The lightest pilot-driven airplane ever built was the Baby Bird. Suppose the Baby Bird moves along the ground without a pilot at a velocity of 88,000 m/h, and the momentum of the empty plane is 2790 kg·m/s. What is the mass of the plane?

Answers

Answer 1

The mass of the empty plane is 70.94 kg when the Baby Bird moves along the ground without a pilot at a velocity of 88,000 m/h.

Momentum is the product of mass and velocity. It is expressed in kg m/s.

Momentum = Mass x Velocity

Given that momentum of the empty plane is 2790 kg m/s and

the velocity of the empty plane is 88,000 m/h or 39.334 m/s,

the mass of the empty plane can be calculated as follows:

Momentum = Mass x Velocity

2790 kg m/s = Mass × 39.334 m/s

Mass = 2790 kg m/s ÷ 39.334 m/s

Mass = 70.94 kg

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Related Questions

Why will a delivery truck filled with birds sitting on its floor be heavier than a truck with the same birds flying around inside.

Answers

The reason why a delivery truck filled with birds sitting on the floor be heavier than a truck with the same birds flying around is because when the birds are sitting on the floor, they are adding their weight to the truck.

Meanwhile, if the birds are flying around they aren't resting on the truck or touching it, so therefore their weight wouldn't be added to the truck.

The mass of the truck will remain the same as you cannot change the mass but the weight will vary depending on the items and objects placed in it.

An electron is confined to a region of space of length 0.300 nm. what is the value of e2, the second allowed energy of the electron?

Answers

The second allowed energy of an electron is 4 times the first allowed energy.

The first allowed energy can be calculated using the following equation:

En = n²h² / 8mL²where n is the principal quantum number, h is Planck's constant, m is the mass of the electron, and L is the length of the region of space to which the electron is confined.

The value of the first allowed energy is given by;E1 = h² / 8mL²

The value of h = 6.626 x 10^-34 J·s, and the value of m = 9.11 x 10^-31 kg.

Therefore, we have:E1 = (6.626 x 10^-34 J·s)² / 8(9.11 x 10^-31 kg)(0.300 x 10^-9 m)² = 3.69 x 10^-19 J

The second allowed energy of the electron, E2, is given by:E2 = 4E1= 4 × 3.69 x 10^-19 J= 1.48 x 10^-18 J

The answer is 1.48 x 10^-18 J.

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whne was physics created

Answers

Answer:

energy and matter

Explanation:

physics is the study of matter and it interaction with energy

how do u cure a headache without any pills no bots or I will report u?

Answers

Answer:

Try a Cold Pack. Use a Heating Pad or Hot Compress. Ease Pressure on Your Scalp or Head. Dim the Lights. Try Not to Chew. Hydrate. Get Some Caffeine. Practice Relaxation.

Answer:

Listen to calming music

Explanation:

Thats what I do. You could also sleep ;)

Calculate the current in the 3.0 Ω resistor in the figure above when the current in the 9.0 Ω resistor is 2.4A

Calculate the current in the 3.0 resistor in the figure above when the current in the 9.0 resistor is

Answers

The current in the 3.0 Ω resistor is mathematically given as

I_X=1.8A

This is further explained below.

What is current?

The proportion of individual resistance to the overall resistance is the same as the current flowing through a branch to the current flowing through the whole system.

When the total current in a parallel circuit is already known, a shortcut approach for finding the branch currents in the circuit may be found via the use of a formula called the current divider formula.

In series circuits, the voltage drops across each resistor, but the current stays the same.

This is analogous to what happens in parallel circuits when the current splits between two branches.

The following diagram illustrates how the entire voltage is distributed across each resistor while maintaining the same amount of current throughout. Ohm's law states that V = I*R.

current dividers ruleis used when current is divided in parallel, such as it is in this case so we employ the current dividers rule as follows

Generally,  the equation for current dividers rule is mathematically given as

\(I_X=\frac{R_T}{R_X+R_T} I_T\)

where,

I_X = current

R_X = resistor

R_T = total resistance

I_T = sum of the current flowing into a network where R _X is connected in parallel with R_T

Therefore

\(I_X=\frac{9}{3+9} 2.4\)

I_X=1.8A

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what is a multiple motion ? give example ​

Answers

Answer:when a body possesses more than one simple motion, it is called a multiple motion.

