The dotted arrow in this reaction is a placeholder. Select the arrow that best describes the relationship between the reactants and products. -CECAH -CEC-L Identify the correct arrow descriptor.

The final temperature of the water is: T_final = 45.0°C

We can use the formula for the specific heat capacity of the water to solve this problem:

q = mcΔT

First, we can calculate the initial energy of the water:

q = mcΔT

q = (10.0 g) (4.184 J/g°C) (25.0°C)

q = 1,046 J

Next, we can calculate the final temperature after absorbing 840 J:

q = mcΔT

840 J = (10.0 g) (4.184 J/g°C) (ΔT)

ΔT = 20.0°C

Therefore, the final temperature of the water is:

T_final = T_initial + ΔT

T_final = 25.0°C + 20.0°C

T_final = 45.0°C

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Answer:

Rabeprazole belongs to a class of drugs known as proton pump inhibitors (PPIs).

Answer:

-1

Explanation:

Electrons have a negative charge, so when you add an electron to an element their charge goes down by 1.

Answer:

the answer is nitrogen and rubidium (C)

Explanation:

ionic bonds only form between metals and non-metals

Answer:

answer 7.4 atm

Explanation:

i did this and got it correct

Answer:

Please tell us the full question

Answer:

D) 7.5 grams

Explanation:

Hello,

In this case, since the percent yield is defined by:

\(Y=\frac{m^{actual}}{m^{theoretical}} *100\%\)

In such a way, since the percent yield is up to 25% and the expected or theoretical amount is 30 g of the product, the actual yield of the reaction is:

\(m^{actual}=\frac{Y*m^{theoretical}}{100\%} =\frac{25\%*30g}{100\%} \\\\m^{actual}=7.5g\)

Therefore the answer is D) 7.5 grams.

Best regards.

Answer: a

Explanation:

this is common sense

Answer:

C'est fini sous la lettre A. Ice crystals from forming inside it's body

Answer:

9.) Homeostasis

10.) Epidermis

11.) Cytoplasim

12.) Classification

Based on the heat of reaction, if 123 kJ of heat is evolved when the reaction described below is carried out, the mass of HCl gas (36.46 g/mol) produced is 23.6 g.

The heat of a reaction is the amount of heat energy given off or absorbed in the reaction.

During a reaction, energy changes occur as a result of the breaking of bonds in the reactants as well as the formation of bonds in the products.

The sum of the overall energy change that accompanies the formation of products from the reactants gives the heat change of a reaction.

Considering the heat change of the given reaction below:

3 Cl₂ (g) + PH₃ (g) → PCl₃ (g) + 3 HCl (g)     ∆H = - 570.4 kJ

The formation of 3 moles of HCl results in the evolution of 570.4 kJ of heat.

If 123 kJ of heat are evolved, then the moles of HCl produced will be:

Moles of HCl produced = 123 kJ * 3 moles / 570.4 kJ

Moles of HCl produced =  0.647 moles

Mass of HCl produced = 0.647 * 36.46

Mass of HCl produced = 23.6 g

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When hydrogen bromide is added to 2-methylbut-2-ene, two products are expected to be produced: 2-bromo-2-methylbutane (major product) and 3-bromo-2-methylbutane (minor product).

The addition of HBr to 2-methylbut-2-ene follows the Markovnikov addition rule. This means that the hydrogen atom and the bromine atom will add to the carbon atoms in the double bond, such that the hydrogen atom adds to the carbon with the greater number of hydrogen atoms, and the bromine atom adds to the carbon with the lesser number of hydrogen atoms.

In this case, the hydrogen atom will attach to the second carbon atom, which has three hydrogen atoms, while the bromine atom will attach to the third carbon atom, which has only one hydrogen atom. This produces the major product, 2-bromo-2-methylbutane.

The formation of the minor product, 3-bromo-2-methylbutane, occurs due to the rearrangement of the carbocation intermediate formed during the addition reaction. The carbocation can rearrange either by shifting a methyl group from the second to the third carbon, or by shifting a hydrogen atom from the third to the second carbon. This rearrangement produces the minor product, 3-bromo-2-methylbutane.

In conclusion, the addition of HBr to 2-methylbut-2-ene produces two products: 2-bromo-2-methylbutane (major product) and 3-bromo-2-methylbutane (minor product). The major product forms due to Markovnikov addition rule, while the minor product forms due to carbocation rearrangement.

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852 grams of chromium carbonate needs to be measured out to produce 3 moles of chromium carbonate.

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Answer:

The acid will react with the metal, causing hydrogen gas and salt to form from it.

