Two point particles, with masses m and 2 m, are separated by some distance Lin an uniform gravitational field. The center of gravity of this two particle system is:________
А. located L/2 distance away from either mass and on the line joining the two particles.
B. located 1/3 distance away from 2 m and on the line joining the two particles.
C. located L/4 distance away from 2 m and on the line joining the two particles.
D. located L/3 distance away from mand on the line joining the two particles.
E. located L/4 distance away from m and on the line joining the two particles.
F. located where the mass 2 m is located.

The advantage that the runner nearest the gun in the 100-meter dash might have is known as  the "reaction time advantage."

A reaction time advantage is known to allow runners in a race  to be agile and efficient when it comes to responding to stimuli in situations like driving, playing sports, or even having a conversation.

It is believed that the runner closest to the gun has a shorter distance for the sound wave to travel which might result in a slightly quicker reaction time in comparison to the other runners.

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Answer:

14 secs and velocity will be 48

Explanation:

It takes approximately 9.05 seconds to roll the drum a distance of 36 meters.

We can use the formula for the circumference of a circle:

Circumference = 2 * π * radius

Given:

Radius (r) = 0.40 m

Circumference (C) = 2 * π * 0.40 m

We must figure out how many full rotations the drum makes to go 36 meters in order to calculate how long it takes to roll the drum. Since we are aware of the circumference, we can determine the number of full turns as follows:

Number of turns = Distance / Circumference

Given:

Distance = 36 m

Number of turns = 36 m / (2 * π * 0.40 m)

Now that we know how many turns there are, we can calculate the time by multiplying that number by the length of a turn, which is given as 8.0 seconds:

Time = Number of turns * Time per turn

Time = (36 m / (2 * π * 0.40 m)) * 8.0 s

By substituting the values into the equation, we can calculate the time:

Time = (36 / (2 * 3.14159 * 0.40)) * 8.0 s

Time ≈ 9.05 s

So, it takes approximately 9.05 seconds to roll the drum a distance of 36 meters.

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The water flow rate from the faucet, assuming a steady flow, is approximately 0.0001608 cubic meters per second.

The phenomenon of a water stream "necking down" as it falls can be explained by the principle of conservation of mass. According to this principle, the flow rate of water remains constant throughout the system.

In the given figure, the water stream emerges from a faucet with an initial cross-sectional area of 1.8 cm² (Area one). As the water falls, it narrows down to a smaller cross-sectional area of 0.3 cm² (Area two) at a height of 25 cm.

To calculate the water flow rate assuming steady flow, we can use the formula:

Flow rate = A₁√(2gh) / A₁² - A₂²

Where A₁ and A₂ are the initial and final cross-sectional areas, respectively, g is the acceleration due to gravity, and h is the height of the water column.

Plugging in the given values, we have:

Flow rate = 1.8 cm² √(2 × 9.8 m/s² × 25 cm) / (1.8 cm²)² - (0.3 cm²)²

Converting the units to match, we get:

Flow rate = 0.018 m² √(2 × 9.8 m/s² × 0.25 m) / (0.018 m²)² - (0.003 m²)²

Simplifying the expression, we find:

Flow rate ≈ 0.0001608 m³/s

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The rank of the forces in order of increasing magnitude is Fg < FB < FA.

option D is the correct answer.

The net force on an elevator moving upwards is determined by the force of gravity acting downwards and the normal force of the elevator acting upwards.

That is, the two forces acting on a person when he is moving in an elevator are:

When the two forces are of equal magnitude, the elevator will be static or moving with constant velocity.

When the magnitude of the two force are unequal, then the elevator will be accelerating upward or downward.

Since the elevator is moving upwards, it implies that the normal force is greater than the force of gravity acting downwards.

The box at the bottom will feel much heavier due to the weight of box and gravity acting downwards.

FA = FB + Fg

Thus, the force exerted on box A is the greatest, followed by the force on box B and then, the smallest is force of gravity.

