The current model of the atom suggests that ?
Answers
Answer:
i dont see the model bro
Explanation:
Answer:
The current model of the atom shows an atom that is mostly empty space. In the center is a small nucleus made of protons and neutrons.
Explanation:
Related Questions
Question 14 PM2.5 is defined as ________
- the mass concentration of particles in the air less than or equal to 2.5 micrometers in diameter. - the mass concentration of particles in the air equal to 2.5 micrometers in diameter. - the mass concentration of particles in the air greater than or equal to 2.5 micrometers in diameter. Question 15 Carbon dioxide (CO2) is a criteria air pollutant. - True - False Question 16 Roughly percent of emissions of carbon monoxide in Santa Clara County come from mobile sources (select the choice closest to the correct answer). - 50 - 75 - 25 Question 17
The term "photochemical smog" is most synonymous with which of the following criteria air pollutants? - lead (Pb) - carbon monoxide (CO) - sulfur dioxide ( SO2) - ozone (O3) Question 18 "Attainment" of ambient air quality standards requires that measured concentrations at all monitoring stations within an air district are below ambient air standards. - True - False
Answers
: PM2.5 is defined as the mass concentration of particles in the air less than or equal to 2.5 micrometers in diameter.Question 15: False, carbon dioxide (CO2) is not considered a criteria air pollutant.
Question 16: The closest answer is 50%, but the exact percentage is not provided in the question.Question 17: The term "photochemical smog" is most synonymous with ozone (O3), which is a criteria air pollutant.Question 18: True, attainment of ambient air quality standards requires that measured concentrations at all monitoring stations within an air district are below ambient air standards.
Question 14 asks about the definition of PM2.5. PM2.5 refers to particulate matter with a diameter less than or equal to 2.5 micrometers. It represents the mass concentration of particles suspended in the air, which are small enough to be inhaled into the respiratory system and can have adverse health effects.
Question 15 states whether carbon dioxide (CO2) is a criteria air pollutant. Criteria air pollutants are a set of pollutants regulated by environmental agencies due to their detrimental impact on air quality and human health. However, carbon dioxide is not considered a criteria air pollutant because it does not directly cause harm to human health or the environment in the same way as pollutants like ozone or particulate matter.
Question 16 asks about the percentage of carbon monoxide (CO) emissions from mobile sources in Santa Clara County. While the exact percentage is not provided in the question, the closest answer option is 50%. However, it is important to note that the precise percentage may vary depending on specific local conditions and emissions sources.
Question 17 inquires about the criteria air pollutant most synonymous with the term "photochemical smog." Photochemical smog is primarily associated with high levels of ground-level ozone (O3). Ozone is formed when nitrogen oxides (NOx) and volatile organic compounds (VOCs) react in the presence of sunlight, creating a hazy and polluted atmospheric condition.
Question 18 addresses the concept of "attainment" of ambient air quality standards. To achieve attainment, measured concentrations of pollutants at all monitoring stations within an air district must be below the established ambient air quality standards. This ensures that the air quality in the given area meets the required standards for protecting human health and the environment.
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which of the following options correctly describe the reaction of an aldehyde or ketone with the cyanide ion? select all that apply.
Answers
The reaction of an aldehyde or ketone with the cyanide ion is correctly described as **nucleophilic addition** and leads to the formation of **cyanohydrins**.
In this reaction, the cyanide ion (CN⁻) acts as a nucleophile, meaning it donates a pair of electrons to the electrophilic carbon atom in the carbonyl group (C=O) of an aldehyde or ketone. This results in the addition of the cyanide group to the carbon and a hydroxyl group (OH) to the oxygen, forming a cyanohydrin compound. Nucleophilic addition reactions are characteristic of carbonyl compounds like aldehydes and ketones. The cyanohydrin products are versatile intermediates in organic synthesis, as they can be further converted to other functional groups, such as carboxylic acids and amines.
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how many valence electrons does sr2+ have
Answers
Answer:
8 valence electrons
Explanation:
The unheated gas in the above system has a volume of 20.0L
at a temperature of 25.0 °C and a pressure of 1.00 atm. The
gas is heated to a temperature of 100.0 °C while the volume
remains constant. What is the pressure of the heated gas?
Ignore the block labeled "A".
da Hint?
Answers
Answer:
need more info on block labeled ''A''
Explanation:
Show that each of these conditional statements is a tautology by using truth tables. a) (p∧q)→p b) p→(p∨q) c) ¬p→(p→q) d) (p∧q)→(p→q) 10. Show that each of these conditional statements is a tautology by using truth tables. [p∧(p→q)]→q 22. Show that (p→q)∧(p→r) and p→(q∧r) are logically equivalent. 23. Show that (p→r)∧(q→r) and (p∨q)→r are logically equivalent. 24. Show that (p→q)∨(p→r) and p→(q∨r) are logically equivalent.
