There were 2555 players in a race. If 123 player went away and 2345 players joined,how many players were there now?

Answer:

Step-by-step explanation:

A horizontal line is a "y =  " line. So the horizontal line that goes through the point given has the equation y = -1 (-1 being the y coordinate of the point). That means that another point on this line, y = -1, will also have to have a y coordinate of -1. The only one is the last one, (-2, -1).

Answer:

D

Step-by-step explanation:

I just took the test

The average rate of change for the function between the given values is approximately 8491275.888.

To find the average rate of change for a given function, we will use the formula:

average rate of change = (f(b) - f(a)) / (b - a)

where f(a) and f(b) are the values of the function at points a and b, respectively, and (b-a) represents the change in the independent variable over the interval from a to b.

Using the given function f(x) = x² + 4x and the interval from 6 to 84818129/2, we can calculate the average rate of change as follows:

Let a = 6 and b = 84818129/2, then we can calculate the function values at a and b:

f(a) = f(6) = 6² + 4(6) = 36 + 24 = 60

f(b) = f(84818129/2) = (84818129/2)² + 4(84818129/2) = 360020447540116.5.

The change in the independent variable over the interval from a to b is:

b - a = (84818129/2) - 6 = 42409058.5

We can now substitute these values into the formula for the average rate of change:

average rate of change = (f(b) - f(a)) / (b - a)= (360020447540116.5 - 60) / 42409058.5≈ 8491275.888

Therefore, the average rate of change for the function between the given values is approximately 8491275.888.

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Answer:

Hi The Answer is A.

Step-by-step explanation:

The Answer is A Because of the funter travel of the X.

x*y=z

Hope This Helps.

:)

My name is John henry.

Answer:

1st choice

Step-by-step explanation:

(r² -4r + 5 - r² -2r + 8) / (r - 4)

= (-6r + 13) / (r - 4)

To prove a number is irrational we divide the integer by another integer is the decimal is non terminating and non repeating then it will be a irrational number .

What are Irrational Numbers ?

The Irrational numbers can be defined  a number that cannot be expressed as a fraction \(\frac{p}{q}\) for any integers p and q.

The Irrational numbers have decimal expansions that do not terminate nor repeat (periodic) . Every transcendental number is an irrational number .

(i) To prove a number irrational  when we divide an integer by another integer, and  if decimal expansion does not terminate and do not  repeat then it is an irrational .

(ii) if the number cannot be expressed in the form of \(\frac{p}{q}\) , then also the number will be called as irrational numbers .

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The volume of the display case is 2161 1/8 cubic inches.To find the volume of a rectangular prism-shaped display case, we multiply its length, width, and height.

Given that the display case is 30 1/2 inches wide, 10 1/2 inches long, and 32 1/4 inches tall, we can calculate the volume as follows:

Volume = Length * Width * Height

Using the given measurements:

Volume = 10 1/2 inches * 30 1/2 inches * 32 1/4 inches

To simplify the calculation, we can convert the mixed numbers to improper fractions:

Volume = (21/2) inches * (61/2) inches * (129/4) inches

Next, we multiply the fractions:

Volume = (21/2) * (61/2) * (129/4) = 17289/8

The resulting fraction, 17289/8, is an improper fraction. To convert it back to mixed number form:

Volume = 2161 1/8 in³.

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Answer:

250%. the total amount.

Answer: 190,870,314

Step-by-step explanation:

It would be 190,870,314

An association between the two variables can be implied if the relative frequencies vary across the columns.

In a two-way table, the relative frequencies represent the proportion of observations within each cell relative to the total number of observations in that column. If the relative frequencies differ significantly across the columns, it suggests that there is an association between the two variables being examined. This indicates that the distribution of one variable is not independent of the other variable, and there may be a relationship or dependence between them. It is important to analyze the patterns in the data, perform additional statistical tests, and consider other factors to confirm the presence and strength of the association.

An association between the two variables can be implied if the relative frequencies vary across the columns.

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the beta of a portfolio given the expected return of the portfolio will be 1.5.

The beta of a portfolio measures its sensitivity to market movements. It is calculated as the covariance between the returns of the portfolio and the market divided by the variance of the market returns. Mathematically, the formula for beta (β) is:  β = Cov(rp, rm) / Var(rm),

where Cov(rp, rm) represents the covariance between the portfolio returns (rp) and the market returns (rm), and Var(rm) represents the variance of the market returns.

Given that e(rp) = 18% (expected return of the portfolio), rf = 6% (risk-free rate), and e(rm) = 14% (expected return of the market), we can use these values to calculate the beta.