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Answer:

The magnitude of the force that the 6.3 kg block exerts on the 4.3 kg block is approximately 41.9 N

Explanation:

Forces on block 4.3 kg are:

63N to the right and R21 (contact force from the 6.3 kg block) to the left

Net force on 4.3 kg block is: 63 N - R21

Forces on the 6.3 kg block are:

R12 to the right (contact force from the 4.3 kg block) and 11 N to the left.

So net force on the 6.3 kg block is: R12 - 11 N

According to the action-reaction principle the contact forces R21 and R12 must be equal in magnitude (let's call them simply "R").

Then, since the blocks are moving with the SAME acceleration, we equal their accelerations:

a1 = (63 N - R)/4.3 = (R - 11 N)/6.3 = a2

solve for R by cross multiplication

6.3 (63 - R) = 4.3 (R - 11)

396.9 - 6.3 R = 4.3 R - 47.3

369.9 + 47.3 = 10.6 R

444.2 = 10.6 R

R = 444.2 / 10.6

R = 41.90 N

Answer:

1) Assuming an adult person has an average mass of m=80 kg, and assuming it takes about 30 seconds to climb 5 meters of stairs, the energy used by the person is

So the power output is

And since the estimate we made is very rough, we can say that the power output of the person is comparable to the power output of the light bulb of 100 W.

2) Based on the results we found in the previous part of the exercise, since the power output of the person is comparable to the power output of 1 light bulb of 100 W, we can say that the person could have kept burning only one 100-W light bulb during the climb.

Explanation:

The final amount of pressure caused by the force is 90 N/m².

Initial amount of force, F₁ = 22 x 10³ N

Initial amount of pressure produced, P₁ = 110 N/m²

Final amount of force exerted, F₂ = 18 x 10³ N

Pressure is defined as the amount of force acting on an object per unit area of the object.

So, we can say that the force and pressure are directly proportional.

F ∝ P

So, F₁/P₁ = F₂/P₂

Therefore, the final amount of pressure caused by the force is,

P₂ = F₂P₁/F₁

P₂ = 18 x 10³x 110/22 x 10³

P₂ = 18/0.2

P₂ = 90 N/m²

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Question :-

Answer :-

\( \rule {180pt} {2pt} \)

Given :-

To Find :-

Solution :-

As per the provided information in the given question, we have been given that the Radius of the Watch is 5 meter , Time is given 2 seconds . And, we have been asked to calculate the Velocity of the Watch .

For calculating the Velocity , we will use Formula :-

Therefore , by Substituting the given values in the above Formula :-

⇒ Velocity = Displacement / Time

⇒ Velocity = 5 / 2

⇒ Velocity = 2.5

Hence :-

\( \underline {\rule {180pt} {4pt}} \)

⇒ Velocity = Displacement / Time

⇒ Velocity = 5 / 2

⇒ Velocity = 2.5

two objects colliding inelastically in one dimension. Kinetic friction is not conserved, but momentum is. (a) Two equal-mass objects initially move in the same direction.

What does physics mean when it refers to friction?

The force preventing sliding against one another of hard substrates, fluid sheets, and material components is known as friction. There are various kinds of friction: ... Friction between two surfaces causes kinetic energy from moving surfaces to be converted into infrared radiation

What does kinetic friction look like?

In the case of static friction or kinetic friction, the force of tension is always applied to counteract actual or potential movement between the contacting materials. A bent stone sliding all along ice, for instance, encounters a kinetic force that slows it down.

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The correct answer to find the radius of curvature (in m) of the path is: 0.00239 m.

The radius of curvature of the path of a 0.230 MeV proton moving perpendicularly to the 1.45 T field of a cyclotron can be found using the formula:

r = (mv)/(qB)

Where r is the radius of curvature, m is the mass of the proton, v is the velocity of the proton, q is the charge of the proton, and B is the magnetic field strength.

