the figure shows four charges at the corners of a square of side l. assume q and q are positive.

A magnetic field is experienced by the charged particle in the +y direction.

Discussion:

Fleming's left-hand rule:

In accordance with Fleming's Left Hand Rule, the thumb, forefinger, and middle finger of the left hand should be positioned perpendicular to one another. The thumb should point in the path of the power exerted by the conductors, the forefinger should point in the magnetic field direction, and the middle finger should point in the path of the electric current.

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Answer:

1.5 m\s Ans ......

Explanation:

Data:

f = 0.5 Hz

w = 3 m

v = ?

Formula:

v = fw

Solution:

v = (0.5)(3)

v = 1.5 m\ s Ans ........

A total differential is an equation in which all the differentials can be integrated independently of each other. To verify that the given expressions are total differentials, we must check if they meet the conditions of being an exact differential function.The given expression is not an exact differential function.

According to the exact differential function, an expression dQ should be equal to the sum of two partial derivatives of the same function. i.e, dQ= dP+ dRA primitive function of an expression is obtained by integrating the given expression partially. Let's solve the given expressions, one by one:

1. Expression : (x² + 2xy-y²)dx + (x²-2xy - y²)dy. Now, we need to find the partial derivatives of the above function with respect to x and y.∂P/∂x = x² + 2xy - y²  ∂Q/∂y = x² - 2xy - y².

On verifying, we get:∂P/∂x = ∂Q/∂y.

Hence, the given expression is an exact differential function.

To find the primitive function, we need to integrate any one of the partial derivatives with respect to x and other with respect to y.

∴ P(x,y) = ∫(x² + 2xy - y²)dx = x³/3 + x²y - xy² + C1 and ∴ Q(x,y) = ∫(x² - 2xy - y²)dy = x²y - y³/3 + C2.

Therefore, the primitive function of the expression is: P(x,y) = Q(x,y) = x³/3 + x²y - xy² - y³/3 + C2.

Expression : (2xcosy - y² sinx) dx + (2ycosx - x² siny) dy. Now, we need to find the partial derivatives of the above function with respect to x and y.∂P/∂x = 2cosy  ∂Q/∂y = 2ycosx.

On verifying, we get:∂P/∂x ≠ ∂Q/∂y .

Hence, the given expression is not an exact differential function.

Therefore, there does not exist a primitive function for the given expression.

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If the distance between two objects is decreased to one fourth of the original distance, then the new force of attraction between the objects will be 16 times the initial force.

From Newton's law of universal gravity, the force of attraction between two objects is given as:

F = GM₁M₂ / r²

Where

Obtaining a relationship between the force of attraction and the distance, we have:

F = GM₁M₂ / r²

Cross multiply

Fr² = GM₁M₂

GM₁M₂ = constant

F₁r₁² = F₂r₂²

With the above formula, we can obtain the new force of attraction as follow:

F₁r₁² = F₂r₂²

F × r² = F₂ × (0.25r)²

Fr² = F₂ × 0.0625r²

Divide both side by 0.0625r²

F₂ = Fr² / 0.0625r²

F₂ = F / 0.0625

F₂ = 16F

Thus, the new force of attraction is 16 times the initial force.

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The magnitude of the Thevenin impedance (Zth) is 2.4 ohms.

The Thevenin theorem allows us to represent a complex power system with a simpler equivalent circuit, consisting of a Thevenin voltage source in series with an impedance. In this case, the power system is represented by a 120 V source with a Thevenin impedance (Zth) in series.

To find the magnitude of Zth, we can use the formula: Zth = Vth/Isc, where Vth is the Thevenin voltage and Isc is the short circuit current.

Given that the short circuit current (Isc) is 50 A, we need to find the Thevenin voltage (Vth). The Thevenin voltage can be determined by measuring the voltage across the terminals of the power system when it is open-circuited.

However, since only the short circuit current is provided and the Thevenin voltage is not given, we cannot directly calculate the magnitude of the Thevenin impedance.

