the main goal of utilizing a mass customization production system is to ________.

Answer:

Vehicle manufacturers specify various reference points on the frame, body, fender, bumper or suspension. On some applications, ride height may even be specified as a distance between two points on the vehicle's suspension, such as the distance from the frame rail to the axle or a suspension control arm.

Answer:

Explanation:

The process that Piaget called "adding another example to an existing scheme" is called assimilation. Assimilation refers to the cognitive process of incorporating new information or experiences into existing mental schemas or frameworks. In this case, Tammy assimilates the new example of a golf ball into her existing "ball" scheme, expanding her understanding of what falls under the category of a ball.

Answer:

Here are some characteristics that describe customers who are more likely to have low assets and medium-low debt:

* **Age:** Younger customers are more likely to have lower assets and debt than older customers. This is because they have had less time to accumulate assets and may be carrying more student loan debt.

* **Income:** Customers with lower incomes are more likely to have lower assets and debt than customers with higher incomes. This is because they have less money to save and invest, and may be spending more of their income on necessities.

* **Education:** Customers with less education are more likely to have lower assets and debt than customers with more education. This is because they may have lower-paying jobs and may be less likely to save and invest.

* **Marital status:** Single customers are more likely to have lower assets and debt than married customers. This is because they may have less income and may be spending more of their income on housing and other expenses.

* **Employment status:** Unemployed customers are more likely to have lower assets and debt than employed customers. This is because they may have less income and may be spending more of their income on necessities.

* **Credit score:** Customers with lower credit scores are more likely to have lower assets and debt than customers with higher credit scores. This is because they may have difficulty qualifying for loans and may be paying higher interest rates on debt.

It is important to note that these are just general trends, and there are always exceptions. There are many factors that can affect a customer's assets and debt, including their personal circumstances, financial decisions, and economic conditions.

Explanation:

Answer:

The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency.

Explanation:

I did it on edge and got it right.

Answer:

The energy in pneumatic power systems is easily transmitted to gases, which absorb the energy of the system and lower its efficiency

Thanks for points!!! :D

Answer:

Sarah is a professional interior designer.

Therefore, Sarah carries the title of a _registered___ interior designer.

Explanation:

Some states require only the licensed designers to carry out interior designs, while some others allow both the licensed and unlicensed interior designers to carry on the work of interior designers.  In the states where only the licensed designers are allowed to use the title of interior designer, they are registered after passing the state-prescribed examinations and meeting some professional experience requirements. The most common exam is the National Council for Interior Design Qualification (NCIDQ) examination, which only bachelor degree holders in interior design are allowed to sit for.

Answer:

pakipic na lang po question nyo para masagot po

Explanation:

please po di ko masyado gets po e

it is simple the title name after all it is just asking your name

Answer:

False, metal and dirt ARE considered contaminants!

Explanation:

i ride motocross! trust me!

The statement "Metal and dirt are not considered contaminants to oil" is false. The correct option is B.

Metals are chemical elements that have high thermal and electrical conductivity, and they are soft and ductile. Magnesium, helium, gold, and silver are metals. They are very reactive, and they contain both gas and solids.

Oil and dirt are considered contaminated to oil. It causes a chemical reaction in the oil, that's why it is a problem with contamination of the oil. It causes reactions like depletion or oxidation.

In motor oils, there are many chances of pollution with dirt and metals, and other oxides. This causes debris and leads to degradation of work of lubrication of engine parts, which causes friction.

Thus, the statement is true. The correct option is B.

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Answer:

The wheel will go through 1146 revolutions in 5 minutes.

Explanation:

We can the formula:

\(\boxed{\omega = \frac{2 \pi}{T}}\)

where

ω ⇒ angular speed (24 rad/s),

T ⇒ time period (? s),

and solve for T to find the time it takes for the wheel to complete one revolution.

⇒  \(24 = \frac{2 \pi}{T}\)

⇒  \(T = \bf \frac{2 \pi}{24}\)  s

This means it takes \(\bf \frac{2 \pi}{24}\) seconds for the wheel to complete one revolution.

Now, using the unitary method,

In \(\frac{2 \pi}{24}\) seconds          ⇒    1 revolution completed

In 1 second              ⇒    1 ÷ \(\frac{2 \pi}{24}\)   =  \(\frac{24}{2 \pi}\)  revolutions completed

In (5 × 60 = ) 300s  ⇒     \(\frac{24}{2 \pi}\)   ×  300   = 1145.9

                                                            ≅ 1146 revolutions completed

Answer:

a rock is made up of two or more minerals but a mineral is a natural substance with chemical and physical properties

Answer:

Trade association.

