To decide whether an object is electrically charged, we need to observe its repulsion from some other object, not its attraction. Why is attraction insufficient

Answers

Answer 1

To decide whether an object is electrically charged, we need to observe its repulsion from some other object, not its attraction.

The reason attraction is insufficient for this purpose is because both charged and uncharged objects can attract each other. As such, attraction cannot be used to distinguish between charged and uncharged objects We need to observe an object's repulsion from another object to determine if it is electrically charged.

This is because attraction is not a sufficient indicator of an object's electrical charge. Charged and uncharged objects can attract each other, making attraction an unreliable method of determining electrical charge.

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Related Questions

Normally, materials are electrically neutral because there are

Answers

Same number of protons and electrons

Listed below are the measured radiation absorption rates​ (in W/kg) corresponding to 11 cell phones. Use the given data to construct a boxplot and identify the​ 5-number summary. 1.16 0.85 0.69 0.75 0.95 0.93 1.18 1.17 1.42 0.54 0.57 The​ 5-number summary is nothing​, nothing​, nothing​, nothing​, and nothing​, all in​ W/kg. ​(Use ascending order. Type integers or decimals. Do not​ round.)

Answers

Answer:

The 5-number summary is

1. Median = 0.93 W/kg

2. Lower quartile = 0.69 W/kg

3. Upper quartile = 1.16 W/kg

4. Minimum value = 0.54 W/kg

5. Maximum value = 1.42 W/kg

Explanation:

We are given the measured radiation absorption rates​ (in W/kg) corresponding to 11 cell phones.

1.16 0.85 0.69 0.75 0.95 0.93 1.18 1.17 1.42 0.54 0.57

What is 5-number summary?

A 5-number summary refers to a box plot that basically shows 5 statistical characteristics of a data set.

These statistical characteristics are:    

1. Median

2. Lower quartile

3. Upper quartile  

4. Minimum value  

5. Maximum value  

1. Median:

Arrange the data in ascending order

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

(n+1)/2 gives the median value of the data set.

(11 + 1)/2 = 6th position

Therefore, 0.93 W/kg is the median of the data set.

2. Lower quartile:

Divide the data set into two equal halfs (include median in both if n = odd)

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The lower quartile is the median of the lower half of the data set.

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

The median is 6/2 = 3rd position

Therefore, the lower quartile of the data set is 0.69 W/kg

3. Upper quartile:

Divide the data set into two equal halfs (include median in both if n = odd)

Lower half = 0.54 0.57 0.69 0.75 0.85 0.93

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The upper quartile is the median of the lower half of the data set.

Upper half = 0.93 0.95 1.16 1.17 1.18 1.42

The median is 6/2 = 3rd position

Therefore, the upper quartile of the data set is 1.16 W/kg

4. Minimum value:

The minimum value is the least value in the data set.

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

Therefore, the minimum value of the data set is 0.54 W/kg

5. Maximum value  

The maximum value is the least value in the data set.

0.54 0.57 0.69 0.75 0.85 0.93 0.95 1.16 1.17 1.18 1.42

Therefore, the maximum value of the data set is 1.42 W/kg

The box plot is illustrated in the attached diagram.

Listed below are the measured radiation absorption rates (in W/kg) corresponding to 11 cell phones. Use

A proper cool-down
O increases the heart-rate
O makes muscles cold
O helps prevent fainting or dizziness
none are correct

Answers

Answer:

Option D (none are correct) is the appropriate solution.

Explanation:

After yet another workout, a cool or calming down allows the breathing as well as pulse rate to recover more quickly. It will also assist to eliminate the lactic acid build-up during the exercise, eventually increasing the muscle soreness with delayed onset. Wind yourself off for 5 to 10 minutes by taking public transportation a stationary bicycle.

Some other three scenarios do not correspond to something like the situation described. So, this same correct decision is the one above.

one significant method for assessing body fat distribution is measurement of ______ circumference.