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Answer:

30 J

Explanation:

You have to transform g in kg, so 600 g=0,6 kg

the kinetic energy value is

K= ½ mv² so it is K=½ (0.6×100)=30 J

\(\text{Kinetic energy,}\\\\~~~~~~E_k = \dfrac 12 mv^2\\\\~~~~~~~~~~=\dfrac 12 \times 6\times 10^{-1} \times 10^2~~~~~~~;[m = 600 g = 600 \times 10^{-3}~ \text{kg} = 6\times 10^{-1}~ \text{kg}]\\\\~~~~~~~~~~=\dfrac{60}2\\\\~~~~~~~~~~= 30~ J\)

The S.I. unit of E is NC^-1 and that of B is NA^-1 m^-1, then unit of E/B is A m/C (ampere meter per coulomb). This unit represents the ratio between the electric field and the magnetic field, indicating the strength and direction of the electromagnetic field.

The SI unit of electric field (E) is NC^(-1) (newton per coulomb) and the SI unit of magnetic field (B) is NA^(-1) m^(-1) (tesla). To determine the unit of E/B, we need to divide the unit of E by the unit of B.

Dividing the unit of E (NC^(-1)) by the unit of B (NA^(-1) m^(-1)), we can simplify the expression:

E/B = (NC^(-1))/(NA^(-1) m^(-1))

To simplify this expression, we can cancel out the common units in the numerator and denominator:

E/B = (N/C)/(N/(A m))

Now, let's simplify further by dividing the numerator and denominator:

E/B = (N/C) * (A m/N)

Canceling out the common units:

E/B = (A m)/(C)

Therefore, the unit of E/B is A m/C (ampere meter per coulomb).

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When a cannonball is fired, the momentum of the system (cannon + cannonball) is conserved if there are no external forces acting on the system. This means that the total momentum of the system before firing the cannonball is equal to the total momentum of the system after the cannonball is fired. In other words, the momentum of the cannonball in one direction is equal to the momentum of the cannon in the opposite direction.

To further understand this concept, it is important to know that momentum is defined as the product of an object's mass and velocity. Therefore, if the mass of the cannonball is increased, the momentum of the system will increase as well. Similarly, if the velocity of the cannonball is increased, the momentum of the system will increase.

In conclusion, the conservation of momentum is a fundamental principle in physics that is essential in understanding the behavior of moving objects. It is important to note that the momentum of a system is only conserved if there are no external forces acting on the system. This principle is applicable not only to cannonballs but to all moving objects in the universe.

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The line graph consists of a horizontal x-axis and a vertical y-axis. Most line graphs only deal with positive number values and it is more easy to understand.

It is beneficial for showing changes and trends over different time periods in the graphs. It is also helpful to show small changes in the graph which are difficult to measure in other graphs. Line graph is common and effective charts because they are simple easy to understand and more efficient. It is better for seeing the rate clearly. It is more easily to compare.

So we can conclude that: The line graph consists of a horizontal x-axis and a vertical y-axis. Most line graphs only deal with positive number values and it is more easy to understand.

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Answer:

the correct one is 2

Explanation:

The emission and arcion spectra are similar, in the emission spectra a heated material emits photons for the internal transitions of the electrons, in the absorption spectrum the continuous emission of a lamp is absorbed at the energies that the material has transitions.

In our case the material is low early, so all the electrons are in their base states.

As the light beam has all wavelengths, those corresponding to the first emission of the material will be observed.

When reviewing the answers, the correct one is 2

Lightning produces its most intense radiation in the visible light spectrum, while a nuclear explosion would radiate most strongly in the X-ray part of the electromagnetic spectrum, due to the differences in their respective temperatures.

Lightning and nuclear explosions both produce extreme temperatures but at different orders of magnitude. Lightning can generate temperatures on the order of 10⁴K, while nuclear explosions can reach temperatures on the order of 10⁷K.

When it comes to the part of the electromagnetic spectrum where each would radiate most strongly, we need to consider their respective temperatures and the relationship between temperature and the wavelength of radiation emitted.

For lightning, with its maximum temperature of 10⁴K, the radiation it emits most strongly falls within the visible light spectrum. Visible light has a wavelength range of approximately 400 to 700 nanometers, and this is the range in which lightning produces its most intense radiation. This is why we see lightning as a bright flash of light.

(b) A nuclear explosion, with its much higher temperature of 10⁷K, would radiate most strongly in the X-ray part of the electromagnetic spectrum. X-rays have much shorter wavelengths compared to visible light, typically ranging from 0.01 to 10 nanometers. At the high temperatures of a nuclear explosion, the emitted radiation shifts towards shorter wavelengths, resulting in intense X-ray emission.