First, we need to determine the excess return of the portfolio and the market:

Excess Return of Portfolio (ERP) = e(rp) - rf = 18% - 6% = 12%

Excess Return of Market (ERM) = e(rm) - rf = 14% - 6% = 8%

Next, we can calculate the beta using the formula:

β = Cov(rp, rm) / Var(rm) = ERP / ERM

Plugging in the values, we have:  β = 12% / 8% = 1.5

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Step-by-step explanation:

N n P = all the even numbers between 3 and 9 =

= {4, 6, 8}

Answer:

The constant of proportionality = k = 2/5

Step-by-step explanation:

Also given that The number of gallons, g (/), is proportional to the number of

seconds, t (x).

i.e.

g ∝ t

g = k × t

k = g / t

as

g = 2

t = 5

Thus,

k = g / t

  = 2 / 5

Thus, the constant of proportionality = k = 2/5

Answer:

Step-by-step explanation:

NEPK ≅ VXSR

A.

G.

D.

F.

Therefore, x = 9 is not a solution. The valid x-intercepts are x = -3 and x = 3.

To find the x-intercepts of the function \(f(x) = (4x^2 - 36)/(x - 9)\), we need to set f(x) equal to zero and solve for x.

Setting f(x) equal to zero, we get:

\((4x^2 - 36)/(x - 9) = 0\)

Since the numerator \((4x^2 - 36)\)is a difference of squares, we can factor it as:

\((4x^2 - 36) = (2x + 6)(2x - 6)\)

So, the equation becomes:

\((2x + 6)(2x - 6)/(x - 9) = 0\)

Now we set each factor equal to zero and solve for x:

\(2x + 6 = 0\)

\(2x = -6\)

\(x = -3\)

and

\(2x - 6 = 0\)

\(2x = 6\)

\(x = 3\)

So the x-intercepts of the function f(x) are x = -3 and x = 3. These are the values of x for which the function f(x) equals zero. Note that x = 9 is not a valid x-intercept, as it would result in division by zero in the original function due to the (x - 9) in the denominator. Therefore, x = 9 is not a solution. The valid x-intercepts are x = -3 and x = 3.

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Answer:

Step-by-step explanation:

= 10x^2 - 2xy + 6x + 5xy - y^2 + 3y

Now, we can combine like terms: = 10x^2 + 3xy + 6x - y^2 + 3y

So, the product of (2x + y) and (5x - y + 3) is 10x^2 + 3xy + 6x - y^2 + 3y.

The distribution of X, the number of heads obtained by tossing three unbalanced coins, has probabilities of 8/27 for X=0, 4/27 for X=1, 2/27 for X=2, and 1/27 for X=3.

The possible outcomes of a single coin toss are either a head or a tail, with probabilities of 1/3 and 2/3 respectively. Since we are tossing three coins, there are \(2^3 = 8\) possible outcomes, which we can list in a sample space:

{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT}

where H represents a head and T represents a tail.

To find the probability of each outcome, we can simply multiply the probabilities of each individual coin toss. For example, the probability of getting HHT is \($\frac{1}{3}\cdot\frac{1}{3}\cdot\frac{2}{3}=\frac{2}{27}$\), since the first two coins must land on a head and the third coin must land on a tail.

We can then calculate the probability of each value of X, the number of heads, by adding up the probabilities of the outcomes that correspond to that value of X.

X = 0: P(X=0) = P(TTT) = \($\left(\frac{2}{3}\right)^3 = \frac{8}{27}$\)

X = 1: P(X=1) = P(HTT, THT, TTH) = \($3\cdot\frac{1}{3}\cdot\frac{2}{3}\cdot\frac{2}{3}=\frac{4}{27}$\)

X = 2: P(X=2) = P(HHT, HTH, THH) = \($3\cdot\frac{1}{3}\cdot\frac{1}{3}\cdot\frac{2}{3}=\frac{2}{27}$\)

X = 3: P(X=3) = P(HHH) = \($\left(\frac{1}{3}\right)^3=\frac{1}{27}$\)

Therefore, the distribution of X is:

X 0 1 2 3

P(X) 8/27 4/27 2/27 1/27

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Hi! :)

_______ ☆ ☆_____________________

Answer:

Answer will be below...

Step-by-step explanation:

The easiest way for me is using the formula.

Formula: (example) 1+ 2+ __+ n = [goes on...]

Hope this helps! :)

_______ ☆ ☆______________________

By, BrainlyMember ^-^

✨ Good luck! ✨

Answer:

C is the correct answer.

