use the above information to answer the questions, Run 1 Distance between the intervals position (m) AB= 1,3 BC=1,3 CD 1,3 DE = 1,3 EF = 1,3 Perioel (P)=1/25×5 =0,2sec Run2 Distance between the intervals position (m) AB= 1,5 BC = 1,8 CD = 2 DE 2,2 EF=2,4 Draw a graph of position versus time for 2.1 Run 1 2.2 Run 2
Answers
Using the charter system conversation in the right angled value triangle we apply distance formula and get the G-plot value of 9.876 u.
How is position determined in velocity - time?The movement in a graph is determined through the two perpendicular axis in which the first coordinate represents the distance to be traveled in the x axis and the second coordinate shows the distance to be traveled in the y axis .
What is distance formula ?If you want to determine the distance between any two point in a graph the distance formula is used in such case the distance formula is applied like Pythagoras theorem.
Given:
A (1,3)
Period = 0.2 seconds
B (1,5)
Period = 0.5 seconds
Before applying distance formula we need to simplify the given value into charter system.
Where,
A become a substituted value for the argument of square on the basic structure.
Since A symmetrical is that of right angled triangle we can use the basic charter values.
Therefore A now become A(π,2)
Similarly B become B(e,nπ)
Using distance formula to find the graph plot we get:
AB = 5.6π - e×3.14
AB = 9.876
where AB is the distance between A and B.
Therefore using the charter system conversation in the right angled value triangle we apply distance formula and get the G- plot value of 9.876 u.
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Related Questions
Gary is interested in the effect of lighting on focus so he tests participants ability to focus on a complex task under three different lighting conditions: bright lighting (M = 10), low lighting (M = 5), neon lighting (M = 4). His results were significant, F(2, 90) = 5.6, p < .05. What can Gary conclude? O a. Bright lights make it easier to focus than low lights or neon lights. O b. Type of lighting has no effect on focus. O c. Bright lights make it more difficult to focus than low lights or neon lights. O d. Type of lighting has some effect on focus.
Answers
Based on the given information, Gary conducted an experiment to test the effect of lighting on participants' ability to focus. He compared three different lighting conditions: bright lighting, low lighting, and neon lighting. The results showed a significant effect, with an F-value of 5.6 and p-value less than 0.05. Now we need to determine what Gary can conclude from these results.
The F-value and p-value are indicators of statistical significance in an analysis of variance (ANOVA) test. In this case, the F(2, 90) value suggests that there is a significant difference in participants' ability to focus across the three lighting conditions.
Since the p-value is less than 0.05, Gary can reject the null hypothesis, which states that there is no difference in focus ability between the different lighting conditions. Therefore, he can conclude that the type of lighting does have some effect on focus.
However, the specific nature of the effect cannot be determined solely based on the information provided. The mean values indicate that participants performed best under bright lighting (M = 10), followed by low lighting (M = 5), and neon lighting (M = 4). This suggests that bright lights may make it easier to focus compared to low lights or neon lights, but further analysis or post-hoc tests would be required to provide a more definitive conclusion.
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Consider two future observatories in space. Observatory X consists of a single 50-meter telescope. Observatory Y is an interferometer consisting of five 10-meter telescopes, spread out over a region 100 meters across. Which observatory can detect dimmer stars, and which one can see more detail in its images
Answers
The size and aperture of the telescopes determine its ability to gather light
and reveal details.
A) Observatory X can detect dimmer stars and Observatory Y reveals more
details.
Reasons:
The benefits of using several small telescopes included the production
high resolution images of bright objects such as binary stars that reveal
more details similar to a telescope with a very large aperture, with a
process known as interferometry, through which a star's diameter can be
determined.
The benefit of a large telescope is its ability to gather light from a source,
thereby making possible to detect a dim light source, such as dimmer
stars.
Therefore;
The single large telescope in observatory X can detect dimmer stars while
the interferometer consisting of five 10-meter telescopes, spread out over a
region 100 meters across can see more detail in its images.
The correct option is; A) Observatory X can detect dimmer stars and
Observatory Y reveals more details.