Answers
This means that they are true for all possible combinations of truth values for p, q, and r
a) (p∧q)→p
p | q | p∧q | p→p
-- | -- | -- | --
T | T | T | T
T | F | F | T
F | T | F | T
F | F | F | T
b) p→(p∨q)
p | q | p∨q | p→(p∨q)
-- | -- | -- | --
T | T | T | T
T | F | T | T
F | T | T | T
F | F | F | T
c) ¬p→(p→q)
p | ¬p | p→q | ¬p→(p→q)
-- | -- | -- | --
T | F | T | F
F | T | F | T
d) (p∧q)→(p→q)
p | q | p∧q | p→q | (p∧q)→(p→q)
-- | -- | -- | -- | --
T | T | T | T | T
T | F | F | T | T
F | T | F | T | T
F | F | F | T | T
10. [p∧(p→q)]→q
p | q | p→q | p∧(p→q) | [p∧(p→q)]→q
-- | -- | -- | -- | --
T | T | T | T | T
T | F | F | F | F
F | T | T | F | F
F | F | T | F | F
22. (p→q)∧(p→r) and p→(q∧r)
p | q | r | p→q | p→r | (p→q)∧(p→r) | p→(q∧r)
-- | -- | -- | -- | -- | -- | --
T | T | T | T | T | T | T
T | T | F | T | T | T | T
T | F | T | T | F | T | F
T | F | F | T | F | T | F
F | T | T | T | T | T | T
F | T | F | T | T | T | F
F | F | T | T | F | T | F
F | F | F | T | F | T | F
23. (p→r)∧(q→r) and (p∨q)→r
p | q | r | p→r | q→r | (p→r)∧(q→r) | (p∨q)→r
-- | -- | -- | -- | -- | -- | --
T | T | T | T | T | T | T
T | T | F | T | T | T | T
T | F | T | T | T | T | T
T | F | F | T | T | T | T
F | T | T | T | T | T | T
F | T | F | T | T | T | T
F | F | T | T | T | T | T
F | F | F | T | T | T | F
24. (p→q)∨(p→r) and p→(q∨r)
p | q | r | p→q | p→r | (p→q)∨(p→r) | p→(q∨r)
-- | -- | -- | -- | -- | -- | --
T | T | T | T | T | T | T
T | T | F | T | T | T | T
T | F | T | T | T | T | T
T | F | F | T | T | T | T
F | T | T | T | T | T | T
F | T | F | T | T | T | T
F | F | T | T | T | T | T
F | F | F | T | T | T | F
As you can see, all of the conditional statements are tautologies.
This means that they are true for all possible combinations of truth values for p, q, and r
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a) (p∧q)→p is shown as a tautology by using truth tables
b) p→(p∨q) is shown as a tautology by using truth tables
c) ¬p→(p→q) is shown as a tautology by using truth tables
d) (p∧q)→(p→q) is shown as a tautology by using truth tables
How do we explain?This can be explained as meaning that they are true for all possible combinations of truth values for p, q, and r
a)
for (p∧q)→p
p | q | p∧q | p→p
-- | -- | -- | --
T | T | T | T
T | F | F | T
F | T | F | T
F | F | F | T
b)
p→(p∨q)
p | q | p∨q | p→(p∨q)
-- | -- | -- | --
T | T | T | T
T | F | T | T
F | T | T | T
F | F | F | T
c) ¬p→(p→q)
p | ¬p | p→q | ¬p→(p→q)
-- | -- | -- | --
T | F | T | F
F | T | F | T
d) (p∧q)→(p→q)
p | q | p∧q | p→q | (p∧q)→(p→q)
-- | -- | -- | -- | --
T | T | T | T | T
T | F | F | T | T
F | T | F | T | T
F | F | F | T | T
10. [p∧(p→q)]→q
p | q | p→q | p∧(p→q) | [p∧(p→q)]→q
-- | -- | -- | -- | --
T | T | T | T | T
T | F | F | F | F
F | T | T | F | F
F | F | T | F | F
22. (p→q)∧(p→r) and p→(q∧r)
p | q | r | p→q | p→r | (p→q)∧(p→r) | p→(q∧r)
-- | -- | -- | -- | -- | -- | --
T | T | T | T | T | T | T
T | T | F | T | T | T | T
T | F | T | T | F | T | F
T | F | F | T | F | T | F
F | T | T | T | T | T | T
F | T | F | T | T | T | F
F | F | T | T | F | T | F
F | F | F | T | F | T | F
23.
