the terminal voltage of a power supply is 24 v (dc) before a load is applied. when a 100 w resistor is connected to the power supply, the voltage drops to 22 v. what is the internal resistance of the power supply

The time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

The cooling law is given by:

$$\frac{dQ}{dt}=-k(T-T_0)$$

where Q is the heat in the object, t is the time taken, T is the temperature of the object at time t, T0 is the temperature of the environment and k is a constant known as the cooling constant.

We need to find the time it takes for the coffee to reach a drinking temperature of 73°C given that its initial temperature is 93°C.

Therefore, we need to find the time it takes for the coffee to cool down from 93°C to 73°C when placed in a room temperature of 18°C.

Let’s assume that the heat energy that is lost by the coffee is equal to the heat energy gained by the environment. We can express this as:

dQ = - dQ where dQ is the heat energy gained by the environment.

We can substitute dQ with C(T-T0) where C is the specific heat capacity of the object.

We can rearrange the equation as follows:

$$-\frac{dQ}{dt}=k(T-T_0)$$

$$-\frac{d}{dt}C(T-T_0)=k(T-T_0)$$

$$\frac{d}{dt}T=-k(T-T_0)$$

The differential equation above can be solved using separation of variables as follows:

$$\frac{d}{dt}\ln(T-T_0)=-k$$

$$\ln(T-T_0)=-kt+c_1$$

$$T-T_0=e^{-kt+c_1}$$

$$T=T_0+Ce^{-kt}$$

where C = e^(c1).

We can now use the values given to find the specific value of C which is the temperature difference when t=0, that is, the temperature difference between the initial temperature of the coffee and the room temperature.

$$T=T_0+Ce^{-kt}$$

$$73=18+C\cdot e^{-0.09t}$$

$$55=C\cdot e^{-0.09t}$$

$$C=55e^{0.09t}$$

$$T=18+55e^{0.09t}$$

We can now solve for the value of t when T=93 as follows:

$$93=18+55e^{0.09t}$$

$$e^{0.09t}=\frac{93-18}{55}$$

$$e^{0.09t}=1.3636$$

$$t=\frac{\ln(1.3636)}{0.09}$$

Using a calculator, we can find that the time taken for the coffee to cool from 93°C to 73°C is approximately 36.1 minutes.

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Momentum, a property of moving objects that measures their propensity to continue travelling in the same direction, is equal to their mass times their velocity.

You can use the momentum equation, p = mv, where p seems to be the momentum, m the mass, & v is the velocity, to determine the mass & velocity when you only have the momentum. You may rewrite this equation to find the mass or velocity if you know the momentum m = p / v  and v = p / m

The word employed to denote the state of the motion of a thing with a mass greater than zero is momentum. As a result, momentum can be applied to every moving object.

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Answer:

the charges get closer together

Perception refers to the process of interpreting and organizing sensory information received from the environment. It involves the integration of sensations with prior knowledge, expectations, and other contextual factors to form a meaningful experience.

The primary difference between perception and sensation is that sensation refers to the physical experience of detecting stimuli through the sensory organs, while perception involves the cognitive interpretation and processing of that sensory information. Sensation is the first step in the process of perception, as it provides the raw data that is then interpreted by the brain. In other words, sensation is the primary sensory experience, while perception is the cognitive understanding and interpretation of that experience.

Perception refers to the process of interpreting and organizing sensory information, enabling us to recognize meaningful objects and events. Sensation, on the other hand, is the process of receiving raw sensory data from the environment through our sense organs. The primary difference between perception and sensation is that sensation involves the collection of sensory information, while perception is the interpretation and understanding of that information.

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\({ \purple{ \tt{Here \: is \: your \: answer...}}}\)

Umm it's quiet difficult to understand. But let us note down the given values.