Answer:

Explanation:

The formula of the compound in which the atom combining ratios are:

chlorine : oxygen : fluorine = 1:3:1 is ClO3F i.e. perchloryl fluoride.

The chemical formula is define as a method of providing information about chemical properties of atoms that make a particular chemical compound or molecule by chemical name and symbols.

There are mainly three types of chemical formula

Thus, the formula of the compound in which the atom combining ratios are:

chlorine : oxygen : fluorine = 1:3:1 is ClO3F i.e. perchloryl fluoride.

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Answer:

the work done on the gas is 4,988.7 J.

Explanation:

Given;

number of moles of the monoatomic gas, n = 4 moles

initial temperature of the gas, T₁ = 300 K

final temperature of the gas, T₂ = 400 K

The work done on the gas is calculated as;

\(W = \Delta U = nC_v(T_2 -T_1)\)

For monoatomic ideal gas: \(C_v = \frac{3}{2} R\)

\(W = \frac{3}{2} R \times n(T_2-T_1)\)

Where;

R is ideal gas constant = 8.3145 J/K.mol

\(W = \frac{3}{2} R \times n(T_2-T_1) \\\\W = \frac{3}{2} (8.3145) \times 4(400-300) \\\\W = \frac{3}{2} (8.3145) \times 4(100)\\\\W = 4,988.7 \ J\)

Therefore, the work done on the gas is 4,988.7 J.

The correct answer is a) KBr.

KBr is an ionic compound composed of a metal (K) and a non-metal (Br). When this compound is added to water, the polar water molecules surround the ions in the solid and separate them, which leads to the compound dissolving in water.

What is Ionic Compound?

An ionic compound is a chemical compound composed of ions held together by electrostatic forces called ionic bonds. Ions are atoms or molecules that have gained or lost one or more electrons, giving them a positive or negative charge. In an ionic compound, a positively charged ion (cation) and a negatively charged ion (anion) are attracted to each other to form a stable compound.

CO2, CH4, and O2 are nonpolar molecules, and therefore, do not dissolve well in water. CO2 and O2 are gases at room temperature and pressure, while CH4 is a gas at room temperature but can be liquefied under pressure.

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Fluorine (F-) is the element with the fewest valence electrons. Seven electrons make up the outermost shell of fluorine, and one of them is unpaired. As a result, fluorine possesses seven valence electrons altogether.

Eight valence electrons are present in magnesium (Mg2+), nine are present in gallium (Ga+), eight are present in argon (Ar+), four are present in carbon (C+), six are present in sulphur (S2-), and seven are present in fluorine (F-).

Fluorine has a lower number of valence electrons than the other elements because it has a greater effective nuclear charge. This indicates that the fluorine atom will take electrons away from its outermost shell since it is more attracted to electrons than the other elements.

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If a beaker contains 15.6 moles of water, H\(_2\) O, 9.3×10²⁴  are the number of molecules this represent.

The smallest recognisable unit into that a pure substance may be divided while retaining its composition & chemical properties is a molecule, which is a collection of more than one atom.

Until parts made up of individual molecules are reached, splitting of a sample of an item smaller progressively smaller parts does not result in a change regarding its composition as well as its chemical properties.

5.number of molecules= 15.6 ×  6.022×10²³

                                  =9.3×10²⁴  

6. .number of molecules=0.317  ×  6.022×10²³

                                  =1.89×10²³

7. number of moles =6.01 x 10 25/ 6.022×10²³

                               = 100 moles

8.  number of moles =3.54 x 10²¹/ 6.022×10²³

                               = 0.005moles

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Explanation:

A. Around December 21, the Northern Hemisphere tilts the farthest away from the Sun. This is called the northern winter solstice, and it is when we have the least amount of daylight of any time of the year.

B.Solstices and shifting solar declinations are a result of Earth's 23.5° axial tilt as it orbits the sun. Throughout the year, this means that either the Northern or Southern Hemisphere is tilted toward the sun and receives the maximum intensity of the sun's rays.

C.The tilt of the Earth's axis also defines the length of daylight. Daylight hours are shortest in each hemisphere's winter. Between summer and winter solstice, the number of daylight hours decreases, and the rate of decrease is larger the higher the latitude. The fewer sunlight hours the colder the nights

D.The second solstice occurs on December 21 or 22 when the north pole is tilting 23.5 degrees away from our Sun and the south pole is inclined toward it. This is the shortest day of the year in the northern hemisphere — the northern hemisphere winter solstice.

Answer:

Its called bad cholesterol because a high LDL level leads to  buildup of cholesterol in your arteries.

Explanation:

The balanced equation is: 4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

The given chemical equation is unbalanced. To balance it, we need to adjust the coefficients in front of each chemical species until the number of atoms on both sides of the equation is equal.

