two speakers are emitting identical sound waves with a wavelength of 4.0 m. the speakers are 8.0 m apart and directed toward each other, as shown:

Answers

Answer 1

Constructive, Destructive, and Something in Between, per the provided statement.

What are frequency and wavelength?

The distance between two wave crests, which also applies to troughs, is known as the wavelength. The unit of frequency in frames a second (Hz), which is the quantity of vibrations that cross a specific area in a second (Hertz).

What is the name for a light wavelength?

The horizontal space between the wave's two peaks is known as a wavelength. Light's wavelength is used to measure it (in nanometers). Typically, wavelengths in the 400–700 nanometer (nm), or one hundred thousandth of a meter, range are considered to be visible light.

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Related Questions

A 82.0-kg person is being pulled away from a burning building as shown in the figure below.
(a) Calculate the tension in the first rope, T1, if the person is momentarily motionless. (Enter the magnitude only.)
(b) Calculate the tension in the second rope, T2, if the person is momentarily motionless. (Enter the magnitude only.)

Answers

The tension in the first rope, T1, is 805 N.

The tension in the second rope, T2, is 805 N.

(a) The tension in the first rope, T1, can be calculated by balancing the forces acting on the person in the vertical direction. The weight of the person, mg, acts downwards, and the tension in the rope, T1, acts upwards. Therefore:

T1 = mg

where m is the mass of the person and g is the acceleration due to gravity. Substituting the given values:

T1 = (82.0 kg)(9.81 m/s²) = 805 N

Therefore, the tension in the first rope, T1, is 805 N.

(b) The tension in the second rope, T2, can be calculated by balancing the forces acting on the person in the horizontal direction. The tension in the first rope, T1, acts to the left, and the tension in the second rope, T2, acts to the right. Therefore:

T2 = T1

Substituting the value of T1 obtained in part (a):

T2 = 805 N

Therefore, the tension in the second rope, T2, is 805 N.

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when a 2.0 kg mass is connected to the bottom, the new equilibrium position is 5.0 cm lower. the mass is then pulled down and released. it is observed that the speed of the mass is 2.1 m/s when the mass passes the original equilibrium position (before the mass was attached). how far down were the mass and spring pulled together when released?

Answers

The mass and spring were pulled down 0.122 m from their original equilibrium position before being released.

Let's start by using Hooke's Law, which states that the force exerted by a spring is proportional to its displacement from its equilibrium position. Mathematically, we can express this as

F = -kx

where F is the force exerted by the spring, x is the displacement from the equilibrium position, and k is the spring constant.

We can use this equation to find the spring constant, k. We know that when a 2.0 kg mass is connected to the spring, the new equilibrium position is 5.0 cm lower. So, the displacement of the spring from its original equilibrium position is

x = 5.0 cm = 0.05 m

The force exerted by the spring is equal to the weight of the mass, which is

F = mg = (2.0 kg)(9.81 m/s^2) = 19.62 N

Using Hooke's Law, we can write

19.62 N = -k(0.05 m)

Solving for k, we get

k = -392.4 N/m

Now, let's consider the motion of the mass after it is pulled down and released. We know that at the equilibrium position, the net force on the mass is zero, so the kinetic energy of the mass is converted entirely into potential energy stored in the spring. Therefore, we can write

1/2 mv^2 = 1/2 kx^2

where m is the mass of the object (which we know is 2.0 kg), v is the speed of the mass when it passes the original equilibrium position (which we know is 2.1 m/s), x is the displacement of the spring from its original equilibrium position when the mass is released (which we want to find), and k is the spring constant (which we just calculated).

Plugging in the values we know and solving for x, we get

x = sqrt((mv^2)/k) = sqrt((2.0 kg)(2.1 m/s)^2/(392.4 N/m)) = 0.122 m

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Who was known for being a pilot and an astronaut that walked on the moon?.

Answers

Answer:

Neil Armstrong was the astronaut

Who was known for being a pilot and an astronaut that walked on the moon?.

does anyone knows how to do this ?

does anyone knows how to do this ?