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Question options:
A) Observatory X can detect dimmer stars and Observatory Y reveals more
details.
B) Observatory Y can detect dimmer stars and Observatory X reveals more
details.
C) Observatory X both detect dimmer stars and reveals more details
D) Observatory Y both detect dimmer stars and reveals more details
a.) What happens when a force is applied to an atom? b.) What is this called?
Answers
Answer:
it binds the negatively charged electrons to the positively charged atomic nucleus.
Explanation:
its called Electromagnetic Force
Two charges of 5 x 10-6 C are a certain distance apart. These two positive charges experience 3.6 N of repelling electrical force between them. How far apart are these charges?
Answers
Answer:
r = 0.2499 m
Explanation:
Use Coulomb's Law: \(F_{e} = kq_{1}q_{2} / r^{2}\) where Fe is the electric force, q1 and q2 are the 2 charges respectively, k is a constant (8.99*10^9 N • m^2 / C^2) and r is the distance.
\(3.6 N = (8.99*10^{9})(5*10^{-6})(5*10^{-6}) / r^{2}\)
r = 0.2499 m
The distance that should be apart from these charges should be considered when the r = 0.2499 m.
Calculation of the distance apart:Since
Two charges of 5 x 10-6 C are a certain distance apart. These two positive charges experience 3.6 N of repelling electrical force between them
So
here we use Columb law
Electric force = k * two charges * two charges)r^2
3.6 N = (8.99*10^9) * ( 5 * 10^-6) * (5*10^-6)r^2
r = 0.2499 m.
Hence, The distance that should be apart from these charges should be considered when the r = 0.2499 m.
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Consider the simple model of the zoom lens shown in Fig.34.43a in the textbook. The converging lens has focal length f1=12cm, and the diverging lens has focal length f2=−12cm. The lenses are separated by 4 cm as shown in Fig.34.43a. A)Now consider the model of the zoom lens shown in Fig.34.43b, in which the lenses are separated by 8 cm. For a distant object, where is the image of the converging lens shown in Fig.34.43b, in which the lenses are separated by 8 cm? B)The image of the converging lens serves as the object for the diverging lens. What is the object distance for the diverging lens? C)Where is the final image?
Answers
In the given setup, the image of the converging lens is formed 12 cm behind it, and the final image is formed 144/13 cm behind the diverging lens.
A) In the model shown in Fig.34.43b, where the lenses are separated by 8 cm, the image of the converging lens (f1=12 cm) is formed at a distance behind the converging lens. This distance can be determined using the lens formula:
1/f1 = 1/v1 - 1/u1,
where f1 is the focal length of the converging lens and u1 is the object distance.
Since the object is assumed to be at infinity (distant object), the object distance u1 is equal to infinity. Plugging these values into the lens formula, we get:
1/f1 = 1/v1 - 1/infinity.
As 1/infinity approaches zero, the equation simplifies to:
1/f1 = 1/v1.
Rearranging the equation, we find:
v1 = f1 = 12 cm.
Therefore, the image of the converging lens is formed at a distance of 12 cm behind the lens.
B) The image formed by the converging lens (v1 = 12 cm) serves as the object for the diverging lens. The object distance for the diverging lens (f2 = -12 cm) is equal to the image distance of the converging lens, which is 12 cm.
C) To determine the position of the final image, we can use the lens formula for the diverging lens:
1/f2 = 1/v2 - 1/u2,
where f2 is the focal length of the diverging lens and u2 is the object distance.
Substituting the given values, we have:
1/-12 = 1/v2 - 1/12.
Simplifying the equation, we find:
-1/12 = 1/v2 - 1/12.
Combining the fractions, we get:
-1/12 = (12 - v2) / (12v2).
Cross-multiplying and rearranging the equation, we find:
v2 = 144/13 cm.
Therefore, the final image is formed at a distance of 144/13 cm behind the diverging lens.
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You placed the bottom section of the loop in the magnetic field and measured the force upon it when current was flowing through the wire. Imagine instead that both the bottom and one side of the loop were placed in the magnetic field (but not the top or other side). What would be the net direction of the force upon this loop?