Answers

One significant method for assessing body fat distribution is measurement of waist circumference.

Waist circumference is a widely used method for assessing body fat distribution and is an important indicator of central obesity. It involves measuring the circumference of the waist at a specific anatomical landmark, typically at the level of the narrowest point between the ribs and the iliac crest.

The measurement of waist circumference provides valuable information about the distribution of body fat. Excess fat accumulation in the abdominal region, also known as central obesity or android obesity, is associated with a higher risk of various health conditions, including cardiovascular diseases, type 2 diabetes, and metabolic syndrome.

By measuring waist circumference, healthcare professionals can evaluate an individual's body fat distribution and assess their risk for developing obesity-related health problems.

The measurement of waist circumference is relatively simple and non-invasive, making it a practical method for assessing body fat distribution in clinical and research settings. It is often used in conjunction with other anthropometric measurements, such as body mass index (BMI), to provide a comprehensive evaluation of an individual's body composition and health status.

Regular monitoring of waist circumference can help track changes in body fat distribution over time and guide interventions aimed at reducing central obesity and improving overall health.

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PLS HELP!! I will make brainliest!!

Which process is an example of a chemical reaction?

a. an iron nail rusting
b. bath water cooling while you take a bath
c. a piece of metal being heated until it expands
d. a glass window breaking when hit with a baseball​

Answers

Answer:

Rusting!

Explanation:

Rusting is a chemical reaction because it is the process of oxidation of a metal.  

Answer:

rusting

Explanation:

For an Ultrasonic Vaporizer Us Duty Rate 4.2%, valued in USD$750, transported via Air and no valid CUSMA certificate available calculate: - Duty Charge - MPF - HMF

2. Same Ultrasonic Vaporizer Us Duty Rate 4.2%, valued in USD$750, transported via Ocean and no valid CUSMA certificate available calculate:

Duty Charge

MPF

HMF

Answers

1. The duty charge, MPF and HMF for the Ultrasonic Vaporizer transported via air are USD$31.50, USD$2.60 and USD$0.94, respectively.

2. The duty charge, MPF and HMF for the Ultrasonic Vaporizer transported via ocean are USD$31.50, USD$0.94 and USD$0.94, respectively.

How to calculate duty charge, MPF and HMF

For the Ultrasonic Vaporizer transported via air

Duty Charge:

Given information;

Duty rate = 4.2%

Value of goods = USD$750

Duty charge = Value of goods x Duty rate

Duty charge = USD$750 x 4.2%

Duty charge = USD$31.50

Merchandise Processing Fee (MPF)

MPF rate = 0.3464% (as of 2021)

Value of goods = USD$750

MPF = Value of goods x MPF rate

MPF = USD$750 x 0.3464%

MPF = USD$2.60

Harbor Maintenance Fee (HMF)

HMF rate = 0.125% (as of 2021)

Value of goods = USD$750

HMF = Value of goods x HMF rate

HMF = USD$750 x 0.125%

HMF = USD$0.94

Therefore, the total import fees for the Ultrasonic Vaporizer transported via air are:

Duty charge = USD$31.50

MPF = USD$2.60

HMF = USD$0.94

For the Ultrasonic Vaporizer transported via ocean

Duty Charge:

Given information:

Duty rate = 4.2%

Value of goods = USD$750

Duty charge = Value of goods x Duty rate

Duty charge = USD$750 x 4.2%

Duty charge = USD$31.50

Merchandise Processing Fee (MPF)

MPF rate = 0.125% (as of 2021)

Value of goods = USD$750

MPF = Value of goods x MPF rate

MPF = USD$750 x 0.125%

MPF = USD$0.94

Harbor Maintenance Fee (HMF):

HMF rate = 0.125% (as of 2021)

Value of goods = USD$750

HMF = Value of goods x HMF rate

HMF = USD$750 x 0.125%

HMF = USD$0.94

Therefore, the total import fees for the Ultrasonic Vaporizer transported via ocean are:

Duty charge = USD$31.50

MPF = USD$0.94

HMF = USD$0.94

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Duty Charge=$31.50

The MPF will be $27.23.