\({ \green{ \tt{given : - }}}\)

\({ \red{ \tt{ λ = 5000 \times {10}^{ - 10} m}}}\)

\({ \red{ \tt{ λ = 5 \times {10}^{ - 7}m}}} \)

\({ \red{ \tt{ \beta = 0.6cm = 6 \times {10}^{ - 3} m}}}\)

\({ \red{ \tt{D' = \frac{D}{2}}}}\)

\({ \red{ \tt{ \beta' = 0.003m = 3 \times {10}^{ - 3}m}}}\)

Answer:

Argon is the third most abundant gas in our atmosphere, making up about one percent in terms of moles of gas.

Explanation:

Roughly, our atmosphere is 78% nitrogen, 21% oxygen, 1% argon, and trace amounts of many other gases plus variable amounts of water vapor.

The diameter of the X-ray source, calculated based on a flickering frequency of 200 cycles per second, is approximately 2.53 × 10⁻¹⁷ kilometers.

To calculate the diameter of the X-ray source, we need to utilize the concept of the diffraction limit. The diffraction limit states that the smallest resolvable detail in an image is determined by the wavelength of the radiation and the aperture size of the instrument.

In this case, since we are dealing with X-rays, which have a very short wavelength, we can assume that the diffraction limit is governed by the size of the X-ray source itself. The formula for the diffraction limit is given by:

θ = λ / D

Where θ is the angular resolution, λ is the wavelength of the radiation, and D is the diameter of the source.

To calculate the diameter, we rearrange the formula:

D = λ / θ

Since the flickering frequency is given as 200 cycles per second, which corresponds to 200 oscillations in one second, we can determine the angular resolution as:

θ = 2πf

Where f is the frequency. Substituting the values into the equation, we have:

θ = 2π * 200 = 400π radians per second

Assuming an X-ray wavelength of approximately 0.01 nm, or 10⁻¹¹ meters, we can calculate the diameter as:

D = (10⁻¹¹ m) / (400π rad/s) ≈ 2.53 × 10⁻¹⁴ meters

Converting this to kilometers, we find that the diameter of the X-ray source is approximately 2.53 × 10⁻¹⁷ kilometers.

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Answer:

\(60^{\circ}\) (assuming that air resistance is negligible.)

Explanation:

Let \(g\) denote the gravitational field strength. If air resistance on the projectile is negligible:

Let \(\theta\) denote the angle at which the projectile is launched. Let \(v\) denote the initial velocity of the projectile:

Also because air resistance is negligible, vertical velocity of the projectile will be \(v_{y} = (-u_{y}) = (-v\, \sin(\theta))\) right before the projectile lands. In other words, while the projectile was in the air, the change in vertical velocity would be \((-v\, \sin(\theta)) - (v\, \sin(\theta)) = (-2\, v\, \sin(\theta))\).

Divide the change in velocity by acceleration to find the duration of the flight:

\(\begin{aligned}t &= \frac{v_{y} - u_{y}}{a_{y}} \\ &= \frac{(-v\, \sin(\theta)) - (v\, \sin(\theta))}{(-g)} \\ &= \frac{(-2\, v\, \sin(\theta))}{(-g)} \\ &= \frac{2\, v\, \sin(\theta)}{g}\end{aligned}\).

Range measures the horizontal distance that this projectile has travelled. At a constant horizontal velocity of \(u_{x} = v\, \cos(\theta)\), this projectile would travel a distance of:

\(\begin{aligned}(\text{range}) &= u_{x}\, t \\ &= (v\, \cos(\theta))\left(\frac{2\, v\, \sin(\theta)}{g}\right) \\ &= \frac{2\, v^{2}\, \sin(\theta)\, \cos(\theta)}{g}\end{aligned}\).

Apply the double angle identity \(2\, \sin(\theta) \, \cos(\theta) = \sin(2\, \theta)\) to further simplify this expression:

\(\begin{aligned}(\text{range}) &= \cdots \\ &= \frac{2\, v^{2}\, \sin(\theta)\, \cos(\theta)}{g} \\ &= \frac{v^{2}\, (2\, \sin(\theta)\, \cos(\theta))}{g} \\ &= \frac{v^{2}\, \sin(2\, \theta)}{g}\end{aligned}\).