Explanation:you are traveling by a train. Your wrist watch is also sharing the linear motion of the train. But the hands of the watch are also undergoing rotational motion. Thus they have 2 kinds of motion, I, e, Multiple motion.so also the blades of the fan in the train have multiple motion (a linear motion of the train and the rotation).

The system is in equilibrium, and the pulleys are weightless and frictionless.
Find the tension T.
The acceleration of gravity is 32 ft/s^2
Note: lb ≡ slug · ft/s^2

Answer in units of lb.

There is an attachment of the system below

The system is in equilibrium, and the pulleys are weightless and frictionless.Find the tension T. The

Answers

Answer:

F = M a    where F is in lbs, M in slugs and a in ft/s^2

Apparently this system is motionless so

T + 15 is the downward force on the mass of 15 lbs

1 slug * 32 ft/s^2 is 32 lbs the weight of the other block

It takes a force of 32 / 2 = 16 lbs on the cable to support this weight

16 lbs = T + 15 lbs

T = 1 lbs

Consider S:M (i.e. surface area to mass ratio) of an object. What happens to the ratio when the density of an object decreases while the surface area and volume remain the same?Group of answer choices:it increasesthe outcome cannot be determinedit depends on the nature of the material in the objectit decreasesit remains the same

Answers

The ratio of surface area to mass when the density of an object decreases while the surface area and volume remain the same, increases. The correct option is A.

An object's surface area and volume don't change, but its density does. The formula for density

ρ = m ÷ V

V = m ÷ ρ

m = mass (kg)

V = volume (m³)

ρ = the density (kg/m³)

The density decreases

ρ₁ > ρ₂

The surface area remains the same

A₁ = A₂

The volume remains the same

V₁ = V₂

V₁ = V₂

m₁ ÷ ρ₁  = m₂ ÷ ρ₂

m₂ × ρ₁ = m₁ × ρ₂

m₂ = (m₁ × ρ₂) ÷ ρ₁

ρ₁ > ρ₂

m₂ < m₁

The density decreases, and the mass also decreases.

The quantity of surface area per unit mass of an object is known as the surface area to mass ratio.

S:M = A ÷ m

At initial (S:M)₁ = A₁ ÷ m₁

At final (S:M)₂ = A₂ ÷ m₂

A₁ = A₂

m₂ < m₁

(S:M)₂ > (S:M)₁

Thus, the surface area to mass ratio will increase.

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a convex mirror has a focal length of -12 cm. a lightbulb with diameter of 6 cm is placed 60 cm from the mirror

Answers

Here the focal length of the convex mirror as -12 cm, a light bulb with a diameter of 6 cm is placed 60 cm from the mirror. Hence, the image distance is -60 cm, and the image height is 6 cm.

To find the image distance and height, we will use the mirror formula for a convex mirror, which is given as follows;1/f = 1/v + 1/u. Where, f = focal length of the convex mirror;

v = the image distance;

u = the object distance

If the object distance is positive, it means the object is placed in front of the mirror, and if it is negative, it means the object is placed behind the mirror. The focal length of a convex mirror is always negative, as given above.

Therefore, u = -60 cm and f = -12 cm.

Plugging in the values in the mirror formula, we get:1/-12 = 1/v + 1/-60=> -5/60 = 1/v - (1/60) => -5/60 = (60 - v)/60=> v = -300/5= -60 cm

The image distance is -60 cm, which means the image is virtual and erect. The negative sign indicates that the image is formed behind the mirror.

To find the image height, we use the magnification formula:

m = -v/u= -(-60)/(-60)= 1

The magnification is 1, which means the image is of the same size as the object. The height of the light bulb is 6 cm, so the height of the image will also be 6 cm.

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The distance between Earth and the Moon was determined by measuring the time it took for light waves from Earth to travel to the Moon and back. Why was it not possible to use sound waves for this experiment?

Answers

Answer: there is no sound in space

Explanation: there is no vacum in space for sound to travel, therfore no sound waves

define watt and write how much watt is equal to one horse power

Answers

Answer:

A watt (W) is a joule (J) of energy used or produced per second. In 2010, the average US power use was 3.3 terawatts, or 3,300,000,000,000 watts. A horsepower is a unit of power. 1 horsepower (hp) is 745.7 watts.

extra info

How many watts does it take to make 1 horsepower?

746 watts !