The HMF rate is $0.125 per metric ton.

Ultrasonic Vaporizer transported via Air:

Duty Charge: $31.50

MPF: $26.79

HMF: Not applicable

Ultrasonic Vaporizer transported via Ocean:

Duty Charge: $31.50

MPF: $27.23

HMF: HMF rate and weight of the vaporizer are needed to calculate the HMF.

Ultrasonic Vaporizer transported via Air:

Duty Charge: The duty charge is calculated by multiplying the value of the product ($750) by the duty rate (4.2%): Duty Charge = \(\$750 * 4.2\%\)

= \(\$31.50.\)

MPF: The MPF for air transport is based on the value of the merchandise. As the value of $750 is below the maximum, the MPF will be $26.79.

HMF: The HMF is not applicable for air transport.

Ultrasonic Vaporizer transported via Ocean:

Duty Charge: The duty charge is calculated in the same way as for air transport: Duty Charge = \(\$750 * 4.2\%\)

= \(\$31.50\).

MPF: The MPF for ocean transport is also based on the value of the merchandise. As the value of $750 is below the maximum, the MPF will be $27.23.

HMF: The HMF is applicable for ocean transport. The HMF rate is $0.125 per metric ton. The weight of the Ultrasonic Vaporizer is needed to calculate the HMF.

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what do you predict will happen in activity 2-2 when the coil is pulled away from the north pole of magnet

Answers

So, in Activity 2-2, if the coil is pulled away from the north pole of a magnet, it is likely that an EMF will be induced in the coil.

What is EMF?

However, based on general principles of electromagnetism, if a coil is pulled away from the north pole of a magnet, it will experience a change in magnetic flux, which can induce an electromotive force (EMF) in the coil. This phenomenon is known as electromagnetic induction.

How is direction of EMF known?

The magnitude and direction of the induced EMF will depend on several factors, such as the strength of the magnet, the velocity at which the coil is moved, and the orientation of the coil with respect to the magnetic field. If the coil is part of a circuit, the induced EMF can cause a current to flow in the circuit.

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A student collects 25 mL of gas at 96 kPa. What volume would this gas occupy at 101.325 kPa. There is no change in temperature or mass.

Answers

Answer:

The answer is 23.69 mL

Explanation:

The new volume can be found by using the formula

\(P_1V_1 = P_2V_2\)

Since we are finding the new volume

\(V_2 = \frac{P_1V_1}{P_2} \\\)

From the question we have

101.325 kPa = 101325 Pa

96 kPa = 96000 Pa

From the question we have

\(V_2 = \frac{25 \times 96000}{101325} = \frac{2400000}{101325} \\ = 23.68615840...\)

We have the final answer as

23.69 mL

Hope this helps you

10. A cyclist reaches the top of a hill at 5.0 m/s and accelerates downhill, reaching the bottom
in 8.3 s with a speed of 11.4 m/s. How long was the hill (total length down)?

Answers

Answer:94.62 m

Explanation:Distance=speed×time

Downhill,

Distance= 11.4 m/s×8.3 m/s

Therefore, Distance= 94.62 m (downhill)

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(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)(^o^)

You are pulling on a rope attached to the outer radius of a pulley with a moment of inertia I = 2.85 kg-m^2 as shown. The tension force of you on the pulley is 266.3 N. A pack of mass 23.4 kg is attached to the pulley's inner radius as shown. If the inner radius of the pulley is 0.43 m and the outer radius is 0.66 m, what is the magnitude of the linear acceleration of the pack? If instead of using a pulley with two radii, you were to replace the two radii pulley with a simple pulley of one radius: how would using the simple pulley instead of the two radii pulley affect the difficulty of holding the pack at rest over the edge? It will be easier to hold the pack. Not enough information to tell. There will be no difference. It will be harder to hold the pack.