First, we need to convert the energy of the proton from MeV to Joules:

E = 0.230 MeV × 1.602 × 10^-13 J/MeV = 3.6846 × 10^-14 J

Next, we can use the formula E = (1/2)mv^2 to find the velocity of the proton:

v = √(2E/m) = √((2 × 3.6846 × 10^-14 J)/(1.67 × 10^-27 kg)) = 3.495 × 10^6 m/s

Now we can plug in the values into the formula for the radius of curvature:

r = (mv)/(qB) = ((1.67 × 10^-27 kg)(3.495 × 10^6 m/s))/((1.602 × 10^-19 C)(1.45 T)) = 0.00239 m

Therefore, the radius of curvature of the path of the proton is 0.00239 m.

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Answer: 3 s

Explanation:

i took the test in physics :)

The time taken by the wave to travel the distance is 3 seconds.

What is meant by frequency of a wave ?

Frequency of a wave is defined as the number of oscillations or cycles completed by the wave within one second.

Here,

Distance travelled by the wave, d = 600 m

Wavelength of the wave, λ = 0.4 m

Frequency of the wave, f = 500 Hz

The expression for the velocity of the wave is given by,

v = fλ

v = 500 x 0.4

v = 200 m/s

Therefore, the time taken by the wave to travel the distance of 600 m can be given as,

Time taken = displacement/velocity

So,

t = d/v

t = 600/200

t = 3 s

Hence,

The time taken by the wave to travel the distance is 3 seconds.

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Answer:

The greatest common factor (GCF) is the greatest factor that is common to two or more numbers (they share it). The greatest common factor of two (or more) numbers is the product of all the prime factors the numbers have in common.

Explanation:

The force acting on the system of two blocks connected by a rope passing over a pulley is -13.26 N.

The system of two blocks connected by a rope passing over a pulley are M1 and M2, where M1 rests on the triangle edge to the left of the pulley, which makes an angle of theta subscript 1 with the base of the triangle. The coefficient of friction between box M1 and the surface is mu subscript 1. M2 rests on the triangle edge to the right of the pulley, which makes an angle of theta subscript 2 with the base of the triangle.

The coefficient of friction between box M2 and the surface is mu subscript 2. The system sits atop a scalene triangle whose long edge forms the base. The pulley is attached to the apex of the triangle.M1 has a mass of 2.25 kg and is on an incline of angle 1=42.5∘ that has a coefficient of kinetic friction 1=0.205. M2 has a mass of 5.55 kg and is on an incline of angle 2=33.5∘ that has a coefficient of kinetic friction 2=0.105.The free-body diagram of M1 shows that the weight of M1 acts straight downwards (vertically) and the normal force acts perpendicular to the slope.

The force of friction opposes the motion and acts opposite to the direction of motion.M1 = 2.25 kgTheta subscript 1 = 42.5 degreesMu subscript 1 = 0.205g = 9.81 m/s²In the free-body diagram of M2, the normal force acts perpendicular to the incline of the slope, the weight of the object acts vertically downwards and parallel to the incline, and the force of friction opposes the motion and acts opposite to the direction of motion.M2 = 5.55 kgTheta subscript 2 = 33.5 degreesMu subscript 2 = 0.105g = 9.81 m/s²The tension in the string is the same throughout the rope. Since the masses are being pulled by the same rope, the acceleration of the objects is the same as the acceleration of the rope.

The tension in the string is directly proportional to the acceleration of the objects and the rope.A system of two blocks connected by a rope passing over a pulley has a total mass of M. The acceleration of the system is given by the formula below:a = [(m1-m2)gsin(θ1) - μ1(m1+m2)gcos(θ1)] / (m1 + m2)Where, μ1 = 0.205 is the coefficient of friction of block M1θ1 = 42.5 degrees is the angle of the incline of block M1M1 = 2.25 kg is the mass of block M1M2 = 5.55 kg is the mass of block M2g = 9.81 m/s² is the acceleration due to gravitysinθ1 = sin 42.5 = 0.67cosθ1 = cos 42.5 = 0.75The acceleration of the system is:a = [(2.25-5.55)(9.81)(0.67) - (0.205)(2.25+5.55)(9.81)(0.75)] / (2.25 + 5.55)a = -1.7 m/s² (the negative sign indicates that the system is accelerating in the opposite direction).