Answers
If both the bottom and one side of the loop were placed in the magnetic field (but not the top or other side), the net direction of the force upon this loop would be upwards.
When an electric current flows through a wire in a magnetic field, a magnetic force is generated on the wire. This force is perpendicular to both the direction of the current and the direction of the magnetic field, according to Fleming's Left-Hand Rule. In the scenario described in the question, the current is flowing through the wire on one side of the loop and not on the other side. As a result, the magnetic force will act on the side of the loop where the current is flowing, in a direction perpendicular to both the current and the magnetic field. This will cause the loop to move upwards, as the force acting on the side of the loop will be greater than the force acting on the bottom. Therefore, the net direction of the force upon this loop will be upwards.
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a person throws a ball at an angle of 30 o with the horizontal with a velocity of 32 m/s. as the ball is thrown, a second person is running past the thrower at a constant velocity. at what velocity must this second person run so that she may catch the ball as it hits the ground?
Answers
If the second player moved horizontally, the speed he must maintain to catch the ball is 27.67 m/s.
What is the range of the projectile (ball)?
The range of the projectile is the maximum horizontal distance travelled by the ball.
R = (u²sin(2θ)) / (g)
where;
u is the initial velocityθ is the angle of projectiong is acceleration due to gravityR = (32² x sin(2 x 30) ) / (9.8)
R = 90.49 m
The time of motion of the ball is calculated as follows;
R = uₓt
where;
uₓ is the horizontal component of the velocityR = ucosθ(t)
t = R/ucosθ
t = (90.49) / (32 cos30)
t = 3.27 seconds
If the second player moved horizontally, the speed he must maintain to catch the ball is calculated as;
R = Ut
U = R/t
U = (90.49) / (3.27)
U = 27.67 m/s
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2. The velocity of a moving body increases from 10 m/s to 15 m/s in 5 seconds. Calculate its acceleration. 1m/s²]
Answers
Answer:
a=1m/s²
Explanation:
note that the moving body is accelerating from 10m/s to 15m/s, so in this case the initial velocity is 10mls, and the final velocity is 15m/s, and the body makes this increase in just 5seconds. so looking at what we've been given in the question, we can now calculate acceleration.
so our Data is;
V= 15m/s
U= 10m/s
t= 5m/s
a=?
we can find acceleration by using these two formulas;
1) V= U + at
15= 10+ a(5)
15=10+5a
make 5a the subject of the formula, and to make it the subject of the formula, we need to transpose 10m/s, and when we transpose it, it will
become a negative number because of crossing the equal sign
15-10=5a
5=5a
divide throughout by 5 to remain with a
5/5=5a/5
1=a
:. a=1m/s²
then the second formula is;
a= (V-U)/t
a=(15-10)/5
a=5/5
a=1m/s²
what is the bad side of the Integration /eclectic theory ?
Answers
The Integration/Eclectic Theory is a broad concept encompassing various fields and concepts. Without specific context, providing a comprehensive answer is challenging. Nevertheless, potential drawbacks or criticisms associated with integration or eclectic approaches .
Integration or eclectic approaches can be discussed:
Lack of coherence: Integrating different perspectives, frameworks, or methodologies from multiple disciplines may broaden understanding but can also result in a lack of coherence or consistency. The components may not seamlessly fit together, leading to a fragmented or unclear theoretical framework.
Overgeneralization: Eclectic approaches may incorporate diverse ideas without critically evaluating their compatibility or applicability in specific contexts. This can lead to overgeneralization or oversimplification of complex phenomena, disregarding important nuances or specific factors.
Inconsistencies and contradictions: Combining different theories or approaches carries the risk of encountering inconsistencies or contradictions among the components. This can create confusion and hinder drawing clear conclusions or making accurate predictions.
Lack of depth: Eclectic or integrative theories aiming to cover a wide range of perspectives may sacrifice depth. By attempting to include multiple viewpoints, the theory may not delve deeply into any one perspective, resulting in a superficial understanding of the underlying concepts.
