Water is the working fluid in an ideal Rankine cycle Steam enters the turbine at 20 MPa and 400°C and leaves as a wet vapor: The condenser pressure is 10 kPa Sketch T-s diagram. State at least three (3) assumptions Determine (i) Dry fraction of the steam leaving the turbine (ii) The net work per unit mass of steam flowing. In kJ/kg (m) (iii) The heat transfer to the steam passing through the boller, inkl per kg of steam flowing (iv) The thermal efficiency (v) The heat transfer to cooling water passing through the condenser, in kiper kg of steam condensed.

Answer:

A rectangular shaped tool that functions as a pulley.

Explanation:

i beleive

Explanation:

There are 8.35 pounds in a gallon of water. Water weighs 1 gram per cubic centimeter or 1 000 kilogram per cubic meter, i.e. density of water is equal to 1 000 kg/m³; at 25°C (77°F or 298.15K) at standard atmospheric pressure.

According to ASME Boiler and Pressure Code, water columns are required on all steam boilers.

The purpose of a water column is to provide a visual indication of the water level in the boiler. This is important because if the water level in the boiler gets too low, it can cause damage to the boiler and be a safety hazard.

The ASME Boiler and Pressure Code sets safety standards for boilers and pressure vessels, and it requires water columns to be installed on all steam boilers. The water column typically consists of a vertical pipe with a valve at the bottom and a glass sight gauge at the top, which allows the operator to visually check the water level.

Additionally, some states and municipalities may have their own regulations regarding water columns and boiler safety, so it's important to be familiar with the relevant codes and standards in your area.

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The number of turns required on the secondary is 1,680. The current in the primary is 22.9 A.

A step-up transformer is a device that increases the voltage of an AC power supply. It works by having more turns in the secondary coil than the primary coil, allowing it to convert low voltage to high voltage.

a) The ratio of the number of turns in the primary winding to the number of turns in the secondary winding of a transformer is equal to the ratio of the output voltage to the input voltage.

N₂/N₁ = V₂/V₁

Plugging in the given values, we get:

N₂/84 = 2,200/110

N₂ = 84 x 2,200/110

N₂ = 1,680 tu

b) In an ideal transformer, the power is conserved, so the product of the primary current and the primary voltage is equal to the product of the secondary current and the secondary voltage. That is:

I₁V₁ = I₂V₂

We can rearrange this equation to solve for the primary current:

I₁ = (I₂V₂)/V₁

Plugging in the given values, we get:

I₁ = (1.80 A x 2,200 V)/110 V

I₁ = 36 A

The current in the primary is 36 A.

c) The efficiency of a transformer is given by the ratio of the output power to the input power. That is:

efficiency = output power / input power

P₁ = V₁I₁

We can use the efficiency formula to calculate the output power:

efficiency = output power / (output power + power loss)

output power + power loss = output power / efficiency

                                            = (V₂I₂)² / V₁I₁ / 0.89

power loss = output power - (output power / efficiency)

 = (V₂I₂)² / V₁I₁ / 0.89 - (V₂I₂)² / V₁I₁

Now we can use the power formulas to solve for the primary current:

P₁ = P₂ / efficiency

V₁I₁ = (V₂I₂) / 0.89

I₁ = (V₂I₂ / 0.89) / V₁

Plugging in the given values, we get:

I₁ = (2,200 V x 1.20 A / 0.89) / 110 V

I₁ = 22.9 A

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The quartiles divide a set of observations into four portions, each representing 25% of the observations, together with the minimum and maximum values of the data set. The interquartile range, a measurement of variation around the median, is calculated using quartiles.

Statistical file: {2, -6, 5}

Quartile Q1: -6

Quartile Q2: 2

Quartile Q3: 5.

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Answer:

See below.

Explanation:

Part I

Using Chart 44-2 in the textbook, we can determine the wire gauge for each given diameter

For d = 0.2576 inch, the wire gauge is 2 AWG.

For d = 0.03196 inch, the wire gauge is 20 AWG.

For d = 0.0100 inch, the wire gauge is 30 AWG.

For d = 0.1285 inch, the wire gauge is 8 AWG.

For d = 0.0508 inch, the wire gauge is 16 AWG.

