what happens when the temperature of a solid reaches its melting point

Answer:

They can use man made materials or they can also have designed areas that people can’t go into

Explanation:

C/ If Fe is greater than Fg, the negatively charged oil droplet will move freely toward the negatively charged plate.

In the Millikan oil droplet experiment, the negatively charged oil droplets are subjected to an electric field created by the charged plates. The electric force (Fe) acts on the oil droplet in a direction opposite to the gravitational force (Fg). When Fe is greater than Fg, the electric force overcomes the gravitational force, causing the negatively charged oil droplet to experience an upward force. As a result, the oil droplet moves freely upward toward the negatively charged plate.

Option B is incorrect because if Fe is equal to Fg, the forces balance each other, resulting in a stationary droplet. However, the question states that Fe is increased until it is greater than Fg, implying that the droplet is no longer stationary but moves in response to the electric force.

Therefore, option C is the correct answer, as it describes the effect of an electric field on the motion of a negatively charged oil droplet in the Millikan oil droplet experiment.

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Answer: C. Na2B4O7•10H2O

Explanation:

Hope this helps :)

The formula is tetrasodium borate-Na2B4O7.10H2O

Given- 0.0132 mol Na2B4O7 and 0.1311 mol H2O

Using the molar mass of the anhydrous Na2B4O7 and its mass percentage, we can calculate the molar mass of the hydrate (if we look at it as 100% of the mass) by stoichiometry.

Molar mass of Na = (22.990 g/mol)

Molar mass of B = (10.811 g/mol)

Molar mass of O = (15.999 g/mol)

Molar mass of Na2B4O7= 2⋅22.990 g/mol +4⋅10.811 g/mol +7⋅15.999 g/mol = 201.217 g/mol

201.217g/mol : 52.8%=x g/mol : 100%

​x g/mol = 201.217 g/mol⋅100%÷52.8 %

x g/mol= 381.093 g/mol

In 381.093 g of hydrate, we have 201.217 g of anhydrous Na2B4O7 , the rest of the mass is water.

381.093g−201.217g= 179.876 g of water

Molar mass of H = 1.008 g/mol

Molar mass of O = 15.999 g/mol

Molar mass of  H2O= 1.008 g/mol+ 15.999g/mol  = 18.015 g/mol

179.876g ÷18.015 = 9.98= 10 moles of water per mole of hydrate.

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Answer:

48.059

Explanation:

Find on periodic table and add

32.06+15.99

A. It alters when the temperature changes.

The reaction's temperature affects the equilibrium constant (K) of the process.

The position of equilibrium and the value of the equilibrium constant can both be impacted by changes in temperature, as well as the relative rates of the forward and reverse reactions.

The van't Hoff equation describes the connection between K and temperature. Only at a particular temperature is the equilibrium constant; otherwise, it varies with temperature.

When the amounts of reactants and products do not tend to fluctuate, a chemical process is in equilibrium. It is up to us to decide which components are deemed reactants and which are products when we write a chemical reaction in a certain way.

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Answer:

1. B

2.C

3.D

4.Sorry don't this one :(

5.A

Explanation:

please give me at least 20 points ❤

If the experiment is repeated at the pH 11 level, the enzyme activity will be less than at the pH 9 level.

We can arrive at this answer because:

In this case, we can say that if the experiment is repeated at pH 11, the enzyme activity level will be even lower, since from pH 5 onwards, as the pH rises, the enzyme activity goes down.

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Kc for this reaction will be relatively large because the equilibrium favors the products (OCl- and HClO3) due to the relative strengths of the acid-base pairs involved.

Based on the reaction given, we can analyze the size of Kc using our knowledge of relative acid-base strengths and equilibrium. The reaction involves the following species:

HOCl(aq) - a weak acid
ClO3-(aq) - a weak base
OCl-(aq) - a weak base
HClO3(aq) - a strong acid

In this reaction, a weak acid (HOCl) reacts with a weak base (ClO3-) to form a strong acid (HClO3) and a weak base (OCl-). Since strong acids favor dissociation and have a larger equilibrium constant, the reaction will tend to shift towards the right to produce more of the strong acid (HClO3) and weak base (OCl-). As a result, we can conclude that the size of Kc for this reaction is likely to be greater than 1, indicating that the reaction favors the formation of products over reactants.

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The ocean floor being featureless was the assumption was proved wrong after the invention of sonar.

This employs the use of sound propagation to measure the distance or presence of objects under the water.

