the two wires are made of the same material. what are the current and the electron drift speed in the 2.0 mm diameter segment of the wire
Answers
The current flowing in the 2.00 mm diameter segment of the wire is 2.56L × 10⁻² A and the electron drift speed in the 2.00 mm diameter segment of the wire is 0.028 m/s.
Electric Current: The movement of electrons constitutes an electric current. It is measured in amperes (A).
Electron Drift Speed: When an electric field is applied to a metal wire, the electrons within the wire move in response to the field.
The average speed of electrons in the metal wire is known as electron drift speed. It is given by = I / (nAq),
Where, n is the number of electrons per unit volume of the conductor,
A is the cross-sectional area of the conductor, and
q is the charge on an electron.
Given data shows that both wires are made of the same material so the material properties (number density of electrons, atomic properties) are constant for both wires.
Hence, the electron drift speed in both wires would be the same. Let’s say the current flowing in both wires is I1 and I2 respectively and the diameter of the wire is 2.00mm or radius R = 1.00mm.
According to Ohm’s Law = the resistance of the wire can be expressed as R = ρL / A
where ρ is the resistivity of the wire,
L is the length of the wire, and
A is the cross-sectional area of the wire.
The cross-sectional area of the wire can be written as = πR²
Now combining both equations of resistance and the cross-sectional area we get,
R = ρL / πR²Now, I = V / R
So, I = V πR² / ρL
The current density can be written as J = I / A = V πR² / ρL πR²
Now we can express V as J ρL = I
Substitute the given values,
Current density J = 3.00 × 10⁶ A/m²ρ = 2.70 × 10⁻⁸ Ωm
Diameter of wire = 2.00mm
Therefore, the radius of wire = R = 1.00 mm = 1.00 × 10⁻³ m
Using the given formula, I = J πR²ρLSo, I = 3.00 × 10⁶ × π × (1.00 × 10⁻³)² × 2.70 × 10⁻⁸ × L = 2.56 L × 10⁻² A
The electron drift speed can be written as, v = I / (nAq)
Let’s say the number of electrons per unit volume of the conductor is n, the electron charge be q and
the length of the wire be L.
Then, L × πR² × nq = where m is the mass of the conductor.
L × πR² × nq = ρV
Where ρ is the density of the conductor and
V is the volume of the conductor.
So, V = πR²Lρ And, L × πR² × nq = ρπR²L
Therefore, nq = ρ
The electron drift velocity is given as,v = I / (nAq)So, v = I / (n × πR² × q)
The number density of electrons n can be expressed as = N / V
Where N is the total number of electrons in the conductor.
Substituting the given values,
Number density n = 8.49 × 10²⁸ / (π(1.00 × 10⁻³)² × L × 2.70 × 10⁻⁸)
Current I = 2.56L × 10⁻² A
Electron charge q = 1.6 × 10⁻¹⁹ C
Cross-sectional area A = πR²
Where radius R = 1.00mm or R = 1.00 × 10⁻³ m.
Now substituting the above values
we get, v = 2.56L × 10⁻² / (8.49 × 10²⁸ / (π(1.00 × 10⁻³)² × L × 2.70 × 10⁻⁸) × π(1.00 × 10⁻³)² × 1.6 × 10⁻¹⁹)
Hence the electron drift speed can be calculated as v = 0.028 m/s.
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Related Questions
A 15,000 kg rocket traveling at +230 m/s turns on its engines. Over a 6. 0 s period it burns 1,000 kg of fuel. An observer on the ground measures the velocity of the expelled gases to be −1,200 m/s
Answers
First, we need to calculate force of the rocket.
What is Velocity?
Velocity is a vector quantity that describes the rate and direction of a body's motion. It is represented by an arrow pointing in the direction of motion and having a length equal to the rate of motion. Velocity is a fundamental concept in classical mechanics and is defined as the rate of change of position with respect to time.
Calculate the force of the rocket:
F = ma = (15,000 kg)(230 m/s) = 3,450,000 kg m/s2
Calculate the force of the exhaust gases:
F = ma = (1,000 kg)(-1,200 m/s) = -1,200,000 kg m/s2
Calculate the net force on the rocket:
Net Force = F_rocket + F_exhaust = 3,450,000 kg m/s2 + (-1,200,000 kg m/s2) = 2,250,000 kg m/s2
Calculate the acceleration of the rocket:
a = F/m = (2,250,000 kg m/s2)/(15,000 kg) = 150 m/s2
Calculate the change in velocity of the rocket:
Δv = a × t = (150 m/s2)(6.0 s) = 900 m/s.
