The magnetic field 10 cmcm from a wire carrying a 1 aa current is 2 μtμt. part a what is the field 2 cmcm from the wire?

Answers

Answer 1

To find the magnetic field 2 cm from the wire, we can use the formula for the magnetic field produced by a straight wire:

B = (μ₀ * I) / (2 * π * r)

where B is the magnetic field, μ₀ is the permeability of free space (4π x 10^-7 T*m/A), I is the current in the wire, and r is the distance from the wire.

In this case, we are given that the magnetic field 10 cm from the wire is 2 μT and the current is 1 A.

We can plug these values into the formula to find the magnetic field 2 cm from the wire:

B = (μ₀ * I) / (2 * π * r)
B = (4π x 10^-7 T*m/A * 1 A) / (2 * π * 0.02 m)
B = (4π x 10^-7 T*m) / (0.04π m)
B = 10^-5 T

Therefore, the magnetic field 2 cm from the wire is 10 μT.

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Related Questions

Amount of heat required to raise temperature of 10gm water through 2 deg * C is​

Answers

The amount of heat required to raise the temperature of 10 g of water through 2°C is 83.68 Joules.

To determine the amount of heat required to raise the temperature of 10 g of water through 2°C, we will use the formula:Q = m × c × ΔT

Where Q is the amount of heat required, m is the mass of the substance being heated, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

So, for 10 g of water, the mass (m) would be 10 g.

The specific heat capacity (c) of water is 4.184 J/(g°C), so we'll use that value.

And the change in temperature (ΔT) is 2°C.

Substituting these values into the formula, we get:Q = 10 g × 4.184 J/(g°C) × 2°CQ = 83.68 Joules

Therefore, the amount of heat required to raise the temperature of 10 g of water through 2°C is 83.68 Joules.

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An illuminated object is 20 cm from the center of a convex lens. A focused image is formed on a screen 100 cm from the lens. What is the focal length of the lens?

Answers

The focal length of the conves lense with image distance of 100cm and object distance of 20cm is f = 10cm

Convex Lense

Given Data

Object Distance u = 20 cmImage Distance v = 100 cm

We know that the expression for calculating the Focal lenght is given as

F = (uv)/(u + v) cm

Substittuting the Given Parameter into the expression we have

F = 20*100/20+100

F = 1200/120

F = 10 cm

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Two forces act on a moving object that has a mass of 27 kg. One has a magnitude of 12 N and points due south, while the other has a magnitude of 17 N and points due west. What is the acceleration of the object

Answers

0.77 m/s2 directed 35° south of west

net force = (-17,-12)

net force = mass * acceleration

(-17,-12) = 27 * (x-acceleration,y-acceleration)

(x-acceleration,y-acceleration) = (-17/27,-12/27) = (-0.629629629..., -0.444...)

angle of acceleration = tan^-1 (-0.444.../-0.629629...) = 35.21759 degrees below negative x-axis.

magnitude of acceleration = sqrt((-0.629629...)^2 + (-0.444...)^2) = 0.77069 (5dp)

a. Discuss the 1) coastal engineering projects, 2) phases of a coastal engineering project. b. A wave is approaching perpendicular to the 500 m long breakwater. The incident wave is 1.5 m high and 30 m long. Estimate the height of the wave on 1) the back side of the breakwater at a distance of 250 m from one of the ends, 3) at a distance of 60 m from one of the edges along the time which is at a 60-degree angle with the breakwater. c. A wave in water that is 15 m deep has a period of 11 s and a height of 1.4 m. a) calculate the water particle velocity and the pressure at a point 0 m ahead of the wave crest and 2 m below the still water level, b) calculate the horizontal and vertical displacement of the water particle orbit at this point

Answers

Coastal engineering projects involve the design and construction of structures to manage and protect coastal areas from erosion, floods, and other natural hazards.

In a wave approaching perpendicular to a 500 m long breakwater, the height of the wave on the backside at a distance of 250 m from one of the ends can be estimated using wave transformation principles.

