The product of
2x and 3y​

Answer:

11x +98 just assume it to be an arithmetic progression

60 degrees is the measure of arc BC from the figure

The given diagram is a circle with several arc angles

arcAWB = 120 degrees

The line AC is a diameter

Since the sum of angles on a straight line is 180 degrees, hence:

arc AWB + arcBC = 180

arcBC = 180 - arc ZWX

arcBC = 180 - 120

arcBC = 60 degrees

Hence the measure of the arc BC from the diagram is 60 degrees

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the degrees of freedom for this test Women found this trait to be important, and this result was significant, t(15)=8.00, p<.05

Various amounts of data or information can be used to estimate statistical parameters. The degrees of freedom refers to the quantity of independent data points used to estimate a parameter. The number of independent scores that are utilized in an estimate of a parameter, minus the number of parameters used as intermediary stages in the estimation of the parameter itself, is generally considered to be the measure of the degree of freedom of the estimate. The degrees of freedom, for instance, are equal to the number of independent scores (N) minus the number of parameters calculated as intermediary steps, or N 1, if the variance is to be estimated from a random sample of N independent scores.

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The population proportion who participated in voting (63%) is higher than the sample proportion from this survey (58.91%).

To determine whether the population proportion who participated in voting or the sample proportion from the survey is higher, we need to compare the percentages.

The population proportion who participated in voting is given as 63% of all registered voters.

This means that out of every 100 registered voters, 63 participated in voting.

In the survey of retired voters, 162 out of 275 participants voted. To calculate the sample proportion, we divide the number of retired voters who participated (162) by the total number of retired voters in the sample (275) and multiply by 100 to get a percentage.

Sample proportion = (162 / 275) \(\times\) 100 ≈ 58.91%, .

Comparing the population proportion (63%) with the sample proportion (58.91%), we can see that the population proportion who participated in voting (63%) is higher than the sample proportion from this survey (58.91%).

Therefore, based on the given data, the population proportion who participated in voting is higher than the sample proportion from this survey.

It's important to note that the sample proportion is an estimate based on the surveyed retired voters and may not perfectly represent the entire population of registered voters.

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Answer:

For the first question since 1 mile equals 1.6 km we have to divide, 14.4/1.6=9

For the second question the formula is to divide by 9, if we do this our anser will be 5.

For the third question the answer is 100,000 cm^2, the reason this is, is because if 1m^2=10,000cm^2 , 1x10=10 and 10x10,000=100,000

Hope I helped tell me if i have to clarify anything :)

To find the area of the shaded region R enclosed by the graphs of y = e^(-x^2) in the first quadrant, you can use integration.

The integral represents the area under a curve between two x-values. In this case, we want the area in the first quadrant, so we need to integrate the function from x = 0 to some positive x-value.

The integral to find the area of R is given by:

A = ∫[0 to a] e^(-x^2) dx

Unfortunately, there is no elementary function to find the antiderivative of e^(-x^2) in terms of elementary functions. Therefore, the integral cannot be evaluated using simple algebraic methods.

However, the integral can be approximated using numerical methods or specialized techniques such as Gaussian quadrature or Monte Carlo methods. These methods can provide an approximation of the area of the shaded region R.

Alternatively, you can use software or graphing calculators that have built-in functions to find definite integrals to numerically approximate the area under the curve.

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Answer:

$548.9

Step-by-step explanation:

$499 x (1+10%) = $ 548.9

4214.7 is the balance in the account after 2 months .

What does compound and simple interest mean?

A fixed proportion of the principal amount borrowed or lent is what is known as simple interest and is paid or received over a given period of time.

                               Borrowers are required to pay interest on interest in addition to principal because compound interest accrues and is added to the total amount of interest from earlier periods.

P = $4200

R = 2.1% = 2.1/100 = 0.021  =

    T = 2 month = 2/12 = 1/6

   I = PRT

    = 4200 * 0.021 * 1/6 = 14.7

Amount = P + I = 4200 + 14.7  = 4214.7

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The solution of the system of equations will be (2, 8).

What is substitution method?

To find the value of any one of the variables from one equation in terms of the other variable is called the substitution method.

Given that;

The system of equations are,

y = 4x

And, y = 3x + 2

Now,

Solve the linear equations as;

The system of equations are,

y = 4x      .... (i)

y = 3x + 2   .. (ii)

Substitute y = 4x in equation (ii) as;

y = 3x + 2

4x = 3x + 2

4x - 3x = 2

x = 2

And, y = 4x

y = 4 × 2

y = 8

Thus, The solution of the system of equations will be (2, 8).