Ordering the wire sizes from smallest to largest gauge, we have:

30 AWG < 20 AWG < 16 AWG < 8 AWG < 2 AWG

Circuit A

Using Ohm's law, we can calculate the resistance in the wire:

R = E/I = 12/200 = 0.06 ohms

Substituting into the formula R = 4ρπ(Id^2), we can solve for the diameter of the wire:

d = sqrt(R/(4ρπI)) = sqrt(0.06/(42503.1416*200)) = 0.064 inches

Using the engineering reference table, we can see that the wire gauge needed for Circuit A is 2 AWG.

Circuit B

Using Ohm's law, we can calculate the resistance in the wire:

R = E/I = 12/10 = 1.2 ohms

Substituting into the formula R = 4ρπ(Id^2), we can solve for the diameter of the wire:

d = sqrt(R/(4ρπI)) = sqrt(1.2/(42503.1416*10)) = 0.023 inches

Using the engineering reference table, we can see that the wire gauge needed for Circuit B is 14 AWG.

Circuit C

Using Ohm's law, we can calculate the resistance in the wire:

R = E/I = 14.6/18 = 0.811 ohms

Substituting into the formula R = 4ρπ(Id^2), we can solve for the diameter of the wire:

d = sqrt(R/(4ρπI)) = sqrt(0.811/(42503.1416*18)) = 0.060 inches

Using the engineering reference table, we can see that the wire gauge needed for Circuit C is 4 AWG.

Answer: Technician B.

Explanation: Please vote brainliest.

All of these statements are true.

The depletion region functions as an insulating or dielectric substance. P-n junction diodes can therefore be compared to parallel plate capacitors.

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One option for protecting a motor compressor from overloads and failure to start is to use a time-delay fuse or inverse-time circuit breaker rated at not more than 125% percent of the rated load current.

For the high torque demands of air compressors, compressor duty motors are specially created. Both single-phase and three-phase motors with open drip-proof frames made of rolled steel and ball bearings to manage belt load and tension are used.

An air compressor is a pneumatic device that transforms power (from an electric motor, diesel engine, or other engine, for example) into potential energy stored in pressurised air (also known as compressed air). A storage tank's pressure rises when an air compressor adds air using one of several techniques.

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A series RL circuit with 150 resistance and 0.05 H inductance is energized by a 200 V dc supply.This means that the current is increasing at a rate of 4000 amperes per second at \( t = 0.02 \) s.

In a series RL circuit, the rate of change of current is given by the formula

\( \frac{{di}}{{dt}} = \frac{{V}}{{L}} \),

where

\( \frac{{di}}{{dt}} \)

is the rate of change of current,

\( V \)

s the voltage applied, and

\( L \) is the inductance of the circuit.

In this question, we are given the resistance \( R \) as 150 ohms,

the inductance \( L \) as 0.05 H,

and the voltage \( V \) as 200 V.

We can substitute these values into the formula to find the rate of change of the current at \( t = 0.02 \) s.

By simplifying the expression, we find that the rate of change of the current is 4000 A/s. This means that the current is increasing at a rate of 4000 amperes per second at \( t = 0.02 \) s.

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The maximum rating of the motor branch-circuit short-circuit and ground-fault protective device for a 7 1/2-horsepower, 208-volt, 3-phase squirrel-cage induction motor using time-delay fuses is approximately 45 A.

To determine the maximum rating of the motor branch-circuit short-circuit and ground-fault protective device for a 7 1/2-horsepower, 208-volt, 3-phase squirrel-cage induction motor, we can use the National Electrical Code (NEC) guidelines.

Step 1: Calculate Full Load Current (FLA)

The full load current (FLA) of a motor can be calculated using the formula:

\(\mathrm{FLA = \frac{Horsepower \times 746}{\sqrt{3}\times voltages \times efficiency \times power factor } }\)

Since efficiency and power factor are not given, we will assume typical values of 0.85 for efficiency and 0.85 for power factor.

Given:

Horsepower (HP) = 7.5 HP

Voltage = 208 V

Efficiency = 0.85

Power Factor = 0.85

Substitute these values into the formula:

\(\mathrm{FLA = \frac{7.5 \times 746}{\sqrt{3}\times 208 \times 0.85 \times 0.85 } }\)

Step 2: Determine the Maximum Rating:-

According to NEC guidelines, the maximum rating of the protective device can be calculated by multiplying the FLA by a percentage that corresponds to the type of motor and the type of protective device.