However, the height of the wave at a distance of 60 m from one of the edges along a 60-degree angle with the breakwater requires additional information, such as wave direction and wave transformation equations, to provide an accurate estimate.

For a wave in water that is 15 m deep with a period of 11 s and a height of 1.4 m, the water particle velocity and pressure at a point 0 m ahead of the wave crest and 2 m below the still water level can be calculated using wave theory equations. The horizontal and vertical displacement of the water particle orbit at this point can also be determined using the properties of wave motion and particle orbits.

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A wooden block with mass 1.15 kg is placed against a compressed spring at the bottom of a slope inclined at an angle of 29.0° (point A). When the spring is released, it projects the block up the incline. At point B, a distance of 7.55 m up the incline from A, the block is moving up the incline at a speed of 6.25 Im/s and is no longer in contact with the spring. The coefficient of kinetic friction between the block and incline is 0.45. The mass of the spring is negligible.

Constants Part A Calculate the amount of potential energy that was initially stored in the spring. Take free fall acceleration to be 9.80 m/s^2.

Answers

To calculate the amount of potential energy initially stored in the spring, we need to consider the conservation of mechanical energy.

The mechanical energy of the block-spring system is conserved when no external forces other than gravity and friction are acting on it. At point A, the mechanical energy is stored entirely as potential energy in the compressed spring. The potential energy stored in the spring can be calculated using the formula: Potential Energy (PE) = (1/2)kx^2

where k is the spring constant and x is the displacement of the spring from its equilibrium position.

To find the spring constant, we need to know the force constant of the spring (k) or the spring's compression distance (x). Unfortunately, this information is not provided in the given question. If you have any additional information about the spring constant or the compression distance, please provide it so that I can assist you further.

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Telescopes designed to study the earliest stages in galactic lives should be optimized for observations in ______.
A) X rays B) visible light
C) infrared light
D) radio waves

Answers

Telescopes designed to study the earliest stages in galactic lives should be optimized for observations in infrared light (Option C).

How telescopes designed to study the observations in infrared light?

Telescopes designed to study the earliest stages of galactic formation need to observe light that can penetrate the dust clouds that often obscure these early events. Infrared light is well suited for this purpose because it has longer wavelengths than visible light and can penetrate dust clouds more easily. Infrared telescopes can detect the heat radiation given off by the dust, which is a signature of the formation of stars and planets.

Additionally, infrared light can reveal the presence of cold gas, which is necessary for the formation of stars. By using telescopes optimized for observations in infrared light, astronomers can gain important insights into the early stages of galactic lives.

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using your results in the calculations of the density of di water in part f, a) which measuring device did you expect to give the greatest accuracy?

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Measuring the density of DI water, a balance or scale with high precision and accuracy would be expected to give the greatest accuracy since it can measure the mass of the water with high accuracy and low systematic and random errors.

In the calculation of the density of DI water, several measuring devices can be used to determine the mass and volume of the water, such as a balance or scale for mass measurement and a graduated cylinder or burette for volume measurement. The accuracy of the measuring device can affect the accuracy of the calculated density.

In general, the measuring device with the greatest accuracy is the one with the smallest systematic and random errors. Systematic errors are those that affect the accuracy of the measurement consistently, while random errors are those that affect the accuracy randomly and independently. Therefore, a measuring device with a small systematic error and low random error will give the greatest accuracy.

A graduated cylinder or burette may introduce some errors due to the uncertainties in reading the volume, but these errors can be reduced by using a smaller volume measuring device or increasing the number of readings taken.

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An oxygen gas container has a volume of 20.0 L. How many grams of oxygen are in the container if the gas has a pressure of 876 mmHg at 23 C?

Answers

The mass of the oxygen gas in the oxygen container is found to be 14 grams.

The volume of the oxygen container is 20L and the pressure of the container at 23 degree Celsius is 876 mmHg.

From the ideal gas equation,

PV = W/MRT

Where,

P is pressure,

V is volume,

M is the molar mass,

W is the actual mass,

R is the gas constant,

T is the temperature.

