What are a few ways diseases spread?

Answer:

Volume = 3.4 L

Explanation:

In order to calculate the volume of CO₂ produced when 15.2 g of CaCO₃ is heated, we need to first write out the balanced equation of the thermal decomposition of CaCO₃:

CaCO₃ (s) + [Heat] ⇒ CaO (s) + CO₂ (g)

Now, let's calculate the number of moles in 15.2 g CaCO₃:

mole no. = \(\mathrm{\frac{mass}{molar \ mass}}\)

                 = \(\frac{15.2}{40.1 + 12 + (16 \times 3)}\)

                 = 0.1518 moles

From the balanced equation above, we can see that the stoichiometric molar ratios of CaCO₃ and CO₂ are equal. Therefore, the number of moles of CO₂ produced is also 0.1518 moles.

Hence, from the formula for the number of moles of a gas, we can calculate the volume of  CO₂:

mole no. = \(\mathrm{\frac{Volume \ in \ L}{22.4}}\)

⇒ \(0.1518 = \mathrm{\frac{Volume}{22.4}}\)

⇒ Volume = 0.1518 × 22.4

                 = 3.4 L

Therefore, if 15.2 g of CaCO₃ is heated, 3.4 L of CO₂ is produced at STP.

Answer:

if you meant CH3-CH=CH-CH3, the IUPAC name is 2-butene.

The volume of potassium iodide used will be 0.087 L or 87 mL

The equation of the reaction goes thus: \(Pb(NO_3)_2(aq) + 2KI --- > PbI_2(s) + 2KNO_3(aq)\)

The mole ratio of the 2 reactants is 1:2.

Mole of 9.42 g \(Pb(NO_3)_2\) = 9.42/331.2 = 0.02844 mol

Equivalent mole of KI = 0.02844 x 2 = 0.05688 mol

Volume of 0.05688 mol, 0.655 mol/L KI = 0.05688/0.655 = 0.087 L or 87 mL

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The amount of the potassium superoxide that reacted in the equation is  15.9 moles.

We have to note that the amount of the potassium super oxide that was reacted in this case can be obtained from the stoichiometry of the reaction.  Looking at the stoichiometry of the reaction, we can now be able to understand that;

Number of moles of oxygen produced = 380 g/ 32 g/mol

= 11.9 moles

4 moles of the potassium super oxide produced 3  moles of oxygen

x moles of potassium super oxide produced 11.9 moles of oxygen

x = 4 * 11.9/3

= 15.9 moles

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Answer: Hydrogen

Explanation: Hydrogen has the lowest atomic number, hydrogen's atomic number is 1.

I hope this helps!

Answer:

See explanation and image attached.

Explanation:

Solvolysis is a reaction in which the solvent is also the nucleophile. The reaction occurs by SN1 mechanism since it yields most stable carbocation. The SN1 mechanism predominates since a weak nucleophile/base is used.

The major product as shown is the image attached to this answer. The first step is the loss of the bromide ion followed by nucleophillic attack of the solvent. Loss of H^+ completes the mechanism.

Answer:

0.13 s

Explanation:

We'll begin by converting 24900 mile to metres (m). This can be obtained as follow:

1 mile = 1609.344 m

Therefore,

24900 mile = 24900 mile × 1609.344 m / 1 mile

24900 mile = 4.01×10⁷ m

Finally, we shall determine the time taken for light to circumnavigate the Earth, this can be obtained as follow:

Distance = 4.01×10⁷ m

Speed = 2.998×10⁸ m/s

Time =?