This helped to show that the ocean floor had features such as canyons, mountains etc hence option B was chosen.

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Answer:

3.14

Explanation:

pH=-log(H+)

- Hope that helps! Please let me know if you need further explanation.

Answer:

A. Barium

Explanation:

hope this helps! :)

The arrangement that orders the n-alkanes from lowest to highest boiling point is:

C8 < C9 < C10 < C11 < C12 < C14 < C16 < C18 < C20

Order the boiling point of n-alkanes of n-alkanes from lowest to highest boiling point is: Methane < Ethane < Propane < Butane < Pentane < Hexane < Heptane < Octane < Nonane < Decane.

The boiling point of n-alkanes increases with increasing molecular weight and surface area. Therefore, the correct order of n-alkanes from lowest to highest boiling point is:

Methane < Ethane < Propane < Butane < Pentane < Hexane < Heptane < Octane < Nonane < Decane

This order is based on the assumption that all the n-alkanes are at standard conditions (1 atm and 25°C). However, it's important to note that deviations from this trend can occur due to factors such as branching, cyclic structures, and functional groups.

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Answer:

C    shake it repeatedly

Explanation:

i think thats the answer if not sorry hope it helps you.

Answer:

C.

Explanation:

Answer:

I think it's the second one im not sure tho

Hope this helps :)

It is hemoglobin.

In the red blood cells (erythrocytes) of vertebrates, hemoglobin, an iron-containing protein, transports oxygen from the lungs to the body's tissues and organs and returns carbon dioxide to the lungs. In a complete blood cell (CBC) test, the amount of hemoglobin in the blood is often measured.

A globin group is surrounded by four heme groups, which together form a tetrahedral shape in each hemoglobin molecule. Heme is an organic complex known as a porphyrin that has an iron atom linked to it. Heme makes up only 4% of the weight of the molecule. As the blood circulates between the lungs and the tissues, the iron atom is what holds oxygen in place. Each hemoglobin molecule contains four iron atoms, and as a result, it has the capacity to bind four oxygen molecules. Two linked pairs of polypeptide chains make up globin.

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Dry bulk terminals typically handle a wide range of minerals. Here are some common types of minerals processed at dry bulk terminals: Coal, Iron ore, Bauxite, Limestone, Gypsum, Phosphate rock, Salt, Silica sand, Copper concentrate and Zinc concentrate.

1. Coal: A combustible sedimentary rock composed primarily of carbon. It is a valuable energy resource used for power generation and industrial purposes.

2. Iron ore: A rock containing iron minerals that can be extracted and processed to produce iron and steel. It is an essential raw material for the metallurgical industry.

3. Bauxite: A sedimentary rock rich in aluminum minerals. Bauxite is the primary source of aluminum and is processed to extract alumina, which is further refined to produce aluminum metal.

4. Limestone: A sedimentary rock composed mainly of calcium carbonate. Limestone is used in the production of cement, as a flux in metallurgical processes, and as a building material.

5. Gypsum: A mineral composed of calcium sulfate dihydrate. Gypsum is used in the production of plaster, wallboard, and as a soil amendment.

6. Phosphate rock: A mineral used in the production of fertilizers. It contains phosphorus compounds necessary for plant growth.

7. Salt: Sodium chloride or halite is a mineral processed for various industrial applications, including chemical production, water treatment, and food processing.

8. Silica sand: A high-purity form of sand composed mainly of silica. It is used in glass manufacturing, foundries, and as a proppant in hydraulic fracturing.

9. Copper concentrate: A product of copper mining, containing a high percentage of copper along with other valuable minerals. It is processed to extract copper metal.

10. Zinc concentrate: A product of zinc mining, consisting of zinc minerals and other impurities. It is processed to extract zinc metal.

These are just a few examples, and there are many other types of minerals processed at dry bulk terminals depending on regional resources and industrial needs.

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Answer

crush the cubes of broth, add warm water and stir the container.

Explanation

The FASTEST way to make the chicken broth with the cubes you have will be to increase the surface area of the cubes broth by crushing and raise the temperature of the cubes broth by adding warm water and by stirring the container.

Hence, the correct answer to your question is:

crush the cubes of broth, add warm water and stir the container.

Answer:

B.) Trigonal planar

Explanation:

This molecule has 3 bonds and no lone pairs. The angles are all 120° and the bonds are within the same plane. These molecules have the molecular shape of trigonal planar.