Putting values,

876 x 20 = W/16 x 62.36 x 300

W = 14 grams.

So, the mass of the oxygen gas in the container is 14 grams.

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A duck floats backwards a distance of 3 meters in 15 seconds. What is the duck's velocity?

Answers

I think the ducks velocity is 45


Increasing the resistance (R) will decrease the E (electric field) but increasing the L (length) will decrease it more significantly. why?

Answers

The electric field (E) is directly proportional to the voltage (V) divided by the distance (d) between the two points.

Therefore, as the resistance (R) in the circuit increases, the voltage (V) decreases

The electric field (E) is directly proportional to the voltage (V) divided by the distance (d) between the two points. Therefore, as the resistance (R) in the circuit increases, the voltage (V) decreases, resulting in a decrease in the electric field (E). However, when the length (L) of the circuit increases, the distance (d) between the two points also increases, resulting in a greater decrease in the electric field (E) compared to the decrease caused by an increase in resistance (R). This is because the electric field (E) is inversely proportional to the distance (d), meaning that a greater distance (d) results in a smaller electric field (E). Therefore, increasing the length (L) of the circuit has a more significant effect on decreasing the electric field (E) compared to increasing the resistance (R).

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A student is recording how far an ant can crawl over time. He gets so interested in the project that he forgets to enter a few data
points. Based on the data in the table the values for the missing data points are MOST LIKELY
A)
9 minutes and 8 inches
B)
9 minutes and 9 inches
10 minutes and 9 inches
D)
10 minutes and 10 inch
Eliminate

Answers

Answer: 10 minutes and 9 inches

Explanation:

I got it right and they are counting by 2 and 3

ANSWER ALL QUESTIONS IN DETAIL AND WILL MARK BRAINLIEST IF ANSWERED CORRECTLY AND WELL. 20 POINTSSSSS

ANSWER ALL QUESTIONS IN DETAIL AND WILL MARK BRAINLIEST IF ANSWERED CORRECTLY AND WELL. 20 POINTSSSSS

Answers

Answer:

(a) - \(R_{eq.}=8 \ \Omega\)

(b) - \(I_1=3 \ A, \ I_2= 1.8 \ A, \ I_3=1.2 \ A\)

(c) - \(\Delta V_1=6 \ V, \ \Delta V_2= 18\ V, \ \Delta V_3= 18 \ V\)

Conceptual:

Things to know about parallel/series resistors:

\(\boxed{\left\begin{array}{ccc}\text{\underline{Resistors in Series:}}\\\\R_s=R_1+R_2+R_3+\dots +R_n\\\\I_1=I_2=I_3= \dots = I_n\\\\\Delta V_1+\Delta V_2+\Delta V_3+ \dots +\Delta V_n=\Delta V\end{array}\right} \ \ \boxed{\left\begin{array}{ccc}\text{\underline{Resistors in Parallel:}}\\\\\frac{1}{R_p}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3}+ \dots + \frac{1}{R_n} \\\\\Delta V_1=\Delta V_2=\Delta V_3= \dots =\Delta V_n\\\\I_1+I_2+I_3+ \dots + I_n=I\end{array}\right}\)

What is a resistor?

A resistor takes electrical energy and converts it to some other form of energy, such as heat. In doing so this can alter a circuit's current and divide voltages.

What is current?

Electrical current is the flow of charged particles.

What is voltage?

To put it simply, voltage is what "pushes" current through a circuit.

\(\boxed{\left\begin{array}{ccc}\text{\underline{Ohm's Law:}}\\\\\Delta V=IR\end{array}\right}\)

How you should tackle these types of problems:

I recommend combining resistors until you have one resistor. This one resistor is what your total resistance is, which I call the equivalent resistor. Then work backwards from the equivalent resistor to find any information you need, utilizing Ohm's law and properties of parallel/series resistors.

Step-by-step:

Refer to the attached image(s).