Speed = distance / time

2.998×10⁸ = 4.01×10⁷ / time

Cross multiply

2.998×10⁸ × time = 4.01×10⁷

Divide both side by 2.998×10⁸

Time = 4.01×10⁷ / 2.998×10⁸

Time = 0.13 s

Thus, it will take 0.13 s for light to circumnavigate the Earth.

the poly atomic molecule is H2

Answer:

Condensation

Explanation:

Zoe is quite keen to have noticed what we call condensation. Air contains many components, one of those being water vapor. Like how sugar is soluble in water, water can be said to be "soluble" in air. Water will evaporate into the air to a certain extent. The higher the temperature of the air, the more water the air can hold. If the air has more water that it can hold (potentially because of a temperature decrease), the extra water will come out of the air. Zoe's water bottle was cold, and because the air around Zoe's bottle had cooled down, the air can not hold as much water as it could when it was warm, so the air deposited the extra water in the form of liquid water onto the bottle, giving the illusion that her bottle was sweating.

Answer: A

Explanation: I just took the quiz.

Shade-grown coffee trees produce more coffee beans per plant.

What are shade-grown coffee beans?

Shade-grown coffee is coffee grown underneath a canopy of taller trees that provide shade from the sun. Traditionally, coffee has been grown in this manner – underneath a natural forest canopy – and when done so, there are many benefits.

Majority of coffee varieties are not able to tolerate direct sunlight. They grow better under the canopy of sun-filtering shade trees. The canopy of shady trees protects the coffee from the direct sun. Further, shade-grown coffee does not require chemical fertilizers and pesticides. In the shade, the coffee beans mature more slowly. Thus, shade-grown coffee produces more beans. With slow growth, the natural sugars and flavour of the coffee get increased or enhanced. This coffee provides biodiversity and a home for birds.

Hence, option D is correct.

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The grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g. None of the options provided match the calculated value of 466.64 g.

To determine the grams of magnesium hydroxide (Mg(OH)2) needed to yield 8.00 moles of magnesium chlorate (Mg(ClO3)2), we need to consider the balanced chemical equation for the reaction between magnesium hydroxide and chlorine.

The balanced equation is as follows:

2 Mg(OH)2 + 6 Cl2 → 2 Mg(ClO3)2 + 2 H2O

From the balanced equation, we can see that 2 moles of Mg(OH)2 react with 6 moles of Cl2 to produce 2 moles of Mg(ClO3)2.

Therefore, the stoichiometric ratio is 2 moles of Mg(OH)2 : 2 moles of Mg(ClO3)2.

To calculate the grams of Mg(OH)2 needed, we can use the stoichiometric ratio and the given moles of Mg(ClO3)2.

Given:

Moles of Mg(ClO3)2 = 8.00 moles

Using the stoichiometric ratio, we have:

8.00 moles Mg(ClO3)2 × (2 moles Mg(OH)2 / 2 moles Mg(ClO3)2) = 8.00 moles Mg(OH)2

To convert moles to grams, we need to multiply by the molar mass of Mg(OH)2.

The molar mass of Mg(OH)2 = (24.31 g/mol) + (2 * 16.00 g/mol) = 58.33 g/mol

Grams of Mg(OH)2 = 8.00 moles Mg(OH)2 × 58.33 g/mol = 466.64 g

Therefore, the grams of magnesium hydroxide needed to yield 8.00 moles of magnesium chlorate is approximately 466.64 g.

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Answer:

Explanation:

The protein comprises of two 60-kD polypeptides and two 40-kD polypeptides. Each one of the 40-kD chains has a disulfide-bond which is directly bonded to a 60-kD chain.

The 100-kD units attach noncovalently to produce a protein with a molecular mass of 200 kD. The interaction among the different subunits in the protein is not affected by the Gel filtration chromatography.

Hence, the protein seems to be 200 kD in size. When SDS-PAGE takes place samples are being subjected to heat and therefore undergoing denaturation conditions. The aftermath effect of this causes disorganization in the 100 kD units.

However, the reducing agent (BME) main task is the reduction of disulfide bonds in a protein.

It implies that BME is responsible for the reduction between the R1-S-S-R2 bond between 40 kD and 60 kD to R1-SH and R2-SH, resulting in seperate proteins.