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Answer:

Step-by-step explanation:

The white box is a rectangle with width of:

a = 2 m

and length of:

b = 7 m - 1 m = 6 m

So its area is  A = 2 m × 6 m = 12 m²

{The shaded blue area is: (5 m + 1 m)(8 m) - 12 m² = 48 m² - 12 m² = 36 m²}

Answer:

Step-by-step explanation:

As it is impossible to understand who have done what ,

the correct construction should be :

You are given point A, point B and point C.

Construct a line parallel to that line AB passing through point C.

1) Place the compass on point B, and swing an arc that crosses line AB and line BC.

  Label the points D and E.

2) Keep the compass at the same width, and place it on point C.

3) Swing an arc that crosses line BC, and label the point F outside the segment [BC] .

4) Open the compass to the width between points D and E.

  Keeping the compass at the same width, place it on point F.

5) Swing an arc that intersects the arc created from line BC at point C.

6) Mark the intersection of the two arcs as point G.

7) Draw a line through point C and point G.

You just have to discover who has done that.

a Probability that Upper X 0.0013 ,

b. Upper X less than 80 is 0.0228

c  Upper X less than 95 or Upper X greater than 125 is 0.6853.

d 99% of the values are between 76.7 and 123.3 (symmetrically distributed around the mean).

Given a normal distribution with mu equals 100 and sigma equals 10, we can use the cumulative standardized normal distribution table to complete the following parts:

a. What is the probability that Upper X greater than 70?
Using the cumulative standardized normal distribution table, we find the z-score for 70 as (70-100)/10 = -3. We then look up the probability for a z-score of -3, which is 0.0013. Therefore, the probability that Upper X greater than 70 is 0.0013. (Round to four decimal places as needed.)

b. What is the probability that Upper X less than 80?
Using the cumulative standardized normal distribution table, we find the z-score for 80 as (80-100)/10 = -2. We then look up the probability for a z-score of -2, which is 0.0228. Therefore, the probability that Upper X less than 80 is 0.0228. (Round to four decimal places as needed.)

c. What is the probability that Upper X less than 95 or Upper X greater than 125?
Using the cumulative standardized normal distribution table, we find the z-score for 95 as (95-100)/10 = -0.5 and the z-score for 125 as (125-100)/10 = 2.5. We then find the probabilities for each of these z-scores, which are 0.3085 and 0.0062, respectively. To find the probability that Upper X is either less than 95 or greater than 125, we add these two probabilities and subtract from 1 (to account for the overlap): 1 - (0.3085 + 0.0062) = 0.6853. Therefore, the probability that Upper X less than 95 or Upper X greater than 125 is 0.6853. (Round to four decimal places as needed.)

d. 99% of the values are between what two X-values (symmetrically distributed around the mean)?
To find the z-score corresponding to the 99th percentile, we look up the probability of 0.99 in the cumulative standardized normal distribution table, which is 2.33 (rounded to two decimal places). Using this z-score, we can find the corresponding X-values using the formula z = (X - mu)/sigma. Solving for X, we get: X = z*sigma + mu = (2.33)(10) + 100 = 123.3 and X = (-2.33)(10) + 100 = 76.7. Therefore, 99% of the values are between 76.7 and 123.3 (symmetrically distributed around the mean).

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The graph is in the attached image.

Answer:

500 feet brainliest please

Step-by-step explanation:

Answer:

is there any more context?

Step-by-step explanation:

Answer:

53.130°

Step-by-step explanation:

tan(x)=16/12

x is used in replacement of theta symbol

Answer:

0.63 is your answer.

Step-by-step explanation:

7/9

= 0.63

Answer:

a number

Step-by-step explanation:

not a letter

Answer:

28

Step-by-step explanation:

90 - 62 = 28

Answer:

28

Step-by-step explanation:

hence it forms 90degree 90-62=28

To find the parametric equations for the tangent line, we need to find the derivative of the given parametric equations and evaluate it at the specified point:

x'(t) = 2t, y'(t) = 1/(t^2 + 15), z'(t) = 1

x'(4) = 8, y'(4) = 1/31, z'(4) = 1

So the direction vector of the tangent line is <8, 1/31, 1>.

To find a point on the tangent line, we can use the given point (4, ln(16), 1) as it lies on the curve.

Therefore, the parametric equations for the tangent line are:

x(t) = 4 + 8t
y(t) = ln(16) + (1/31)t
z(t) = 1 + t

Note that we can also write the parametric equations in vector form as:

r(t) = <4, ln(16), 1> + t<8, 1/31, 1>
To find the parametric equations for the tangent line to the curve at the specified point (4, ln(16), 1), we need to find the derivative of x(t), y(t), and z(t) with respect to the parameter t, and then evaluate these derivatives at the point corresponding to the given parameter value.