Answers

The magnitude of the linear acceleration of the pack can be calculated using the following equation:a = (T - Fr) /m where a is the magnitude of the linear acceleration of the pack,T is the tension force of you on the pulley,Fr is the frictional force, and m is the mass of the pack.Substitute the given values to the formula:a = (T - Fr) / ma = (266.3 - Fr) / 23.4.

The frictional force can be determined using the moment of inertia of the pulley.I = mr²I = 2.85 kg-m²m = I / r²m = 2.85 / 0.43²m = 15.57 kgFr = maFr = 15.57 × aa = (266.3 - 15.57a) / 23.4Solve for a by multiplying both sides by 23.4:23.4a = 266.3 - 15.57a23.4a + 15.57a = 266.3a = 266.3 / 39.97a = 6.66 m/s².

Therefore, the magnitude of the linear acceleration of the pack is 6.66 m/s².If instead of using a pulley with two radii, you were to replace the two radii pulley with a simple pulley of one radius, it will be harder to hold the pack.

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Earth’s plates move only a few _____ per year.

a. centimeters
b. meters

Answers

Answer:

centimeters

Explanation:

earth's plates move only a few centimeters per year.

If two points have 3.0 V and 7.0 V potential, what is the voltage or potential difference between the two points

Answers

Voltage or potential difference is calculated by taking the difference between the voltages at two points. Thus, if two points have 3.0 V and 7.0 V potential, the voltage or potential difference between the two points can be found by subtracting the lower potential from the higher potential.

That is:

Potential difference = Higher potential - Lower potential
                                 = 7.0 V - 3.0 V
                                 = 4.0 V
Therefore, the potential difference between the two points is 4.0 V. The electric potential difference between two points is the work done per unit charge in moving a test charge from one point to the other.

A potential difference is a measure of the electric potential energy per unit charge between two points in an electric field. The electric potential at a point is defined as the work done per unit charge in bringing a test charge from infinity to that point.

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True or False
The ecological niche of a species is the place where its members live.

Answers

Answer:

true

Explanation:

What is the momentum of a 15 kg tire rolling down a hill at 3 m/s?

5 kg • m/s
18 kg • m/s
45 kg • m/s
60 kg • m/s

Answers

Answer:

The answer is 45 kg • m/s

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question

mass = 15 kg

velocity = 3 m/s

We have

mass = 15 × 3

We have the final answer as

45 kg • m/s

Hope this helps you

Answer:

45 kg • m/s

Explanation:

what are reasons that a promontory will be more vulnerable to wave erosion than a bay? multiple select question. waves bend around a promontory and strike it from both sides. larger waves enter into a bay than strike a promontory. a promontory will receive more wave action than a bay. powerful waves focus most of their energy at a promontory.

Answers

The reasons that a promontory will be more vulnerable to wave erosion than a bay;- Waves bend around a promontory and strike it from both sides,- Powerful waves focus most of their energy at a promontory and - A promontory will receive more wave action than a bay.

A promontory is more vulnerable to wave erosion than a bay due to the following reasons:

1. Waves bend around a promontory and strike it from both sides: This phenomenon, called wave refraction, concentrates the wave energy on the promontory, making it more prone to erosion.

2. A promontory will receive more wave action than a bay: Bays are generally more sheltered and have a lower exposure to waves, whereas promontories are exposed to the full force of waves, leading to more erosion.

3. Powerful waves focus most of their energy at a promontory: Due to the shape of the coastline, waves tend to focus their energy on the headlands, like promontories, which makes them more vulnerable to erosion compared to bays.

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professor brown holds on to the end of the minute hand of a clock atop citv hall. if the minute hand is 4.0 m long. what is the professor's centripetal acceleration?

Answers

The centripetal acceleration of the professor holding onto the end of the minute hand of a clock atop City Hall is 0.00133 m/s².

What is centripetal acceleration?

