the vaule of delta h for the reaction below is -336kj. calculate the heat relased to the surroundings when 23g of hcl is formed

Driving at 60 mph or 100 km/h, it would take about 6 minutes to cover a distance equal to the thickness of the breathable atmosphere.

The thickness of the breathable atmosphere is about 6 miles or 10 kilometers.

Therefore, driving at 60 miles per hour (mph) or 100 kilometers per hour (km/h), it would take about 6 minutes to cover a distance equal to the thickness of the breathable atmosphere.

The thickness of the breathable atmosphere is about 6 miles or 10 kilometers. The speed at which the distance would be covered can be determined by the formula for average speed:

AVERAGE SPEED = TOTAL DISTANCE / TOTAL TIME

The distance to be covered here is 6 miles or 10 kilometers. Since we are concerned about how long it would take to drive this distance, we can rearrange the formula as follows:

TOTAL TIME = TOTAL DISTANCE / AVERAGE SPEED

Suppose we want to drive this distance at a speed of 60 miles per hour (mph) or 100 kilometers per hour (km/h). Then the time it would take to drive the distance would be:

T = 6 miles / 60 mph

= 0.1 hour

= 6 minutes

OR

T = 10 kilometers / 100 km/h

= 0.1 hour

= 6 minutes

Therefore, driving at 60 mph or 100 km/h, it would take about 6 minutes to cover a distance equal to the thickness of the breathable atmosphere.

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Answer:

The correct answer would be B.

Fluorine (a halogen) is very reactive because it has 7  outer shell electrons.

Explanation:

It's located at the top of the Halogen Group in the periodic table and it's the most electronegative element, this makes it very reactive.

I hope this helps you:)

Fluorine (a halogen) is Very Reactive because it has 7 outer shell electrons.Hence, option (D) is correct.

The halogens are a group in the periodic table consisting of five or six chemically related elements: fluorine, chlorine, bromine, iodine (I), and astatine.

The artificially created element 117, tennessine, may also be a halogen. In the modern IUPAC nomenclature, this group is known as group 17

Therefore, Fluorine (a halogen) is Very Reactive because it has 7 outer shell electrons. Hence, option (D) is correct.

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Answer:

Explanation:

\(\mathrm {Hey, there!}\)

Let's solve your problem -

The answer to the question is 4.18 10^7.

Here is my clarification/explanation to support:

To convert a standard number to scientific notation, we have to move the decimal point up until we have a 1 digit number.

When we keep moving the decimal point, we get 4.18

Now, we will count the numbers after the 8 to get the 10 area.

There are five numbers after the 8, so we get 10^5.

Now, we will add 2 more to the 5, we get 10^7

Our answer will be: 4.18 10^7

\(\mathrm {Best, of, Luck!}\)

No, the volume of water in a beaker is not an extensive property.

Extensive properties are those that depend on the amount or size of the substance being measured. In other words, they are properties that change with the quantity of the substance. Examples of extensive properties include mass, volume, and total energy.

In the given scenario, the volume of water in the beaker is 50 milliliters. This volume remains the same regardless of the quantity of water present. Whether it's 50 milliliters or 500 milliliters, the volume measurement does not change. Therefore, the volume of water in the beaker is an example of an intensive property.

Intensive properties are independent of the amount or size of the substance. They are characteristics that remain constant regardless of the quantity of the substance. Examples of intensive properties include temperature, density, and color.

It's important to note that the distinction between extensive and intensive properties depends on the specific property being considered. While volume is typically an extensive property for a bulk substance, in the case of a fixed volume of water in a beaker, it becomes an intensive property.

In summary, the volume of water in a beaker is not an extensive property but rather an intensive property because it does not change with the quantity of the substance.

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Answer:

The correct response is "3.127 weeks". A further explanation is given below.

Explanation:

As we know,

y = 1.3431x

Use, y = 4.2 cm

Now,

⇒ \(y = 1.3431x\)

On substituting the values of y, we get

⇒ \(4.2=1.3431x\)

⇒ \(x = \frac{4.2}{1.3431}\)

⇒    \(=3.127 \ weeks\)

Answer:

fewer collisions occur between particles or lowering the temperature

Explanation:

According to the experiment, the snack provides approximately 50.16 J of energy per gram.