Difficulty in application: Applying eclectic theories can be challenging due to a lack of clear guidelines or principles. The absence of a unified framework makes it difficult to translate the theory into practical applications or develop specific interventions based on its recommendations.
It is important to note that these drawbacks are not inherent to all integration or eclectic theories. Some approaches successfully integrate multiple perspectives and provide valuable insights. However, it is crucial to critically evaluate the strengths and weaknesses of any theoretical framework to ensure its suitability for a particular context or research question.
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Types of Spectra 5) Stars like our Sun have low-density, gaseous atmospheres surrounding their hot, dense cores. If you were looking at the spectra of light coming from the Sun (or any star), which of the three types of spectrum would be observed? Explain your reasoning.
Answers
The spectrum observed from the Sun (or any star) would exhibit an absorption spectrum. This is because the outer gaseous atmosphere of the star absorbs specific wavelengths of light, resulting in dark absorption lines in the spectrum.
In the cooler, lower-density outer atmosphere, where white light from the star travels, some atoms or molecules in the atmosphere absorb photons with particular energy. In the spectrum, these absorptions show up as black lines at specific wavelengths. The specific set of absorption lines that each element or molecule generates results in a distinctive pattern that can be used to identify the elements that are present in the star's atmosphere.
The absorption spectrum offers insightful data on the chemical make-up and physical characteristics of the star. Astronomers can ascertain the elements present, their abundances, and other characteristics like the temperature, pressure, and velocity of the star's atmosphere by examining the absorption lines.
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Thirty Joules of energy are transferred out of a system. The energy is lost through heat, mechanical, and electrical energy. If mechanical energy took up 10 J and electrical energy took up 5 J, how many Joules were lost through heat energy?
OPTIONS
5 J
15 J
30 J
45 J
Answers
Answer:
its 15 J i belive
Explanation:
Describe specifically why a one-time pad is completely unbreakable. What happens if we try and brute-force
something encrypted with a one-time pad?
Encrypt the message "yellowstone" using the key "wolf" using the vignere cipher.
Answers
A one-time pad is a type of encryption that is completely unbreakable if it is done correctly. It works by generating a random key that is at least as long as the message being encrypted. The key is then combined with the message using an XOR operation.
This produces a ciphertext that cannot be decrypted without the key. The key is used only once and then discarded, hence the name "one-time pad". A one-time pad is completely unbreakable because there is no pattern to the key that can be used to decrypt the message. Each character in the key is generated randomly and independently of the other characters. Therefore, the key is completely unpredictable. Even if an attacker knows the key length and has access to the ciphertext, they cannot use any techniques to decrypt it.
This is because there is no pattern to the ciphertext that can be used to determine the key.The only way to decrypt a one-time pad is to have the key. If an attacker tries to brute-force the encryption by trying all possible keys, they will generate every possible message that is the same length as the original message. This means that the ciphertext is completely meaningless without the key. It is therefore important to keep the key secret and ensure that it is only used once. ,Message: yellow stone Key: wolf To encrypt the given message using the vigenere cipher, we follow the steps below:Step 1: Write the message and key in a tabular form as shown below. To keep the process organized, we use the letters of the key to label the columns.
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Hello please .
How far would a person run in seconds at an average speed of 7ms-1
Answers
At an average speed of 7m/s, the distance covered in one second is 7 meters.
What is the distance covered in one second?Speed is simply referred to as distance traveled per unit time.
It is expressed mathematically as;
Speed = Distance ÷ time.
Given the data in the question;
Speed = 7m/sElapsed time = 1 secondDistance traveled = ?Plug the given values into the above formula and solve for distance traveled.
Speed = Distance ÷ time
Distance = Speed × Time
Distance = 7m/s × 1.0s
Distance = 7ms/s
Distance = 7m
Therefore, in a second, the person covers 7 meters.
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PLEASE HELP
A pendulum is in a spacecraft to measure
acceleration during lift off. Before the launch, its period
is 6.5 X 10-3 s. At a point during lift off, its period is 3.1
X 10-3 s. What is the acceleration at this point?