To summarize, lightning produces its most intense radiation in the visible light spectrum, while a nuclear explosion would radiate most strongly in the X-ray part of the electromagnetic spectrum, due to the differences in their respective temperatures.

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The angular diameter of the Earth from the surface of the Moon is, between a=1.80226° (at apogee and the Earth is near the horizon) and a=2.02452° (at perigee and for an observer at the equator and when the Earth is at maximum altitude on the meridian)

We calculate the angular diameter of the Earth using the equation:

a=arctanD/d

where a is the angular diameter, D is the physical diameter of the Earth, and d is the distance from the Moon to the Earth.

The equatorial radius of the Earth is rE=6378.1km, the diameter is therefore

D=2×rE=12756.2.

   The mean distance to the Moon is d=384399km. This gives a (mean) angular diameter of a=1.90065°.

At Perigee the distance is d=362,600km. This gives an angular diameter of a=2.01482°

At Apogee the distance is d=405,400km. This gives an angular diameter of a=1.80226°

These Moon-Earth distances are as seen from the centre of the Moon. To calculate the diameter from the surface of the Moon, to subtract the position of the observer along the Moon-Earth axis.

If the observer is on the Moon's equator and the Earth is at zero-hour angle, the distance to the Earth needs to be subtracted by rM=1738.14km. Thus, we have;

 The mean distance to the Moon is d=384399−1738=382661km, giving an angular diameter of a=1.90928°.

At Perigee the distance is d=362600−1738=360862km. We have an angular diameter of a=2.02452°

At Apogee the distance is d=405400−1738=403662km. We have an angular diameter of a=1.81001°

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(a) Flowchart: A condenser process flowchart is provided, illustrating the inputs and outputs of the humid air stream, O₂, N₂, and the condensed liquid water. (b) Total flow rate: The total flow rate of the feed stream entering the condenser is 5.296F mol/s, considering the flow rates of water vapor, O₂, and N₂. (c) Enthalpy and heat transfer: The enthalpy changes for water vapor and O₂ are calculated, resulting in a heat transfer of -0.072 kF kW, indicating heat removal by the condenser. the heat transferred by the condenser is -0.072 kF kW.

(a) Flowchart:

(b) Total flow rate of the feed stream:

The flow rate of N2 leaving the condenser is given as 5.18 mol/s.

The flow rate of water vapor entering the condenser is 58.0 mol% of F.

80% of the above water vapor is condensed and removed, leaving 20% remaining.

So, 20% of the above water vapor remaining in the humid air after condensation is 0.116F mol/s.

The flow rate of O2 is given as 8.8 mol% of F.

The total flow rate of the feed stream is the sum of the flow rates of water vapor, O2, and N2:

Total flow rate = Flow rate of water vapor + Flow rate of O2 + Flow rate of N2

              = 0.116F + 0.088F + 5.18

              = 5.296F mol/s

(c) Inlet-Outlet Enthalpy Table:

To calculate the heat transferred by the condenser, we need to determine the enthalpy changes for water vapor (H3 to H4) and O2 (H5).

The enthalpy change for water vapor can be calculated as:

ΔH_vap = Enthalpy of water vapor at 30°C - Enthalpy of water vapor at 150°C

      = [40.657 + 0.119 × (30 - 0)] - [40.657 + 0.119 × (150 - 0)]

      = -13.607 kJ/kmol

Enthalpy of water leaving the condenser (H4) can be calculated as:

H4 = Enthalpy of water vapor at 30°C = 40.657 kJ/kmol

Enthalpy of O2 leaving the condenser (H5) can be taken as:

H5 = Enthalpy of O2 at 30°C = 0.102 kJ/kmol

The heat transferred by the condenser (q) can be calculated as:

q = Total flow rate × ΔH

 = (5.296F mol/s) × (-13.607 kJ/kmol) × 10⁻³ kW/J

 = -0.072 kF kW (where kF is the constant conversion factor 10⁶)

Therefore, the heat transferred by the condenser is -0.072 kF kW.

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First, let's calculate the total resistance in the circuit.