Answers

Answer:

yea it seems pretty simple.... just follow the instruction

TRUE/FALSE. a recently discovered extrasolar planet appears to be rockier and denser than earth. it is 16 times as massive as earth, but its diameter is only twice that of earth.

Answers

The acceleration of free fall on the planet is given by 39.2 m/s².

What is  the acceleration of free fall?

The acceleration of free fall is the acceleration at which a body falling freely experiences the gravitational pull of a single planet. It is also known as a gravitational acceleration.

Value of  the acceleration of free fall on earth is 9.8 m/s².

The formula of acceleration of free fall on any planet is given by:

g₁ = GM/R²

As the extrasolar planet appears to be rockier and denser than earth. it is 16 times as massive as earth, but its diameter is only twice that of earth, the acceleration of free fall on any planet is given by:

g₁ = GM/R² = 16GMe/(2Re)² = 4 GMe/Re = 4g = 4× 9.8 m/s² = 39.2 m/s² .

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The guitarist shortens the oscillating length of the properly tuned D-string by 0.15 m by pressing on the string with a finger. What is the fundamental frequency, in hertz, of the new tone that is produced when the string is plucked?

Answers

Answer:

The fundamental frequency is "190.52 Hz".

Explanation:

The given question is incomplete, please find attachment of the complete problem.

The given values are:

Frequency,

f = 146.8 Hz

Length of D-string,

L = 0.61

As we know,

⇒ \(f = \frac{v}{2L}\)

On putting the given values, we get

⇒ \(146.8 = \frac{v}{(2\times 0.61)}\)

⇒       \(v=146.8\times 1.22\)

⇒       \(v=179 \ m/s\)

So,

The new length will be:

⇒  \(f = \frac{179}{(2\times 0.47)}\)

⇒     \(=\frac{179}{0.94}\)

⇒     \(=190.52 \ Hz\)

The guitarist shortens the oscillating length of the properly tuned D-string by 0.15 m by pressing on

The fundamental frequency, in hertz, of the new tone that is produced when the string is plucked is 168.84 Hz

Let assume that the oscillating length on the guitar is 0.62 m,

If the guitarist shortens the oscillating length of the properly tuned D-string by 0.15 m.

Then the new length of the oscillating string L' = (0.62 - 0.15 )m = 0.47 m

The fundamental frequency of the new tone can be computed by using the formula:

\(\mathbf{f = \dfrac{1}{2L'} \sqrt{\dfrac{T}{m/L}}}\)

where;

mass (m) is assumed to be 1.5× 10⁻³ kg, and;tension T = 4Lf² m

T  = 4× 0.62× 147 × 1.5× 10⁻³  (assuming old fundamental frequency = 147)

T  = 4× 0.62× 147 × 1.5× 10⁻³

T = 80.39 N

\(\mathbf{f = \dfrac{1}{2 \times 0.47} \sqrt{\dfrac{80.39}{1.5 \times 10^{-3}/0.47}}}\)

f = 168.84 Hz

Therefore, the fundamental frequency, in hertz, of the new tone that is produced when the string is plucked is 168.84 Hz

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Carlos listed some advantages and disadvantages of using nonrenewable resources. Which best describes Carlos's error? Coal is not plentiful anywhere. Coal generates very little energy. Ores do not make many useful products. Ores must be processed.

Answers

Answer:

This question is incomplete as it lacks the table that shows the advantages and disadvantages of the two mentioned nonrenewable source of energy (coal and ore). However, the question can be answered based on general understanding.

The answer is D. Ores must be processed.

Explanation:

Energy can be of two major sources namely: renewable and nonrenewable sources. Based on the mentioned area in this question, NONRENEWABLE SOURCES OF ENERGY are those sources of energy that cannot be replenished or replaced when exhausted. They are utilized faster than they form. Examples of nonrenewable sources of energy are coal, ores, fuel etc.