for (p→r)∧(q→r) and (p∨q)→r
p | q | r | p→r | q→r | (p→r)∧(q→r) | (p∨q)→r
-- | -- | -- | -- | -- | -- | --
T | T | T | T | T | T | T
T | T | F | T | T | T | T
T | F | T | T | T | T | T
T | F | F | T | T | T | T
F | T | T | T | T | T | T
F | T | F | T | T | T | T
F | F | T | T | T | T | T
F | F | F | T | T | T | F
24.
(p→q)∨(p→r) and p→(q∨r)
p | q | r | p→q | p→r | (p→q)∨(p→r) | p→(q∨r)
-- | -- | -- | -- | -- | -- | --
T | T | T | T | T | T | T
T | T | F | T | T | T | T
T | F | T | T | T | T | T
T | F | F | T | T | T | T
F | T | T | T | T | T | T
F | T | F | T | T | T | T
F | F | T | T | T | T | T
F | F | F | T | T | T | F
In conclusion, we see that all of the conditional statements are tautologiesand that they are true for all possible combinations of truth values for p, q, and r
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A buffer solution with a particular pH can be prepared by adding a strong acid to a strong base solution. Selected answer will be automatically saved. For keyboard navigation, press upydown arrow keys to select an answer. True False
Answers
A buffer solution with a particular pH can be prepared by adding a strong acid to a strong base solution is false.
A buffer solution is not typically prepared by adding a strong acid to a strong base solution. Buffer solutions are designed to resist changes in pH and are usually composed of a weak acid and its conjugate base, or a weak base and its conjugate acid. The weak acid or base component in the buffer system reacts with any added strong acid or base to prevent drastic changes in pH.
When a strong acid is added to a strong base solution, the reaction results in complete neutralization, forming water and a salt. This process does not create a buffer solution because both the strong acid and strong base are fully ionized and do not have the ability to maintain a stable pH. Buffer solutions are important in various applications, such as biological systems and chemical reactions, where maintaining a specific pH range is crucial for optimal functioning.
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HELP ASAP SCIENCE GIVING BRAINLIST FOR CORRECT
Answers
Answer:
Jellyfish :)
Have an amazing day!!
Please rate and mark brainliest!!
A planet's orbit around the sun affect's the planet's ability to support life
true
false
Answers
Answer:True i believe
Explanation:
The photo shows wires made of pure copper, an element,
What would the smallest piece of copper be?
Answers
1. For the reaction C + 2H2 → CH4, how many moles of carbon are needed to make 150.6 grams of methane, CH4 ?
Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0
Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:
Element
Molar Mass
Hydrogen
1
Carbon
12
2. S + 6 HNO3 --> H2SO4 + 6 NO2 + 2 H2O
In the above equation how many moles of water can be made when 113 grams of HNO3 are consumed?
Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0
Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:
Element
Molar Mass
Hydrogen
1
Nitrogen
14
Sulfur
32
Oxygen
16
3. 3 Cu + 8HNO3 --> 3 Cu(NO3)2 + 2 NO + 4 H2O
In the above equation how many moles of water can be made when 117.8 grams of HNO3 are consumed?
Round your answer to the nearest tenth. If you answer is a whole number like 4, report the answer as 4.0
Use the following molar masses. If you do not use these masses, the computer will mark your answer incorrect.:
Element
Molar Mass
Hydrogen
1
Nitrogen
14
Copper
63.5
Oxygen
16
Answers
Answer:
1) 9.4 mol
2) 0.6 mol
3) 0.9 mol
What is Stoichiometry?
In chemical equations, unless stated otherwise, the reactants and products will theoretically always remain in stoichiometric ratios.
The stoichiometry of a reaction is the relationship between the relative quantities of products and reactants, typically a ratio of whole integers.
Consider the following chemical reaction: aA + bB ⇒ cC + dD.
The stoichiometry of reactants to products in this reaction is the ratio of the coefficients of each species: a : b : c : d.
Converting between moles and mass:
To convert from mass to moles, divide the mass present by the molar mass, resulting in the number of moles. Mathematically, the units present themselves like this: \(\frac{g}{gmol^{-1}} =g(g^{-1}mol)=mol\).
Thence, the formula for moles: n = m/M, where n = number of moles, m = mass present, and M = molar mass. This formula can be easily rearranged to find mass present from molar mass and moles, or molar mass from mass and moles.