The calorimeter absorbs 2508 J of energy from the snack. To calculate the amount of energy provided by the snack per gram (J/g), we need to know the mass of the snack. Let's say the mass of the snack is m grams.

The formula to calculate energy per gram is:

Energy per gram (J/g) = Total energy absorbed (J) / Mass of the snack (g)

In this case, the total energy absorbed is 2508 J.

So, the equation becomes:

Energy per gram (J/g) = 2508 J / m g

To find the energy per gram, we need to know the mass of the snack in grams. Once we have the mass, we can plug it into the equation to calculate the energy per gram.

For example, if the mass of the snack is 50 grams:

Energy per gram (J/g) = 2508 J / 50 g
Energy per gram (J/g) = 50.16 J/g

So, according to the experiment, the snack provides approximately 50.16 J of energy per gram.

It's important to note that the energy provided by the snack per gram may vary depending on the composition of the snack and the specific calorimeter used in the experiment. The experiment provides a way to measure the energy content of the snack and determine its nutritional value.

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Answer:

It's answer is c) exactly 37 protons

Answer:

C) ,  Exactly 37 protons.

Explanation:

Remember the electrons have a negative charge, so to make a atom with 37 electrons neutral, you will need the same amount of the opposite type. That means you need 37 protons.

f an electron drops down from excited state c (950 zj) to ground state a (150 zj), the wavelength of the photon that is emitted is 1.22 x 10^7.

Energy of the radiation emitted when the muon jumps from the second orbital to the ground sate E=RX² (2-2) (x-1);(R=2-2x168) E= R (1) 3R. R = 3x2+2x10'3 4 -18 1.65×10. Wavelength of the radiation emitted, λ= he = 6.6 x 1034, E x3x10 1.65 x1018 -7 = 1.2x10 m. An electron is in an excited state when it momentarily takes up an energy state larger than just its ground state. Whenever an electron absorbs a photon or throughput of light, or comes into contact with a near the area atom or particle, it gains additional energy and then becomes excited. The dipole moment is the lowest energy level that an atom can occupy. This is the atomic power state that's also considered the norm. The length between corresponding points (adjacent crests) in adjoining loops of the a signal signal propagated in room or along a wire is characterised as the wavelength. This length is generally defined in wireless systems in metres (m), centimetres (cm), or millimetres (mm) (mm).

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Vanadium(V) oxide is the inorganic compound with the formula V₂O₅. Commonly known as vanadium pentoxide, it is a brown/yellow solid, although when freshly precipitated from aqueous solution, its colour is deep orange. Because of its high oxidation state, it is both an amphoteric oxide and an oxidizing agent.

formula:V2O5

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Answer:

is it vanadium v oxide or just vanadium oxide

Explanation:

The current concentration of carbon dioxide in the atmosphere is higher than at any point in the last 800,000 years.

An electric current is a circulation of charged particles, including electrons or ions, shifting thru an electrical conductor or space. Its miles are measured because of the net fee of drift of electric fee through a floor or into a managed extent.

The current is one of the most important and essential elements within electric and electronic technology. The contemporary flowing in a circuit may be utilized in an expansion of ways from generating warmness to inflicting circuits to replace, or information to be saved in an included circuit.

Current is decided by the number of electrons passing through a cross-section of a conductor.

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Answer:

1. B

2. 100 C

3.  C

4. D

5. D

Explanation:

(i) The vehicle outputs approximately 11.58 kg of CO₂ per week. (ii) The Biofuel Obligation Scheme in Ireland is implemented by requiring fuel suppliers.

To calculate the amount of CO₂ output per week, we need to determine the amount of fuel used and then use the given combustion equation to find the ratio of CO₂ produced per unit of fuel.