Centripetal acceleration is the inward force acting on a body moving in a circular path that changes the direction of the velocity of the body and constantly pulls it toward the center of the circle.To determine the professor's centripetal acceleration, we use the formula;

`a= (v²)/r`

Where `a` is the centripetal acceleration, `v` is the velocity, and `r` is the radius. We have the length of the minute hand which is the radius of the circle.

So,`r = 4 m`We need to find the velocity which is given by the formula:

`v= (2πr)/T`

Where `π` is pi (3.14), `r` is the radius, and `T` is the time taken for one complete rotation which is 60 minutes since it's the minute hand.

Therefore;`v = (2 x 3.14 x 4 m) / (60 min x 60 s / 1 min)``v = 0.42 m/s`Substitute `v` and `r` into `a = (v²)/r` to get:`a = (0.42 m/s)² / 4 m``a = 0.00133 m/s²`

Therefore, the centripetal acceleration of the professor holding onto the end of the minute hand of a clock atop City Hall is 0.00133 m/s².

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If the distance between slits on a diffraction grating is 0. 50 mm and one of the angles of diffraction is 0. 25°, how large is the path difference? nm How many orders of bright lines does this equal for red light with a wavelength of 650 nm? wavelengths.

Answers

The distance the wave traveled between the two-point is the path difference. The path difference will be 2200 nm and 3 orders of bright lines do this equal red light with a wavelength of 650 nm.

What is diffraction grating?

A diffraction grating is a type of optical instrument obtained with a continuous pattern. The pattern of the diffracted light by a grating depends on the structure and number of elements present.

The equation of diffraction grating is given as

\(\rm n\lambda=dsin\phi\\\\\rm n\lambda=0.50\times10^{-3}\times sin(0.25) \\\\ n\rm \lambda=2.18\times10^{-6} \;m \\\\\rm n\lambda=2200\;nm\)

Hence the path difference will be 2200 nm.

\(\rm n\lambda=2200\;nm \\\\\rm n\times650=2200 \\\\\rm n=3.38\)

n= 3

Hence 3 orders of bright lines do this equal red light with a wavelength of 650 nm.

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please help urgent have you ever seen the old “Pull the tablecloth out from under the dishes” trick? Use Newton’s 1st Law to explain the following:
a. In this trick, are the dishes “objects in motion,” or “objects at rest?”
b. If the dishes end up staying on the table, was an UNBALANCED FORCE applied to them? How do you know?

Answers

Answer:

I kinda dont remember the 1st law so search it up on

and it should tell u , but if u need any help from the

a proton traveling at 39o respect to a magnetic field of strength 4.3 mt experiences a magnetic force of 5.0 x 10-17n a) find the proton’s speed b) find the proton’s kinetic energy

Answers

a) The magnetic force on a charged particle moving with velocity v in a magnetic field B is given by the formula:

F = q v B sinθ

where q is the charge of the particle and θ is the angle between v and B.

In this case, the proton has charge q = +1.602 x 10\(^-19\)C, the magnetic field strength is B = 4.3 x 10\(^-3\) T, and θ = 90° - 39° = 51° (since the proton is traveling at an angle of 39° with respect to the magnetic field, the angle between v and B is 90° - 39° = 51°).

Substituting these values and the given force F = 5.0 x 10\(^-17\) N into the formula, we can solve for the proton's speed v:

F = q v B sinθ

Therefore, the proton's speed is approximately 1.32 x 10\(^5\) m/s.

b) The kinetic energy of the proton can be calculated using the formula:

K = (1/2) m v\(^2\)

where m is the mass of the proton (which is approximately 1.67 x 10\(^-27\)kg).

Substituting the values of m and v, we get:

K = (1/2) m v\(^2\) = (1/2) (1.67 x 10\(^-27\) kg) (1.32 x 10^5 m/s)\(^2\) ≈ 1.14 x 10\(^-14 J\)

Therefore, the kinetic energy of the proton is approximately 1.14 x 10\(^-14 J\)J.

