Using java
Use the UML diagram given to create the 3 classes and methods.
The class house is an abstract class. The method forsale() and location() are abstract methods in the House class
The forSale method returns a String that states the type of villa or apartment available example : "1 bedroom apartment"
The location method is of type void and prints in the output the location of the villa and apartment, example: "the villa is in corniche"
Finally create a test class. In the test class make two different objects called house1 and house2 and print the forsale and location method for apartment and villa
Use the UML diagram given to create the 3 classes and methods.
The class house is an abstract class. The method forsale() and

Answer:

3

Explanation:

it is compulsory to have a bachelor's degree

To sketch the root locus, we need to find the poles and zeros of the transfer function. In this case, the poles are located at s = -4 and s = 6, and the zero is located at s = -1.

The root locus starts at the poles and ends at the zeros. It consists of a set of branches that represent the possible locations of the closed-loop poles as the gain factor K varies.

To find the break-in and breakaway points, we analyze the behavior of the root locus as K approaches infinity and as K approaches zero.

As K approaches infinity, the root locus tends to the poles. The break-in point occurs when a branch of the root locus crosses the imaginary axis. In this case, there is no break-in point since the poles are real and located on the real axis.

As K approaches zero, the root locus tends to the zeros. The breakaway points occur when two branches of the root locus meet and move away from each other. To find the breakaway points, we need to calculate the values of K at which this occurs.

Since the transfer function has a single zero, there will be no breakaway points.

To determine the value of K for which the system is closed-loop stable, we need to check the root locus branches for the range of K values that keep the poles on the left-hand side of the complex plane (i.e., the stability region). In this case, as K increases, the poles move towards the right, and the system becomes unstable for K > 0.

Therefore, there is no specific value of K for which the system is closed-loop stable in this case.

To get a more precise plot and find the break-in and breakaway points, you can use software tools like MATLAB or any other tool that can plot root loci.

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Since the turn of the millennium, there have been numerous technological advancements in various fields that have revolutionized our economy. Here are ten such advancements.

Smartphones - The introduction of smartphones in 2007 has had a significant impact on the economy, creating new markets and transforming the way businesses operate.

Cloud Computing - This technology has enabled businesses to store and process data more efficiently and cost-effectively, allowing for greater collaboration and flexibility.

Social Media - Platforms like Fac. ebook and Twi. tter have revolutionized communication and marketing, enabling businesses to reach out to customers and target audiences in new and innovative ways.

Big Data Analytics - With the explosion of data, big data analytics has become essential in enabling businesses to make informed decisions and gain a competitive edge.

3D Printing - This technology has transformed manufacturing, allowing for more efficient and cost-effective production of goods.

Artificial Intelligence - AI is transforming industries from healthcare to finance, with its ability to analyze data and provide insights that were previously impossible to obtain.

Electric and Self-Driving Cars - The rise of electric and self-driving cars has disrupted the transportation industry, creating new markets and reducing the carbon footprint of vehicles.

Blockchain - This technology has the potential to revolutionize industries from finance to logistics, enabling secure and transparent transactions without the need for intermediaries.

Virtual and Augmented Reality - These technologies have transformed industries from gaming to retail, enabling immersive experiences and new forms of engagement with customers.

Internet of Things - IoT has enabled businesses to connect with customers and devices in new and innovative ways, creating new markets and opportunities for growth.

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Note that a loopback plug is specifically designed to test the DC voltage on a hard disk drive power connector. (Option A)

A loopback plug is a 10-inch wire device with a tiny plastic connection at one end that isolates network circuit difficulties. It is constructed using RJ-45 connectors, crimping equipment, and unshielded twisted pair (UTP) cables.

Loopback plugs are commonly used to verify data transmission by routing electrical signals and digital data streams from the output back to the same origin. Loopback is used in telecommunications, serial interfaces, virtual network interfaces, and networking.

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Nash equilibrium in mixed strategies would exist in Prisoner's Dilemma, Chicken Games, and Leadership Games, but not in games with 2 pure Nash equilibria or 2x2 games with dominated strategies.

To determine in which classes of games a Nash equilibrium in mixed strategies would exist, we need to analyze each class of game and consider the conditions for a Nash equilibrium. Here's a step-by-step explanation:

1. Prisoner's Dilemma: In the Prisoner's Dilemma, where two players must decide to cooperate or betray each other, a Nash equilibrium in mixed strategies can exist. Each player can randomize their actions to create uncertainty for the opponent and achieve an equilibrium.