One electric horsepower is equal to exactly 746 watts.

can someone help me with my qustions :(

A radio announcer's voice is transmitted via radio waves a distance of 998.25 km. How much time, in microseconds, will it take to transmit the wave over this distance?

Answers

A radio wave travels at the speed of light, which is equal to approximately 300,000 km/s.

So, to travel a distance of 998.25 km, the time needed is:

\(\begin{gathered} distance=speed\cdot time\\ \\ 998.25=300000\cdot time\\ \\ time=\frac{998.25}{300000}\\ \\ time=0.0033275\text{ seconds}\\ \\ time=3327.5\text{ microseconds} \end{gathered}\)

Therefore the time required is approximately 3327.5 microseconds.

i) Show that total energy of the body at points A, B and C during the fall is same. ii) Find the distance from A to B and final velocity of the ball just reach before C. mass =5 kg, total height (h)= 100m​

i) Show that total energy of the body at points A, B and C during the fall is same. ii) Find the distance

Answers

The total energy of the body at evevry point is remained same due to the law of conservation of energy. Distance from A to B and final velocity of the ball just reach before C is 44.3 m/s.

d (distance) from A to B is = √2gh

In this case given are, g = 9.8 m/s² and h = 100m,

so here d = √(2⋅9.8⋅100) = 44.3m.

Final velocity ,v = √2gh

Here given are , v is the velocity, g is the acceleration due to gravity, and h is the height. In this case,

g = 9.8 m/s² ,h = 100m,

v = √(2⋅9.8⋅100)

= 44.3 m/s (final velocity)

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Explain at least 3 different ways that you can motivate yourself past any distractions to reach your goals. (The subject is Physical Education)
Help!
Due today

Answers

Answer:

Explanation:

Set specific, achievable goals: Break down your larger goal into smaller, more manageable targets that you can work towards each day. When you accomplish these smaller goals, it will give you a sense of accomplishment and motivation to continue working towards your larger goal.

Visualize your success: Imagine yourself successfully achieving your goal and all of the positive feelings that come along with it. This visualization can help keep you focused and motivated when distractions arise.

Find an accountability partner: Find someone who shares your goals and who can help you stay focused and motivated. This could be a friend, family member, or a coach. Having someone to share your progress with and to hold you accountable can be a powerful motivator.

Reward yourself: Set up a system of rewards for yourself when you reach certain milestones on the way to your goal. These rewards could be something as simple as a treat or a movie, or something more substantial like a new piece of workout equipment.

Get organized: Plan out your workouts and stick to a routine. Having a clear plan and structure can help you stay focused and motivated, as you can see how each workout is helping you to reach your goal.

Surround yourself with positive influences: Surround yourself with people who support and encourage your goals. Having positive influences in your life can help you stay motivated and inspired to reach your goals.

Dave runs a 400 m race with a speed of 4 m/s. What time will it take him to finish the
race?

Answers

Answer:

The answer should be 100 if not try 200

Explanation:

d=v x t

400m=4m/s x t

/4           /4

100=t

2. A quantity of gas is trapped by a piston in a cylinder with thin metal walls. The piston is free to move
without friction within the cylinder.
a) The air in the freezer is at atmospheric pressure, which is 1.0 × 105Pa. The area of the piston in
contact with the air in the freezer is 2.4 × 10–3m2
.
i. Calculate the force exerted on the piston by the air in the freezer.
ii. When the cylinder is first placed into the freezer, the temperature of the gas in the cylinder decreases
and the air pushes the piston into the cylinder. Calculate the work done on the piston by the air in the
freezer as the air pushes the piston at distance of 0.021m into the cylinder.
b) The initial temperature of the cylinder and the gas is 21°C and, in the freezer, the temperature of the
cylinder decreases to –18°C. The thermal capacity of the cylinder is 89J/ °C. Calculate the change in
the internal energy of the cylinder.

