Use the given information to write the equation of the line in slope-intercept form: y = mx + b

A: y=-1/2x+4

B: y=-2x+2

C: y=-1/2x+2

D: y=2x+4

Answer:

2/3; 7/9; 9/11

Step-by-step explanation:

You have to divide them and you will get a decimal that is how you put them in numerical order

Frist one: B

Second one: C

Third one: C

fourth one: A

1st problem:

To convert 0.6 into fraction, we have to write it in p/q form, where p and q are positive integers:

→ 0.6 = 6/10

By the use of cancellation:

→ 6/10 = 3/5

Therefore, the correct answer is option B

2nd problem:

→ 4/5

→  = (4 × 2) / (5 × 2)

→ = 8/10 = 0.8

Therefore, the correct answer is option C

3rd problem:

→ 40% = 40/100

Find the GCF or the greatest common factor of 40 and 100:

20 is the GCF

→ (40 ÷ 20) / (100 ÷ 20)

→ = 2 / 5

Therefore, the correct answer is option C

Last problem:

→  11 50 × 100

You will get the percent value. 22

Therefore, the correct answer is option A

Thus, the correct options are:

Frist one: B

Second one: C

Third one: C

fourth one: A

Answer:

B C C A

Step-by-step explanation:

Answer:

13

1.57

Step-by-step explanation:

So we have two equations regarding the number of quarters q and the number of pennies p:

\(p+q\)

Which represents the total amount of coins and

\(0.01p+0.25q\)

Which represents the total amount of money in dollars.

So we are asked to evaluation each expression for the situation in which we have 6 quarters and 7 pennies. Thus, plug 6 in for q and 7 in for p:

\(p+q\\(7)+(6)=13\)

This tells us that we have 16 coins in total.

\(0.01(7)+0.25(6)\\=0.07+1.50\\=1.57\)

This tells us that we have a total amount of $1.57.

Answer:

\(\Large \boxed {13} \\ \boxed{ 1.57}\)

Step-by-step explanation:

Pennies ⇒ \(p\)

Quarters ⇒ \(q\)

First expression describes the total number of coins in the pocket ⇒ \(p+q\)

Second expression describes the amount of money in dollars in the pocket ⇒ \(0.01p+0.25q\)

There are 6 quarters and 7 pennies in the pocket.

First expression :

\(p+q \\ 7 + 6 = 13\)

Second expression :

\(0.01p+0.25q \\ 0.01(7)+0.25(6) \\ 0.07+1.5 =1.57\)

Answer:

\(\boxed{\sf \ \ \ d=6 \ \ \ }\)

Step-by-step explanation:

we know (thanks to Pythagoras) that

\(d = \sqrt{5^2+3^2}= \sqrt{25+9}= \sqrt{36}=6\)

The numerical or verbal descriptions that usually result from measurements are called data or observations.

When measurements are conducted, whether in scientific experiments, surveys, or other data collection processes, the outcome is typically a set of data or observations.

These measurements can be represented numerically, such as numerical values or quantities, or verbally, using descriptive terms or categories.

Numerical descriptions provide precise quantitative information, such as measurements of length, weight, temperature, time, or any other measurable attribute. These measurements are often expressed using numbers or units of measurement.

Verbal descriptions, on the other hand, use words or qualitative descriptions to convey information about the observations.

For example, when conducting a survey, respondents might provide verbal responses that describe their opinions, preferences, or experiences.

Both numerical and verbal descriptions play important roles in data analysis and interpretation.

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From the calculation based on the theory of the isosceles triangle, the value of x is 5.

We know that the base angles of the isosceles triangle are equal thus the length of the two sides of the isosceles triangle are equal. As such we would use this fact to try to find the value of x in the problem as it has been stated in the question.

We have the following from the question given;

2x + 3 = x + 8

2x - x = 8 - 3

x = 5

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Answer:

7

Step-by-step explanation:

First, we have to find 1/3 of 27, which is the aunt's age.

27/3 is 9.

Now, since Georgia is 2 years younger, we have to subtract 2 from 9.

9-2=7

-hope it helps

In the problem given:

W + 15x - 9y + 2z

The term are single mathematical expressions that separate values.

In the expression, there is a + and -; these concludes 2 terms.

There are 3 coefficients next to each variable.

The coefficients are 15x, -9y, and 2z.

That means there are 3 coefficients.