ANSWER ALL QUESTIONS IN DETAIL AND WILL MARK BRAINLIEST IF ANSWERED CORRECTLY AND WELL. 20 POINTSSSSS
ANSWER ALL QUESTIONS IN DETAIL AND WILL MARK BRAINLIEST IF ANSWERED CORRECTLY AND WELL. 20 POINTSSSSS
ANSWER ALL QUESTIONS IN DETAIL AND WILL MARK BRAINLIEST IF ANSWERED CORRECTLY AND WELL. 20 POINTSSSSS

the block of mass m in the following figure slides on a frictionless surface

Answers

For the right block to balance the forces and remain steady, it needs to weigh 7.9 kg.

The force is an external agent which is applied to the body or an object to move it or displace it from one position to another position.

When there is no net force acting on the system, the two blocks stay in place. In this instance, the strain in the rope holding the two blocks together balances the pull of gravity on them. The sine of the angles, along with the masses of the blocks, can be used to calculate the tension in the rope.

\(T= (m_1 \times g) \times sin(\theta_1) + (m_2\times g) \times sin(\theta_2)\)

Substituting the known values:

\(T = (10 \times 9.8 )\times sin(23^o) + (m_2\times 9.8 )\times sin(40^o)\)

Solving for m₂:

\(m_2= \dfrac{(T- (10 \times 9.8 )\times sin(23^o)} { (9.8\times sin(40^o))}\)

The mass of the right block must be 7.9 kg for the two blocks to remain stationary.

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The question is -

Two blocks in the Figure below are at rest on frictionless surfaces What must be the mass of the right block so that the two blocks remain stationary? 4.9kg 6.1kg 7.9kg 9.8kg

the block of mass m in the following figure slides on a frictionless surface

what is the highest order dark fringe, , that is found in the diffraction pattern for light that has a wavelength of 561 nm and is incident on a single slit that is 1420 nm wide?

Answers

The highest order dark fringe for a 561 nm light incident on a 1420 nm wide slit is the 3rd order.

Diffraction occurs when light passes through a narrow opening or slit, causing the wave to bend and interfere with itself. The pattern of bright and dark fringes produced by this interference is called a diffraction pattern. The position of these fringes can be determined using the equation d sin θ = mλ, where d is the width of the slit, θ is the angle of diffraction, m is the order of the fringe, and λ is the wavelength of the light.

Using this equation, we can calculate that the 3rd order dark fringe corresponds to an angle of approximately 5.68 degrees for a 561 nm light incident on a 1420 nm wide slit. Therefore, the highest order dark fringe in this situation is the 3rd order.

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2. A 9.6 kg object is pulled along a horizontal surface. If the coefficient of friction between the surfaces is 0.11, what is the force of friction?

Answers

The force of friction is 10.36 N. Friction is an important concept in physics and plays a crucial role in various phenomena, such as walking, driving, and the operation of machines.

What is Frictions?

Friction is a force that opposes motion between two surfaces that are in contact with each other. It arises due to the roughness of the surfaces and the interlocking of the irregularities on the surfaces. Friction acts in a direction opposite to the direction of motion or the tendency of motion.

The force of friction can be calculated using the formula:

f = μN

where:

f = force of friction

μ = coefficient of friction

N = normal force (the force perpendicular to the surface)

In this case, we are given the coefficient of friction and the mass of the object, but we need to find the normal force. Since the object is being pulled horizontally, the normal force is equal to the weight of the object:

N = mg

where:

m = mass of the object

g = acceleration due to gravity (9.81 m/s^2)

N = (9.6 kg)(9.81 m/s^2) = 94.18 N

Now we can calculate the force of friction:

f = μN = (0.11)(94.18 N) = 10.36 N

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If a soap bubble is 110 nm thick, what wavelength is most strongly reflected at the center of the outer surface when illuminated normally by white light? assume that n=1.32 .

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If a soap bubble is 110 nm thick then the wavelength is most strongly reflected at the center of the outer surface when illuminated normally by white light would be  580.8 nanometers.

What is Wavelength?