Explanation:

I'm thinking it is as it represents contractors who design, install, inspect and maintain amongst other activities electrical and electronic equipments or service.

The current capability of the transformer is 51.21 amps on the 12470-volt side of the transformer.

The transformer data plate has given a 3-phase 1000 kVA rating. The primary side of the transformer is rated at 12470 volts and the secondary side is rated at 480 volts. The current capability on the 12470-volt side of the transformer can be determined by using the formula:

I=KVA/ (√ (3) x KV)

Where,

I = Current in amperes

KVA = Kilovolt-amperes

KV = Voltage

KVA is the rating of the transformer that represents its capacity. In this scenario, the transformer is rated at 1000 kVA. We'll substitute these values in the formula.

I = 1000/(√ (3) x 12,470)

I = 51.21 amps

It is crucial to know the current capability of the transformer because it helps us to choose the appropriate wire size and circuit breaker required for the transformer to function correctly. It also aids in the selection of the proper protective equipment for the transformer.

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Answer:

Utilizing flush valves for toilets and urinals and/or low-flow versions of each, as well as installing low-flow faucets, or aerators can significantly reduce water use.

Explanation:

A software engineer might engage in any of the following activities that could be deemed illegal, immoral, and unethical:
Software piracy, security breaches, data theft, software spying or snooping, creating viruses or other harmful code, intentionally producing defective code, and knowingly releasing software with bugs or security flaws.


Creating software that serves a beneficial social or moral purpose, such as software that promotes environmental sustainability, public safety, and public health. Software that serves the public good is legal, but some software might have unintended or unforeseen ethical implications.

According to the IEEE code of ethics, engineers should support and participate in pro bono and charitable work that promotes the public good. Therefore, as a software engineering company owner, you should allow your employees to do pro bono work on company time as long as it does not interfere with their assigned tasks or affect the company's productivity.

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Answer:

The answer "K = 0.0075"

Explanation:

If we try to measure up to 69 kPa of air, find mercury or fluid for gauge.  

While mercury was its largest liquid with a density of 13600 kg / m3 at normal room temperature.  

Let's all measure for 69 kPa that height of the  mercury liquid column.

\(\to P = 69 \ kPa\)

       \(= 69000 Pa \\\\\)

\(\to \rho = 13600 \ \ \frac{kg}{m^3} \\\\\\to g = 9.81 \ \ \frac{m}{s^2} \\\\\)

Formula:

\(\to P=\rho \ gh\)

\(\to 69000 = 13600\times9.81 \times h\\\\\to h= \frac{69000}{13600\times9.81} \\\\\to h= \frac{69000}{133416} \\\\\to h= 0.517179349 \\\\ \to h= 517 \ mm \\\\\)

The right choice for pressure measurements up to 69 kPa is mercury.  

Atmospheric Mercury up to 69 kPa Air 517 mm  

The relationship of Hg to Pa is = 134.22 Pa 1 mm Hg  

Static sensitivity to Pa of mm hg = change of mercury height to Pa:

\(= \frac{\Delta Hg }{ \Delta P }\\\\= \frac{1 }{ 133.3 }\\\\= 0.0075\)

Answer:

a) the mass flow rate of the steam is  \(\mathbf{m_1 =6.92 \ kg/s}\)

b) the exit velocity of the steam  is \(\mathbf{V_2 = 562.7 \ m/s}\)

c) the exit area of the nozzle is  \(A_2\) = 0.0015435 m²

Explanation:

Given that:

A steam with 5 MPa and 400° C enters a nozzle steadily

So;

Inlet:

\(P_1 =\) 5 MPa

\(T_1\) = 400° C

Velocity V = 80 m/s

Exit:

\(P_2 =\) 2 MPa

\(T_2\) = 300° C

From the properties of steam tables  at \(P_1 =\) 5 MPa and \(T_1\) = 400° C we obtain the following properties for enthalpy h and the speed v

\(h_1 = 3196.7 \ kJ/kg \\ \\ v_1 = 0.057838 \ m^3/kg\)

From the properties of steam tables  at \(P_2 =\) 2 MPa and \(T_1\) = 300° C we obtain the following properties for enthalpy h and the speed v

\(h_2 = 3024.2 \ kJ/kg \\ \\ v_2= 0.12551 \ m^3/kg\)

Inlet Area of the nozzle = 50 cm²

Heat lost Q = 120 kJ/s

We are to determine the following:

a) the mass flow rate of the steam.

From the system in a steady flow state;

\(m_1=m_2=m_3\)

Thus

\(m_1 =\dfrac{V_1 \times A_1}{v_1}\)

\(m_1 =\dfrac{80 \ m/s \times 50 \times 10 ^{-4} \ m^2}{0.057838 \ m^3/kg}\)

\(m_1 =\dfrac{0.4 }{0.057838 }\)

\(\mathbf{m_1 =6.92 \ kg/s}\)

b) the exit velocity of the steam.