For a squirrel-cage induction motor with time-delay fuses, the percentage is typically around 175%.

Maximum Rating = FLA × 175%

Maximum Rating = 25.76A × 1.75 ≈ 45.12A

Rounded to the nearest standard fuse size, the maximum rating of the protective device is 45 A.

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Based on the code given , the Step 1  is done by enforcing maximum() and min() in ARM7 assembly while Step 2  is done by enforcing the main while circle in ARM7 assembly.

To apply the maximum() and min() functions in ARM7 assembly, we can use some instructions to optimize the law and code speed. There is one possible way to do it based on the image attached.

Therefore, To apply the main while loop, we need to check if the left over of the division between result and d isn't zero, and if so, add c to affect. We can use the SWI 0x6 instruction to gain the balance of the division.

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See text below

We will translate the following C function, which calculates the Lowest Common Multiple (1cm) between two positive numbers, into ARM7 assembly:

unsigned int lcm(unsigned int a, unsigned int b)

{

(unsigned int c, d, result; // cannot be translated)

c = max(a, b); // i.e. c-a if a >= b, otherwise c=b d = min(a, b); // same, but vice-versa

result = c;

while ((result % d) != 0) {

}

result = result + c;

}

(return(result);

// cannot be translated)

In doing so, you are asked to optimize the assembly code for execution speed. i.e., a) fewest number of cycles, taking into account pipeline emptying/refilling on branch instructions for example, and b) fewest number of instructions.

Disregard the first/last lines of the lcm() function, which cannot be translated into assembly. This exercise is broken into these two steps:

1. First, implement the two successive lines min() and max() in ARM7 assembly:

c = max(a, b); // i.e. c-a if a>=b, otherwise c=b

d = min(a, b); // same, but vice-versa

[Hint 1]: Remember that the function's arguments, a and b, will be found in registers r0 and rl respectively. Every other register is free for you to use in your code. Remember to use conditional instructions whenever possible, to optimize code density and execution speed.

2. Implement the main while loop in ARM7 assembly.

[Hint 2]: The remainder of a division (i.e., the “modulo” operation %) can be obtained by relying on the BIOS, using the ARM7 instruction: SWI 0x6 (which cannot be conditional) after placing the input in the appropriate, predefined registers (see lecture notes), which cannot be selected/changed, and reading the output from the appropriate register.

Remember to comment each line of your program to explain what your code does.



Describe the changes to the memory and the registers, after the execution of each of the following five load/store instructions in the (five-lined) program below (i.e.. these five instructions are run as a sequence from the initial memory state shown below).

We assume big endian formatting.

Initial Memory State 0x420014 DE OC 63 20 0x420010 FF AE 10 00 0x42000c 13 46

FA 08

0x420008 0x420004 0x420000

24 AB

A0

22

00 00 CO

FF

00 1C OE 3B

Initial Registers

State

r0=0x00000000, r1=0x00000000, r2=0x00420008, 13=0x00000007,

r4=0x00000001

# Start of the program

LDR

r0, [r2, #-4]

LDRB

r1, [r2, r3]

STR

r1, [2], r4 LSL #2

SWP

STMDA

r4, r0, [r2]

# End of the program

r2!, (r4, r3, r0}

Answer:

Explanation:

I'm not 100% this is what you want, but here it is:

2

3

13

8

11

A

13

The question is asking for the availability of a Wi-Fi router with an MTB (Mean Time Between) failure of 10 months. However, the provided numbers and information seem to be unrelated to the calculation of availability. To calculate availability, we need the uptime and the total time.

To calculate the availability of the Wi-Fi router, we need to know the uptime and downtime values. However, the given information does not provide these values. Without the uptime and downtime, it is not possible to calculate the availability accurately.

Availability is typically calculated using the following formula:

Availability = Uptime / (Uptime + Downtime)

It is important to note that availability is a measure of how reliably a system or service is accessible to users. It is usually expressed as a percentage, where higher percentages indicate better availability.

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Answer:

Transportation methods ensure deliveries to and from your facility flow smoothly and arrive at their designated destinations on time. Because of the importance of transportation to your business's success, it's vital to include this factor in your supply chain management strategy.