Answer:

third point

Explanation:

omniscient because it gives info about every character instead of one  

hope this helps

10.0 trillion DNA molecules is equal to 1.66 × 10–11 moles of DNA.

The correct option is A.

The directions needed for a creature to grow, endure, and reproduce are encoded in its DNA. DNA sequences must be converted into messages that can be utilized to create proteins, that are the complex molecules that carry out the majority of the work in our bodies, in order to perform these activities.

The DNA of a person can be found in almost all of their cells. The majority of DNA is found in the cell nucleus (where it is known as nuclear DNA), but there is also a tiny quantity of DNA in the mitochondrial .

1 trillion = 10¹² DNA molecules

6.022 × 10²³ molecule = 1 mole

10¹² DNA molecules = 1 / 6.022 × 10²³ × 10¹²

                                 = 1.66 × 10–11 moles.

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The complete question is -

10.0 trillion DNA molecules is equal to how many moles of DNA?

A-1.66 × 10–11 moles

B-6.02 × 1010 moles

C-6.02 × 1036 moles

D-1.66 × 1010 moles

Calculate the normality of 1 Kg of aluminum sulfide in 5000 ml of solution.

Normality comes out to be 8.11

n-factor for \(Al_{2}S_{3}\) is 6 and molar mass is 148g

So, on calculating equivalent mass is equal to 24.66g

FORMULAE of Normality (N) = (Mass of the solute) / (Equivalent mass of the solute (E) × Volume of the solution (V)

                                           N=\(\frac{1000}{24.66*5}\)

                                          N=8.11

Therefore, normality of 1 kg aluminum sulfide is 8.11

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Answer: A single bond because they share 2 electrons

Explanation:

The following is involved in bonding between atoms is electron

There are four type of chemical bonds essential for life to exist and it is ionic bond, covalent bond, hydrogen bond, and Vander wall interaction and all of these are different kind of bond to play various role in biochemical interaction and the electron on the outermost energy level of the atom are called valence electron and the valence electron are involved in bonding one atom yo another

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Answer:

See image attached

Explanation:

a)

The full reaction mechanism of step 1 was obtained from Bartleby and attached to this answer. The steps involved in the reaction are:

1) Loss of Br- and formation of a carbocation

2) Attack of CH3CN on the carbocation

4) Formation of a quaternary nitrogen intermediate

5) Attack of water on the quaternary nitrogen intermediate

6) Loss of the water molecule

5) Formation of the amide product

b)

i) sodium hydroxide

ii) HCl

Answer:

The amino sequence of an octapeptide can be determined by :

i.Amino acids present in the peptide

ii.By the behaviour shown by the treatment of these material with different biological and chemical reactions

As shown ammonium was released from the peptide,which shows that the peptide contains either Asn or Gln.

As there is presence of Asp in the amino acid analysis which indicates that the octapeptide contains Asp.

Acid hydrolysis hydrolyzes the peptide bonds which yields a Ala-Val  which is the result of partial acid hydrolysis.

Chymotrypsin is on the C-terminal side of the aromatic amino acids Phe, Tyr, and Trp. The peptide has Tyr which indicates that  the two present tetrapeptides after chymotrypsin treatment are fourth and eighth amino acids i-e N--Tyr-C and Tyr as the fourth amino acid and Ala-Val somewhere in the octapeptide

As Arg is only present on the C terminal side  of the Trypsin cleavage therefore Arg must be the second or the sixth amino acid for the two dipeptides to form as a result of arginine treatment of a tetrapeptide

Cyanogen bromide cleaves on the C-terminal side of Met residues. For free Tyr to be produced from cyanogen bromide treatment of one of the tetrapeptides, Met must be either the third or seventh amino acid. Because Ala was present in both tetrapeptides, Ala must be either the first or fifth amino acid, present in the same tetrapeptide as Arg and Met,i-e N.-Tyr-C and Ala-Val somewhere in the octapeptide and Ala-Arg-Met as the first, second, and third or fifth, sixth, and seventh amino acids and Tyr as the fourth amino acid.