Answers
Answer:
im just 15 yearsold hehhez i dont know that either
If the object's initial velocity is 0 m/s , what is the velocity of an object at t = 8.0s
Answers
Answer:
0_8.0
8.0m/s
Explanation:
8.0m/s is the velocity of an object .
Consider the causal LTI system with impulse response h(t) = u(t). Prove that this system is an integrator, i.e., the output of the system is the integral of the input. X(t) 1 2 t t(2-t) 0 h(t) 1 b 1 21 Figure 1: Input function and impulse response
Using the input and impulse response given in Fig.1, find and sketch the output calculating x(t) * h(t). You can either use the integral definition of the convolution or the Reflect-and-Shift approach.
Answers
The impulse response of the LTI system is h(t) = u(t).Let's find the output for the given input and impulse response using the integral definition of the convolution, given as follows:x(t) h(t) = ∫x(τ)h(t-τ)dτWe have to consider two cases when t < 0 and t ≥ 0.
Case 1:
When t < 0x(t) h(t) = ∫x(τ)h(t-τ)dτWhen t < 0, h(t - τ) = u(t - τ) = 0 for all τ > t. Therefore, for this range of t, x(t) h(t) = 0.Case 2:
When t ≥ 0x(t) h(t) = ∫x(τ)h(t-τ)dτ= ∫x(τ)u(t-τ)dτSince u(t - τ) = 1 for τ ≤ t and u(t - τ) = 0 for τ > t, we can split the integral into two parts:x(t) h(t) = ∫x(τ)u(t-τ)dτ= ∫x(τ)u(t-τ)dτ + ∫x(τ)u(τ-t)dt= ∫x(τ)u(t-τ)dτ + ∫x(t-τ)u(τ)dτ= ∫0tu(τ)x(t-τ)dτ + ∫t∞u(τ)x(t-τ)dτ= ∫0tx(t-τ)dτAs the function x(t) is given,we can evaluate the integral:
x(t) h(t) = ∫0tx(t-τ)dτ= ∫0t(2-τ)dτ= 2t - t²/2Let's plot the graph of the output function using the given input and impulse response:Graph of the output functionAbout Impulse ResponseIn signal processing and control theory, the impulse response, or impulse response function, of a dynamic system is its output when presented with a brief input signal, called an impulse. More generally, the impulse response is the reaction of any dynamic system in response to some external change.
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what is voltage? please help
Answers
Explanation:
Voltage is the pressure pushing electrons through a power circuit. Express in volts
You can always search on go ogle to give you an easier answer.
who plays rob.lox , adopt me here?
Answers
Want to be friends?
A fan rotating with an initial velocity of 1000 rev/min is switched off. In 2 seconds, the angular velocity decreases to 200 rev/min. Assuming angular acceleration is constant, how many revolutions does the blade undergo during this time?
Answers
Answer:
easy
Explanation:
Find the radius of the orbit when (a) an electron or (b) a proton moves perpendicular to a magnetic field of 0.86 T with a speed of 6.47 X 10^5 m/s.
Answers
The radius of the orbit when (a) an electron is 1.13 X 10^-3 m or (b) a proton moves perpendicular to a magnetic field of 0.86 T with a speed of 6.47 X 10^5 m/s is 1.08 X 10^-3 m.
The radius of the orbit for a charged particle moving perpendicular to a magnetic field can be calculated using the formula
r = mv/qB,
where m is the mass of the particle, v is its velocity, q is its charge, and B is the magnetic field strength. For an electron and a proton moving perpendicular to a magnetic field of 0.86 T with a speed of 6.47 X 10^5 m/s, the radius of the orbit can be calculated.
The radius of the orbit for a charged particle moving perpendicular to a magnetic field can be calculated using the formula r = mv/qB, where m is the mass of the particle, v is its velocity, q is its charge, and B is the magnetic field strength.
For an electron with a charge of -1.602 X 10^-19 C, mass of 9.109 X 10^-31 kg, and a velocity of 6.47 X 10^5 m/s perpendicular to a magnetic field of 0.86 T, the radius of the orbit is calculated to be 1.13 X 10^-3 m.