Given parametric equations:
x(t) = t^2 + 15
y(t) = ln(t^2 + 15)
z(t) = t

First, find the derivatives:
dx/dt = 2t
dy/dt = (1/(t^2 + 15)) * (2t)
dz/dt = 1

Now, find the value of t at the specified point. Since x = 4 and x(t) = t^2 + 15, we can solve for t:
4 = t^2 + 15
t^2 = -11
Since there's no real value of t that satisfies this equation, it seems there's an error in the given point or equations. Please verify the given information and try again.

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The statement that "the tribe is the οldest sοciοpοlitical type; the tribe predates the state" is a widely accepted view in anthrοpοlοgy and archaeοlοgy.

It suggests that human sοcieties evοlved frοm smaller, kinship-based grοups knοwn as tribes befοre transitiοning tο larger, centralized fοrms οf pοlitical οrganizatiοn knοwn as states.

Tribes are characterized by a clοse-knit sοcial structure based οn kinship ties, with members sharing cοmmοn ancestry and οften living in smaller, decentralized cοmmunities. Tribal sοcieties typically have egalitarian sοcial structures, with leadership based οn kinship οr achieved status rather than fοrmal hierarchical systems.

As human sοcieties evοlved, sοme tribes eventually develοped intο states, which are characterized by centralized pοlitical authοrity, fοrmal legal systems, and defined territοrial bοundaries. States οften have mοre cοmplex sοcial hierarchies, specialized institutiοns, and a mοnοpοly οn the use οf fοrce.

The transitiοn frοm tribes tο states is believed tο have οccurred gradually οver thοusands οf years, as human pοpulatiοns grew and interactiοns between grοups increased. The emergence οf agriculture, surplus prοductiοn, and the need fοr larger-scale gοvernance are οften cited as factοrs cοntributing tο the develοpment οf states.

While the specific timeline and prοcesses οf this transitiοn are still subjects οf οngοing research and debate, it is generally accepted that tribal sοcieties predate the develοpment οf states in human histοry.

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Answer: FV = $13,961,371.83 The phrase "compounded continuously" has nothing to do with when the interest was compounded but refers to how the annual rate was miscalculated by multiplying an interval rate by the number of intervals in a year. Such rates are called "nominal" rates as they are known to be incorrect but close. A compounded continuosly rate is the worse that such a rate could be from the true rate and is when the number of intervals is infinite. Basically 5% per annum compounded continuously is really more like 5.1271% per annum.

Step-by-step explanation:

By answering the presented question, we may conclude that equation Asymptotes: y = ±(3/9)x and y = ±(-3/9)x, which simplify to y = ±(1/3)x and y = ∓(1/3)x. and The hyperbola opens Vertically.

In mathematics, an equation is a statement that states the equivalence of two expressions. An equation is made up of two sides separated by an algebraic equation (=). For example, the argument "2x + 3 = 9" contends that the phrase "2x + 3" equals the number "9." The purpose of equation solving is to identify the value or values of the variable(s) that will make the equation true. Simple or complicated equations, regular or nonlinear, with one or more components are all possible. For example, in the equation\("x2 + 2x - 3 = 0,\)" the variable x is raised to the second power. Lines are utilized in many areas of mathematics, including algebra, calculus, and geometry.

Center: (0,0)

Transverse axis length: 2a = 2*3 = 6

Conjugate axis length: 2b = 2*9 = 18

Vertices: (0,±3)

Foci: (0,±√18)

Asymptotes: y = ±(3/9)x and y = ±(-3/9)x, which simplify to y = ±(1/3)x and y = ∓(1/3)x.

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Answer:

C.

Step-by-step explanation:

Hope this helps.

Answer:

rational

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

Answer:

They are both correct

Step-by-step explanation:

We can test by plugging 5 in for x, and 15 in for y.

Jared:

Nicole:

Equations are equal.

By evaluating both side of divergence theorem for cube define by -0.1< x,y,z < 0.1 if D = 6x\(e^{2y}(\bar a_x+x\bar a_y)\) will get \(\int\limits^._ v\triangle .D dv=0.0481\).

Given that,

We have to evaluate both side of divergence theorem for cube define by -0.1< x,y,z < 0.1 if D = 6x\(e^{2y}(\bar a_x+x\bar a_y)\)

We know that,

Before solving divergence theorem,

First we need to calculate Δ.D

Where,

Δ.D = del operator

Δ = \((\bar a_x \frac{d}{dx}+ \bar a_y \frac{d}{dy}+ \bar a_z \frac{d}{dz})\)

Then, Δ.D = \((\bar a_x \frac{d}{dx}+ \bar a_y \frac{d}{dy}+ \bar a_z \frac{d}{dz})\)6x\(e^{2y}(\bar a_x+x\bar a_y)\)

We know that dot product of two vector field is valid for same unit vector multiplication.