Since the two resistors are in series, the total resistance is the sum of each resistance:

Now, to calculate the current, we can divide the voltage by the total resistance:

Therefore the current is 2.083 A.

The Current throughout the circuit is 2.083 A.

To calculate the current, we will use the formula:

I = V / R

Where,

I = current,

V = Voltage of Battery.

R = Total Resistance.

Now, we will use the given values in the question,

V = 25 V

R = 7Ω + 5Ω

Now, we have to find total Resistance,

Total Resistance =  7Ω + 5Ω

= 12Ω.

Now, we will calculate the current using the above formula,

Putting all the values,

I = 25 / 12

I = 2.083 A.

Therefore, the Current running throughout the circuit is 2.083 A.

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Explanation:

Speed = 100/20 = 5cm/s

Option A is the correct answer

Speed = Distance/Time, therefore the speed of the mouse is 5 cm/s. Hence, option A is correct.

The pace at which a distance changes over time is referred to as speed. It has a dimension of time distance. As a result, the fundamental unit of time and the basic unit of distance are combined to form the SI unit of speed. Thus, the meter per second (m/s) is the SI unit of speed.

You can determine an object's speed if you know how far it moves in a given amount of time. For instance, an automobile is moving at a pace of 70 miles per hour if it covers 70 miles in an hour (miles per hour).

If you know how far something has traveled and how long it took to get there, you can calculate its average speed. Speed is calculated as speed = distance/time. Hence, option A is correct.

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The magnitude of the gravitational field strength is  2.76 * 10^-18 N/Kg.

The gravitational force is the force that acts on an object that is found in the earth's gravitational field. Let us recall that if an object is thrown up, the object must surely and definitely come down. This is because, there is a force of gravity that is acting on the object on the earth gravitational filed and that the direction of this force as it were is always towards the center of the earth.

In this case we are asked by the question that we ought to be able to obtain the gravitational field strength of the Hubble telescope as we have in the question and this we want to do.

Hence;

g = Gm/r^2

G = gravitational constant

m = mass of the object

r = distance covered

g = 6.67 * 10^-11 * 1.3 * 10^4/(5.6 * 10^5)^2

g = 2.76 * 10^-18 N/Kg

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The centripetal acceleration of the hammer is 36.36 m/s².

Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.

Mass of the hammer = 6.90 kg.

Angular speed of the hammer = 0.9 rev/s

= 2π × 0.9 rad/s

= 6.031 rad/s

Length of the chain = 1.0 meter.

Hence,  the centripetal acceleration of the hammer is = ω²r

= (6.03)² × 1.0 m/s²

= 36.36 m/s²

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Answer:

The answer is . A 46.2g

The applied force is exerted by a moving object, in this case, the ruler. It is the force that is used to push or move the ball. The direction of the applied force is along the surface of the ruler, and it is represented by an arrow pointing in the direction of the push or motion.

The normal force, on the other hand, is exerted by a stationary object, in this case, the barrier or surface that the ball rests on. The normal force acts perpendicular to the surface and prevents the ball from sinking into the surface. It is represented by an arrow pointing perpendicular to the surface of the barrier or ground.

To provide a visual representation, you can imagine drawing an arrow on the ruler to represent the applied force, pointing in the direction of the ruler's motion or push. Additionally, you can draw another arrow on the ball, pointing vertically upwards, to represent the normal force exerted by the surface. This will indicate the direction and magnitude of both forces acting on the ball.

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Answer:

yeah this statement is tru

Explanation:

it is because the speed of the bullet is more than the speed of rolling ball .so from this reason we cannot catch a bullet.

A bullet will be moving much faster than a rolling ball. Even seeing a bullet in flight requires it to be extremely low velocity.

Answer:

1. Motion

2. Empty space

3. Far apart

4. Independently

5. Random or rapid

6. Collision

7. Kinetic energy

8. Atmospheric

9. 273 Kelvin or 0° Celsius

10. 1 atm, 101.3 kPa or 760 mmHg

Explanation:

In science, matter can be defined as anything that has mass and occupies space. Any physical object that is found on earth is typically composed of matter. Matter are known to be made up of atoms and as a result has the property of existing in states.