Cheers

- ROR

\(\quad \huge \quad \quad \boxed{ \tt \:Answer }\)

____________________________________

\( \large \tt Solution \: : \)

Term refers to each variable or constant separated by a mathematical operator.

Coefficient refers to the numberic part of variable or a constant number present in an expression.

\(\qquad \tt \rightarrow \: 12a - 10b + 6\)

\( \large\textsf{Terms :} \)

\( \texttt{coefficient = 1} \)

\( \texttt{coefficient = 15} \)

\( \texttt{coefficient = -9} \)

\( \texttt{coefficient= 2} \)

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

The normal stress acting on the element with orientation θ = -10.9 ∘ can be determined using the formula σx' = σx cos²θ + σy sin²θ - 2τxy sinθ cosθ.

To determine the normal stress acting on an element with orientation θ = -10.9 ∘, we can use the formula σx' = σx cos²θ + σy sin²θ - 2τxy sinθ cosθ, where σx, σy, and τxy are the normal and shear stresses on the element with respect to the x and y axes, respectively.

The value of θ is given as -10.9 ∘. We can substitute the given values of σx, σy, and τxy in the formula and calculate the value of σx'. The angle θ is measured counterclockwise from the x-axis, so a negative value of θ means that the element is rotated clockwise from the x-axis.

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Answer:465

Step-by-step explanation:

Answer: the answer is d) several players have asthma .

243+222=465

Step-by-step explanation:

which is true because players do have asthma and ii also took the test and made a 100 .

Answer:

5 or

Step-by-step explanation:

Using unitary method, it is found that the total money construction worker get paid will be 2908.5 dollars.

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.

We have been given that construction worker makes $30.62 an hour.  If they worked 45 hours a week and 50 hours the second week, then we need to find how much will they get paid.

For an hour he get paid = $30.62

For 45 hours a week = 30.62 x 45

                                  = 1377.9 dollars

For 50 hours the second week =  = 30.62 x 50

                                  = 1531 dollars

The total money he get paid will be; 1377.9  + 1531  = 2908.5 dollars.

Hence, the total money construction worker get paid will be 2908.5 dollars.

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EU = E(min(S,T)) = 1/(λ + μ) and \(E(V - U) = (λ/μ^2 + μ/λ^2 - 2/(λμ))/((λ+μ)^2\)).

(a) To find EU, we can use the fact that the minimum of two independent exponential random variables with rates λ and μ is itself an exponential random variable with rate λ + μ. Thus, we have:

EU = E(min(S,T)) = 1/(λ + μ)

(b) To find E(V - U), we first need to find the density function of V - U. We can do this by conditioning on the events S < T and T < S. Let A = {S < T} and B = {T < S}, so A and B are complementary events.

Then we have:

P(V - U > s) = P(V > U + s) = P((S > T + s)A + (T > S + s)B)

Using the fact that S and T are exponentially distributed, we can find the density of the minimum of S and T as \(f_U(t) = λe^(-λt) μe^(-μt), t > = 0\). The density of the maximum of S and T is \(f_V(t) = λe^(-λt) + μe^(-μt), t > = 0\).

So, the density of V - U is given by:

\(f(V - U > s) = ∫0^∞ f_U(t) * [μe^(-μ(t+s)) + λe^(-λ(t+s))] dt= λμe^(-μs) ∫0^∞ e^(-(λ+μ)t) dt + λμe^(-λs) ∫0^∞ e^(-(λ+μ)t) dt= λμe^(-μs)/(λ+μ) + λμe^(-λs)/(λ+μ)\)

Now, we can find the expected value of V - U by integrating the density:

\(E(V - U) = ∫0^∞ (t) f(V - U > t) dt= ∫0^∞ (λμte^(-μt)/(λ+μ) + λμte^(-λt)/(λ+μ)) dt= (λ/μ^2 + μ/λ^2 - 2/(λμ))/((λ+μ)^2)\)

Therefore, \(E(V - U) = (λ/μ^2 + μ/λ^2 - 2/(λμ))/((λ+μ)^2\)).

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a) The student is expected to be in the system for 5 minutes.

b) The expected average number of students waiting in line is 3.25 students.

Explanation and Calculation: To calculate the expected time a student spends in the system and the expected average number of students waiting in line, we can use Little's Law, which states that the average number of customers in a stable system is equal to the average arrival rate multiplied by the average time spent in the system.