2. Games with 2 pure Nash equilibria: In games with 2 pure Nash equilibria, where both players have two possible strategies resulting in Nash equilibria, there is no need for mixed strategies. Each player can simply choose one of the pure Nash equilibria.

3. Chicken Games: In Chicken Games, where two players must decide whether to swerve or continue straight, a Nash equilibrium in mixed strategies can exist. By randomizing their choices, players can create uncertainty and ensure no player has an incentive to deviate.

4. Leadership Games: Leadership Games involve a leader and a follower, where the leader chooses an action first, and the follower observes it before making their decision. In such games, a Nash equilibrium in mixed strategies can exist if the leader randomizes their actions and the follower's best response is a mixed strategy.

5. 2x2 game with dominated strategies: In a 2x2 game with dominated strategies, where one strategy is strictly dominated by another for both players, there is no Nash equilibrium in mixed strategies. The players would have dominant strategies, and the equilibrium would be in the form of a pure strategy.

6. Battle of the 2 Cultures: There is not enough information provided to determine whether a Nash equilibrium in mixed strategies would exist in the Battle of the 2 Cultures game. Without knowledge of the specific game structure and payoff matrix, it is not possible to make a definitive determination.

7. 3x3 game with a dominant strategy by only 1 player: In a 3x3 game where only one player has a dominant strategy, there can still be a Nash equilibrium in mixed strategies. The player with the dominant strategy can randomize their choices, while the other player chooses their actions accordingly.

In summary, a Nash equilibrium in mixed strategies would exist in the Prisoner's Dilemma, Chicken Games, and Leadership Games. It would not exist in games with 2 pure Nash equilibria or 2x2 games with dominated strategies. The determination for the Battle of the 2 Cultures game cannot be made without further information.

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Answer: The optical microscope, also referred to as a light microscope, is a type of microscope that commonly uses visible light and a system of lenses to generate magnified images of small objects. Optical microscopes are the oldest design of microscope and were possibly invented in their present compound form in the 17th century. Basic optical microscopes can be very simple, although many complex designs aim to improve resolution and sample contrast.

The object is placed on a stage and may be directly viewed through one or two eyepieces on the microscope. In high-power microscopes, both eyepieces typically show the same image, but with a stereo microscope, slightly different images are used to create a 3-D effect. A camera is typically used to capture the image (micrograph).

The sample can be lit in a variety of ways. Transparent objects can be lit from below and solid objects can be lit with light coming through (bright field) or around (dark field) the objective lens. Polarised light may be used to determine crystal orientation of metallic objects. Phase-contrast imaging can be used to increase image contrast by highlighting small details of differing refractive index.

A range of objective lenses with different magnification are usually provided mounted on a turret, allowing them to be rotated into place and providing an ability to zoom-in. The maximum magnification power of optical microscopes is typically limited to around 1000x because of the limited resolving power of visible light. While larger magnifications are possible no additional details of the object are resolved.

Alternatives to optical microscopy which do not use visible light include scanning electron microscopy and transmission electron microscopy and scanning probe microscopy and as a result, can achieve much greater magnifications.

In this scenario, a pipeline made of carbon steel failed after three years of operation due to corrosion. The wall thickness of the pipeline had reduced to about half of its original value. The pipeline was constructed of nominal 100 mm (4 in) schedule 40 pipe, with an inside diameter of 102.3 mm (4.026 in) and an outside diameter of 114.3 mm (4.5 in).

To estimate the rate of corrosion in IPY (inches per year) and mm per year, we need to use the following formula:

Rate of Corrosion = (Original Thickness - Remaining Thickness) / (Operation Time x Corrosion Allowance)

The original thickness of the pipeline can be calculated as:

Original Thickness = (Outside Diameter - 2 x Corrosion Allowance)

We know that the outside diameter of the pipeline is 114.3 mm (4.5 in) and the schedule 40 pipe has a corrosion allowance of 3.05 mm (0.12 in). Therefore, the original thickness can be calculated as:

Original Thickness = (114.3 mm - 2 x 3.05 mm) = 108.2 mm (4.26 in)

Now we can use the formula to estimate the rate of corrosion in IPY and mm per year:

Rate of Corrosion in IPY = (Original Thickness - Remaining Thickness) / (Operation Time x Corrosion Allowance)
Rate of Corrosion in IPY = (108.2 mm - 0.5 x 108.2 mm) / (3 years x 0.12 in)
Rate of Corrosion in IPY = 49.6 IPY