Note that in this question, \(v^{2}\) and \(g\) are both constant. Hence, for another angle of elevation \(\hat{\theta}\), the range of the projectile will be the same as long as \(\sin(2\, \hat{\theta}) = \sin(2\, \theta)\).

\(\sin(2\, \hat{\theta}) = \sin(2\, (30^{\circ}))\).

Since \(0^{\circ} \le \hat{\theta} \le 90^{\circ}\), \(0^{\circ} \le 2\, \hat{\theta} \le 180^{\circ}\):

\(\sin(2\, \hat{\theta}) = \sin(180^{\circ} - 2\, \hat{\theta}) = \sin(2\, (90^{\circ} - \hat{\theta}))\).

Therefore, \(\hat{\theta} = 90^{\circ} - \theta = 90^{\circ} - 30^{\circ} = 60^{\circ}\) will ensure that \(\sin(2\, \hat{\theta}) = \sin(2\, \theta)\). Launching the projectile at \(60^{\circ}\) will reach the same range.

\(\begin{aligned}(\text{new range}) &= \frac{v^{2}\, \sin(2\, (60^{\circ}))}{g} \\ &= \frac{v^{2}\, \sin(2\, (30^{\circ}))}{g} = (\text{original range})\end{aligned}\).

Answer: B

Explanation: Materials that allow electricity to pass through them are called conductors.

The main difference between Kinetic energy and Potential energy is that kinetic energy refers to movement while potential energy refers to storage.

Kinetic energy is a type of energy in motion or energy in movement such as a turbine (mechanical energy), while Potential energy refers to the energy that is stored to be used when required (e.g. chemical bonds of foods).

Therefore, with this data, we can see that  Kinetic energy is used as movement, while Potential energy is stored to be used in the future.

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When the planet Mars is, on average, about 228 million km from the Sun, the correct option is about 1.52 hours.

The time it takes light from the Sun to reach Mars when the planet Mars is, on average, about 228 million km from the Sun is about 12.7 minutes.

The given question can be solved using the formula; Time = Distance / Speed of light

Given that Distance of Mars from the Sun = is 228 million km

The speed of light = 300,000 km/sNow, let's plug in the values in the formula.

Time = Distance / Speed of light = 228 × 106 km / 300,000 km/s = 760 secondsTherefore, the time taken for light to reach Mars from the Sun is 760 seconds.1 hour is equal to 3600 seconds.

Therefore, the time taken for light to reach Mars from the Sun is about 760 / 3600 hours = 0.21 hours or about 1.52 hours.

Hence, the correct option is about 1.52 hours.

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The weight of the air above us causes air pressure. The right answer is (a).

Atmospheric air pressure is the weight of the surrounding atmosphere. A barometer is a tool used to gauge atmospheric pressure. One of the earliest types of traditional barometers is the mercury barometer. The standard unit of measurement for atmospheric pressure in public weather reporting is inches of mercury. At sea level, the average pressure is over 30 inches of mercury (about 76 cm of mercury). Winds are produced as air masses move from locations of higher pressure to areas of lower pressure. As a result, air pressure results from the weight of the air above it. Consequently, the appropriate choice is (a)

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The magnitude of the magnetic field at the point at the center of a long, straight solenoid if the solenoid carries a current of 0.300 A and has 4.00 ×10³ windings per meter would be 1.512 ×10⁻³ N/Amps m

A magnetic field could be understood as an area around a magnet, magnetic material, or an electric charge in which magnetic force is exerted. The SI unit of the magnetic field is tesla.