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an airplane flies 1,592 miles east from arizona to georgia in 3.68 hours. what is the average velocity of the airplane

Answers

Answer: Around 433 miles

Explanation:

what is the minimum internal cooking temperature and holding time for chopped sirloin

Answers

The recommended minimum internal cooking temperature for ground beef, including chopped sirloin, is 160°F (71°C). This temperature should be measured using a food thermometer inserted into the thickest part of the meat.

The minimum internal cooking temperature and holding time for chopped sirloin (ground beef) depend on food safety guidelines to ensure that harmful bacteria, such as E. coli, are sufficiently destroyed.

In terms of holding time, it is generally recommended to cook ground beef until it reaches the minimum internal temperature of 160°F (71°C) and then maintain that temperature for at least 15 seconds to ensure any potential pathogens are killed.

It's important to note that these guidelines are based on food safety recommendations, and following them helps reduce the risk of foodborne illnesses. Cooking ground beef, like chopped sirloin, to the proper internal temperature is crucial for food safety.

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A 600 nm laser illuminates a double-slit apparatus with a slit separation distance of 3.55 μm. The viewing screen is 1.50 meters behind the double slits. What is the distance, in cm, between the 2nd and 3rd dark fringes?

Answers

The distance between the 2nd and 3rd dark fringes will be 0.09 cm.

In a double-slit interference pattern, the distance between the dark fringes can be determined using the following formula:

Y = (λ × L) / d

where:

Y is the distance between the dark fringes,

λ is the wavelength of the light,

L is the distance from the double slits to the viewing screen (also known as the slit-to-screen distance), and

d is the slit separation distance.

Given:

λ = 600 nm = 600 × 10⁻⁹m (since 1 nm = 10⁻⁹ m)

L = 1.50 m

d = 3.55 μm = 3.55 × 10⁻⁶ m (since 1 μm = 10⁻⁶m)

Plugging these values into the formula, we get:

Y = (600 × 10⁻⁹ m) ×(1.50 m) / (3.55 × 10⁻⁶m)

Simplifying, we get:

Y = 0.0009 m

To convert this to centimeters, we multiply by 100 (since 1 m = 100 cm):

Y = 0.0009 m× 100 cm/m = 0.09 cm

So, the distance between the 2nd and 3rd dark fringes is 0.09 cm.

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Find the frequency of voilet of its wavelength is 400cm

Answers

The frequency of the violet light is\(7.5 x 10^14 Hz (Hertz).\)

The frequency of the wave is determined by dividing the velocity of light by its wavelength.

\(v=f/λWhere:v = velocity of light f = frequency λ = wavelength of the light\)

The speed of light is\(3.00 x 10^8\) meters per second (m/s).

To convert 400 cm into meters, divide 400 by 100. 400 cm = 4 m

Therefore,λ = 4 meters

Plugging these values into the formula, \(v = (3.00 x 10^8 m/s) / (4 m) = 7.5 x 10^14 Hz\)

So, the frequency of the violet light with a wavelength of \(400 cm is 7.5 x 10^14 Hz.\)

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A student is given a red and a blue liquid. The two samples of liquids are
heated in identical beakers over identical Bunsen burners. The red liquid
shows a dramatically faster increase in temperature. Which of these is the
most likely explanation for this? *
O A) The red liquid has a greater mass.
O B) The blue liquid has a smaller mass.
O C) The red liquid has a greater specific heat.
OD) The red liquid has a smaller specific heat

Answers

Option D) The red liquid has a smaller specific heat

When a substance has smaller specific heat it needs less heat to shows changes in it hence making the option D correct.

Answer:

option D) the red liquid has a smaller specific heat

Explanation:

Which describes the electric field at the center of a ring of uniform negative charge?.