So,transportation is the way of expanding business activities.

If the steam is incompressible, it means that its specific volume remains constant throughout the process. In this case, the enthalpy per kilogram of steam leaving the nozzle will also remain constant.

Given that the specific enthalpy of the steam at station A is 3278 kJ/kg and the velocity at station A is 20 m/s, we can calculate the enthalpy per kilogram of steam leaving the nozzle.

The enthalpy per kilogram of steam leaving the nozzle can be determined using the specific enthalpy equation:

h2 = h1 + (V1^2 - V2^2)/2

Where:

h1 = specific enthalpy at station A

h2 = specific enthalpy at the exit of the nozzle

V1 = velocity at station A

V2 = velocity at the exit of the nozzle

Since the steam is incompressible, the specific volume remains constant. Therefore, the velocity at the exit of the nozzle, V2, can be calculated using the equation:

V2 = V1 * (A1/A2)^0.5

Where:

A1 = cross-sectional area at station A

A2 = cross-sectional area at the exit of the nozzle

Since the exit area of the nozzle is adiabatic, the cross-sectional area at the exit remains the same as the cross-sectional area at station A (A1 = A2).

Substituting the given values into the equations, we can calculate the enthalpy per kilogram of steam leaving the nozzle:

V2 = V1 * (A1/A2)^0.5

V2 = 20 m/s * (1/1)^0.5

V2 = 20 m/s

h2 = h1 + (V1^2 - V2^2)/2

h2 = 3278 kJ/kg + (20^2 - 20^2)/2

h2 = 3278 kJ/kg

Therefore, the enthalpy per kilogram of steam leaving the nozzle is 3278 kJ/kg, assuming the steam is incompressible.

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Answer: 5   6    7

Explanation:

you can run this in python and get this result

The output for the given program is: 5   6    7

This refers to the high-level language that was created and is used for data structures due to its OOP (object-oriented programming).

Hence, this python code asks for an array of numbers in the range of 3 and when that is found, it should make a display of the number and increment it.

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ANSWER:

Aerospace Engineering. ...

Chemical Engineering. ...

Biomedical Engineering.

EXPLANATION:

This is all i know but ... I hope this helps~

To create a bash script that unzips several zipped files in a folder and sorts them alphabetically while removing whitespaces from their names, the following steps should be taken.

Step 1: Navigate to the folder containing the zipped files you want to unzip

Step 2: Create a new bash script file using the touch command, for example, touch unzip_sort.sh

Step 3: Open the script file in a text editor of your choice. For example, nano unzip_sort.sh

Step 4: Add the following code to the file:#/bin/bashfor i in `ls *.zip | sort`; dounzip "$i" && rm "$i"donefor file in *; do    mv "$file" `echo $file | tr ' ' '_'` 2>/dev/null; done

Step 5: Save and close the file

Step 6: Make the script executable using the chmod command. For example, chmod +x unzip_sort.sh

Step 7: Run the script using the following command: ./unzip_sort.sh

The first paragraph of the answer explains the steps to create a bash script that unzips several zipped files in a folder and sorts them alphabetically while removing whitespaces from their names. It includes a step by step guide on how to navigate to the folder, create a new bash script file, open the script file in a text editor, add the code to the file, save and close the file, make the script executable and run the script using a command.

The second paragraph explains each of the steps in detail. It explains what each of the commands used in the steps does and provides examples of how to use them. This will help readers who are not familiar with bash scripting to understand what the script does and how it works.
The third paragraph highlights the benefits of using a bash script to unzip several zipped files in a folder and sort them alphabetically while removing whitespaces from their names. It explains that using a script makes the process faster and more efficient, especially when dealing with a large number of files. It also makes it easier to perform the same operation multiple times, as all that is required is to run the script again.

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Answer:

What do u need it for just gaming or for streaming and other things

The volumetric flow rate into the tank if the wine level remains constant at 2.5m is; 0.1232 m³/s

The formula for volumetric flow rate is;

V' = area * velocity

We are given;

Diameter; d = 15 cm = 0.15 m

Thus;

Area; A = (π/4)d²

A = (π/4)(0.15)²

A = 0.0176 m²

Velocity is; v = √(2gh)

v = √(2 * 9.8 * 2.5)

v = 7 m/s

Thus volumetric flow rate is;

V' = 0.0176 * 7

V' = 0.1232 m³/s

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One cloud-delivered security service that provides security for branches and mobile users is Zscaler.

