Answer:
6468 mm²
Step-by-step explanation:
Given:
21 mm = length of the shortest of the small rectangleLet y = length of the longest of the small rectangleTherefore, the area of the small rectangle is:
= width × length
= 21 × y
= 21y mm²
From inspection of the larger rectangle
longest side length = 4 × 21 = 84 mmshortest side length = (2y + 21) mmTherefore, the area of the larger rectangle is:
= width × length
= 84(2y + 21)
= 168y + 1764 mm²
We know that the area of the larger rectangle is 11 times the area of the smaller rectangle. Therefore,
⇒ 11 small rectangles = larger rectangle
⇒ 11(21y) = 168y + 1764
⇒ 231y = 168y + 1764
⇒ 63y = 1764
⇒ y = 28
Therefore, the missing side length of the smaller rectangle is 28 mm.
Finally, to find the area of the larger rectangle, substitute the found value of y into the found expression for its area:
⇒ area = 168y + 1764
⇒ area = 168(28) + 1764
⇒ area = 4704 + 1764
⇒ area = 6468 mm²
The sun came out and the temperature quickly rose 18 degrees. the a thunderstorm hits and the temperature drops 6 degrees. the sun comes back out the temperature raises 12 degrees. the temperature is now 94 degrees. what was the starting temperature?
By solving a linear equation we will see that the initial temperature was 66 degrees.
What was the initial temperature?
Let's define T as the initial temperature.
First, it increases by 18 F, then it decreases 6 F, and finally, it increases another 12 F, such that the end temperature is 94F.
Then we can write:
T + 18F - 6F + 12F = 94F
Now we can solve that linear equation to find T.
T = 94F - 18F + 6F - 12 F = 66 F
In this way, we conclude that the initial temperature was 66 degrees.
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helllppppppppppppppppppppppppppppp
The equation: n - 4 = -15
Now let's solve our equation for n.
n - 4 = -15
Add 4 to both sides.
n = -11
Answer correctly !!!!!!!!! Will be marking Brianliest !!!!!!! HELP ME PLEASE PLEASE
Answer:
(-2,-5)
Step-by-step explanation:
point A=(-8,5)
point M=(-5,0)
The difference between them is that point m is 3 to the right and 5 down. We have to do this again to find point b
Point B= (-2,-5)
Julian is deciding between two different movie streaming sites to subscribe to. Plan A costs $5 per month plus $2.50 per movie watched. Plan B costs $29 per month plus $0.50 per movie watched. Let AA represent the monthly cost of Plan A if Julian watches xx per month, and let BB represent the monthly cost of Plan B if Julian watches xx movies per month. Write an equation for each situation, in terms of x,x, and determine which plan would be cheaper if Julian plans on watching 11 movies each month.
A;
5 + 2.5xx = AA
B;
20 + 0.5xx = BB
A: 5 + 2.5 • 11
B: 20 + 0.5 • 11
A = 32.5
B = 25.5
if you were informed that it takes one year for the earth to revolve around the sun, and that the square of that period was proportional to the cube of the earth's average distance from the sun, what law would fit that description?
Answer:kepler's 3rd law
Step-by-step explanation:
4(x-2)-9x = - 13x
hello, I just want to make shure if this true thank you
Answer:
Step-by-step explanation:
PLEASE HELP GIVING BRAINLIEST
Answer:
first question is 9 1/2 - 2nd answer
2nd question is 2nd answer 4 3/4 - ur correct
Suppose there are five processes, their arrival time and running time are listed as follows. Adopt FCFS and SJF, respectively, give the schedule order and average waiting time. (12) 1) Give the schedule order of FCFS. (3) 2) Compute the average waiting time of FCFS. (3) Give the schedule order of SJF. (3) 3) 4) Compute the average waiting time of SJF. (3) Process Arrival time Running time Pl 0 3 P2 3 10 P3 4 6 P4 5 1
Average waiting time for FCFS: 8.75
SJF schedule order: Pl -> P4 -> P3 -> P2Average waiting time for SJF: 4.75
To solve this scheduling problem using FCFS (First-Come, First-Served) and SJF (Shortest Job First) algorithms, let's go step by step:
Schedule order for FCFS:
The FCFS algorithm schedules processes based on their arrival time. So, the schedule order for FCFS is as follows:
Pl -> P2 -> P3 -> P4
Average waiting time for FCFS:
To compute the average waiting time for FCFS, we need to calculate the waiting time for each process and then take the average.