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A ray gets successively reflected from two mirrors inclined at an angle of 40º. If the angle of incidence on the first mirrors is 60º, then the net deviation of this ray is -
a)40º
b)280º
c)80º
d)160º
Answers
Which would take more force to stop in 10 seconds: an 8.0-kilogram ball rolling in a straight line at a speed of 0.2 m/sec or a 5.0-kilogram ball rolling along the same path at a speed of 1.0 m/sec?
Answers
Answer:
Higher force would be required to stop 5 kg of ball
Explanation:
The force required to stop a moving object depends on its momentum.
The momentum for 8 kg of rolling ball is = 8 kg * 0.2 m/s = 1.6 kgm/s
The momentum for 5 kg of rolling ball is = 8 kg * 1.0 m/s = 5 kgm/s
Hence, momentum of 5 Kg ball is higher than the momentum of 8 Kg of ball
Hence, higher force would be required to stop 5 kg of ball
4. If the circuit below draws a current of 0.195 A, what is the equivalentresistance? Hint: Use Ohm’s law.
Answers
62.53 ohms
Explanation
Ohm's law states that the voltage or potential difference between two points is directly proportional to the current or electricity passing through the resistance, and directly proportional to the resistance of the circuit.
\(\begin{gathered} V=IR \\ so \\ R=\frac{V}{I} \end{gathered}\)then
Step 1
a)let
\(\begin{gathered} V=12.0\text{ v} \\ I=0.195\text{ A} \end{gathered}\)now, replace in the formula
\(\begin{gathered} R=\frac{V}{I} \\ R=\frac{12.0\text{ v}}{0.195\text{ A}} \\ R=62.53\text{ }\Omega \end{gathered}\)therefore, the answer is
62.53 ohms
I hope this helps you
using newton's second law, why does a hunter always presses the butt of a rifle tightly against his shoulder before firing a bullet ?
Answers
Answer:
Below
Explanation:
SO the equal but opposite force of the bullet being fired forward doesn't cause the backward force of the rifle to slam into his shoulder possibly causing injury
A hunter always presses the butt of a rifle tightly against his shoulder before firing a bullet because this causes a change in the momentum of the bullet being fired.
What is Newton's second law of motion?Newton's second law of motion states that the rate of change of momentum of a body is directly proportional to the force which is applied to it and the change in momentum of an object takes place in the direction in which the force is being applied.
The acceleration of an object as produced through a net force is directly proportional to the magnitude of the net force, in the same direction as that of the net force, and inversely proportional to the mass of the object.
The butt of the rifle is pressed tightly against the shoulder of the hunter to cause a change in the momentum of the bullet.
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What is the force two changed objects exert on one another if they are 9 meters apart and one has a charge of 2.5 x 10^-6 C and the second has a charge 0f 4.5 x 10^-7 C
Answers
Answer:
The force exerted between the two charges is 0.0001248N
Explanation:
we will be using Columb's law to solve this problem.
Columb's law explains that the Force between two charged bodies is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.
Mathematically,
\(F = K\frac{Q_1 \times Q_2}{r^2}\)
WHere K = constant of proportionality = \(8.9875 \times 10^9 N m^2/c^2\)
\(F = 8.9875 \times 10^9 \times\frac{2.5 \times10^{-6} \times 4.5 \times 10^{-7}}{9^2}= 0.0001248N\)
The force exerted between the two charges is 0.0001248N
Newton's first law of motion: Objects in motion will stay in motion and objects at rest will stay at rest, unless acted on by
a. friction
b. acceleration
c. unbalanced force
d. contact force
Answers
Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This is normally taken as the definition of inertia
Determine the magnitude of the Coulomb force on the tape using the value of tan θ and your equation from the previous exercise for FCoulomb.FCoulomb = .40 x 10^-3 N
Answers
The magnitude of the Scotch tape is 13 0.05 cm, and the linear mass density (d) is 1.44 0.01 g/m.