One of the tetrapeptides contains Ala-Val as its second and third amino acids and Asn as its N-terminal amino acid. Therefore two combinations are possible as below

N-Asn-Ala-Val-Tyr-Ala-Arg-Met-Tyr-C or N-Ala-Arg-Met-Tyr-Asn-Ala-Val-Tyr-C

Answer:

The amino aciid sequence of an octapeptide can be determined from the amino acids that are present in the peptide and from the results of different chemical and biological treatments.

One equivalent of ammonium was released fro the peptide, indicating that the peptide contains either Asn or Gln. The presence os Asp in the amino analysis indicates that the octapeptide contains Asn.

A) Acid hydrolysis hydrolyzes peptide bonds. The dipeptide Ala-Val is obtained by partial acid hydrolysis. The indicates that Ala-Val is present in the peptide

B) Chymotrypsin cleaves on the C-terminal side of the aromatic amino acids. Phe, Tyr, and Trp. The peptide contains only Tyr. The presence of tetrapeptides after the treatment of ohymotrypsin indicates that Tyr is the fourth and eighth amino acids.

N-Tyr-C and Tyr present as the fourth amino acid. in constrast, Ala-Val is present in the octapeptide

C) Trpsin cleaves on the C-terminal side of Arg and Lys residues. only Arg is present in the octapeptide. Arg must be the second or sixth amino acid, for two dipeptide to be formed from arginine during the treatment of one tetrapeptide.

D) Cyanogen bromide cleaves on the C-terminal side of Met residues. For free Tyr to be produced from cynogen bromide treatment of one of the tetrapeptides, Met must be either the third or seventh amino acid. Because Ala is present in both tetrapeptides, Ala must be either the first or fifth amino acid, present in the same tetrapeptide as Arg and Met.

In addition, presence of N-...-Tyr-C and Ala-Val in the octapeptide and Ala-Arg-Met as the first, second, third or fifth, sixth or seventh amino acids and Tyr as the fourth amino acid.

E) One of the tetrapides contains Asn as its N-terminal amino acid, and Ala-Val as its second and third amino acids. Two octapeptides are possible from this peptide analysis.

The amino acid sequence of the octapeptide is the following:

N-Asn-Ala-Val-Tyr-Ala-Arg-Met-Tyr-C:

N-Ala-Arg-Met-Tyr-Asn-Ala-Val-Tyr-C:

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To graph the function g(x) = f(-x), you can start with the graph of f(x) and then reflect it about the y-axis.

To find the graph of the function g(x) = f(-x), we can start with the graph of the function f(x) and then reflect it about the y-axis.

If the graph of f(x) is symmetric with respect to the y-axis, meaning it is unchanged when reflected, then g(x) = f(-x) will have the same graph as f(x).

However, if the graph of f(x) is not symmetric with respect to the y-axis, then g(x) = f(-x) will be a reflection of f(x) about the y-axis.

In either case, the resulting graph of g(x) = f(-x) will be symmetric with respect to the y-axis.

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Chlorination extraction of gold from the body may refer to the use of methylene chloride to extract gold particles from the scalp and hair. During prolonged exposure, the methylene chloride can be inhaled which can cause serious health issues.

This method was founded on the idea that gold turns into the trichloride AuCl₃ when chlorine reacts with moisture. This compound can then be washed away, and the gold is precipitated using ferrous sulfate, sulphate of potash, hydrogen sulfide, or charcoal. Long contact is necessary to remove coarse gold, which should be done via amalgamation. Thoroughly oxidized ore may be handled immediately for pyrite ore or concentrate, but basic ores—which contain lime and particularly magnesia—absorb a lot of chlorine and may become heated. This was verified by finishing the roasting at a high temperature to frit the magnesia with silica.