It can be understood in terms of the distance between any two similar successive points across any wave for example wavelength can be calculated by measuring the distance between any two successive crests.

n =  Index of refraction of soap bubble  = 1.32

t = thickness of the soap bubble = 110 nm = 110 x 10⁻⁹ m

m = 0

The necessary condition for the reflection to happen,

2nt = (m+ 0.5)λ

2×(1.32)×(110 x 10⁻⁹ ) = (0 +0.5)λ

λ= 580.8 ×10⁻⁹

λ= 580.8 nanometers

Thus, the wavelength of the reflected light would be 580.8 nm.

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a 10.0-mh inductor carries a current i 5 imax sin vt, with imax 5 5.00 a and f 5 v/2p 5 60.0 hz. what is the self-induced emf as a function of time?

Answers

The self-induced electromotive force (EMF) as a function of time in the given scenario is given by the expression: ε = -L(di/dt), where L is the inductance of the inductor and di/dt is the rate of change of current with respect to time.

In an inductor, a changing current induces an opposing EMF. According to Faraday's law of electromagnetic induction, the magnitude of the self-induced EMF in an inductor is proportional to the rate of change of current. The negative sign indicates that the self-induced EMF opposes the change in current.

Given that the inductor carries a current i = 5Imax sin(vt), where Imax = 5.00 A and f = v/2π = 60.0 Hz, we can find the rate of change of current with respect to time by taking the derivative of i:

di/dt = d/dt (5Imax sin(vt))

      = 5Imax cos(vt) (dv/dt)

      = 5Imax cos(vt) (2πf)

Since the frequency f is 60.0 Hz, the expression simplifies to:

di/dt = 5Imax cos(2π(60.0)t)

Now, we can calculate the self-induced EMF as a function of time using the formula ε = -L(di/dt). Given that the inductance L is 10.0 mH (millihenries), which is equivalent to 0.010 H, we have:

ε = -0.010 * 5Imax cos(2π(60.0)t)

This equation represents the self-induced EMF as a function of time in the given scenario.

Inductors are passive electrical components that store energy in a magnetic field when a current flows through them. They are characterized by their inductance, which is a measure of their ability to oppose changes in current.

The self-induced EMF, also known as back EMF, is the electromotive force that arises in an inductor due to the change in current. It is determined by the rate of change of current with respect to time and is given by the equation ε = -L(di/dt), where L is the inductance of the inductor. Understanding the concept of self-induced EMF is crucial in various fields of electrical engineering, such as circuit analysis, power electronics, and electromagnetics.

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true or false: the resistances measured in this experiment are very small. the values of resistance will be less than 1 ω.

Answers

False. The statement that the resistances measured in the experiment are very small and less than 1 Ω cannot be determined solely based on the information provided.

The values of resistance in an experiment can vary widely depending on the specific setup and components used.

Resistances can range from very small values (less than 1 Ω) to extremely large values, depending on the context and purpose of the experiment. Additional information about the specific experiment and its components would be needed to make a definitive statement about the resistances being measured.

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Suppose a blanket has a sock stuck to it due to static electricity. When you pull the sock off of the blanket, what happens to the potential energy between them?

Answers

Explanation:

When you pull the sock off of the blanket, the socks gain electrons out of blanket. This makes socks slightly negatively charged. The potential energy of the socks rise whereas potential energy of the blanket reduces. This happens because of exchange of electrons between socks and blanket.

2. A car accelerates uniformly from +10.0 m/s to +40.0 m/s over a distance of 125 m. How long did it take to go that distance? Show all your work, including the equation used, given and unknown quantities, and any algebra required. Make sure your answer has the correct number of significant figures.

Answers

The time taken for the car to cover the distance of 125 m is 5 seconds

How to determine the time

From the question given above, the following data were obtained:

Initial velocity (u) = 10 m/sFinal velocity (v) = 40 m/sDistance (s) = 125 mTime (t) =?