Rate of Corrosion in mm per year = (Original Thickness - Remaining Thickness) / (Operation Time x Corrosion Allowance)
Rate of Corrosion in mm per year = (108.2 mm - 0.5 x 108.2 mm) / (3 years x 3.05 mm)
Rate of Corrosion in mm per year = 4.8 mm/year

The rate of corrosion in IPY is estimated to be 49.6 IPY, and in mm per year, it is estimated to be 4.8 mm/year. These calculations help us to understand the rate at which the pipeline deteriorated due to corrosion, which can be used to prevent future failures and ensure the safety and longevity of similar pipelines.

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Answer: B) Rotating

Explanation: Osha 10 Career safe

Answer:

A) V_o = 0.7543 V

B) W = 328.42 nm

C) X_n = 298.56 nm and X_p = 29.86 nm

D) Q_j = 47.767 × 10^(-15)

Explanation:

We are given;

Acceptor concentration; N_A = 10^(17) /cm³

donor concentration; N_D = 10^(16) /cm³

ni = 1.5 × 10^(10) /cm3

A) The formula for the built - in - voltage at the junction is given by;

V_o = V_T(In (N_A × N_D/ni²))

Where V_T is thermal voltage at room temperature with a value from online sources as 25.9 mV

Thus;

V_o = 25.9(In (10^(17) × 10^(16))/(1.5 × 10^(10))²

V_o = 0.7543 V

B) Now, formula for the width of the depletion region (W)is given as;

W = √(2ε_s/q[(1/N_A) + (1/N_D)]V_o)

Where;

ε_s is the permittivity in the semiconductor with a constant value of 1.04 × 10^(-12) F/cm

q is the electron charge = 1.6 × 10^(-19) C

Thus;

W = √(2 × 1.04 × 10^(-12)/(1.6 × 10^(-19)) [(1/10^(17)) + (1/10^(16)]0.7543)

W = 32.842 × 10^(-6) cm

Converting to m gives;

W = 328.42 nm

C) Formula for extent of the n region is;

X_n = W × (N_A/(N_A + N_D))

X_n = 32.842 × 10^(-6) × (10^(17)/(10^(17) + 10^(16))

X_n = 29.856 × 10^(-6) cm

Converting to m gives;

X_n = 298.56 nm

Formula for extent of the p region is;

X_p = W - X_n

X_p = 328.42 nm - 298.56 nm

X_p = 29.86 nm

D) The charge stored on either side of the junction is given by the formula;

Q_j = Aq[(N_A × N_D)/(N_A + N_D)]W

Where A is junction Area and we are given junction area as 10 µm² = 100 × 10^(-8) cm

Thus;

Q_j = (100 × 10^(-8) × 1.6 × 10^(-19))[(10^(17) × 10^(16))/(10^(17) + 10^(16)] × 32.842 × 10^(-6)

Q_j = 47.767 × 10^(-15)

Answer:

you know you could use like quora or yahoo answers

To compute ||x−y||1, we need to take the absolute values of the differences between the corresponding components of x and y, add them up, and then take the maximum of those sums. So we have:

||x−y||1 = |(-5) - 5| + |-2 - 5| + |3 - 0| = 10 + 7 + 3 = 20

To compute ||x−y||[infinity], we need to take the maximum absolute difference between the corresponding components of x and y. So we have:

||x−y||[infinity] = max(|-5 - 5|, |-2 - 5|, |3 - 0|) = 7

To compute ||x−y||2, we need to take the square root of the sum of the squares of the differences between the corresponding components of x and y. So we have:

||x−y||2 = sqrt[(-5 - 5)^2 + (-2 - 5)^2 + (3 - 0)^2] = sqrt[100 + 49 + 9] = sqrt(158)

Therefore, ||x−y||1 = 20, ||x−y||[infinity] = 7, and ||x−y||2 = sqrt(158).

I hope that helps! Let me know if you have any other questions.

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Programmable logic controllers are more closely associated with the discrete manufacturing industries.

Discrete manufacturing industries involve the production of distinct items, such as automobiles, furniture, and toys. Programmable logic controllers are used in these industries to control the production processes and ensure that each item is produced correctly and efficiently.

In contrast, process industries involve the production of continuous products, such as chemicals, food, and pharmaceuticals. While programmable logic controllers can be used in these industries, they are not as closely associated with them as they are with discrete manufacturing industries.