For a proton with a charge of +1.602 X 10^-19 C, mass of 1.673 X 10^-27 kg, and a velocity of 6.47 X 10^5 m/s perpendicular to a magnetic field of 0.86 T, the radius of the orbit is calculated to be 1.08 X 10^-3 m.
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What is the normal force acting on a 70kg person riding a drop tower when they are falling
at an acceleration of 9.8 m/s^2
Answers
Answer:
686 N
Explanation:
OH BOY, NEWTONS LAWS OF MOTION!
look at this:
\(F = ma\)
a fun fact is that acceleration 9.8 m/s^2 is actually GRAVITY.
so lets do this and rewrite the formula...
\(F = 70kg * 9.8 m/s^2\)
lets multiply 70 and 9.8
we get 686 N.
if you want to be technical about it...... the answer should only have two sig figs. so it would be... \(6.9 * 10^{2}\) N
NICE!
This is an example of which scientific practice?
Answers
The example of the scientific practice is missing here but it should always involve the application of the scientific method.
What is the scientific method?The scientific method is a series of steps by which researchers can collect empirical evidence that enables them to test hypotheses and generate scientific theories.
The scientific method starts with the observation of a given phenomenon from the real world, which then enables the raising of a question that in turn enables the formulation of a plausible explanation called hypothesis.
In conclusion, the example of the scientific practice is missing here but it should always involve the application of the scientific method.
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W= 346 J & P= 12.9 W…calculaue the total time.
Answers
The total time is approximately 26.82 seconds.
the total time, we need to know the relationship between power, work, and time. Power is defined as the rate at which work is done, so we can use the formula:
Power = Work / Time
Time = Work / Power
We are given the values of work and power, so we can substitute them into the formula and solve for time:
Time = Work / Power = 346 J / 12.9 W ≈ 26.78 seconds
The total time is the length of time needed to finish a specific task or procedure. In this instance, we were given the energy W in joules and the power P in watts, and we calculated the total time using the formula t = W / P. The formula compares the energy consumed with the power being given, and the outcome is the length of time needed to perform the activity.
It's vital to remember that the calculation's units must match; in this case, the units for energy and power are joules and watts, respectively. Around 26.82 seconds were obtained as the total. Where power and energy consumption are important concepts, such as in physics, engineering, and technology, this computation is helpful.
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You push a 13‑kg table in the cafeteria with a horizontal force of 20 N, but the table does not move. You then push the table with a horizontal force of 25 N, and it accelerates at 0.26 m/s2. What, if anything, can you conclude about the coefficients of static and kinetic friction?
Answers
The coefficient of static fiction is 0.15 and the coefficient of kinetic friction is 0.19
What is coefficient of static and kinetic friction?Coefficient of static friction is the maximum ratio of applied force to normal force with no motion. We all know Frictional force is a force which opposes motion. Coefficient of static friction of the table is :
coefficient of static friction = applied force/normal reaction
applied for when it's stable = 20N
normal reaction = m×g = 13× 10= 130N
therefore the coefficient of static friction = 20/130 = 0.15
The coefficient of kinetic friction (μk) is the ratio of the friction force to the normal force experienced by a body moving on a dry, non-smooth surface.
μk = moving force/ normal reaction
therefore μk = 25/130
μk = 0.19
therefore the coefficient of kinetic friction is 0.19
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Can you list out the signs (positive or negative) of objective and eyepiece of microscope (simple and compund) and telescope?
NO SPAM ❌❌
Answers
For compound microscope: the objective lens produces a real, inverted image that is then magnified by the eyepiece lens to produce an upright, virtual image.
For simple microscope: The objective lens produces a real, inverted image that is viewed directly by the eye without the need for an eyepiece lens.
For telescope: The objective lens or mirror produces a real, inverted image that is then magnified by the eyepiece lens to produce an upright, virtual image. The eyepiece can be positive or negative depending on the desired magnification.