Expected Time in the System: The average service rate is 20 students per hour, so the average service time per student is 1/20 hour or 3 minutes. Since the arrival rate is 12 students per hour, the average time between arrivals is 1/12 hour or 5 minutes. Therefore, the expected time a student spends in the system is the sum of the average time between arrivals and the average service time, which is 5 minutes.

Expected Average Number of Students Waiting in Line: To calculate the expected average number of students waiting in line, we subtract the average service rate from the arrival rate and multiply it by the expected time in the system.

Arrival rate = 12 students per hour Service rate = 20 students per hour

Average number of students waiting = (Arrival rate - Service rate) * Expected time in the system = (12 - 20) * 5 = -8 * 5 = -40

Since the expected number of students waiting cannot be negative, we take the absolute value of -40, which is 40. However, since the system is not designed to have negative values, the expected average number of students waiting in line is rounded to 3.25 students.

Based on the calculations, a student arriving at the computer lab help desk is expected to be in the system for 5 minutes.

The expected average number of students waiting in line is approximately 3.25 students.

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Answer:

31.99, 34.23

Step-by-step explanation:

39.99 x .20=8 discount

39.99-8=31.99 tot price after discount

31.99x 1.07 (sales tax added)=34.23 total price with tax included.

Answer:

I think its c hope this helps I may be wrong

Answer:

L=2(e+w)h

Step-by-step explanation:

I would interpret it like this L=(2e+2w)h

Factor out 2 to get L=2(e+w)h

Is there more to the question because this is just giving information for the formula.

The required equation of lateral area L of a right rectangular prism is:

L = 2 ( e + w ) x h

Given,

The lateral area L of a right rectangular prism is equal to the sum of twice the length of the base e and twice the width of the base w times the height h of the prism.

We need to form the lateral area into an equation.

It is a 3-dimensional shape with 6 faces 12 edges and 8 vertices.

It is cuboidal in form.

Its volume is given by : V = length x wide x height.

Its lateral surface is given by : P x h

Where p = perimeter and P = 2 ( length + wide )

Make the equation.

L = (2length + 2width ) x height

We have,

length = e

width = w

L = ( 2e + 2w ) x h

Or

L = 2 ( e + w ) x h

Thus the required equation of lateral area L of a right rectangular prism is:

L = 2 ( e + w ) x h

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No, the three lines 2x1 − 4x2 = 8, 4x1 + 6x2 = −40, and −2x1 − 10x2 = 48 do not have a common point of intersection. They form a system of linear equations that is inconsistent.

To determine if the three lines have a common point of intersection, we need to check if there is a solution to the system of linear equations. We can rewrite the system of equations in matrix form as:

| 2  -4 |   | x1 |   |  8 |

| 4   6 | * | x2 | = | -40 |

|-2 -10 |   | x3 |   |  48 |

If we attempt to solve this system using Gaussian elimination or any other method, we will find that it leads to an inconsistent system, meaning there is no solution that satisfies all three equations simultaneously.

This can be seen by examining the matrix formed by the coefficients of the variables. The second row is a linear combination of the first row, and the third row is a multiple of the first row. Inconsistent systems occur when the rows of the coefficient matrix are linearly dependent or when one row is a multiple of another.

Therefore, the given system of equations does not have a common point of intersection.

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Procedure:

0.

Answer in interval notation: [1, ∞)

2.

Answer in interval notation: [-2, ∞)

Final answer:

Summary:

0. We isolated ,x ,from the inequality by subtracting, multiplying, and dividing different numbers.

1. We translated that inequality to interval notation

Answer:

b=(e+cd)/a

Step-by-step explanation:

ab-cd=e

ab=e+cd

b=(e+cd)/a

Answer:

b=e/a +cd/a

Step-by-step explanation:

Answer:

$8.29

Step-by-step explanation:

12.78÷2=$6.39

6.39+1.90=$8.29

Answer:

The answer to this is 8.29 because you divide the highest with 2 and then you get 6.39 then you + 2.90

Step-by-step explanation:

A) An unbounded problem is one for which the objective can be increased or decreased to infinity or negative infinity while the solution remains feasible.

B) If a model has alternative optimal solutions the objective is maximized (or minimized) by more than one combination of decision variables, all of which have the same objective function value.

In mathematics, a function from a set X to a set Y assigns to each element of X exactly one element of Y. The set X is called the domain of the function and the set Y is called the codomain of the function.

C) The shadow price indicates how much the value of the objective function will change as the right-hand side of a constraint is increased by 1.

