

x = v₀ * cosθ * t,

where x is the horizontal distance and t is the time of flight.

Since the ball goes up and then comes back down, the total time of flight can be calculated as:

t_total = 2 * (v₀ * sinθ) / g.

Plugging in the values, we get:

t_total = 2 * (41 * sin45°) / 32 ≈ 2.88 s.

Using this total time, we can find the horizontal distance:

x = 41 * cos45° * 2.88 ≈ 81.36 ft.

Therefore, the ball lands at a horizontal distance of approximately 81.36 ft.

Moving on to the second question:

To find the position of a particle at time t = 14, given its acceleration, initial position, and initial velocity, we can use the equations of motion.

The position function s(t) can be obtained by integrating the acceleration function twice with respect to time. Since the given acceleration is a linear function, we have:

s(t) = (1/6)at³ + (1/2)v₀t² + s₀,

where a is the acceleration, v₀ is the initial velocity, and s₀ is the initial position.

Plugging in the given values, we get:

s(14) = (1/6)(24)(14)³ + (1/2)(15)(14)² + 12 ≈ 546.67.

Therefore, the position of the particle at time t = 14 is approximately 546.67.

Lastly, for the average value of f(x) = x³ + 9x on the interval [1, 2], we can use the formula for the average value of a function on an interval:

Average value = (1 / (b - a)) * ∫[a, b] f(x) dx,

where [a, b] represents the interval.

Plugging in the values, we have:

Average value = (1 / (2 - 1)) * ∫[1, 2] (x³ + 9x) dx.

Evaluating the integral, we get:

Average value = (1 / 1) * [(1/4)x⁴ + (9/2)x²] evaluated from 1 to 2,

Average value = (1/4)(2⁴ + 9(2²)) - (1/4)(1⁴ + 9(1²)),

Average value = (1/4)(16 + 36) - (1/4)(1 + 9),

Average value = (1/4)(52) - (1/4)(10),

Average value = 13 - 2.5,

Average value ≈ 10.5

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what is the approximate thermal energy in kj/mol of molecules at 75 ° c?

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Answer:

if you like it please do appreciate

To calculate the approximate thermal energy in kilojoules per mole (kJ/mol) of molecules at a given temperature, you can use the Boltzmann constant (k) and the ideal gas law.

The Boltzmann constant (k) is approximately equal to 8.314 J/(mol·K). To convert this to kilojoules per mole, we divide by 1000:

k = 8.314 J/(mol·K) = 0.008314 kJ/(mol·K)

Now, we need to convert the temperature to Kelvin (K) since the Boltzmann constant is defined in Kelvin. To convert from Celsius to Kelvin, we add 273.15 to the temperature:

T(K) = 75°C + 273.15 = 348.15 K

Finally, we can calculate the thermal energy using the formula:

Thermal energy = k * T

Thermal energy = 0.008314 kJ/(mol·K) * 348.15 K

Thermal energy ≈ 2.894 kJ/mol

Therefore, at 75°C, the approximate thermal energy of molecules is approximately 2.894 kilojoules per mole (kJ/mol).

The heat capacity of one mole of water is approximately 75.29/1000 = 0.07529 kj/mol. This value represents the approximate thermal energy in kj/mol of water molecules at 75 ° C.

Thermal energy refers to the energy present in a system that arises from the random movements of its atoms and molecules. When a body has a temperature of 75 ° C, it has a thermal energy that depends on the type of molecules in it and their specific heat capacity.

In this context, we will consider the thermal energy in kj/mol of molecules at 75 ° C.Let's use water as an example to calculate the approximate thermal energy in kj/mol of molecules at 75 ° C. The specific heat capacity of water is 4.18 J/g °C, and the molar mass of water is 18.01528 g/mol. Therefore, the thermal energy in kj/mol of water molecules at 75 ° C can be calculated as follows:ΔH = mcΔt, whereΔH = thermal energy,m = mass of the sample,c = specific heat capacity of the sample,Δt = change in temperature

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Can someone plz help me on this, it would me alot to me
thx

Can someone plz help me on this, it would me alot to me thx

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Answer:

its a opinonated question

Explanation:

XD

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