1) For the reaction C + 2H₂ → CH₄, how many moles of carbon are needed to make 150.6 g of methane, CH₄? (Molar Masses: H=1; C=12)
Stoichiometry of carbon to methane = 1 : 1.
Therefore, moles of CH₄ = moles of C. Using the formula to find moles, n(CH₄) = m/M = 150.6/(12+1×4) =9.4125 ≈ 9.4 mol
Therefore, we require 9.4 moles of carbon.
2) S + 6HNO₃ → H₂SO₄ + 6NO₂ + 2H₂O
In the above equation, how many moles of water can be made when 113 g of HNO₃ are consumed? (Molar Masses: H=1; N=14; S=32; O=16)
Stoichiometry of Nitric acid to water = 6 : 2 = 3 : 1. Therefore, we produce 1 mole of water for every 3 moles of nitric acid consumed. Hence, n(HNO₃) = m/M = 113/(1+14+16×3) = 1.79365 mol
Therefore: n(H₂O) = 1/3 × n(HNO₃) = 0.59788 mol ≈ 0.6 mol
3) 3Cu + 8HNO₃ → 3Cu(NO₃)₂ + 2NO + 4H₂O
In the above equation, how many moles of water can be made when 117.8 grams of HNO3 are consumed?
Stoichiometry of Nitric acid to water = 8 : 4 = 2 : 1. Therefore, we produce 1 mole of water for every 2 moles of nitric acid consumed. Hence, n(HNO₃) = m/M = 117.8/(1+14+16×3) = 1.86984 mol
Therefore: n(H₂O) = 1/2 × n(HNO₃) = 0.9349 mol ≈ 0.9 mol
Calculate the pH of a solution prepared by mixing 100 mL of 0.1 M NaH2PO4 and 100 mL of 0.1 M Na2HPO4. How many mL of 0.1 M H3PO4 should be added to the above solution to lower the pH by one unit
Answers
Given: Volume of NaH2PO4 = 100 mL
Volume of Na2HPO4 = 100 mL Concentration of NaH2PO4 = 0.1 M
Concentration of Na2HPO4 = 0.1 M
We need to calculate the pH of the given solution and also the volume of 0.1 M H3PO4 that should be added to lower the pH by one unit.
Calculation for pH:
To calculate the pH of the solution, we need to calculate the pKa value of the buffer solution. pKa = (pKa1 + pKa2)/2wherepKa1 = 2.12pKa2 = 7.21pKa = (2.12 + 7.21)/2pKa = 4.665pH = pKa + log [salt/acid][salt/acid] = 10^(pH-pKa)Salt is Na2HPO4Acid is NaH2PO4salt concentration = 0.1 Macid concentration = 0.1 M
Therefore,[salt/acid] = (0.1)/(0.1)[salt/acid] = 1pH = pKa + log [salt/acid]pH = 4.665 + log (1)pH = 4.665
Therefore, the pH of the given solution is 4.665.Calculation for the volume of 0.1 M H3PO4:To lower the pH of the solution by one unit, we need to add H3PO4 in such a way that the ratio of [HPO42-]/[H2PO4-] becomes 10 : 1 at pH 3.665.pH = pKa + log [HPO42-]/[H2PO4-]3.665 = 4.665 + log [10]/[1][HPO42-]/[H2PO4-] = 10^(-1)
Therefore, the ratio of [HPO42-]/[H2PO4-] should become 10 :
1.To calculate the volume of 0.1 M H3PO4, we need to use Henderson-Hasselbalch equation. pH = pKa + log [salt/acid]
Here, salt is Na2HPO4Acid is NaH2PO4pH = 3.665pKa = 4.665[salt/acid] = 10[mol of salt]/[mol of acid] = 10
Therefore,[Na2HPO4] / [NaH2PO4] = 10[Na2HPO4] = 10 * [NaH2PO4]Concentration of Na2HPO4 = 0.1 M Volume of Na2HPO4 = 100 mL
Calculation of moles of Na2HPO4:n = C * Vn = 0.1 * (100/1000)n = 0.01 mol
No. of moles of NaH2PO4 = 0.01/10 = 0.001 mol
Concentration of H3PO4 = 0.1 M
To calculate the volume of H3PO4:Let V be the volume of H3PO4.V * 0.1 = 0.001V = 0.01 L or 10 mL
Therefore, 10 mL of 0.1 M H3PO4 should be added to the above solution to lower the pH by one unit.
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Carbon disulfide and carbon monoxide are produced when carbon is heated with sulfur dioxide.