Process | Arrival Time | Running Time | Waiting Time
Pl | 0 | 3 | 0
P2 | 3 | 10 | 3
P3 | 4 | 6 | 13
P4 | 5 | 1 | 19
Average waiting time = (0 + 3 + 13 + 19) / 4 = 8.75
Therefore, the average waiting time for FCFS is 8.75.
Schedule order for SJF:
The SJF algorithm schedules processes based on their running time. The process with the shortest running time gets executed first. If multiple processes have the same running time, the process with the earliest arrival time is selected first. The schedule order for SJF is as follows:
Pl -> P4 -> P3 -> P2
Average waiting time for SJF:
To compute the average waiting time for SJF, we need to calculate the waiting time for each process and then take the average.
Process | Arrival Time | Running Time | Waiting Time
Pl | 0 | 3 | 0
P4 | 5 | 1 | 3
P3 | 4 | 6 | 6
P2 | 3 | 10 | 10
Average waiting time = (0 + 3 + 6 + 10) / 4 = 4.75
Therefore, the average waiting time for SJF is 4.75.
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To prepare for a bake-Off, Sebastian used 830 grams of flour each day for 4 weeks. How many kilograms did Sebastian use in those 4 weeks?
1 q = 0.001 kg
If 830 grams = 1 day.
23.24 kilograms = 4 weeks.
23.24 kilograms were used by Sebastian in those 4 weeks.
What is an equation?An equation is a mathematical statement that is made up of two expressions connected by an equal sign.
Example: 3x = 4 is an equation.
We have,
830 grams is used each day.
830 grams = 1 day ___(1)
1 week = 7 days
Multiply 4 on both sides.
4 weeks = 28 days ___(2)
From (1) and (2) we get,
4 weeks = 28 days
4 weeks = 28 x 1 day
4 weeks = 28 x 830 grams
4 weeks = 23240 grams ____(3)
1000 grams = 1 kg
Multiply both sides by 23240/1000.
23240 grams = 23.24 kilograms _____(4)
From (3) and 94) we get,
4 weeks = 23.24 kilograms
Thus,
23.24 kilograms were used by Sebastian in those 4 weeks.
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What is the three-period weighted moving average for july using the weights 0.5 (most recent), 0.3, and 0.2?
The three-period weighted moving average for july is 145.4.
What is Weighted Moving Average?A weighted moving average technique is one of several methods for forecasting a given month's value or attribute. Other techniques for forecasting from historical data include the evenly weighted moving average method, a regression analysis method, and so on.
When evaluating the movable average estimate of such an observation, each observation is usually weighted the same way. In some cases, it is advantageous to assign different weights to the observations so that the observation closest to the forecasted time period has a higher weight. This is known as the weighted moving average method. In such a weighted moving average technique, the sum of the individual weights must equal 1.Now, according to the question;
The weighted moving average strategy forecast for month of July is given by:
= (Weight for May * Sales for May) + (Weight for April * Sales for April) + (Weight for June * Sales for June)
= (0.5 * 148) + (0.3 * 142) + (0.2* 144)
= 145.4
Therefore, the three-period weighted moving average for july is 145.4.
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The complete question is -
13. Given the following historical data and weights of .5, .3, and .2, what is the three-period weighted moving average forecast for period 5?
Period Value
1 - 138 (march)
2 - 142 (april)
3 - 148 (may)
4 - 144 (june)
Can someone pls help im new to this
Answer:
5
Step-by-step explanation:
\(\frac{-10}{-2} \\\\5\)
how many 5-card hands that can be dealt off of a 52-card deck, such that two cards are clubs and 3 are hearts?
Answer:
22308-------------------
There are 13 clubs and 13 hearts in the deck.