According to this question, Carlos listed some advantages and disadvantages of using nonrenewable resources. However, among the listed disadvantages, Carlo's error is that he included that: ORES MUST Be PROCESSED.

Ores are rock materials that contain metals, which are extracted and purified in a series of processing techniques. Hence, ORES NEED PROCESSING making Carlo's claim erroneous.

Answer:

Carlos listed some advantages and disadvantages of using nonrenewable resources.

Which best describes Carlos’s error?

Coal is not plentiful anywhere.

Coal generates very little energy.

Ores do not make many useful products.

Ores must be processed.

Explanation:

the answer is D

ons: READ each question below and ANSWER each part of the question.
Questions:
1. Ms. Woodard walks 1 m between each desk in her classroom. She walks
from desk 1 to desk 3, from desk 3 to desk 4, and finally from desk 4 back to
desk 2.
a. DRAW Ms. Woodard's path to all the desks here:
a.
a.
What DISTANCE has Ms. Woodard traveled? CONVERT (change) your answer to
millimeters.
What is Ms. Woodard's DISPLACEMENT?

Answers

Ms. Woodard has traveled a distance of 5 m.

Ms. Woodard's displacement is 1 m.

ons: READ each question below and ANSWER each part of the question.Questions:1. Ms. Woodard walks 1 m

A balloonist drops his camera from a height of 100 m while his balloon is ascending at 5 m/s. How
long did it take to reach the ground?

Answers

20 i think is the answer

How would gravity cause planets to move if they did not have inertia?

A. Planets would orbit Jupiter, the largest planet
B. Planets would run into one another
C. Planets would be pulled into the sun
D. Planets would move in a straight line away from the sun​

Answers

i’d think the answer would be C. i’m just kinda guessing but my thought process is this (as simply as i can put it because physics is confusing):

so for example say you throw a ball across a flat surface. inertia is what keeps the ball rolling straight in a line, so unless you were to maybe put your hand in front of the ball or something, it would just go straight forever.

this is what happens with the planets. they go in a straight line, but since there’s gravity, the planets are also being pulled towards the sun. so gravity and inertia are why the planets orbit in the circle pattern they do. so when we remove inertia, we’re removing the state in which the planets keep going straight while being pulled towards a center point (the sun). this causes gravity to be the only factor in the planets orbiting. so that being said, the planets would just be pulled towards the sun. :)

Answer: Planets would be pulled into the sun

Explanation:

This is the correct answer.

a small but rigid u shaped wire carrying a 5.0 a current is placed inside a solenoid the solenoid is 17 cm long and has 800 loops of wire and the current in each loop is

Answers

The current in each loop of the solenoid is 6.25 A. current is placed inside the solenoid, we can assume that the current passing through each loop is the same.

The solenoid is 17 cm long and has 800 loops of wire. Since the wire carrying the 5.0 A current is placed inside the solenoid, we can assume that the current passing through each loop is the same.

To find the current in each loop, we can use the formula:

I_solenoid = N * I_wire

Where:

I_solenoid is the current in the solenoid,

N is the number of loops,

I_wire is the current in the wire.

Plugging in the values, we have:

I_solenoid = 800 * I_wire

5.0 A = 800 * I_wire

Solving for I_wire, we get:

I_wire = 5.0 A / 800 = 0.00625 A

Therefore, the current in each loop of the solenoid is 6.25 A.

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A 2. 00-kg object is attached to an ideal massless horizontal spring of spring constant 100. 0 N/m and is at rest on a frictionless horizontal table. The spring is aligned along the x-axis and is fixed to a peg in the table. Suddenly this mass is struck by another 2. 00-kg object traveling along the x-axis at 3. 00 m/s, and the two masses stick together. What are the amplitude and period of the oscillations that result from this collision? 0. 300 m, 1. 26 s 0. 424 m, 5. 00 s 0. 424 m, 0. 889 s 0. 300 m, 0. 889 s 0. 424 m, 1. 26 s

Answers

The correct option is A, the amplitude and period of the oscillations that result from this collision are 0.300 m in 1.26s.