Given;

Average fuel efficiency: 7.5 km per litre

Distance traveled per week: 300 km

Mass of fuel per litre: 0.75 kg

First, we calculate the total fuel used per week;

Fuel used = Distance traveled / Fuel efficiency

= 300 km / 7.5 km per litre

= 40 litres

Next, we find the mass of fuel used per week:

Mass of fuel used = Fuel used × Mass of fuel per litre

= 40 litres × 0.75 kg per litre

= 30 kg

Using the combustion equation, we know that 2 moles of C₈H₁₈ produce 16 moles of CO₂. Therefore, we can calculate the moles of CO₂ produced from the given mass of fuel;

Moles of CO₂ produced = Moles of C8H18 × (16 moles of CO₂ / 2 moles of C₈H₁₈)

= (30 kg / (114 g/mole)) × (16 moles of CO₂ / 2 moles of C₈H₁₈)

= (30,000 g / 114 g/mole) × (16 moles of CO₂ / 2 moles of C₈H₁₈)

= 263.16 moles of CO₂

Finally, we convert the moles of CO₂ to kilograms;

Mass of CO₂ produced = Moles of CO₂ produced × Molar mass of CO₂

= 263.16 moles × (44 g/mole)

= 11,579.04 g

= 11.58 kg (rounded to two decimal places)

Therefore, the vehicle outputs approximately 11.58 kg of CO₂ per week.

The Biofuel Obligation Scheme in Ireland is implemented by requiring fuel suppliers to include a certain percentage of biofuels in their overall fuel sales, thereby reducing the carbon footprint by promoting the use of renewable and lower-carbon-emitting fuels.

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The list of celestial bodies from smallest to largest are asteroids, moons, planets, and Stars.

A celestial body is an occurrence that naturally takes place in space. The terms object and body can be used interchangeably when referring to space and galaxies. Celestial bodies are firmly bound things with intricate shapes and structures that contain hundreds of smaller items.

The sun, moon, stars, and planets are examples of celestial bodies, sometimes known as heavenly bodies. The cosmos contains celestial objects, which are cosmic bodies that are visible in space and are positioned distant from the earth. We can only see the majority of the celestial groupings with a telescope.

They are usually seen at night and are invisible to the unaided eye. The size of certain celestial bodies is considerably greater than that of the planet. They are located outside of the atmosphere of the earth. There are millions of celestial bodies in the Kuiper belt.

Therefore, the list of celestial bodies, from smallest to largest are asteroids, moons, planets, and stars.

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Yes, a miscibility gap exists for a mixture of water and 1-butanol at 928C. The range of compositions over which this gap exists is between the eutectic point and the upper cloud point.

The eutectic point is the composition where the two components form two liquid phases, and the upper cloud point is the composition where the two components form a single liquid phase.

The van Laar parameters for this system (L12) indicate the degree to which changes in temperature, pressure, and composition affect the relative solubility of the two components.

For a mixture of 1-butanol and water at 928C, the relative solubility of the two components decreases as the composition deviates from the eutectic point, resulting in a miscibility gap. The range of compositions over which this gap exists is determined by the van Laar parameters.

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Answer:

Yes, the basis for science and its theories are always built upon observations.

Explanation:
Everything begins with an observation. As is it with science, scientist look to nature and try to decode it secrets and law upon which it is built, For which scientific method is used and within that the first step is one must make observation of the phenomenon that is under study.
Hope that answers that!

Answer: a beating heart,emotions,pain

Explanation:

Answer:

Its compounds are used by oil and gas industries to make drilling mud. Drilling mud simplifies drilling through rocks by lubricating the drill. Barium compounds are also used to make paint, bricks, tiles, glass, and rubber. Barium nitrate and chlorate give fireworks a green colour.

Answer:

You can protect yourself from radiation by getting further away from the radiation source .

Answer:

It reacts by fizzing and wearing away/dissolving the rock.

Explanation:

Answer:

Explanation:

Calcium and Beryllium are similar to Magnesium because all the three elements belong to the same group and have 2 valence electrons in their outer shell.

Potassium has 19 protons and - since the number of protons is the same as the number of electrons- also 19 electrons. To find out the number of neutrons you have to look at the atomic mass or weight of the element.

Answer:

Any base with an ability to dissolve in water are called alkalis. All alkalis are bases, however, not all bases are alkalis.

