The fundamental frequency of a string fixed at both ends is 255 Hz. How long does it take for a wave to travel the length of this string? (Answer in s)

A reaction yields 2.5165×10⁶ kJ. So, A) 2.300×10−6 kg mass was lost.

This question involves the use of Einstein's famous equation, E=mc², which relates energy and mass. Rearranging the equation, we get m=E/c², where m is the mass lost, E is the energy released, and c is the speed of light.

Substituting the given values, we get:

\(m = \frac{2.5165 \times 10^8 \, \text{kJ}}{c^2}\)

We can convert kJ to J by multiplying by 1000, and c is approximately 3×10⁸ m/s.

Substituting these values, we get:

\(m = \frac{2.5165 \times 10^{11} \, \text{J}}{9 \times 10^{16} \, \text{m}^2/\text{s}^2}\)

m = 2.7961×10⁻⁶ kg

Therefore, the closest option is A) 2.300×10−6 kg.

It is important to note that the equation E=mc² is only applicable for processes involving the complete conversion of mass into energy, such as nuclear reactions. In other cases, the amount of mass lost may be negligible compared to the total mass involved in the reaction.

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Answer:

v=wavelength x f = 2 x 3 = 6 m/s

Explanation:

The speed of a wave is the product of its frequency and wavelength. The speed of the periodic wave with the frequency of 3 Hz and wavelength of 2 m is 6 m/s.

Frequency of a wave is the number of wave cycles per unit time. It is the inverse of the time period of the wave. Frequency is inversely proportional to the wavelength  of the wave.

The relation between speed, frequency and wavelength of a wave is given by the expression as written below:

c =νλ

where, c is the speed, ν be the frequency and λ be the wavelength.

Given that ν = 3 Hz or 3 s⁻¹

and λ = 2 m

then speed c = 2 m × 3 Hz = 6 m/s

Therefore, the speed of the periodic wave is 6 m/s.

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Answer:

The sound waves from a radio speakers

Explanation:

Answer:

girl bye you must love to exercise

:D

The quality of a protostar that determines which path it will take through stellar evolution is its mass.

The mass of a protostar determines the internal temperature and pressure, which in turn determines the rate of nuclear reactions in the core of the star. These nuclear reactions generate the energy that keeps the star shining and determines its evolution.

A protostar with a mass less than about 0.08 solar masses will not be able to sustain nuclear reactions and will become a brown dwarf, which is an object that is too small to be a star but too large to be a planet. A protostar with a mass between 0.08 and 0.4 solar masses will become a red dwarf, which is a small and relatively cool star that can burn hydrogen for a very long time. A protostar with a mass between 0.4 and 8 solar masses will become a main-sequence star, which is a star that is burning hydrogen in its core. Finally, a protostar with a mass greater than 8 solar masses will become a high-mass star, which will follow a different path of evolution leading to a supernova explosion.

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Answer:

In most plants, the leaves are the main food factories. They capture the sun's energy with the help of chlorophyll in the leaf cells. The chlorophyll traps and packages the energy from the light of the sun in a process called photosynthesis. Leaves usually have a large surface so they can collect the most sunlight.

Explanation:

Hope this helps...maybe

Answer:

C

Explanation:

The solar system is the planetary system that includes the Sun and all of the objects that orbit around it. These objects include planets, dwarf planets, moons, asteroids, comets, and other space debris.

The eight planets in the solar system, in order of their distance from the Sun, are Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune. Pluto was previously classified as the ninth planet but has since been reclassified as a dwarf planet.

The largest planet in the solar system is Jupiter, which is also the fifth planet from the Sun. Jupiter is a gas giant, meaning that it is primarily composed of hydrogen and helium, and has numerous moons, including the four largest known as the Galilean moons.

The inner planets, including Mercury, Venus, Earth, and Mars, are known as the terrestrial planets because they are primarily composed of rock and metal. They are also relatively small in size compared to the gas giants.

The solar system is constantly in motion, with each object following its own unique orbit around the Sun. These orbits are affected by the gravitational pull of other objects in the solar system, which can cause objects to change their paths or collide with one another.