The expression for Period of spring is,

\(T = 2\pi\sqrt{\frac{2m}{k} }\)

Here, m is the mass of the spring and k is the spring constant

Substitute 2 kg

for m

and 100N/m

for k

in equation \(T = 2\pi\sqrt{\frac{2m}{k} }\)

and solve for T .

\(T = 2\pi\sqrt{\frac{(2)2 kg}{100 N/m} }\)

T = 1.26s

In physics, amplitude refers to the maximum displacement or distance moved by a wave from its equilibrium or mean position. It is a measure of the intensity or strength of a wave, and it is usually represented as the height of the crest or depth of the trough of the wave.

The amplitude of a wave can be measured in various units, depending on the type of wave and the context in which it is being studied. For example, the amplitude of a sound wave is measured in decibels (dB), while the amplitude of an electromagnetic wave is measured in volts per meter (V/m). Amplitude plays an important role in the behavior of waves. It determines the energy carried by the wave and affects other properties such as frequency, wavelength, and phase.

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Complete Question: -

A 2.00-kg object is attached to an ideal massless horizontal spring of spring constant 100.0 N/m and is at rest on a frictionless horizontal table. The spring is aligned along the x-axis and is fixed to a peg in the table. Suddenly this mass is struck by another 2.00-kg object traveling along the x-axis at 3.00 m/s, and the two masses stick together. What are the amplitude and period of the oscillations that result from this collision

A) 0.300 m, 1.26 s

B) 0.300 m, 0.889 s

C) 0.424 m, 0.889 s

D) 0.424 m, 1.26 s

E) 0.424 m, 5.00 s

What was not a positive benefit of Spanish exploration in Oklahoma?
A.
Future interactions between the Spanish and French would have a buffer zone.
B.
Historians gained a written account of Oklahoma in the 15th and 16th centuries.
C.
Geographers gained new knowledge about the continent of North America.
D.
The Spanish and American Indian tribes enjoyed exclusively friendly relations.

Answers

the answer is:

d. the spanish and american indian tribes enjoyed exclusively friendly relations.

Answer:

b. the spanish and american indian tribes enjoyed exclusively friendly relations.

Explanation:

How much power is theoretically available from a mass flow of 1 000 kg/s of water that falls a vertical distance of 100 m?

Answers

The theoretically available power from a mass flow of 1,000 kg/s of water falling a vertical distance of 100 m is 9,800,000 Watts or 9.8 Megawatts.

The power available from a mass flow of water can be calculated using the formula:

Power = (mass flow rate) * g * h

where:

- Power is the available power

- mass flow rate is the rate at which mass flows (in kg/s)

- g is the acceleration due to gravity (approximately 9.8 m/s^2)

- h is the vertical distance the water falls (in meters)

mass flow rate = 1,000 kg/s

vertical distance = 100 m

Using the formula, we can calculate the power:

Power = (1,000 kg/s) * (9.8 m/s^2) * (100 m)

Power = 9,800,000 Watt

Therefore, the theoretically available power from a mass flow of 1,000 kg/s of water falling a vertical distance of 100 m is 9,800,000 Watts or 9.8 Megawatts.

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What is the unit for intensity? Describe the relationship between intensity and area of the wave.

Answers

The unit for intensity is watts per square meter (W/m²) and the intensity of a wave is proportional to the square of the amplitude of the wave and inversely proportional to the square of the distance from the source of the wave.

Intensity is a measure of the power or energy of a wave per unit area, and it is proportional to the square of the amplitude of the wave. This means that the intensity of a wave increases as the amplitude of the wave increases, and it decreases as the distance from the source of the wave increases.

The relationship between intensity and area of the wave can be described by the inverse square law. According to this law, the intensity of a wave is inversely proportional to the square of the distance from the source of the wave. This means that as the distance from the source of the wave increases, the intensity of the wave decreases, and as the area of the wave increases, the intensity decreases.

For example, if you move twice as far away from a source of sound waves, the intensity of the sound waves will decrease by a factor of four. Similarly, if you double the area over which the waves are spread out, the intensity of the waves will be halved.