5C(s)+2SO2(g)→CS2(l)+4CO(g)
How many moles of C are needed to react with 0.460 mole SO2?
How many moles of CO are produced when 2.0 moles C reacts?
How many moles of SO2 are required to produce 0.35 mole CS2?
How many moles of CS2 are produced when 2.4 moles C reacts?
Answers
1) To react with 0.460 mole of SO₂, 1.15 moles of C are needed.
2) When 2.0 moles of C reacts, 1.6 moles of CO are produced.
3) To produce 0.35 mole of CS₂, 0.70 moles of SO₂ are required.
4) When 2.4 moles of C reacts, 0.48 moles of CS₂ are produced.
1.
From the balanced equation, the stoichiometric ratio between C and SO₂ is 5:2. Therefore, to calculate the moles of C required, we can set up a proportion:
(5 moles C / 2 moles SO₂) = (x moles C / 0.460 moles SO₂)
Solving for x, we find:
x = (5/2) × 0.460 = 1.15 moles C
2.
From the balanced equation, the stoichiometric ratio between C and CO is 5:4. Therefore, to calculate the moles of CO produced, we can set up a proportion:
(5 moles C / 4 moles CO) = (2.0 moles C / x moles CO)
Solving for x, we find:
x = (4/5) × 2.0 = 1.6 moles CO
3.
From the balanced equation, the stoichiometric ratio between SO₂ and CS₂ is 2:1. Therefore, to calculate the moles of SO₂ required, we can set up a proportion:
(2 moles SO₂ / 1 mole CS₂) = (x moles SO₂ / 0.35 moles CS₂)
Solving for x, we find:
x = (2/1) × 0.35 = 0.70 moles SO₂
4.
From the balanced equation, the stoichiometric ratio between C and CS₂ is 5:1. Therefore, to calculate the moles of CS₂ produced, we can set up a proportion:
(5 moles C / 1 mole CS₂) = (2.4 moles C / x moles CS₂)
Solving for x, we find:
x = (1/5) × 2.4 = 0.48 moles CS₂
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How many liters of O2 are needed to react completely with 52.0 L of H2S at STI
2H2S(g) + 3O2(g) → 2SO2(g) + 2H₂O(g)
Answers
72.2 liters of O₂ are needed to react completely with 52.0 L of H₂S at STP.
What is a chemical equation?
The chemical equation also indicates the physical states of the reactants and products (e.g. solid, liquid, gas, or aqueous solution).The balanced chemical equation is:
2H2S(g) + 3O₂(g) → 2SO₂(g) + 2H₂O(g)
According to the equation, it takes 3 moles of O₂ to react completely with 2 moles of H₂S.
To determine how many liters of O₂ are needed to react completely with 52.0 L of H₂S, we need to convert the volume of H₂S from liters to moles using the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.
Assuming STP (Standard Temperature and Pressure, which is 0°C and 1 atm), the volume of 52.0 L of H₂S can be converted to moles as follows:
n = PV/RT = (1 atm)(52.0 L)/(0.0821 L·atm/mol·K)(273 K) = 2.27 mol H₂S
From the balanced equation, we know that 2 moles of H₂S react with 3 moles of O₂. Therefore, we need to use a proportion to determine the number of moles of O₂ required to react with 2.27 moles of HS:
2 mol H₂S / 3 mol O2 = 2.27 mol H2S / x mol O₂
x = (3 mol O₂)(2.27 mol H₂S / 2 mol H₂S) = 3.41 mol O₂
Finally, we can convert the number of moles of O₂ to liters using the ideal gas law:
V = nRT/P = (3.41 mol)(0.0821 L·atm/mol·K)(273 K)/(1 atm) = 72.2 L O2
Therefore, 72.2 liters of O2 are needed to react completely with 52.0 L of H₂S at STP.
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If 3.2 g of salicylic acid and 6.3 ml of acetic anhydride are used in synthesis of aspirin, what is the theoretical yield in grams? the molar mass of aspirin is 180 g/mol. (hint: you need to find the limiting reagent first) a)2.4 g b)1.9 g c)4.2 g d)3.2 g
Answers
C. The theoretical yield of aspirin is found to be 4.2g
What information does theoretical yield provide?The largest amount of product that could be generated from the provided reactant amounts is termed as the theoretical yield. The quantity of product that actually formed during the reaction in a laboratory environment is known as the actual yield.