Answers

Answer:

A negatively charged particle -q is placed at the center of a uniformly charged ring, where the ring has a total positive charge Q as shown in the following figure. The particle, confined to move along the x axis, is moved a small distance x along the axis ( where x << a) and released. Show that the particle oscillates in simple harmonic motion with a frequency given by,

Deep Space 1 was a spacecraft powered by an engine that gave off xenon particles to change velocity. It had a mass of 500 kg. Which expression can be used to find the spacecraft’s acceleration if its engine created a net force of 0.10 N?

Answers

The expression can be used to find the spacecraft’s acceleration if its engine created a net force of 0.10 N

\($$\begin{aligned}& a=F / m \\& a=0.10 \mathrm{~N} / 500 \mathrm{Kg}\end{aligned}$$\)

Definition:

Acceleration: The rate at which the speed and direction of a moving object vary over time. A point or object going straight forward is accelerated when it accelerates or decelerates. Even though the speed is constant, motion on a circle accelerates because the direction is always shifting.

Formula:

\($$\begin{aligned}& \mathrm{a}=\Delta \mathrm{v} / \Delta \mathrm{t} \\& \mathrm{a}=\text { acceleration } \\& \Delta \mathrm{v}=\text { change in velocity } \\& \Delta \mathrm{t}=\text { change in time }\end{aligned}$$\)

Units:

The unit of acceleration is\($\mathrm{m} \cdot \mathrm{s}^{-2}$\).

Acceleration can also be determine through following formula,

\($$\begin{aligned}& F=m \times a \\& a=F / m\end{aligned}$$\)

Given data:

Mass \($=500 \mathrm{Kg}$\)

Force \($=0.10 \mathrm{~N}$\)

Acceleration = ?

Solution:

\($$\begin{aligned}& a=F / m \\& a=0.10 \mathrm{Kg} \cdot \mathrm{m} \cdot \mathrm{s}^{-2} / 500 \mathrm{Kg} \\& a=0.0002 \mathrm{~m} \cdot \mathrm{s}^{-2}\end{aligned}\)

In mechanics, acceleration is the rate of change of the velocity of an object with respect to time. Accelerations are vector quantities .

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20.0 l of a monatomic ideal gas at a pressure of 100 kpa expand adiabatically until the volume doubles. what is the pressure in the gas at that point?

Answers

The pressure in the gas at that point is equal to the initial pressure, 100 kPa.

To expand adiabatically, there must be no heat transfer involved. Adiabatic expansion means that no heat is transferred between the gas and its surroundings; this means that if we double the volume of our gas, nothing should change in terms of temperature as long as there is no heat transfer to or from our system during expansion.

Since we're starting out with a monatomic ideal gas, we know that its entropy is going to stay constant throughout this process, so the ideal gas law gives us a relationship between pressure, volume, and temperature: PV = nRT

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A sound wave enters a new medium where sound travels faster. How does this affect the frequency and wavelength of the sound?
OA The frequency increases and the wavelength decreases.
OB. The frequency decreases and the wavelength increases.
Ос. . The frequency stays the same and the wavelength increases.
OD. The frequency stays the same and the wavelength decreases.
O E. Neither the frequency nor the wavelength is affected.

Answers

When a sound enters a new medium where the sound travels faster, it means the vibration of particles is high, and the wavelength of the waves increases which means the speed of the wave has increased. The frequency on the other hand will remain constant.

Humpback whales are known to produce a collection of elaborate
and repeating sounds with frequencies ranging from 20 Hz to 10 kHz. The sound
waves travel through water at speeds of approximately 1400 m/s. Determine the
wavelengths of the waves at the lower and the upper end of this frequency
range.​

Answers

Answer:

70 m.

Explanation:

Given,

Frequency, f = 20 HZ

speed of sound, v = 1400 m/s

wavelength of the waves = ?

we know,

v = f λ

Hence, the wavelength of the wave is equal to 70 m.

A teacher wishes to set up a demonstration that involves connecting a bowling ball of mass M to a fixed-point O on the ceiling by a string

Answers

D (please say I got it right need points)
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