Δ.D = \(\frac{d}{dx}6xe^{2y}(\bar a_x. \bar a_x)+\frac{d}{dy}6x^2e^{2y}(\bar a_y. \bar a_y)+\frac{d}{dz}(0)\)

Δ.D = 6\(e^{2y}+12x^2e^{2y}\)

Now, using divergence theorem,

\(\int\limits^._ v\triangle .D dv=\int\limits^{0.1}_{x=-0.1}\int\limits^{0.1}_{y=-0.1}\int\limits^{0.1}_{z=-0.1}{\triangle.D} \, dx dydz\)

\(\int\limits^._ v\triangle .D dv=\int\limits^{0.1}_{x=-0.1}\int\limits^{0.1}_{y=-0.1}\int\limits^{0.1}_{z=-0.1}{(6e^{2y}+12x^2e^{2y})} \, dx dydz\)

\(\int\limits^._ v\triangle .D dv=\int\limits^{0.1}_{x=-0.1}\int\limits^{0.1}_{y=-0.1}{(6e^{2y}+12x^2e^{2y})} [z]^{0.1}_{z=-0.1}\, dx dy\)

\(\int\limits^._ v\triangle .D dv=(0.2)\int\limits^{0.1}_{x=-0.1}\int\limits^{0.1}_{y=-0.1}{(6e^{2y}+12x^2e^{2y})}\, dx dy\)

\(\int\limits^._ v\triangle .D dv=(0.2)\int\limits^{0.1}_{x=-0.1}{(\frac{6e^{2y}}{2}+\frac{12x^2e^{2y}}{2})^{0.1}_{y=-0.1}}\, dx\)

\(\int\limits^._ v\triangle .D dv=(0.2)\int\limits^{0.1}_{x=-0.1}{[3e^{2(0.1)}+6x^2e^{2(0.1)}-3e^{2(0.1)}-6x^2e^{2(0.1)}]\, dx\)

\(\int\limits^._ v\triangle .D dv=(0.2)\int\limits^{0.1}_{x=-0.1}{[3+6x^2]e^{(0.2)}- [3+6x^2]e^{(-0.2)}\, dx\)

\(\int\limits^._ v\triangle .D dv=(0.2){[(3x+\frac{6x^3}{3})e^{(0.2)}- (3x+\frac{6x^3}{3})e^{(-0.2)}]^{0.1}_{x=-0.1}\, dx\)

\(\int\limits^._ v\triangle .D dv=(0.2){[(3(0.1)+\frac{6(0.1)^3}{3})e^{(0.2)}]- [(3(0.1)\frac{6(0.1)^3}{3})e^{(-0.2)}]\) \(-[(3(-0.1)+\frac{6(-0.1)^3}{3})e^{(0.2)}]+ [(3(-0.1)\frac{6(-0.1)^3}{3})e^{(-0.2)}]\)

\(\int\limits^._ v\triangle .D dv=(0.2){[(0.3+0.002)\times 2\times e^{0.2}-(0.3+0.002)\times 2\times e^{-0.2}]\)

\(\int\limits^._ v\triangle .D dv=(0.2)[0.735-0.4945]\)

\(\int\limits^._ v\triangle .D dv=(0.2)(0.2405)\)

\(\int\limits^._ v\triangle .D dv=0.0481\)

Therefore, By evaluating both side of divergence theorem for cube define by -0.1< x,y,z < 0.1 if D = 6x\(e^{2y}(\bar a_x+x\bar a_y)\) will get \(\int\limits^._ v\triangle .D dv=0.0481\).

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The question is incomplete the complete question is -

Evaluate both side of divergence theorem for cube define by -0.1< x,y,z < 0.1 if D = 6x\(e^{2y}(\bar a_x+x\bar a_y)\)

Answer:

---------------------

The angle formed by a tangent and secant is half the difference of the intercepted arcs:

Find the measure of ∠MLJ by substituting 4 for x in the angle measure:

Answer:

(a) 2.22

(b) 1.3986

(c) 1.183

Step-by-step explanation:

Let X denote the number of women who consider themselves fans of professional baseball.

The proportion of women who consider themselves fans of professional baseball is, p = 0.37.

A random sample of n = 6 women are selected and each was asked if she considers herself a fan of professional baseball.

Each woman's reply is independent of the others.

The random variable X thus follows a binomial distribution with parameters n = 6 and p = 0.37.

(a)

Compute the mean of the binomial distribution as follows:

\(\text{Mean}=np=6\times 0.37=2.22\)

(b)

Compute the variance of the binomial distribution as follows:

\(\text{Variance}=np(1-p)=6\times 0.37\times (1-0.37)=1.3986\)

(c)

Compute the standard deviation of the binomial distribution as follows:

\(\text{Standard Deviation}=\sqrt{np(1-p)}=\sqrt{6\times 0.37\times (1-0.37)}=1.183\)