What are objective and eyepieces?The following are some signs (positive or negative) of objective and eyepiece lenses in microscopes and telescopes:
Objective lens:
Positive sign (+): used for normal, upright specimens; brings light rays to a focus in front of the lensNegative sign (-): used for inverted specimens; brings light rays to a focus behind the lensEyepiece lens:
Positive sign (+): increases the magnification of the image and produces a larger virtual imageNegative sign (-): decreases the magnification of the image and produces a smaller virtual imageLearn more about objective and eyepiece here: https://brainly.com/question/14055649
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Which resistors in the circuit are connected in parallel?
Answers
Answer:
I think it's C - sorry if I'm wrong
Answer:
B and C
Explanation:
Based on the law of conservation of energy, which statement is correct?
A Energy is always being added to all parts of the Universe.
B. Energy is often destroyed in some parts of the Universe.
O C. Energy in a closed system cannot change forms.
D.
Energy in an isolated system remains constant.
Answers
Answer:
D. Energy in an isolated system remains constant
Explanation:
I recently took this test and this was the correct answer. Please like if this helped you! :)
The statement "Energy in an isolated system remains constant" is correct which is based on the law of conservation of energy option (D) is correct.
What is the law of conservation of energy?The law conservation of energy can be defined as the energy that cannot be created either it cannot be destroyed it only can change from one state to another state.
As we know, from the definition of the law of conservation of energy,
The energy that cannot be created either cannot be destroyed.
According to the rule of conservation of energy, the energy in an isolated system doesn't change.
Thus, the statement "Energy in an isolated system remains constant" is correct which is based on the law of conservation of energy option (D) is correct.
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If an object has ____
particles (more mass), but is the same _____
then it will have more thermal energy
Answers
Big, mass
Unpolarized light passes through two polarizers whose transmission axes are at an angle of 35.0 ∘ with respect to each other. What fraction of the incident intensity is transmitted through the polarizers? I/I0=??
Answers
About 6.15% of the incident intensity is transmitted through the polarizers. When unpolarized light passes through a polarizer, only the component of the electric field vector that is parallel to the transmission axis is transmitted, while the component perpendicular to it is absorbed. If the light passes through another polarizer whose transmission axis is at an angle to the first polarizer, the intensity of the transmitted light depends on the relative orientation of the axes.
In this case, the transmission axes of the two polarizers are at an angle of 35.0 ∘ with respect to each other. We can use Malus' law to calculate the fraction of the incident intensity that is transmitted through the polarizers. Malus' law states that the intensity of light transmitted through a polarizer is proportional to the square of the cosine of the angle between the transmission axis and the polarization direction of the incident light.
Let I0 be the incident intensity of the unpolarized light, and I1 and I2 be the intensities of the light transmitted through the first and second polarizers, respectively. The first polarizer will transmit only half of the incident intensity, since the light is unpolarized and has equal components in all directions. Therefore, I1 = (1/2)I0.
The second polarizer will transmit a fraction of the light that depends on the angle between its transmission axis and the polarization direction of the light transmitted through the first polarizer. This angle is the sum of the angles between the first polarizer and the incident light and between the second polarizer and the transmitted light. Since the transmission axes are at an angle of 35.0 ∘ with respect to each other, this angle is 70.0 ∘. Therefore, the fraction of the intensity transmitted through the second polarizer is:
I2/I1 = cos²(70.0 ∘) = 0.123
Multiplying this by the intensity transmitted through the first polarizer gives:
I2 = (0.123)(1/2)I0 = 0.0615I0
Therefore, the fraction of the incident intensity that is transmitted through both polarizers is:
I/I0 = I2/I0 = 0.0615
So, about 6.15% of the incident intensity is transmitted through the polarizers.
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A beaver runs at a speed of 2.0\,\dfrac{\text m}{\text s}2.0 s m 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction with 45\,\text J45J45, start text, J, end text of kinetic energy.
Answers
Answer:
22.5kg
Explanation:
Since we not told wat to find, we can as well find the mass of the beaver.
Kinetic energy formula is expressed as;
KE = 1/2mv²
m is the mass
v is the speed
Given
KE = 45Joules
v = 2.0m/s
Substitute into the formula and get the mass
45 = 1/2m(2)²
45 = 2m
m =45/2
m = 22.5kg
Hence the mass of the beaver is 22.5kg