Answers

a)

i. The force exerted on the piston by the air in the freezer is 240 N.

ii. The work done on the piston by the air as it pushes the piston 0.021 m into the cylinder is 5.04 J.

b) The change in the internal energy of the cylinder is 3486 J.

a)  

i. To calculate the force exerted on the piston by the air in the freezer, we can use the formula:

Force = Pressure * Area

Given:

Pressure (P) = 1.0 × \(10^5\) Pa

Area (A) = 2.4 ×\(10^(^-^3^) m^2\)

Substituting these values into the formula, we have:

Force = (1.0 × 10^5 Pa) * (2.4 ×\(10^(^-^3^) m^2)\)

      = 240 N

ii. To calculate the work done on the piston by the air in the freezer as the air pushes the piston, we can use the formula:

Work = Force * Distance

Given:

Force = 240 N

Distance (d) = 0.021 m

Substituting these values into the formula, we have:

Work = (240 N) * (0.021 m)

     = 5.04 J

b) To calculate the change in the internal energy of the cylinder, we can use the formula:

ΔU = mcΔT

Given:

Initial temperature (T1) = 21°C = 21 + 273 = 294 K

Final temperature (T2) = -18°C = -18 + 273 = 255 K

Thermal capacity (c) = 89 J/°C

Substituting these values into the formula, we have:

ΔU = (89 J/°C) * (294 K - 255 K)

   = 3486 J

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I WILL GIVE BRAINLIEST PLEASE HELP ME
What happens to a baseball in space under the following 2 conditions

a. The baseball is in space and stationary. What will the ball do? ___ Why? ___
b. The ball is in space and someone hits it with a bat. What will the ball do? ___ Why? ___
c. The ball has a small jet pack attached that is continuously firing. What will the ball do? ___ Why? ___

Answers

Answer:

First, we need to remember the second Newton's law:

This says that:

F = m*a

Force equals mass times acceleration.

This means that if we apply a force to an object, the object will accelerate.

This also means that if an object is not moving, or moving with a constant velocity, it will keep doing that until a force is applied.

Now let's answer the 3 cases:

a. The baseball is in space and stationary. What will the ball do? Nothing, it will keep being stationary Why? There is no force applied, or the net force is equal to zero.

b. The ball is in space and someone hits it with a bat. What will the ball do? Will move with constant speed Why? A hit with a bat can be thought as a great force applied for a really short period of time, this means that the speed of the ball will increase a lot, but because the force only last for a really short time, after that the ball will keep moving with constant speed.

c. The ball has a small jet pack attached that is continuously firing. What will the ball do? The ball's speed will keep increasing more and more. Why? Now we have a constant force, this means that we will have a constant acceleration, and as we know, the acceleration is the rate of change of the speed, this will mean that the speed of the ball will keep increasing until the jet pack stops firing, and after that, the ball will keep moving with constant speed.

A race car is traveling at a speed of 80. 0 m/s on a circular racetrack of radius 450 m. What is it's centripetal acceleration in m/s2?.

Answers

Answer:

14.2m/s^2

Explanation:

The centripetal acceleration of the race car is 14.22 m/s².

What is centripetal acceleration?

Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.

In your daily existence, you must have encountered numerous instances of centripetal acceleration. A centripetal acceleration occurs when you drive in a circle, and a centripetal acceleration also occurs when a satellite orbits the earth. Centripetal refers to being in the center.

Given that: Speed of the race car: v = 80.0 meter/second.

Radius of the racetrack: r = 450 meter.

Hence, the centripetal acceleration of the car is = v²/r

= (80.0)²/450 m/s²

= 14.22 m/s².

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A block of weight w = 25.0 N sits on a frictionless inclined plane, which makes an angle θ = 30.0 ∘ with respect to the horizontal, as shown in the figure. (Figure 1)A force of magnitude F = 12.5 N , applied parallel to the incline, is just sufficient to pull the block up the plane at constant speed.

A: The block moves up an incline with constant speed. What is the total work Wtotal done on the block by all forces as the block moves a distance L = 3.80 m up the incline? Include only the work done after the block has started moving at constant speed, not the work needed to start the block moving from rest.

B :What is Wg , the work done on the block by the force of gravity w⃗ as the block moves a distance L = 3.80 m up the incline?

C: What is WF , the work done on the block by the applied force F⃗ as the block moves a distance L = 3.80 m up the incline?

D: What is WN , the work done on the block by the normal force as the block moves a distance L = 3.80 m up the inclined plane?