Answer:

No. The density of the gold-colored ring is 16.9 g/mL, which is less than that of pure gold, whose density is 19.3 g/mL. Therefore, the ring is not pure gold.

Explanation:

Density is an intrinsic property of a substance, which means that it is a characteristic of the substance that is independent of the size or amount of the sample. This makes density a useful property for identifying a substance, such as gold, as it can be determined for any size or amount of the sample.

In this question, by comparing the density of the ring to the known density of pure gold, we can determine whether the ring is pure gold. If the ring had the same density as pure gold, we would conclude that it is pure gold.

The density of a substance can be calculated by dividing its mass by its volume, both of which are provided:

Density = mass / volume

The density of the ring = 18.9 g / 1.12 mL = 16.9 g/mL

The known density of pure gold is 19.3 g/mL. Since the density of the ring is less than the density of pure gold, the ring is not pure gold.

Answer:  A basic solution is defined as a solution which has more hydroxide (OH-) ions than hydronium ions (H+)

The half-life of palladium-100 is 4 days. after 16 days a sample of palladium-100 has been reduced to a mass of 7 mg.

The initial mass ( in mg) of the sample is 112 mg. The mass of the sample 8 weeks after the start is approximately 0.0068 mg.

The half-life of palladium-100 is 4 days, which means that every 4 days the amount of palladium-100 in a sample is reduced by half.

Let's use N(t) to represent the mass of the sample at time t, and N0 to represent the initial mass of the sample.

Since the half-life of palladium-100 is 4 days, we know that:

N(t) = N0 * (1/2)^(t/4)

We are given that after 16 days, the mass of the sample is 7 mg. So we can plug in these values and solve for N0:

7 = N0 * (1/2)^(16/4)

7 = N0 * (1/2)^4

7 = N0 * 1/16

N0 = 7 * 16

N0 = 112 mg

So the initial mass of the sample was 112 mg.

Now we can use the same formula to find the mass of the sample after 8 weeks (which is 56 days):

N(56) = 112 * (1/2)^(56/4)

N(56) = 112 * (1/2)^14

N(56) = 112 * 1/16384

N(56) = 0.00683594 mg.

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The states of matter of the materials;

1) Dispersion forces - Yes

2) Hydrogen bonding - No

3) Ionic - No

4) Dispersion forces - No

5)  Dispersion forces - Yes

6) Ionic  - No

7) Hydrogen bonding - No

Sublimation is a physical process in which a substance transitions directly from its solid phase to its gaseous phase without passing through the intermediate liquid phase. In sublimation, the solid substance is heated, and the resulting gas molecules escape from the solid lattice structure without the need for melting.

One common example of sublimation is the process of dry ice. Dry ice is solid carbon dioxide (CO2) that sublimes at a temperature of -78.5 degrees Celsius (-109.3 degrees Fahrenheit). When dry ice is exposed to room temperature, it transitions directly from a solid to a gas, producing a fog-like effect.

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In chemistry, the density of many substances is often compared to that of water. It has a density of 1 g/cm3, which makes it easy to remember and a good point of reference for other substances.

For example, if a substance has a density of 0.7 g/cm3, you can immediately tell that it is less dense than water and will therefore float in it.

This property of water also makes it an ideal medium for many chemical reactions, as most substances will easily dissolve in it and react with each other without the need to be heated or mixed in a special environment. This makes it an essential component of many laboratory experiments, as it can be used to create solutions quickly and safely.

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Answer:

?? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ?

To prepare 1.30 liters of a 0.200 M solution of silver nitrate (AgNO3), you will need 44.2 grams of AgNO3.

This can be calculated using the molar mass of AgNO3 (169.87 g/mol) and the number of moles of AgNO3 needed to make the solution [3], which is 0.0269 moles (1.30 L x 0.200 M = 0.0269 moles). Thus, 0.0269 moles x 169.87 g/mol = 44.2 g AgNO3.

To further develop the topic, it is important to note that silver nitrate can also be used as a reagent in various chemical reactions. For example, silver nitrate can be used to precipitate out insoluble metal salts such as silver chloride, which can be used for a variety of purposes, including photography and medicine.

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