Answer:

(m1+m2)v

Explanation:

where m1 is the mass of the first body

m2 is the mass of the second body

v is the velocity

Answer:

What is the question needing to be answered?

Explanation:

Usually with a scientific hypothesis, you ask the question in an if, then statement. For example: If it rains outside, then the ground will be wet. It's kind of like a cause and effect statement.

Answer: The estimated Kd for benzene for this site is 68.12430112919306 cm³/g.

Explanation: Here are the steps involved in estimating the Kd for benzene for this site:

Step 1: Calculate the log10 Koc using the following formula:

\(log10\) \(Koc = 0.81 log10 Kow + 0.1\)

Substitute the values of Kow and foc into the formula:

\(Kow = 138\)

\(foc = 0.041\)

\(log10 Koc = 0.81 log10 (138) + 0.1\)

\(log10 Koc = 3.76\)

Step 2: Convert the log10 Koc to Koc by raising 10 to the power of log10 Koc:

Koc = 10 ^ log10 Koc

Koc = 10 ^ 3.76

Koc = 68.12430112919306 cm3/g

Therefore, the estimated Kd for benzene for this site is 68.12430112919306 cm³/g.

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RCA cleaning, SC1/SC2 cleaning, and megasonic cleaning are the three  silicon wafer cleaning methods. Each of them have their advantages and are commonly used in semiconductor manufacturing processes.

There are several methods used to clean silicon wafers in the semiconductor industry.

Here are three common methods along with a comparison of their efficacy:

1) RCA Cleaning (Radio Corporation of America):

RCA cleaning is a widely used method for silicon wafer cleaning. It involves a two-step process:

a. RCA-1: The wafer is immersed in a mixture of deionized water, hydrogen peroxide (H₂O₂), and ammonium hydroxide (NH4OH). This step removes organic contaminants, particles, and some metal ions from the wafer surface.

b. RCA-2: The wafer is then immersed in a mixture of deionized water, hydrogen peroxide, and hydrochloric acid (HCl). This step removes metallic and ionic impurities from the wafer surface.

Efficacy: RCA cleaning is highly effective in removing organic and inorganic contaminants. It provides a good level of cleanliness for most semiconductor fabrication processes.

2) SC1 and SC2 Cleaning (Standard Clean 1 and Standard Clean 2):

SC1 and SC2 cleaning are alternative methods to RCA cleaning and are used for wafer surface preparation. The process involves the following steps:

a. SC1: The wafer is immersed in a mixture of deionized water, hydrogen peroxide, and ammonium hydroxide. This step removes organic and ionic contaminants from the wafer surface.

b. SC2: The wafer is immersed in a mixture of deionized water, hydrogen peroxide, and hydrochloric acid. This step removes metallic and oxide contaminants from the wafer surface.

Efficacy: SC1 and SC2 cleaning methods are effective in removing various types of contaminants from the wafer surface. They provide comparable cleanliness to RCA cleaning.

3) Megasonic Cleaning:

Megasonic cleaning involves the use of high-frequency sound waves (usually in the range of 800 kHz to 2 MHz) to agitate the cleaning solution and remove particles from the wafer surface. It is often used in conjunction with RCA or SC cleaning methods.

Efficacy: Megasonic cleaning is highly effective in removing particles from the wafer surface. It can dislodge and remove smaller particles that may be difficult to remove by chemical cleaning methods alone.

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Answer:

After CaMKII (calcium/calmodulin-dependent protein kinase II) causes the release of CREB (cAMP response element-binding protein), several events occur in the postsynaptic cell.

Explanation:

Here are some of the key processes:

CREB Activation: Once released, CREB becomes activated by undergoing phosphorylation. Phosphorylated CREB plays a crucial role in gene transcription and cellular responses.

Gene Transcription: Activated CREB binds to specific DNA sequences called cAMP response elements (CREs) within the nucleus. This binding promotes the transcription of target genes, leading to the synthesis of new proteins.

Protein Synthesis: The transcription of CREB target genes results in the production of various proteins, including those involved in synaptic plasticity, cell growth, and neuronal survival. These newly synthesized proteins play a role in the long-term changes and adaptations that occur within the postsynaptic cell.

Structural Changes: The activation of CREB and subsequent protein synthesis can lead to structural changes in the postsynaptic cell. These changes may involve modifications to dendritic spines, the formation of new synapses, or alterations in synaptic strength, all of which contribute to synaptic plasticity and the strengthening of neural connections.