Generally, matter exists in three (3) distinct or classical phases and these are;

I. Gas.

II. Solid.

III. Liquid.

Filling the missing words or texts in the question, we have;

The kinetic theory describes the motion of particles in matter and the forces of attraction between them. The theory assumes that the volume occupied by a gas is mostly empty space, that the particles of gas are relatively far apart, move independently of each other, and are in constant random or rapid motion. The collision between particles are perfectly elastic so that the total kinetic energy remains constant. Gas pressure results from the simultaneous collisions of billions of particles with an object. Barometers are used to measure atmospheric pressure. Standard conditions are defined as a temperature of 273 Kelvin or 0° Celsius and a pressure of 1 atm, 101.3 kPa or 760 mmHg.

The speed of the hot dog cart going at point B wen jasmine finally wakes up is 21.36 m/s.

Mass of the cart = m = 327 Kg

Speed of the cart while rolling downhill = v = 2.9 m/s

Height of the hill = h = 50 m

Height at point B = h' = 30 m

Speed of the cart when jasmine wakes up = v' =

Using the conservation of energy theorem,

= sum of kinetic and potential energy initially = sum of kinetic energy finally at point B

= mgh + (1/2)mv² = (1/2)mv'²

= gh + (1/2)v² = (1/2)v'²

= 9.81 X (50-30) + (1/2) X 2.9² = (1/2)v'²

= v'² = 21.36 m/s

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Answer:B

Explanation:

.03 of an hr is 2 mins and if it takes 2 mins to drive 4 miles enter it in pace calulator you are going 120mph so the closest to 120 is 133mph

The kid is breaking the speed limit of 45 miles/hr since he is going at 133.3 miles/hr.

Speed is the ratio of distance travelled to time taken. It is given by:

Speed = distance / time

Since the distance to the mall is 4 miles, the time taken is 0.03 hours, hence the speed is:

Speed = distance / time

Speed = 4 miles / 0.03 hours

Speed = 133.3 miles/hr

Hence the kid is breaking the speed limit of 45 miles/hr since he is going at 133.3 miles/hr.

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This can be calculated by the formula - CD=FD12ρAv2Explanation:Air resistance, or drag, is dependent on a number of factors including the density of the air, the area of the object, its velocity, and other properties of the object. The units for the force of air resistance are in Newtons (N).

The magnitude of the drag force is characterized by the dimensionless drag coefficient CD , given by CD=FD12ρAv2, C D = F D 1 2 ρ A v 2.

Where ρ is the density of the fluid (in this case, air), A=(1/4)πD2 A = ( 1 / 4 ) π D 2 is the cross-sectional area of the object, and v is the object's speed.

Therefore,  Air resistance can be calculated by taking air density times the drag coefficient times area all over two, and then multiply by velocity squared.

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Answer:

The correct answer would be C. 5.0kg

Explanation:

The mass of an object never changes unless parts of the object are taken away. In other words, although the gravitational force is different on the moon then on the earth the mass of the object would remain the same.

The flaw in the experiment on water recycling is that the student did not see water dripping off the glass plate as expected. To correct this flaw, the student should use a cold glass plate instead of a hot glass plate.

The correct option to the given question is option 4.

When the student holds the hot glass plate above the beaker, the water vapor in the atmosphere will come into contact with the cold surface of the plate and condense, forming water droplets. However, if the glass plate is already hot, it will not be able to cool down the water vapor quickly enough for condensation to occur.

By using a cold glass plate, the temperature difference between the plate and the water vapor will be greater, allowing for faster condensation. This will result in water droplets forming on the glass plate and dripping off, demonstrating the process of water recycling through the atmosphere.

Therefore, the correct method to correct the flaw in this experiment is to use a cold glass plate instead of a hot glass plate. This will enable the student to observe water droplets on the glass plate as expected.

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Answer:

100kPa

Explanation:

Given parameters:

Initial volume of gas  = 1L

Pressure  = 200kPa

Final volume  = 2L

Unknown:

Final pressure  =  

Solution:

According to Boyles's law "the volume of fixed mass of gas of a gas varies inversely as the pressure changes if temperature is constant".

  Mathematically;

            P₁V₁  = P₂V₂

P and V are volume and pressure

1 and 2 are initial and final states

  Insert the parameters and solve;

            200 x 1  = P₂ x 2

                 P₂  = 100kPa