Three samples of a solid substance composed of elements A and Z were prepared. The first contained 4.31 g A and 7.70 g Z. The second sample was 35.9% A and 64.1% Z. It was observed that 0.718 g A reacted with Z to form 2.00 g of the third sample. Show that these data illustrate the law of definite composition.

Answer:

x=51.66

Explanation:

1 ml = 1 gram

(mass) (Δt) (Cp) = (mass) (Δt) (Cp)

Substituting values into the above, we then have:

(25)(25-x)(4.184)=(50)(x-65)(4.18)

Solve for x

x= 51.6667

The final temperature is "51.67°C".

According to the question,

At 65°C,

= \(\frac{50}{50+25}\)

= \(\frac{50}{75}\)

= \(0.66667\)

At 25°C,

= \(\frac{25}{50+25}\)

= \(\frac{25}{75}\)

= \(0.33333\)

By multiplying the volume fractions, we get

→ \(65^{\circ} C\times 0.66667\) = \(43.3334^{\circ}C\)

→ \(25^{\circ} C\times 0.33333\) = \(8.3333325^{\circ} C\)

hence,

The final temperature will be:

= \(43.33334+8.333325\)

= \(51.6666^{\circ}C\)

or,

= \(51.67^{\circ} C\)

Thus the above answer is right.

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Answer:

hydrochloric acid

Explanation:

chemical compound any substance composed of identical molecules consisting of atoms

A mole of hydrogen peroxide and mole of hydrogen chloride both represent the same number of particles, they are different substances with different chemical properties and different mass per mole.

Mole is a unit of measurement that represents a specific number of particles, which is approximately 6.022 x 10²³ particles. When we say "a mole of hydrogen peroxide (H2O2)" or "a mole of hydrogen chloride (HCl)," we are referring to the same number of particles, which is 6.022 x 10²³ particles of each substance.

Hydrogen peroxide (H2O2) and hydrogen chloride (HCl) are different substances with different chemical properties. H2O2 is a compound that consists of two hydrogen atoms and two oxygen atoms and HCl is a compound that consists of one hydrogen atom and one chlorine atom.

A mole of H2O2 has a different molar mass than mole of HCl, which means that they have different mass per mole. Molar mass of H2O2 is approximately 34 grams per mole whereas molar mass of HCl is approximately 36.5 grams per mole.

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The volume of oxygen is 14.7 litres.

What is volume?

volume is a measure of occupied three dimensional space.

Sol-Balanced chemical reaction: C₃H₈ + 5O₂ → 3CO₂ + 4H₂O.

m(C₃H₈-propane) = 5.53 g.

n(C₃H₈) = m(C₃H₈) ÷ M(C₃H₈).

n(C₃H₈) = 5.53 g ÷ 44.1 g/mol.

n(C₃H₈) = 0.125 mol.

From chemical reaction: n(C₃H₈) : n(O₂) = 1 : 5.

n(O₂) = 0.625 mol.

T = 25° = 298.15K.

p = 1.04 atm.

R = 0.08206 L·atm/mol·K.

Ideal gas law: p·V = n·R·T .

V(O₂) = n·R·T / p.

V(O₂) = 0.625 mol · 0.08206 L·atm/mol·K · 298.15 K / 1.04 atm.

V(O₂) = 14.7 L.

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Answer:

The lewis structure for NO₃⁻ is shown in the attachment below

For the central nitrogen atom:

The number of lone pairs = 0

The number of single bonds = 2  

The number of double bonds= 1

Explanation:

The lewis structure for NO₃⁻ is shown in the attachment below.

From the Lewis structure

For the central nitrogen atom:

The number of lone pairs = 0

The number of single bonds = 2  

The number of double bonds= 1

Answer:

18.015

Explanation:

Using the periodic table of the elements to find atomic weights, we find that hydrogen has an atomic weight of 1, and oxygen's is 16. In order to calculate the molecular weight of one water molecule, we add the contributions from each atom; that is, 2(1) + 1(16) = 18 grams/mole.

To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.

To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.

If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).

However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.

In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.

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A dam constructed to produce tidal power does so by harnessing water flow to drive turbines and electric generators .

Tidal energy was employed in grain mills to crush grains mechanically, just like wind energy was. grain crushing Here, the tidal energy generated by the turbines was used. Hydroelectric dams, which serve as significant energy storage, also employ tidal energy to store energy.

Tidal power can harm marine life because tidal turbines' whirling blades can cause marine organisms to perish. Fish habitations in tidal power settings may be impacted by noise from the turbines' rotation. Tidal energy can also affect how sediment and water are processed.

Therefore, option B is correct.