First, find the number of ways to choose 2 clubs out of 13:
C(13, 2) = 13! / (2!(13-2)!) = 78 combinationsNext, find the number of ways to choose 3 hearts out of 13:
C(13, 3) = 13! / (3!(13-3)!) = 286 combinationsNow, multiply these two results:
78 * 286 = 22308 possible handsT/F if you’re comparing the test scores between two groups, you should use a one-sample z-test.
The given statement "if you’re comparing the test scores between two groups, you should use a one-sample z-test." is False because you should use two-sample t-test.
If you are comparing the test scores between two groups, you should use a two-sample t-test. A one-sample z-test is used to compare a sample mean to a known population mean when the population standard deviation is known.
However, in most cases, the population standard deviation is unknown, and the sample size is typically small, so a t-test is preferred. The two-sample t-test is used to compare the means of two independent groups. The test assumes that the samples are normally distributed and have equal variances.
If the variances are unequal, a modified version of the t-test called the Welch's t-test should be used. In summary, the appropriate test to use depends on the nature of the comparison being made, the sample size, the distribution of the data, and whether the variances of the two groups are equal or not.
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to decrease sample error, a pollster must __________ the number of respondents.
A) issue-scale B) increase C) decrease D) underrepresented
The correct option is B) increase.
To decrease sample error, a pollster must increase the number of respondents. The larger the sample size, the more representative it is likely to be of the target population, leading to a lower margin of error.
When conducting surveys or polls, it is essential to obtain responses from a diverse and random group of individuals. By increasing the number of respondents, the pollster can capture a broader range of perspectives, which helps to reduce sampling bias and increase the accuracy of the results.
For example, let's say a pollster wants to understand the political preferences of voters in a particular city. If they only survey 50 people, the sample may not accurately reflect the larger population, and the margin of error could be high. However, if they survey 500 or even 1000 people, the results are more likely to provide a reliable estimate of the overall population's preferences.
Therefore, to decrease sample error, pollsters should increase the number of respondents in their surveys or polls. This approach helps to ensure a more accurate representation of the population's views and minimize the potential for misleading or biased results.
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a spinner has 20 equal sized sections . eight of those sections are green. what is the probability that the spinner will land on green? use words to describe the probability
Round to the nearest hundredth : 8.113
plz help :)
Answer:
\(8.11\)
Step-by-step explanation:
Rounded to nearest hundredth.
After Round to the nearest hundredth value of number is,
⇒ 8.11
We have to given that;
A number is,
⇒ 8.113
And, We an Round to the nearest hundredth.
Since, Rounding numbers refers to changing a number's digits such that it approximates a value.
Here, In number 8.113,
Digit in thousandth place is 3 which is less thn 5.
Hence, After Round to the nearest hundredth value of number is,
⇒ 8.11
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An initial population of 385 quail increases at an annual rate of 30%. Write an exponential function to
model the quail population. What will the approximate population be after 5 years?
The exponential function that models the quail population is:
P(t) = P0 * (1 + r)^t
where:
P0 is the initial population (385)
r is the annual growth rate (30% or 0.3)
t is the time in years
Substituting the values, we get:
P(t) = 385 * (1 + 0.3)^t
Simplifying:
P(t) = 385 * 1.3^t
To find the approximate population after 5 years, we substitute t = 5:
P(5) = 385 * 1.3^5
P(5) = 385 * 3.277
P(5) = 1262.45
Therefore, the approximate population after 5 years is 1262 quail
The map shows a linear section of Highway 35. Today, the Ybarras plan to drive the 360 miles from
Springfield to Junction City. They will stop for lunch in Roseburg, which is at the midpoint of the trip. If they
have already traveled 55 miles this morning, how much farther must they travel before they stop for lunch?
a. 125 mi
b. 145 mi
c. 180 mi
d. 305
They must travel 125 miles farther before they stop for lunch and option A is the correct answer.
We have,
The total distance of the trip is 360 miles.
They plan to stop for lunch at the midpoint of the trip, which is
360 / 2 = 180 miles.
Now,
They have already travelled 55 miles this morning.
To find out how much farther they must travel before stopping for lunch, we subtract the distance travelled from the midpoint:
180 - 55
= 125 miles.