In summary, the unit for intensity is watts per square meter.

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how many square feet are there in an area of 1 sq metres? ______ physical universe

Answers

There are 10.76 square feet in an area of 1 square meter.

In geometry, the area is the amount of space enclosed by a two-dimensional figure. It is measured in square units such as square centimeters, square meters, and square feet. The area of a square is the length of one of its sides squared. For example, if a square has a side length of 3 meters, its area would be 3 x 3 = 9 square meters.

We have to use conversion units to find the answer to the given question.

According to the conversion units, we have that:

1 square meter is equal to 10.76 square feet.

Therefore, the answer is 10.76 square feet.

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10. What is the acceleration of a 1000 kg car subject to a 500 N net force?

Answers

Answer:

0.5m/s^2

Explanation:

We can use the formula [ F = ma ] but solve for "a" since that is what we are looking for.

F = ma

F/m = a

We know the net force and mass so substitute those values and simplify.

500/1000 = 0.5m/s^2

Best of Luck!

1. What is the atomic mass of the new atom?
2. What is the atomic number of the new atom?
3. What is the symbol of the new atom?
4. What type of decay is demonstrated here?

1. What is the atomic mass of the new atom?2. What is the atomic number of the new atom?3. What is the

Answers

1. The atomic mass of the new atom be 243.  Hence, Option (e) is correct.

2. The atomic number of the new atom be 94. Hence, Option (f) is correct.

3. The symbol of the new atom be Pu.  Hence, Option (h) is correct.

4. Alpha decay is demonstrated here. Hence, Option (i) is correct.

What is Alpha decay?

A type of radioactive decay known as "alpha decay" occurs when an atomic nucleus emits an alpha particle as it changes or decays into a new atomic nucleus. Here, the newly produced atom will have a four-less atomic mass number and a two-less atomic number. A helium nucleus is another name for the alpha particle that was released. The alpha particles have a positive charge and a sizeable mass.

Ernest Rutherford investigated how radiation is deflected through a magnetic field to distinguish alpha decay from other types of radiation. Given that the particles carry a +2e charge, the alpha decay would deflect a positive charge.

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A diverging lens has a focal length of magnitude 21.8 cm.
(a) Locate the images for each of the following object distances.
43.6 cm
distance cm
location ---Select--- in front of the lens behind the lens
21.8 cm
distance cm
location ---Select--- in front of the lens behind the lens
10.9 cm
distance cm
location ---Select--- in front of the lens behind the lens
(b) Is the image for the object at distance 43.6 real or virtual?
realvirtual
Is the image for the object at distance 21.8 real or virtual?
realvirtual
Is the image for the object at distance 10.9 real or virtual?
realvirtual
(c) Is the image for the object at distance 43.6 upright or inverted?
uprightinverted
Is the image for the object at distance 21.8 upright or inverted?
uprightinverted
Is the image for the object at distance 10.9 upright or inverted?
uprightinverted
(d) Find the magnification for the object at distance 43.6 cm.
Find the magnification for the object at distance 21.8 cm.
Find the magnification for the object at distance 10.9 c

Answers

A diverging lens has a focal length of magnitude 21.8 cm and the images are located behind the lens.

(a) u = -10.9 cm

1/v= 1/10.9 - 1/21.9

v= 21.8cm

Behind the lens.

(b) 1. Virtual

   2. Virtual

   3. Real

(c) m = v/u

1. Erect/ Upright

2. Upright

3. Inverted

(d) m = v/u

1. m = -43.6/-43.6 = 1. Magnification = 1.

2. infinity.

3. m = 21.8 / -10.9 = -2. Magnification = -2.

Therefore, these are the answers for above given question.

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Since astronauts in orbit are apparently weightless, a clever method of measuring their masses is needed to monitor their mass gains or losses to adjust diets. One way to do this is to exert a known force on an astronaut and measure the acceleration produced. Suppose a net external force of 53.5 N is exerted and the astronaut's acceleration is measured to be 0.978 m/s2. Calculate her mass in kilograms.