The magnetic field at the point at the center of a long, straight solenoid can be calculated by using the formula

B = μnI

where B is the magnetic field

μ is the Permeability constant having a value of 1.26 × 10⁻⁶ T/m

n is the number of winding per meter

I represent the current

By substituting the respective value in the formula

B=( 1.26 × 10⁻⁶ )×  (4.00 ×10³)×0.300

B =1.512 ×10⁻³ N/Amps m

Thus, the magnitude of the magnetic field at the point at the center of a long, straight solenoid would be 1.512 ×10⁻³ N/Amps m.

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Match the volcano type with its correct

1. Cinder Cone:

Plate Tectonic Setting: Mostly Spreading Ridges, some Mantle Plumes

2. Composite/Stratovolcano:

Plate Tectonic Setting: Subduction Zones (Convergent Margins)

3. Shield Volcano:

Plate Tectonic Setting: Mostly Mantle Plumes, some Spreading Ridges

4. Large Igneous Provinces (LIPs):

Plate Tectonic Setting: Various tectonic settings

Volcano types can be associated with specific plate tectonic settings and magma compositions. Let's match the volcano types with their correct plate tectonic settings and magma compositions:

1. Cinder Cone:

Plate Tectonic Setting: Mostly Spreading Ridges, some Mantle Plumes

Magma Composition: Mafic

Cinder cones are typically small, steep-sided volcanoes that form from the eruption of basaltic magma. They are commonly found in volcanic regions associated with spreading ridges, where tectonic plates are moving apart, or in areas influenced by mantle plumes, such as hotspot volcanism.

2. Composite/Stratovolcano:

Plate Tectonic Setting: Subduction Zones (Convergent Margins)

Magma Composition: Intermediate, varies from felsic to mafic

Composite or stratovolcanoes are characterized by their steep slopes and alternating layers of lava flows and pyroclastic materials. They are commonly found in subduction zones, where an oceanic plate is being subducted beneath  continental plate. The magma composition of these volcanoes varies, ranging from felsic (high silica content) to mafic (lower silica content).

3. Shield Volcano:

Plate Tectonic Setting: Mostly Mantle Plumes, some Spreading Ridges

Magma Composition: Mafic

Shield volcanoes are large, broad, and gently sloping volcanoes that form from the eruption of basaltic magma. They are often associated with mantle plumes, such as those found in hotspot regions, as well as in volcanic areas influenced by spreading ridges.

4. Large Igneous Provinces (LIPs):

Plate Tectonic Setting: Various tectonic settings

Magma Composition: Mafic

Large Igneous Provinces (LIPs) are extensive regions of volcanic and intrusive rock formations that are associated with massive outpourings of mafic magma. They can occur in various tectonic settings, including continental rifts, hotspot regions, and flood basalt provinces.

5. Seafloor Volcanism, Pillow Lava:

Plate Tectonic Setting: Mostly Spreading Ridges

Magma Composition: Mafic

Seafloor volcanism is primarily associated with spreading ridges, where magma wells up and creates new oceanic crust. The lava erupted underwater cools rapidly, forming pillow-shaped structures known as pillow lavas. The magma composition is typically mafic, dominated by basaltic lavas.

These associations between volcano types, plate tectonic settings, and magma compositions provide insights into the geological processes and Earth's dynamics that shape the Earth's surface.

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Answer:

F • t = m • Δ v

Explanation:

By the velocity, they will travel 6.875 m and the dog catches the man at 2.08s.

We need to know about velocity to solve this problem. Velocity can be determined as the distance traveled divided by time interval. It can be written as

v = s / t

where v is velocity, s is distance and t is the time interval.

From the question above, we know that.

v man = 1.5 m/s

v dog = 3.3 m/s

to = 2.5s

Determine the distance traveled by man when the dog waits

so = vman . to

so = 1.5 x 2.5 = 3.75 m

Find the man's total distance

total distance = distance after dog run + distance when the dog waits

total distance = vman . t + 3.75

We know that the total distance by man's will be caught by the dog, Thus

total distance = vman . t + 3.75

v dog . t = 1.5t + 3.75

3.3t = 1.5t + 3.75

1.8t = 3.75

t = 2.08 s

Find total distance

total distance = vdog . t

total distance = 3.3 x 2.08

total distance = 6.875 m

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The catch in this one is:  We don't know how much force the student used to push the bike.  