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Answer:

Explanation:

The density of a substance can be found by using the formula

\(density = \frac{mass}{volume} \\\)

From the question

mass = 8.11 g

volume = final volume of water - initial volume of water

volume = 44.72 - 25.26 = 19.46 mL

We have

\(density = \frac{8.11}{19.46} \\ = 0.416752312...\)

We have the final answer as

Hope this helps you

Answer:

Refer to the picture. I managed to solve a few.

In the J = 0 state, the BrF molecule does not undergo any revolutions per second. In the J = 1 state, it undergoes approximately 0.498 revolutions per second, and in the J = 10 state, it undergoes approximately 15.71 revolutions per second.

To calculate the rotational constant B, we can use the formula:

B = 1 / (2 * π * Δν)

Where:

B = rotational constant

Δν = spacing between consecutive lines in the rotational spectrum

Given that the spacing between consecutive lines is 0.71433 cm^(-1), we can substitute this value into the formula:

B = 1 / (2 * π * 0.71433 cm^(-1))

B ≈ 0.079 cm^(-1)

The moment of inertia (I) of the molecule can be calculated using the formula:

I = h / (8 * π^2 * B)

Where:

h = Planck's constant

Given that the value of Planck's constant (h) is approximately 6.626 x 10^(-34) J·s, we can substitute the values into the formula:

I = (6.626 x 10^(-34) J·s) / (8 * π^2 * 0.079 cm^(-1))

I ≈ 2.11 x 10^(-46) kg·m^2

The bond length (r) of the molecule can be determined using the formula:

r = sqrt((h / (4 * π^2 * μ * B)) - r_e^2)

Where:

μ = reduced mass of the molecule

r_e = equilibrium bond length

To calculate the wavenumber (ν) of the J = 9+ to J = 10 transition, we can use the formula:

ν = 2 * B * (J + 1)

Substituting J = 9 into the formula, we get:

ν = 2 * 0.079 cm^(-1) * (9 + 1)

ν ≈ 1.58 cm^(-1)

To determine the most intense spectral line at room temperature (300 K), we can use the Boltzmann distribution law. The intensity (I) of a spectral line is proportional to the population of the corresponding rotational level:

I ∝ exp(-E / (k * T))

Where:

E = energy difference between the levels

k = Boltzmann constant

T = temperature in Kelvin

At room temperature (300 K), the population distribution decreases rapidly with increasing energy difference. Therefore, the transition with the lowest energy difference will have the most intense spectral line. In this case, the transition from J = 0 to J = 1 will have the most intense spectral line.

To calculate the number of revolutions per second, we can use the formula:

ω = 2 * π * B * J

Where:

ω = angular frequency (in radians per second)

J = rotational quantum number

For J = 0:

ω = 2 * π * 0.079 cm^(-1) * 0 = 0 rad/s

For J = 1:

ω = 2 * π * 0.079 cm^(-1) * 1 ≈ 0.498 rad/s

For J = 10:

ω = 2 * π * 0.079 cm^(-1) * 10 ≈ 15.71 rad/s

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Answer:

THE STANDARD ENTHALPY OF FORMATION OF AMMONIA GAS IS 293.75kJ OF HEAT.

Explanation:

To solve this question, you must first write out the equation for the reaction.

Equation:

N2 (g) + 3H2(g) <-------> 2NH3(g)

So therefore, when 50 g of N2 reacts, 164.5 kJ of Heat was liberated.

First equate the number of moles of Nitrogen and ammonia gas

1 mole of N2 produces 2 moles of ammonia

Calculate the molar mass of each variables:

Molar mass of N2 = 14*2 = 28 g/mol

Molar mass of ammonia = ( 14 + 1*3) = 17 g/mol

So, 1 mole of N2 = 2 moles of NH3

28 g/mol of N2 = 17 * 2 g/mol of NH3

If 50 g of nitrogen was used to react with excess hydrogen, the mass of ammonia formed is;

28 g of N2 = 34 g/mol of NH3

50 g of N2 = ( 50 * 34 / 28 ) g of NH3

= 1700 / 28

= 60 .71 g of ammonia.

At standard conditions, 34 g of ammonia will liberate 164.5 kJ of heat. What amonut would be generated by 60.71 g of ammonia?

34 g of ammonia = 164.5 kJ of heat

60.71 g of ammonia = ( 60.71 * 164.5  / 34) kJ of heat

= 9987.5 / 34

= 293.75 kJ of heat.

In other words, the standard enthalpy of formulation for ammonia gas is 293.75 kJ of heat.

Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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Draw a structural formula for the major product of the reaction shown:

The structural formula for the major product (2-butene) of the given reaction is as follows:$$\ce{CH3CH2CH=CH2}$$

The given reaction is an acid-catalyzed dehydration reaction.

During the reaction, the hydroxyl group (OH) and the adjacent hydrogen atoms (H) on the reactant alcohol (2-butanol) undergo dehydration (loss of water) to form an alkene (2-butene) as the major product.