The unbalanced equation is:

2 \(H_2S\)+ 3 \(O_2\)→ \(SO_2\)

Let's start by balancing the sulfur (S) atoms. We have two sulfur atoms on the left side and one sulfur atom on the right side. To balance the sulfur, we can place a coefficient of 2 in front of the \(SO_2\):

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)

Now, let's balance the hydrogen (H) atoms. We have four hydrogen atoms on the left side (2 from each \(H_2S\)) and none on the right side. To balance the hydrogen, we can place a coefficient of 4 in front of the water (H2O) on the right side:

2 \(H_2S\)+ 3 \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

Finally, let's balance the oxygen (O) atoms. We have six oxygen atoms on the right side (3 from \(O_2\) and 3 from 2 \(SO_2\)) and three on the left side (2 from \(H_2S\)). To balance the oxygen, we can place a coefficient of 3/2 in front of the O2:

2 \(H_2S\)+ (3/2) \(O_2\)→ 2 \(SO_2\)+ 4 \(H_2O\)

To remove the fractional coefficient, we can multiply all coefficients by 2:

4 \(H_2S\) + 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

Now the equation is balanced, with an equal number of atoms on both sides. The balanced equation is:

4 \(H_2S\)+ 3 \(O_2\)→ 4 \(SO_2\)+ 8 \(H_2O\)

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In a formaldehyde compound we will have a central Carbon being linked to 2 Hydrogens and one Oxygen, even though the bonding with the two hydrogens is a covalent bond, which means they are sharing electrons in the valence shell, the polarity between oxygen and carbon in the double bond makes the compound to be a Polar Covalent Compound, having a polar covalent bonding

When defining a type of bonding between elements, we can use the electronegativity rules, which states, if:

The difference in electronegativity between the two elements is less than 0.5, the compound will be covalent, in Carbon and Hydrogen for example the difference is 2.5 C - 2.1 H = 0.4, this is why in compounds with only C and H we will always have a covalent bonding, or nonpolar covalent bonding, because neither elements are pulling the electrons in the valence shell from each other, they are sharing it, all 4 electrons from C and 1 electron from H

If the difference is between 0.5 and 1.6, the bonding will be considered to be a polar covalent bonding, it is not an ionic bonding but it will cause some pulling of the electrons towards one element, and in Carbon and Oxygen case this is exactly what happens

3.5 O - 2.5 C = 1.0, which is why formaldehyde will be a polar covalent compound, because the 6 electrons from the valence shell of the Oxygen will pull with a considerable force the 2 electrons shared from the Carbon atom

If the difference is greater than 1.6 we will have an ionic bonding, which is the case of NaCl for example

The partial pressure of H2S gas in the headspace of the pipe is \(1*10^{-16\)if the wastewater has an s2- concentration of \(1*10^{-15\)m and ph is 7.

The partial pressure of H2S gas in the headspace of the pipe can be calculated using the following equation:

\(H2S(aq) + H2O(l) < - > H3O+(aq) + HS-(aq)\)

Where [H3O+] = [HS–] = \(1*10^{-7\) M as given that pH = 7

We can calculate the partial pressure of H2S using the equation

pH2S = [H2S] * Kb Where Kb is the dissociation constant for the reaction:

Kb = [HS–] * [H3O+] / [H2S]

Given the concentration of H2S =\(1 * 10^{-15\)M

Kb = \((1*10^{-7} M) * (1*10^{-7} M) / (1*10^{-15} M)\)

Kb = \(1*10^{-1\)M

Therefore, the partial pressure of H2S gas in the headspace of the pipe is pH2S = [H2S] * Kb

pH2S = \((1*10^{-15} M) * (1*10^{-1} M)\)

pH2S =\(1*10^{-16} atm\)

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Answer:

To calculate the number of significant figures in a number with decimal,

start at the first non-zero digit in the number and count the total number of digits till the end

hence, in this number:

we will have 6 significant figures

Answer:

answer C) 1 and 4

Explanation:

Answer:

C) 1 and 4

Explanation:

I took the test. Hope this helps!

Explanation:

Isomers are molecules of organic substances that have the same molecular formula but have different properties and structural characteristics.

Answer: Isomers

Answer:

The solubility of alkaline earth metal hydroxides in water increases down the group because the size of the metal cation increases as you move down the group. This increase in size results in a decrease in the cation's charge density, which makes it less able to attract and hold onto hydroxide ions. As a result, the hydroxides become more soluble in water as you move down the group. Additionally, the lattice energies of the hydroxides decrease down the group, making it easier to break apart the crystal lattice structure and dissolve the hydroxides in water.