It wasn't necessarily the 100N.  That's just the weight of the bike. But you know that you can push a car, a wagon, or a bicycle hard, you can push it not so hard, you can give it a little push, you can give it a big push, you can push it strong, you can push it weak, you can push it medium.  The harder you push, the more it'll accelerate, but it's completely up to you how hard you want to push.  That's what's so great about wheels !  That's why they were such a great invention ! This is where I made my biggest mistake. This guy came into my store one day and said he's got this great invention, it's definitely going to take off, it'll be a winner for sure, he called it a "wheel".  I looked at it, I turned it over and I looked on all sides. I thought it was too simple.  I didn't know then it was elegant. I threw him out.  I was so dumb.  I could have invested money in that guy, today I would have probably more than a hundred dollars.

Anyway, can we figure out how much force the student used to push with ?  Stay tuned:

-- The bike covered 15 meters in 5 seconds.  Its average speed during the whole push was (15m/5s) = 3 meters/sec.

-- If the bike started out with no speed, and its average speed was 3 m/s, then it must have been moving at 6 m/s at the end of the push.

-- If its speed increased from zero to 6 m/s in 5 seconds, then its acceleration was (6m/s / 5 sec) = 1.2 m/s²

-- The bike's weight is 100N.  

(mass) x (gravity) = 100N

Bikemass = (100N) / (9.8 m/s²)

Bikemass = 10.2 kilograms

-- F = m A

Force = (mass) x (acceleration)

Force = (10.2 kg) x (1.2 m/s²)

Force = 12.24 N

-- Work = (force) x (distance)

Work = (12.24 N) x (15 m)

Work = 183.67 Joules

-- Power = (work done) / (time to do the work)

Power = (183.67 joules) / (5 seconds)

Power = 36.73 watts

The frequency you hear if the cop was driving away from you at a speed of 25 m/s is  652 Hz. The correct option is C.

It is the number of oscillations per second of the sinusoidal wave.

A cop car’s siren has a frequency of 700. H z. If you are standing on the sidewalk as the cop car approaches you at a speed of 15.0 m/ s.

The cop was driving away from you at a speed of 25 m/s. The speed of sound is 343 m/ s.

The frequency you hear will be calculated using the following formula

f' = f(Vs - Vo)/(Vs +Vc)

Substitute the values into the above equation, we get

f' = 700 x (343 - 0) / (343 + 25)

f' = 652.45 Hz

or f' = 652 Hz

Thus, the frequency you hear when the cop is driving away is  652 Hz.

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For the first two minutes of flight, the Solid Rocket Boosters (SRBs) run concurrently with the main engines to supply the extra thrust required for the Orbiter to escape the Earth's gravity.

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Answer:

5738929292

Explanation:

simple math

A. Tensional stress - 1. Normal fault

B. Compressional stress - 2. Reverse fault

C. Shear stress - 3. Strike-slip fault

Explanation:

A. Tensional stress is a type of stress that pulls or stretches rocks apart. It occurs when forces act in opposite directions, causing the rocks to be pulled apart. This type of stress is associated with the stretching and thinning of the Earth's crust. The movement caused by tensional stress is vertical and in opposite directions.

1. Normal fault: A normal fault is formed when tensional stress causes the hanging wall to move downward relative to the footwall. The movement is caused by the rocks being pulled apart along a inclined fault plane. The result is a vertical displacement where the hanging wall moves down relative to the footwall.

B. Compressional stress is a type of stress that pushes rocks together. It occurs when forces act in the same direction, compressing the rocks. This type of stress is associated with the shortening and thickening of the Earth's crust. The movement caused by compressional stress is also vertical.