In summary, programmable logic controllers are more closely associated with the discrete manufacturing industries, where they are used to control the production of distinct items.

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Answer:

the curve will flatten due to the supply and demand theory.

Answer:

ee

Explanation:

This is an over the top question

The program requires a sequence control structure; First, we get input for the variables, and then use the formula to calculate the amount of calories burnt.

The program in python is as follows, where comments (in italics) are used to explain each line.

#This gets input for age, in years

age = int(input("Age (years): "))

#This gets input for weight, in pounds

weight = int(input("Weight (pounds): "))

#This gets input for heart rate, in beats per minutes

heart_rate = int(input("Heart Rate (beats per minutes): "))

#This gets input for time, in minutes

time = int(input("Time (Minutes) : "))

#This calculates the calories burnt for men

calories_man = ((age * 0.2017) - (weight * 0.09036) + (heart_rate * 0.6309) - 55.0969) * time / 4.184

#This calculates the calories burnt for women

calories_woman = ((age * 0.074) - (weight * 0.05741) + (heart_rate * 0.4472) - 20.4022 ) * time / 4.184

#This prints the calories burnt for men

print('Men: %0.2f calories' % calories_man)

#This prints the calories burnt for women

print('Women: %0.2f calories' % calories_woman)

Please note that the program does not check for valid inputs

See attachment for program output

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Here are some steps you can follow to approach this problem:

The problem requires writing a program in Python that calculates the cost of hosting three pizza parties on Friday, Saturday, and Sunday.

The program should read input from the user, calculate the number of pizzas needed, calculate the cost of all pizzas, calculate the sales tax and delivery charges, and finally, output the total cost including tax and delivery charges.

Therefore, Read the input values: number of people, average slices per person, and cost of one pizza.

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Answer:

I can help you with your calculation.

To add and subtract angles in degrees, minutes, seconds (DMS) form, you need to follow these steps12:

Align the angles so that the degrees, minutes, and seconds are in the same column.

Add or subtract the seconds first. If the result is more than 60 or less than 0, adjust the minutes accordingly.

Add or subtract the minutes next. If the result is more than 60 or less than 0, adjust the degrees accordingly.

Add or subtract the degrees last.

Using this method, your calculation can be done as follows:

64º26’18’’ + 195º57’12,75’’ – 100º55’35’’ = 64º26’18’’ + 195º57’12.75’’ – 100º55’35’’ = 159º83’30.75’’ – 100º55’35’’ = 159º83’(30.75 - 35)’’ – 100º55’0’’ = 159º82’55.75’’ – 100º55’0’’ = 159º(82 - 55)’55.75’’ – 100º0’0’’ = 159º27’55.75’’ – 100º0’0’’ = (159 - 100)º27’55.75’’ = 59º27’55.75’’

Therefore, the answer is 59º27’55.75’’. I hope this helps!

Explanation:

Complete Question:

The cost to rent a scooter is $15.50 per hour and the cost to rent a watercraft

is $22.80 per hour. Use the expression 15.5s + 22.8w to determine how much it would cost to rent a scooter for 3 hours and a watercraft for 1 hours.

Answer:

$69.39

Explanation:

Given

15.5s + 22.8w

Required

Evaluate, when w = 1 and s = 3

To do this, we simply substitute 3 for a and 1 for w in the given expression.

15.5s + 22.8w becomes..

15.5 * 3 + 22.8 * 1

46.5 + 22.8

69.3

Hence, the cost is $69.30

Answer:

Explanation:

It appears that you are trying to solve a problem involving an insulated rigid tank containing saturated liquid water and water vapor. To determine the volume of the tank, you will need to know the mass of the liquid water and the mass of the water vapor. The mass of the liquid water can be calculated by multiplying the mass of the water and vapor mixture by the fraction of the mixture that is liquid water (1.4 kg * 0.25 = 0.35 kg). The mass of the water vapor can be calculated by subtracting the mass of the liquid water from the total mass of the mixture (1.4 kg - 0.35 kg = 1.05 kg).

To determine the final temperature of the tank, you will need to know the amount of heat added to the tank by the electric resistor and the specific heat capacity of the water and water vapor mixture. The specific heat capacity is a measure of the amount of heat required to raise the temperature of a substance by a certain amount. The specific heat capacity of water is 4.186 J/g°C, and the specific heat capacity of water vapor is 2.080 J/g°C.