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Answer:

A

Explanation:

I took the test on progress learning and got it right.

If we increase the velocity of an object by 1 meter per second, as a result the kinetic energy of the object will increase as velocity is directly proportional to the kinetic energy.

The kinetic energy of an object is the energy which the object possesses due to its motion. Kinetic energy is defined as the work which is required be done to accelerate an object of a given mass from the state of rest to its stated velocity.

Kinetic energy is the energy possessed by an object due to its motion. Potential energy is the form of energy which is possessed by an object due to the position or state. Kinetic energy is directly proportional to the mass and velocity of the object. Therefore, if we increase the velocity of an object, then kinetic energy of the object will increase.

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Answer:

1.3823 rad/s

20.7345 m/s

28.66129935 m/s²

2006.29095 N radially outward

Explanation:

r = Radius = 15 m

m = Mass of person = 70 kg

g = Acceleration due to gravity = 9.81 m/s²

Angular velocity is given by

Angular velocity is 1.3823 rad/s

Linear velocity is given by

The linear velocity is 20.7345 m/s

Centripetal acceleration is given by

The centripetal acceleration is 28.66129935 m/s²

Acceleration in terms of g

Centripetal force is given by

The centripetal force is 2006.29095 N radially outward

The torque will be experienced when the centrifuge is speeding up of slowing down i.e., when it is accelerating and decelerating.

The force that acts in a direction opposite to the motion of the moving object is called drag or air resistance.

Drag or air resistance is a force that acts on a moving object in a fluid medium, such as air or water, opposing its motion. It acts in a direction opposite to the motion of the object and is caused by the friction and pressure differences between the fluid and the object's surface. Drag force increases with the velocity of the object and its surface area, and it's usually modeled as a quadratic function of the velocity. For example, when a car is moving, the air resistance acts in the opposite direction of the car's motion, slowing it down. The drag force is not the only force that acts on the object, but it's one of the most significant forces acting on it, especially for objects moving at high speeds.

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Answer:

Explanation:

SSC student?

Answer:

Approximately \(33\; {\rm m\cdot s^{-2}}\).

Approximately \(55\; {\rm m\cdot s^{-2}}\).

(Assume that the table is level, and that the \(60\; {\rm N}\) force is horizontal.)

Explanation:

Consider all three blocks as one object of mass \(m = (1 + 4 + 6)\; {\rm kg} = 11\; {\rm kg}\). Among all the forces that are in action, the only unbalanced external force on this \(m = 11\; {\rm kg}\) object will be the \(60\; {\rm N}\) force. Hence, the resultant force of this combined object of mass \(m = 11\; {\rm kg}\) will be \(F_{\text{net}} = 60\; {\rm N}\).

Acceleration \(a\) of this combined object will be:
\(\begin{aligned}a &= \frac{F_{\text{net}}}{m} \\ &= \frac{60\; {\rm N}}{11\; {\rm kg}} \\ &= \frac{60}{11}\; {\rm m\cdot s^{-2}}\end{aligned}\).

Since the three crate blocks are moving together, each will have the same acceleration, \(a = (60/11)\; {\rm m\cdot s^{-2}}\).

Resultant force on each of the crate blocks will be:

Assume that the \(60\; {\rm N}\) external force on the \(1\; {\rm kg}\) block points to the right.

When the crates are considered individually, external forces on the \(1\; {\rm kg}\) crate will include:

Since these two forces are in opposite directions, the resultant force on this \(1\; {\rm kg}\) block will be \((60\; {\rm N} - x\; {\rm N})\). However, since the actual resultant force on this block (calculated from acceleration) is \((60 / 11)\; {\rm N}\):

\(\displaystyle 60\; {\rm N} - x\; {\rm N} = \frac{60}{11}\; {\rm N}\).

Therefore, the force that the \(4\; {\rm kg}\) block exerts on the \(1\; {\rm kg}\) block will be

\(\displaystyle 60\; {\rm N} - \frac{60}{11}\; {\rm N} = \frac{600}{11}\; {\rm N} \approx 55\; {\rm N}\).