The force acting on the system is given by:F = MaWhere M is the total mass of the system and a is the acceleration of the system. The total mass of the system is:M = m1 + m2M = 2.25 + 5.55M = 7.8 kgThe force acting on the system is:F = 7.8(-1.7)F = -13.26 N (the negative sign indicates that the force is acting in the opposite direction).

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The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D

A unit of measurement is a specified magnitude of a quantity that is established and used as a standard for measuring other quantities of the same kind. It is determined by convention or regulation.

The base SI units are meter, kilogram, second, kelvin, ampere, candela, and mole

The unit of energy is Joules which is equivalent in mks unit as Kg m²s⁻²

Thus, The kilogram is an SI base unit that makes up part of the unit of energy, therefore the correct answer is option D

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Answer:

The ball would be traveling fastest at point (C).

Point (D) appears to be the same height as point (C) but the ball would probably have lost some speed on rebounding,

If we observe the skies from the surface of another planet, we can see  heliocentric solar system, that is, all the planets are rotating around the sun.

The Heliocentric model is an astronomy theory that places the Sun at the centre of the cosmos, with the Earth and other planets revolving around it. In the past, geocentrism, which put the Earth at its center, was countered by heliocentrism.

Aristarchus of Samos first offered the idea that the Earth revolves around the Sun in the third century BC after being influenced by a theory put forth by Philolaus of Croton (c. 470 – 385 BC).

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Goal posts at the end of football field are padded as a safety measure to players who might run into them,these thick paddings of the goal posts are done to prevent injuries to the players because the padding of the goal post increases the time of impact and this in-turn decreases the force on the the players body or the force it will have when a player's body hit against it and therefore decreasing the force applied to bring the player to a stop.

We can also say that it increases the time of collision between the player's body and the post.

Answer:

Iron deficiency

Explanation:

or more scientifically explained as decreased hemoglobin levels in your blood but still caused by lack of iron.

If an airplane is  is accelerating down a runway at 2.5 m/s². It's velocity changes 2.5 m/s in each second.

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates.

Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.

Hence, the velocity of the airplane changes 2.5 m/s in each second  when it  is accelerating down a runway at 2.5 m/s².

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Answer:

it takes light approximately 0.25 minutes to travel from the Sun to Neptune.

Explanation:

The distance from Neptune to the Sun is 30.0 times farther than from the Earth to the Sun, so it's 30.0 * 93 million miles = 2,790 million miles.

The speed of light is approximately 186,282 miles per second, so it takes light approximately 2,790 million miles / 186,282 miles/second = 14.97 seconds to travel from the Sun to Neptune.

Since there are 60 seconds in a minute, this is equivalent to 14.97 seconds / 60 seconds/minute = 0.25 minutes.

So, The distance from Neptune to the Sun is 30.0 times farther than from the Earth to the Sun, so it's 30.0 * 93 million miles = 2,790 million miles.

The speed of light is approximately 186,282 miles per second, so it takes light approximately 2,790 million miles / 186,282 miles/second = 14.97 seconds to travel from the Sun to Neptune.

Since there are 60 seconds in a minute, this is equivalent to 14.97 seconds / 60 seconds/minute = 0.25 minutes.

so  it takes light approximately 0.25 minutes to travel from the Sun to Neptune.

The change in velocity in y direction, if the runner accelerates at 0.350 m/s² at 52° angle is 2.83 m/s.

Acceleration of an object is the rate of change in velocity. It is a vector quantity having both direction and magnitude.

a = Δv/t

The initial velocity u = 2.88 m/s

a = 0.350 m/s²

the time t = u/a = 2.88 /0.350 = 8.2 s.

vy = uy + ay t

uy = u sin θ = 2.88 sin 52 =2.84 m/s

ay = 0.350 sin 52 = 0.345 m/s²

then vy = 2.84 m/s + (0.345 m/s²) 8.22 s = 5.67 m/s

then change in velocity in the y-direction is calculated as:

Δy = vy - uy

    = 5.67 m/s  - 2.84 m/s = 2.83 m/s

Therefore, the change in velocity in y-direction Δy for the runner is 2.83 m/s.