Long-Term Potentiation (LTP): LTP is a process associated with the strengthening of synaptic connections and is crucial for learning and memory. The activation of CREB and subsequent gene transcription contribute to the induction and maintenance of LTP, allowing for the long-lasting enhancement of synaptic transmission.

In summary, after CaMKII triggers the release of CREB, the activated CREB promotes gene transcription, leading to protein synthesis, structural changes, and the facilitation of long-term changes in the postsynaptic cell. These processes are essential for synaptic plasticity, learning, and memory formation.

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Answer:

125 pounds = 56.6990463 kilograms

Explanation:

When the three different phase compounds are mixed, and treat my mixture with aqueous NaOH the acidic mixture remain in the organic phase. So, right answer is option(b).

We have, a mixture which contain three compounds a,b and n. Here, a is acidic, b is base and n is non-acidic in nature. Then this mixture is treated with aqueous NaOH solution. As we know that NaOH is strong base so in order to divert our mixture to organic phase we need acidic mixture A to follow the acid - base extraction. The acid-base extraction method is used to separte the acidic, basic and the neutral compound. This is also known as liquid-liquid extraction. We can add add mineral base for an acidic and neutral compound to start and to take the proton away from the acidic compound. Because the acidic compound is ionic and water-soluble. So, the remained organic phase of solution is acidic.

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Complete question :

I have a mixture of 3 compounds: a is acidic, b is basic and n is non acidic. if i treat my mixture with aqueous naoh, which compound(s) will remain in the organic phase?

a) N ( neutral mixture)

b) A ( acidic mixture)

c) B ( basic mixture)

d) None of the above.

The selection of an appropriate solvent is critical for the success of a recrystallization process, as it can significantly affect the yield and purity of the final product. Some of the most important factors to consider when selecting a solvent for recrystallization are:

What is recrystallization?

Recrystallization is a technique used in chemistry to purify solid compounds based on their solubility. The process involves dissolving a crude mixture of the compound to be purified in a suitable solvent, which is then heated to a temperature at which the compound dissolves.

Overall, the ideal solvent for recrystallization should be able to dissolve the compound at high temperatures, but not at low temperatures, be selective towards the desired compound, and be safe, available, and affordable.

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Answer:

1) Monochrome

2) Monocot

3) Monosaccharide

4) Monounsaturated

5) Monoxide

Explanation:

The prefix mono or mon is of Greek origin and it means single, lone or one.

From the meaning of the words we can tell that they have something in common:

1) Monochrome: This refers to an artwork, a painting or drawing that has just one color.

2) Monocot: This is a type of flowering plant that has a single embryo and a single cotyledon.

3) Monosaccharide: This is a type of simple sugar that contains one sugar unit that cannot be split.

4) Monounsaturated: This refers to a molecule that contains one double or triple bond.

5) Monoxide: This refers to a form of oxide that contains only one oxygen atom.

From the definitions above, all the words mean having only one or a single item.

That is what they have in common.

The molar heat of vaporization of sulfur dioxide is approximately 25,207 J/mol. To calculate the molar heat of vaporization of sulfur dioxide, you can use the Clausius-Clapeyron equation, which is:

ln(P2/P1) = -ΔHvap/R * (1/T2 - 1/T1)

where P1 and P2 are the vapor pressures at temperatures T1 and T2, respectively, ΔHvap is the molar heat of vaporization, and R is the ideal gas constant (8.31 J/K*mol).

First, convert the temperatures from Celsius to Kelvin:
T1 = -21.0°C + 273.15 = 252.15 K
T2 = -44.0°C + 273.15 = 229.15 K

Next, plug the values into the equation:

ln(140.5/462.7) = -ΔHvap/8.31 * (1/229.15 - 1/252.15)

Now, solve for ΔHvap:

ΔHvap = 8.31 * (ln(140.5/462.7) / (1/229.15 - 1/252.15))^-1

ΔHvap ≈ 25,207 J/mol

So, the molar heat of vaporization of sulfur dioxide is approximately 25,207 J/mol.

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Answer:

A) provide energy for cellular work

Explanation:

The Adenosine triphosphate (ATP) molecule is the nucleotide known in biochemistry as the "molecular currency" of intracellular energy transfer; that is, ATP is able to store and transport chemical energy within cells. ATP also plays an important role in the synthesis of nucleic acids.

ATP always GIVES ENERGY