The time taken for the car to cover the 125 m distance can be obtained as illustrated below:

s = (u + v)t / 2

125 = [(10 + 40) × t] / 2

125 = (50 × t) / 2

Cross multiply

50 × t = 125 × 2

50 × t = 250

Divide both sides by 50

t = 250 / 50

t = 5 s

Thus, the time taken by the car to cover the 125 m distance is 5 seconds

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A source produces 20 crests and 20 troughs in 4 seconds. The second crest is 3 cm away from the first crest.Calculate :
i. Wavelength [ Ans : 3 × \( {10}^{ - 2} \) m ]
ii. Frequency [ Ans : 5 Hz ]
iii. Wave speed [ Ans : 1.5 × \( {10}^{ - 1} \tt{ {ms}^{ - 1}} \) ]

Show your workings !
*Irrelevant / Random answers will be reported!

Answers

Answer:

Solution given:

No of waves[N] =20crests & 20 troughs

=20waves

Time[T]=4seconds

distance[d]=3cm=0.03m

Now

Wave length=3cm=3 × \( {10}^{ - 2}m \)

Frequency=\( \frac{No of waves}{time}\)

=\( \frac{20}{4} \)=5Hertz

and

Wave speed:wave length×frequency=3 × \( {10}^{ - 2}m \)×5=1.5 × \( {10}^{ - 1} \tt{ {ms}^{ - 1}} \).

A 5kg traveling at 4 m/s slams into a 1kg object and sticks to it. What will the final velocity of the two objects be?

Answers

Answer:

Below

Explanation:

Using conservation of momentum

mv = mv

5(4)  + 1(0)   = (4+1) v    

                ( this assumes the 1 kg mass was not moving before being struck)

20  = 5 v

v = 4 m/s          

Please help asap!
the probability of a chance event is a number between 0 and 1 that expresses the ___ that an event ___ occur.
1: number of times / likelyhood
2: can / cannot

Answers

The probability of a chance event is a number between 0 and 1 that expresses the likelihood that an event can occur.

This means that the probability is a measure of how likely or probable it is that a particular event will happen. The closer the probability is to 1, the more likely the event is to occur, while the closer it is to 0, the less likely it is to occur.

For example, if the probability of an event is 0.8, it means that there is an 80% chance that the event will happen, while a probability of 0.2 means that there is only a 20% chance that the event will occur. It's important to note that the probability can never be greater than 1 or less than 0, as these values represent impossible and certain events, respectively.

When the probability is close to 1, the event is highly likely to happen, while a probability close to 0 indicates that the event is unlikely to occur. An event with a probability of 1 means it will certainly happen, whereas an event with a probability of 0 cannot happen. Understanding probabilities allows us to make informed decisions and predictions about future events based on their likelihood of occurrence.

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a pulse covers a distance of 5m in 15seconds . Calculate the sped of the pulse.​

Answers

According to the question the speed of pulse is = 0.33m/s

What does "speed" in science mean?

Velocity is the pace and direction of either an object's movement, whereas speed is now the time rate which an object is travelling along a path. In other words, velocity is a vector, whereas speed would be a scalar value. If you determine how far an object travels in a certain amount of time, you can calculate its speed.For instance, an automobile is moving at a pace of 70 miles per hour if it covers 70 miles in an hour .

How is speed measured?

The equation for speed can be obtained by simply dividing time by distance.

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Someone please help

Someone please help

Answers

Based on the attached image:

The name of the longitude line that passes through point A is the International Date LineThe longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° ELongitude 120° is BSolar time at Point B is 4 pmThe location will correspond to any point on the same latitude as A

What are lines of longitude?

Lines of longitude are imaginary lines which run along the earth from the North pole. to the South pole.

Longitude lines divide the earth into semi-circles.

Longitude lines are known as meridians and each meridian measures one arc degree of longitude.

Considering the attached image:

The name of the longitude line that passes through point A is the International Date LineThe longitude 180° is experiencing solar noon because the rays of the sun are parallel to it.The longitude for 6 pm is 90° W, 12 midnight is 0°, and 6 am is 90° ELongitude 120° is BSolar time at Point B is 4 pmthe location will correspond to any point on the same latitude as A

In conclusion, longitude lines are imaginary lines and run from North to South on the earth.