Answers

Given,Net external force applied on astronaut, F = 53.5 N

Acceleration produced, a = 0.978 m/s²

We know that,

Newton's Second Law states that,F = m * a

where,F is the net external force applied

m is the mass of the object

a is the acceleration produced by the object.

Now, substituting the given values in the above equation, we get;

53.5 N = m * 0.978 m/s²

Solving for mass, we have;

m = 53.5 / 0.978

= 54.7 kg.

Therefore, the mass of the astronaut is 54.7 kg, which is a clever method of measuring the astronaut's mass in the absence of gravity. This helps to monitor the mass gain or losses and adjust diets in order to keep the astronauts healthy.

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4. Look at the picture to the left. Both of the people on the left are pulling with
a force of 30N to the left. On the right side of the rope, one person is pulling
with 35 N to the right, and the other person is pulling with 20N to the right.
What is the net force on the rope?

Answers

Friction force is what pulls an item to the left while it is travelling to a right on the a rough surface (f). The net force exerted on the rope was equal to a distinction two loads exerted on it operating in opposite directions.

What is an illustration of a force pulling an object?

An item is pulled towards the centre of the Earth by gravity. A ball that has been tossed above slows down and returns to the earth. This is as a result of gravity bringing the soccer ball back to the ground. The pull of gravity affects everything on Earth.

What is an example of a force or pull?

When a force propels an object inside the direction of a person pulling it, such action is referred to as pulling. Opening a door, plucking a guitar string, drawing water from a well, or drawing a curtain are all examples of pull-related actions.

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If the acceleration is 600m/s/s and the mass is 300kg, calculate the for the force

Answers

Answer:

180000N

Explanation:

Given parameters:

Acceleration  = 600m/s²

Mass  = 300kg

Unknown:

Force  = ?

Solution:

From Newton's second law of motion;

    Force  = mass x acceleration

Force  = 300 x 600 = 180000N

A mountain climber has a mass (with all of their equipment) of 95, point, 0, k, g,95.0kg. If they were perfectly efficient, and ate 500, g,500g of chocolate (providing 11, point, 1, M, J,11.1MJ of chemical energy), how high could they climb?

Answers

Answer:

11900 meters

Explanation:

Use the Potential energy = mgh formula, substituting these in to get 11.1x10^6 = 95 x 9.81 x h.

Rearrange to make h the subject and the answer given is 11900 (3sig.fig.)

The maximum height to which he can climb will be 1.168 x 10⁴ meters.

What is potential energy?

The potential energy of a body is the energy of the body due it position. The potential energy always exist for two bodies which are in mutual interaction with each other for example by a force. For body a on earth, the potential energy of the body - earth system is -

E[P] = mgh

Given is a mountain climber that has a mass of 95 kg.

We can write -

Mass of climber = [M] = 95 kg

Energy gained by eating the chocolate = [E] = 11.1 MJ = 1.11 x 10⁷ joules

Assume that the height achieved achieve by the climber is [h] meters

Therefore, the potential energy gained at that height will be equal to 11 MJ

Therefore -

mgh = 1.11 x 10⁷

95 x 10 x h = 1.11 x 10⁷

95 x 10 x h = 1110 x 10⁴

h = (1110 x 10⁴)/950

h = 1.168 x 10⁴ meters

Therefore, the maximum height to which he can climb will be 1.168 x 10⁴ meters.

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5. Chad wants to investigate whether adding a solute to water affects its boiling point and freezing point. He set up an experiment and recorded the boiling and freezing point in degrees Celsius (°C), his results are in the data table.