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The scenario presented is an example of negative punishment.

Negative punishment involves the removal of a desirable stimulus or the addition of an aversive stimulus in response to a behavior, with the goal of decreasing the likelihood of that behavior occurring again in the future.

In this case, the desirable stimulus that was removed is the son's ability to engage in leisure activities like playing hockey, and the aversive stimulus that was added is the scolding from the parent. By experiencing this consequence, the son may be less likely to forget his chores in the future in order to avoid the negative outcome.

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If A box of mass 210 kg is pulled from rest with a string of tension 1300n inclined at 35° to the horizontal. if the box moved with a speed of 10m/s and the frictional force between the box and surface is 100 n, Then the distance covered by the box is 10.89 meters.

To calculate the distance covered by the box, we need to analyze the forces acting on it and apply the work-energy principle.

Given:

Mass of the box, m = 210 kg

Tension in the string, T = 1300 N

The angle of inclination, θ = 35°

Frictional force, f = 100 N

Initial speed, u = 0 m/s

Final speed, v = 10 m/s

First, let's resolve the tension force into components parallel and perpendicular to the incline. The parallel component of the tension force can be calculated as:

T_parallel = T * cos(θ)

Next, let's calculate the net force acting on the box along the incline. The net force is given by:

Net force = T_parallel - f

Now, using Newton's second law, we can calculate the acceleration (a) of the box:

Net force = m * a

From the given information, we have the final velocity (v), initial velocity (u), and acceleration (a). We can use the following kinematic equation to calculate the distance covered (s):

v^2 = u^2 + 2as

Rearranging the equation, we get:

s = (v^2 - u^2) / (2a)

Now, let's plug in the given values and calculate the distance covered:

T_parallel = 1300 N * cos(35°) ≈ 1067.35 N

Net force = 1067.35 N - 100 N = 967.35 N

a = (967.35 N) / (210 kg) ≈ 4.61 m/s^2

s = (10 m/s)^2 - (0 m/s)^2 / (2 * 4.61 m/s^2) ≈ 10.89 m

Therefore, the distance covered by the box is approximately 10.89 meters.

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Answer:

A) W =250J B) Power = 125 J/s  C) Work = 250 J Power = 250 J/s

Explanation:

Work = Force*distance

A:

\(W = 10kg*10m/s^2*2.5m\\W = 250 J\\\)

B:

Power is J/s

Power = 250J/2.0s = 125 J/s

C:

Work stays the same

Power increases to 250 J/s

Answer:

Explanation:

D.

Thermodynamics is the study of  how different   types of energy is transferred through the  chemical systems

Answer: Thermodynamics is the flow of energy, heat, and work.

Explanation: This is seen in the formula for the first law of thermodynamics,  U = Q - W, or “The change of the internal energy of a system (U) is equal to the heat absorbed (Q) minus the work done by that system (W).”

Answer:

Homogeneous mixtures

Explanation:

I think so because homogeneous means mixed mixtures

Answer:

a

  \(B = 0.0533 \ T\)

b

  \(B = 0.04 \ T\)

Explanation:

From the question we are told that

   The inner radius is \(r = 1.2 \ cm = 0.012 \ m\)

   The  outer radius is  \(r_o = 2.4 \ cm = \frac{2.4}{100} = 0.024 \ m\)

    The nu umber of turns is  \(N = 960\)

    The current it is carrying is  \(I = 2. 5 A\)

Generally the magnetic field is mathematically represented as

      \(B = \frac{\mu_o * N* I }{2 * \pi * r }\)

Where  \(\mu_o\) is the permeability of free space with a constant value    

            \(\mu = 4\pi * 10^{-7} N/A^2\)

And the given distance where the magnetic field is felt is  r =  0.9 cm  =  0.009 m

Now  substituting values

     \(B = \frac{ 4\pi * 10^{-7} * 960* 2.5 }{2 * 3.142 * 0.009 }\)

    \(B = 0.0533 \ T\)

    Fro the second question the distance of the position considered from the center is  r =  1.2 cm  =  0.012 m

So the  magnetic field is  

        \(B = \frac{ 4\pi * 10^{-7} * 960* 2.5 }{2 * 3.142 * 0.012 }\)

        \(B = 0.04 \ T\)

The magnetic field at a distance of 0.9 cm from the center of the toroid is 0.053 T.