Step-by-step explanation:

\(f(x) = 2x + 2\)

\(f(2) = 2(2) + 2 = 4 + 2 = 6\)

Answer: x =8

Step-by-step explanation:

A midsegment cuts a line in half

\(x = \frac{15}{10} \times y\)

.

Answer:

Either 4/9 as a fraction or 0.44444444447

The ans is :

y_2(x) = x - (1/3!)x^3 + (2/135!)x^5 - (1/4725!)x^7 + ...

We are given the differential Equation:

y′′ + 2xy′ + 2y = 0

To find two power series solutions about the ordinary point x=0, we assume that y has a power series representation of the form:

y = ∑n=0^∞ a_n x^n

Differentiating this expression twice, we get:

y′ = ∑n=1^∞ na_n x^(n-1)

y′′ = ∑n=2^∞ n(n-1)a_n x^(n-2)

Substituting these expressions into the differential equation, we get:

∑n=2^∞ n(n-1)a_n x^(n-2) + 2x ∑n=1^∞ na_n x^(n-1) + 2 ∑n=0^∞ a_n x^n = 0

Simplifying and rearranging terms, we get:

∑n=0^∞ [(n+2)(n+1)a_(n+2) + 2na_n + 2a_n] x^n = 0

Since this equation must hold for all x, we can equate the coefficients of x^n to obtain a recurrence relation:

(n+2)(n+1)a_(n+2) + 2na_n + 2a_n = 0

Simplifying this expression, we get:

a_(n+2) = -[(2n+2)/(n+2)(n+1)] a_n

This is our recurrence relation. We can use it to find the coefficients a_n for any n once we have determined the values of a_0 and a_1.

Let us now find two power series solutions about x=0.

First Solution:

We take a_0 = 1 and a_1 = 0 to get:

a_2 = -2/2! a_0 = -1

a_3 = 0

a_4 = 4/4! a_2 = 1/3!

a_5 = 0

a_6 = -2/6! a_4 = -1/90!

a_7 = 0

a_8 = 4/8! a_6 = 1/2520!

...

Hence, the first power series solution is:

y_1(x) = a_0 + a_2 x^2 + a_4 x^4 + a_6 x^6 + ...

Substituting the values of a_n, we get:

y_1(x) = 1 - x^2 + (1/3!)x^4 - (1/90!)x^6 + ...

Second Solution:

We take a_0 = 0 and a_1 = 1 to get:

a_2 = 0

a_3 = -2/3! a_1 = -1/3!

a_4 = 0

a_5 = 4/5! a_3 = 2/135!

a_6 = 0

a_7 = -2/7! a_5 = -1/4725!

a_8 = 0

...

Hence, the second power series solution is:

y_2(x) = a_1 + a_3 x^3 + a_5 x^5 + a_7 x^7 + ...

Substituting the values of a_n, we get:

y_2(x) = x - (1/3!)x^3 + (2/135!)x^5 - (1/4725!)x^7 + ...

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After subtraction (3x+4) - (x+7), the resultant answer is 2x-3.

One of the four operations used in mathematics, along with addition, multiplication, and division, is subtraction.

Removal of items from a collection is represented by the operation of subtraction.

For instance, in the following image, there are 5 2 peaches, which means that 5 peaches have had 2 removed, leaving a total of 3 peaches.

So, we have:

(x+7) and (3x+4)

We have to subtract as:

(3x+4) - (x+7)

Now, subtract as follows:

(3x+4) - (x+7)

3x+4 - x-7

2x-3

Therefore, after subtraction (3x+4) - (x+7), the resultant answer is 2x-3.

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Answer:

  circumcenter

Step-by-step explanation:

You want to know the name of the point equidistant from the vertices of a triangle.

The circle that passes through the vertices of a triangle is called a "circumcircle". It circumscribes the triangle. Its center is equidistant from all points on the circle, so is equidistant from the triangle's vertices.

The point equidistant from the vertices of a triangle is the circumcenter.

__

Additional comment

The circumcenter is at the intersection of the perpendicular bisectors of the sides of the triangle.

Answer:

Contain: AC; BC; CD; AD; BD

Don’t contain: AB

Step-by-step explanation:

It’s kinda easy to see

The segments on line l that: a) contain point C: AD, BD, BC and CD

b) do not contain point C: AB

"It is a part of line that has two endpoints."

For given question,

We have been given a line l.

The line segments that contain point C are:

AD

BD

BC

CD

The line segments that do not contain point C:

AB

Therefore, all segments on line l that: a) contain point C: AD, BD, BC and CD

b) do not contain point C: AB

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