Given that the length of the Scotch tape is 13 0.05 cm and the linear mass density (d) is 1.44 0.01 g/m, the answers to the following questions calculate the coulomb force, the number of atoms, and the elementary charges.
where r is the distance between the charges, Q1 and Q2 are the magnitudes of the charges on the two pieces of tape, and k is Coulomb's constant. Given that F Coulomb is equal to 0.40 x 10-3 N, we can use the following equation to find the charge, Q: where is the static friction coefficient, which was determined in the preceding exercise.
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A ray of light strikes a plane mirror at an angle of incidence equal to 35°. The angle between
the incident ray and the reflected ray is
A)
70°
B)
0°
C)
55°
D)
35°
Answers
Answer:
55 degrees
Explanation:
A ray of light strikes a plane mirror at an angle of incidence. The angle between the incident ray and the reflected ray is 70°. The correct option is A.
What is law of reflection?The law states that angle of incidence of the incident ray is equal to the angle of reflection through a plane surface.
Here, angle of incidence of light on a plane mirror is 35°, then the angle of reflection will also be 35°.
i = r = 35°
Then the angle between the incident ray and the reflected ray will be
i +r = 35 + 35 =70°
Thus, the correct option is A.
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A force of 40 N stretches a spring 0.20 m what is the spring
constant?
a. 2000 N/m
b. 200 N/m
c. 20 N/m
d. 2 N/m
Answers
If you put more mass on a cart so it hovers closer to the track, what happens to the magnetic potential energy?
Answers
Answer:If you put more mass on a cart so it hovers closer to the track in a magnetic levitation system, the magnetic potential energy increases. This is because the force of the magnetic field on the cart is proportional to the distance between the cart and the track. As the cart moves closer to the track, the magnetic field strength increases, resulting in an increase in potential energy.
Explanation:
Read this statement: Biotechnology uses primary clarifiers for biological nutrient removal.
Which part of the statement is not true?
Biological nutrients are found in wastewater.
Primary clarifiers remove biological nutrients.
Biological nutrients are part of biotechnology processes.
Biological nutrient removal is part of wastewater management.
Answers
Primary clarifiers removing biological nutrients is not true. Primary clarifiers
involves the use of processes such as sedimentation in order to remove
particles floating or other inorganic solids from the waste water.
Biological nutrients such as nitrogen and phosphorus are found in waste
water and removal of these important nutrients for other uses is a part of
waste water management.
The secondary clarifiers are the ones responsible for the removal of
biological nutrients in the waste water through biofiltration etc.
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A 0.003 kg copper penny drops a distance of 50.0 m to the ground
If 65% of the initial potential energy goes into increasing the
internal energy of the penny, determine the magnitude of the
increase.1
Answers
As per the law of conservation of energy, since the work done on the object is equal to m×g×h, the energy gained by the object = m×g×h, which in this case is the potential energy E.
The force acting on the two objects affects the potential energy formula. The formula for gravitational force is P.E. = mgh, where g is the acceleration caused by gravity (9.8 m/s2 at the earth's surface) and h is the height in metres.
Similar to this, when a spring is moved away from its equilibrium position, it gains some energy, which we can notice by the stress our hands experience when we stretch it. Potential energy is a type of energy that arises from a change in its position or state, according to our definition.
Let's learn the formula, unit, and examples of potential energy after understanding potential energy and what it means.
m is the mass in kilograms
g is the acceleration due to gravity
h is the height in meters
Potential Energy Unit
Gravitational potential energy has the same units as kinetic energy: kg m2 / s2
Note: All energy has the same units – kg m2 / s2, and is measured using the unit Joule (J).
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etsyven with the best and largest telescopes, we can't see all the stars in the milky way galaxy, even though these same telescopes can show us other galaxies. why is that?
Answers
This is because the Milky Way Galaxy is incredibly large and contains an estimated 200-400 billion stars, which is too many to be seen from Earth with the current technology.
Furthermore, the Milky Way is also estimated to be 100,000 light years across, meaning that even if we could see all the stars at once, the distant stars would be too faint to be seen from Earth.
To put it into perspective, if we could see all the stars, it would look like a giant, fuzzy patch of light in the night sky.
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During a baseball game, a batter hits a high
pop-up.
If the ball remains in the air for 5.86 s, how
high above the point where it hits the bat
does it rise? Assume when it hits the ground
it hits at exactly the level of the bat. The
acceleration of gravity is 9.8 m/s².
Answer in units of m
Answers
Answer:
Доброе утро, ответ 5+5="4
Explanation:
describe the importance of measurements in brief.