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Describe the sequence of mechanical energy events that lets you hear the
muffled sound of a radio from inside your neighbor's closed house.

Describe the sequence of mechanical energy events that lets you hear themuffled sound of a radio from

Answers

Answer:

Starting from the beginning.

There is a radio signal that is received by the radio.

The radio interprets the signal and produces a current in response to it.

That current goes to a membrane that oscillates producing sound, the oscillation of the membrane is the first mechanical energy event here.

These oscillations can travel in material mediums, for example, the air. Then there is a production of waves (soundwaves) that travel in the air (second event).

Those waves now hit the wall that separates you and your neighbor, as the wall is made of a material, the soundwaves can travel through it, but they will be dispersed (a part of the waves rebounds on the wall, and another part is dissipated as the wave travels through the wall), there is also a transmitted part of the wave, that is now in your house. (this change of medium will be the third event). Now only the lower frequencies survive, this is why the sound is "muffled".

Those remaining frequencies now travel in your house, and when they reach your ear, your ear sends a signal to your brain and your brain interprets them as sound. The wave interacting with your ear will be the fourth and last mechanical energy event.

All interactions between the atmosphere and the geosphere involve

gases or particles in air and water

water and living things.

soil and gases or particles in the air

soil and living things

Answers

Answer:

The geosphere consists of the solid Earth and the atmosphere consists of the gaseous components in the air. Thus, the answer is C.

Explanation:

Answer:

C

Explanation:

At t=0, an 850-g mass at rest on the end of a horizontal spring (k = 168 N/m ) is struck by a hammer which gives it an initial speed of 2.20 m/s .
Determine the period of the motion.
Determine the frequency of the motion.
Determine the amplitude.
Determine the maximum acceleration.
Determine the total energy.
Determine the kinetic energy when x=0.40A where A is the amplitude.

Answers

To solve this problem, we can use the principles of simple harmonic motion (SHM) and the equations related to it.

1. Determining the period of the motion:

The period (T) of an object undergoing SHM is the time it takes to complete one full cycle. It can be calculated using the formula:

T = 2π√(m/k)

where m is the mass of the object and k is the spring constant.

Given:

Mass (m) = 850 g = 0.85 kg

Spring constant (k) = 168 N/m

Using the formula, we can calculate the period:

T = 2π√(0.85/168) ≈ 0.782 seconds

Therefore, the period of the motion is approximately 0.782 seconds.

2. Determining the frequency of the motion:

The frequency (f) of an object undergoing SHM is the number of cycles completed per unit of time. It can be calculated as the reciprocal of the period:

f = 1/T

Substituting the calculated value of T:

f = 1/0.782 ≈ 1.28 Hz

Therefore, the frequency of the motion is approximately 1.28 Hz.

3. Determining the amplitude:

The amplitude (A) of the motion is the maximum displacement of the object from its equilibrium position. In this case, it is not directly given. However, we can calculate it using the initial velocity (v) and the angular frequency (ω).

The angular frequency (ω) can be calculated using the formula:

ω = √(k/m)

Substituting the given values:

ω = √(168/0.85) ≈ 17.414 rad/s

The amplitude (A) can be calculated using the initial velocity and angular frequency:

A = v/ω

Given:

Initial velocity (v) = 2.20 m/s

Substituting the values:

A = 2.20/17.414 ≈ 0.126 m

Therefore, the amplitude of the motion is approximately 0.126 m.

4. Determining the maximum acceleration:

The maximum acceleration (amax) of an object undergoing SHM can be calculated using the formula:

amax = ω^2A

Substituting the calculated values:

amax = (17.414)^2 × 0.126 ≈ 30.34 m/s^2

Therefore, the maximum acceleration of the motion is approximately 30.34 m/s^2.

5. Determining the total energy:

The total energy (E) of an object undergoing SHM can be calculated as the sum of its potential energy (PE) and kinetic energy (KE). In SHM, at any point in the motion, the total energy remains constant.