The magnetic field at a distance of 1.2 cm from the center of the toroid is 0.04 T.

The given parameters;

The magnetic field at a distance of 0.9 cm from the center of the toroid is calculated as follows;

\(B = \frac{\mu_o NI}{2\pi r} \\\\B = \frac{(4\pi \times 10^{-7})\times (960) \times (2.5)}{2\pi \times 0.009} \\\\B = 0.053 \ T\)

The magnetic field at a distance of 1.2 cm from the center of the toroid is calculated as follows;

\(B = \frac{\mu_o NI}{2\pi r} \\\\B = \frac{(4\pi \times 10^{-7})\times (960) \times (2.5)}{2\pi \times 0.012} \\\\B = 0.04 \ T\)

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Answer:

6.1 cm

61 N

35°

Explanation:

Given scale:  1 cm = 10 N

Parallelogram method (attachment 1)

When two vectors are represented by two adjacent sides of a parallelogram by direction and magnitude, the resultant of these vectors is represented (in magnitude and direction) by the diagonal of the parallelogram starting from the same point.

F₁ = 30 N = 3 cm

F₂ = 40 N = 4 cm

Draw a 3 cm horizontal line from the head of vector F₂ that is parallel to and the same length as vector F₁.

Draw a 4 cm line from the head of vector F₂ that is parallel to and the same length as vector F₁.

You have now constructed a parallelogram.

The diagonal of the parallelogram represents the resultant force vector.

Measure the length of the diagonal:

Measure the angle between the x-axis and the resultant force vector:

Polygon method (attachment 2)

If a number of vectors can be represented in magnitude and direction by the sides of a polygon taken in the same order, then their resultant is represented in magnitude and direction by the closing side of the polygon taken in the opposite order.

F₁ = 30 N = 3 cm

F₂ = 40 N = 4 cm

Draw a 3 cm horizontal line from the origin along the x-axis.  This is vector F₁.

Draw a 4 cm line at 60° to the x-axis from the head of F₁.  The is vector F₂.

Close the polygon by drawing a line that connects the tail of vector F₁ to the head of vector F₂.  This is the resultant force vector.

Measure the length of the closing side of the polygon:

Measure the angle between the x-axis and the resultant force vector.

Note: The resultant vector length, force and direction are the same for both methods.

Using parallelogram method for vector addition of two vectors with magnitude 40 Newton and 30 Newton at an angle of 60 degree the resultant vector is equal to 60.8 Newton and its length is equal to 6.08 cm.

The parallelogram rule says that on placing two vectors such that they have the same initial point, and complete into a parallelogram, then the sum of the vectors is the directed diagonal that starts at the same point as the vectors.

Polygon law of vector addition states that if a number of vectors can be represented in magnitude and direction by the sides of a polygon taken in the same order, then their resultant is represented in magnitude and direction by the closing side of the polygon taken in the opposite order.

Given:

Magnitude of first vector (a) = 30N

Magnitude of second vector (b) = 40N

Direction between two vectors= 60°

Using the law of parallelogram vector addition we get the value of resultant vector (R)-

\(R = \sqrt{(900+1600+1200)}\)

R = 60.8 newton

Now it is given that 1 cm in graph represents 10 newton.

Therefore, 60.8 newton will comprise a length = 60.8/10

60.8 newton will comprise a length = 6.08cm

The direction of the resultant vector is equal to 34.7° .

Here only two vectors are given therefore polygon law of vector addition becomes exactly like parallelogram vector addition.

Therefore,

\(R = \sqrt{(900+1600+1200)}\)

R = 60.8 newton

60.8 newton will comprise a length of 6.08cm.

Vector addition of two vectors with magnitude 40 Newton and 30 Newton at an angle of 60 degree the resultant vector is equal to 60.8 Newton and its length is equal to 6.08 cm.

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