A merger unites two or more businesses to form a new organization. A merger and an amalgamation are not the same thing because neither business exists as a separate legal entity. Instead, a brand-new organization is created to hold the merged assets and obligations of the two businesses.

Even when a new company is formed, the term amalgamation has typically lost favor in the United States and been replaced with merger or consolidation.

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Groups are numbered 1–18 from left to right. The elements in group 1 are known as the alkali metals; those in group 2 are the alkaline earth metals; those in 15 are the pnictogens; those in 16 are the chalcogens; those in 17 are the halogens; and those in 18 are the noble gases.

Answer:

In group 1 or IA there are alkali metals and in group 18 or O there are inert gases

Answer:

The molar mass and molecular weight of Al(CH3CO2)3 is 204.1136.

Explanation:

Answer:

168.1 g/mol

General Formulas and Concepts:

Chemistry

Explanation:

Step 1: Define

Al(CH₃O₂)₃

Step 2: Find molar masses

Molar Mass of Al - 26.98 g/mol

Molar Mass of C - 12.01 g/mol

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Al(CH₃O₂)₃ - 26.98 + 3(12.01) + 9(1.01) + 6(16.00) = 168.1 g/mol

Answer:

the other variable is also doubled

Explanation:

direct proportion, same thing has to happen to both variables

Answer:

Phosphorus(P) and Oxygen(O)=Covalent bond

Chlorine(Cl) and Sodium(Na) = Ionic bond

Silver (Ag) and Silver (Ag)= Metallic bond

The reaction is spontaneous under conditions of low pressure and high temperature

We can say that a reaction is spontaneous when we know that the reaction is able to go on on its own. This implies that there is a mnimum energy that is required for the reaction to proceed.

The reaction is thus a sort of a self propagating system that goes on freely of its own accord.. We can see that what is going on here is the decomposition of the nitrogen V oxide gas as shown.

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Answer:

The nucleus is the most densely compacted part of the atom, it is in the center circled by the electron cloud or shells. It is filled with positively charged protons, and neutrons which have no charge. It is smaller than the electron cloud in size, but in quantity it has more subatomic particles since protons and electrons are equal and the nucleus has nuetrons

empirical = C3HF2, molecular = C24H8F16

Explanation:

VIEW ON LAPTOP TO AVOID SPACING ERRORS                    

                     carbon                   hydrogen                   fluorine

mass             18.24                       0.51                           16.91

no. of            18.24/12                  0.51/1                         16.91/19

moles            = 1.52                     = 0.51                         = 0.89

ratio             1.52/0.51                  0.51/0.51                    0.89/0.51

                    ≈ 3                           = 1                               ≈ 2

empirical formula = C3HF2

(find number of moles by dividing mass by element's mass number. find ratio by dividing number of moles by overall smallest number of moles, in this case hydrogen)

__________________________________

let the molecular formula be (C3HF2)n

molar mass = 562.0g/mol

*[3(12) + 1 + 2(19)]n = 562.0

n = 562/75

  = 7.49

  ≈ 8

molecular formula = (C3HF2)8

                              = C24H8F16

*substitute C, H, and F with their mass numbers

In the given Galvanic cell, the electrons are flowing from left to right. The Zinc is oxidized into Zn²⁺ ions.

A galvanic cell can be described as an electrochemical cell in which electricity is produced from spontaneous Oxidation-Reduction reactions. Galvanic cells exhibit spontaneous redox reactions but the energy generated from the said reaction.

A common apparatus of the galvanic cell consists of two different metals or electrodes such as Zinc and copper electrodes, each immersed in different beakers containing their respective ion solution. Therefore, the Zinc electrode is placed in ZnSO₄ solution and the copper electrode is placed in CuSO₄ solution.

On the left end, the zinc metal is oxidized into Zn²⁺ ions, and the electrons from the Zinc electrode travel to the copper electrode (right end). The cooper Cu²⁺ ions from the CuSO₄ solution accepts those electrons and deposit as copper metal on the copper electrode.

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