Answers

a ) The total work Wtotal done on the block by all forces = 0

b ) The work done on the block by the force of gravity = - 47.5 J

c ) The work done on the block by the applied force F = 47.5 N

a ) The total work Wtotal done on the block by all forces,

Since, only the work done after the block has started is considered, the total work done is the change in kinetic energy. Since, the block is moving at a constant speed there is no change in kinetic energy and so total work Wtotal done is zero.

b ) The work done on the block by the force of gravity,

Wg = Fg * h * cos θ

Fg = W = 25 N

sin 30 = h / 3.8

h = 1.9 m

Wg = 25 * 1.9 * cos 180

Wg = - 47.5 J

c ) The work done on the block by the applied force F,

WF = F * d * cos θ

WF = 12.5 * 3.8 * cos 0

WF = 47.5 N

d ) The work done on the block by the normal force,

Normal force acts perpendicular to the surface. The movement is towards the right side of the surface. So cos θ will be cos 90 which is equal to zero. So the work done will be zero.

Therefore,

a ) The total work Wtotal done on the block by all forces = 0

b ) The work done on the block by the force of gravity = - 47.5 J

c ) The work done on the block by the applied force F = 47.5 N

d ) The work done on the block by the normal force = 0

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five scientist who travelled to space​

Answers

Answer:

The Most Famous Astronomers of All Time. Karl Tate, SPACE.com. ...

Claudius Ptolemy. Bartolomeu Velho, Public Domain. ...

Nicolaus Copernicus. Public Domain. ...

Johannes Kepler. NASA Goddard Space Flight Center Sun-Earth Day. ...

Galileo Galilei. NASA

what is the name of the part of the microscope that the objectives are attached to? (choose the best answer)

Answers

The part of the microscope that the objectives are attached to is called the (C) nosepiece.

The nosepiece is a rotating mechanism located below the microscope's body tube. It holds the objectives, which are the lenses responsible for magnifying the specimen. The nosepiece typically has multiple positions, allowing the user to switch between different objective lenses for varying levels of magnification.

This convenient feature eliminates the need to manually remove and replace objectives when changing magnification. By rotating the nosepiece, different objectives can be brought into position above the specimen. This allows for quick and efficient adjustments in magnification without disrupting the viewing process.

Hence, the nosepiece plays a critical role in the microscope's functionality by providing a convenient way to switch between objectives and adjust the magnification level.

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Here is the complete question:

What is the name of the part of the microscope that the objectives are attached to? (Choose the best answer)

A. Ocular

B. Stage

C. Nosepiece

D. Arm

The function s(t) = 9 – 15t + 8t² describes the distance s from the origin at time t of an object in rectilinear motion. Find the velocity v of the object at any time t. (Use symbolic notation and fractions where needed.) v(t) = When is the object at rest? (Use symbolic notation and fractions where needed.) t = The function s(t) = 9 – 15t + 8t² describes the distance s from the origin at time t of an object in rectilinear motion. Find the velocity v of the object at any time t. (Use symbolic notation and fractions where needed.) v(t) = When is the object at rest? (Use symbolic notation and fractions where needed.) t =

Answers

At time t = 15/16, the object reaches a state of zero velocity, indicating a momentary pause in its motion. Prior to this time, the object moves in one direction, while after this time, it changes direction and moves in the opposite direction. The value t = 15/16 represents the specific moment when the object transitions from one direction to another and experiences a brief period of rest.

To find the velocity v(t) of the object at any time t, we differentiate the given distance function s(t) = 9 - 15t + 8t² with respect to time:

v(t) = d/dt (9 - 15t + 8t²)

Applying the power rule of differentiation, we obtain:

v(t) = -15 + 16t

Therefore, the velocity v(t) of the object at any time t is given by v(t) = -15 + 16t.

To determine when the object is at rest, we set the velocity v(t) equal to zero and solve for t:

-15 + 16t = 0

Adding 15 to both sides of the equation, we have:

16t = 15

Finally, dividing both sides by 16, we find

t = 15/16

Hence, the object is at rest when t = 15/16.

This means that at time t = 15/16, the object's velocity is zero, indicating that it is momentarily stationary. Before this time, the object is moving in one direction, and after this time, it is moving in the opposite direction. The value t = 15/16 represents the specific point in time when the direction of motion changes, and the object is at rest for an instant.

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As defined in physics "work" is

Answers

Answer:

in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement.