Answers
Answer:
importance of measurement is it gives proper required amount of anything if it will not exist then alot of work be disrupted .In many work measurement is very necessary like in scientific works
which feedback loop reverses or stops a change? group of answer choices reinforcing reversal balancing charging
Answers
The feedback loop that reverses or stops a change is known as a balancing feedback loop.
A balancing feedback loop usually results in oscillation or movement in the direction of equilibrium. The capacity of the oceans to store heat, which helps keep global temperatures within habitable ranges, is an illustration of a negative, or balancing, feedback loop. The capacity of plants and soil to absorb carbon dioxide and remove it from the atmosphere is another unfavorable feedback loop. A negative feedback loop results in equilibrium. The result of a positive feedback loop is rapid development (or fall). A system with a positive feedback loop may begin close to equilibrium, but with time, it will drift further away from it.
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A car accelerates from 20.0 m/s to 28.0 m/s over a distance of 50.0 m. What is the car’s acceleration?
Answers
Answer:
Explanation:
\(V^2=V^2_o+2a(x_f-x_i)\)
\(28^2=20^2+2a(50)\\784=400+100a\\384=100a\\a=3.84m/s^2\)
A car traveled 210 km in 1.5 hrs, what was the car's average speed?
Answers
Answer:
140km/h
Explanation:
Average speed= Distance/Time
= 210/1.5
= 140 I'm/h
What is a good source of
soluble fiber?
A.Oatmeal
B.Chicken
C.Chocolate chip cookie
D.Waffles
Answers
A. Oatmeal is a great source of soluble fiber. Soluble fiber is a type of fiber that dissolves in water and forms a gel-like substance in the digestive tract. This gel helps slow down digestion, which can help regulate blood sugar levels, lower cholesterol, and promote a feeling of fullness.
Other good sources of soluble fiber include beans, lentils, peas, barley, fruits such as apples and oranges, and vegetables such as carrots and Brussels sprouts. It is recommended to consume at least 25 grams of fiber per day, with at least 10-15 grams coming from soluble fiber.
A good source of soluble fiber is a type of fiber that dissolves in water and forms a gel-like substance in the digestive tract. This gel helps slow down digestion, which can help regulate blood sugar levels, lower cholesterol, and promote a feeling of fullness. According to the American Heart Association, soluble fiber is beneficial for heart health as it binds to cholesterol in the digestive tract and removes it from the body. It is recommended to consume at least 25 grams of fiber per day, with at least 10-15 grams coming from soluble fiber. Some other good sources of soluble fiber include beans, lentils, peas, barley, fruits such as apples and oranges, and vegetables such as carrots and Brussels sprouts. Consuming foods high in soluble fiber can help improve digestion, promote feelings of fullness, and help maintain a healthy weight. Therefore, including soluble fiber in the diet is crucial.
Source: American Heart Association (https://www.heart.org/en/healthy-living/healthy-eating/eat-smart/nutrition-basics/fiber)
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A radioactive isotope has a half-life of 2 hours. If a sample of the element contains 600,000 radioactive nuclei at 12 noon, how many radioactive nuclei would be left at 6 pm?
Answers
Answer: There will be 75258 nuclei left at 6 pm.
Explanation:
a) half-life of the radioactive substance:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
\(t_{\frac{1}{2}}=\frac{0.69}{k}\)
\(k=\frac{0.69}{t_{\frac{1}{2}}}=\frac{0.693}{2hours}=0.346hours^{-1}\)
b) Expression for rate law for first order kinetics is given by:
\(A=A_0e^{-kt}\)
where,
k = rate constant
t = time for decomposition = 6 hours ( from 12 noon to 6 pm)
A = activity at time t = ?
\(A_0\) = initial activity = 600, 000
\(A=600000\times e^{-0.346\times 6}\)
\(A=75258\)
Thus there will be 75258 nuclei left at 6 pm.
What are the common sedimentation tanks found in waste treatment
plants and what is the purpose of each tank
Answers
In waste treatment plants, there are several common types of sedimentation tanks .some of the most common sedimentation tanks and their purposes: Primary Sedimentation Tank , Secondary Sedimentation Tank ,Tertiary Sedimentation Tank:
1. Primary Sedimentation Tank: The primary sedimentation tank, also known as a primary clarifier or primary settling tank, is designed to remove settleable solids and heavy particles from wastewater. It allows the heavier particles to settle at the bottom of the tank, forming sludge, while the lighter particles float to the top and are skimmed off. The primary sedimentation tank helps in the removal of large suspended solids and organic matter.