The potential energy (PE) of the system can be calculated using the formula:

PE = 0.5kA^2

Substituting the given values:

PE = 0.5 × 168 × (0.126)^2 ≈ 1.34 J

The kinetic energy (KE) of the system can be calculated using the formula:

KE = 0.5mv^2

Substituting the given values:

KE = 0.5 × 0.85 × (2.20)^2 ≈ 2.042 J

The total energy (E) is the sum of potential energy and kinetic energy:

E = PE + KE = 1.34 + 2.042 ≈ 3.382 J

Therefore, the total energy of the system is approximately 3.382 J.

6. Determining the kinetic energy when x = 0.40A:

The kinetic energy (KE) at a specific displacement (x) from the equilibrium position can be calculated using the formula:

KE = 0.5k(A^2 - x^2)

Given:

x = 0.40A = 0.40 × 0.126 = 0.0504 m

Substituting the given values:

KE = 0.5 × 168 × (0.126^2 - 0.0504^2) ≈ 0.737 J

Therefore, the kinetic energy when x = 0.40A is approximately 0.737 J.

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A 0.48 kg circus monkey is about to be shot from a cannon as part of his thrilling circus act. Draw a free body diagram labeling the forces acting on him at the moment he is launched from the cannon. F_(Net= ) 86N

Answers

What is it that you need help on?

Objects with masses of 141 kg and 494 kg are separated by 0.396 m. A 74.8 kg mass is placed midway between them.
1 ) Find the magnitude of the net gravitational force exerted by the two larger masses on the 74.8 kg mass.
The value of the universal gravitational constant is 6.672 × 10−11 N · m^2 /kg^2.
Answer in units of N.

2 ) Leaving the distance between the 141 kg and the 494 kg masses fixed, at what distance from the 494 kg mass (other than infinitely remote ones) does the 74.8 kg mass experience a net force of zero?
Answer in units of m.

Objects with masses of 141 kg and 494 kg are separated by 0.396 m. A 74.8 kg mass is placed midway between

Answers

( 1) The net gravitational force between the 74.8 kg mass is  8.09 x 10⁻⁵ N.

( 2) The distance from the from the 494 kg mass where the middle mass experiences net zero force is 0.258 m.

What is net gravitational force on the middle mass?

The net gravitational force acting on the middle mass is calculated by applying Newton's law of universal gravitation as shown below.

F = ( GmM ) / ( R² )

where;

G is universal gravitation constantm is the mass of the middle massM is the mass of the first massR is the distance of separation between the two masses

The force between the first mass and the middle mass is calculated as;

F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( 0.198² )

F' = 1.8 x 10⁻⁵ N

The force between the third mass and the middle mass is calculated as;

F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.198² )

F'' = 6.29 x 10⁻⁵ N

The net gravitational force on the middle mass;

F (net)  = 6.29 x 10⁻⁵ N + 1.8 x 10⁻⁵ N

F ( net ) = 8.09 x 10⁻⁵ N

Let the distance of zero net force from the 141 kg mass = d.

then the distance from the 494 kg mass = 0.396 m - d

F' = ( 6.672 x 10⁻¹¹ x 141 x 74.8 ) / ( d² )

F' = 0.704 x 10⁻⁶ / d²

F'' = ( 6.672 x 10⁻¹¹ x 494 x 74.8 ) / ( 0.396 - d )²

F'' = 2.47 x 10⁻⁶ / ( 0.396 - d )²

for zero net force, the two forces must be equal

0.704 x 10⁻⁶ / d²  = 2.47 x 10⁻⁶ / ( 0.396 - d )²

0.704 (0.396 - d )² = 2.47d²

(0.396 - d )²  = ( 2.47d² ) / ( 0.704 )

(0.396 - d )²  = 3.51d²

0.396 - d = √ ( 3.51d² )

0.396 - d = 1.87d

1.87d + d = 0.396

d (1.87 + 1) = 0.396

d (2.87) = 0.396

d = 0.396 / 2.87

d = 0.138 m

The distance from the 494 kg mass = 0.396 - 0.138 m = 0.258 m

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