Using Energy Balance equation:

\(\Delta E _{system} = E_{in}-E_{out}\)

In a steady flow process;

\(\Delta E _{system} = 0\)

\(E_{in} = E_{out}\)

\(m(h_1 + \dfrac{V_1^2}{2})\) \(= Q_{out} + m (h_2 + \dfrac{V_2^2}{2})\)

\(- Q_{out} = m (h_2 - h_1 + \dfrac{V_2^2-V^2_1}{2})\)

\(- 120 kJ/s = 6.92 \ kg/s (3024.2 -3196.7 + \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)

\(- 120 kJ/s = 6.92 \ kg/s (-172.5 + \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)

\(- 120 kJ/s = (-1193.7 \ kg/s + 6.92\ kg/s ( \dfrac{V_2^2- 80 m/s^2}{2}) \times (\dfrac{1 \ kJ/kg}{1000 \ m^2/s^2})\)

\(V_2^2 = 316631.29 \ m/s\)

\(V_2 = \sqrt{316631.29 \ m/s\)

\(\mathbf{V_2 = 562.7 \ m/s}\)

c) the exit area of the nozzle.

The exit of the nozzle can be determined by using the expression:

\(m = \dfrac{V_2A_2}{v_2}\)

making \(A_2\) the subject of the formula ; we have:

\(A_2 = \dfrac{ m \times v_2}{V_2}\)

\(A_2 = \dfrac{ 6.92 \times 0.12551}{562.7}\)

\(A_2\) = 0.0015435 m²

i] The density of the pellet is 0.977 g/cm^{3}. ii] The macropore volume in cm^{3}/g is 0.205 cm^{3}/g. iii] The macropore void fraction in the pellet is 25.1%.iv] The micropore void fraction in the pellet is 49.0%. v] The solid fraction of the pellet is 25.9%. vi] The density of the particles is 1.222 g/cm^{3}.

i] To determine the density of the pellet, we can use the formula:

Density = Mass / Volume

Given that the mass of the pellet is 3.15 g and the volume is 3.22cm^{3}, we can calculate the density as follows:

Density = 3.15 g / 3.22 cm^{3}≈ 0.977 \(g/cm^{3\)

ii] The macropore volume in cm3/g can be calculated by dividing the macropore volume of the pellet (0.645 cm3) by the mass of the pellet (3.15 g):

Macropore volume = 0.645 cm^{3} / 3.15 g ≈ 0.205 \(cm^{3} /g\)

iii] The macropore void fraction in the pellet can be calculated using the formula:

Macropore void fraction = Macropore volume / Total volume of the pellet

Total volume of the pellet = Volume - Macropore volume = 3.22 cm^{3}- 0.645 cm^{3} = 2.575 cm^{3}

Macropore void fraction = 0.645 cm^{3} / 2.575 \(cm^{3}\)≈ 0.251 or 25.1%

iv] The micropore void fraction in the pellet can be calculated using the given micropore volume of the particles (0.40 cm^{3} /g) and the mass of the pellet (3.15 g):

Micropore volume in the pellet = Micropore volume/g x Mass

Micropore volume in the pellet = 0.40 \(cm^{3} /g\) x 3.15 g = 1.26 cm3

Micropore void fraction = Micropore volume in the pellet / Total volume of the pellet

Micropore void fraction = 1.26 \(cm^{3}\) / 2.575 \(cm^{3}\) ≈ 0.490 or 49.0%

v] The solid fraction of the pellet can be calculated by subtracting the sum of macropore and micropore void fractions from 1:

Solid fraction = 1 - (Macropore void fraction + Micropore void fraction)

Solid fraction = 1 - (0.251 + 0.490) ≈ 0.259 or 25.9%

vi] The density of the particles can be determined using the mass of the pellet (3.15 g) and the total volume of the particles:

Total volume of the particles = Volume - Macropore volume = 3.22 \(cm^{3}\)- 0.645 \(cm^{3}\) = 2.575\(cm^{3}\)

Density of the particles = Mass / Total volume of the particles

Density of the particles = 3.15 g / 2.575\(cm^{3}\) ≈ 1.222 \(g/cm^{3}\)

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Tech A is correct. A rotor that is too thin is not as effective in the braking system and will not be able to handle the heat as well. This can lead to a quicker wearing and fading of the brake parts.