This service offers a cloud-native platform that provides secure access to applications and data for remote workers, as well as secure connectivity for branch offices. Zscaler's security solution includes web security, cloud sandboxing, threat prevention, data protection, and secure access service edge (SASE) capabilities, all delivered from a single platform. This ensures that all traffic, whether from branch offices or mobile users, is secured with the same level of protection. Additionally, Zscaler provides a zero trust security model that verifies identity and device posture before granting access to corporate resources, making it an ideal solution for today's distributed workforce.

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Answer:

(a)  5.89 ft/s

(b) x= 1.77 ft

Explanation:

Given that the acceleration of the particle, a=-k/x

As \(a=v\frac{dv}{dx}\) , so

\(v\frac{dv}{dx}=-\frac{k}{x} \\\\\Rightarrow vdv=-k\frac{dx}{x} \\\\\)

On integrating both sides, we have

\(\frac{v^2}{2}=-k\ln(x) + C\cdots(i)\)

where C is a constant.

At x=0.6 ft, v=15 ft/s

From equation (i)

\(\frac{15^2}{2}=-k\ln(0.6) + C \\\\\Rightarrow C=\frac{225}{2} + k\ln(0.6) \cdots(ii)\)

Similarly, at x=1.2 ft, v=9 ft/s

\(\frac{9^2}{2}=-k\ln(1.2) + C \\\\\Rightarrow \frac{81}{2} = -k\ln(1.2) + \frac{225}{2} + k\ln(0.6) \\\\\Rightarrow k(\ln(1.2) - \ln(0.6))= \frac{225}{2}-\frac{81}{2} \\\\\Rightarrow k\ln(1.2/0.6)= 72 \\\\\Rightarrow k = 72 / ln(2)=103.87\)

From equation (ii),

\(C=\frac{225}{2} + 103.87 \times \ln(0.6) \\\\\Rightarrow C=112.5-53.06=59.44\)

Putting the value of k and C in the equation (i), we have

\(\frac{v^2}{2}=-103.87\ln(x) + 59.44 \\\\\Rightarrow v^2=-207.74\ln(x) + 118.88 \\\\\Rightarrow v = \sqrt{-207.74\ln(x) + 118.88}\)

(a) At x=1.5 ft, the velocity of the particle is

\(\Rightarrow v = \sqrt{-207.74\ln(1.5) + 118.88} \\\\\)

\(\Rightarrow v = 5.89\) ft/s

At x=1.5 ft, the velocity of the particle is 5.89 ft/s.

(b) For v=0, we have

\(\Rightarrow 0 = \sqrt{-207.74\ln(x) + 118.88} \\\\\Rightarrow \ln(x) = -118.88/-207.74=0.572 \\\\\Rightarrow x= e^{0.572} \\\\\)

\(\Rightarrow x= 1.77\) ft

At x= 1.77 ft the velocity of the particle is zero.

A handsfree device may be used if it can be activated or deactivate with a cellphone.

Handsfree is a device which when connected to a cell device can be used in listening to audio, video and messages.

A driver can also activate or deactivate with a swipe when connect to the vehicle audio device.

Therefore,

A handsfree device may be used if it can be activated or deactivate with a cellphone.

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Nec Article 430 covers selection of time-delay fuses for motor- overload protection.

Article 430 that is found in  National Electrical Code (NEC) is known to be state as “Motors, Motor Circuits and Controllers.” .

Note that the article tells that it covers areas such as motors, motor branch-circuit as well as feeder conductors, motor branch-circuit and others.

Therefore, Nec Article 430 covers selection of time-delay fuses for motor- overload protection.

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Graphic designers and UI/UX designers are more likely to work for Jasmine. A member of her team.

The building and maintenance of websites require a variety of skills and disciplines known as web design. Among the many components of web design are search engine optimization, user interface design (UI design), authorship, which includes standardized code and custom software, and web graphic design. Even while some designers manage every step of the design process, it is typical for many people to collaborate in teams to handle different areas. Web design is sometimes used to describe the process of designing a website's front-end (client side) design, which involves authoring HTML. Web design and web engineering partially overlap within the broader context of web development.

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