2. Reverse fault: A reverse fault is formed when compressional stress causes the hanging wall to move upward relative to the footwall. The movement is caused by the rocks being pushed together along an inclined fault plane. The result is a vertical displacement where the hanging wall moves up relative to the footwall.

C. Shear stress is a type of stress that causes rocks to slide past each other horizontally. It occurs when forces act parallel to each other but in opposite directions, causing the rocks to shear. The movement caused by shear stress is horizontal and in opposite directions.

3. Strike-slip fault: A strike-slip fault is formed when shear stress causes the rocks on either side of the fault to slide horizontally past each other. The movement is caused by the rocks shearing along a nearly vertical fault plane. The result is a horizontal displacement where the rocks move past each other horizontally.

By considering the direction of movement caused by the stress, we can match each type of stress to its corresponding type of fault.

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Answer:

M = 1.994 × 10^(30) kg

Explanation:

We are given;

Orbital radius; r = 1.5 × 10^(8) km = 1.5 × 10^(11) m

Gravitational constant; G = 6.67 × 10^(-11) N.m²/kg²

If the orbit is circular, the it means the gravitational force is equal to the centripetal force.

Thus; F_g = F_c

GMm/r² = mv²/r

Simplifying gives;

GM/r = v²

M = v²r/G

Now, v is the speed of the earth around the sun and from online sources it has a value of around 29.78 km/s = 29780 m/s

Thus;

M = (29780^(2) × 1.5 × 10^(11))/6.67 × 10^(-11)

M = 1.994 × 10^(30) kg

c is the correct answer ......... if we cut a magnet i will divide into two halves and ecah half have a southpole and northpole.

Hope it helps

When a bar magnet is cut in half, each half has both a north pole and a south pole. Therefore, option C is correct.

This phenomenon is due to the rearrangement of magnetic domains within the material. The newly formed magnets will have a north pole on one end and a south pole on the other end. This process can be repeated, resulting in smaller and smaller magnets, but each piece will always exhibit both north and south poles.

The magnetic properties are retained even when the magnet is divided into smaller segments. Each half of the magnet becomes a new magnet with its own north and south pole.

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Answer:

Explanation:

F = m * a

The apple's acceleration is not influenced by the acceleration due to gravity for this question.  In real life it most certainly is influenced by gravity.

F = m * a

F = 10 Newtons.

a = 6 m/s^2

m = 10/6 = 1.66 kg. Mighty  large apple

Part 1: The number of pathways in a circuit determines the possible routes for electric current to flow.

There are maximum of five pathways in this circuit, depending on its complexity and the arrangement of components.

Part 2: Determining whether the circuit is series or parallel requires more information.

In a series circuit, components are connected in a single path, and the current flows through each component sequentially.

If the circuit has only one pathway (zero or one pathway), it suggests a series circuit.

However, if the circuit has multiple pathways (two or more pathways), it indicates a parallel circuit.

To conclusively determine the circuit's nature, we need to analyze the circuit diagram or obtain additional details regarding the component connections and their interactions.

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Answer:

force×distance

Explanation:

work is the ability of an object to move a distance as a result of the force being applied

The accumulation of electric charges on an object is referred to as static electricity.

Static electricity is an imbalance of electric charges on an object, which can cause it to become charged and attract or repel other objects with opposite or similar charges, depending on the charge's polarity. Positive charges attract negative charges, and vice versa. When an object becomes charged, it is referred to as an electrostatic charge.
Static electricity can occur in a variety of circumstances, including friction, induction, and conduction. When two objects rub against one another, they can exchange electrons, causing one object to become positively charged and the other negatively charged. Induction occurs when an object with a positive charge comes into close proximity to an object with a negative charge, causing electrons to move between the two objects. Conduction occurs when an object with a charge comes into direct contact with another object, causing the charge to be transferred.
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Answer:

Explanation:

A - 4.5