The reaction is shown below:$$\ce{CH3CH2CH2CH2OH + H2SO4 ->[\Delta] CH3CH2CH=CH2 + H2O}$$To draw the structural formula for the major product of the given reaction, we need to consider the following points:

1. The reactant alcohol (2-butanol) is a four-carbon alcohol with the hydroxyl group (OH) attached to the second carbon atom (C2) of the chain.

2. The product alkene (2-butene) will be a four-carbon alkene with a double bond between the second and third carbon atoms (C2 and C3) of the chain.

The other two carbon atoms will have a single bond with the adjacent carbon atoms and a hydrogen atom each attached to them.

3. The major product will be formed via the elimination of water (dehydration) between the hydroxyl group (OH) and the adjacent hydrogen atoms (H) on the second carbon atom (C2) of the reactant alcohol (2-butanol).

4. The acid catalyst (H2SO4) does not participate in the reaction and remains unchanged. It only facilitates the formation of the alkene by providing a proton (H+) to the hydroxyl group (OH) and a medium for the elimination of water.

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The electron configuration 1s22s22p6 corresponds to the noble gas neon (Ne), which has a completely filled valence shell.

What is Electric Configuration?

The placement of electrons around the nucleus of a specific atom or molecule is known as its electronic configuration.

Protons, neutrons, and electrons are the minuscule components that make up an atom. There are the same number of protons and electrons in a neutral atom. The quantity and location of an atom's electrons are revealed by its electronic configuration.

We say that electrons orbit the nucleus of an atom, like the rings of Saturn orbit the planet. Electrons move in orbitals that can accommodate a specific number of electrons as they circle the nucleus.

Four elements that may have ions with this electron configuration are:

Fluorine (F-) - gains one electron to achieve a noble gas configuration (1s22s22p6)

Oxygen (O2-) - gains two electrons to achieve a noble gas configuration (1s22s22p6)

Sodium (Na+) - loses one electron from the valence shell to achieve a noble gas configuration (1s22s22p6)

Magnesium (Mg2+) - loses two electrons from the valence shell to achieve a noble gas configuration (1s22s22p6)

Therefore, the symbols for these ions are:

Na+, Mg2+, F-, O2-.

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Answer:primary consumer

Explanation:

i got it right

Answer:

all of the above

Explanation:

To find moles when given the molar mass, you can use the concept of molar mass as a conversion factor.Molar mass represents the mass of one mole of a substance, expressed in grams per mole (g/mol).

To calculate moles, divide the given mass of the substance by its molar mass. The equation is:

moles = mass / molar mass

For example, if you have 56 grams of carbon dioxide (CO2) and want to find the number of moles, you need to know the molar mass of CO2, which is approximately 44 g/mol. Using the equation above:

moles = 56 g / 44 g/mol

moles ≈ 1.27 mol

Therefore, there are approximately 1.27 moles of carbon dioxide in 56 grams.

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Answer:

d. increases PFK activity, decreases FBPase activity

Explanation:

Fructose-2,6-bisphophate is formed by the phosphorylation of fructose-6-phosphate catalyzed by phosphofructokinase-2, PFK-2.

Fructose-2,6-bisphophate functions as an allosteric effector of the enzymes phosphofructokinase-1, PFK-1 and fructose-1,6-bisphosphatase, FBPase.

Fructose-2,6-bisphophate has opposite effects on the enzymes, PFK-1 and FBPase. When it binds to the allosteric site of the enzyme, PFK-1, it increases the enzymes's activity by increasing its affinity for its substrate fructose-6-phosphate and reduces its affinity for its allosteric inhibitors ATP and citrate. However, when it binds to FBPase, it reduces its activity by reducing its affinity for glucose, its substrate

Answer:

40,113 years

Explanation:

To find the age of the sample, you need to use the half-life formula:

\(N(t)=N_0(\frac{1}{2})^{t/h\)

In this formula:

------> N(t) = current mass (g)

------> N₀ = initial mass (g)

------> t = time passed (yrs)

------> h = half-life (yrs)

You can plug the given values into the equation and rearrange the formula to find "t".

N(t) = 0.781 g                       t = ? yrs

N₀ = 100 g                           h = 5730 yrs

\(N(t)=N_0(\frac{1}{2})^{t/h\)                                           <----- Half-life formula

\(0.781=100(\frac{1}{2})^{t/5730}\)                                     <----- Insert values

\(0.00781=(\frac{1}{2})^{t/5730}\)                                       <----- Divide both sides by 100

\(log_{1/2}(0.00781)=log_{1/2}((\frac{1}{2})^ {t/5730})\)               <----- Take \(log_{1/2}\) of both sides

\(7.00 = \frac{t}{5730}\)                                                   <----- Solve \(log_{1/2}\)

\(40,113 = t\)                                                   <----- Multiply both sides by 5730

The given sample is 40,113 years .