When considered individually, the only unbalanced external force on the \(m = 6\; {\rm kg}\) block is the normal force from the \(4\; {\rm kg}\) block. Hence, this force will be equal to the resultant force on the \(m = 6\; {\rm kg}\) block, \((360 / 11)\; {\rm N} \approx 33\; {\rm N}\).

The resistor of the electric lamp is marked at 240 volts and 60 watts is 960 ohms. Thus, option D is correct.

The resistance is a property that gives obstruction the current flow.  It blocks the current flow in the circuit. The unit of resistance is the ohm.    

From the given,

The voltage of the electric lamp (E) = 240 volt

Power in the circuit (P) = 60 watt

Resistance =?

Power (P) = E² / R

R = E²/P

   = 240×240/60

  = 960 Ω

The resistance of the electric lamp with a given voltage and power is 960 Ω. Thus, the ideal solution is D.

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In a merry-go-round rotating at constant angular speed, two children Ana and Bobby are riding at different points A and B, respectively.

The linear velocity of a point on a rotating object depends on its distance from the center of rotation and the angular velocity of the object. The farther a point is from the center of rotation, the greater its linear velocity.

Therefore, the child riding at the outermost point, which is Bobby in this case, will have a greater magnitude of linear velocity compared to the child riding at the innermost point, which is Ana.

Thus, option (b) is correct - Bobby has the greater magnitude of linear velocity. This concept is important in understanding centripetal force and its effects on objects in circular motion.

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Answer:

Inertia is directly proportional to mass of an object. Therefore, when the force of inertia increases the mass also increases, and when it decreases the mass also decreases.

Explanation:

Answer: Inertia is _ directly proportional_ to mass.

Explanation:

If the distance between two objects is decreased to one-fourth of the original distance, the force of attraction increases sixteen-fold.

The effect of the decrease in the distance on the force of attraction between two objects is determined from the law of gravitational attraction as follows:

where;

From the equation above, G, m₁, and m₂ are constant.

Hence, the force of attraction, F is given as;

F = 1 / (d/₄)²

F = 1 / (d²/16)

Hence, the value of the force of attraction increases sixteen-fold.

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In order to calculate the direction of the vector, first let's draw its components:

since the horizontal component is positive and the vertical component is negative, the vector is pointing to the 4th quadrant.

To calculate the angle, we can use the arc tangent as follows:

Rounding to nearest tenth, the direction is -26.6°.

According to the question the net force on particle q1 is \(1.45 * 10^-4 N.\)

Force is an influence that produces a change in the motion, direction, shape, or orientation of an object. It is a vector quantity, meaning it has both magnitude and direction. Force can be derived from different sources, including physical contact, gravity, magnetism, or even electrical fields. Force affects objects by producing acceleration, deceleration, or changes in direction.

The net force on particle q1 is the sum of the forces due to the two other particles. The force on particle q1 due to particle q2 is given by Coulomb's Law:

\(F12 = k(q1q2/r12^2)\)

Where k is the Coulomb's Constant, q1 and q2 are the charges of the two particles, and r12 is the distance between them, which is 0.220m.

Similarly, the force on particle q1 due to particle q3 is given by:

\(F13 = k(q1q3/r13^2)\)

Where q1 and q3 are the charges of the two particles, and r13 is the distance between them, which is 0.330m.

The net force on particle q1 is then the vector sum of these two forces:

Fnet = F12 + F13

Substituting the values for the charges and distances into Coulomb's Law gives:

\(Fnet = (9*10^9)(-(8.99*10^-6)(5.16*10^-6)/(0.22^2)) + (9*10^9)(-(8.99*10^-6)(-89.9*10^-6)/(0.33^2))\)

Simplifying, we get

\(Fnet = 1.45 * 10^-4 N\)

Therefore, the net force on particle q1 is\(1.45 * 10^-4 N.\)

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Answer:

number 2

Explanation:

the 2 one is right

The main answer is:The volume of water displacement of the floating oil rig is 339,394 cubic feet.Explanation:A floating oil rig is anchored in the seabed with cables giving a net pull of 2,250,000 lbf down. Here is how to determine how large a water displacement volume that leads to:

Let us recall the principle of Archimedes: It states that "when an object is fully or partially immersed in a liquid, it experiences an upward force that is equal to the weight of the liquid displaced."The upward force exerted on the floating oil rig is equal to the weight of the water displaced by it, which can be determined using the following formula:Upward force = Weight of water displacedThe formula for the weight of water displaced is:Weight of water displaced = Volume of water displaced × Density of waterwhere

:Volume of water displaced = VDensity of water = ρWe know that the upward force exerted on the oil rig is equal to the net pull of the cables, which is 2,250,000 lbf down. This is also the weight of the oil rig. Therefore, we can say that:Upward force = Weight of water displaced2,250,000 lbf = V × ρ × gwhere:g = acceleration due to gravity = 32.2 ft/s² (this is the value used in the United States)ρ = density of water = 62.4 lb/ft³ (this is the value used in the United States)Solving for V:V = 2,250,000 lbf / (ρ × g)V = 2,250,000 lbf / (62.4 lb/ft³ × 32.2 ft/s²)V ≈ 339,394 ft³Therefore, the volume of water displaced by the floating oil rig is 339,394 cubic feet.

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The magnitude of the car's acceleration is approximately 39,603 mi/h². The magnitude of acceleration can be determined using the formula:
acceleration = (final velocity - initial velocity) / time

Given that the initial velocity is 63 mi/h, the final velocity is 30 mi/h, and the time is 3.0 s, we can substitute these values into the formula:
acceleration = (30 mi/h - 63 mi/h) / 3.0 s
Simplifying this expression, we get:
acceleration = (-33 mi/h) / 3.0 s
Now, let's convert the units so that the time is in seconds:
acceleration = (-33 mi/h) / (3.0 s / 3600 s/h)
Simplifying further, we get:
acceleration = (-33 mi/h) / (0.0008333 h)
Finally, we divide the two values to find the acceleration:
acceleration = -39,603 mi/h²
Therefore, the magnitude of the car's acceleration is approximately 39,603 mi/h².

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The height of the tower is approximately 29.4 meters. The period of the pendulum on the moon would be approximately 17.8 seconds. The equation of motion for a simple pendulum is, θ''(t) + (g/L) * sin(θ(t)) = 0, where θ(t) is the angular displacement at time t, and the θ'' represents the second derivative of θ with respect to time.

The period of a simple pendulum is given by,

T = 2π * √(L/g)

where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. Rearranging this formula,

L = (gT²) / (4π²)

Substituting g = 9.81 m/s² (acceleration due to gravity on Earth) and T = 12.0 s,

L = (9.81 m/s² * (12.0 s)²) / (4π²) = 29.4 m

On the moon, the acceleration due to gravity is 1.67 m/s². Using the same formula as before,

T' = 2π * √(L/g')

where T' is the new period, g' is the acceleration due to gravity on the moon, and L is the length of the pendulum. Rearranging this formula,

L = (g'T'²) / (4π²)

Substituting g' = 1.67 m/s² and solving for T',

T' = 2π * √(L/g') = 2π * √((29.4 m)/(1.67 m/s²)) = 17.8 s

The equation of motion for a simple pendulum is:

θ''(t) + (g/L) * sin(θ(t)) = 0

where θ(t) is the angular displacement of the pendulum from its equilibrium position at time t, and the double prime notation (θ'') represents the second derivative of θ with respect to time. This is a second-order differential equation that can be solved using various techniques, such as the small-angle approximation or numerical methods. The solution gives the function θ(t), which describes the motion of the pendulum as a function of time.

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Given,

The length of the slab, L=12 m

The initial temperature, T₁=10°C

The final temperature, T₂=30°C

The coefficient of the linear expansion of the concrete is α=12×10⁻⁶ /°C

The change in the length of the slab is given by,

Where ΔT is the change in the temperature.

Therefore,

On substituting the known values,

Thus the expansion in the length of the slab in the given temperature range is 0.003 m.