2. Secondary Sedimentation Tank: The secondary sedimentation tank, also called a secondary clarifier or final settling tank, is used in biological treatment processes. It receives the treated wastewater from the biological reactor, such as an activated sludge process or a trickling filter, and allows the remaining suspended solids, microorganisms, and flocs to settle. This tank separates the treated wastewater from the biological sludge or biomass before the water is discharged or subjected to further treatment.
3. Tertiary Sedimentation Tank: Tertiary sedimentation tanks, also known as tertiary clarifiers or polishing basins, are used for additional treatment after the secondary sedimentation tank. These tanks further remove fine suspended solids, residual organic matter, and nutrients, such as phosphorus or nitrogen, from the wastewater. Tertiary treatment is often required to meet strict effluent quality standards before the wastewater is discharged into the environment.
4. Imhoff Tank: An Imhoff tank is a type of sedimentation tank used for the treatment of sludge or sewage solids. It consists of two chambers: an upper chamber for settling and a lower chamber for anaerobic digestion of the settled sludge. The Imhoff tank allows for the natural decomposition of organic solids in the lower chamber, reducing the volume of sludge and producing biogas.
These sedimentation tanks play a crucial role in wastewater treatment by allowing the separation and removal of solids from the wastewater, improving the overall quality of the treated effluent. The specific design and purpose of each tank may vary depending on the treatment process and the requirements of the wastewater treatment plant.
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The Current in a wire is 0.500A. How much charge flows through a cross section of the wire in 10.0s? How many electrons move through the same cross section in 10.0s?
Answers
5 Coulomb charge flows through a cross section of the wire in 10 sec, and 3.1205 × 10¹⁹ electron passing through the same cross section in 10 seconds.
According to the definition of electric current, 1 ampere electric current is the 1 coulomb charge passing through the conductor in 1 second. 1 coulomb charge contains 6.241 x 10¹⁸ electrons. So,
0.5 A current flow means 0.5 C charge flows in 1 second.
So, the charge flows in 10 sec, = 0.5 × 10 = 5 C
Number of electrons pass in 10 seconds, n = 5 × 6.241 x 10¹⁸
n = 3.1205 x 10¹⁹
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Open the pt activity. perform the tasks in the activity instructions and then answer the question. which set of configuration commands issued on sw1 will successfully complete the etherchannel link between sw1 and sw2?
Answers
SW2 (config-if-range)channel-group 1 mode desirable. Ether-channel is made by combining multiple physical links that are seen as one link between two switches.
The possible combination to establish an ether-channel between SW1 and SW2 using LACP or PAgP .Ether-channel is a port link aggregation technology or port channel architecture used primarily on Cisco.
Ether-channel is used for providing fault tolerance and high-speed links between switches, routers and servers. To form an Ether-channel there are 2 protocol and link aggregation control protocol. Also load balances traffic across links in the bundle. Traffic is not necessarily distributed equally among all the links. Ether-channel will double or quadruple your bandwidth.
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Two in-phase loudspeakers, which emit sound in all directions, are sitting side by side. One of them is moved sideways by 6.0 m, then forward by 4.0 m. Afterward, constructive interference is observed 1/4 and 3/4 of the distance between the speakers along the line that joins them.
Part A
What is the maximum possible wavelength of the sound waves?
Express your answer with the appropriate units.
Answers
The maximum possible wavelength of the sound waves is determined by the distance between the two in-phase loudspeakers. After they were moved, the distance between them was 10 m. The maximum possible wavelength of the sound waves is 7.2 meters.
Wavelength is the distance between two consecutive points on a wave that are in phase. When the amplitude of two waves combines, it results in a constructive interference.
The wavelength of the sound wave can be determined using the following formula:
λ = 2d/n where,λ = wavelength, d = distance between the two loudspeakers n = number of nodes.
The distance between the two loudspeakers is 6 + 4 = 10 m. Also, there are two nodes between the loudspeakers, as we see from the fact that constructive interference occurs at 1/4 and 3/4 the distance.
Hence, using the above formula:
λ = 2(10 m) / 2 = 20 meters.