Thus,
They must travel A. 125 miles farther before they stop for lunch.
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Sin y = 4xy + x^2. Find dy/dx
Answer:
dy/dx=(4y+2x)/(cos y-4x)Step-by-step explanation:
Siny= 4xy +x²
dy/dx(cos y) =4y+ 4x(dy/dx)+2x
making dy/dx the subject
dy/dx(cos y)-4x(dy/dx)=4y+2x
dy/dx(cos y -4x)=4y+2x
dy/dx=(4y+2x)/(cos y -4x)
If Sample #1 contains 2. 98 moles of hydrogen at 35. 1 degrees C and 2. 3 atm
in a 32. 8 L container. How many moles of hydrogen are in a 45. 3 liter
container under the same conditions?
To calculate the number of moles of hydrogen in a 45.3-liter container under the same conditions as Sample #1, we can use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature in Kelvin.
Given that Sample #1 contains 2.98 moles of hydrogen at 35.1 degrees C (308.25 K) and 2.3 atm in a 32.8 L container, we can use these values to find the value of R.
R = (PV) / (nT) = (2.3 atm * 32.8 L) / (2.98 moles * 308.25 K)
Once we have the value of R, we can use it to calculate the number of moles in the 45.3-liter container at the same conditions:
n = (PV) / (RT) = (2.3 atm * 45.3 L) / (R * 308.25 K)
By substituting the appropriate values and solving the equation, we can determine the number of moles of hydrogen in the 45.3-liter container.
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solve for x 3(x-8) = -29.7
Answer:
\(x = - 1.9 \)
The answer of this equation is:
1.9
The difference of x and y is 14. The value of x is 3 more than
twice the value of y. Write two equations and graph to find
the value of x.
O X = 25
O x = -17
OX= 4
O x = 11
The value of X = 25.
The difference of x and y is 14. The value of x is 3 more thantwice the value of y. Find the value of x and y.Solution:
The two equations are
(i) the first condition is difference of x and y is 14
x - y = 14 ---------equation 1
(ii) the second condition of the given data is value of x is 3 times more than two times of y value.
x - 2y = 3 --------equation 2
From equation 2, we have to separate two variables x and y,
x = 3 + 2y --------equation 3
We have to Substitute equation 3 in equation 1
3 + 2y - y = 14
3 + y = 14
y = 14 - 3
y = 11
Substitute y = 11 in equation 1........
x - 11 = 14
x = 14 + 11
x = 25
So, the value of x is 25 and y is 11.
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Answer:
x - y = 14x - 2y = 3x = 25Step-by-step explanation:
Given the difference of x and y is 14, and the difference of x and 2y is 3, you want two equations, their graph, and the value of x.
EquationsThe difference of 'a' and 'b' is (a -b). Here, the two differences are expressed as the equations ...
x - y = 14x - 2y = 3GraphThe attachment shows a graph of these equations. Their point of intersection is (25, 11), meaning the value of x is 25.
The graph of the first equation is easily drawn by recognizing the x- and y-intercepts are 14 and -14, respectively.
The graph of the second equation will go through the x-intercept point of (3, 0) and the y-intercept point of (0, -3/2). It is probably easier to graph this by hand by considering the x-intercept point and the slope of 1/2.
Algebraic solutionSince we're only interested in the value of x, it is convenient to eliminate the variable y. We can to that by subtracting the second equation from twice the first:
2(x -y) -(x -2y) = 2(14) -(3)
x = 25 . . . . . . . . . simplify
3. Which point is closest to -3 on the number line?
Answer: D.
Step-by-step explanation:
-2/20 = -0.1, 0.1 is the closet one to -3
Write a quadratic equation in standard form with \(\frac{3}{4}\) an -5 as its roots
Knowing the roots first write the equation in factored form:
(X - 3/4)(x +5) = 0
Now use the FOIL method ( multiply each term in one set of parentheses by each term the other set:
X•x + x•5 -3/4•x -3/4•5
Simplify:
X^2 + 5x -3/4x -3 3/4
Combine like terms:
X^2+ 4 1/4x - 3 3/4
True or false
When ice melts, it releases thermal energy.