C₇H₆O₃ + C₄H₆O₃→ C₉H₈O₄ ( aspirin)
No of moles of salicylic acid => 3.2/138.122 => 0.023 mol
no of moles of acetic anhydride => 1.08 g/mL x 6.3 mL / 102.089 g/mol
=> 0.066mol
salicylic acid is limiting reagent
Theoretical yield calculated:
1 mole of salicylic acid=> 1 mole of aspirin
Hence, 0.023 mol of aspirin formed in this reaction.
Theorectical yield of aspirin => 0.023 mol x 180g/mol => 4.2g
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4. How many moles are in 9.12 x 1023 molecules of sugar? And I want the steps to so that I can understand better
Answers
Answer:
Step 1: List the known quantities and plan the problem.
Known
number of C atoms = 4.72 × 10 24
1 mole = 6.02 × 10 23 atoms
Unknown
4.72 × 10 24 = ? mol C
One conversion factor will allow us to convert from the number of C atoms to moles of C atoms.
Step 2: Calculate.
4.72 times 10^{24} text{atoms C} times frac{1 text{mol C}}{6.02 times 10^{23} text{atoms C}}=7.84 text{mol C}
Step 3: Think about your result.
The given number of carbon atoms was greater than Avogadro’s number, so the number of moles of C atoms is greater than 1 mole. Since Avogadro’s number is a measured quantity with three significant figures, the result of the calculation is rounded to three significant figures.
Explanation:
the image is 4 step2 mwa
Question 14
1 pts
How many moles of NaCl could be found in 0.4 L of a 0.9 M solution? Round your answer to
two decimal places.
Answers
Answer:
0.36mol
Explanation:
Given parameters:
Volume of NaCl = 0.4L
Molarity = 0.9M
Unknown:
Number of moles = ?
Solution:
To find the number of moles, the molarity of a solution is the amount of solute contained in a solution.
Molarity = \(\frac{number of moles}{volume}\)
Number of moles = molarity x volume
Insert the parameters and solve;
Number of moles = 0.4 x 0.9 = 0.36mol
A substance such as a frozen sample of carbon dioxide, CO, does not melt into a liquid
form but rather transitions directly to vapor, a gas. This form of physical change is called?
Answers
Answer:heat caused an increase in gas production
Explanation:
If the amount of gas and temperature are constant and you double the volume of the gas,
Answers
Explanation:
pressure decrease and collision decreases
TIMED TEST PLS HELP (will give BRAINLIEST) According to some scientists, which is a cause of global warming? PICK ONLY ONE A) decrease of nitrous oxide B) increase in cloud cover C) decrease of methane gas D) increase in carbon dioxide
Answers
Answer:
D : increase in carbon dioxide
Answer: the Answer is D, 100% sure
increase in carbon dioxide
Explanation: i did the GED school and got it right
Water samples found in the laboratory and in the environment may differ significantly in a number of ways. Consider the composition of deionized water, freshwater, brackish water, and seawater. Predict the relative conductivity of these four types of water and rank them from lowest to highest.
Answers
The conductivity order from lowest to highest order is Deionized water, fresh water, brackish water and finally sea Water.
The sea water has highest conductivity due to high impurities whiles Deionized water do not conduct electricity due to high purity.
(Lowest conductivity to Highest conductivity) :
Deionized water, Fresh water, Brackish water, Sea water.
Conductivity is the measure of the ease at which an electric rate or warmth can skip via a material. A conductor is a material which offers little or no resistance to the float of an electric contemporary or thermal electricity. Substances are classified as metals, semiconductors, and insulators.
Conductivity is a degree of ways nicely a solution conducts electricity. Maximum conductivity measurements are made in aqueous answers, and the ions responsible for the conductivity come from electrolytes dissolved within the water.
Electric conductivity is generally represented through the image σ. In which R is the electrical resistance of a sample of mterial of duration L and uniform go-sectional location A.
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Atom A has triply as long a half-life as atom B. Part A If both of them start out with an amount N0, then in the time that A has been reduced to N0/2, B has been reduced to
Answers
If atom A has a triply as long half-life as atom B, then in the time it takes for atom A to reduce to half its initial amount (N0/2), atom B would be reduced to N0/8. Therefore, the correct answer is option (C) N0/8.
The half-life of a radioactive substance is the time it takes for half of the substance to decay. Let's consider atom A and atom B starting with an initial amount N0.
If atom A has a triply as long half-life as atom B, it means that the half-life of atom A is three times longer than the half-life of atom B. Let's assume the half-life of atom A is t_A and the half-life of atom B is t_B.