Thus the gap between the slabs should be 0.003 m

Given that Radius of the disc, r = 20 cm = 0.2 m Mass of the disc, m = 20 kgAngular acceleration, α = 4 rad/s²

We are to find the torque required to create this angular acceleration.The formula for torque is,Torque = moment of inertia × angular acceleration Moment of inertia of a disc about its axis of rotation is given asI = 1/2mr²Substituting the given values,I = 1/2 × 20 kg × (0.2 m)² = 0.4 kg m²Therefore,Torque = moment of inertia × angular acceleration= 0.4 kg m² × 4 rad/s²= 1.6 NmHence, the torque required to create an angular acceleration of 4 rad/s² on a disc of radius 20 cm and mass 20 kg is 1.6 Nm.

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a) The weight of the box of textbooks can be calculated as follows;

Weight of

box= mass × acceleration due to gravity

Where mass= 55 kg

Acceleration due to

gravity= 9.8 m/s²Thus, the weight of the box of textbooks is given by;

Weight of

box= 55 kg× 9.8 m/s²= 539 N

the weight of the box of textbooks is 539 N.

b) The coefficient of friction can be calculated using the formula;Coefficient of friction= frictional force/ Normal forceWhere, frictional force is the force required to keep the box moving at constant velocity and normal force is the force acting on the box perpendicular to the surface on which the box is resting.

The force F of the student pushing the box can be resolved into its horizontal and vertical components as follows;

F_x= 320 N (this is the horizontal component of the force)F_y=

(This is the vertical component of the force)Thus, the normal force on the box is given by;

F_y= Normal forceNormal force= weight of box= 539 NThe frictional force is given by.

F_f= F_x= 320 NThe coefficient of friction is given by;Coefficient of friction= frictional force/ Normal forceCoefficient of friction= F_f/ F_yCoefficient of friction= 320 N/ 539 NCoefficient of friction= 0.593Therefore, the coefficient of friction is 0.593.

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(a) The normal force on the sleigh is 596.36 N.

(b) The magnitude and direction of acceleration of the sleigh is 3.2 m/s² upwards.

The given parameters;

The normal force on the sleigh is calculated as follows;

\(F_n = mg \times cos(\theta)\\\\F_n = 63 \times 9.8 \times cos(15)\\\\F_n = 596.36 \ N\)

The magnitude and direction of acceleration of the sleigh is calculated as follows;

\(\Sigma F= ma\\\\F - mgsin(\theta) - F_f = ma\\\\F - mgsin(\theta) - \mu F_n = ma\\\\510\ - \ 63 \times 9.8 \times sin15 \ -\ 0.25\times 596.36 = 63a\\\\201 .11 = 63a\\\\a = \frac{201.11}{63} \\\\a = 3.2 \ m/s^2 \ upwards\)

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The energy transformation taking place when the person eats food is chemical energy to kinetic energy. The energy gain from food make us active by giving sufficient kinetic energy.

One form of energy can be transformed to the form naturally or mechanically. For instance, we are using electrical devices all such as light, bulb, fan, motors etc.

In light bulb, the electrical energy is converting to light energy and in fan, electrical energy is converting to the mechanical energy. We need energy to activate ourselves and when we starts to move we gain some kinetic energy.

When we eat food, the chemical energy stored in food is transferring to us and converts it to kinetic energy which helps us to be active. Hence, option B is correct.

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A.brass is heavier than water.

A:

The white light is divided into its component hues - red, orange, yellow, green, blue, and violet - as it passes through the prism. Dispersion is the splitting of visible light into its many hues.

B:

Dispersion is the splitting of visible light into its many hues. Each hue is associated with a certain wave frequency, as stated in the Light and Color unit, and different frequencies of light waves bend at different rates while passing through a prism.

C:

The white light is divided into its component hues - red, orange, yellow, green, blue, and violet - as it passes through the prism. Dispersion is the splitting of visible light into its many hues.

D:

The sun and the weather combine to create a rainbow. As it passes from air to denser water, light enters a water droplet, slowing and bending. The light bounces off the interior of the droplet, separating the wavelengths—or colors—that make up the droplet. A rainbow is created as light escapes the droplet.