Half-life, in radioactivity, is the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay.

Half-life formula,

\(\rm N(t)\;=N_0(\dfrac{1}{2})^\frac{t}{t1/2}\)   .......(1)

where,

N(t)=current mass

N₀=initial mass

t=time period

h=half -life

Given,

N(t)=0.781g, t=? yrs, N₀=100g, h=5730 years

\(\rm N(t)\;=N_0(\dfrac{1}{2})^\frac{t}{t1/2}\)

put the values, in ......(1)

0.781=100(1/2) \(t/5730\\\)

log₁/₂(0.00781)=log₁/₂ ( 1/2)\(t/5730\)

7=t/5730

40,113=t

Hence, the given sample is 40,113 years .

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Answer:

b d my good mannnnnnnnnnnn

\(\huge\boxed{3.2 Grams}\)

Moles is the unit which measures the amount of substance in the System International (SI). A mole is the amount of substance that contains the same amount of substance as the amount of substance exactly in exactly 12 g of carbon-12. C-12 is the standard to measure moles.

I have attached the Equations for moles.

For this question we will use the formula,

                                      \(Moles = \frac{Given Mass}{Atomic Mass}\)

Rearrange the equation,

                                      \(Mass = (Moles)x(Atomic Mass)\)

Given:

          Moles = 0.2

          Molecular Mass of Oxygen Atom(Not molecule) = 16

Thus,

                                        \(Mass = (0.2)x(16)\\\\Mass = 3.2 grams\)

The mass of 0.2 moles of oxygen atom is 3.2 grams.

Answer:

Explanation:

SI unit is an international system of measurements that are used universally in technical and scientific research to avoid the confusion with the units. Having a standard unit system is important because it helps the entire world to understand the measurements in one set of unit systems.

Unit of Electric Charge: Unit of Wavelength

Unit of Mass: Unit of Velocity:

Since what we have is an alpha decay, the missing component is 234/90 Th

Alpha decay is a type of radioactive decay in which an atomic nucleus emits an alpha particle, which is a helium nucleus consisting of two protons and two neutrons. During alpha decay, the atomic number of the parent nucleus decreases by two, and the mass number decreases by four.

Apha particles can be stopped by a thin layer of material such as paper or skin, and they do not penetrate very far into matter.

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Explanation:

First, you need to balance the equation:

N2    +  3 H2   ====>    2  NH3

                  so three moles of H2   result in  2 moles of NH3

                               ratio of   3:2

How many moles of NH3 is 36.5 gm  ??

   Using periodic table NH3 mole weight = 14.007  + 3*1.008 =17.031 g/mole

     36.5 g / 17.031 g/mole = 2.14 moles  of NH3

Using the ratios above   3/2 = x / 2.14   shows x = 3.21 moles of H2 needed

Answer:

The answer is 82

Explanation:

Dude in the stop says so

We can produce more products by;

A. Increasing the concentration of H₂ gas in the reaction vessel

B. Decreasing the temperature in the reaction vessel

C. Removing the H₂O from the reaction vessel as it forms

Water is created through an exothermic process. Heat energy is released when hydrogen gas (H2) and oxygen gas (O2) mix to make water (H2O). An exothermic reaction is characterized by this energy release.

The reaction's overall energy change is negative, which shows that energy is released. The reaction is exothermic because the extra energy is released as heat into the environment.

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Missing parts;

Water can be made using the reversible reaction shown. Which change would

keep this reaction from shifting to form more of the product?

2H₂+022H₂O + energy

A. Increasing the concentration of H₂ gas in the reaction vessel

B. Decreasing the temperature in the reaction vessel

C. Removing the H₂O from the reaction vessel as it forms

D. Increasing the temperature in the reaction vessel

Answer:

Explanations:

Physical changes are changes that affect the form of a chemical substance while chemical changes are irreversible reaction involving the rearrangement of the atoms of the molecules.

For Ice cream melting, this involves change in phase from solid (freezing)

The solid and the liquid coexist at the melting point, which is the point where the temperature remains constant during the phase transition.

In the given cooling curve, the melting point is at 50°C, indicated by the flat region on the curve between points C and D. At this point, the energy being released during cooling is used to overcome the energy required for the substance to transition from a liquid to a solid state.

Once all of the substance has solidified, the temperature begins to decrease again.

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Answer: all points on the curve between Q and S

Explanation: Where the graph looks like <-------->horizontal.

Answer:

D

Explanation:

I believe it is D. your kinetic energy would be at b. A, the cart would be going at a constant rate, because there is no hill or steep slope.