Explanation:

A heat conduction equation is given as follow: ∂2T /∂x2=1/2 ∂T /∂t
and is valid for the case where 00. The boundary conditions are T(0,t)=T(3,t) =0 and the initial condition is T(x,0)=5sin(4πx). a. By using separation of variable by taking T(x,t)=M(x)N(t), find the expression for both d2M/dx2 and dN/dt in the general form of M and N. b. By defining separation constant first, solve the ODE of d2M/dx2 and dN/dt by getting the general expression of these equations. c. From answer of part [b], simplify your arbitrary constant to get an equation to define T(x,t). Remember T(x,t)=M(x)N(t). d. By using the B.C. and I.C., find the arbitrary constants you have defined in part [c] and prove that T(x,t)=5sin(4πx)e−32π2t

Answers

(a) To apply separation of variables, we assume T(x,t) = M(x)N(t), and substitute it into the heat conduction equation. This leads to two separate equations: d²M/dx² = -λ²M and dN/dt = -λ²/2N.

(b) For N(t), the ODE dN/dt = -λ²/2N has the general solution N(t) = \(Ce^{-\lambda^2t/2}\), where C is an arbitrary constant.

(c)  From the general expressions of M(x) and N(t), we combine them to define T(x,t) = (Acos(λx) + Bsin(λx). Hence, T(x,t) = \(5sin(4\pi x)e^(\lambda^2t/2)\).

(d) The arbitrary constant is determined as λ² = (4π)², which gives us λ = 4π. Thus, the final solution is T(x,t) = \(5sin(4\pi x)e^{-32\pi^2t}\).

a. To apply separation of variables, we assume T(x,t) = M(x)N(t), and substitute it into the heat conduction equation.

By differentiating twice with respect to x and once with respect to t, we obtain: ∂²M/∂x²N + 1/2M∂N/∂t = 0.

Since the left side depends on x and the right side depends on t, both sides must be equal to a constant, which we denote as -λ².

This leads to two separate equations:

d²M/dx² = -λ²M and dN/dt = -λ²/2N.

b. By solving the ODE for M(x), d²M/dx² = -λ²M,

we find that M(x) has the general form M(x) = Acos(λx) + Bsin(λx), where A and B are constants determined by the boundary conditions T(0,t) = T(3,t) = 0.

For N(t), the ODE dN/dt = -λ²/2N has the general solution:

N(t) = \(Ce^{-\lambda^2t/2}\), where C is an arbitrary constant.

c. From the general expressions of M(x) and N(t), we combine them to define:

T(x,t) = (Acos(λx) + Bsin(λx))\(Ce^{-\lambda^2t/2}\).

Simplifying the arbitrary constant C, we can rewrite it as

C = 5sin(4πx)/M(x) at t = 0,

which corresponds to the initial condition

T(x,0) = 5sin(4πx).

Hence, T(x,t) = \(5sin(4\pi x)e^{\lambda^2t/2}\).

d. Applying the boundary conditions T(0,t) = T(3,t) = 0,

we find that sin(λx) should be zero at x = 0 and x = 3.

This gives us λ = nπ/3, where n is an integer.

Substituting this value of λ into the expression for T(x,t), we obtain

T(x,t) = \(5sin(4\pi x)e^{-32\pi^2t}\),

which matches the given solution

T(x,t) = \(5sin(4\pi x)e^{-32\pi^2t}\).

Therefore, the arbitrary constant is determined as λ² = (4π)², which gives us λ = 4π.

Thus, the final solution is T(x,t) = \(5sin(4\pi x)e^{-32\pi^2t}\).

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Use dimensional analysis to determine how many centimeters are in 15 kilometers.A. 15,000 cmB. 1,500 cmC. 1,500,000 cmD. 150 cm

Answers

In order to find how many centimeters are in 15 kilometers, we can use the following conversion rate:

1 km = 100,000 cm.

So, for 15 kilometers, we have:

\(15\text{ km}=15\cdot(100,000\text{ cm})=(15\cdot100,000)\text{ cm}=1,500,000\text{ cm}\)

Therefore the correct option is C.

electronic sensors with a(n) ? output interface can switch ac or dc without the specific polarity requirements for dc circuits.

Answers

Electronic sensors with a digital output interface can switch AC or DC without the specific polarity requirements for DC circuits.

Electronic sensors with a bidirectional output interface can switch AC or DC without the specific polarity requirements for DC circuits. These sensors can handle both types of currents, making them versatile for various applications.

A device that detects a physical property of interest (such as heat, light, or sound) and converts it into an electrical signal so that it may be measured and used by an electrical or electronic system is known as an electrical sensor, also known as an electronic sensor.