A thinner rotor is not as effective in a braking system because it does not have as much surface area, which means less friction. This reduces the amount of contact between the brake pad and the rotor, resulting in less braking power. Additionally, a thinner rotor will not be able to handle the heat generated from braking as well as a thicker rotor.

This can lead to the rotor cracking or warping due to the excessive heat, and it can also cause the brake pads to wear out more quickly. This can lead to a shorter lifespan of the brake parts and a less effective braking system. Therefore, it is important to ensure that the rotor is thick enough to be able to handle the heat and provide adequate braking power.

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Answer:

Use a non digital multimeter.

Explanation:

If a digital multimeter displays "000" when reading amperage, the technician should adjust the multimeter to a higher amperage range.

This is because "000" typically indicates that the current being measured is too low for the current range selected on the multimeter.

By switching to a higher amperage range, the technician can get a more accurate reading and ensure that the multimeter is properly measuring the current in the circuit under test.

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Answer:

Explanation:

sorry i dont know

When there are requirements to the form and appearance of a contract, it is considered a formal contract. Formal contracts have specific requirements and must follow certain legal formalities to be valid and enforceable. This may include the presence of witnesses, the signature of all parties involved, and the inclusion of specific clauses and terms.

It is important to note that a formal contract is not always the best option, and that there are situations where an informal contract may be more appropriate. Informal contracts can be equally valid and enforceable, although they may be more difficult to prove in case of disputes or breach.

In general, the choice between a formal or informal contract will depend on the specific circumstances of the agreement and the needs of the parties involved. If it is a complex or high-risk agreement, or if the agreement is expected to be of long duration, it may be more appropriate to opt for a formal contract to ensure greater legal protection.

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Technician A says that the preferred method to run in a rebuilt engine is on a chassis dynamometer. Technician B says that an engine also could be run-in using proper procedures during a test drive.

Who is correct?Both technicians are correct to some extent, as they are both discussing ways of running in a rebuilt engine, which is necessary to prevent premature engine failure.There are a variety of ways to run-in a rebuilt engine, and different people have their own preferred methods. There are, however, a few methods that are generally accepted as being effective.The chassis dynamometer method, according to Technician A, is one such method. A chassis dynamometer is a device that allows a car to be driven on a set of rollers, which enables the engine to be run-in under load without the vehicle being driven on the road.

The advantage of this method is that the engine can be run-in under controlled conditions, with the ability to measure power output, fuel consumption, and other important parameters.Technician B, on the other hand, suggests running the engine-in during a test drive, which is another effective method of running-in a rebuilt engine. During this process, the engine should be operated at varying RPMs, with short periods of high engine speeds interspersed with longer periods of low engine speeds, to allow the engine to gradually build up heat and increase the load on the moving parts.While both methods have their advantages, the best method of running in a rebuilt engine ultimately depends on the engine itself and the intended use of the vehicle.

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Answer:

Reduce manufacturing costs.

Explanation:

Hope This Helps

Have A Great Day

Answer:

18 gauge

Explanation:

Standard automotive primary wire is 18 gauge. (internet search) Hope this helps

Answer:

I think we would.

Explanation:

Only if u invent it.

answer

i don't think so

but it will take a lot of thinking if it is

possible

Answer:

a) 0.01558 Ω per 1000 feet

b) 0.0923  Ω per mile

c)  3.57%

Explanation:

a) Calculate and verify the DC resistance

Dc resistance = R = р \(\frac{l}{A}\)

for aluminum at 20°C

р = 17 Ωcmil/ft

hence R = 17 * 1000 / ( 113000 ) = 0.01527 Ω per 1000 feet

there when there is an increase in resistance of 2% spiraling

R = 1.02 * 0.01527 = 0.01558 Ω per 1000 feet

b) Calculate the DC resistance at 50°C

R2 = R1 ( \(\frac{T+t2}{T+ t1}\) )

where ; R1 = 0.01558 , T = 228 , t2 = 50, t1 = 20 ( input values into equation above )

hence R2 = ( 0.01746 / 0.189 ) Ω per mile = 0.0923  Ω per mile

c ) Determine the percentage increase due to skin effect

AC resistance = 0.0956 ohm per mile

Hence; Increase in skin effect

= ( 0.0956  -0.0923 ) / 0.0923

=  0.0357 ≈ 3.57%

Answer:

Explanation:

Considering the flow of mercury in a tube:

When it comes to laminar flow of mercury, the thermal entry length is quite smaller than the hydrodynamic entry length.

Also, the hydrodynamic and thermal entry lengths which is given as DLhRe05.0= for the case of laminar flow. It should be noted however, that Pr << 1 for liquid metals, and thus making the thermal entry length is smaller than the hydrodynamic entry length in laminar flow, like I'd stated in the previous paragraph