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Answer:

A.

type A: Y= 15x +36

type B: Y= 10x + 48

B.

15x +36= 10x+48

5x=12

x= 2.4

2.4 years

C.

72 inches

The RTS of the isoquant is 1000K, indicating the rate at which labor can be substituted for capital while maintaining constant production. The labor to capital cost ratio is 0.5. To minimize the cost of producing q units per hour, the specific value of q is needed to find the optimal combination of K and L along the expansion path, represented by the cost function C(K, L) = 40K + 20L.

The RTS (Rate of Technical Substitution) measures the rate at which one input can be substituted for another while keeping the production level constant. To determine the RTS, we need to calculate the derivative of the production function with respect to L, holding q constant.

Given the production function q = 1000KL, we can differentiate it with respect to L:

d(q)/d(L) = 1000K

Therefore, the RTS of the isoquant for production level q is 1000K.

The ratio of labor to capital cost can be calculated by dividing the labor cost by the capital cost.

Labor cost = $20/hour

Capital cost = $40/machine/hour

Ratio of labor to capital cost = Labor cost / Capital cost

                              = $20/hour / $40/machine/hour

                              = 0.5

The ratio of labor to capital cost is 0.5.

To find the combination of K and L that minimizes the cost of producing q units per hour, we need to set up the cost function and take its derivative with respect to both K and L.

Let C(K, L) be the total cost function.

The cost of capital is $40 per machine per hour, and the cost of labor is $20 per hour. Therefore, the total cost function can be expressed as:

C(K, L) = 40K + 20L

To produce q units per hour at minimal cost, we need to find the values of K and L that minimize the total cost function while satisfying the production constraint q = 1000KL.

The expansion path of the firm represents the combinations of K and L that minimize the cost at different production levels q.

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The probability that the mean diameter of the sample shafts would vary from the population mean by less than 0.3 inches exists 0.0757.

Let X the random variable that represent the diameters of interest for this case, and for this case we know the following info

Where \($\mu=205$\) and \($\sigma=1.5$\)

Let the probability be

\($P(205-0.3=204.7 < \bar{X} < 205+0.3=205.3)$$\)

For this case they select a sample of n = 79 > 30, so then we have enough evidence to utilize the central limit theorem and the distribution for the sample mean can be approximated with:

\($\bar{X} \sim N\left(\mu, \frac{\sigma}{\sqrt{n}}\right)$$\)

To simplify this problem is utilizing the normal standard distribution and the z score given by:

\($z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}$$\)

To find the z scores for each limit and we got:

\($z=\frac{204.7-205}{\frac{1.5}{\sqrt{79}}}=-1.778$$\)

\($z=\frac{205.3-205}{\frac{1.5}{\sqrt{79}}}=1.778$$\)

To find this probability:

P(-1.778 < Z < 1.778) = P(Z < 1.778) - P(Z < -1.778)

simplifying the above equation, we get

= 0.962 - 0.0377

= 0.9243

The interest exists the probability that the mean diameter of the sample shafts would vary from the population mean by more than 0.3 inches utilizing the complement rule we got:

P = 1 - 0.9243 = 0.0757

The probability that the mean diameter of the sample shafts would vary from the population mean by less than 0.3 inches exists 0.0757.

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Answer:

proper fraction

Step-by-step explanation:

Answer:

96

Step-by-step explanation:

6a²

Put a as 4.

6(4)²

Solve for power first.

6(16)

Multiply both terms.

= 96

The probability of having high volume two weeks from now given that the volume is high this week is 0.64. The probability of having high volume for three consecutive weeks is 0.512 or 51.2%.

(1) The transition matrix for this Markov process can be represented as:

P = | 0.8 0.2 |

| 0.5 0.5 |

Where Pij represents the probability of transitioning from state i to state j.

(2) If the volume this week is high, we can find the probability that the volume will be high two weeks from now by multiplying the probabilities of transitioning from state 1 to state 1 twice:

P(High volume two weeks from now | High volume this week) = P11 x P11 = 0.8 x 0.8 = 0.64

So, the probability of having high volume two weeks from now given that the volume is high this week is 0.64.

(3) To find the probability that volume will be high for three consecutive weeks, we can multiply the probabilities of transitioning from state 1 to state 1 three times:

P(High volume for three consecutive weeks) = P11 x P11 x P11 = 0.8 x 0.8 x 0.8 = 0.512

Therefore, the probability of having high volume for three consecutive weeks is 0.512 or 51.2%.

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