The physical activity that needs to be monitored is converted by a sensor into its electrical counterpart, which is then processed so that the electrical signals may be delivered and further processed with ease. The sensor can emit a binary value indicating whether or not an object is present or a digital or analogue value indicating when a measurement value has been attained.

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What is the approximate number of wavelengths of light that can travel in 1 direction within a retroreflecting bead that has a diameter of 5 × 10-5 m? (Note: The speed of light = 3 × 108 m/s, and its frequency is approximately 1015Hz.)
0.6
1.7 × 10^2
1.5 × 10^4
3.3 × 10^6

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The approximate number of wavelengths of light that can travel in one direction within a retroreflecting bead that has a diameter of 5 ×\(10^-^5\) m is 167.

Number of wavelengths of light in a retroreflecting bead with 5 × 10^-5 m diameter?

This calculation is based on the formula n = L/λ, where n is the number of wavelengths, L is the length of the object, and λ is the wavelength of light. To calculate the wavelength of light, we use the formula c = λf, where c is the speed of light and f is the frequency of light.

In this problem, we are given the diameter of the retroreflecting bead, which is assumed to be spherical. Therefore, its length is equal to its diameter, which is 5 × \(10^-^5\)m. We are also given the speed of light, which is 3 × \(10^8\) m/s, and an approximation of the frequency of light, which is \(10^1^5\) Hz.

Using the formula c = λf, we can solve for the wavelength of light:

λ = c/f = (3 ×\(10^8\) m/s)/\((10^1^5\)Hz) = 3 ×\(10^-^7\)m

Finally, we can use the formula n = L/λ to calculate the approximate number of wavelengths of light that can travel in one direction within the retroreflecting bead:

n = L/λ = (5 ×\(10^-^5\) m)/(3 ×\(10^-^7\) m) = 166.67 ≈ 167

Therefore, the approximate number of wavelengths of light that can travel in one direction within a retroreflecting bead that has a diameter of 5 ×\(10^-^5\) m is 167.

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If the temperature in a region of the corona is 2 MK (two million Kelvins), what is the characteristic wavelength emitted by this region

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WeWe can see here the characteristic wavelength emitted by a region of the corona with a temperature of 2 MK is approximately 1.449 nanometers.

What is a wavelength?

A wavelength is a fundamental property of a wave. It is defined as the distance between two consecutive points in a wave that are in phase with each other.

The formula for Wien's displacement law is given by:

λmax = b / T

where λmax is the peak wavelength, b is Wien's displacement constant (approximately equal to \(2.898 * 10^{-3}\)meters per Kelvin), and T is the temperature in Kelvin.

Substituting the given temperature into the equation:

λmax = (\(2.898 * 10^{-3}\)  ) / (\(2 * 10^{6}\) )

λmax ≈  \(1.449*10^{-9}\)

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A football player throws a football 30 meters in 2.5 seconds, What is the speed of the ball?​

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the answer is 12. you divide 30 by 2.5 and get 12.

A football player throws a football 30 meters in 2.5 seconds, divide 30 by 2.5 and get 12.

What is Speed?

An object's speed, also known as "v," is the amount by which its position changes over time or by how much it changes per unit of time, making it a scalar number.  

The instantaneous speed is the upper limit of the average speed as the duration of the time interval approaches zero. The average speed of an item in a period of time is equal to the distance traveled by the object divided by the duration of the period. Velocity and speed are not the same thing.

The parameters of speed are time divided by distance. The metre per second (m/s), the SI measure of speed, is the most widely used unit of speed in daily life.

Therefore, A football player throws a football 30 meters in 2.5 seconds, divide 30 by 2.5 and get 12.

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what are electric field lines?

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An imaginary line or curve representing an electric field is called a "electric field line" and it can be traced from any point along it to determine the direction of the electric field there.

1. Electric field lines with a positive charge at one end and a negative charge at the other

2. The number of field lines that begin or terminate at a charge is inversely correlated with the charge's size.

We may determine the direction of the electric force that will act on a positive charge if it is placed at any given spot by looking at the direction of the electric field line at that location. Since we are aware that a charge would experience a force when placed in an electric field and that force is a vector quantity, it is necessary to describe both its magnitude and its direction. The direction of the electric field in space determines the direction of the electric force acting on a charge. If the charge is negatively charged, an electric force will act on it that is counter to the direction of the point's electric field.

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