EFFECT OF SOLUTE ON BOILING AND FREEZING POINTS

Test
A.Water
B.Water + 10 grams of salt
C.Water + 20 grams of salt
D.Water +30 grams of salt
E.Water + 40 grams of salt
Boiling Point (°C)
A.100.0
B.100.5
C.101.0
D.101.5
E.102.0
Freezing Point (°C)
A.0
B.-2
C.-4
D.-6
E.-8

Based on the data, which statement would be the best conclusion?
A. Adding salt to water decreases the boiling point.
B. Adding any solute to water increases the boiling point.
C. Adding salt to water increases the boiling point and decreases the freezing point.
D. Adding any solute to water increases the boiling point and decreases the freezing point.​

Answers

Answer:

Explanation:

C. Adding salt to water increases the boiling point and decreases the freezing point.

An underlying theme of astronomy is that the...
a) fundamental physical laws differ randomly from galaxy to galaxy, but they can be learned for a given galaxy by detailed observation.
b) fundamental physical laws governing the universe change in a predictable way with increasing distance from Earth.
c) the universe is a hodgepodge of unrelated things behaving in arbitrary and unexplainable ways.
d) entire universe is governed by a single set of fundamental physical laws.

Answers

Answer:

d) entire universe is governed by a single set of fundamental physical laws.

Explanation:

Astronomy is the field of study that researches and studies about the objects beyond Earth. The phenomena occurring in the universe and their effects on the planet Earth are all death under the subject of astronomy. The discovery and the origin of the Earth, the heavenly bodies and their existence are covered under astronomy. The fundamental laws of the astronomy proves to be equivalent for all the bodies. These laws are universal that helps in the research of the science of universe.

If the resistance remains constant and the voltage doubles, what effect will that have on the power? A. The power will remain the same. B. The power will decrease by a factor of 2. C. The power will decrease by a factor of 4. D. The power will increase by a factor of 2. E. The power will increase by a factor of 4.

Answers

Answer:

D

Explanation:

6. What is the mass of an object that requires a force of 30 N to accelerate at 5 m/s??

Answers

According to the Newton's second law,

\(F=ma\)

where F is the force on the object, m is the mass of the obect and a is the acceleration of the object.

Substituting the known values,

\(30=m\times5\)

Thus, the mass of the object is,

\(\begin{gathered} m=\frac{30}{5} \\ m=6\text{ kg} \end{gathered}\)

Hence, the mass of the object is 6 kg.

Determine the acceleration of a soccer ball if a footballer may strike a ball of mass 500g with a force of 200 N

Answers

The acceleration of the soccer ball is determined as 400 m/s².

What is the acceleration of the soccer ball?

The acceleration of the soccer ball is calculated by applying Newton's second law of motion as follows;

Mathematically, the formula for Newton's second law of motion is given as;

F = ma

where;

m is the mass of the object in kga is the acceleration of the object is m/s²

The acceleration of the soccer ball is calculated as;

a = ( F ) / ( m )

a = ( 200 N ) / ( 0.5 kg )

a = 400 m/s²

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A child and sled with a combined mass of 50. 0 kg slide down a frictionless hill that is 7. 34 m high. If the sled starts from rest, what is its speed at the bottom of the hill?.

Answers

The speed of sledge at the bottom of the hill is 11.99 m/s .

One conserves energy. The total of the kinetic and potential energy at the beginning and end of the process are equal.

PEi+KEi=PEf+KEf

Recall the PE and KE formulas:

PE is defined as m g h, where m is mass, g is gravitational acceleration, and h is height.

Where m is the mass and v is the velocity, KE = \(\frac{1}{2} mv^2\)applies.

Get our variables ready.

g=9.8 Gravity is 9.8 m/s.

Unknown height at the beginning is 7.34m

Initial speed is 0 m/s; vi=0

The final height is 0 (hf=0).

Final speed is is v

9.8 ( 7.34) + 0 = 9.8 (0) + \(v^2\)/2

71.932 x 2 = \(v^2\)

v = 11.99 m/s

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If the incident angle of a light ray is 30 degrees to the normal, what will the reflected angle be?

Answers

The incident ray will have an angle of reflection of 30 degrees (made with a surface normal to the mirror surface). The reflected ray will make an angle of 60 degrees (90 - 30 degrees) with the mirror surface.
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