To determine the electric power rating of the resistor, you will need to know the amount of heat added to the tank by the resistor and the time over which the heat was added. The power rating of the resistor is equal to the amount of heat added to the tank divided by the time over which the heat was added.

I hope this helps clarify the problem and provide some guidance on how to solve it. If you have any further questions or need additional help, please don't hesitate to ask.

Answer:

Engineers work in a variety of fields to analyze, develop and evaluate large-scale, complex systems. This can mean and improve and maintaining current systems or creating brand new projects. Engineers will design and draft blueprints, visit systems in the field and manage projects.

Answer:

Engineers work in a variety of fields to analyze, develop and evaluate large-scale, complex systems.

Explanation:

Answer:

#include <iostream>

using namespace std;

// named constant to give mnemonic name to "magic number"

const float SqFtPerGal = 350.0f;

// the function main() is always the entry point of the application

int main()

{

float length, width, area, paint; // to hold user values and results

// prompt user for length and width of wall

cout << "Enter length of wall : " << flush;

cin >> length;

cout << "Enter width of wall : " << flush;

cin >> width;

// calculate area and amount of paint needed

area = length * width;

paint = area / SqFtPerGal;

// output results with reasonable text

cout << "You need " << paint << " gallons of paint to cover "

<< area << " square feet of wall." << endl;

// program stops executing when it returns from main(), 0 means O.K.

return 0;

}

Explanation:

Answer:

Steampunk Mechanical

Explanation:

Your welcome

Prefix Symbol Multiplier Exponential

yotta Y 1,000,000,000,000,000,000,000,000 1024

zetta Z 1,000,000,000,000,000,000,000 1021

exa E 1,000,000,000,000,000,000 1018

peta P 1,000,000,000,000,000 1015

tera T 1,000,000,000,000 1012

giga G 1,000,000,000 109

mega M 1,000,000 106

kilo k 1,000 103

hecto h 100 102

deca da 10 101

1 100

deci d 0.1 10¯1

centi c 0.01 10¯2

milli m 0.001 10¯3

micro µ 0.000001 10¯6

nano n 0.000000001 10¯9

pico p 0.000000000001 10¯12

femto f 0.000000000000001 10¯15

atto a 0.000000000000000001 10¯18

zepto z 0.000000000000000000001 10¯21

yocto y 0.000000000000000000000001 10¯24

The output after the given operations would be: After the operation Push(myData, Hal), the stack myData would be: Tom, Sam, Hal (with Hal being the new top element). After the operation Pop(myData), the top element (Hal) would be removed from the stack.

the stack would be: Tom, Sam (with Tom being the new top element).After the operation Pop(myData), the top element (Tom) would be removed from the stack, and the stack would be: Sam (with Sam being the new top element).After the operation Pop(myData), the top element (Sam) would be removed from the stack, and the stack would be empty .The operation Pop(myData) would return an error or null value, as the stack is already empty. Therefore, the final output would be an error or null value.

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The dependability of a measurement is also indicated by error bars based on confidence intervals (C.I. ), which are a component of inferential statistics. These error bars show a range that would, 95% of the time, reflect the population mean.

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Answer:

I don't know the answer but you can download Ga u t h math to answer that

Explanation:

no spacing it is just can't lay aside

Answer:

Yes, there are several shower systems that are relatively simple to install. One option is the Delta In2ition Two-in-One Showerhead, which can be easily installed using a standard shower arm. Another option is the Kohler K-9245-2 2.5 GPM Moxie and Kohler K-9245-CP 2.5 GPM Moxie and Kohler K-9245-BN 2.5 GPM Moxie Showerhead, which comes with a removable hand-held showerhead that can be easily installed onto the existing shower arm. Additionally, the AquaDance 7" Premium High Pressure 3-Way Rainfall Combo for the Best Relaxation has a simple installation process and can be easily mounted onto the wall or shower arm. Overall, it is important to carefully read the instructions and have the necessary tools on hand to ensure a smooth installation process.

Answer: Yes

Explanation:

We know that installing a shower system can be a hassle. But what if we told you there was an easier way?

The HYDRO-BLOK Shower System is lightweight and easy to install, so you can get started tiling in as little as an hour. And here's the best part: once it's installed, the HYDRO-BLOK system is 100% waterproof—we promise! There's no need for any additional waterproofing steps or messy materials.

So why not give it a try? You won't be disappointed.