This wavelength is the smallest possible, when the two loudspeakers are at the furthest distance apart from each other. However, the loudspeaker moved 6 m sideways and 4 m forward, and as such the actual maximum wavelength is longer than 20 m. Hence, to get the maximum possible wavelength, we have to find the length of the diagonal from the original position to the moved position. This length is given by:
d² = (6 m)² + (4 m)²
d = 7.2 m.
Now, using the same formula:
λ = 2(7.2 m) / 2 = 7.2 meters.
Thus, the maximum possible wavelength of the sound waves is 7.2 meters.
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Reference frame definitely changes when also changes
Answers
the head loss through a straight pipe can be represented by a friction factor f h equals fraction numerator 4 f l u squared over denominator 2 g d end fraction where h : head loss (m) l : pipe length (m) u : average flow velocity (m/s) g ; gravitational acceleration (m/s2) d : pipe diameter (m) what is the unit of a friction factor f?
Answers
After canceling out the common units, we can observe that the friction factor (f) is dimensionless, meaning it has no units.
The formula that has been provided for head loss through a straight pipe is commonly known as the Darcy-Weisbach equation, which relates the head loss to the flow rate and properties of the pipe. The friction factor f is a measure of the resistance to flow through the pipe and is determined by the roughness of the pipe wall and the Reynolds number of the flow. A detailed explanation of how to calculate the friction factor is beyond the scope of this answer, but it involves solving the Colebrook-White equation, which is an empirical relation derived from experimental data. The friction factor is an important parameter in many fluid mechanics problems, as it affects the pressure drop and energy losses in the system.
The unit of the friction factor (f) in the equation for head loss (h) through a straight pipe can be determined from the
equation h = (4 * f * l * u²) / (2 * g * d). In this equation, h is the head loss (m), l is the pipe length (m), u is the average flow velocity (m/s), g is the gravitational acceleration (m/s²), and d is the pipe diameter (m).
To find the unit of friction factor (f), we need to rearrange the equation to solve for f. This can be done by multiplying both sides by (2 * g * d) and then dividing by (4 * l * u²):
f = (h * 2 * g * d) / (4 * l * u²)
Now, we can substitute the units of each variable into the equation:
f = [(m) * (m/s²) * (m)] / [(m) * (m/s)²]
Thus, after canceling out the common units, we find that the friction factor (f) is dimensionless, meaning it has no units.
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Sound waves travel through steel railroad rails a distance of 2350 m in 0.383 s. What is the speed of sound in the rails?
(units = m/s)
Answers
Answer:
Speed of sound ways in railroad = 6,135.8 m/s
Explanation:
Given:
Distance cover by sound wave = 2,350 meter
Time taken by sound wave to cover distance = 0.383 seconds
Find:
Speed of sound ways in railroad
Computation:
Speed = Distance / Time
Speed of sound ways in railroad = Distance cover by sound wave / Time taken by sound wave to cover distance
Speed of sound ways in railroad = 2,350 / 0.383
Speed of sound ways in railroad = 6,135.77
Speed of sound ways in railroad = 6,135.8 m/s
In a certain series R L C circuit, Irms=9.00A, ΔVrms=180V, and the current leads the voltage by 37.0⁰. (a) What is the total resistance of the circuit?
Answers
The total resistance of the RLC series circuit is determined as 20 ohms.
Total resistance of the circuit
The total resistance of the RLC series circuit is calculated as follows;
R = Vrms / Irms
where;
Vrms is the root mean square voltageIrms is the root mean square currentSubstitute the given parameters and solve for the total resistance
R = (180) / (9)
R = 20 ohms
Thus, the total resistance of the RLC series circuit is determined as 20 ohms.
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A 150-kg object takes 1.5 minutes to travel a 2,500-meter straight path. It begins the trip traveling 120 meters per second and decelerates to a velocity of 20 meters per second.
What was its acceleration?
Responses
(A) −1.11 m/s2
(B) −0.3 m/s2
(C) +1.11 m/s2
(D) +80 m/s2
Answers
Answer: So the answer is (A) -1.11 m/s^2.
Explanation: To solve this problem, we need to use the formula for average acceleration, which is given by:
a = (vf - vi) / t
Where a is the acceleration, vf is the final velocity, vi is the initial velocity, and t is the time.
Plugging in the values given in the problem, we get:
a = (20 m/s - 120 m/s) / (1.5 minutes * 60 seconds/minute) = -100 m/s / 90 seconds = -1.11 m/s^2
So the answer is (A) -1.11 m/s^2.