Answer:true
Step-by-step explanation:
The points scored by a basketball team in its last 6 games
are shown. Use these data for 7 and 8.
Which measure better describes the typical number of points scored?
Explain.
(Points scored= 73,77,85,84,37,115)
Answer:
73+78+85+84+37+115 because you will add all point scored by the last 6games =471
Enter the solutions from least to greatest. -2x^2 -9=-107
Answer:
x = -7, 7
Step-by-step explanation:
Step 1: Write out equation
-2x² - 9 = -107
Step 2: Add 9 on both sides
-2x² = -98
Step 3: Divide both sides by -2
x² = 49
Step 4: Square root both sides
x = ±7
Step 5: Arrange
-7 < 7
So x = -7, 7
Select all possible cross sections of a sphere.
A
point
B
square
circle
D
triangle
Answer:
The only cross sections a sphere has is a circle.
Find the area of the circle. Use 3.14 for π. Round your answer to the nearest hundredth.
A circle with radius 1.2 kilometers is shown.
The area of the circle is approximately 4.52 square kilometers.
To find the area of a circle with radius 1.2 kilometers, we can use the formula:
Area = π × \(r^{2}\)
Plugging in the values we get:
Area = 3.14 ×\(1.2^{2}\)
Area = 3.14 × 1.44
Area = 4.5216
Rounding to the nearest hundredth, we get:
Area ≈ 4.52 square kilometers
The area of a circle is the measure of the region enclosed by the circle in a two-dimensional space. It is the amount of space inside the circle and is usually measured in square units, such as square meters, square feet, square centimeters, etc. The formula for calculating the area of a circle is A =\(\pi r^{2}\)
, where A is the area, r is the radius of the circle, and π (pi) is a mathematical constant approximately equal to 3.14. In simpler terms, the area of a circle is the total surface area of the circle, including the interior region, and is directly proportional to the square of its radius.
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the complete questionis :
determine the area of the solution, use 3.14 as \(\pi\) value and round the answer to the nearest hunderedth.
a circle with radius 1.2km is shown
Δ baryons have spin 3/2, which means that they can have four different spin projections along the z axis. They also have isospin 3/2, which means that there are four different Δ particles with regards to the up and down quarks that they are composed of. Write down the isospin ⊗ spin wavefunctions for the four different spin states of a Δ 0
particle, in terms of the wavefunctions of the quarks it is composed of.
The isospin ⊗ spin wavefunctions for the four different spin states of a Δ0 particle, in terms of the wavefunctions of the quarks it is composed of, are:
|3/2, 3/2⟩ = |u↑d↑⟩
|3/2, 1/2⟩ = (√3/2)|u↓d↑⟩ + (√1/2)|u↑d↓⟩
|3/2, -1/2⟩ = (√1/2)|u↓d↑⟩ - (√3/2)|u↑d↓⟩
|3/2, -3/2⟩ = |u↓d↓⟩
The Δ baryons are composed of three quarks: two down (d) quarks and one up (u) quark. The isospin of a particle represents its behavior under rotations in the isospin space, which is related to the behavior of the particle under the strong force. The spin of a particle represents its intrinsic angular momentum.
For the Δ0 particle, which has isospin 3/2, there are four different spin states. Each spin state corresponds to a different combination of up and down quark spin projections along the z axis. The isospin ⊗ spin wavefunctions represent the composite wavefunctions of the quarks that make up the Δ0 particle for each spin state.
In the first spin state, |3/2, 3/2⟩, both the up and down quarks have their spins aligned in the upward direction. In the second spin state, |3/2, 1/2⟩, the up quark has its spin aligned upward while the down quark has its spin aligned downward. The third spin state, |3/2, -1/2⟩, has the up quark with its spin aligned downward and the down quark with its spin aligned upward. Finally, in the fourth spin state, |3/2, -3/2⟩, both the up and down quarks have their spins aligned in the downward direction.
These wavefunctions provide a mathematical description of the different spin states of the Δ0 particle, taking into account the wavefunctions of the constituent quarks. They help us understand the quantum mechanical properties and behavior of the Δ0 baryon in terms of its quark composition.
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