In the time it takes for atom A to reduce to half its initial amount (N0/2), the number of half-lives that have passed can be calculated as follows:
N_A = N0 * (1/2)^(t/t_A)
Since we want N_A to be N0/2, we can set up the equation:
N0/2 = N0 * (1/2)^(t/t_A)
Simplifying the equation, we find:
1/2 = (1/2)^(t/t_A)
Since (1/2)^(t/t_A) is equal to (1/2)^1, we can conclude that t/t_A = 1.
Now let's consider atom B. Since the half-life of atom B is t_B, in the same time t that it takes for atom A to reach N0/2, the number of half-lives that have passed for atom B can be calculated as:
N_B = N0 * (1/2)^(t/t_B)
Since t/t_A = 1, we can substitute this value into the equation:
N_B = N0 * (1/2)^(1/t_B)
We know that N_B is the amount to which atom B is reduced. So, when N_B is equal to N0/8, it implies:
N0/8 = N0 * (1/2)^(1/t_B)
Simplifying the equation, we find:
1/8 = (1/2)^(1/t_B)
Since (1/2)^(1/t_B) is equal to (1/2)^3, we can conclude that 1/t_B = 3.
Therefore, in the time it takes for atom A to be reduced to N0/2, atom B is reduced to N0/8. Thus, the correct answer is option (C) N0/8.
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Atom A has triply as long a half-life as atom B.If both of them start out with an amount N0, then in the time that A has been reduced to N0/2, B has been reduced to_______?
(A) N0/2
(B) N0/16
(C) N0/8
(D) N0/4
What force opposes gravity and keeps objects from falling to the center of
the earth?
Answers
La fuerza de la gravedad depende de la masa (el peso) de cada objeto. La fuerza con que se atraen dos objetos es proporcional a su masa y disminuye rápidamente en el momento en que los separamos. De hecho, nosotros también atraemos objetos con ‘nuestra’ fuerza gravitatoria, pero pesamos tan poco que no podemos percibirlo. En cambio, el Sol es tan grande que es capaz de mantenernos girando a su alrededor a pesar de estar muy lejos. La Luna también ejerce su propia fuerza gravitatoria, pero, como es más pequeña y ligera que la Tierra, si nos pesásemos sobre su superficie veríamos que pesamos unas seis veces menos que en la Tierra.
Podríamos preguntarnos por qué la Luna no cae sobre la Tierra al igual que una manzana cae del árbol. La razón es que nuestro satélite nunca está quieto. Se mueve constantemente a nuestro alrededor. Sin la fuerza de atracción terrestre, se alejaría flotando en el espacio. Gracias a esta combinación de velocidad y distancia de nuestro planeta, la Luna siempre está en equilibrio, ni cae ni se aleja. Si se moviera más rápido, se alejaría, si se moviera con más lentitud, ¡caería!
Hemos dicho que la fuerza de la gravedad también depende de la distancia. Si nos alejásemos lo suficiente de la Tierra, escaparíamos a su fuerza de atracción. Y eso es lo que tratamos de hacer con las naves espaciales. Necesitamos superar la llamada ‘velocidad de escape’, que es aproximadamente 11,2 km/s (a esa velocidad, podríamos viajar de Londres a Nueva York ¡en tan solo 10 minutos!). Cuando un cohete alcanza esa velocidad, ya es libre para viajar por el sistema solar.
Dentro de una nave en órbita, no sentimos la fuerza de la gravedad terrestre. Los objetos no caen, sino que flotan, así que si saltas, no regresas al suelo. Es lo que les ocurre a los astronautas cuando están a bordo de una estación espacial que orbita alrededor de la Tierra.
Does anybody know how to do this if so please help !
Answers
Answer:
add x to 7 and divide by 3
Explanation:
easier formula
janice g. smith, organic chemistry, sixth edition, mcgraw hill, new york, 2019. (isbn 978-1-260-11910-7) (solution guide is provided with this package!!!).
Answers
The book "Organic Chemistry, Sixth Edition" by Janice G. Smith, published by McGraw Hill in New York in 2019, includes an ISBN of 978-1-260-11910-7. It also comes with a solution guide.
The book "Organic Chemistry, Sixth Edition" is authored by Janice G. Smith and published by McGraw Hill in New York in 2019. It is a comprehensive resource for studying organic chemistry. The book covers various topics in organic chemistry, including the structure, properties, and reactions of organic compounds. It provides a thorough understanding of the principles and theories that govern organic chemistry.
The ISBN (International Standard Book Number) 978-1-260-11910-7 uniquely identifies this edition of the book. The ISBN is a standardized numerical code used to identify books and facilitate their distribution and cataloging.
It is mentioned that the solution guide is provided with this package, which indicates that the book includes a separate guide containing solutions to the problems and exercises presented in the book. The solution guide can be a valuable resource for students studying organic chemistry as it helps in understanding and practicing problem-solving techniques.
Overall, "Organic Chemistry, Sixth Edition" by Janice G. Smith is a reputable textbook in the field of organic chemistry, offering comprehensive content and a solution guide to aid students in their learning process.
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lead can be prepared from galena [lead(ii) sulfide] by first roasting the galena in oxygen gas to form lead(ii) oxide and sulfur dioxide. heating the metal oxide with more galena forms the molten metal and more sulfur dioxide. (a) write a balanced equation for each step, including the state of each chemical. (1) (2) (b) write an overall balanced equation for the process, including the state of each chemical. (c) how many metric tons of sulfur dioxide form for every metric ton of lead obtained? 0.309 metric tons
Answers
(a). PbS(s) + 3O2(g) → PbO(s) + 2SO2(g) & PbO(s) + PbS(s) → 2Pb(l) + SO2(g), (b). 2PbS(s) + 3O2(g) → 2Pb(l) + 2SO2(g) , (c). 2PbS(s) + 3O2(g) → 2Pb(l) + 2SO2(g).
(a) The two steps involved in the preparation of lead from galena are: Step 1: Roasting of galena to form lead(II) oxide and sulfur dioxide.\(PbS(s) + 3O2(g)\) → \(PbO(s) + 2SO2(g)\) . Step 2: Reduction of lead(II) oxide with galena to form lead metal and sulfur dioxide. \(PbO(s) + PbS(s)\) → \(2Pb(l) + SO2(g)\) . (b) The overall balanced equation for the process is obtained by combining the above two equations: \(2PbS(s) + 3O2(g)\)→ \(2Pb(l) + 2SO2(g)\) . (c) For every metric ton of lead obtained, 0.309 metric tons of sulfur dioxide is formed according to the balanced equation in part (b).
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Is Fire a gas, liquid, or solid...
Answers
Answer:
gas
Explanation:
fire is a gas not liquid or soild
If 17.6 grams of Ca combines completely with 24.2 grams of S to form a compound, what is the percent composition of Ca in the compound?
PLEASE I NEED HELP ASPA!!!!
Answers
The percent composition of Ca in the compound is 42.06%.
The percent composition of Ca in the compound can be calculated using the formula:
% Ca = (mass of Ca/mass of compound) x 100
Given that 17.6 grams of Ca combine completely with 24.2 grams of S to form a compound, we can calculate the mass of the compound as:
mass of compound = mass of Ca + mass of S = 17.6 + 24.2 = 41.8 g
Substituting these values in the formula above, we get:
% Ca = (17.6 / 41.8) x 100 = 42.06%
Therefore, the percent composition of Ca in the compound is 42.06%.
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Which two types of clouds produce precipitation (rain)?
Answers
Answer:
nimbostratus (cumulonimbus) and stratus
Explanation:
The isotopes K-37 and K-42 have the same...
1) number of neutrons
2) number of protons
3) mass number for their atoms
Answers
Answer:
WHEA O IN AN EREM STATO. PETUA TOT low 6 EN 6ACY STATE ... Determine both the total number of protons and the total number of neutrons in an atom of the naturally occurring carbon isotope with the largest mass number.
Explanation:
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Polarities of analyte functional group increase in the order of hydrocarbon ethers < esters
Answers
The correct order of the increasing polarity of the analyte functional group isEthers < Esters.
The given statement is "Polarities of analyte functional group increase in the order of hydrocarbon ethers < esters." The order of polarities of functional groups is the order of their increasing polarity (i.e., less polar to more polar) based on their electron-donating or withdrawing ability from the rest of the molecule.Polarity of analyte: The analyte's polarity is directly proportional to the dipole moment of the functional group, which is associated with a difference in electronegativity between the atoms that make up the functional group.The electronegativity of an element is its ability to attract electrons towards itself. The greater the difference in electronegativity between two atoms, the more polar their bond, and hence the greater the polarity of the molecule.
To find the correct order of the increasing polarity of the analyte functional group, let's first compare the two groups: hydrocarbon ethers and esters. Here, esters have a carbonyl group while ethers have an oxygen atom with two alkyl or aryl groups. The carbonyl group has more electronegative oxygen, which pulls electrons away from the carbon atom, resulting in a polar molecule. On the other hand, ethers have a less polar oxygen atom with two alkyl or aryl groups, making them less polar than esters. Therefore, the correct order of the increasing polarity of the analyte functional group isEthers < Esters.
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